Find the slope between the points (7,8) and (-2,9)

Answer:

The banana slug would travel 5,100 centimeters.

Step-by-step explanation:

First, multiply 17*60.

Then, multiply 1,020 * 5.

Answer = 5,100

The required Banana slug moves in 5 hours is 5100 cm.

Given that,
Banana slugs can move at 17 cm per minute. if a banana slug travels for 5 hours, how far will it travel is to be determined.

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Distance is defined as the object traveling at a particular speed in time from one point to another.

here,
in 1 hour = 60 min
In 5 hour = 5(60) = 300 min
Now in 300 min, Banana slugs move,
Distance = speed (time)
Distance = 300 (17)
Distance = 5100 cm

Thus, The required Banana slug moves in 5 hours 5100 cm.

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When the population standard deviation is unknown and the population is not skewed or has outliers, we can use the t-distribution for inference about a mean.

If the population standard deviation, σ, is unknown, and the shape of the original population is not skewed and does not possess outliers, we may use the t-distribution for inference about a mean.

The t-distribution is a probability distribution that is similar to the normal distribution but with slightly thicker tails. It is used when the population standard deviation is unknown and the sample size is small (typically less than 30). The t-distribution allows us to calculate confidence intervals and perform hypothesis tests for the population mean.

To use the t-distribution, we need to know the sample mean, sample size, and the critical value from the t-table or t-distribution calculator. The critical value depends on the desired level of confidence and degrees of freedom, which is determined by the sample size minus one.

To calculate a confidence interval, we use the formula:

Confidence interval = sample mean ± (t-critical value) * (sample standard deviation / sqrt(sample size))

To perform a hypothesis test, we compare the test statistic (calculated using the t-distribution) to the critical value from the t-table.

In summary, when the population standard deviation is unknown and the population is not skewed or has outliers, we can use the t-distribution for inference about a mean.

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Answer:

1/6 studets

Step-by-step explanation:

The three objects that make up the Alpha centauri system, given their description, are all D. stars.

Alpha Centauri is a star system that consists of three stars, not planets, asteroids, or comets. The three stars are named Alpha Centauri A, Alpha Centauri B, and Proxima Centauri.

Alpha Centauri A and B are similar to the Sun, while Proxima Centauri is a smaller and cooler red dwarf star. The three stars in the Alpha Centauri system produce light and rotate on their own axis, and the system is located an average of 4 light-years from Earth.

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Answer:

0.375

Step-by-step explanation:

Take 3 divided by 8 which will give you the answer, 0.375.

Approximate value of y when x=1 is 2 (based on the given model and parameter estimates). Therefore, the answer is option b.

To predict the value of the y variable when x=1 using the given model and parameter estimates, we substitute the values into the equation:

y = β + β ln(x) + u

Given parameter estimates:

β1 = 2

β2 = 1

Substituting x=1 into the equation:

y = 2 + 2 ln(1) + u

Since ln(1) is equal to 0, the equation simplifies to:

y = 2 + 0 + u

y = 2 + u

As we don't have information about the value of the error term u, we can't provide an exact value for y when x=1. However, we can say that the approximate value of y when x=1 is 2, based on the given model and parameter estimates. Therefore, the answer is option b.

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Answer:

2x + y = 3

Step-by-step explanation: because if you do 2x1 you'll get 2

Are you sure about the numbers ( 83 x 52) ? I think there is a mistake

1. True  2. True  3. True   4. False

1. Split gateways must have exactly two incoming and at least one outgoing sequence flows: True.

Split gateways, also known as XOR gateways, are used to create exclusive decision points in a process flow. They require exactly two incoming sequence flows, representing the different paths leading to the decision point. Additionally, there must be at least one outgoing sequence flow, indicating the possible outcomes of the decision.

This ensures that the process flow can continue along one of the paths based on the conditions specified in the gateway.

2. Intermediate events must have at least one incoming and one outgoing sequence flow:  True.

Intermediate events occur within the flow of a process and can trigger specific actions or conditions. They must have at least one incoming sequence flow, indicating the event's dependency on a preceding activity or event. Similarly, they must have at least one outgoing sequence flow, showing the subsequent flow of the process after the event occurs.

This ensures that the intermediate event has a clear cause and effect relationship with the surrounding activities.

3. A message flow must connect one pool with a different pool:  True.

Message flows represent the exchange of information between pools in a BPMN (Business Process Model and Notation) diagram. Pools typically represent different participants or organizations involved in a process. A message flow connects an activity or message event of one pool to an activity or message event of a different pool, indicating communication or data exchange between them.

This ensures that the process flow accurately represents the interaction between various participants.

4. Only intermediate catching boundary events can be attached to an activity's border: False.

Both intermediate catching and throwing boundary events can be attached to an activity's border. Intermediate catching boundary events are triggered when certain conditions are met during the execution of the activity. They interrupt the normal flow and allow for additional actions to be performed.

On the other hand, intermediate throwing boundary events initiate an external interrupt and can be used to signal an error or exception. Both types of boundary events can enhance the flexibility and exception handling capabilities of an activity.

In summary, the true statements are:
- Split gateways must have exactly two incoming and at least one outgoing sequence flows.
- Intermediate events must have at least one incoming and one outgoing sequence flow.
- A message flow must connect one pool with a different pool.

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The expression that shows how much Diego saves in the third month is 2³ which equals 8.

To determine how much Diego saves in the third month, to consider the pattern established in the problem that Diego saves $2 in the first month, and each subsequent month he saves twice as much as the previous month.

Let's break it down:

First month: $2

Second month: Twice as much as the first month = 2 * $2 = $4

Third month: Twice as much as the second month = 2 * $4 = $8

From the pattern that Diego saves $8 in the third month.

To represent this pattern algebraically,  use the following expression:

2 × 2 × 2

This simplifies to:

2³

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The optimal mix of crops to plant is 1,304 acres of soybeans, 761 acres of corn, and 341 acres of cotton, which will maximize the family's total profit.

3.51 Farm Management problem: Formulate and solve a linear programming model for this problem in a spreadsheet.The given table contains information about the labor-hours and fertilizer needed per acre and the total expected profit per acre for the potential crops under consideration.

Given that Dwight, Hattie, and their children can work at most 6.500 total hours during the upcoming season and have 200 tons of fertilizer available. We need to find the mix of crops that maximizes the family's total profit.Let x1, x2, and x3 be the amount of acres for soybeans, corn, and cotton, respectively.

We need to maximize the profit, which is given byZ = 70x1 + 60x2 + 90x3subject to the constraints given below:2x1 + 3x2 + 4x3 <= 6,500 (labor-hours constraint)3x1 + 2x2 + 4x3 <= 200 (fertilizer constraint)x1, x2, x3 >= 0 (non-negativity constraint)The linear programming model for this problem can be written as follows:maximize Z = 70x1 + 60x2 + 90x3Subject to:2x1 + 3x2 + 4x3 ≤ 6,5003x1 + 2x2 + 4x3 ≤ 200x1, x2, x3 ≥ 0Solving the problem using a spreadsheet, we get the following optimal solution.

 The optimal solution is obtained for x1 = 1,304 acres of soybeans, x2 = 761 acres of corn, and x3 = 341 acres of cotton.

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Answer: P = $ 12000

r = 14%

t = 1 (for first year)

I = (P X r X t)/100

∴ I = (12000 X 14 X 1)/100

   = 120 X 14

   = $ 1680   <---------- (Interest on loan at the end of first year)

∴ Total amount owing at the end of first year = (P + I)

                                                                          = (12000 + 1680)

                                                                          =  $ 13680

Repayment = $ 7800

Amount still outstanding (at the start of second year) = 13680 - 7800

                                                                                       =  $ 5880

Interest on the outstanding amount at the end of second year,

P (new) = $ 5880

r (same) = 14%

t = 1 (for the current second year)

∴ I = (P X r X t)/100

   = (5880 X 14 X 1)/100

   = 82320 / 100

   = $ 823.2   <-------------------------- (Interest on outstanding amount at the end of second year)

Answer: 7 and 8

Step-by-step explanation:

Square root and squared cancel out

Answer:

a=7

b=32

Step-by-step explanation:

The first one (a) is 7 because if you square a square root, you get the number inside the root. Also, technically a square root has an exponent of (1/2) so when you have a power-to-a-power (power rule of exponents) you multiply the exponents. So (\(7^{1/2}\))^2 is 7.

For (b) you have to take it in two parts. Square the square root and you get 2. Square the 4 in front, you get 16. Multiply those two numbers (16 and 2) together and you get 32.

Edit: Check on your calculator, you get the same answers I got! :)

Answer:

80mi^2

Step-by-step explanation:

the area of a parallelogram is the base x height so 8*10=80

The value of \(f_{x}\)(3,2)≈12.2, \(f_{x}\)(3,2.2)≈16.8, \(f_{x}\)(3,2)≈23.25

This problem aims to find the values of a function having alternate independent variables.

A-

\(f_{x}(3,2) f_{x} (x,y)=lim_{h-0} \frac{(3+0.5,2)-f(3,2)}{0.5}\)    considering h =±0.5

Solving for h=0.5

⇒\(\frac{f(3.5,2)-f(3,2)}{0.5}\)

Using the table to plug in the values of the function: 22.4-17.5/0.5=9.8

Now, solving for h=-0.5

⇒\(\frac{f(3.5,2)-f(3,2)}{-0.5}\)

Using the table to plug in the values of the function: 22.4-17.5/(-0.5)=14.6

Taking the average of both ±0.5 answers for the final answer of f(3,2)

\(f_{x}(3,2)=\frac{9.8+14.6}{2} \\or, f_{x}(3,2)=12.2\)

B-

\(f_{x}(3,2.2)=lim_{h-0} \frac{(3+0.5,2.2)-f(3,2.2)}{0.5}\)    considering h =±0.5

Solving for h=0.5

⇒\(\frac{f(3.5,2.2)-f(3,2.2)}{-0.5}\)

Using the table to plug in the values of the function: 26.1-15.9/0.5=20.4

Now, solving for h=-0.5

⇒\(\frac{f(2.5,2.2)-f(3,2.2)}{-0.5}\)

Using the table to plug in the values of the function: 9.3-15.9/(-0.5)=13.2

Taking the average of both ±0.5 answers for the final answer of f(3,2.2)

\(f_{x}(3,2.2)=\frac{20.4+13.2}{2} \\or, f_{x}(3,2.2)=16.8\)

C-

\(f_{xy} (3,2)=lim_{h-0} \frac{f_{x}(3,2+h)-f_{x} (3,2) }{h} \\\)     considering h =±0.2

Solving for h=0.2

⇒\(\frac{f_{x} (3,2.2)-f_{x} (3,2)}{0.2}\)

Plugging in the answers from A and B: 16.8-12.2/0.2= 23

Now solving for h= -0.2

⇒\(\frac{f_{x} (3,1.8)-f_{x} (3,2)}{-0.2}\)

Plugging in the values: 7.5-12.2/-0.2= 23.5

Taking an average of h=±0.2 answers to find the final answer:

\(f_{x}(3,2)=\frac{23+23.5}{2} \\or, f_{x}(3,2)=23.25\)

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Answer:

62.5 %

Step-by-step explanation:

Take the original amount and subtract the new amount

32-12 = 20

Divide by the original amount

20/32 =.625

Multiply by 100 to get to percent form

62.5 %

The first statement is false and the second statement is true.

Probability is the branch of discrete mathematics. It is used for calculating how likely an event is to occur or happen. There are two types of random variables.

A random variable that takes a finite number of possible values can be defined as a Discrete random variable. A random variable that takes an infinite number of possible values can be defined as a Continuous random variable. A continuous random variable consists of only continuous values.

Continuous random variables are defined at intervals of values. Continuous random variables are represented by the area under a curve.

⇒  The number of cars that go through the drive-in window at a local bank each hour.

The number of cars can be counted and can be an integer like 10, 20,100 etc.

∵ The number of cars is countable it is not an example of a continuous random variable        

⇒ The high daily temperature in Anchorage.

High daily temperature can be an integer or function like 60°, 120° etc

∵ The high daily temperature is an example of a continuous random variable.

Therefore, The number of cars that go through the drive-in window at a local bank each hour is not an example of a continuous random variable and The high daily temperature in Anchorage is an example of a continuous random variable.

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The complete question is

Answer:

13u = 26

13*2 = 26

2 is the answer

Answer:

Today: Monday, 12 October 2020

Hour: 09.17 WIB (in Indonesian)

_________________________

13u = 26

u = 26/13

u = 2

Answer:

28/11

Step-by-step explanation:

4x7=28

1x11=11

so and: 28/11

hope this helps

Yes, this is true.

A normal distribution with a mean of 0 and a standard deviation of 1 is often denoted as N(0, 1) or n(0, 1). This distribution is also known as the standard normal distribution. It is a symmetric bell-shaped distribution where the majority of the data falls within approximately three standard deviations from the mean.

The standard normal distribution, denoted as N(0, 1) or n(0, 1), is a specific type of normal distribution that has a mean of 0 and a standard deviation of 1. It is often used as a benchmark for comparing and standardizing data in statistical analysis.

The shape of the standard normal distribution is symmetric and bell-shaped. It follows the familiar "bell curve" pattern, where the data is concentrated around the mean and gradually tails off towards the extremes. The total area under the curve is equal to 1, representing the entire probability space.

The standard deviation of 1 indicates the spread or variability of the data. In a standard normal distribution, about 68% of the data falls within one standard deviation of the mean, approximately 95% falls within two standard deviations, and roughly 99.7% falls within three standard deviations.

The standard normal distribution is widely used in statistical calculations and hypothesis testing. It serves as a reference distribution for many statistical methods, such as z-tests and z-scores. By converting data from other normal distributions into standard units using z-scores, researchers can compare and analyze data from different distributions on a common scale.

The standard normal distribution also has specific properties that make it mathematically tractable. The cumulative distribution function (CDF) of the standard normal distribution, often denoted as Φ(z), gives the probability that a standard normal random variable is less than or equal to a given value z. This CDF is tabulated in standard statistical tables or can be calculated using mathematical functions.

Overall, the standard normal distribution is a fundamental concept in statistics, providing a reference distribution for comparing and analyzing data and serving as a basis for many statistical techniques and calculations.

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Answer:

25 is the right not comform

Answer:

B

Step-by-step explanation:

(x-8)^2=(x-8)(x-8)=x^2-8x-8x+64=x^2-16x+64

Answer:

x2 − 16x + 64; is a polynomial

Answer: B. 45

Step-by-step explanation:

Answer:

b 45

Step-by-step explanation:

The probability that the largest of n random samples is greater than the population median M is bounded above by\(1 - F(M)^(n-1) \times F(X(n))\).

Assumptions about the population and the sampling method.

Let's assume that the population has a continuous probability distribution with a well-defined median, and that we are taking independent random samples from this population.

Let \(X1, X2, ..., Xn\) be the random samples that we take from the population, where n is the sample size.

Let M be the population median.

The probability that the largest of these random samples, denoted by X(n), is greater than M.

Cumulative distribution function (CDF) of the population distribution to calculate this probability.

The CDF gives the probability that a random variable takes on a value less than or equal to a given number.

Let F(x) be the CDF of the population distribution.

Then, the probability that X(n) is greater than M is:

\(P(X(n) > M) = 1 - P(X(n) < = M)\)

Since we are assuming that the samples are independent, the joint probability of the samples is the product of their individual probabilities:

\(P(X1 < = x1, X2 < = x2, ..., Xn < = xn) = P(X1 < = x1) \times P(X2 < = x2) \times ... \times P(Xn < = xn)\)

For any x <= M, we have:

\(P(Xi < = x) < = P(Xi < = M) for i = 1, 2, ..., n\)

Therefore,

\(P(X1 < = x, X2 < = x, ..., Xn < = x) < = P(X1 < = M, X2 < = M, ..., Xn < = M) = F(M)^n\)

Using the complement rule and the fact that the samples are identically distributed, we get:

\(P(X(n) > M) = 1 - P(X(n) < = M)\)

= \(1 - P(X1 < = M, X2 < = M, ..., X(n) < = M)\)

=\(1 - [P(X1 < = M) \times P(X2 < = M) \times ... \times P(X(n-1) < = M) \times P(X(n) < = M)]\)

\(< = 1 - F(M)^(n-1) \times F(X(n))\)

Probability depends on the sample size n and the distribution of the population.

If the population is symmetric around its median, the probability is 0.5 for any sample size.

As the sample size increases, the probability generally increases, but the rate of increase depends on the population distribution.

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Answer:

u ≈ 5.7

Step-by-step explanation:

Using the Sine rule in Δ TUV, that is

\(\frac{t}{sinT}\) = \(\frac{u}{sinU}\) , substitute values

\(\frac{2.5}{sin26}\) = \(\frac{u}{sin85}\) ( cross- multiply )

u × sin26° = 2.5 × sin85° ( divide both sides by sin26° )

u = \(\frac{2.5sin85}{sin26}\) ≈ 5.7 ( to 1 dec. place )

Answer:

The photo

Step-by-step explanation:

All is wreaten in the photo

3,4,5 is correct

as we know that ,

3² + 4² = 5²

9 + 16 = 5²

25 = 25

hence . 3,4,5 is correct

Answer:

I'm pretty sure it's 3,4,5 but I'm not sure (is it in cm,mm etc?)

The slope of the line is -1.

Given is a line we need to find the slope,

The line passing through (0, 1) and (1, 0).

The slope of a line passing through two points (x₁, y₁) and (x₂, y₂) is given by = y₂ - y₁ / x₂ - x₁

Here, (x₁, y₁) and (x₂, y₂) = (0, 1) and (1, 0)

So,

Slope = 0-1 / 1-0 = -1.

We know that,

The greater the slope, the greater the rate of change.

Hence the slope of the line is -1.

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Answer:

Step-by-step explanation:An average household, earned $19,074.00 in December, 1981. How much would that income be in October, 2008? ($19,074.00 * (216.573/94.000) = $43,945.89).