Find the measure of the missing angle.

Answer:

y = 3x - 8

Step-by-step explanation:

_______________

The number of total selections that can be made is 1184040 i.e., option e is correct.

The number of different combinations of x objects from a set of n elements is given by the formula mentioned below:

\(C_{n,x}\) = \(\frac{n!}{x!(n-x)!}\)

This formula is used when the order in which the elements are chosen does not matter.

As per the question we know that seven tablets are chosen from a set of 28 tablets, hence the number of selections that can be made is given by:

\(C_{28,7}\) = \(\frac{28!}{7!(28-7)!}\)

\(C_{28,7}\) = ( 28 × 27 ×26 × 25 × 24 × 23 × 22 × 21! ) / ( 7! × 21!)

\(C_{28,7}\) = ( 28 × 27 ×26 × 25 × 24 × 23 × 22 ) / ( 7 × 6 × 5 × 4 × 3 × 2 × 1 )

\(C_{28,7}\) = 1184040

Thus, we can conclude that  total selections that can be made is 1184040.

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Answer:

b) 30^2 + b^2 = 40^2

Step-by-step explanation:

This is cuz the diagonal is the hypotenuse of the diagonal formed so it'll be c^ 2

c ^ 2 always is on the right hand side of the equation.

In this case since 40^2 is c^2 is should be on the right side of the equation.

Answer:  p=-2 and q=-1 [(p^2)(q^-3)]^-2. 1. See answer

Step-by-step explanation:

(i) Gas pseudo critical properties: Tₚc = 387.8 °R, Pₚc = 687.6 psia.

(ii) Pseudo reduced temperature and pressure: Tₚr = 1.657, Pₚr = 3.638.

(iii) Gas deviation factor:

(iv) Gas formation volume factor and gas expansion factor is 0.0067.

(v) Gas flow rate in scf/day 493.5 scf/day.

Gas pseudo critical properties i -

The specific gravity (SG) is given as 0.72. The gas pseudo critical properties can be estimated using the specific gravity according to the following relationships:

Pseudo Critical Temperature (Tₚc) = 168 + 325 * SG = 168 + 325 * 0.72 = 387.8 °R

Pseudo Critical Pressure (Pₚc) = 677 + 15.0 * SG = 677 + 15.0 * 0.72 = 687.6 psia

(ii) Pseudo reduced temperature and pressure:

The average pressure is given as 2,500 psia and the temperature is 130 °F. To calculate the pseudo reduced temperature (Tₚr) and pressure (Pₚr), we need to convert the temperature to the Rankine scale:

Tₚr = (T / Tₚc) = (130 + 459.67) / 387.8 = 1.657

Pₚr = (P / Pₚc) = 2,500 / 687.6 = 3.638

(iii) Gas deviation factor:

The gas deviation factor (Z-factor) can be determined using the Pseudo reduced temperature (Tₚr) and pressure (Pₚr). The specific equation or correlation used to calculate the Z-factor depends on the gas composition and can be obtained from applicable sources.

(iv) Gas Formation Volume Factor (Bg):

T = 130°F + 460 = 590°R

P = 2,500 psia

Z = 1 (assuming compressibility factor is 1)

Bg = 0.0283 × (590°R) / (2,500 psia × 1) ≈ 0.0067

(v) Gas Flow Rate in scf/day:

Gas flow rate = 15,000 ft³/day × 0.0329

≈ 493.5 scf/day

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Challenge To travel on vacation, a family wants to rent a car. Company A bills $70.50 plus 17 cents each mile. Charges from Company B are $30.50 plus 8 per mile. For every x miles that Company A charges, Company B is (39.24x)

Before figuring out their difference for x miles, we must first determine their difference for one mile.

Difference per mile = ($70.50 + $0.14) - ($30.50 + $0.90)

= $70.64 - $31.40

= $39.24

Difference for x miles = $39.24 × x miles

= $(39.24x)

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We disregard r = 0 since the radius of a cylinder cannot be zero.The cylinder with the largest volume has a radius of 9 inches.

Calculus may be used to determine the radius of the circular cylinder with the highest capacity given that the sum of its height and diameter is 18 inches.
Let's write r for the cylinder's radius and h for its height. Since the height and diameter added together equal 18 inches, we have the following equation:

2r + h = 18

We must maximise the volume of a cylinder's formula, V = r2h, in order to determine its highest value.

The equation above can now be used to find h in terms of r:

h = 18 - 2r

With this value of h entered into the volume formula, we obtain:

V = πr^2(18 - 2r)
We take the derivative of V with respect to r and set it to zero to determine the maximum volume:

dV/dr = 0

When we differentiate V in relation to r, we obtain:

36r - 4r2 = 0 for dV/dr

When we simplify this equation, we get:

36r - 4r^2 = 0

Factoring r out, we obtain:

r(36 - 4r) = 0

This equation gives us two options for the value of r: r = 0 and r = 9.


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Given the equation 6y = 2x, y varies directly with x and the constant of variation k has a value of 1/3.

There are two kinds of variations: direct and inverse.

Direct variation is a linear function defined by an equation of the form y = kx where variable y varies directly as x. On the other hand, inverse variation is a nonlinear function defined by an equation in the form y = k/x where variable y varies inversely as x.

Transforming 6y = 2x into a function of y,

y = 2/6 x

y = 1/3 x

where k = 1/3

Notice that it resembles the form y = kx which describes a direct variation between x and y.

Hence, the equation 6y = 2x shows that y varies directly with x and k = 1/3.

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The probability of having 90 or more wins in the next three hours of playing is 0.0506 or 5.06% (approx).

We are required to find the probability of having 90 or more wins in the next three hours of playing a mobile phone game similar to Pokémon, given that the number of successive win follows a Poisson distribution with a mean of 27 wins per hour.

The given mean of Poisson distribution is λ = 27.

The Poisson distribution formula is:P(X = x) = (e^-λ λ^x) / x!

We need to calculate the probability of having 90 or more wins in 3 hours.

We can combine these three hours and treat them as one large interval, for which λ will be λ1 + λ2 + λ3= (27 wins/hour) * 3 hours= 81 wins.

P(X ≥ 90) = 1 - P(X < 90)

To calculate P(X < 90), we can use the Poisson distribution formula with λ = 81.P(X < 90) = Σ (e^-81 * 81^k) / k!, k = 0, 1, 2, ....89= 0.9494

Using the above formula and values, we get P(X ≥ 90) = 1 - P(X < 90)= 1 - 0.9494= 0.0506

Therefore, the probability of having 90 or more wins in the next three hours of playing is 0.0506 or 5.06% (approx).

Hence, the probability of having 90 or more wins in the next three hours of playing is 0.0506 or 5.06% (approx).

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We are asked to find a number that added to 95 will give 98 as a result. We call such number "x" (our unknown):

x + 95 = 98

we solve for "x" by subtracting 95 from both sides and leaving the unknown "x" isolated on the left:

x = 98 - 95

x = 3

The other number is "3".

Answer:

Step-by-step explanation:

25, i think

The equation that represents the distance is -25x² + y² + z² = 0

Given data :

The distance between two points, is the number of units between them.

The equation that represents the distance is -25x² + y² + z² = 0

The distance between a point and the x-axis is represented as:

D = ( y² + x² ) \(\frac{1}{2}\)

From the question, we have:

D = 5x

Equate both expressions for D

5x =- ( y²  + z² ) \(\frac{1}{2}\)

Square both sides

25x² =  y² + z²

Equate to 0

y² + z² - 25x² = 0

Rewrite as:

-25x² + y² + z² = 0

Hence, the equation that represents the distance is -25x² + y² + z² = 0

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Answer: $1.23

Step-by-step explanation: to find the cost of one pound we need to divide 6 pounds by how much it costs so, 6 ÷ 4.86= 1.23.

Step-by-step explanation: Goes up 1 and over 1.

(If you want y-intercept it is also 1)

Answer:

The first one is a the second one is b

Step-by-step explanation:

Answer:

4 miles

Step-by-step explanation:

Given that:

Charges for the first \(\frac{1}2\) mile = $3.50

Tip given to driver = $4

Charges for additional 0.1 mile = $0.50

Total money available = $25

To find:

Total number of miles that a person can ride?

Solution:

Let us have a look at the money left after charges for the first \(\frac{1}{2}\) mile and tip.

\(\Rightarrow \$3.50 + \$4 = \$7.50\)

Money left = $25 - $7.50 = $17.50

$0.50 is required for the distance = 0.1 mile

$1 is required for the distance = 0.2 miles

$17.50 is required for the distance = 0.2 \(\times\) $17.50 = 3.5 miles

Total distance traveled = First half mile + Distance traveled with the amount of money remaining as calculated above. = 0.5 + 3.5 = 4 miles

Answer:

IQR = 3

Step-by-step explanation:

That would be 20 - 17, or 3.

\(\huge\fcolorbox{blue}{red}{Answer}\)

════════════════════

\(\frac{ x }{ 3 } +6-2x=-6\)

\(x+18-6x=-18 \)

\(-5x+18=-18 \)

\(-5x=-18-18 \)

\(-5x=-36 \)

\(x=\frac{-36}{-5} \)

\(x=\frac{36}{5} \)

\(= 7 \frac{1}{5}\)

\(= 7.2\)

So the answer is \(x = 7.2\) or \(= 7.2\)

══════════════════════

Step-by-step explanation:

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The particular solution of the differential equation  y''-5y' 4y=8e^x is A*e^x form.

To find the form of the particular solution for the given differential equation, y'' - 5y' + 4y = 8e^x, we will first identify the terms involved and then determine an appropriate trial function for the particular solution.

Given differential equation: y'' - 5y' + 4y = 8e^x

Here, the left side represents a linear differential equation with constant coefficient and the right side is the non-homogeneous term (8e^x).

To find the form of the particular solution, we'll assume a trial function based on the non-homogeneous term. Since the non-homogeneous term is 8e^x, our trial function will have the form:

Trial function: Y_p(x) = A*e^x

Now, we need to find the derivatives of Y_p(x) and substitute them into the differential equation:

First derivative: Y_p'(x) = A*e^x
Second derivative: Y_p''(x) = A*e^x

Substituting these into the differential equation:

(A*e^x) - 5(A*e^x) + 4(A*e^x) = 8e^x

Simplifying the equation:

(A - 5A + 4A)e^x = 8e^x

Now, we compare the coefficients:

A = 8

So, the form of the particular solution for the given differential equation is Y_p(x) = 8e^x

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Answer: t = 7°

Step-by-step explanation:

        We know that a straight line is equal to 180 degrees and that the little box represents 90 degrees. Using this information we can create an equation to solve for t.

   Given:

180° = 90° + 6t° + 6° + 7t° - 7°

   Combine like terms:

180° = 89° + 13t°

   Subtract 89 from both sides of the equation:

91° = 13t°

   Divide both sides of the equation by 13:

t = 7°

The three root finding problems are:

1. g₁(x) = x + e^x - cos(x)

2. g₂(x) = ln(x + cos(x))

3. g(x) = x - (x + e^x - cos(x))/(1 + e^x + sin(x))

The ranking of convergence speed at x₀ = 0.5:

1. g₁(x)

2. g₂(x)

3. g(x)

Using the Bisection Method and Regula Falsi, the solutions for the equation x + e^x = cos(x) are approximately:

- Bisection Method: x ≈ -0.5

- Regula Falsi: x ≈ I (no real root exists)

The three different root finding problems g₁(x), g₂(x), and g(x) for the equation x + e^x = cos(x) are as follows:

g₁(x) = x - cos(x) + e^x

g₂(x) = x - cos(x)

g(x) = x + e^x - cos(x)

Ranking the functions from fastest to slowest convergence at x₀ = 0.5:

1. g₁(x)

2. g₂(x)

3. g(x)

To rank the functions in terms of convergence speed, we can consider their derivatives at the root x₀ = 0.5. The faster the derivative approaches zero, the faster the convergence.

Taking the derivative of each function and evaluating it at x = 0.5:

g₁'(x) = 1 + sin(x) + e^x, g₁'(0.5) ≈ 2.78

g₂'(x) = 1 + sin(x), g₂'(0.5) ≈ 1.71

g'(x) = 1 + e^x + sin(x), g'(0.5) ≈ 1.98

From the above derivatives, we can see that g₁'(x) approaches zero the fastest at x₀ = 0.5, followed by g'(x), and then g₂'(x). Therefore, g₁(x) converges the fastest, followed by g(x), and g₂(x) converges the slowest.

Now, solving the equation x + e^x = cos(x) using the Bisection Method and Regula Falsi with the given roots:

For the Bisection Method, we have:

Initial interval: [-1, 0]

After several iterations, the approximate root is x ≈ -0.5671432904097838.

For the Regula Falsi method, we have:

Initial interval: [-1, 0]

After several iterations, the approximate root is x ≈ -0.5671432904097838.

Both methods yield the same approximate root.

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The logarithmic value equation is A = logₓ ( y )²

Given data ,

Let the logarithmic equation be represented as A

Now , the value of A is

A = ( logₓy )²

On simplifying , we get

(logₓy)² represents the logarithm of y to the base x, raised to the power of 2

From the properties of logarithm , we get

log Aⁿ = n log A

So , A = logₓ ( y )²

Hence , the equation is A = logₓ ( y )²

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Answer:

Step-by-step explanation:

D

Answer:

2/20

Step-by-step explanation:

if you add all of the marbles you will get 20 marbles in total.

The equation of the line through \((1,2)\) which make equal intercepts on the axis \(x+y=3\)

The equation of the line through (1,2) makes an equal intercept on the axis

The formula of the intercept form is

\(\frac{x}{a} +\frac{y}{b} =1\)

If they make an equal intercept

\(a=b\\\frac{x}{a} +\frac{y}{a} =1\\x+y=a\)

Put the value of the point in the axis, and we get.

\(1+2=a\\a=3\)

Put the value in the equation, and we get.

\(x+y=3\)

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Answer:

tan is 2.0 rounded to the nearest thousandths.

with out rounding it would be 1.7934

Step-by-step explanation:

The estimated current total cost for the installed and insulated tank is $12,065.73.

The first step is to calculate the surface area of the tank. The surface area of a cylinder is calculated as follows:

surface_area = 2 * pi * r * h + 2 * pi * r^2

where:

r is the radius of the cylinder

h is the height of the cylinder

In this case, the radius of the cylinder is 1 meter (half of the diameter) and the height of the cylinder is 1 meter. So the surface area of the tank is:

surface_area = 2 * pi * 1 * 1 + 2 * pi * 1^2 = 6.283185307179586

The insulation will add a thickness of 0.05 meters to the surface area of the tank, so the total surface area of the insulated tank is:

surface_area = 6.283185307179586 + 2 * pi * 1 * 0.05 = 6.806032934459293

The cost of the insulation is $40 per square meter and the cost of labor is $95 per square meter, so the total cost of the insulation and labor is:

cost = 6.806032934459293 * (40 + 95) = $1,165.73

The original cost of the tank was $10,900, so the total cost of the insulated tank is:

cost = 10900 + 1165.73 = $12,065.73

Therefore, the estimated current total cost for the installed and insulated tank is $12,065.73.

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Non-normal distributions can take various forms, therefore, the correct answer is "All of the above."

A normal distribution, also known as a Gaussian distribution or bell curve, is characterized by a symmetrical shape with the majority of data points clustered around the mean, and the tails extending equally in both directions. However, real-world data often deviate from the normal distribution pattern.

Right-skewed distribution: This distribution is also known as positively skewed or right-tailed. It occurs when the tail of the distribution extends towards higher values, while the majority of the data is concentrated towards lower values.

Left-skewed distribution: Also referred to as negatively skewed or left-tailed, this distribution exhibits a tail extending towards lower values, while the bulk of the data is clustered towards higher values.

Leptokurtic distribution: Leptokurtic distributions have a higher peak and heavier tails compared to the normal distribution. They are characterized by a greater concentration of data points around the mean and a higher probability of extreme values.

Platykurtic distribution: Platykurtic distributions have a flatter shape and lighter tails compared to the normal distribution. They exhibit a lower peak and a lower probability of extreme values.

In summary, non-normal distributions encompass various shapes and characteristics, including right-skewed, left-skewed, leptokurtic, and platykurtic distributions. Therefore, all of the options provided are examples of non-normal distributions.

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Answer: No entiendo lo que está tratando de preguntar

Step-by-step explanation: