find the percent dissociation of a 0.100 mm solution of a weak monoprotic acid having ka=1.8×10−3ka=1.8×10−3 .

Answer: Whats ur Question?

Explanation:

Given that the enthalpy change ΔH for the reaction is negative, energy is released during the reaction (Option D)

From the data given above, we can see that the enthalpy change (ΔH) for the reaction is negative.

This simple means that heat energy is lost to the environment.

Therefore, we can conclude that the during the reaction, energy is released (Option D)

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Answer:

Friction between the hand and the wood decreased.

Explanation:

The texture of the wood went from rough → smooth! This means friction between the hand and the wood was notably decreased.

According to this prompt, the carpenter used sandpaper against the wood. Sandpaper just so happens to be a very abrasive substance. The sandpaper polished and leveled out the wood which wore all the jutting bits away.- overall, making it much smoother and more pleasant to touch!

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1. The volume of the metal ball is 33.49 cm³

2. The density of the metal ball is 7.99 g/cm³

3. The metal ball is iron

We can obtain the identity of the metal by doing the following:

1. Determine the volume

The volume of the metal ball can be obtain as follow:

V = 4/3πr³

V = (4/3) × 3.14 × 2³

Volume = 33.49 cm³

2. Determine the density

The density can be obtain as follow:

Density = mass / volume

Density of metal ball = 267.4794 / 33.49

Density of metal ball = 7.99 g/cm³

3. Determine the identity

From the above, we can see that the density of metal ball is 7.99 g/cm³.

Thus, the metal ball is iron

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Cementation during the diagenesis process reduces the porosity and permeability of rocks by filling the pore spaces between grains with mineral cements, impacting fluid flow and rock strength.

Cementation is a process in which minerals precipitate and fill the spaces between sediment grains, binding them together. This process occurs as pore fluids, such as groundwater, carry dissolved minerals that can precipitate and form a solid cementing material.

During diagenesis, cementation can significantly impact the permeability and porosity of rocks. The precipitation of mineral cements fills the pore spaces between grains, reducing the overall porosity of the rock. This reduction in porosity limits the amount of fluid that can flow through the rock and decreases its permeability.

The type of mineral cement formed during cementation can also influence the strength and durability of the rock. Common mineral cements include calcite, silica, and iron oxides, which can impart different properties to the rock.

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The following statement “an oxidation reaction often occurs without a corresponding reduction reaction.” is False.

An oxidation reaction and a reduction reaction are always coupled together and occur simultaneously. This is known as a redox (reduction-oxidation) reaction. In a redox reaction, one species undergoes oxidation (loses electrons) while another species undergoes reduction (gains electrons). The transfer of electrons from the oxidized species to the reduced species ensures that the total number of electrons remains conserved.

For example, consider the reaction:

2Na + Cl₂ → 2NaCl

In this reaction, sodium (Na) loses an electron and is oxidized to Na⁺, while chlorine (Cl₂) gains an electron and is reduced to 2Cl⁻. The oxidation of sodium is always accompanied by the reduction of chlorine, and vice versa. The transfer of electrons allows for charge balance between the reacting species.

It is important to note that oxidation and reduction are complementary processes that occur together. One species cannot be oxidized without another species simultaneously undergoing reduction in a redox reaction.

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Points that do not lie on the same line are non-collinear or noncollinear.

Answer:

a white precipitate of barium chloride is formed as displacement reaction takes place.

Explanation:

6 CO2 + 12 H2O ---->C6H12O6 + 6 O2+ 6 H2O

Answer: A white precipitate of silver sulfate (Ag2SO4) is formed.

Explanation:
When aqueous silver nitrate (AgNO3) reacts with aqueous potassium sulfate (K2SO4), a double displacement reaction occurs. The cations and anions of the two compounds switch places to form two new compounds, which are potassium nitrate (KNO3) and silver sulfate (Ag2SO4).

AgNO3 + K2SO4 → Ag2SO4 + 2KNO3

The insoluble product of this reaction is silver sulfate (Ag2SO4), which appears as a white precipitate. This reaction is commonly used to detect the presence of sulfate ions in solution, as the formation of the silver sulfate precipitate confirms the presence of sulfate ions.

To address the crevice corrosion issue in the high-pressure connectors and piping of the SWRO plant, several remedies can be considered, A SWRO (Sea Water Reverse Osmosis) plant is a water desalination facility that uses reverse osmosis technology to treat seawater or brackish water and produce freshwater

Material Selection: Evaluate the material compatibility with the operating conditions, especially the chloride ion concentration and temperature. Consider using corrosion-resistant alloys such as duplex stainless steel (e.g., 2205) or super duplex stainless steel (e.g., 2507) that have better resistance to chloride-induced corrosion compared to 316L or 317L stainless steel.

Surface Treatment: Apply appropriate surface treatments to enhance corrosion resistance. Passivation or pickling can remove surface contaminants and create a protective oxide layer on the metal surface, reducing the susceptibility to corrosion.

Design Modifications: Evaluate the design of the connectors and piping to minimize crevices and stagnant areas where corrosion can occur. Smooth transitions, avoiding sharp angles or crevices, can help promote better fluid flow and prevent the accumulation of corrosive substances.

Cathodic Protection: Implement cathodic protection methods, such as impressed current or sacrificial anodes, to protect the connectors and piping from corrosion. This technique involves introducing a more easily corroded metal (anode) to the system, which sacrifices itself to protect the connected metal (cathode) from corrosion.

Monitoring and Maintenance: Regularly monitor the corrosion levels and condition of the connectors and piping. Implement a maintenance program that includes periodic inspections, cleaning, and repairs, if necessary, to prevent corrosion from progressing.

It is important to consult with corrosion experts and engineers who specialize in SWRO plant operations to assess the specific conditions, perform material testing, and provide tailored solutions to mitigate the crevice corrosion problem effectively.

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75 for all

Explanation:

Answer:

Explanation: Li= Lithium, Na= Sodium, K= Pottasium, Rb= Rubdium Cs= Cesiuna, Fr= Fransium

6. Energy levels increases as if you move down a group during the number of electrons increases again.

7. A charge with higher and effective nuclear charge makes greater attractions to the electrons, pulling the electrons cloud closer to the nucleus makes it in a smaller atomic radius.

8. Ge= Germanium, He= Helium, O=Oxygen, Barium

most prolly option D

Explanation:

NaCl + H2SO4 -> Na2SO4 + HCl[g]

The reaction between between common salt and concentrated tetraoxosulphate(vi) acid will liberate Hydrogen chloride gas .

This is the type of reaction in which two or more elements/compounds react  together to form a new substance.

The reaction between common salt and concentrated tetraoxosulphate(vi) acid can be seen below:

NaCl + H2SO4 ⇒ Na2SO4 + HCl(g)

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Using an ice bath to cool the solution is most likely to reduce the concentration of sodium chloride in the solution. Option D is correct.

When a solution is cooled, the solubility of most solids decreases. As a result, some of the sodium chloride may precipitate out of the solution, reducing the concentration of the solute. The other options listed would not reduce the concentration of sodium chloride in the solution.

Heating the solution on a hot plate could potentially increase the solubility of sodium chloride and lead to more dissolving, whereas adding more sodium chloride would only increase the concentration. Removing some solution with a pipette would not change the concentration, as the amount of solute would remain the same in the remaining solution. Hence Option D is correct.

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Answer:

A. How hot or cold the substance is.

Explanation:

If we know the temperature of the substance

we can know how hot or cold the substance is.

And as we know temperature is the degree of hotness or coldness of a body.

Conjugate acid-base pairs are two species that are related to each other by the transfer of a proton (H+). When an acid donates a proton, it forms its conjugate base, and when a base accepts a proton, it forms its conjugate acid. The conjugate acid of a base is formed by adding a proton to the base, while the conjugate base of an acid is formed by removing a proton from the acid.

In the given equation:

HNO2(aq) + HS−(aq) ⇌ NO−2(aq) + H2S(g)

The conjugate acid-base pairs are:

a. HS−/NO2− (HS− is the conjugate base of H2S, and NO2− is the conjugate acid of HNO2)

c. HNO2/NO−2 (HNO2 is the conjugate acid of NO−2, and NO−2 is the conjugate base of HNO2)

d. H2S/HS− (H2S is the conjugate acid of HS−, and HS− is the conjugate base of H2S)

Therefore, options a, c, and d represent the specific conjugate acid-base pairs in the given equation.

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Answer:

S

Explanation:

The symbol for entropy is S, and a change in entropy is shown as “delta” S or ΔS. If the entropy of a system increases, ΔS is positive. If the entropy of a system decreases, ΔS is negative.

Answer:

Sodium has 11 electrons and Chlorine has 17 electrons

Explanation:

You can find the number of electrons by looking at the atomic number

The atomic number is the number above the elements on the periodic table

The atomic number is also the number of protons there are too

hope this helps

Answer:

It is a redox reaction.

Explanation:

I would only partially agree the student. In a redox reaction, the oxidation states of compounds change with at least one atom going up in oxidation state and at least one atom going down in oxidation state. Zinc originally has an oxidation state of 0, and it changes to +2 in ZnO. Oxygen originally has an oxidation state of 0, and it changes to -2 in ZnO. Zinc has gone up in oxidation state while oxygen has gone down, so this is a redox reaction. The student is correct by saying that it is a combustion reaction, but incorrect by claiming that it is not a redox reaction. All combustion reactions are redox reactions because in the process of combustion, an oxidant is reduced and a fuel is oxidized.

The  correct number of atoms from each element from the reactant side of the equation are Al = 4, C = 6, O = 18, H = 36, P = 8.

On the reactant side and the product side, there is one carbon atom each. The same is true for oxygen, although oxygen has two atoms on each side instead of one (remember that the subscript of two in the oxygen molecule means that there are two oxygen atoms bonded together).

Oxygen and hydrogen gases are both made up of diatomic (two-atom) molecules. The reactants in the process are these molecules.

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Answer:

There is no hydrogen in the first half reaction

Drawing conclusions is the process of making sense of information that has been hinted at or implied. As a result, the information is seldom given in an obvious way.

To arrive at trustworthy findings, careful evidence collecting, analysis, and judgements that can withstand scrutiny are required. As an author, you are presenting your findings for readers to assess, thus you must be compelling based on the information you present in your piece.

Posing a sound question, formulating a working hypothesis, conducting research, identifying and controlling factors, recording observations during testing, gathering data, and drawing conclusions are all necessary steps. If you use spec sheets, diagrams, and graphs, your results are simpler to organise and present.

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Explanation:

A physical change does not change the chemical properties of a compound. Instead a change in state occurs, for example evaporation where a liquid becomes a gas.

Answer:

Physical change

Explanation:

A physical change is a change of matter from one form to another without a change in chemical properties.

Answer:

20ml is your answer according to CBSE . thank you

The balanced chemical equation for the reaction between aluminum oxide and water to form aluminum hydroxide is:

Al2O3 + 3 H2O → 2 Al(OH)3

We can see that for every 1 mole of Al(OH)3 produced, we need 1/2 mole of Al2O3:

1 mole Al2O3 produces 2 moles Al(OH)3

1/2 mole Al2O3 produces 1 mole Al(OH)3

So, if we need 0.64 moles of Al(OH)3, we can calculate the amount of Al2O3 needed as:

0.64 moles Al(OH)3 x (1/2) moles Al2O3 per 1 mole Al(OH)3 = 0.32 moles Al2O3

Therefore, we need 0.32 moles of aluminum oxide to produce 0.64 moles of aluminum hydroxide, assuming there is plenty of water.

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Answer:

Explanation:

La molaridad son los moles que hay por litro de solución.

En este caso tenemos 0,24 moles de KCL por 1000 ml de solución. El problema nos plantea que hay que preparar una solución de 54ml para poder sacar los moles hacemos una regla de tres.

1000 ml -----------0,24mol

54ml----------------X=(54ml*0,24mol)/1000ml

moles necesarios=0.0129 moles de KCl

Ahora para expresarlo en gramos utilizaremos la masa molar del compuesto, esto se hace buscando en la tabla periódica cada componente del compuesto y sumarlos.

En este caso tenemos el potasio (K) con una masa molar de 39 y el cloro (Cl) de 35,45 gramos lo

masa KCL=35,45+39=74,45 Gramos/mol

como tenemos 0.0129 moles haremos otra vez una regla de 3

1mol----------74,45 gramos

0.0129 mol-----0,960 gramos

espero que te sirva la respuesta! no te olvides de calificar :)

Mass can be calculated by using moles which can be further calculated from multiplication of Molarity to volume. The mass of KCl to make this solution is 0.960gram.

Molarity can be calculated by dividing  number of moles of solute by volume of solution in liter. Molarity is affected by temperature. Its unit is mole/litre. It measure the concentration of any solute in a solution.

Other concentration terms are molality, normality and mole fraction. Molarity can be used to find out the ionic strength of any solution.

Mathematically,

Molarity= number of moles of solute/volume of solution in litre

Where,

moles= given weight ÷ molecular weight

         = w/ 74.55

Substituting values in equation 1

0. 24=(w/ 74.55 )/(52/1000)

w=0.960gram

Thus the mass of KCl is 0.960gram.

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Answer:

Planck's constant, represented by h, relates the energy in one quantum (photon) of electromagnetic radiation to the frequency of that radiation. In the International System of units (SI), the constant is equal to approximately 6.626176 x 10-34 joule-seconds.

Explanation:

i hope this will help you :)