Find the midpoint of points A(-10,3) and B(-7,-4) graphically .

The value of the seventh half-life for this reaction is 1134 seconds.

A first-order reaction is a type of reaction where the rate of reaction is directly proportional to the concentration of the reactant. The half-life of a reaction is the time it takes for half of the reactant to be consumed.

Given that the first half-life of the reaction is 162 seconds, we can use this information to calculate the value of the seventh half-life.

To do this, we can use the formula for the half-life of a first-order reaction:

t1/2 = (0.693 / k)

where t1/2 is the half-life and k is the rate constant of the reaction.

By rearranging the formula, we can solve for the rate constant:

k = 0.693 / t1/2

Now, we can use the rate constant to find the seventh half-life. Since each half-life is the same duration, we can multiply the first half-life by 7 to get the seventh half-life:

seventh_half_life = 7 * 162 seconds

Calculating this gives us:

seventh_half_life = 1134 seconds

Therefore, the value of the seventh half-life for this reaction is 1134 seconds.

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When the two pith balls are pulled apart, the potential energy of the system rises. This is due to the electrostatic force of repulsion, which is activated when the two pith balls have opposing charges and repel one another.

The two pith balls are pushed apart, and the energy required to do so is stored in the system as potential energy, in accordance with the law of conservation of energy.

This explains why pulling apart the two pith balls increases the system's potential energy. E = qV, where q is the charge on the pith ball and V is the potential difference between the two pith balls, may be used to compute the system's potential energy.

while the two When pith balls are pulled apart, the potential difference between them grows, increasing the system's potential energy. The rise in potential energy is also caused by the electrostatic force of repulsion between the two pith balls. This is due to the fact that when the two pith balls are dragged apart, the electrostatic force of repulsion between them grows, increasing the system's potential energy.

This explains why pulling apart the two pith balls increases the system's potential energy.

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Answer:

Virus is living due to reproduction and non-living due to crystal appearance.

Explanation:

Characteristics that viruses display is the ability of reproduction in which they increase in population which is a living character and have DNA or RNA which help them to make exact copies of itself. Virus is parasitic in nature because it causes harm to the living host such as humans, animals and plants. Some characteristics that viruses don't display are that they are not like living cells, have no membrane around them, no organelles such as mitochondria, golgi bodies, endoplasmic reticulum and lysosomes etc. Viruses are present in crystal form outside the cell.

Answer:

• Abogado

• Administrador o conservacionista de campo

• Agrícola o agrónomo

• Apiculturísta

• Arquitecto

• Arquitecto ambiental

• Asistente de investigación

• Astrónomo

• Bioquímico

• Científico animal

• Científico avícola

• Científico de suelo

• Consejero vocacional

• Contador

• Criador animal

• Economista

• Entomólogo

• Epidemiólogo

• Farmacólogo

• Físico

• Fitogenetista

• Forestal

• Genetista

• Geoquímico

• Geofísico

• Horticultor

• Ingeniero

• Matemático (incluyendo estadístico)

• Meteorólogo

• Nutriólogo

• Profesor

• Químico

• Silviculturiasta (incluyendo forestalista)

• Terapeuta recreativo

• Topógrafo

• Trabajador social

• Urbanista (incluyendo geógrafo)

• Zoologísta

• Técnico científico de cualquiera de las siguientes disciplinas: ciencias agrícolas, astronomía, biología, química, ingeniería, silvicultura, geología, geofísica, meteorología o física

Explanation:

Answer:

The new volume is 5.0L

Explanation:

Given:

Initial pressure (P₁) = 1.4 atm

Initial volume (V₁) = 2.3 L

Final pressure (P₂) = 0.65 atm

We'll use Boyle's Law:

P₁V₁ = P₂V₂

Substituting the given values:

(1.4 atm)(2.3 L) = (0.65 atm)(V₂)

Now, let's solve for V₂:

V₂ = (1.4 atm * 2.3 L) / 0.65 atm

Calculating this expression step-by-step:

V₂ = (3.22 atm·L) / 0.65 atm

V₂ ≈ 4.953 L

Rounded to one decimal place, the new volume is approximately 5.0 L.

Answer:

100g

Explanation:

The amount of sugar in the beaker still remains 100g. There is no addition or loss of any quantity of sugar unit.

Physical and chemical changes obey and complies with the law of conservation of matter.

The law suggests that matter is neither created nor destroyed but can be changed from one form to another.

Answer:

It is used to make black gunpowder and also to make sulfuric acid which is used in batteries, fertilizers, etc...

Explanation:

It is used to make black gunpowder and also to make sulfuric acid which is used in batteries, fertilizers, etc..

Answer:

Calcium carbonate

Explanation:

Hope this helps :)

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Answer:

The answer would be C.

Explanation:

I took a test with the same question.

The activation energy is very high. Hence, option C is correct.

Activation energy is the sufficient amount of energy necessary to initiate a chemical reaction.

When sodium hydroxide (NaOH) dissolves in water, it is distributed into positively-charged sodium ions and negatively - charged hydroxide ions.

These cations and anions move around in the water, free and independent of each other, though cations tend to be surrounded more closely by anions and vice versa.

Hence, when sodium hydroxide and water will react at room temperature, the activation energy is very high.

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Step 1 - Brief revision of Boyle's Law

Boyle's law is a law concerning the behavior of gases. It states that the pressure and the volume are inversely proportional given that the temperature is kept constant.

That is, if we increase the pressure, the volume will decrease. This principle is behind the proper functioning of our lungs, for example. This can also be described mathematically as:

Step 2 - Choosing the right alternative

As we have seen in step 1, we can use the following formula to work with Boyle's Law:

Therefore, the correct alternative is item d.

Answer:

Catabolic reactions

Explanation:

Anabolic reactions combine monosaccharides to form polysaccharides, fatty acids to form triglycerides, amino acids to form proteins, and nucleotides to form nucleic acids. These processes require energy in the form of ATP molecules generated by catabolic reactions.

Respuesta:

16,7 mL

Explicación:

Paso 1: Información provista

Paso 2: Calcular el volumen de la solución concentrada

Queremos preparar una solución diluida de hipoclorito de sodio a partir de una concentrada. Podemos calcular el volumen inicial que debemos tomar usando la regla de dilución.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0,5% × 200 mL / 6% = 16,7 mL

The 3 examples of metaphors: 1. life is a dual carriageway. 2. Her eyes were diamonds.3. he is a shining big name.

A metaphor is discernment of speech that, for rhetorical effect, directly refers to 1 thing by bringing up another. it may provide clarity or become aware of hidden similarities between two one-of-a-kind thoughts. A metaphor is a discernment of speech that describes an item or movement in a manner that isn't always actually genuine but helps explain a concept or make an assessment.

See if the sentence makes use of a word inclusive of “as” or “like” as a preposition. that is, it's far from evaluating things explicitly. If it compares matters without the usage of prepositions consisting of “like” or “as” it is a metaphor.

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The true statements regarding metabolism and basal metabolic rate are:

a) Our Basal Metabolic Rate (BMR) is the total amount of calories burned per day by bodily functions and all activities performed. If more calories are burned than consumed, individuals tend to lose weight.

b) Our Basal Metabolic Rate (BMR) tends to drop as we age.

f) Cardiovascular activity and strength training are helpful in preventing weight gain as we age.

g) Our Basal Metabolic Rate (BMR) is the amount of calories burned while simply keeping bodily functions going.

h) The more active our bodies are, the more calories we burn.

These statements accurately reflect the relationship between metabolism, basal metabolic rate, calorie consumption, physical activity, and weight management.

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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Answer:

Volcanologists can predict eruptions if they have a thorough understanding of a volcano's eruptive history, if they can install the proper instrumentation on a volcano well in advance of an eruption, and if they can continuously monitor and adequately interpret data coming from that equipment.

Explanation:

We have a total of 9.27 moles of the molecule that weights 134.1 g/mol.

The molecular mass of the molecule is 134.7 g/mol.

The amount of the molecule that we have is 1.25kg.

We know,

1 kilogram = 1000 grams.

1.25 kilograms = 1250 grams.

The mass of the amount of molecule we have is 1250 grams.

The moles of a molecule are given by,

Moles = Mass that we have/molecular mass

Putting the values accordingly,

Moles = 1250/134.7

Moles = 9.27 moles.

So, we have 9.27 moles of that molecule whose molecular mass is 134.1 g/mol.

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According to the nurse preceptor, the new nurse adheres to a number of safe practices while administering red blood cells (RBCs) to a patient.

Based on the given options, the actions that are deemed safe by the nurse preceptor are:

Using large gauge catheters (20-24 gauge). When giving red blood cells (RBCs) to a patient, the novice nurse follows a number of safe procedures, according to the nurse preceptor. To ensure appropriate flushing and lower the chance of an air embolism, the inexperienced nurse correctly primes the intravenous tube with 0.9% sodium chloride in the first step. The second step is for the inexperienced nurse to collect and record a complete set of baseline vital signs. This creates a baseline for monitoring the client's status both before and after the transfusion. Third, in accordance with the advised duration for safe administration, the nurse modifies the infusion rate to administer the RBCs in 4 hours as opposed to 6 hours. Fourth, the inexperienced nurse employs big gauge catheters (20-24 gauge) to promote quick and smooth blood product flow and reduce problems.

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A soluble impurity usually has two effects on the melting point of a compound: an increase in melting point range and a decrease in melting point.

In chemistry, there are two types of impurities: soluble and insoluble.

Soluble impurities are those that dissolve in water quickly and also have a significant impact on the chemical properties of a compound such as a significant increase or decrease in the melting point and boiling point.

For example, salt, milk, and sugar compounds are soluble impurities.

Similarly, insoluble impurities remain undissolved when mixed in water and are also known as suspended impurities.

Examples of insoluble impurities are sand, oil, chalk, rocks, pebbles, etc.

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Answer:

6.022  ×10(index 23) / 7.5 = 0.8293 ×10(index 23)

Explanation:

molar mass of C =  12gmol

therefore in 12g of C there is one mole or an amount of 6.022 ×10(index 23)

∴12g/6.02210(index 23) ×1.6g

The difference between the heat of fusion and the heat of vaporization is that melting only needs a minimal amount of energy to cause molecules to break free from their positions in the crystal lattice while maintaining other molecular interactions.

How is the heat of fusion different from the heat of vaporization?

The energy required for one gram of a solid to melt without experiencing any temperature change is known as the heat of fusion. The amount of energy required for one gram of a liquid to evaporate (boil) without a change in pressure is known as the heat of vaporization.

What happens to heat energy during fusion?

It is possible to heat solids to the point at which the molecules holding their bonds together separate and turn the solid into a liquid. The most typical illustration is when solid ice transforms into liquid water. The molecules within the substance become less structured as a result of this process, which is also known as melting or heat of fusion.

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Answer:

When a solid dissolves the solid (solute) and the liquid (solvent) form a very close intimate mixture called a solution. :)

(Brainliest?)

Explanation:

The acid associated with \(NH_3\) is \(NH_4^+\), with I- is HI, with \(SO_4^{2-}\) is \(HSO_4^-\), with Cl- is HCl, with OH- is \(H_2O\), and with F- is HF.

1. NH3: It is a base that accepts a hydrogen ion (H+) from an acid. \(NH_3 + H^+ --> NH_4^+\). The acid associated with \(NH_3\) is \(NH_4^+\).

2. I-:  is a base that accepts a hydrogen ion (H+) from an acid. \(I^- + H^+ --> HI\) . The acid associated with I- is HI.

3. \(SO_4^{2-}\) : is a base that accepts a hydrogen ion (H+) from an acid. \(SO_4^{2-} + H^+ --> HSO_4^-\). The acid associated with \(SO_4^{2-}\) is \(HSO_4^-\).

4. Cl-: is a base that accepts a hydrogen ion (H+) from an acid. Its conjugate acid is the species formed when Cl- accepts a hydrogen ion (H+). \(Cl^- + H^+ --> HCl\). The acid associated with Cl- is HCl.

5. OH-: It is a base that accepts a hydrogen ion (H+) from an acid. Its conjugate acid is the species formed when OH- accepts a hydrogen ion (H+). \(OH^- + H^+ --> H_2O\). The acid associated with OH- is \(H_2O\).

6. F-:  It is a base that accepts a hydrogen ion (H+) from an acid. \(F^- + H^+ --> HF\).  The acid associated with F- is HF.

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BASIC

bc here:

1,2,3,4,5,6. 7. 8,9,10

The ones in bold are acids.

7 is neutral.

The ones in italic are basic.

The risk assessment team, consisting of various members from different departments within the winery, conducted a comprehensive assessment of the potential risks associated with sulfur dioxide (SO2) and dimethyl dicarbonate (DMDC) operations.

Data was collected regarding the equipment, chemicals, procedures, training, incident history, and physical attributes of the workplace. The team also interviewed employees to gather their experiences, concerns, and suggestions.

After reviewing the collected information, the team identified the potential risks of fatalities or serious incidents related to workplace exposures of SO2 and DMDC. These risks were considered of utmost priority and required immediate control to ensure an acceptable level of safety. The consultant highlighted the importance of addressing these serious risks, as fatality and serious incident rates have not shown a decline and demand serious attention.

Factors contributing to the potential for environmental releases, explosions, and disasters were identified, including unusual and nonroutine work, nonproduction tasks, facility modification or construction activities, shutdowns and startups for repair and maintenance tasks, exposure to high-energy sources (such as electrical, steam, pneumatic, chemical), and situations transitioning from normal to abnormal (upsets).

Based on the assessment and the identified risks, it is crucial for the winery to implement effective control measures to minimize the potential for fatalities, serious incidents, and environmental disasters. These measures may include improving procedures, enhancing operator training, implementing stricter safety protocols, and ensuring proper handling and storage of chemicals.

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Answer:

The removal of this ion from water by the calcifiers will definitely decrease the pH of water.

What is the bicarbonate ion?

The bicarbonate ion is the ion that is designated as HCO3-. We must notice that this ion is present in abundant amounts in the sea. This amount definitely make the sea slightly alkaline.

Now we must note that the removal of this ion from water by the calcifiers that require it to make their shell will definitely decrease the pH of water.

Explanation:

The removal of this ion from water by the calcifiers will definitely decrease the pH of water.

The bicarbonate ion is the ion that is designated as \(HCO^{3-}.\) We must notice that this ion is present in abundant amounts in the sea. This amount definitely makes the sea slightly alkaline.

Now we must note that the removal of this ion from water by the calcifiers that require it to make their shell will definitely decrease the pH of water.

Hence, the removal of this ion from water by the calcifiers will definitely decrease the pH of water.

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Monounsaturated fatty acid has a bend in its structure, which prevents tight packing and makes it liquid at room temperature. Option B is the correct answer.

Monounsaturated fatty acids have one double bond in their hydrocarbon chain, which creates a bend or kink in their structure. This bend prevents the fatty acid molecules from packing tightly together, which in turn lowers the melting point and makes them liquid at room temperature. In contrast, saturated fatty acids have no double bonds and can pack tightly together, which increases the melting point and makes them solid at room temperature.

Trans fatty acids, which have a similar structure to saturated fatty acids, also tend to pack tightly together and have higher melting points. Overall, the degree of unsaturation and the resulting structure of a fatty acid plays a significant role in determining its physical properties. Hence, option B is correct choice.

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Answer:

17 electrons, 17 protons and 18 neutrons

Explanation:

35-Chlorine has 17 Protons, and 18 Neutrons in its Nucleus.

Kilogram (kg) is use for the measurement of mass

1kg = 1000g (gram)

Answer:

option 1

Explanation:

i had a test with same question