Find the value of x.

The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

In the question ,

it is given that ,

the fixed rent for a car is = $35 .

the per mile charge for the car is = $0.10 miles

let the number of miles driven is = n miles

the function C that represents the linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is given by

C(n) = fixed charge + (per mile charge)×(number of miles)

Substituting the values , we get

C(n) = 35 + 0.10×n

Therefore , The linear equation for the monthly charge C dollars , in terms of the number of miles driven(n) is C(n) = 35 + 0.10×n  .

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Answer:
id say, C=0.10=35

Step-by-step explanation:

not really sure, but I tried!

Answer:

B

Step-by-step explanation:

First, the formula of a triangle is l x h/2, so 6 x 7 = 42, but 42/2 = 21 so your answer is B

Hope this helps!

Answer:

B I think

Step-by-step explanation:

7 x 6 divided by 2 = 21

It doesn't have the lengths of the rectangle.

Answer:

-7 + 4 = -3

Step-by-step explanation:

So you start at -7 and if you add a positive number to a negative number you basically subtract from the negative number, so you would do -7 + 4 which equals -3

Answer:

Letter B

Step-by-step explanation:

I used a graphing calculator,

Hope this helps

1. The quadratic function for the Area in terms of x: A(x) = 24x.

2. The cross-sectional area is maximized when the depth of the gutter is 0.

3. The maximum cross-sectional area is square inches 0.

To determine the depth of the gutter that maximizes its cross-sectional area and allows the greatest amount of water to flow, we need to follow a step-by-step process.

1. Write a quadratic function for the area in terms of x:

The cross-sectional area of the gutter can be represented as a rectangle with a width of 24 inches and a depth of x. Therefore, the area, A(x), is given by A(x) = 24x.

2. The cross-sectional area is maximized when the depth of the gutter is:

To find the value of x that maximizes the area, we need to find the vertex of the quadratic function. The vertex of a quadratic function in form f(x) = ax² + bx + c is given by x = -b/(2a). In our case, a = 0 (since there is no x² term), b = 24, and c = 0. Thus, the depth of the gutter that maximizes the area is x = -24/(2 * 0) = 0.

3. The maximum cross-sectional area is square inches:

Substituting the value of x = 0 into the quadratic function A(x) = 24x, we get A(0) = 24 * 0 = 0. Therefore, the maximum cross-sectional area is 0 square inches.

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Answer:

$6.96 more was the book than the lunch

Step-by-step explanation:

do cost of the book subtract the cost of the lunch forget the decimals and just subtract like normally. then at the end bring down the decimals, hope this helps

The inequality as per the question is x ≥ 9 and y > 3 and the diagram according to this is attached below.

Inequalities are mathematical expressions where neither side is equal. In inequality, as opposed to equations, we compare the two values. Less than (or less than and equal to), larger than (or greater or equal to), or not similar to signs are used in place of the equal sign in between.

As per the given information in the question.,

x ≥ 9 and,

y > 3

The equation is,

650 x + 1400 y ≤ 1

\(\frac{x/15000}{650}+\frac{y/15000}{1400} \leq 1\)

x/23.07 + y/10.71 ≤ 1

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The triangle ABC is a right triangle

The length of AC is 12.00 cm

From the figure, we have the following parameters:

Length AB = 13 cm

Angle A = 22.6 degrees

Represent the length AC with b.

So, we have the following cosine ratio

\(\cos(A) = \frac{b}{AB}\)

Substitute known values

\(\cos(22.6) = \frac{b}{13}\)

Make b the subject

\(b = 13 * \cos(22.6)\)

Evaluate the product

\(b = 12.00\)

Hence, the length of AC is 12.00 cm

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Answer:

16

Step-by-step explanation:

3^x +1 = f(X)

2x-4 = g(x)

find f(2)-g(-1)

we substitute in function f(X) by value (2), and in function g(X) by value (-1)

1. 3^x +1 becomes 3^2+1 =9+1=10

2. 2(-1)-4= -2-4=-6

then f(2)-g(-1)

= 10-(-6) =10+6=16

1) All boys: Probability = 1/16 , 2) All girls: Probability = 1/16, 3) Exactly 3 boys: Probability = 5/16, 4) At least 1 boy: Probability = 15/16, 5) At most 3 girls: Probability = 15/16.

1) All boys: There are 16 possible combinations of 4 children, with each gender combination having an equal probability of 1/16. Therefore, the probability of all boys is 1/16.

2) All girls: Similarly, the probability of all girls is also 1/16.

3) Exactly 3 boys: To find the probability of exactly 3 boys, we need to consider all the cases with 3 boys and 1 girl. There are 4 possible combinations of 3 boys and 1 girl, so the probability of exactly 3 boys is 4/16, or 5/16.

4) At least 1 boy: To find the probability of at least 1 boy, we need to consider all the cases with 1, 2, 3, or 4 boys. There are 15 possible combinations with at least 1 boy (1 boy, 2 boys, 3 boys, and 4 boys), so the probability of at least 1 boy is 15/16.

5) At most 3 girls: To find the probability of at most 3 girls, we need to consider all the cases with 0, 1, 2, or 3 girls. There are 15 possible combinations with at most 3 girls (0 girls, 1 girl, 2 girls, and 3 girls), so the probability of at most 3 girls is 15/16.

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Answer:

Step-by-step explanation:

Even ( I think)

positivie ( I think )

x intercept - (0,0)(-2,0)(-4,0)

y intercept - (0,0)

Answer:

Differences=

\( {120cm}^{3} \)

Step-by-step explanation:

Volume of first box=15cm×4cm×8cm

\(480 {cm}^{3} \)

Volume of second box=10cm×9cm×4cm

\( {360cm}^{3} \)

Answer:

98

Step-by-step explanation:

Answer:

296

Step-by-step explanation:

I hope this helps you out!

Answer:

b < 3

Step-by-step explanation:

3 ( b - 5 ) < - 2b

3 ( b ) - 3 ( 5 ) < - 2b

3b - 15 < - 2b

3b + 2b < 15

5b < 15

b < 15/5

b < 3

Step-by-step explanation:

3+2/x=1

(3x+2)/×=1

3x+2=x

2=-2×

x= -1

Answer:

you need  thing like bills need to be sent to you so you can pay them , if you use your friends adrdress you wont have easy acesses to to all of that information which isnt  a good thing in the long run

Step-by-step explanation:

The rental rates that David recorded are:

500, 650, 600, 505, 450, 550, 515, 495, 640

So the rents (in $ per month) were:

$500/month

$650/month

$600/month

$505/month

$450/month

$550/month

$515/month

$495/month

$640/month

The fraction of the area of the tray occupied by the blondies is 1/9.

To find the fraction of the area of the tray occupied by blondies, we need to determine the area occupied by the blondies and compare it to the total area of the tray.

Let's calculate the area of each individual blondie:

The blondies are squares with 3-inch sides, so the area of each blondie is 3 inches × 3 inches = 9 square inches.

Now, let's calculate the area occupied by the blondies in each row:

Since there are 4 rows of blondies and each row contains 4 blondies, the total number of blondies is 4 rows × 4 blondies per row = 16 blondies.

So, the total area occupied by the blondies is 16 blondies × 9 square inches per blondie = 144 square inches.

Next, let's determine the area occupied by the brownies:

The brownies are squares with 6-inch sides, so the area of each brownie is 6 inches × 6 inches = 36 square inches.

Since there are also 4 rows of brownies and each row contains 4 brownies, the total number of brownies is 4 rows × 4 brownies per row = 16 brownies.

Therefore, the total area occupied by the brownies is 16 brownies × 36 square inches per brownie = 576 square inches.

Now, let's calculate the total area of the tray:

Given that the tray is completely full and has an area of 648 square inches, we can subtract the area occupied by the brownies from the total area to find the remaining area occupied by the blondies:

Total area of the tray - Area occupied by the brownies = Area occupied by the blondies

648 square inches - 576 square inches = 72 square inches.

So, the fraction of the area of the tray occupied by the blondies is:

Area occupied by the blondies / Total area of the tray = 72 square inches / 648 square inches.

To simplify this fraction, we can divide both the numerator and denominator by their greatest common divisor, which is 72 in this case:

72 square inches / 648 square inches = 1/9.

Therefore, the blondies' percentage of the tray's surface area is 1/9.

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Each step of this theorem is proved below.

Given that,

S is finite,

Now enumerate all of its elements as x₁, x₂,..., x\(_{n}\).

According to the cancellation rule,

This product is independent of the order of the factors.

As a result, we can define the identity element e as this product.

It is simple to demonstrate that e meets the criteria of an identity element.

Now, let's show that every element of S has an inverse.

Let a be any element of S. Consider the set {a, a, a, ...}.

Since S is finite,

There exist positive integers m and n such that

am = an   for some m > n.

By the cancellation law,

We can cancel a power of a from both sides to get a\({(m-n)}\) = e.

This means that a has an inverse, and we can conclude that S is a group.

Consider the set of all positive integers under addition, except 1, as an example of an infinite semigroup in which the cancellation laws hold but which is not a group.

This set clearly meets the cancellation laws, but it does not have an inverse for every element, because the inverse of 2, for example, is not an integer.

As a result, this is not a group.

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Solution :

Given :

There are five cities in a network and the cost of \(\text{building}\) a road directly between \(i\) and \(j\)  is the entry \(a_{i,j}\)

\(a_{i,j}\)  refers to the matrix.

Road cannot be built because there is a mountain.

The given matrix :

\(\begin{bmatrix}0 & 3 & 5 & 11 & 9\\ 3 & 0 & 3 & 9 & 8\\ 5 & 3 & 0 & \infty & 10\\ 11 & 9 & \infty & 0 & 7\\ 9 & 8 & 10 & 7 & 0\end{bmatrix}\)

The matrix on the left above corresponds to the weighted graph on the right.

Using the \(\text{Kruskal's algorithm}\) we can select the cheapest edge that is not creating a cycle.

Starting with 2 edges of weight 3 and the edge of weight 5 is forbidden but the edge is 7  is available.

The edge of the weight 8 completes a minimum spanning tree and total weight 21.

If the edge of weight 8 had weight 10 then either of the edges of weight 9 could be chosen the complete the tree and in this case there could be 2 spanning trees with minimum value.

Answer:

the comedy films, action and horror is 14, 49 and 7 respectively

Step-by-step explanation:

The computation of each one dvds is as follows;

Total dvds is 70

Now the ratio of comedy films to action to horror is 2:7:1

So the total of 10

Now the each one dvds is

For comedy flms

= 70 × 2 ÷ 10

= 14

For actions

= 70 × 7 ÷ 10

= 49

For horror

= 70 × 1 ÷ 10

= 7

Hence the comedy films, action and horror is 14, 49 and 7 respectively

Its Taylor polynomial T3(x) for function f with the number an as the center is T 3(x)=(x 2 + 61 x 2 ). 3

Sums of terms with the pattern kxn—where k is any positive integer and n is an arbitrary number—are known as polynomials. A polynomial is something like 3x+2x-5. Polynomials: An introduction In this video, basic terms such terms, degrees, standard form, monomial, binomial, and trinomial are covered. A polynomial is a function that exclusively uses positive integer exponents or non-negative integer powers of a variable in an equation, such as a quadratic or cubic equation. A polynomial with an exponent of 1 is, for instance, 2x+5.

T 3 (x)=f(a) + 1!f ′ (a)(xa) + 2!f ′′(a)(xa) 2 plus 1 3!f ′′′(a)(x−a) 3=0plus 1!−1(x− 2π)+ 2!0(x− 2π) 2 plus 1 3!1​ (x− 2π) 3=−(x− 2π)+ 61\s(x− 2π) 3

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In general, if the range of a function is y≥−1, its inverse has a domain of y≥−1. So, the range of the inverse of the cubic root function is y≥−1.

The range of a cubic root function becomes the domain of a cube function and vice versa since a cubic root function is an inverse function of a cube function. Therefore, the cube function's range is x3 if the cubic root function's domain is x3.

A function's inverse typically has a domain of y1 if its range is y1. Therefore, y1 is the domain of the inverse of the cubic root function.

Describe a function.

A function is a mathematical relationship between a domain—a set of inputs—and a range—a set of outputs. Each input in the domain is given a distinct output, known as the function value, by a function. An equation or graph can be used to depict the function value.

A function is typically represented symbolically by an equation that describes the relationship between the inputs and outputs and a letter, like f or g, as well as the letter. For instance, the equation of a function that accepts a value of x as input and produces its square is f(x) = x2.

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Answer:

r = -36

Step-by-step explanation:

-9 = r/4

Multiply both sides by 4 to isolate r

-9 x 4 = r/4 x 4

-36 = r

r = -36

Step-by-step explanation:

Given: To make smallest 3-digit number of 825.

To find: The smallest 3-digit number of 825.

Solution: We can make the smallest 3-digit number of 825 by separating the numbers and arranging it to ascending order. The given number is 825. ...

Final answer: The smallest 3-digit number of 825 is 258.

hope it helps

Answer:

258

Step-by-step explanation:

We are given 3 numbers:

8 2 5

And we are asked to find the smallest 3 digit number using those 3 digits above.

To make the smallest number, place the numbers in value from least to greatest:

2 5 8

This is your 3 digit number: 258.

Hope this helps! :)

Answer:2

Step-by-step explanation:

\(\frac{14}{5} -5\)

Divide 14 by 2 to get 7.

7−5

Subtract 5 from 7 to get 2.

Answer=2

Answer:

16

Step-by-step explanation:

x+y=30  solve for x   x=30-y

substitute x with 30-y and solve

11.25x+22.4y=515.9

11.25(30-y)+22.4y=515.9

337.5+11.15y=515.9

11.15y=178.4

y=16

since we're solving for just large candles it's 16

if need small cangle number 30-16=14

To calculate the volume of the cone we use its formula and the values given.

Answer:

a) the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

- the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

- the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

- the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

Step-by-step explanation:

Given the data in the question;

proportion p = 0.6

sample size n = 10

binomial distribution

let x rep number of orders for raw materials arriving late in the sample.

(a) probability of committing a type I error if the true proportion is  p = 0.6;

∝ = P( type I error )

= P( reject null hypothesis when p = 0.6 )

= ³∑\(_{x=0\) b( x, n, p )

= ³∑\(_{x=0\) b( x, 10, 0.6 )

= ³∑\(_{x=0\) \(\left[\begin{array}{ccc}10\\x\\\end{array}\right]\)\((0.6)^x\)\(( 1 - 0.6 )^{10-x\)

∝ = 0.0548

Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b)

the probability of committing a type II error for the alternative hypotheses p = 0.3

β = P( type II error )

= P( accept the null hypothesis when p = 0.3 )

= ¹⁰∑\(_{x=4\) b( x, n, p )

= ¹⁰∑\(_{x=4\) b( x, 10, 0.3 )

= ¹⁰∑\(_{x=4\) \(\left[\begin{array}{ccc}10\\x\\\end{array}\right]\)\((0.3)^x\)\(( 1 - 0.3 )^{10-x\)

= 1 - ³∑\(_{x=0\) \(\left[\begin{array}{ccc}10\\x\\\end{array}\right]\)\((0.3)^x\)\(( 1 - 0.3 )^{10-x\)

= 1 - 0.6496

= 0.3504

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

the probability of committing a type II error for the alternative hypotheses p = 0.4

β = P( type II error )

= P( accept the null hypothesis when p = 0.4 )

= ¹⁰∑\(_{x=4\) b( x, n, p )

= ¹⁰∑\(_{x=4\) b( x, 10, 0.4 )

= ¹⁰∑\(_{x=4\) \(\left[\begin{array}{ccc}10\\x\\\end{array}\right]\)\((0.4)^x\)\(( 1 - 0.4 )^{10-x\)

= 1 - ³∑\(_{x=0\) \(\left[\begin{array}{ccc}10\\x\\\end{array}\right]\)\((0.4)^x\)\(( 1 - 0.4 )^{10-x\)

= 1 - 0.3823

= 0.6177

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

the probability of committing a type II error for the alternative hypotheses p = 0.5

β = P( type II error )

= P( accept the null hypothesis when p = 0.5 )

= ¹⁰∑\(_{x=4\) b( x, n, p )

= ¹⁰∑\(_{x=4\) b( x, 10, 0.5 )

= ¹⁰∑\(_{x=4\) \(\left[\begin{array}{ccc}10\\x\\\end{array}\right]\)\((0.5)^x\)\(( 1 - 0.5 )^{10-x\)

= 1 - ³∑\(_{x=0\) \(\left[\begin{array}{ccc}10\\x\\\end{array}\right]\)\((0.5)^x\)\(( 1 - 0.5 )^{10-x\)

= 1 - 0.1719

= 0.8281

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

The probability of committing a type I is 0.0548, type II error for  p = 0.3 is 0.3504, type II error for p = 0.4 is 0.6177, type II error for s p = 0.5 is 0.8281.

The sample size n = 10

Binomial distribution summarizes the number of trials, or observations when each trial has the same probability of attaining one particular value.

\(\rm p= \left[\begin{array}{ccc}n\\x\\\end{array}\right] \times p^{x} \times q^{n-x}\)

(a) Probability of committing a type I error if the true proportion is  p = 0.6;

∝ = P( type I error )

= P( reject null hypothesis when p = 0.6 )

\(\rm p= \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.6^{x} \times 0.6^{10-x}\\\)

∝ = 0.0548

Therefore, the probability of committing a type I error if the true proportion is p = 0.6 is 0.0548

b) The probability of committing a type II error for the alternative hypotheses p = 0.3

β = P( type II error )

= P( accept the null hypothesis when p = 0.3 ) = ¹⁰∑

\(\rm p= \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.3^{x} \times 0.3^{10-x}\\\)

= 1 - ³∑

= 1 - 0.6496

= 0.3504

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.3 is 0.3504

The probability of committing a type II error for the alternative hypotheses p = 0.4

β = P( type II error )

= P( accept the null hypothesis when p = 0.4 )

\(\rm \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.4^{x} \times 0.4^{10-x}\\\) = ¹⁰∑

= 1 - ³∑

= 1 - 0.3823

= 0.6177

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.4 is 0.6177

The probability of committing a type II error for the alternative hypotheses p = 0.5

β = P( type II error )

= P( accept the null hypothesis when p = 0.5 )

¹⁰∑ = \(\rm \left[\begin{array}{ccc}10\\x\\\end{array}\right] \times 0.5^{x} \times 0.5^{10-x}\\\)

= 1 - ³∑

= 1 - 0.1719

= 0.8281

Therefore, the probability of committing a type II error for the alternative hypotheses p = 0.5 is 0.8281

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