find the value of each variables in the parallelogram

Answer:

3^8

Step-by-step explanation:

Answer: A, C and E.

Step-by-step explanation: They all equal to 5.

The probability of getting heads each time is 1/16, and the probability of getting the same outcome (either heads or tails) each time is 1/8.

We know that the probability of getting a head or a tail when flipping a fair coin is 1/2. Let us use this fact to answer the given questions. The probability it will land the same way each time:

The probability of getting heads each time is (1/2) × (1/2) × (1/2) × (1/2) = 1/16.

The probability of getting tails each time is also 1/16.

Therefore, the probability of getting the same outcome (either heads or tails) each time is (1/16) + (1/16) = 1/8.

The probability of getting heads each time is lower than the probability of getting tails each time. This is because there are more ways to get tails each time than to get heads each time. For example, if we flip the coin four times, we can get heads-tails-heads-tails or tails-heads-tails-heads, but we cannot get heads-heads-heads-heads and tails-tails-tails-tails at the same time.

Therefore, the probability of getting heads each time is 1/16, and the probability of getting the same outcome (either heads or tails) each time is 1/8.

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Stu had quite a collection of baseball cards. One day he decided to give half of them to his brother Seth. Then he gave one-third of what he had left to a friend. Then he gave half of what was left to another friend. Stu now has 50 baseball cards. How many did he start with? It seems that I should work

let Stu have x cards

he gave half to seth

so he had x/2 cards

He had x/2 he gave 1/3 of x/2 to a friend

=x/6.

Now he had x/2 - x/6 = x/3 with him balance

1/2 of x/3 he gave to another friend =x/6

Balance he had was x/3 - x/6 = x/6

x/6 = 50

multiply by 6

x= 300

Answer:

Now he had x/2 - x/6 = x/3 with him balance

1/2 of x/3 he gave to another friend =x/6

Balance he had was x/3 - x/6 = x/6

x/6 = 50

multiply by 6

x= 300

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

125 x .08 = 10

Step-by-step explanation:

(a) To find the position of the car when it has zero velocity, we need to find the times at which the velocity, x'(t), is equal to zero. The velocity of the car is given by:

x'(t) = (4.85m/s^2)t^2 - (0.100m/s^6)t^6

Setting x'(t) equal to zero and solving for t, we find:

0 = (4.85m/s^2)t^2 - (0.100m/s^6)t^6

t^2 = (0.100m/s^6)t^6 / (4.85m/s^2)

We can't solve for t analytically, but we can use numerical methods to find approximate values for the two times at which the velocity is equal to zero.

The first instant is approximately t = 0.68 s and the second instant is approximately t = 2.28 s.

Using these values for t, we can find the positions of the car at these instants:

x(0.68s) = 2.31m + (4.85m/s^2)(0.68s)^2 - (0.100m/s^6)(0.68s)^6

x(2.28s) = 2.31m + (4.85m/s^2)(2.28s)^2 - (0.100m/s^6)(2.28s)^6

(b) The acceleration of the car is given by the derivative of its velocity, x'(t):

x''(t) = 2(4.85m/s^2)t - 6(0.100m/s^6)t^5

Using the values of t from part (a), we can find the acceleration of the car at the instants when it has zero velocity:

x''(0.68s) = 2(4.85m/s^2)(0.68s) - 6(0.100m/s^6)(0.68s)^5

x''(2.28s) = 2(4.85m/s^2)(2.28s) - 6(0.100m/s^6)(2.28s)^5

410/5 = ?

410/5 = 82

82 miles per hour

82*12 = ?

82*12 = 984

Answer: 984 miles in 12 hours

False. The quantity consumed in a base period is not an example of a weight used in the calculation of a weighted index.

In the calculation of a weighted index, a weight is a factor used to assign relative importance or significance to different components or categories included in the index. These weights reflect the contribution of each component to the overall index value. The purpose of assigning weights is to ensure that the index accurately reflects the relative importance of the components or categories being measured.

An example of a weight used in a weighted index could be market value, where the weight is determined based on the market capitalization of each component. This means that components with higher market values will have a greater weight in the index calculation, reflecting their larger impact on the overall index value.

On the other hand, the quantity consumed in a base period is not typically used as a weight in a weighted index. Instead, it is often used as a reference point or benchmark for comparison. For example, in a price index, the quantity consumed in a base period is used as a constant quantity against which the current prices are compared to measure price changes.

Therefore, the statement that the quantity consumed in a base period is an example of a weight used in the calculation of a weighted index is false.

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Answer: 6 seconds

Step-by-step explanation:

Time            Jabal (2.5mps)            Michael (5mps)

Start              15                                   0

1 sec              17.50                              5

2                    20                                  10

3                    22.5                               15

4                    25                                  20

5                    27.5                               25

6                    30                                  30

7

8

9

10

Answer:

6 sec

Step-by-step explanation:

Let d = distance for Jabal

d + 15 = distance for Michael

t = d/r

d/2.5 = time for Jabal

(d + 15)/5 = time for Michael

The times are equal since they both started walking at the same time.

(d + 15/5 = d/2.5

2.5(d + 15) = 5d

2.5d + 37.5 = 5d

37.5 = 2.5d

d = 15 m. = Jabal's distance

15/2.5 = 6 sec.

By using Python, you will come up with your own challenging algorithm for other students to trace.

If a certain is true, the if/else expression triggers a sequence of instructions to run. Another piece of code may be run if the condition is false.

The if/else statement is a component of Python's "Conditional" Statements, which are used to carry out various operations based on various circumstances.

These conditional statements are available in Python:

If you want a block of code to run only if a certain condition is true, use the if statement.

If the same expression is false, use instead that to provide a set of instructions that should be run.

If the first expression is false, can use else if sentence to establish a comprehensive criterion to test.

To choose which of the several program code should be performed, use the switch.

How to write the code?

num = 100

if num < 20:

print('Less than 20')

if num < 30:

print('Less than 30')

if num < 40:

print('Less than 40')

if num < 50:

print('Less than 50')

if num > 100 or num == 100:

print('More than or equal to 100')

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The probability of a player weighing less than 250 pounds is approximately 0.9772.

Answer: a. 0.9772

We can use the normal distribution to find the probability of a football player weighing less than 250 pounds.

First, we need to calculate the z-score of 250, using the formula:

\(z = (x - μ) / σ\)

where x is the weight of interest, μ is the mean weight, and σ is the standard deviation.

Plugging in the values, we get:

\(z = (250 - 200) / 25 = 2\)

Using a standard normal distribution table or calculator, we can find the probability that a standard normal random variable is less than 2. This probability is approximately 0.9772.

Since the weight of football players is normally distributed with mean 200 pounds and standard deviation 25 pounds, we can use the standard normal distribution to find the probability of a player weighing less than 250 pounds.

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Answer:

Domain: [-2, 0, 2, 4]

Range: [3]

Step-by-step explanation:

The domain of the function are all values of x that are plotted on the horizontal axis (x-axis), while the range are the corresponding y-values plotted on the vertical axis (y-axis).

Therefore,

Domain of the function = [-2, 0, 2, 4]

Range of the function = [3] (only 1 possible value of y can be seen as plotted on the gray]

The simplification of the expression 4a + 3b - a + 3b + 6 is 3(a + 2b + 2)

Simplify 4a + 3b - a + 3b + 6

collect like terms

= 4a - a + 3b + 3b + 6

= 3a + 6b + 6

factorize

= 3(a + 2b + 2)

side a = 3x - 5

side b = 2x - 1

side c = x + 1

Perimeter = 31 cm

The perimeter of a triangle = side a + side b + side c

31 = (3x - 5) + (2x - 1) + (x + 1)

31 = 3x - 5 + 2x - 1 + x + 1

31 = 6x - 5

Add 5 to both sides

31 + 5 = 6x

36 = 6x

divide both sides by 6

x = 36/6

x = 6

Therefore, the value of x from the perimeter of the triangle is 6

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Both f(t) and g(t) are of exponential order.

To show that a function f(t) is of exponential order, we need to find positive constants M and k such that:

|f(t)| <= M * e^(k*t) for all t >= t0, where t0 is some arbitrary constant.

Let's start by considering f(t) = t³ * sin(t). We can use the fact that |sin(t)| <= 1 to obtain an upper bound for f(t):

|f(t)| = |t³ * sin(t)| <= t³ for all t

Now we need to find k such that t³ <= M * e^(k*t) for all t >= t0. Taking logarithms of both sides yields:

ln(t³) <= ln(M * e^(kt)) = ln(M) + kt

Simplifying the left-hand side:

3 ln(t) <= ln(M) + k*t

Now we can choose M = 1 and k = 1 to obtain:

3 ln(t) <= ln(1) + t

3 ln(t) <= t

This inequality holds for all t >= 1, so we have shown that f(t) is of exponential order with M = 1 and k = 1.

Next, consider g(t) = t² * e^t. We can once again obtain an upper bound using the fact that e^t >= 1:

|g(t)| = |t² * e^t| <= t² * e^t for all t

To find M and k such that t² * e^t <= M * e^(k*t) for all t >= t0, we can again take logarithms of both sides:

ln(t² * e^t) <= ln(M * e^(kt)) = ln(M) + kt

Simplifying the left-hand side:

2 ln(t) + t <= ln(M) + k*t

Now we can choose M = 1 and k = 2 to obtain:

2 ln(t) + t <= ln(1) + 2t

2 ln(t) + t <= 2t

This inequality holds for all t >= 1, so we have shown that g(t) is of exponential order with M = 1 and k = 2.

Therefore, both f(t) and g(t) are of exponential order.

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The answer is d. 18. There are a total of 18 choices of passageways for entering the classroom.

To determine the number of choices of passageways, we need to consider the options at each step. From the ground floor to the second floor, there are 3 staircases, so we have 3 choices. From the second floor to the third floor, there are also 3 staircases, giving us another 3 choices. Now, for each classroom on the third floor, there are 2 doors, so we have 2 choices for each classroom. Since there are a total of 6 classrooms (assuming one classroom per staircase), we multiply the number of choices per classroom by the number of classrooms, which gives us 2 * 6 = 12 choices. Finally, we add up the choices from each step: 3 + 3 + 12 = 18. Therefore, there are 18 choices of passageways in entering the classroom.

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Given information:Position of a particle moving along the x-axis varies in time according to the expression x = 3t², where x is in meters and t is in seconds.

To determine the position at the following times. a. t = 3.30 s, b. t = 3.30 s + Δt xf and c. Evaluate the limit of Δx/Δt as Δt approaches zero to find the velocity at t = 3.30 s. a. To find the position when t = 3.30 s, substitute t = 3.30 s in x = 3t².x = 3t² = 3(3.30)² = 32.67 metersTherefore, the position at t = 3.30 s is 32.67 meters.

b. To find the position when t = 3.30 s + Δt, substitute t = 3.30 s + Δt in x = 3t².x = 3t² = 3(3.30 s + Δt)² = 3(10.89 + 6.6Δt + Δt²) = 32.67 + 19.8Δt + 3Δt²Therefore, the position when t = 3.30 s + Δt is 32.67 + 19.8Δt + 3Δt².c. Velocity is given by Δx/Δt.Δx/Δt = [x(t + Δt) - x(t)]/ΔtBy substituting the given values, we have;Δx/Δt = [x(3.30 + Δt) - x(3.30)]/Δt= [3(3.30 + Δt)² - 3(3.30)²]/Δt= 19.8 + 6ΔtTaking the limit of Δx/Δt as Δt → 0, we have;Δx/Δt = 19.8 + 6(0)Δt = 19.8Therefore, the velocity at t = 3.30 s is 19.8 m/s.

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Answer: C. The y-intercept is 13 spaces lower.

Step-by-step explanation:

B irrational numbers true or false

Answer:

54

Step-by-step explanation:

We are asked to evaluate the triple integral ∫∫∫ Q √(y² + z²) dV, where Q represents the solid region inside the cylinder y² + z² = 16 and between the planes x = 0 and x = 3.

To evaluate the given triple integral, we will use cylindrical coordinates. In cylindrical coordinates, we have x = x, y = r sinθ, and z = r cosθ, where r represents the radial distance, θ represents the angle in the yz-plane, and x represents the height.

First, we determine the limits of integration. Since the region lies inside the cylinder y² + z² = 16, the radial distance r ranges from 0 to 4. The angle θ can range from 0 to 2π to cover the entire yz-plane. For x, it ranges from 0 to 3 as specified by the planes.

Next, we need to convert the volume element dV from Cartesian coordinates to cylindrical coordinates. The volume element dV in Cartesian coordinates is dV = dx dy dz. Using the transformations dx = dx, dy = r dr dθ, and dz = r dr dθ, we can express dV in cylindrical coordinates as dV = r dx dr dθ.

Now, we set up the integral:

∫∫∫ Q √(y² + z²) dV = ∫₀³ ∫₀²π ∫₀⁴ r √(r² sin²θ + r² cos²θ) dx dr dθ

Simplifying the integrand, we have:

∫∫∫ Q r √(r²(sin²θ + cos²θ)) dx dr dθ

= ∫₀³ ∫₀²π ∫₀⁴ r² dx dr dθ

Evaluating the integral, we have:

∫∫∫ Q r² dx dr dθ = ∫₀³ ∫₀²π ∫₀⁴ r² dx dr dθ

Integrating over the given limits, we obtain the value of the integral.

To evaluate the integral ∫∫∫ Q √(y² + z²) dV, we converted it to cylindrical coordinates and obtained the integral ∫₀³ ∫₀²π ∫₀⁴ r² dx dr dθ. Evaluating this integral will yield the final result.

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Participants in a study on the effects of viagra are assigned to groups, the independent variable is The viagra.

In an algebraic equation, an independent variable is a variable whose values are not impacted by changes. It is claimed that the value of y is a function of the value of the independent variable (x), also known as the x value, and the value of y is known as the dependent variable, in an algebraic equation with two variables (x and y), if any value of x is related to any other value of y.

The alphabetic letter that conveys a numerical value or a number is known as a variable in mathematics. In algebraic equations, a variable is used to represent an unknowable quantity.

For these variables, any alphabet from a to z may be used. Most frequently, the variables "a," "b," "c," "x," "y," and "z" are utilised in equations.

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Let x be the number of cans of food, since we need more than or equal to 2000 cans, we can write

where 668 is the number of cans that they have been collected.

Now, we must find x. If we move 668 to the right hand side as -668, we get

which gives

this means that they must collect more than or equalt to 1332 cans of food.

Answer: (2x+6y)^2 = (2x+6y)(2x+6y) = 4x^2 +12xy + 12yx + 36y^2 = 4x^2 + 24xy + 36y^2

So the result of (2x+6y)^2 is 4x^2 + 24xy + 36y^2

d) Tthe probability that there is a moving object given that both sensors detect motion is approximately 0.98.

(a) To find the probability that sensor L detects motion given that there is movement outside and sensor V does not detect motion, we can use Bayes' theorem.

Let's denote the events as follows:

A = Movement outside

B = Sensor V does not detect motion

C = Sensor L detects motion

We are given:

P(A) = 0.7 (probability of movement outside)

P(B|A) = 0.05 (probability of sensor V not detecting motion given movement outside)

P(C|A) = 0.8 (probability of sensor L detecting motion given movement outside)

We want to find P(C|A', B), where A' denotes the complement of event A.

Using Bayes' theorem:

P(C|A', B) = [P(A' | C, B) * P(C | B)] / P(A' | B)

We can calculate the values required:

P(A' | C, B) = 1 - P(A | C, B) = 1 - P(A ∩ C | B) / P(C | B) = 1 - [P(A ∩ C ∩ B) / P(C | B)]

             = 1 - [P(B | A ∩ C) * P(A ∩ C) / P(C | B)]

             = 1 - [P(B | C) * P(A) * P(C | A) / P(C | B)]

             = 1 - [P(B | C) * P(A) * P(C | A) / [P(B | C) * P(A) * P(C | A) + P(B | C') * P(A') * P(C | A')]]

P(B | C) = 0 (since sensor V does not detect motion when there is motion outside)

P(C | A') = 0 (since sensor L does not detect motion when there is no motion outside)

Substituting these values:

P(C | A', B) = 1 - [0 * P(A) * P(C | A) / (0 * P(A) * P(C | A) + P(B | C') * P(A') * P(C | A'))]

             = 1 - [0 / (0 + P(B | C') * P(A') * P(C | A'))]

             = 1 - 0

             = 1

Therefore, the probability that sensor L detects motion given that there is movement outside and sensor V does not detect motion is 1.

(b) To find the probability that the home security system alerts the police given that there is a moving object, we need to consider the different combinations of sensor detections.

Let's denote the events as follows:

D = The home security system alerts the police

M = There is a moving object

We need to calculate P(D | M). This can occur in two ways:

1. Both sensor V and sensor L detect motion.

2. Sensor L detects motion while sensor V does not.

Using the law of total probability:

P(D | M) = P(D, V detects motion, L detects motion | M) + P(D, V does not detect motion, L detects motion | M)

We know:

P(D, V detects motion, L detects motion | M) = P(V detects motion | M) * P(L detects motion | M) = 0.95 * 0.8 = 0.76

P(D, V does not detect motion, L detects motion | M) = P(V does not detect motion | M) * P(L detects motion | M) = (1 - 0.95) * 0.8 = 0.04

Substituting

these values:

P(D | M) = 0.76 + 0.04

        = 0.8

Therefore, the probability that the home security system alerts the police given that there is a moving object is 0.8.

(c) To find the probability of a false alarm, i.e., that there is no movement but the police are alerted anyway, we need to consider the different combinations of sensor detections.

Let's denote the events as follows:

D = The home security system alerts the police

NM = There is no movement

We need to calculate P(D | NM). This can occur in two ways:

1. Both sensor V and sensor L detect motion.

2. Sensor L detects motion while sensor V does not.

Using the law of total probability:

P(D | NM) = P(D, V detects motion, L detects motion | NM) + P(D, V does not detect motion, L detects motion | NM)

We know:

P(D, V detects motion, L detects motion | NM) = P(V detects motion | NM) * P(L detects motion | NM) = 0.1 * 0.05 = 0.005

P(D, V does not detect motion, L detects motion | NM) = P(V does not detect motion | NM) * P(L detects motion | NM) = (1 - 0.1) * 0.05 = 0.045

Substituting these values:

P(D | NM) = 0.005 + 0.045

         = 0.05

Therefore, the probability of a false alarm, i.e., that there is no movement but the police are alerted anyway, is 0.05.

(d) To find the probability that there is a moving object given that both sensors detect motion, we can use Bayes' theorem.

Let's denote the events as follows:

M = There is a moving object

V = Sensor V detects motion

L = Sensor L detects motion

We want to find P(M | V, L).

Using Bayes' theorem:

P(M | V, L) = [P(V, L | M) * P(M)] / [P(V, L)]

We can calculate the values required:

P(V, L | M) = P(V | M) * P(L | M) = 0.95 * 0.8 = 0.76

P(M) = 0.7 (given probability of movement)

P(V, L) = P(V, L | M) * P(M) + P(V, L | M') * P(M')

        = 0.76 * 0.7 + 0.04 * 0.3

        = 0.532 + 0.012

        = 0.544

Substituting these values:

P(M | V, L) = (0.76 * 0.7) / 0.544

           ≈ 0.98

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The sign | | is used to refer to the absolute value of an expression or integer.

Given an integer x

The absolute sign will always return a positive value.

Therefore, the absolute value of 2 is 2.

The correct option is B.

Answer:

true

Step-by-step explanation:

Answer:

11⁹

Step-by-step explanation:

simplifying the question

Answer:

The answer is attached.

See attachment for the graph of the function g(x)=log4(x-1)+2

The equation of the logarithmic function is given as

g(x)=log4(x-1)+2

The parent function of the above logarithmic function is

f(x) = log4(x)

This means that the parent function is translated right by 1 unit and translated up by 2 units

Next, we plot the graph of the function g(x)=log4(x-1)+2

See attachment for the graph of the function g(x)=log4(x-1)+2

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