Therefore, the transition matrix from b to b' is:
[ -2 -3 4 2 ]
[ 3 3 -4 -2 ]
[ -1 -1 2 1 ]
[ -2 -2 5 3 ]
To find the transition matrix from basis b to b', we need to express each vector in b' as a linear combination of the vectors in b, and put the coefficients as columns in the matrix.
We have:
(-2, 3, -1, -2) = a1(1, 0, 0, 0) + a2(0, 1, 0, 0) + a3(0, 0, 1, 0) + a4(0, 0, 0, 1)
= a1(1, 0, 0, 0) + a2(0, 1, 0, 0) + a3(0, 0, 1, 0) + a4(0, 0, 0, 1)
Solving this system, we get a1 = -2, a2 = 3, a3 = -1, and a4 = -2.
Similarly, we can express the other three vectors in b' as linear combinations of the vectors in b:
(-3, 3, -1, -2) = -3(1, 0, 0, 0) + 3(0, 1, 0, 0) - (1, 0, 0, 0) - 2(0, 0, 0, 1)
(2, -2, 1, 2) = 4(1, 0, 0, 0) - 4(0, 1, 0, 0) + 2(0, 0, 1, 0) + 5(0, 0, 0, 1)
(4, -4, 2, 5) = 2(1, 0, 0, 0) - 2(0, 1, 0, 0) + 1(0, 0, 1, 0) + 3(0, 0, 0, 1)
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HELP I NEED HELP ASAP
(-4,6), slope=-1
Write the slope-intercept equation using the given information.
Answer:
y = -x +2
Step-by-step explanation:
y = mx + b
y=6
x=-4
m=-1 (m is the slope)
b=? (b is the y-intercept)
Putting these numbers into this equation,
6 = -1(-4) + b
b=6-4
b=2
So the equation is y = -1x + 2
or just y = -x +2
Test the claim that there is strong correlation between a person daily income and how many hours they excercise, daily income | hrs of exercise per week
142 13 398 39 175 17
191 18 368 36 205 20
225 23 384 38 273 26 255 26
266 27 288 29 306 30 310 30 161 15 321 31 215 32 321 33
181 17
344 35 242 25
The correlation coefficient is negative, indicating a negative correlation between daily income and hours of exercise.
Therefore, we do not have sufficient evidence to support the claim that there is a strong correlation between a person's daily income and how many hours they exercise.
To test the claim that there is a strong correlation between a person's daily income and how many hours they exercise, we can use the Pearson correlation coefficient (r).
The null hypothesis is that there is no correlation (r = 0), and the alternative hypothesis is that there is a correlation (r ≠ 0).
To calculate the correlation coefficient, we first need to find the means and standard deviations of both variables, income and hours of exercise:
mean income = (142 + 398 + 175 + ... + 242)/20 ≈ 246.85
mean hours = (13 + 39 + 17 + ... + 25)/20 ≈ 26.4
standard deviation of income: \(s_{income}\) = 80.76
standard deviation of hours: \(s_{hours}\) = 7.65
Using these values, we can now find the correlation coefficient:
r = ∑[(income - mean income)/\(s_{income}\)][(hours - mean hours)/\(s_{hours}\)] / (n - 1),
where n is the number of pairs of data.
Plugging in the values, we get:
r = [(142-246.85)/80.76 × (13-26.4)/7.65] + [(398-246.85)/80.76 × (39-26.4)/7.65] + ... + [(242-246.85)/80.76 × (25-26.4)/7.65] / (20-1)r
≈ -0.3308
However, the value is only -0.3308, which falls within the range of weak negative correlation.
We can interpret the correlation coefficient as follows:
-1 ≤ r ≤ -0.7: strong negative correlation
-0.7 < r ≤ -0.3: moderate negative correlation
-0.3 < r ≤ -0.1: weak negative correlation
-0.1 < r ≤ 0.1: no correlation
0.1 < r ≤ 0.3: weak positive correlation
0.3 < r ≤ 0.7: moderate positive correlation
0.7 < r ≤ 1: strong positive correlation
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the value of a certain stock increased by 1 and (1/4)%. Explain how to write 1 1/4 percent as a fraction in simplest form
Answer
1.25% expressed in fractions is (1/80).
Explanation
We need to express
\(1\frac{1}{4}\text{ percent in fractions}\)1 (1/4)% = 1.25%
1.25% = (1.25/100)
\(\begin{gathered} \frac{1.25}{100} \\ \text{Multiply numerator and denominator by 100} \\ \frac{1.25}{100}=\frac{125}{10000} \\ \text{Divide numerator and denominator by 125} \\ \frac{125}{10000}=\frac{1}{80} \end{gathered}\)Hence, 1.25% expressed in fractions is (1/80).
Hope this Helps!!!
An Olympic-sized pool currently has 415,800 gallons in it, which is 63% full. How much water does the pool hold?
Answer:
The pool holds 660,000 gallons of water.
Step-by-step explanation:
63/100 = 415,800/x
cross multiply so 415,000 * 100 = 41,500,000
41,500,000 / 63 = 660,000
What are the real and complex solutions of the polynomial equation? x 4 – 41 x 2 = – 400 please show work and how you got then answer
All four zeros are real solutions in the polynomial equation.
What are polynomials in equations?
A polynomial is an expression that consists of one or more variables, coefficients, and non-negative integer exponents of the variables. An equation is a mathematical statement with an equal sign between two algebraic expressions with equal values.
x⁴ – 41 x² = – 400
Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get
x⁴ - 41x² + 400 = -400 + 400
x⁴ - 41x² + 400 = 0
Factoring by product sum rule.
We need product of 400 and sum upto -41.
We can see that 400 = -25 × -16 = 400 and -25-16 = -41.
Therefore,
x⁴ - 25x² - 16x² + 400 = 0
Making it into two groups, we get
(x⁴ - 25x²) + (-16x² + 400) = 0
Factoring out GCF of each group, we get
x²(x² - 25) (x² - 16) = 0
(x² - 25) = x² - 5² = (x - 5) (x + 5)
x² - 16 = x² - 4² = (x - 4)(x + 4)
(x - 5) (x + 5) (x - 4)(x + 4) = 0
Applying zero product rule,
x-5=0
x+5=0
x-4=0 and
x+4=0.
Therefore,
x = -5, -4, 4 and 5.
All four zeros are real solutions.
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solve the initial value problem dy/dx = (x - 4)(y - 5), y(0) = 7.
The solution to the initial value problem dy/dx = (x - 4)(y - 5) with the initial condition y(0) = 7 is y = e^((1/2)x^2 - 4x + ln(2)) + 5.
To solve the initial value problem dy/dx = (x - 4)(y - 5) with the initial condition y(0) = 7, we can separate the variables and integrate.
First, let's rewrite the differential equation as:
1 / (y - 5) dy = (x - 4) dx.
Now, we integrate both sides with respect to their respective variables:
∫(1 / (y - 5)) dy = ∫(x - 4) dx.
Integrating the left side with respect to y gives:
ln|y - 5| = ∫(x - 4) dx = (1/2)x^2 - 4x + C1,
where C1 is the constant of integration.
To simplify, we can exponentiate both sides:
|y - 5| = e^((1/2)x^2 - 4x + C1).
Next, we consider the absolute value. Since we have an initial condition y(0) = 7, we know that y - 5 is positive when x = 0. Therefore, we can remove the absolute value sign:
y - 5 = e^((1/2)x^2 - 4x + C1).
Now, we solve for y:
y = e^((1/2)x^2 - 4x + C1) + 5.
To determine the constant of integration C1, we substitute the initial condition y(0) = 7 into the equation:
7 = e^((1/2)(0)^2 - 4(0) + C1) + 5.
Simplifying, we find:
7 = e^(C1) + 5.
e^(C1) = 7 - 5 = 2.
Taking the natural logarithm of both sides, we get:
C1 = ln(2).
Finally, we substitute the value of C1 back into the equation to obtain the solution to the initial value problem:
y = e^((1/2)x^2 - 4x + ln(2)) + 5.
Therefore, the solution to the initial value problem is y = e^((1/2)x^2 - 4x + ln(2)) + 5.
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Find the 10th term of the geometric sequence 3,15,75
Answer:
5,859,375
Step-by-step explanation:
pattern is x * 5
3, 15, 75, 375, 1875, 9375, 46875. 234375, 1171875, 5859375
\(10^{th}\) term of the geometric sequence is \(\boldsymbol{5859375}\).
Geometric SequenceA geometric progression, also known as a geometric sequence, is a non-zero numerical sequence in which each term after the first is determined by multiplying the preceding one by a fixed, non-zero value known as the common ratio.
Given geometric sequence is \(\boldsymbol{3,15,75}\)
Ratio is \(r=\frac{15}{3}\) that is \(\boldsymbol{r=5}\).
\(n^{th}\) term of a geometric sequence is given by \(\boldsymbol{ar^{n-1}}\) where \(\boldsymbol{a}\) is the first term.
So,
\(10^{th}\) term of the geometric sequence \(=(3)(5)^{10-1}\)
\(=(3)(5)^{9}\\=\boldsymbol{5859375}\)
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Ive already given away 20 points so this time ill give away 100 points in the same day and guess what i dont care if you report HAVE A NICE DAY
Answer:
y
Step-by-step explanation:
Answer I think you didn't care about the bad days
Step-by-step explanation:Have a nice day, thanks for the points
In a social club, the ratio of men to women is 5: 7. There are 595 women. How
many men are there?
Answer:
52
you take 5 ÷ it by 7 the ×it by 595
A ratio is an ordered pair of numbers a and b written as a/b where b is not equal to zero.
if the number of women in the social club is 595 then the number of men in the social club is 425.
What are ratios and proportions?A ratio is an ordered pair of numbers a and b written as:
a / b where b does not equal 0.
A proportion is an equation in which two ratios are equal to each other.
We have,
The ratio of men to women:
= 5:7
= 5/7
Let,
The number of men = 5x
The number of women = 7x
Now,
If the number of women = 595
We have,
7x = 595
Multiplying both sides by 5/7 we get,
5/7 x (7x) = 5/7 x 595
5x = 5/7 x 595
5x = 5 x 85
5x = 425
This means if there are 435 men in the social club if the number of women is 595.
Thus if the number of women in the social club is 595 then the number of men in the social club is 425.
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Select the correct answer from each drag-drop menu.
I’m triangle ABC m
The side lengths, in order from greatest to least, are __________(Ab, Ac, or Bc) for all 3 blanks.
Answer:
I think the answers bc, ab, and ac
Step-by-step explanation:
Sorry if it ends up being wrong i had the question before but im pretty sure that's the answer.
a yard width is 2 less than it's length. If the perimeter of the yard is 20 feet determine the length and the width of the yard
Answer:
The length is 6 feet and the width is 4 feet
Step-by-step explanation:
Let x represent the length of the yard
The width can be represented by x - 2, since it is 2 less than the length.
Use the perimeter formula, P = 2l + 2w, where l is the length and w is width
Plug in the expressions and perimeter:
20 = 2x + 2(x - 2)
Solve for x:
20 = 2x + 2x - 4
20 = 4x - 4
24 = 4x
6 = x
So, the length is 6. Plug this into x - 2 to find the width
x - 2
6 - 2
= 4
So, the length is 6 feet and the width is 4 feet
A movie theater sells out 7 times per month. Chloe counted 168 sellouts at the theater. How long was Chloe recording sales?
Answer:
24 months.
Step-by-step explanation:
168 sellouts.
7 times per month.
So to find the amount of months, all we have to do is divide the sellouts by the times per month.
168/7=24.
24 months.
The difference between 5 thousands and 4thousends is
Answer:
5000-4000=1000
Step-by-step explanation:
you subtract to get your answer
Simplify.
3(x + 4) plzzz answer
Answer:
3x+12
Step-by-step explanation:
When we multipy 3 with (x+4) it becomes 3x+12
Answer:
3x+12
Step-by-step explanation:
3(x+4)
3*x=3.....keep the x with 3 because x just represents 1
3*4=12
so your answer should be
3x+12
hope this helps :)
If the side ratio is 9:16, the perimeter ratio is
The perimeter ratio of the figures is given as follows:
9:16.
How to obtain the perimeter ratio?Considering the side length ratio of a:b, the perimeter ratio has the proportion given as follows:
a:b.
This is because both the side lengths and the perimeter are measured in units, hence the perimeter ratio is the same as the side length ratio.
Considering that the area is measured in square units and the volume in cubic units, their ratios would be given as follows:
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The total cost (in dollars) of producing x food processors is C(x)=1900+60x−0.3x^2
(A) Find the exact cost of producing the 31st food processor.
(B) Use the marginal cost to approximate the cost of producing the 31st food processor.
A) The exact cost of producing the 31st food processor is $3771.70. B) Using the marginal cost, the approximate cost of producing the 31st food processor is $3741.40.
(A) To find the exact cost of producing the 31st food processor, we substitute x = 31 into the cost function C(x) = 1900 + 60x - 0.3x^2:
C(31) = 1900 + 60(31) - 0.3(31)^2
C(31) = 1900 + 1860 - 0.3(961)
C(31) = 1900 + 1860 - 288.3
C(31) = 3771.7
Therefore, the exact cost of producing the 31st food processor is $3771.70.
(B) The marginal cost represents the rate of change of the cost function with respect to the quantity produced. Mathematically, it is the derivative of the cost function C(x).
Taking the derivative of C(x) = 1900 + 60x - 0.3x^2 with respect to x, we get:
C'(x) = 60 - 0.6x
To approximate the cost of producing the 31st food processor using the marginal cost, we evaluate C'(x) at x = 31:
C'(31) = 60 - 0.6(31)
C'(31) = 60 - 18.6
C'(31) ≈ 41.4
The marginal cost at x = 31 is approximately 41.4 dollars.
To approximate the cost, we add the marginal cost to the cost of producing the 30th food processor:
C(30) = 1900 + 60(30) - 0.3(30)^2
C(30) = 1900 + 1800 - 0.3(900)
C(30) = 3700
Approximate cost of producing the 31st food processor ≈ C(30) + C'(31)
≈ 3700 + 41.4
≈ 3741.4
Therefore, using the marginal cost, the approximate cost of producing the 31st food processor is $3741.40.
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SLook at point in the coordinate grid.If a line contains both points and the origin, which point would the line also contain? *(2 points)DS(12,8)(14,7)(15,9)(20, 12)5tvAle--AR
the point which will fall in the line is (14, 7)
Explanation:
The coordinates o f S = (2, 1)
When we draw a line from the origin (0, 0) touching the point S, we will see the next point will be (4, 2). Followed by (6, 3).
So when we look at the trend, we see that the x axis is the double of the y axis:
(2y, y) = (x, y)
(2,1 ) , (4, 2), (6, 3)
From the above, we can say the point which will fall in the line will follow that trend:
When we check the options, the only point with that trend is (14, 7).
This because (2(7), 7) = (2y, y)
Hence, the point which will fall in the line is (14, 7)
Paul Linda and Aaron make handmade cards. Paul can make one card for every three cards Linda makes. Linda can make three cards for every two cards that Aaron makes. During a week Aaron makes 72 cards. How many more cards does Linda make those Paul during this week?
Answer:
Linda makes 3 more cards for every 1 card that Paul makes
Step-by-step explanation:
Paul can make one card for every three cards Linda makes.
Paul : Linda = 1 : 3
P/L = 1/3
3P = L (1)
Linda can make three cards for every two cards that Aaron makes.
Linda : Aaron = 3 : 2
L/A = 3/2
2L = 3A (2)
During a week Aaron makes 72 cards. How many more cards does Linda make those Paul during this week?
From (2)
L = 3/2A
A = 72
L = 3/2*72
= (3*73) / 3
= 216/2
= 108
Linda = 108
From (1)
P = 1/3L
= 1/3*108
= (1*108) / 3
= 108/3
= 36
Paul = 36
Finally, the number of cards that Linda makes more than Paul is:
Linda : Paul = 108 : 36
= 108/36
= 3/1
Linda : Paul = 3 : 1
Therefore, Linda makes 3 more cards for every 1 card that Paul makes
please help! look at image, thank you
Answer:
20.5
Step-by-step explanation:
Area of composite figure:
Rectangle:
length = 5 units ; width = 3 units
Area of rectangle = 5 * 3 = 15 square units
Trapezium:
a = 5 units
b = 3 units ; h= 1 unit
a and b are the parallel sides and h is the height.
\(\sf \text{Area of trapezium = $\dfrac{(a +b)*h}{2}$}\)
\(\sf =\dfrac{(5+3)*1}{2}\\\\=\dfrac{8}{2}\\\\= 4 \ square \ units\)
Triangle:
base = 3 units ; h = 1 unit
\(\sf \text{Area of triangle =$\dfrac{1}{2}*base * height$}\)
\(\sf = \dfrac{1}{2}*3*1\\\\\\= 1.5 \ square \ units\)
Area of the figure = Area of rectangle + area of trapezium + area of triangle
= 15 + 4 + 1.5
= 20.5 square units
1 point) Find the area of △ABC△ABC. Where:
A=(−1,−1), B=(−3,1), C=(−4,−4)
Area:
The area of △ABC is √2/5 square units.
To find the area of the triangle, we can use the formula:
Area = 1/2 * base * height
where the base and height are any two sides of the triangle. Let's use the distance formula to find the lengths of the sides:
AB = √[(x2 - x1)² + (y2 - y1)² ] = √[(-3 - (-1))² + (1 - (-1))² ] = √10
AC = √[(x2 - x1)² + (y2 - y1)² ] = √[(-4 - (-1))² + (-4 - (-1))² ] = √26
BC = √[(x2 - x1)² + (y2 - y1)² ] = √[(-4 - (-3))² + (-4 - 1)² ] = √18
Let's use AB as the base and drop a perpendicular from C to AB to find the height:
The slope of AB is (1 - (-1))/(-3 - (-1)) = -1/2. Therefore, the slope of the perpendicular line through C is 2 (negative reciprocal).
The equation of the line through C is y - (-4) = 2(x - (-4)), which simplifies to y = 2x - 4.
To find the intersection of this line with AB, we solve the system of equations:
y = -1/2 x + 1
y = 2x - 4
Solving for x, we get x = -3/5, and therefore y = 11/5.
The height of the triangle is the distance from C to the point (-3/5, 11/5) on AB, which is:
h = |(-4) - (2(-3/5)) - (-4)| = 2/5
Finally, we can plug in the values into the formula for the area:
Area = 1/2 * AB * h = 1/2 * √10 * 2/5 = √2/5
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You will only be able to answer one question at a time and you will not be able to go back to previous questions. iust also submit your handwritten work as a pdf to the last question. Submissions without a pdf will be given a score of 0. Question 3 What is the boiling point (Celsius) of a soluticn containing 310.3 grams of NiCl
3
in 55 mL of water? Assume the density of water is 0.997 g/mL.
The boiling point of a solution containing 310.3 grams of NiCl3 in 55 mL of water is higher than the boiling point of pure water.
To calculate the boiling point of the solution, we need to consider the effect of the solute (NiCl3) on the boiling point of water. The boiling point elevation (∆Tb) can be calculated using the formula:
∆Tb = Kb * m
Where Kb is the molal boiling point elevation constant and m is the molality of the solution. To find the molality, we need to calculate the moles of solute (NiCl3) and the mass of the solvent (water).
Moles of NiCl3 = Mass / Molar mass
Molar mass of NiCl3 = 58.69 g/mol + (35.45 g/mol * 3) = 164.29 g/mol
Moles of NiCl3 = 310.3 g / 164.29 g/mol = 1.886 mol
Mass of water = Volume * Density
Mass of water = 55 mL * 0.997 g/mL = 54.835 g
Molality (m) = Moles of solute / Mass of solvent
Molality (m) = 1.886 mol / 0.054835 kg = 34.380 mol/kg
Now, we can use the molality to calculate the boiling point elevation (∆Tb). The molal boiling point elevation constant (Kb) for water is approximately 0.512 °C/m.
∆Tb = 0.512 °C/m * 34.380 mol/kg = 17.610 °C
Finally, we add the boiling point elevation (∆Tb) to the boiling point of pure water, which is 100 °C.
Boiling point of the solution = 100 °C + 17.610 °C = 117.610 °C
Therefore, the boiling point of the solution containing 310.3 grams of NiCl3 in 55 mL of water is higher than the boiling point of pure water.
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Suppose we have generated the data with help of polynomial regression of degree 3 (degree 3 will perfectly fit this data). Now consider below points and choose the option based on these points.
Simple Linear regression will have high bias and low variance
Simple Linear regression will have low bias and high variance
polynomial of degree 3 will have low bias and high variance
Polynomial of degree 3 will have low bias and Low variance
A.
Only 1
B.
1 and 3
C.
1 and 4
D.
2 and 4
The option that which based on these points is Simple Linear regression will have high bias and low variance and polynomial of degree 3 will have low bias and high variance
So, the correct answer is B. 1 and 3.
If we use simple linear regression (degree 1) to fit this data, it would have high bias and low variance, as it would underfit the data by having only one feature. Therefore, we would miss most of the data’s details, which may lead to erroneous conclusions.
On the other hand, the polynomial of degree 3 would have low bias and high variance, as it would fit the data perfectly and capture all of its features, but it would fail to generalize well to new data, causing overfitting.
This is due to the fact that the model is too complicated and follows the data too closely. So, it will have high variance.A model with low bias and low variance is preferred as it will have good performance on both the training and test
Hence, the Answer is B.
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Plzzz giving brainilest no cap
Answer:
-0.6 yards
Step-by-step explanation:
If a =2 , b=-3 , c =-4 prove that a MULTIPLY (b+c) =(a multiply b) + (a multiply c)
Answer:
Step-by-step explanation:
a(b+c) = (ab)+(ac)
by property of distribution
a(b+c) = ab + ac
what is the answer to -3x = 4.2 ?
Answer:
\( - 3x = 4.2 \\ - x = \frac{4.2}{3} \\ - x = 1.4 \\ x = - 1.4 \\ thank \: you\)
Cai tried to prove that \triangle FGH\cong \triangle HIJ△FGH≅△HIJtriangle, F, G, H, \cong, triangle, H, I, J. Statement Reason 1 FG=HI=6FG=HI=6F, G, equals, H, I, equals, 6 Given 2 FH=HJ=4FH=HJ=4F, H, equals, H, J, equals, 4 Given 3 \overline{FG} \parallel \overline{HI} FG ∥ HI start overline, F, G, end overline, \parallel, start overline, H, I, end overline Given 4 \angle HFG\cong\angle JHI∠HFG≅∠JHIangle, H, F, G, \cong, angle, J, H, I When a transversal crosses parallel lines, alternate interior angles are congruent. 5 \triangle FGH\cong \triangle HIJ△FGH≅△HIJtriangle, F, G, H, \cong, triangle, H, I, J Side-angle-side congruence What is the first error Cai made in his proof? Choose 1 answer: Choose 1 answer: (Choice A) A Cai used an invalid reason to justify the congruence of a pair of sides or angles. (Choice B) B Cai only established some of the necessary conditions for a congruence criterion. (Choice C) C Cai established all necessary conditions, but then used an inappropriate congruence criterion. (Choice D) D Cai used a criterion that does not guarantee congruence
<HFG ≅ <JHI because they are corresponding angles, therefore: A. Cai used an invalid reason to justify the congruence of a pair of sides or angles.
What are Corresponding Angles?When two parallel lines are crossed by a transversal, the angles that are formed in matching corners along the transversal are regarded as corresponding angles which are congruent to each other.
In the proof, HFG and JHI are corresponding angles that are forrmed. Therefore, they are equal based on the fact that corresponding angles are congruent.
Thus, Cai's first error in the proof was made in his 4th statement. <HFG ≅ <JHI because they are corresponding anglles, therefore: A. Cai used an invalid reason to justify the congruence of a pair of sides or angles.
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Answer:Answer is A
Step-by-step explanation:
just did it on khan academy
rewrite this expression
\( \sqrt[5]{x} \)
A high school choir is holding a fundraiser for its spring contest trip. the amount each student needs to raise varies as the number of students who participate in the fundraiser. if 50 students participate in the fundraiser, each student needs to raise $275. use this information to complete the statements.
If 100 students participate in the fundraiser, each student needs to raise $137.50.If 25 students participate in the fundraiser, each student needs to raise amount $550.
Amount = (Total Amount Needed) ÷ (Number of Students)
For 60 students:
Amount = $275 ÷ 60 = $4.58
For 75 students:
Amount = $275 ÷ 75 = $3.67
For 40 students:
Amount = $275 ÷ 40 = $6.88
To solve this problem, we need to use a simple equation: Amount = (Total Amount Needed) ÷ (Number of Students). We can then plug in the given information to calculate the amount each student needs to raise. For example, if 50 students participate in the fundraiser, we can calculate that each student needs to raise $275 ÷ 50 = $5.50. We can then use this equation to calculate the amount that each student needs to raise if there are different numbers of students participating in the fundraiser. For example, if there are 100 students participating in the fundraiser, each student needs to raise $275 ÷ 100 = $2.75. Similarly, if there are 25 students participating in the fundraiser, each student needs to raise $275 ÷ 25 = $11.00.
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Write a possible recursive rule and then find a7 for { 7,12,17,22,27}
Start from 7, then add 5 each time.
a7 is 7 plus 30, or 37.
Solve: (step by step please)
x^2+9x+9=0
Answer:
\(x=\frac{-9\pm3\sqrt{5} }{2}\)
Step-by-step explanation:
Standard Form: ax² + bx + c = 0
Quadratic Formula: \(x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}\)
Step 1: Write equation
x² + 9x + 9 = 0
Since we cannot factor the expression, we will have to use the quadratic formula.
Step 2: Define
a = 1
b = 9
c = 9
Step 3: Solve for x
Substitute: \(x=\frac{-9\pm\sqrt{9^2-4(1)(9)} }{2(1)}\)Evaluate: \(x=\frac{-9\pm\sqrt{81-36} }{2}\)Evaluate: \(x=\frac{-9\pm\sqrt{45} }{2}\)Simplify: \(x=\frac{-9\pm3\sqrt{5} }{2}\)Answer:
X1= -9-3\(\sqrt5\) over 2 X2= -9+3\(\sqrt5\) over 2 (draw a line under the -9 to the 5
and put a 2 under like a fraction
i cant get the line all the way
across on here sorry
Step by step explanation:
x= -9 \(\sqrt9^2 -4x1x9\) Over (draw a line under that) Put all that under sq root
2 x 1 also
x= -9+ \(\sqrt81-36\) Over 2
2
x= -9 + \(\sqrt45\) Over 2
2
x=-9 +3\(\sqrt5\) Over 2
2
separate solutions gives your answer above
Also ......note ..... put a line under each + sign ok I worked hard getting this all down best i can