Find the original price of a pair of gloves that is on sale for $28, a 30% discount from the original price.

Answer:

48.45in

Step-by-step explanation:

To get the height of Dakota, we will use the SOH CAH TOA

Given the following

angle of elevation = 39degrees

distance from the top of Dakotas head to the tip of the shadow = 77in (Hyp)

Required

Height of Dakota (Opp)

Sin 39 = opposite/hyp

Sin39 = H/77

H = 77sin39

H = 77(0.6293)

H = 48.45in

Hence the Dakota is 48.45in

Answer:

Step-by-step explanation:

The inequality is 500 - 25x >= 200

This insures that he will have at least 200 at the end of the summer.

subtract 200 from both sides of that inequality and add 25x to both sides of that inequality to get 500 - 200 >= 25x

simplify to get 300 >= 25x

divide both sides of that equation by 25 to get 300 / 25 >= x

simplify to get 12 >= x    12 >= x means x <= 12.

Answer: Let's start by figuring out how much money Kimberly will have left at the end of the summer if she withdraws $25 each week.

Since there are 12 weeks in the summer, she will withdraw a total of:

$25 x 12 = $300

So if she starts with $500, she will have:

$500 - $300 = $200

left at the end of the summer.

Therefore, Kimberly can withdraw money for up to 12 weeks and still have $200 in her account at the end of the summer.

Step-by-step explanation:

The length of AE¯¯¯¯¯ is 5√2 cm.

Since quadrilateral ABCD is a square, all four sides are congruent. Let's denote the length of one side as s. Therefore, the length of BD¯¯¯¯¯ is equal to s.

Given that the length of BD¯¯¯¯¯ is 10 cm, we can conclude that s = 10 cm.

Now, we need to find the length of AE¯¯¯¯¯. Looking at the square, AE¯¯¯¯¯ is the diagonal connecting opposite corners.

In a square, the diagonal divides the square into two congruent right triangles. We can use the Pythagorean theorem to find the length of the diagonal.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides.

In this case, the diagonal (the hypotenuse) is the same as the side length, s.

Applying the Pythagorean theorem:

s^2 = AE¯¯¯¯¯^2 + AE¯¯¯¯¯^2

10^2 = AE¯¯¯¯¯^2 + AE¯¯¯¯¯^2

100 = 2 * AE¯¯¯¯¯^2

AE¯¯¯¯¯^2 = 50

Taking the square root of both sides:

AE¯¯¯¯¯ = √50

Simplifying the square root:

AE¯¯¯¯¯ = √(25 * 2) = 5√2 cm

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For the given values of x and y, the value of y/x (that represents the slope of the equation) = 3/1, 3/1, 3

A line's steepness can be determined by looking at its slope. Slope is calculated mathematically as "rise over run" (change in y divided by change in x).

The ratio of the increase in elevation between two points to the run in elevation between those same two points is referred to as the slope.

Given are the values of the x and y

y/x represents the slope of the equation,

for x = -1 and y = -3,

y/x = 3/1

for x = 1 and y = 3

y/x = 3/1

for x = 2 and y = 6

y/x = 6/2 = 3

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The molarity of the solution is (0.4507 ± 0.0007) M.

Molarity of a given solution is defined as the total number of moles of solute per litre of solution. The molality of a solution is dependent on the changes in physical properties of the system such as pressure and temperature as unlike mass, the volume of the system changes with the change in physical conditions of the system. Molarity is represented by M, which is termed as molar. One molar is the molarity of a solution where one gram of solute is dissolved in a litre of solution. As we know, in a solution, the solvent and solute blend to form a solution, hence, the total volume of the solution is taken.

Mass of NaCl = 2.634 ± 0.002 g

Molar mass of NaCl = 58.4430 g/mol

Volume = 100.00 ± 0.08 mL = 0.10000 ± 0.00008 L

Molarity = moles/volume = mass/(molar mass x volume)

= 2.634/(58.443 x 0.1000) = 0.45069555 M

Assuming no uncertainty/error in the molar mass,

%Error in molarity = %error in mass + %error in volume

= 100 x 0.002/2.634 + 100 x 0.08/100.00 = 0.16%

Absolute error in molarity = 0.16/100 x 0.45069555= 0.0007 M

So, Molarity = (0.4507 ± 0.0007) M

Therefore, the molarity of the solution is (0.4507 ± 0.0007) M.

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Using the Chain Rule, we have: dy/dx = f'(g(x)) * g'(x) = 1 * 1 = 1.The derivative of y with respect to x is 1.

When we compose a function, it may be possible to write it in a variety of different ways. Differentiating such functions can result in different derivatives, but the Chain Rule indicates that the derivatives of the compositions should be the same regardless of how the function is written, if the function is continuous and differentiable.For instance, consider the function f(x) = sin(x²). It can be written as f(g(x)) where g(x) = x² and f(x) = sin(x). Furthermore, it can be written as f(h(x)) where h(x) = x² and f(x) = sin(x). These are both compositions of functions, but they are different compositions that lead to different derivatives.However, if the function is a composite of differentiable functions, the Chain Rule tells us that the derivative of a composite function is the derivative of the outer function multiplied by the derivative of the inner function.

To find dy/dx if y = x using the Chain Rule with y as a composite of the following functions, we must first rewrite y as a composite function: y = f(g(x)) where g(x) = x and f(x) = x. This composite function can be written in a variety of different ways, such as y = f(h(x)) where h(x) = x and f(x) = x, or y = f(k(x)) where k(x) = x and f(x) = x. However, regardless of how we write it, the Chain Rule tells us that the derivative of y is equal to the derivative of the outer function (f(x) = x) multiplied by the derivative of the inner function (g(x) = x).

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Answer:

  y = -5/2x +1

Step-by-step explanation:

You want the slope-intercept form equation for the line through the point (-2, 6) that is parallel to 5x +2y = -4.

The equation of a parallel line can be the same as the given equation, except for the constant. The new constant can be found by substituting the given point coordinates:

  5(-2) +2(6) = c

  -10 +12 = c

  2 = c

Now we know the equation of the parallel line can be written as ...

  5x +2y = 2

Solving for y puts this in slope-intercept form:

  2y = -5x +2 . . . . . . . . subtract 5x

  y = -5/2x +1 . . . . . . . . divide by 2

We don't know what your boxes look like, but we can separate the numbers to make it look like this:

  \(\boxed{y=\dfrac{-5}{2}x+1}\)

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Answer:

hbjnmui,lhyjngrfdxw

Step-by-step explanation:

Answer:

Yes

Step-by-step explanation:

(-2, 10)

x = -2

y = 10

y = -4x + 2

Substitute or plug in the x and y values

10 = -4(-2) + 2

Multiply(remember a negative times a negative is a positive)

10 = 8 + 2

Add

10 = 10

Because ten is equal to ten (-2, 10) is a solution for this part

Now take your next equation and repeat the same steps

y = -6x - 2

10 = -6(-2) - 2

10 = 12 -2

10 = 10

(-2, 10) is  a solution to this system of equations

On solving the inequality we know, Barrett should work 25 hours tutoring and 10 hours cutting grass to make $400.

In mathematics, "inequality" refers to a relationship between two expressions or values that is not equal to each other. Therefore, inequality results from a lack of balance.

Solution:-

given,

z=hours of cutting grass

y=hours of tutoring

Two equation can be made using given condition

15z+10y=400

and

z+y=35

Solving both equation simultaneously,

we get

y=25

z=10

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1600 children and 1400 adults attended

Let the children be x and adult be y.

So, we have the following equations:

x + y = 3000

1.5x + 5y = 9400

Make x the subject in x + y = 3000

x = 3000 - y

Substitute x = 3000 - y  in 1.5x + 5y = 9400

1.5(3000 - y) + 5y = 9400

Expand

4500 - 1.5y + 5y = 9400

Evaluate the like terms

3.5y = 4900

Divide both sides by 3.5

y = 1400

Substitute y = 1400 in x = 3000 - y

x = 3000 - 1400

Evaluate

x = 1600

Hence, 1600 children and 1400 adults attended

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Answer:

Hello your answer would be A

Step-by-step explanation:

hev nice day

[o]-[o]

\__/

Answer:

We can start by using the second equation to eliminate x:

2x + 5y - 2z = 3

2x = -5y + 2z + 3

x = (-5/2)y + z + 3/2

Now we can substitute this expression for x into the first and third equations:

x + y + z = 4

(-5/2)y + z + 3/2 + y + z = 4

(-5/2)y + 2z = 5/2

x + 7y - 7z = 5

(-5/2)y + z + 3/2 + 7y - 7z = 5

(9/2)y - 6z = 7/2

Now we have a system of two equations with two variables, (-5/2)y + 2z = 5/2 and (9/2)y - 6z = 7/2. We can use any method to solve for y and z, such as substitution or elimination. However, we will find that the system is inconsistent, meaning there is no solution that satisfies both equations.

Multiplying the first equation by 9 and the second equation by 5 and adding them, we get:

(-45/2)y + 18z = 45/2

(45/2)y - 30z = 35/2

Adding these two equations, we get:

-12z = 40/2

-12z = 20

z = -5/3

Substituting z = -5/3 into (-5/2)y + 2z = 5/2, we get:

(-5/2)y + 2(-5/3) = 5/2

(-5/2)y - 10/3 = 5/2

(-5/2)y = 25/6

y = -5/12

Substituting y = -5/12 and z = -5/3 into any of the original equations, we get:

x + y + z = 4

x - 5/12 - 5/3 = 4

x = 29/12

Therefore, the solution is (x, y, z) = (29/12, -5/12, -5/3). However, if we substitute these values into any of the original equations, we will find that it does not satisfy the equation. For example:

2x + 5y - 2z = 3

2(29/12) + 5(-5/12) - 2(-5/3) = 3

29/6 - 5/2 + 5/3 ≠ 3

Since there is no solution that satisfies all three equations, the system is inconsistent.

Step-by-step explanation:

Answer:

See below for proof.

Step-by-step explanation:

A system of equations is not consistent when there is no solution or no set of values that satisfies all the equations simultaneously. In other words, the equations are contradictory or incompatible with each other.

Given system of equations:

\(\begin{cases}x+y+z = 4\\2x+5y-2z =3\\x+7y-7z =5\end{cases}\)

Rearrange the first equation to isolate x:

\(x=4-y-z\)

Substitute this into the second equation to eliminate the term in x:

\(\begin{aligned}2x+5y-2z&=3\\2(4-y-z)+5y-2z&=3\\8-2y-2z+5y-2z&=3\\-2y-2z+5y-2z&=-5\\5y-2y-2z-2z&=-5\\3y-4z&=-5\end{aligned}\)

Subtract the first equation from the third equation to eliminate x:

\(\begin{array}{cccrcrcl}&x&+&7y&-&7z&=&5\\\vphantom{\dfrac12}-&(x&+&y&+&z&=&4)\\\cline{2-8}\vphantom{\dfrac12}&&&6y&-&8z&=&1\end{aligned}\)

Now we have two equations in terms of the variables y and z:

\(\begin{cases}3y-4z=-5\\6y-8z=1\end{cases}\)

Multiply the first equation by 2 so that the coefficients of the variables of both equations are the same:

\(\begin{cases}6y-8z=-10\\6y-8z=1\end{cases}\)

Comparing the two equations, we can see that the coefficients of the y and z variables are the same, but the numbers they equate to is different. This means that there is no way to add or subtract the equations to eliminate one of the variables.

For example, if we subtract the second equation from the first equation we get:

\(\begin{array}{crcrcl}&6y&-&8z&=&-10\\\vphantom{\dfrac12}-&(6y&-&8z&=&\:\:\;\;\:1)\\\cline{2-6}\vphantom{\dfrac12}&&&0&=&-11\end{aligned}\)

Zero does not equal negative 11.

Since we cannot eliminate the variable y or z, we cannot find a unique solution that satisfies all three equations simultaneously. Therefore, the system of equations is inconsistent.

The distance between point P and line L is 16/9√(13).

To find the distance between point P and line L, we can use the formula for the distance between a point and a line in two-dimensional space. The formula is as follows:

Let P = (x1, y1) be the point and L be the line ax + by + c = 0. Then the distance between P and L is:

|ax1 + by1 + c|/√(a² + b²)

To find a, b, and c for the given line, we need to put it in slope-intercept form y = mx + b by solving for y.

2x - 3y = 12=> 2x - 12 = 3y=> (2/3)x - 4 = y

The slope of the line, m, is the coefficient of x, which is 2/3. Therefore, the line is:

y = (2/3)x - 4The values of a, b, and c are: a = 2/3b = -1c = -4

Now we can substitute the coordinates of P and the values of a, b, and c into the formula for the distance between a point and a line.

Let P = (3, 5).|a(3) + b(5) + c|/√(a² + b²)= |(2/3)(3) - 1(5) - 4|/√[(2/3)² + (-1)²]= |-4/3 - 4|/√(4/9 + 1)= 16/9√(13).

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Answer:

Since the difference between the value for each year is constant, this is an arithmetic sequence.

Step-by-step explanation:

Year 2 - Year 1 = 21,750 - 20,000 = 1,750

Year 3 - Year 2 = 23,500 - 21,750 = 1,750

Year 4 - Year 3 = Year 5 - Year 4 = 1,750

Answer:

11 minutes

Step-by-step explanation:

Because she types only 140 words in 4 minutes so if you add

140+140=280

if you divide

140/4 you get 35

so every minute she types in 35 words. So multiply

11 times 35 and you exactly get 385.

Answer:

11 min

Step-by-step explanation:

140 ÷ 4

= 35 which is the amount of words that she types in 1 min.

385 ÷ 35

= 11

so it will take Jenna 11 min to type 385 words.

#a

#b

That be x and y

So

So

from eq(1)

Put in second one

Put in third one

Take it positive

Answer:

(a) (i)  Factorize \(\sf 4p-6pq+9q-6\)

Rewrite by swapping the order of the first two terms:

⇒ -6pq + 4p + 9q - 6

Factorize the first two terms and the last two terms separately:

⇒ -2p(3q - 2) + 3(3q - 2)

Factor out the common term (3q - 2):

⇒ (3q - 2)(-2p + 3)

(ii)

Square of the binomial: \((a+b)^2=a^2+2ab+b^2\)

Rewrite \(9.9\) as \(10 - 0.1\)

Therefore, \(a = 10\) and \(b = -0.1\)

Also, remember that multiplying a number by 0.1 is the same as dividing it by 10.  (when dividing a decimal number by 10, simply move the decimal point 1 place to the left).

\(\begin{aligned}\implies 9.9^2 & =(10-0.1)^2\\ & =10^2-2 \cdot 10 \cdot 0.1+0.1^2\\& = 100-\dfrac{2 \cdot 10}{10}+\dfrac{0.1}{10}\\& =100-2+0.01\\ & =98 + 0.01\\ & = 98.01\end{aligned}\)

(b) (i)

Let x = number of motor bicycles

Let y = number of cars

Given:

⇒ x + y = 15

Given:

⇒ 2x + 4y = 64

(ii)  Rewrite   x + y = 15  to make x the subject:

⇒ x = 15 - y

Substitute into 2x + 4y = 64  and solve for y:

⇒ 2(15 - y) + 4y = 64

⇒ 30 - 2y + 4y = 64

⇒ 30 + 2y = 64

⇒ 2y = 34

⇒ y = 17 cars

Substitute found value of y into  x = 15 - y  to find x:

⇒ x = 15 - 17 = -2 motorbikes

**There must be an error in the question, as with the given information, the number of motorbikes is -2, which is impossible.**

Here are the possible combinations of number of motorbikes (M) and number of cars (C) whose sum of tires is 64.  As you can see, there is no combination that sums to 15 vehicles:

0 M +  16 C = 16 vehicles

2 M +  15 C = 17 vehicles

4 M +  14 C = 18 vehicles

6 M +  13 C = 19 vehicles

8 M +  12 C = 20 vehicles

10 M +  11 C = 21 vehicles

12 M +  10 C = 22 vehicles

14 M +  9 C = 23 vehicles

16 M +  8 C = 24 vehicles

18 M +  7 C = 25 vehicles

20 M +  6 C = 26 vehicles

22 M +  5 C = 27 vehicles

24 M +  4 C = 28 vehicles

26 M +  3 C = 29 vehicles

28 M +  2 C = 30 vehicles

30 M +  1 C = 31 vehicles

32 M +  0 C = 32 vehicles

Answer:

Option H

Step-by-step explanation:

y = 3x - 4

this is the correct answer.

Answer:

H- y=3x-4

The reason I answered this is because the equations are in slope-intercept format (y=mx+b), the slope(m), is 3. The y intercept(b) is -4. Hope this helped :)

Answer:

x= -4

Step-by-step explanation:

−2(4x+4)−3x−2=34

(−2)(4x)+(−2)(4)+−3x+−2=34(Distribute)

−8x+−8+−3x+−2=34

(−8x+−3x)+(−8+−2)=34(Combine Like Terms)

−11x+−10=34

−11x−10=34

−11x−10+10=34+10

−11x=44

−11x /−11  =  44 /−11

x=−4

\(\text{First term,}~ a = 8\\\\\text{Common ratio,}~ r= \dfrac{32}8 = 4\\\\\text{nth term} = ar^{n-1} \\\\\text{9th term} = 8\cdot 4^{9-1}\\\\\\~~~~~~~~~~~~~=8 \cdot 4^8\\\\\\~~~~~~~~~~~~~=524288\\\\\text{The 9th of the geometric sequence is 525288.}\)

9514 1404 393

Answer:

  (x, y) = (1, 8)

Step-by-step explanation:

A graphing calculator quickly tells you the point of intersection.

__

You can equate the y-values and solve for x.

  3x +5 = -2x +10

  5x = 5 . . . . . . . . . add 2x-5

  x = 1 . . . . . . . divide by 5

  3·1 +5 = y = 8 . . . . substitute for x in the first equation

The point of intersection is (x, y) = (1, 8).

Answer:

the answer would be 80 because it is divisible with all the numbers shown above

The Propositions are resulting

(a) ∀x∃y(x = y²) is False

(b) ∀x∃y(x² = y) is True.

(c) ∃x∀y(xy = 0) is True.

(d) ∀x∃y(x + y = 1) is True.

(a) ∀x∃y(x = y²)

This proposition states that for every x, there exists a y such that x is equal to y². To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any positive value for x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4 = 2². Similarly, if x = 9, then y = 3 satisfies the equation since 9 = 3².

Therefore, the proposition (a) is false.

(b) ∀x∃y(x² = y)

For any given positive or negative value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 4, then y = 2 satisfies the equation since 4² = 2. Similarly, if x = -4, then y = -2 satisfies the equation since (-4)² = -2.

Therefore, the proposition (b) is true.

(c) ∃x∀y(xy = 0)

The equation xy = 0 can only be satisfied if x = 0, regardless of the value of y. Therefore, there exists an x (x = 0) that makes the equation true for every y.

Therefore, the proposition (c) is true.

(d) ∀x∃y(x + y = 1)

To determine the truth value, we need to check if this statement holds true for every value of x.

If we take any value of x, we can find a corresponding value of y that satisfies the equation.

For example, if x = 2, then y = -1 satisfies the equation since 2 + (-1) = 1. Similarly, if x = 0, then y = 1 satisfies the equation since 0 + 1 = 1.

Therefore, the proposition (d) is true.

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The unknown length in the rectangle is ? = 8cm

We we want to find the unknown length.

First, if we look just at the pink and yellow rectangles we can see that these have a combined area of:

A = 12cm² + 18cm²

A = 30cm²

And we know that one side measures 6cm, then the length of AD is:

AD*6cm = 30cm²

AD = 30cm²/6cm

AD = 5cm

Now, the yellow and purple rectangles have a combined area of:

A = 18cm² + 22cm² = 40cm²

Then we can write:

?*AD = 40cm²

?*5cm = 40cm²

? = 40cm²/5cm

? = 8cm

That is the unknown lenght.

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Answer:

It's C buddy

Step-by-step explanation:

Answer:

I got :

Step-by-step explanation:

see attached photo

Step-by-step explanation:

The angle of an equilateral triangle is 180°, and its three internal angles are equal, all being 60°.

The time Jack left Santa Clara is 1 : 55 pm

A word problem in math is a math question written as one sentence or more. These statements are interpreted into mathematical equation or expression.

The time for Jack to walk to lose Altos is 25 min and he uses another 25mins to work to Palo alto.

Therefore, the total time he spent is

25mins + 25 mins = 50 mins

He arrived Palo at 2 :45 pm, therefore the time he left Santa Clare will be ;

2:45 pm = 14 :45

= 14:45 - 50mins

= 13:55

= 1 : 55pm

Therefore he left at 1:55 pm

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Answer:

To pass the test, a student must correctly answer at least 0.6 or 60% of the questions.

Donald's score is 5/8, which can be simplified to 0.625. Since this is greater than 0.6, Donald passes the test.

Karen's score is 0.88, which is greater than 0.6, so Karen passes the test.

Geno's score is 3/5, which can be simplified to 0.6. Since this is equal to 0.6, Geno passes the test.

Ciara's score is 4/5, which can be simplified to 0.8. Since this is greater than 0.6, Ciara passes the test.

Therefore, all the students pass the test.