Find the midpoint of each segment in Exercise 1 above.Example: The midpoint M between point E and point F is calculatedwith the Midpoint Formula.
Answers
We have to calculate the midpoint for each segment.
To do that we have to calculate the average for the coordinates of each point.
1) For AB, we have A = (-5,8) and B = (-5,6).
We can then calculate the midpoint coordinates as:
\(M_{AB}=(\frac{x_A+x_B}{2},\frac{y_A+y_B}{2})=(\frac{-5+(-5)}{2},\frac{8+6}{2})=(-\frac{10}{2},\frac{14}{2})=(-5,7)\)2) For BC we have B = (-5,6) and C = (-2,6).
The midpoint will be:
\(M_{BC}=(\frac{-5+(-2)}{2},\frac{6+6}{2})=(\frac{-7}{2},\frac{12}{2})=(-\frac{7}{2},6)\)3) For CD we have C = (-2,6) and D = (2,3).
The midpoint will be:
\(M_{CD}=(\frac{-2+2}{2},\frac{6+3}{2})=(\frac{0}{2},\frac{9}{2})=(0,\frac{9}{2})\)4) For DE we have D = (2,3) and E = (2,-1).
The midpoint will be:
\(M_{DE}=(\frac{2+2}{2},\frac{3+(-1)}{2})=(\frac{4}{2},\frac{2}{2})=(2,1)\)5) For EF we have E = (2,-1) and F = (6,0).
The midpoint will be:
\(M_{EF}=(\frac{2+6}{2},\frac{-1+0}{2})=(\frac{8}{2},-\frac{1}{2})=(4,-\frac{1}{2})\)Answer:
AB = (-5,7)
BC = (-7/2,6)
CD = (0,9/2)
DE = (2,1)
EF = (4,-1/2)
Related Questions
Jack wants to buy a coat that costs $74.95. The sales tax rate in his city is 612%
. What is the total cost for the coat? Round to the nearest cent.
Answers
Answer:
The total amount that will be paid for the coat would be; $79.95 to the nearest cent.
Step-by-step explanation:
What is income tax?
Income tax is a tax applied on individuals or entities concerning income or profit earned by them.
Given that Jack wants to buy a coat that costs $74.95. The sales tax rate in his city is 6 and 1/2 percent.
Thus, the total cost for the coat can be calculated as;
The amount that will be paid for the coat will be;
= Amount of shirt + Tax
= $74.95 + (6.5% × $74.95)
= $74.95 + (6.5/100 × $74.95)
= $74.95 + $4.80
= $79.95
The total amount that will be paid for the coat would be; $79.95 to the nearest cent.
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The total cost for the coat is $79.55
The total cost of the coat is the sum of the cost of the coat and the sales tax. To find the sales tax, Jack needs to multiply the cost of the coat by the sales tax rate as a decimal.
$74.95 x 0.0612 = $4.60452
To find the total cost, he would add this amount to the cost of the coat:
$74.95 + $4.60452 = $79.55452
Rounding to the nearest cent , the total cost of the coat is $79.55. It means Jack has to pay $79.55 including the sales tax, which is $4.60452 on the original price of $74.95 for the coat.
The total cost of the coat is $79.55.
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Solve for x.
8x - 4 = 2x - 3
Answers
8x-4=2x-3
One solution was found :
x = 1/6 = 0.167
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
8*x-4-(2*x-3)=0
Step by step solution :
Step 1 :
Solving a Single Variable Equation :
1.1 Solve : 6x-1 = 0
Add 1 to both sides of the equation :
6x = 1
Divide both sides of the equation by 6:
x = 1/6 = 0.167
One solution was found :
x = 1/6 = 0.167
i am not solving for x i am solving for you lol!!!
At the grocery store, Jamir bought a box of 12 Snickers Bars for $11.50. How much did he pay for each candy bar?
Answers
Answer:
138
Step-by-step explanation:
$ 11.50 x 12 = 138
because you have to divide
How do I get the answer for 20×5000
Answers
Answer:
100000!
Step-by-step explanation:
Answer:
20×5000=100,000
Step-by-step explanation:
5000
× 20
----------
0000
10,000
-------------
100,000
-------------
If ST=17 and RT=41, find RS. Use the number line below.
Answers
The length of segment RS is given as follows:
RS = 24.
What does the angle addition postulate state?The angle addition postulate states that if two or more angles share a common vertex and a common angle, forming a combination, the measure of the larger angle will be given by the sum of the measures of each of the angles.
The segment RT is the combination of segments RS and ST, hence:
RT = RS + ST.
Hence the length of segment RS is given as follows:
41 = RS + 17
RS = 24.
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if the grass is wet, then the grass is dry true or false?
Answers
Evaluate the expression for the given value of the variable. −9x − 8, when x = −6
Answers
Answer:
46
Step-by-step explanation:
The expression is:
● -9x - 8
Replace x by -6 to evaluate the expression when x = -6
● -9 ×(-6) - 8
● 54-8
● 46
Answer:
\(\huge\boxed{46}\)
Step-by-step explanation:
-9x - 8, when x = -6
Substitute in -6 for x in the expression
-9x - 8
-9(-6) - 8
Multiply -9 * -6
54 - 8
Subtract
\(\huge\boxed{46}\)
Hope this helps :)
-1/6(2x + 12) = 1/3x + 12
Answers
X=-21
Evaluate: Question(2): Z+8-6(z-2a)+5z
Answers
Answer:
Z+12a−z+8+12−+8
Step-by-step explanation:
Z+8−6(z−2a)+5z
+8−6(−2)+5
Z+8−6(−2a+z)+5z
+8−6(−2+)+5
Z+8−6(−2a+z)+5z
+8−6(−2+)+5
Z+8+12a−z+8+12−
Answer:
Z + 8 + 12a − z
12a + 8
Step-by-step explanation:
he following problems add in a minimal threshold value for the species to survive, T, which changes the differential equation to
P't = rp(1-P/K) (1-T/P)
Bengal tigers in a conservation park have a carrying capacity of 100 and need a minimum of 10 to survive. If they grow in population at a rate of 1% per year, with an initial population of 15 tigers, solve for the number of tigers present.
Answers
the solution for the number of tigers present over time is given by:
P - (P^2)/(2K) - (T/K)P + (T/K)ln(P) = rt + 11.375 + 0.1ln(15)
To solve the given differential equation for the population of Bengal tigers in the conservation park, we'll use the given parameters and initial conditions.
The differential equation for the population (P) is:
P't = rp(1 - P/K)(1 - T/P)
Given:
Carrying capacity (K) = 100
Minimum threshold value for survival (T) = 10
Population growth rate (r) = 1% = 0.01 (per year)
Initial population (P0) = 15
Now, let's solve the differential equation to find the number of tigers present over time.
Separating variables, we have:
(1 - P/K)(1 - T/P) dP = rp dt
Integrating both sides:
∫ (1 - P/K)(1 - T/P) dP = ∫ rp dt
Let's evaluate the integral on the left side:
∫ (1 - P/K)(1 - T/P) dP = ∫ (1 - P/K - T/K + T/(KP)) dP
= ∫ (1 - P/K) - (T/K) + (T/PK) dP
= P - (P^2)/(2K) - (T/K)P + (T/K)ln(P) + C1
On the right side, we have:
∫ rp dt = rt + C2
Combining both sides and simplifying, we have:
P - (P²2)/(2K) - (T/K)P + (T/K)ln(P) + C1 = rt + C2
To solve for the constants C1 and C2, we use the initial condition P(0) = P0:
P0 - (P0²2)/(2K) - (T/K)P0 + (T/K)ln(P0) + C1 = r(0) + C2
P0 - (P0²2)/(2K) - (T/K)P0 + (T/K)ln(P0) + C1 = C2
Substituting the given values:
15 - (15²2)/(2×100) - (10/100)×15 + (10/100)ln(15) + C1 = C2
15 - (225/200) - (150/100) + (10/100)ln(15) + C1 = C2
15 - 1.125 - 1.5 + 0.1ln(15) + C1 = C2
Simplifying further, we have:
12.375 + 0.1ln(15) + C1 = C2
Now we have the general solution:
P - (P²2)/(2K) - (T/K)P + (T/K)ln(P) = rt + C
Using the initial condition P(0) = 15, we can solve for C:
15 - (15²2)/(2×100) - (10/100)×15 + (10/100)ln(15) = r(0) + C
15 - 1.125 - 1.5 + 0.1ln(15) = C
11.375 + 0.1ln(15) = C
Therefore, the solution for the number of tigers present over time is given by:
P - (P²2)/(2K) - (T/K)P + (T/K)ln(P) = rt + 11.375 + 0.1ln(15)
This is the general solution for the population of Bengal tigers in the conservation park.
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work out the value of 3*10-5*40000000 give your answer in standard form
Answers
Answer:
3*10 - 5*4000000.
= 30 - 200000000
= 199999970
Step-by-step explanation:
(3×10)-(5×40000000)
=30-200000000
=-199 999 970
At a factory, two machines pack bottles into boxes for shipping. Machine A can pack 8 boxes per minute, and Machine B can pack 11 boxes per minute. Both machines have been packing boxes for some time, and the difference between the number of boxes that Machine B has packed and the number of boxes that Machine A has packed is less than 200. Write and solve an inequality to find the possible lengths of time to the nearest second that the machines have been working. Describe the possible solutions.
Answers
Answer:
Let's let t be the time in minutes that both machines have been working. Then, the number of boxes packed by Machine A in t minutes is 8t, and the number of boxes packed by Machine B in t minutes is 11t.
The difference between the number of boxes packed by Machine B and Machine A is less than 200, so we can write the following inequality:
11t - 8t < 200
Simplifying, we get:
3t < 200
Dividing both sides by 3, we get:
t < 200/3
To the nearest second, this is approximately 66.67 seconds.
Therefore, the possible lengths of time that the machines have been working is t < 66.67 seconds.
Note that this inequality only gives us an upper bound on the time that the machines have been working, since we know that the difference between the number of boxes packed by Machine B and Machine A is less than 200. We do not have any information on the minimum time that the machines have been working, so there are infinitely many possible solutions that satisfy the given conditions.
Step-by-step explanation:
What is the value of t in this equation?
Answers
Answer:
t = 60
Step-by-step explanation:
Exponents by the power of another exponent multiply.
-12 · -5 = 60
So in this instance, the value of t would be 60.
1 Given a parameter k, we are given a discrete signal x; of duration N and taking valuesx(n) = &**/N for n = 0,1,...,N — 1. What is the relationship between the signals x; andXt. ? Explain mathematically (1 point). What is the relationship between x and x ¢. Explainmathematically (1 point).
Answers
The signal x; is a discrete signal with N samples and taking values x(n) = &**/N for n = 0,1,...,N-1. The signal Xt is the discrete Fourier transform of x; and is given by:
Xt(k) = Σn=0N-1 x(n) exp(-i2πnk/N)
This means that the Fourier transform of x(n) gives us a set of coefficients, Xt(k), that represent the contribution of each frequency, k, to the original signal x(n). In other words, the relationship between the signals x; and Xt is that Xt is a frequency-domain representation of x;.
The relationship between x and x ¢ is that x ¢ is the complex conjugate of x. This means that if x(n) = a + bi, then x ¢(n) = a - bi. In terms of the Fourier transform, this means that if X(k) is the Fourier transform of x(n), then X ¢(k) is the complex conjugate of X(k). Mathematically, this can be expressed as:
X ¢(k) = Σn=0N-1 x(n) exp(i2πnk/N)
So, the relationship between x and x ¢ is that they are complex conjugates of each other, and the relationship between their Fourier transforms, X(k) and X ¢(k), is that they are also complex conjugates of each other.
Hi! I understand that you want to know the relationship between signals x and x_t, as well as x and x', given a parameter k and a discrete signal x of duration N with values x(n) = &**/N for n = 0, 1, ..., N-1.
1. Relationship between x and x_t:
Assuming x_t is the time-shifted version of the signal x by k units, we can define x_t(n) as the time-shifted signal for each value of n:
x_t(n) = x(n - k)
Mathematically, the relationship between x and x_t is represented by the equation above, which states that x_t(n) is obtained by shifting the values of x(n) by k units in the time domain.
2. Relationship between x and x':
Assuming x' is the derivative of the signal x with respect to time, we can define x'(n) as the difference between consecutive values of x(n):
x'(n) = x(n + 1) - x(n)
Mathematically, the relationship between x and x' is represented by the equation above, which states that x'(n) is the difference between consecutive values of the discrete signal x(n), approximating the derivative of the signal with respect to time.
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Can someone help me I dont know what to do
Answers
Step-by-step explanation:
1. find P of semicircle
perimeter of a semicircle = pi×r+d
=3.14×5+10
=25.7
2.find P of rectangle
P=10×4=40cm
3. add P of semicircle and P of rectangle
25.7+40=65.7cm
Write your Geometry Statement.
If PQ = 6x - 1 and PR = 15x - 29,
then QR = ?
Answers
Answer:
QR = 21x - 30
Step-by-step explanation:
Iff Q - P - R,
Then
QR = PQ + PR
QR = 6x - 1 + 15x - 29
QR = 21x - 30
How do you calculate the x-intercept of a line written in Standard Form?
Answers
y=0 , solve for x
x=0 , solve for y
Here is an example: (solving for x)
2x + 3y = 6
2x + 3(0) = 6
2x = 6
2x/2 = 6/2
x = 3
Here is an example: (solving for y)
2x + 3y = 6
2(0) + 3y = 6
3y = 6
3y/3 = 6/3
y = 2
Cam used 2/3 of the flour from a 5-lb bag to make all of her holiday cookies. How much flour, in pounds, is left in the bag?
Answers
Answer:
3.3lbs
Step-by-step explanation:
5 x 2/3 = 3.3
min 8x₁ + 6x₂ subject to
a. 4x₁ + 2x₂ ≥ 20
b. −6x₁ + 4x₂ ≤ 12
c. x₁ + x₂ ≥ 6
d. x₁ + x₂ ≥ 0
Answers
The minimum value of the objective function subject to the given constraints is 48 and it occurs at (6,0).
The given problem is:
min 8x₁ + 6x₂ subject to4x₁ + 2x₂ ≥ 20−6x₁ + 4x₂ ≤ 12x₁ + x₂ ≥ 6x₁ + x₂ ≥ 0
The feasible region is as follows:
Firstly, plot the following lines:4x₁ + 2x₂ = 20-6x₁ + 4x₂ = 12x₁ + x₂ = 6x₁ + x₂ = 0On plotting, the following graph is obtained:
Now, let's check each option one by one:
a. 4x₁ + 2x₂ ≥ 20
The feasible region is the region above the line 4x₁ + 2x₂ = 20.
b. −6x₁ + 4x₂ ≤ 12
The feasible region is the region below the line −6x₁ + 4x₂ = 12.c. x₁ + x₂ ≥ 6
The feasible region is the region above the line x₁ + x₂ = 6.d. x₁ + x₂ ≥ 0
The feasible region is the region above the x-axis.
Now, check the point of intersection of the lines.
They are:(10,0),(2,4),(6,0)The point (2,4) is not in the feasible region as it lies outside it.
Therefore, we reject this point.
The other two points, (10,0) and (6,0) are in the feasible region.
Now, check the values of the objective function at these two points.
Objective function value at (10,0): 80
Objective function value at (6,0): 48
Therefore, the minimum value of the objective function subject to the given constraints is 48 and it occurs at (6,0).
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Please help there is no word problem.
5 − a + 4a =
Answers
5-a+4a
=5+3a
answer this question please
Answers
Answer:
[SHOWN IN IMAGE]
Step-by-step explanation:
I have done the simplifying work only... sorry
Simplify;
4x + 5xy – 3x² – 6xy + 6
= – xy – 3x² + 4x + 6
__o__o__
3x + 2x(x+2) – 6x²
= 3x + 2x² + 4x – 6x²
= – 4x² + 7x
___o__o__
(6a + 2b - 3c ) - ( 4a - 4b + 9c + 12 )
(6a + 2b - 3c ) + ( - 4a + 4b - 9c - 12 )
= 2a + 6b – 12c - 12
___o___o__
Subtract ( 3y + xy ) from ( - 5y + 12xy)
Ans; ( – 5y + 12xy ) – (3y + xy)
( – 5y + 12xy ) + ( - 3y - xy)
= – 8y + 11 xy
= 11xy – 8y
___o___o___
Find the product of 6ab and –3a²b³
\((6ab) \times ( - 3 {a}^{2} {b}^{3} ) = - 18 {a}^{3} {b}^{4} \)
___o___o__
\(( - 3 {x}^{2} y) \times (4 {x}^{2} y - 3x {y}^{2} + 4x - 5y) \\ \\ = - 12 {x}^{4} {y}^{2} + 9 {x}^{3} {y}^{3} - 12 {x}^{3} y + 15 {x}^{2} {y}^{2} \)
___o___o___
Example 1; Ans ;
perimeter of triangle = Length of the first side + Length of the second side + Length of the third side
perimeter of triangle = A + B + C
4x² + 17xy + 5 = ( 5xy -3x² ) + ( x² + 5xy - 2 ) + c
4x² + 17xy + 5 = - 2x² + 10xy - 2 + c
c = (4x² + 17xy + 5 ) – ( - 2x² + 10xy - 2)
c = (4x² + 17xy + 5 ) + ( 2x² - 10xy + 2)
c = 6x² + 7xy + 7
So; Length of the third side = ( 6x² + 7xy + 7 )
___o___o___
Example 2 ; Ans;
To find the length of the smallest part, we must subtract the total length from the length of the largest part .
Total length = The length of the largest part + The length of the smallest part
The length of the smallest part = Total length – The length of the largest part
The length of the smallest part = ( 5mn – 2n +1 ) – ( 3mn +n )
The length of the smallest part = ( 5mn – 2n +1 ) + ( – 3mn – n )
The length of the smallest part = 2mn – 3n +1
So ; the length of the smallest part = ( 2mn – 3n + 1 )
I hope I helped you^_^
What are the zeroes of the function?
y = (x – 3)(x + 2)(x – 2)
A. –3, 2, –2
B. –3, 2, 2
C. 3, –2, 2
D. 3, 2, 2
Answers
Answer:
Option C
Step-by-step explanation:
x - 3 = 0
Add 3 to both sides;
x = 3
x + 2 = 0
Subtract 2 from both sides;
x = -2
x - 2 = 0
Add 2 to both sides;
x = 2
Calculate the test statistic 2
A local retailer currently schedules employees based on the assumption that they serve customers uniformly throughout the week (the same number each day). Management is starting to question this assumption and decides to collect data on the number of customers served each day of the week to
perform a Chi-Square goodness-of-fit test at a 5% significance level.
Monday Tuesday Wednesday Thursday Friday
Number Served 40 33 35 32 60
Total 200
Provided the assumptions of the test are satisfied, calculate the test statistic 2
Answers
The value of a Chi-Square goodness-of-fit test at a 5% significance level is 13.45
We need to perform a Chi-Square goodness-of-fit test at a 5% significance level.
First we need to calculate the expected count
expected value = ∑(x)/n
= (40 + 33 + 35 + 32 + 60)/5
= 200/5
= 40
Now we need tocalculate the test statistic value
Observed expected O - E (O - E)^t/E %
40 40 0 0 0
33 40 -7 1.225 9.11
35 40 -5 0.625 4.65
32 40 -8 1.6 11.90
60 40 20 10 74.35
Chi square test is 13.45
Therefore, the value of test statistics is 13.45.
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Stone runs 1 mile five times a week. How many miles does 4 he run each week? Write the equation you would use to solve. Then, fill in the grid with your answer. Tip: Fill in your answer as a fraction greater than 1.
Answers
The number of miles in 4 weeks is 20 mules
How to determine the number of milesFrom the question, we have the following parameters that can be used in our computation:
Stone runs 1 mile five times a week
This means that the rate is
Rate = 1 mile * 5 per week
So, we have
Rate = 5 miles per week
For 4 weeks, we have
Distance = 5 * 4
Evaluate
Distance = 20 miles
Hence, the distance is 20 miles
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Please help me answer these two questions!! Brainliest to be given!!
Answers
Answer:
a=2
b=93
I hope this helps you
Step-by-step explanation:
Answer:
1. 2
2. 93
Step-by-step explanation:
First we have to put the values of x and y into the equation
4(3)-2(5)
(4×3)-(2×5)
12-10=2
Now the second one
2(3)²+3(5)²
18+75=93
4PLEASE HELP ME THIS IS URGENT I WILL GIVE BRAINLIEST
Answers
Answer:
9.3 ft
Step-by-step explanation:
What is the justification for step 2 in the solution process? 12 − x = 7x + 32 Step 1: -x = 7x + 20 Step 2: -8x = 20
A. the division property of equality
B.the addition property of equality
C. the subtraction property of equality
D. the multiplication property of equality
Answers
Answer:
C. the subtraction property of equality
Step-by-step explanation:
given
12 − x = 7x + 32
Subtract 12 from each side using the subtraction property of equality
Step 1: -x = 7x + 20
Subtract -7x from each side using the subtraction property of equality
Step 2: -8x = 20
Consider a circle whose equation is x2 + y2 – 2x – 8 = 0. Which statements are true? Select three options. The radius of the circle is 3 units. The center of the circle lies on the x-axis. The center of the circle lies on the y-axis. The standard form of the equation is (x – 1)² + y² = 3. The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9.
Answers
Answer:
A, B, F
- The radius of the circle is 3 units
- The center of the circle lies on the x-axis
- The radius of this circle is the same as the radius of the circle whose equation is x² + y² = 9
Step-by-step explanation:
The first option is correct because the standard equation of the circle is:
\((x - 1)^{2} + {y}^{2} = 9\)
making the radius equal to 3.
The center is at (-1,0), therefore it lies on the x-axis.
And lastly, the last option is correct because both options have the radius of 3.
Which of the following are assumptions underlying the simple linear regression model y = Bo B1x e? Check all that apply The variance of the error term e varies for differing values of x. The error term is a random variable with an expected value of zero. The error term is normally distributed. The error term E follows a chi-square distribution.
Answers
The error term is a random variable with an expected value of zero.2. The error term is normally distributed
The assumptions underlying the simple linear regression model `y = Bo + B1x + e` are: 1.
The variance of the error term e is constant across all values of x.Thus, the assumptions that are underlying the simple linear regression model `y = Bo + B1x + e` are the second and the third options, which are "The error term is normally distributed." and "The variance of the error term e is constant across all values of x." respectively.
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PLEASE ANSWER!!!!!!!!!!
Answers
Answer:
The answer would be C, or 3
Step-by-step explanation:
2x with a power of 2 to the power of 3 is 6x, with a power of five, plus y to the fower of 3.