Answer:
n = 144
Step-by-step explanation:
6 / n = 5/120
6 * 120 = 5*n
5n = 6*120
5n = 720
n = 720/5
n = 144
Answer:
144
Step-by-step explanation:
you should use a proportion to do this to make it easier to solve.
\(\frac{6}{n} = \frac{5}{120}\)
cross multiply the numbers
\(5n = 6*120\)
\(5n = 720\)
then divide 720 by 5
\(n = 144\)
Now write 40,630 in scientific notation
Answer:
40630=4.063× 10 power 4If profits decrease by 13.8% when the degree of operating
leverage (DOL) is 3.8, then the decrease in sales is:
A) 0.28%
B) 0.52%
C) 3.63%
D) 10%
E) 52.44%
Given that profits decrease by 13.8% when the degree of operating leverage (DOL) is 3.8.
The decrease in sales is: We have to determine the percentage decrease in sales Let the percentage decrease in sales be x.
Degree of Operating Leverage (DOL) = % change in Profit / % change in Sales3.8
= -13.8% / x Thus, we have: x
= -13.8% / 3.8
= -3.63%Therefore, the decrease in sales is 3.63%.Hence, the correct option is C) 3.63%. Percentage decrease in sales = % change in profit / degree of operating leverage
= 13.8 / 3.8
= 3.63% The percentage decrease in sales is 3.63%.
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What is the sum of 7.535 and 29.02
Answer:36.555
Step-by-step explanation:7.535+29.02=36.555
Answer:
36.555
Step-by-step explanation:
Pls work this out I will give you brainest xx
A company offers rectangular pool sizes with the dimensions shown. Each pool includes a deck around it. Write a quadratic function to represent the area of the pool and the deck. If Carolina wants a 15 foot pool with a deck, how many square feet will she need ot have available in her yard?
The formula for calculating the area of a rectangle is expressed as:
A = LW where
L is the length
W is the width
For the pool
Length = 2x
With = x
Get the equation for the area.
Area = 2x * x
Area = 2x²
Hence the area of the quadratic function that represents the area of the pool is 2x² ft²
For the pool with deck
length = 15 + 2x + 15 = 30+2x
Width = 15 + x + 15 = 30+x
Get the areas of the pool with deck
A 60x+2x= (30+2x)(30+x)
A = 900+30x+60x+2x²
A = 2x²+90x+900
The area of the quadratic function that represents the area of the pool with deck is (2x²+90x+900) ft²
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As the sample size becomes larger, the sampling distribution of the sample mean approaches a.
The sampling distributions reach a normal distribution as sample sizes increase.
What is termed as the normal distribution?The proper term for just a probability bell - shaped curve is the normal distribution.The mean of a normal distribution is zero, and the standard deviation is one. It has a skew of 0 and a kurtosis of 3.Even though all symmetrical distributions are normal, not all normal distributions are symmetrical.Many naturally occurring phenomena resemble the normal distribution.For the given statement in the question-
As sample sizes grow larger, sampling distributions reach a normal distribution.
The mean of the sampling distribution equals the population mean (µ) (with "infinite" numbers of the successive random samples).
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If f'(c) < 0 then f(x) is decreasing and the graph of f(x) is concave down when x = c. True False Question 4 (1 point). A local extreme point of a polynomial function f(x) can only occur when f'(x) = 0. True False Question 5 (1 point) If f'(x) > 0 when x < c and f'(x) < 0 when x > c, then f(x) has a maximum value when x = C. True False
Question 3: True
Question 4: False
Question 5: True
If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c.
This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.
Question 3: If f'(c) < 0 then f(x) is decreasing and the graph of f(x) is concave down when x = c.
True
When the derivative of a function, f'(x), is negative at a point c, it indicates that the function is decreasing at that point. Additionally, if the second derivative, f''(x), exists and is negative at x = c, it implies that the graph of f(x) is concave down at that point.
Question 4: A local extreme point of a polynomial function f(x) can only occur when f'(x) = 0.
False
A local extreme point of a polynomial function can occur when f'(x) = 0, but it is not the only condition. A local extreme point can also occur when f'(x) does not exist (such as at a sharp corner or cusp) or when f'(x) is undefined. Therefore, f'(x) being equal to zero is not the sole requirement for a local extreme point to exist.
Question 5: If f'(x) > 0 when x < c and f'(x) < 0 when x > c, then f(x) has a maximum value when x = c.
True
If the derivative of a function, f'(x), is positive for values of x less than c and negative for values of x greater than c, then it indicates a change in the slope of the function. This change from positive slope to negative slope suggests that the function has a maximum value at x = c. This is because the function is increasing before x = c and decreasing after x = c, indicating a peak or maximum at x = c.
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find the length of the curve y = x t3 − 1 dt 1 , 4 ≤ x ≤ 9.
The length of the curve y (x) = ₁∫ˣ √(t³ − 1) dt , 4 ≤ x ≤ 9, is 211/4.
In calculus, arc length of curve is the distance between two points along a portion of the curve. Finding the length of an irregular arc segment by approximating the arc segments as connected (straight) line segments is also known as the integral variation of the curve-corrected distance formula. Arc length formula is
ₐ∫ᵇ√[ 1 + (dy/dx)²] dx --(*)
Where, x is the arc length,
a, b are the integral bounds of the closed interval [a, b],dy/dx is the first derivative.We have calculate the length of curve means the length of arc of curve.
Now, y = y (x) = ₁∫ˣ √(t³ − 1) dt
differentiate both sides with respect to x
=> dy/dx= d/dx( ₁∫ˣ√(t³ − 1 ) dt)
Using the fundamental theorem of calculus,
=> dy/dx = dy/dt × dt/dx
let t = x => dt/dx = 1
dy/dt = √x³ - 1 ( from leibnitz rule )
dy/dx = √x³ - 1
Required length of curve = ₄∫⁹√[ 1 + (√x³ - 1)²] dx
= ₄∫⁹√[ 1 + x³ - 1] dx
= ₄∫⁹√x³ dx
\( = ₄∫⁹{x}^{ \frac{3}{2} } dx\)
\( = \frac{2}{5} ( {9}^{ \frac{5}{2} } - {4}^{ \frac{5}{2} } )\)
\(= 211/4\)
So, the required length is 211/4.
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Complete question:
Find out length of the curve
y (x) = ₁∫ˣ √(t³ − 1) dt , 4 ≤ x ≤ 9.
Andrea sells photographs at art fairs. She prices the photos according to size: small photos cost $10, medium photos cost $15, and large photos cost $40. She usually sells as many small photos as medium and large photos combined. She also sells twice as many medium photos as large. A booth at the art fair costs $300. If her sales go as usual, how many of each size photo must she sell to pay for the booth?
Answer: she must sell 6 large photos and 6 small photos
Step-by-step explanation: and how I knew that is I multiplied 6 40 times and that gives you 240 and if you multiply 6 ten times that gives you 60 so 240 plus 60 is $300
angelina drove at an average rate of 80 kph and then stopped 20 minutes for gas. after the stop, she drove at an average rate of 100 kph. altogether she drove 250 km in a total trip time of 3 hours including the stop. which equation could be used to solve for the time $t$ in hours that she drove before her stop?
Angelina drove for 0.83 hours (or approximately 50 minutes) before her stop.
The equation that could be used to solve for the time $t$ in hours that Angelina drove before her stop is:
$80t + 100(3 - t - \frac{1}{3}) = 250$
Let's break down the information given. Angelina drove at an average rate of 80 kph for a certain amount of time, which we want to find. After that, she stopped for 20 minutes (or $\frac{1}{3}$ of an hour) for gas. Then, she continued driving at an average rate of 100 kph. The total trip time, including the stop, was 3 hours.
To solve for the time Angelina drove before her stop, we can set up an equation based on the distance she traveled. The distance traveled at 80 kph is given by $80t$, where $t$ represents the time in hours. The distance traveled after the stop at 100 kph is $100(3 - t - \frac{1}{3})$, where $3 - t - \frac{1}{3}$ represents the remaining time after the stop.
The sum of these distances should equal the total distance traveled, which is 250 km. Therefore, we set up the equation $80t + 100(3 - t - \frac{1}{3}) = 250$.
By solving this equation, we can find the value of $t$, which represents the time in hours that Angelina drove before her stop.
To solve the equation, we can start by simplifying the expression on the right side:
$80t + 100(3 - t - \frac{1}{3}) = 250$
First, we can simplify the expression $3 - t - \frac{1}{3}$:
$3 - t - \frac{1}{3} = 2\frac{2}{3} - t = \frac{8}{3} - t$
Now, we substitute this expression back into the equation:
$80t + 100(\frac{8}{3} - t) = 250$
Next, we distribute the 100 to both terms inside the parentheses:
$80t + \frac{800}{3} - 100t = 250$
Combining like terms:
$-20t + \frac{800}{3} = 250$
To isolate the variable $t$, we can subtract $\frac{800}{3}$ from both sides:
$-20t = 250 - \frac{800}{3}$
To simplify the right side, we need a common denominator for 250 and $\frac{800}{3}$, which is 3:
$-20t = \frac{750}{3} - \frac{800}{3}$
Subtracting the fractions:
$-20t = \frac{-50}{3}$
Finally, we divide both sides by -20 to solve for $t$:
$t = \frac{\frac{-50}{3}}{-20} = \frac{50}{60} = \frac{5}{6}$
Therefore, Angelina drove for $\frac{5}{6}$ or 0.83 hours (or approximately 50 minutes) before her stop.
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a recent study concludes that you should drink coffee after breakfast in order to lose weight. researchers examined overweight adults who were dieting, and concluded that those who drank coffee after breakfast lost more weight, on average, than those who did not. which of the following is an example of a type i error? group of answer choices we conclude that there is no effect of drinking coffee when, in fact, there is an effect. we conclude that drinking coffee after breakfast leads to greater weight loss when in fact it does not. cannot be determined. we conclude that drinking coffee after breakfast leads to less weight loss when in fact it leads to greater weight loss.
The example of a Type I error in this case is: "We conclude that drinking coffee after breakfast leads to greater weight loss when in fact it does not."
What is Type I error?
A Type I error, also known as a false positive, occurs in statistical hypothesis testing when the null hypothesis (H₀) is incorrectly rejected, despite it being true in reality.
In hypothesis testing, a Type I error occurs when the null hypothesis (H₀) is incorrectly rejected when it is actually true. In this scenario, the null hypothesis would state that there is no effect of drinking coffee after breakfast on weight loss.
If the researchers conclude that drinking coffee after breakfast leads to greater weight loss, but in reality, there is no effect of coffee on weight loss, it would be a Type I error. This error implies that the researchers mistakenly concluded that there is a significant effect of the independent variable (drinking coffee after breakfast) on the dependent variable (weight loss), when there is no real effect present in the population being studied.
It is important to control the risk of Type I errors by selecting an appropriate significance level (alpha) and interpreting the results cautiously.
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Why do we square the residuals when using the least-squares line method to find the line of best fit?
We square the residuals when using the least-squares line method to find the line of best fit because we believe that huge negative residuals (i.e., points well below the line) are just as harmful as large positive residuals (i.e., points that are high above the line).
What do you mean by Residuals?We treat both positive and negative disparities equally by squaring the residual values. We cannot discover a single straight line that concurrently minimizes all residuals. The average (squared) residual value is instead minimized.
We might also take the absolute values of the residuals rather than squaring them. Positive disparities are viewed as just as harmful as negative ones under both strategies.
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find dx dt , dy dt , and dy dx . x = 6t3 3t, y = 5t − 4t2 dx dt = dy dt = dy dx =
So, the answers are: dx/dt = \(18t^2 + 3\), dy/dt = 5 - 8t, dy/dx = \((5 - 8t) / (18t^2 + 3)\)
To find dx/dt, we need to take the derivative of x with respect to t:
dx/dt = \(18t^2 + 3\)
To find dy/dt, we need to take the derivative of y with respect to t:
dy/dt = 5 - 8t
To find dy/dx, we can use the chain rule:
dy/dx = dy/dt / dx/dt
= (5 - 8t) / (18t^2 + 3)\((18t^2 + 3)\)
Hi! I'd be happy to help you with your question. Let's find dx/dt, dy/dt, and dy/dx using the given functions \(x = 6t^3 + 3t \\and \\y = 5t - 4t^2.\)
1. Find dx/dt: This is the derivative of x with respect to t.
Differentiate x = 6t^3 + 3t with respect to t:
dx/dt = \(d(6t^3 + 3t)/dt = 18t^2 + 3\)
2. Find dy/dt: This is the derivative of y with respect to t.
Differentiate y = 5t - 4t^2 with respect to t:
dy/dt = \(d(5t - 4t^2)/dt = 5 - 8t\)
3. Find dy/dx: This is the derivative of y with respect to x.
To find this, we can use the chain rule: dy/dx = (dy/dt) / (dx/dt)
Substitute the values we found for dy/dt and dx/dt:
dy/dx = \((5 - 8t) / (18t^2 + 3)\)
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factorise using the formula
Answer:
please find answer attached
Step-by-step explanation:
Given: AB is parallel to DC and E is the midpoint of AC.
Prove: ▲ABE ≅ ▲CDE
Therefore, the AAA test of congruency demonstrated that ABE is Congruence to CDE.
Congruent Definition ExampleSomething that is "exactly equal" in terms of size and shape is referred to as congruent. No matter which way we spin, flip, or rotate the shapes, they remain accurate. For instance, you may draw two circles with the same radius, cut them out, and stack them.
In this case, we are aware that AB ll DC - GIVEN
In light of the characteristic of parallel lines,
Let's recall the property of parallel lines:-
"When the pair of alternating angles equals one another, two straight lines become parallel."
Alternate angles are angle ABE and angle CDB.
angle BAE ≅ angle DCE -{alternate angles}
E is a midway, given that.
According to the midpoint theorem, opposite angles are congruent when angle AES and angle CED are compared.
Here, we may see the congruency test from AAA.
Hence its proved that ∆ABE ≅ ∆CDE by AAA test of congruency.
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A city has a population of 320,000 people suppose that each year the population grows by 5.25%. What will the population be after 11 years
The population after 11 years will be 56,181.
What will be the population after 11 years?The rate of increase of the population would be represented with an exponential equation.
An exponential equation can be described as an equation with exponents. The exponent is usually a variable.
The general form of exponential equation is f(x) = \(e^{x}\)
Where:
x = the variable e = constantPopulation after t years = \(p(1 + r)^{t}\)
Where:
p = present population r = rate of growth t = time= \(32,000(1 + 0.0525)^{11}\)
= \(32,000(1.0525)^{11}\)
= 56,181
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Select the correct answer. What is the solution to the equation? A. -3 B. 6 C. 7 D. 25
Answer:
The value of x is 7 if the equation can be reduced to (x + 9)³ = 4096 after applying the properties of the integer exponent option (C) 7 is correct.
What is an integer exponent?
In mathematics, integer exponents are exponents that should be integers. It may be a positive or negative number. In this situation, the positive integer exponents determine the number of times the base number should be multiplied by itself.
It is given that:
The equation is:
After solving:
(x + 9)³ = 4096
x + 9 = ∛4096
x + 9 = 16
x = 7
Thus, the value of x is 7 if the equation can be reduced to (x + 9)³ = 4096 after applying the properties of the integer exponent option (C) 7 is correct.
Isaiah volunteers on the weekend at the central library. as a school project, he decides to record how many people visit the library, and where they go. on saturday, 490 people went to the youth wing, 458 people went to social issues, and 329 went to fiction and literature.
on sunday, the library had 600 total visitors. based on what isaiah had recorded on saturday, about how many people should be expected to go to the youth wing? round your answer to the nearest whole number.
On Sunday, about one-third of the people should go to the youth wing, because 600 x 0.33 = 198. Round this number to the nearest whole number, which is 200.
How can probability be calculated?The likelihood that an event will take place is known as probability. In order to calculate the probability, divide the entire number of possible outcomes by the total number of ways the event might take place.
Why is probability relevant?Probability informs us about the likelihood of an event. By studying weather patterns, meteorologists can, for example, predict whether it will rain. In order to understand the relationship between exposures and the risk of health effects, epidemiology uses probability theory.
On Saturday, about one-third of the people went to the youth wing, because 490 / (490 + 458 + 329) = 0.33.
On Sunday, about one-third of the people should go to the youth wing, because 600 x 0.33 = 198. Round this number to the nearest whole number, which is 200.
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6th grade math help me pleaseeee
Answer:
No
Step-by-step explanation:
Because first you have to distribute so you will do
\(3 \times 4 = 12\)
\(3 \times x = 3x\)
Than You will combine 5x and 3x
\(5x + 3x = 8x\)
Last you will get
\(8x - 12\)
Help, needed ASAP Thank you!!
Answer:
∠S = 105°
∠T = 95°
Step-by-step explanation:
Cyclic quadrilateral:
Quadrilateral MNST is a cyclic quadrilateral. In cyclic quadrilateral, the opposite angles are supplementary.
m∠S + m∠M = 180°
3x + 2x + 5 = 180
5x + 5 = 180 {Combine like terms}
5x = 180 - 5 {Subtract 5 from both sides}
5x = 175
x = 175 ÷ 5 {Divide both sides by 5}
x = 35°
∠S = 3x
= 3 * 35
= 105°
∠T = 3x - 10
= (3*35) - 10
= 105 - 10
= 95°
Help pls with an explanation
The number of scooters sold in year 4 is 2240
What is word problem?A word problem is a math problem written out as a short story or scenario. This statement is actually interpreted into mathematical equation or expression.
The total scooter sold in the previous 3 years is ;
725+579+696 = 2000.
Therefore the store sold a total of 2000 scooters for 3 years.
In the 4th year they sold 112% of the total of the 3 years.
therefore the number of scooters sold in the 4th year can be calculated as;
112/100 × 2000
= 112 × 20
= 2,240
therefore 2240 scooters were sold in the 4th year.
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6. Select the number of solutions for each system of two linear equations.
Answer:
0 , 1 or infinitely many solutions
Step-by-step explanation:
Please help
Given m∠LMN=145 what is ∠XMN?
Answer:
(4x+5)°+(6x-10)°=145°
4x+6x+5-10=145°
10x-5=145°
10x=145+5
10x=150°
x=15
(6x-10)°=(6×15-10)°
=80°
The value of ∠XMN = 80.
What is angle?An angle is a figure in plane geometry that is created by two rays or lines that have a shared endpoint.
The value of total ∠LMN = 145.
∠LMN = ∠LMX +∠XMN
145 = (4x + 5) + (6x - 10)
145 = 4x + 5 + 6x - 10
145 = 10x -5
10x = 150
x = 15
Substitute the value of x in ∠XMN = (6x - 10)
∠XMN = 6×15 - 10
= 90 - 10
∠XMN = 80
Therefore, the value of the angle ∠XMN = 80.
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Carrie's head is full of curlers. There are 16 in all. One-fourth of the curlers are pink. There are many green curlers as pink ones. The rest are soda cans. How many cans are on Carrie's head?
Given:
Total number of curlers = 16
Pink Curlers = 1/4 of 16
Green Curlers = same with pink = 1/4 of 16
Soda Cans = 16 curlers minus pink and green curlers
To determine how many soda can curlers are in Carrie's head, let's determine first how many pink and green there are.
Since there are 1/4 of the curlers are pink, let's determine how many curlers exactly are pink by multiplying 1/4 to 16.
\(\frac{1}{4}\times16=\frac{16}{4}=4\)Therefore, there are 4 pink curlers. Similarly, there are also 4 green curlers since it is stated in the problem that they have the same count.
So, 16 curlers minus 4 pink and 4 green curlers, there are 8 soda cans curlers in Carrie's head.
Kayla was asked to rewrite the polynomial expression x ^ 2 + 5x + 9 she rewrite the polynomial ? How could she rewrite with the polynomial?
Answer:
x²+6x+9
x²+3x+3x+9
x(x+3)+3(x+3)
=(x+3)(x+3)
problem 5. show that the number of different ways to write an integer n as the sum of two squares is the same as the number of ways to write 2n as a sum of two squares.
The number of ways to write n as a sum of two squares is equal to the number of ways to write 2n as a sum of two squares.
To show that the number of different ways to write an integer n as the sum of two squares is the same as the number of ways to write 2n as a sum of two squares, we can use the following identity: (a² + b²)(c² + d²) = (ac + bd)² + (ad - bc)².
Suppose we have two integers, x, and y, such that x² + y² = n. We can use this identity to express 2n as a sum of two squares as follows:
(2x)² + (2y)² = 4(x² + y²) = 2n
Conversely, if we have two integers, a and b, such that a² + b² = 2n, we can express n as a sum of two squares as follows:
(a² + b²)/2 + ((a² + b²)/2 - b²) = (a² + b²)/2 + (a²/2 - b²/2) = (a² + 2b²)/2 = n
Therefore, the number of ways to write n as a sum of two squares is equal to the number of ways to write 2n as a sum of two squares.
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Laboratory tests show that the lives of
light bulbs are normally distributed with
a mean of 750 hours and a standard
deviation of 75 hours. Find the
probability that a randomly selected
light bulb will last between 750 and 825
hours.
Answer in percentage!!!
This result is approximate.
=========================================================
Explanation:
mu = 750 = mean
sigma = 75 = standard deviation
The raw scores or x values are x = 750 and x = 825
Let's compute the z score for each x value
z = (x - mu)/sigma
z = (750 - 750)/75
z = 0
and
z = (x - mu)/sigma
z = (825 - 750)/75
z = 1
Therefore P(750 ≤ x ≤ 825) is equivalent to P(0 ≤ z ≤ 1) in this context.
Use a z score table to determine that
P(z ≤ 0) = 0.5
P(z ≤ 1) = 0.84314 approximately
So,
P(a ≤ z ≤ b) = P(z ≤ b) - P(z ≤ a)
P(0 ≤ z ≤ 1) = P(z ≤ 1) - P(z ≤ 0)
P(0 ≤ z ≤ 1) = 0.84314 - 0.5
P(0 ≤ z ≤ 1) = 0.34314 approximately
The value 0.34314 then converts to 34.314% which rounds to 34%
Or you could use the empirical rule as shown below. The pink section on the right is marked 34% which is approximate. This pink section is between z = 0 and z = 1.
solve the given boundary-value problem. (if an answer does not exist, enter dne.) y'' − 2y' 2y = 0, y(0) = 7, y() = 7
The solution of the given boundary-value problem y'' − 2y' + 2y = 0 is y = e^(1x)(7*cos(x) + ((7 - 7*cos())/e^(1())*sin())*sin(x))
This can be done by finding the characteristic equation and solving for the roots. The characteristic equation for this differential equation is r^2 − 2r + 2 = 0. Using the quadratic formula, we can find the roots of this equation:
r = (2 ± √(2^2 - 4(1)(2)))/(2(1))
r = (2 ± √(-4))/2
r = (2 ± 2i)/2
r = 1 ± i
Therefore, the general solution of the differential equation is:
y = e^(1x)(C1*cos(x) + C2*sin(x))
Now we can use the boundary conditions to find the values of C1 and C2. The first boundary condition is y(0) = 7. Plugging this into the general solution gives us:
7 = e^(1(0))(C1*cos(0) + C2*sin(0))
7 = C1
The second boundary condition is y() = 7.
7 = e^(1())(C1*cos() + C2*sin())
7 = e^(1())(C1*cos() + C2*sin())
Solving this equation for C2 gives us:
C2 = (7 - C1*cos())/e^(1())*sin()
C2 = (7 - 7*cos())/e^(1())*sin()
Therefore, the solution to the boundary-value problem is:
y = e^(1x)(7*cos(x) + ((7 - 7*cos())/e^(1())*sin())*sin(x))
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Please help!! BRAINLIEST to correct answer!!
Answer:
Let us use Pythagoras theorem Hence \( {4}^{2} + {b}^{2} = {10}^{2} \)\(16 + {b}^{2} = 100\)\( {b}^{2} = 84\)\(b = \sqrt{84} \)\(b = 9.16\)So Option AThe PlentyofFish dating site company is designing a marketing campaign with the objective of reducing the purchase risk of its dating service in the customer's mind. PlentyofFish is offering a limited free 30-day trial to test out the site. Which stage has the smallest percentage of prospects associated with the AIDA model is PlentyofFish implementing for its campaign ?
The stage that has the smallest percentage of prospects associated with the AIDA model is PlentyofFish implementing for its campaign is the action stage.
What is the AIDA Model?The AIDA Model (Attention, Interest, Desire, and Action) is an advertising effect model that identifies the stages that an individual goes through when purchasing a product or service.
The AIDA model is one of several models known as hierarchy of effects models or hierarchical models, all of which imply that when making a purchase decision, consumers go through a series of steps or stages.
An AIDA model entails the following steps:
Attention: The first step in marketing or advertising is to think about how to get consumers' attention.
Interest: Once a consumer is aware that a product or service exists, the company must work to increase the potential customer's level of interest.
Desire: Once the consumer is interested in the product or service, the goal is to make them want it.
Action: The ultimate goal of a marketing campaign is to motivate the recipient to take action and buy the product or service.
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