Find the slope of the line.

Answer:

10 hours

Step-by-step explanation:

Let A be the Princeton Salon and B is Beauty by Angle.

Build a table that contains the information.  See attached.

The cost, y, for x hours, for each option would be:

A:  y(A) = 50 + 25x

B:  y(B) =    0 + 30x

We want to find the hours, x, for which both options, so set them equal to each other:

50 + 25x = 0 + 30x

-5x = 150

 x = 10 hours

The table confirms this calculation.

Answer:

u = 14

Step-by-step explanation:

2u - 17 = 11

add 17 to both sides:

2u - 17 + 17 = 11  + 17

2u = 28

divide both sides by 2:

2u/2 = 28/2

u = 14

When the subject or predicate is missing from a sentence, the sentence error is a sentence fragment.

Sentence Errors are errors related to grammar and mechanics within sentences in Standard Written English.

An example of a sentence error will be "The children re us"

The phrase "re" is the error word in this sentence.

The three types of sentence errors we have are run-on sentences, sentence fragments and overloaded sentence.

In this problem, the type of sentence error that occurs when a sentence is missing a subject of predicate is a sentence fragment

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Answer:

Carmen received $7.14 for each hour she worked.

Step-by-step explanation:

$350 for 49 hours of work

Write an equation, with hours as the variable

$350 = 49h

Divide both sides of the equation by 49 to find the unit rate

h = $7.14

Carmen received $7.14 for each hour she worked.

Hope this helps :)

George's dog is approximately 32.41 meters away from its crate, if it ran 22 meters, turned and ran 11 meters, and then turned 120° to face its crate.

To determine the distance from George's dog to its crate after the described movements, we can use the concept of a triangle and trigonometry.

The dog initially runs 22 meters, then turns and runs 11 meters, forming the two sides of a triangle. The third side of the triangle represents the distance from the dog's final position to the crate.

To find this distance, we can use the Law of Cosines, which states that in a triangle with sides a, b, and c and angle C opposite side c, the equation is c² = a² + b² - 2abcos(C).

In this case, a = 22 meters, b = 11 meters, and C = 120°. Plugging these values into the equation, we have

c² = 22² + 11² - 2(22)(11)cos(120°).

Evaluating the expression, we get

c ≈ 32.41 meters.

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Answer:

28x-16y+45.4

Step-by-step explanation:

Add up all the variables inside the bracket by first grouping like terms

Then, multiply through by 2 ✅✅

Answer:

28 i believe

Step-by-step explanation:

Based on the provided information, the graph of y = v(3x) - 4 must contain the point (-4, -8) and (b) the graph of y = 1/4 v(x) + 9 must contain the point (-12, 6).

As the graph of y = v(x) contains the point (−12, −7), point that must be on the graph of each of the functions below are:

(a) y = v(3x) - 4

3x = -12

x = (-12)/3= -4

y = -4 – 4 = -8

The graph of y = v(3x) - 4 must contain the point (-4, -8).

(b) y = 1/4 v(x) + 9

x = -12

y = 1/4 (-12) + 9 = 6

The graph of y = 1/4 v(x) + 9 must contain the point (-12, 6).

Note: The question is incomplete. The complete question probably is:  The graph of y=v(x) contains the point (−12,−7). What point must be on the graph of each of the functions below? Enter points as (a,b) including the parentheses. (a) The graph of y = v(3x) - 4 must contain the point _ (b) The graph of y = 1/4 v(x) + 9 must contain the point _ .

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The appropriate type of test for this scenario would be a paired-t test. A paired-t test is used when the same group of subjects are tested twice under different conditions.

In this case, the 20 students were tested before and after receiving the tutorial, making it a paired design.

A paired-t test compares the mean scores of the two tests and determines if there is a significant difference between them.

On the other hand, an independent sample t-test is used when two different groups are tested and compared. It would not be suitable in this scenario since the same group of students were tested twice. In summary, the main answer is that a paired-t test is appropriate in this case.

An explanation for this is that a paired-t test is used for within-subject designs, where the same group of subjects are tested twice under different conditions.

After mentioning that a paired-t test is more powerful and sensitive than an independent sample t-test in detecting significant differences between two sets of scores because it reduces variability between subjects.

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Answer: The answer is 81m + 27t

Step-by-step explanation:

Answer: (3t)^t+3 and 3^t^2 x 27^t are both equivalent to the expression while 9^t x 27^t is not equivalent.

Step-by-step explanation:

Let be x the initial number of cups of punch. Then, we can write in algebraic language the word problem: x/2 because her guests drank 1/2 of punch.

And we can write the equation:

Because there was an initial amount of cups of punch, and then this amount decreased until there were 10 cups of punch left.

Now, we can write the equation for x:

Therefore, the initial number of cups that she started with was 60.

Answer:

vhbsdvidbvdvuib math

Step-by-step explanation:

zdztj

Umm i think you forgot to add the question.

Peter is right and Nadia is wrong.

Equivalent fractions are fractions that represent the same value, even though they look different.

Given is that Peter says 3/4 of a pizza is always the same as 6/8 of a pizza. Nadia says while 3/4 and 6/8 are equivalent fractions, 3/4 and 6/8 of a pizza could represent different amounts.

{ 1 } -

3/4 = (3 x 2)/(4 x 2) = 6/8

Peter is right.

Now -

3/4 = 6/8

So it could not represent two different quantities. So, Nadia is wrong.

{ 2 } -

3/4 = 6/8 = 9/12 = 12/15

These all represent the same quantity. Division of all the expressions will result in same value.

Therefore, Peter is right and Nadia is wrong.

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There are numerous approaches to collecting statistics on the average PSAT results of high school males and girls taking AP Stats which are described in the solution.

The Preliminary SAT/National Merit Scholarship Qualifying Test is abbreviated as the PSAT/NMSQT.

The exam is usually administered through your high school. Some schools administer the PSAT 8/9 in the eighth and ninth grades and the PSAT 10 in the tenth. However, when most people speak about the PSAT, they are talking about the PSAT/NMSQT, which kids typically take in 10th or 11th grade.

There are several ways you could gather data on the average PSAT scores of boys and girls taking AP Stats at a high school. Here are a few options:

Survey: You could conduct a survey of boys and girls taking AP Stats, asking them to report their PSAT scores. This would give you a sample of the scores of boys and girls in the class.

Review school records: Many schools keep records of students' test scores, including the PSAT. You could request access to these records and compile the scores for boys and girls taking AP Stats.

Administer a test: You could administer a test, such as the PSAT or a practice version of the test, to all students taking AP Stats. This would give you a sample of the scores of boys and girls in the class.

Ultimately, the best way to gather data on average PSAT scores will depend on the resources and time available to you.

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Answer:

D 68

Step-by-step explanation:

I think that's the answer

Answer:

71

Step-by-step explanation:

3×3 = 9

5×6 = 30

4 × 8 = 32

30+32+9= 71

The volume of the box is 216 ft cube.

He filled a box with 4 layers of cubes that measured one foot on each side

The bottom of the box fit 6 cubes,

1 cube length = 1 ft.

Therefore,

volume of the box = 6³

Therefore,

volume of the box = 216 ft³

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The distribution of a continuous uniform is f(x) = 1/10

The average time that he has to wait is E[X] = 5

What is continuous uniform distribution?

The continuous uniform distribution is the probability distribution of random number selection from the continuous interval between a and b.

f(x) = 1/(b-a) is the formula of continuous uniform distribution.

What is average?

an average of a list of data is the expression of the central value of a set of data. Mathematically, it is defined as the ratio of summation of all the data to the number of units present in the list. In terms of statistics, the average of a given set of numerical data is also called mean.

A) Given, the time between the successive buses is fixed and that is 10 minutes.

Therefore, the distribution is

The buses arrive always on time every 10' thus the distribution is uniform in [0;10] The density of a continuous uniform is

()=1/−=1/10−0=110

B) Its expectation ( the average time he has to wait) is

()=+/2=0+10/2=5.

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So we have shown that the largest possible area of the triangle is \(a^2,\)which occurs when the third side has length 3a and the height is a.

We can use the formula for the area of a triangle, which is A = (1/2)bh, where b is the length of the base and h is the height. In this case, we know that the base has length 2a, so we need to find the height.

Let's call the third side of the triangle, which is not given, b. We know that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side, so we have:

a + 2a > b

3a > b

We can rearrange this to solve for b:

b < 3a

Now, let's use the formula for the area of a triangle:

A = (1/2)bh

We want to maximize A, so we want to maximize h. We know that h is the height of the triangle, which is perpendicular to the base, so it forms a right angle. We can use the Pythagorean theorem to find h in terms of a and b:

\(h^2 = b^2 - a^2\)

We can substitute our inequality for b:

\(h^2 < (3a)^2 - a^2\)

\(h^2 < 8a^2\)

h < √(8\(a^2\))

h < 2 √(2)a

Now we can use the formula for the area of the triangle again:

A = (1/2)bh

A < (1/2)(2 √(2)a)(a)

A < \(a^2\) √(2)

So we have shown that the largest possible area of the triangle is \(a^2,\)which occurs when the third side has length 3a and the height is a.

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Disease spreading formula

Where d = number of days

Now, we need to calculate the value of P for the different days

Day 1

P = 6*(1)+5 = 11%

Day 2

P = 6*(2)+5 = 17%

Day 3

P = 6*(3)+5 = 23%

Day 4

P = 6*(4)+5 = 29%

Day 5

P = 6*(5)+5 = 35%

Day 6

P = 6*(6)+5 = 41%

Day 7

P = 6*(7)+5 = 47%

Day 8

P = 6*(8)+5 = 5353%

The disease starts spreading from day 1 and continues to increase day after day in a linear fashion. After day 8 there is no cure for the disease as it exceeds 50%.

The peak flow is 1 CIA. The Rational Method is used to calculate the peak discharge or peak flow rate in a catchment. This formula is commonly used in engineering and hydrology, and it's utilized for designing stormwater runoff control measures such as detention ponds, rain gardens, and storm sewers.

In this scenario, we are given that the Time of concentration of a watershed is 30 minutes, and the rainfall duration is also 30 minutes. By using the Rational Method formula, we can determine the peak flow rate. The formula is as follows:

Q = CIA, where Q is the peak flow rate, C is the runoff coefficient, I is the rainfall intensity, and A is the drainage area. Since we're given that the rainfall duration is 30 minutes, we can use the rainfall intensity equation to find out the I value. Using a rainfall intensity map, we can estimate that the rainfall intensity for a 30-minute duration is 2 inches per hour or 3.33 cm/hr. Now, we can substitute the given values into the Rational Method formula:

Q = CIA

Q = (0.4) (3.33) (A)

Q = 1.332 A

Q = 1.3A

According to the Rational Method, the peak flow rate is Q = 1.3A. Therefore, the answer is 1 CIA.

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Answer:

gcf=2

12-2=4(3-1)

hope this is right!

Answer:

x = 5

Step-by-step explanation:

Translate the word problem into an equation and solve for x

4x - 25 = -x

Add 25 to both sides

4x = -x + 25

Add x to both sides

5x = 25

Divide both sides by 5

x = 5

The table of values on the given graph is for the polynomial y = -x+4.

The example we are using is a polynomial in one variable. It is to be represented graphically. The graph for it is given below.

From this graph, we can clearly see the coordinates of all points we have taken. In order to make the table of values, we need to find the x and y intercepts.

We see that the first point from the left is aligned to the -2 on the x-axis and to the 6 on the y-axis. Similarly, we can identify the following values from the given graph.

x = -2 and y = 6

x = -1 and y = 5

x = 0 and y = 4

x = 1 and y = 3

x = 2 and y = 2

This is the table of values that we found out through the graph.

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The standard error of the sample mean is approximately 0.66 km, and the p-value for testing H₀: μY = 22 km vs. H₁: μY ≠ 22 km cannot be determined without additional information.

A survey was conducted in Jade City with a random sample of 144 people to gather data on the distance they travel to reach their workplaces. The sample average distance (Ȳ) was found to be 20.84 km, with a standard deviation (sȲ) of 7.96 km. To estimate the accuracy of the sample mean, we need to calculate the standard error, which measures the variability of the sample mean.

The standard error (SEȲ) of the sample mean is calculated by dividing the standard deviation (sȲ) by the square root of the sample size (n). In this case, since the sample size is 144, we can calculate the standard error as follows:

SEȲ = sȲ / √n = 7.96 / √144 = 7.96 / 12 = 0.6633 (rounded to two decimal places)

This means that the standard error of the sample mean of the distance people travel to reach their workplaces is approximately 0.66 km.

Moving on to hypothesis testing, we are testing the null hypothesis (H₀) that the population mean distance traveled to workplaces (μY) is equal to 22 km against the alternative hypothesis (H₁) that it is not equal to 22 km. The p-value of the test measures the probability of obtaining a sample mean as extreme or more extreme than the observed value, assuming the null hypothesis is true.

To determine the p-value, we would need additional information such as the test statistic or the critical value. Without that information, we cannot calculate the exact p-value in this context.

Therefore, the standard error of the sample mean is approximately 0.66 km, and the p-value for testing H₀: μY = 22 km vs. H₁: μY ≠ 22 km cannot be determined without additional information.

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Answer:

P=1538.461

Step-by-step explanation:

do it by the formula of

I=PRT, I=750 R=3.25% T=15

The equation is | x - 4 | = 3

Here, we are given that x represents all numbers that are at a distance of 3 units from 4.

Now, the distance of x from 4 can be in the positive direction or in the negative direction.

This can be represented by an absolute value function as follows-

| x - 4 | = 3

we can check our result by solving the given equation

| x - 4 | = 3 can be written as-

x - 4 = 3  or  -x + 4 = 3

x = 7 or x = 1

Both, x = 1 and 7 are at a distance of 3 units from 4.

Thus, | x - 4 | = 3 is the absolute value function.

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Answer:

-30

hope i helped

Step-by-step explanation:

The alternative and hull hypotheses is H₀: P=0.03, H₁: P≠0.03.

Given that,

According to a representative of the Ohio Department of Education, 3% of graduating high school seniors in Ohio have dropped out in recent years. Out of the 600 pupils enrolled, 30 students from Podunk High School dropped out of school last year.

We have to find is there enough data to say that this school's dropout rate is higher than the state average. Using symbols and words, state the alternative and hull hypotheses.

We know that,

n is 600,

3% Ohio high school seniors dropout.

30 dropout out of 600 in Podunk high school.

Here,

H₀: μ₁=μ₂  vs   H₁:μ₁≠μ₂

In coordinates,

H₀⇒ dropout number is equal for both schools.

H₁⇒ dropout number not equal for both schools.

H₀: P=0.03, H₁: P≠0.03.

Therefore, The alternative and hull hypotheses is H₀: P=0.03, H₁: P≠0.03.

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Answer:

sodas = 135 hot dogs = 45

Step-by-step explanation:

(S stands for sodas and H stands for hot dogs)

S + H = 180

3H+H = 180

4H = 180

H = 45

S = 45*3

S = 135