The measure of the circled angle is; (8y + 17) = 137°
How to find the congruent angle of the diagram?The line transversal theorem states that If a transversal intersects two parallel lines, then the same-side interior angles are said to be supplementary.
Alternate Interior Angles Theorem states that If a transversal intersects two parallel lines, then it means that alternate interior angles are congruent.
From the given diagram, we can see that the angles (6x - 7)° and (3x - 29)° are supplementary angles.
Thus;
(6x - 7)° + (3x - 29)° = 180°
9x - 36 = 180
9x = 216
x = 216/9
x = 24
Now, (6x - 7)° and (8y + 17)° are opposite angles and are congruent and as such;
(6(24) - 7)° = (8y + 17)°
144 - 7 = 8y + 17
8y = 144 - 7 - 17
8y = 120
y = 15
Thus;
(8y + 17) = 8(15) + 17 = 137°
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What is the value of b?
A.6
B.2sqr 13
C.3sqr13
D.3sqr14
Answer:
En este caso 70 ° y 20 ° son complementarios porque 70° + 20° = 90°.
Más ejemplos podrían ser 47° y 43°, ya que 47° + 43° = 90°, 30° y 60°, 45° y 45° , etc.
Dos ángulos son suplementarios si su suma forma un ángulo llano, es decir, 180°.
Which table represents y as a function of x?
Answer:
Second option?
Step-by-step explanation:
I would go with the second one. It cannot be the first one because a function must have one y value per each x, but in this case it does not. Same reason for option 3 and 4. Am I right? Please let me know :)
Find the area of the largest rectangle that fits into the triangle with sides x=0,y=0 and x4 y6=1.
The largest rectangle that fits into the triangle with sides x=0, y=0, and x=4, y=6 has an area of 24 square units.
The coordinates of the vertices of the triangle are given by;
x=0 ⇒ (0, 0)
y=0 ⇒ (0, 0)
x=4 ⇒ (4, 0)
y=6 ⇒ (0, 6)
The base of the rectangle will be parallel to the x-axis and the height of the rectangle will be parallel to the y-axis. The vertices will lie along the sides of the triangle with lengths 4 and 6.
The area of the largest rectangle is base × height
where;
base (b) = 4
height (h) = 6
By substituting the values of (b) and (h) in the equation, we get;
Area of the rectangle = 4 × 6
⇒ 24 square units.
Therefore, the largest rectangle that fits into the given triangle has an area of 24 sq. units.
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a wire is cut into two pieces, one of length and the other of length . the piece of length is bent to form an equilateral triangle, and the piece of length is bent to form a regular hexagon. the triangle and the hexagon have equal area. what is ?
The value of a/b is \(\sqrt{6}\) / 2
What is called mensuration?The area of mathematics known as mensuration is concerned with measuring geometric shapes and their various characteristics, such as length, volume, shape, surface area, lateral surface area, etc. In fundamental mathematics, learn about mensuration.
What is mensuration in real life?Measurement of agricultural fields, floor areas required for purchase/selling transactions. Measurement of volumes required for packaging milk, liquids, solid edible food items. Measurements of surface areas required for estimation of painting houses, buildings, etc.
According to the question:-
Side of an equilateral triangle equals a/3.
Therefore, the equilateral triangle's area is equal to (1/2)(a/3)2 sqrt (3) / 2 = a2 [sqrt (3)/ 36].
Hexagonal side equals b / 6.
The area is thus 6 (1/2) (b/6)^2 sqrt (3) / 2
= b^2 [ 3 sqrt (3) / 72] = b^2 [sqrt (3) / 24]
So
sqrt (3) / 36 a2 = sqrt (3) / 24 b2
So
A2 / B2 = [Sqrt(3)/24] / [Sqrt(3)/36]
a^2 / b^2 = [ 36 / 24 ]
a^2/ b^2 = 3/2
A/ B = Sqrt(3) / Sqrt(2)
=Sqrt(6) / 2
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can someone please help me
Answer:
145
Step-by-step explanation:
Angle 4 would be equivalent to 1, which means that 1 and 4 would equal 70.
In a circle the angles must equal 360.
So you would do 360 - 70 which equals 290.
The same rule for angles 1 and 4, applies to 2 and 3.
So you would half 290.
Thus, the answer would be 145 degrees.
Hope this helps :)
Help! keep getting different answers! thanks
Answer:
it A
Step-by-step explanation:
tan c=opp c/adj c
tan c=7/16
tan c=0.44
Answer:
D
Step-by-step explanation:
The tangent of C = opposite (7) over the adjacent (18)
Tan C = 7/18
Tan C = 0.388
The closest answer is D
Quadrilateral ABCD is similiar to quadrilateral EFGH. The lengths of the three longest sides in quadrilateral ABCD are 24 feet, 32 feet, and 48 feet long. If the two shortest sides of quadrilateral EFGH are 9 feet long and 18 feet long, how long is the 2nd longest side on quadrilateral EFGH?
Answer:
24 feet
Step-by-step explanation:
12 ÷ 18=16/y
2y=3*16
y=24
Please answer the circled questions! (And also part a and b)
A. When Steven buys 2.32 pounds of trial mix and 4.64 pounds of dry fruit, the cost is $27.84.
B. When Mario got $0.40 in change from buying trail mix The pounds bought will be 5.6 pounds.
How to illustrate the information?A. It should be noted that Steven buys 2.32 pounds of trial mix and 4.64 pounds of dry fruit. The cost will be:
= (2.32 × $3.50) + (4.64 × $4.25)
= $8.120 + $19.72
= $27.84
B. From the information, Mario got $0.40 in change from buying trail mix The pounds bought will be:
20 - 3.50x = 0.40
3.50x = 20 - 0.40
3.50x = 19.60
x = 19.60 / 3.5
x = 5.6 pounds.
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What is 115 lbs in kg?
Answer:
115 lbs = 52.16 kilograms
Step-by-step explanation:
115 pounds is a little over 52kg
Our heroine is trapped in a rectangular room that is 10 feet by 16 feet, with a ceiling that is 9 feet above the floor. The room is filling with water at a rate of 60 cubic feet per minute. When the water reaches a depth of 5.5 feet, how fast is the water rising?
The speed at which the water is rising, given the rate the water is coming in is 0.375 feet/minute.
How to find the speed of the water ?The volume V of water in the room is given by the formula V = length x width x height, where length and width are the dimensions of the room and height is the height of the water.
The rate of change of the height of the water with respect to time (dh/dt) is what we're trying to find. By implicit differentiation, we have:
dV/dt = length x width x dh/dt
60 cubic feet/minute = 16 feet x 10 feet x dh/dt
dh/dt = 60 cubic feet/minute / (160 square feet)
dh/dt = 0.375 feet/minute
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help! what is the missing length?
Answer:
Hello! answer: 30
Step-by-step explanation:
32 × 30 = 960 HOPE THAT HELPS!
Name the property. a + b is a real number.*
Commutative Property of Addition
Commutative Property of Multiplication
Associative Property of Addition
Associative Property of Multiplilcation
Identity Property of Addition
Closure Property of Addition
Answer:
Closure Property of Addition
Step-by-step explanation:
Answer:
\(a + b = b + a \: \forall \: a, \: b \in \: \R \ \\ a \times b = b \times a\: \forall \: a, \: b \in \: \R \\ (a + b) + c = (b + c) + a\: \forall \: a, \: b, \: c, \in \R \\ (a \times b) \times c = (b \times c) \times a \: \forall \: a, \: b, \: c, \in \R \\a+0=0+a=0 \: \forall \: a,\in \: \R \\a +b=c\: \forall \: a, \: b, \: c, \in \R \)
show that if a > √n and b > √n, then n ≠ ab, where a and b are positive integers. n = 25 a = 8 8 > 5 b = 9 9 > 5 25 ≠ (8 * 9) = 72 this is a valid proof.
The statement "if a > √n and b > √n, then n ≠ ab" is saying that if two positive integers, a and b, are both greater than the square root of another positive integer n, then the product of a and b is not equal to n. This statement can be proven by contradiction.
Suppose the opposite is true, and that n = ab, where a and b are positive integers such that a > √n and b > √n. Then, because n = ab, we have n/a = b and n/b = a. But because both a and b are greater than the square root of n, we have √n < a and √n < b. This leads to a contradiction, because it means that n/a = b > √n, but √n is the largest possible value of b such that b < n/a.
Thus, we have proven that if a > √n and b > √n, then n cannot equal ab, and our original statement is true.
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Solve 5(2x + 4) = 15. Round to the nearest thousandth.
PS: x+4 is the power for 2
\(\qquad \qquad\huge \underline{\boxed{\sf Answer}}\)
Let's solve for x ~
\(\qquad \sf \dashrightarrow \: 5(2x + 4) = 15\)
\(\qquad \sf \dashrightarrow \: (5 \times 2x) + (5 \times 4) = 15\)
\(\qquad \sf \dashrightarrow \: 10x + 20 = 15\)
\(\qquad \sf \dashrightarrow \: 10x + 20 - 20 = 15 - 20\)
\(\qquad \sf \dashrightarrow \: 10x = - 5\)
\(\qquad \sf \dashrightarrow \: \dfrac{10x}{10} = \dfrac{ - 5}{10} \)
\(\qquad \sf \dashrightarrow \: x = - \dfrac{ 1}{2} \)
hence value of x is - 1/2
write the symbolic expression for each of the following descriptions, then get rid of the radical and make them exponential expressions in fractional form. 11. the eighth root of fifty seven to the sixth degree
The final exponential expression in fractional form for "the eighth root of fifty-seven to the sixth degree" is 57^(3/4).
To express the given description as a symbolic expression and then convert it into an exponential expression in fractional form, we'll follow these steps:
Step 1: Symbolic Expression
The description states "the eighth root of fifty-seven to the sixth degree." Let's denote this as √[57]^(1/8)^6.
Step 2: Removing Radical
To eliminate the radical (√), we can rewrite it as a fractional exponent. The numerator of the fractional exponent corresponds to the power (6) applied to the base, and the denominator corresponds to the index of the root (8).
So, the expression becomes (57^(1/8))^6.
Step 3: Simplifying Exponents
To simplify the exponent, we multiply the powers:
(57^((1/8)*6))
Simplifying further:
(57^(6/8))
Step 4: Fractional Form
The exponent 6/8 can be simplified by dividing both the numerator and denominator by their greatest common divisor, which is 2:
(57^(3/4))
Therefore, the final exponential expression in fractional form for "the eighth root of fifty-seven to the sixth degree" is 57^(3/4).
This means that we raise 57 to the power of 3/4 to represent the original description. The fraction 3/4 indicates taking the eighth root of 57 and then raising it to the sixth power.
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find a function f(n) that identifies the nth term an of the recursively defined sequence, as an = f(n). a1 = 5 and an+1 = ((n + 1 )an / 5) for n ≥ 1
f(n) =
f(n) = (n+1) * (n) * (n-1) * ... * (2) * (1) * 5 / (5^n). This is the function that identifies the nth term of the recursively defined sequence.
The recursively defined sequence is given by an+1 = ((n + 1 )an / 5) for n ≥ 1, with a1 = 5. We need to find a function f(n) that identifies the nth term an of the sequence, as an = f(n).
To do this, we can use the recurrence relation to express an in terms of a(n-1), a(n-2), and so on, until we reach a1. Substituting an-1 = f(n-1), we have:
an = ((n + 1) an-1 / 5)
= ((n + 1) f(n-1) / 5)
We can simplify this expression by substituting an-2 = f(n-2) into the expression for an-1, and so on, until we obtain:
an = (n+1) * (n) * (n-1) * ... * (2) * (1) * a1 / (5^n)
This expression shows that the nth term an is a function of n, namely f(n) = (n+1) * (n) * (n-1) * ... * (2) * (1) * a1 / (5^n).
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WHAT WOULD THIS BE? SOMEONE PLEASE HELPP
Answer:
A
Step-by-step explanation:
4x2 = 8
3 + 3 = 6
so 8x to the 6th
yeah These points are linear.Find the slope.x-2-1 0 1 1 2y -7 0 7 14 21slope = [?]-
slope=7
Explanation
the slope of a line ( or segment) is given by
\(\begin{gathered} \text{slope}=\frac{\text{ change in y }}{\text{ change in x}}=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1} \\ \text{where} \\ P1(x_1,y_1)\text{ } \\ \text{and} \\ P2(x_2,y_2) \\ \text{are 2 points from the line} \end{gathered}\)so
Step 1
Let
\(\begin{gathered} P1(0,7) \\ P2(2,21) \end{gathered}\)now,replace in the formula
\(\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{21-7}{2-0}=\frac{14}{2}=7 \end{gathered}\)therefore, the slope is 7
I hope this helps you
Homer plans to deposit $150 in the bank in one year. He plans to make the same deposit two years from today and three years from today. How much will Homer have in the bank in four years? Homer's bank pays an interest rate of 5.6%. $502 $689 $652 $476
After making a $150 deposit in the bank in one year, two years, and three years, Homer will have a total of $689 in the bank in four years, considering the interest rate of 5.6%.
Let's break down the problem step by step. In one year, Homer makes a $150 deposit. After one year, his initial deposit will earn interest at a rate of 5.6%. Therefore, after one year, his account balance will be $150 + ($150 * 0.056) = $158.40.
After two years, Homer makes another $150 deposit. Now, his initial deposit and the first-year balance will both earn interest for the second year. So, after two years, his account balance will be $158.40 + ($158.40 * 0.056) + $150 = $322.46.
Similarly, after three years, Homer makes another $150 deposit. His account balance at the beginning of the third year will be $322.46 + ($322.46 * 0.056) + $150 = $494.62.
Finally, after four years, Homer's account balance will be $494.62 + ($494.62 * 0.056) = $689.35, which rounds down to $689. Therefore, Homer will have $689 in the b in four years, considering the interest rate of 5.6%.
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Can i get some help pls!
Answer:
Graph the system on linear equations.
Step-by-step explanation:
(-4, 4) & (-4, -6)
Find a root of an equation f(x)=x³-3x-1 between -1 and 1, using False Position method, after the second iteration.
The root of the equation \(\(f(x) = x^3 - 3x - 1\)\) between -1 and 1, after the second iteration of the False Position method, is approximately -1.
How to find the root of the equation \(\(f(x) = x^3 - 3x - 1\)\)The False Position method involves finding the x-value that corresponds to the x-intercept of the line passing through \(\((a, f(a))\)\) and \(\((b, f(b))\),\)where (a) and (b) are the endpoints of the interval.
Let's begin the iterations:
Iteration 1:
\(\(a = -1\), \(f(a) = (-1)^3 - 3(-1) - 1 = -3\)\)
\(\(b = 1\), \(f(b) = (1)^3 - 3(1) - 1 = -3\)\)
The line passing through (-1, -3) and (1, -3) is (y = -3). The x-intercept of this line is at (x = 0).
Therefore, the new interval becomes [0, 1] since the sign of f(x) changes between\(\(x = -1\) and \(x = 0\).\)
Iteration 2:
\(\(a = 0\), \(f(a) = (0)^3 - 3(0) - 1 = -1\)\)
\(\(b = 1\), \(f(b) = (1)^3 - 3(1) - 1 = -2\)\)
The line passing through\(\((0, -1)\) and \((1, -2)\) is \(y = -x - 1\)\). The x-intercept of this line is at (x = -1).
After the second iteration, the new interval becomes [-1, 1] since the sign of f(x) changes between (x = 0) and (x = -1).
Therefore, the root of the equation \(\(f(x) = x^3 - 3x - 1\)\) between -1 and 1, after the second iteration of the False Position method, is approximately -1.
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Andrea sells photographs at art fairs. She prices the photos according to size: small photos cost $10, medium photos cost $15, and large photos cost $40. She usually sells as many small photos as medium and large photos combined. She also sells twice as many medium photos as large. A booth at the art fair costs $300. If her sales go as usual, how many of each size photo must she sell to pay for the booth?
Answer: she must sell 6 large photos and 6 small photos
Step-by-step explanation: and how I knew that is I multiplied 6 40 times and that gives you 240 and if you multiply 6 ten times that gives you 60 so 240 plus 60 is $300
if x=5, y=-3, and z=-7 z=-7, evaluate 3x^2-9y/yz
Need answer quick. No need for big explanantion
Answer:
Step-by-step explanation:
4.30/40=$0.1075
Hope this helps :)
Someone plz help me
Answer:
Decagon
Step-by-step explanation:
A decagon has 10 vertices. which is greater than the number of vertices a pentagon, hexagon, and octagon has
factor completely 21x^3+35x^2+9x+15
Answer:
(3x+5)(7x^2+3)
Step-by-step explanation:
Factor : 21x^3+35x^2+9x+15
21x^3+35x^2+9x+15
=(3x+5)(7x^2+3)
______________________
Hope this helps!
if 26 children were to be born in a hospital on a given day, how many combinations of 6 boys and 20 girls would exist? 230,230 4 x 10^26 500,000 15 Z
The number of combinations of 6 boys and 20 girls that can exist among 26 children born in a hospital on a given day is 230,230.
]To calculate the number of combinations, we can use the concept of binomial coefficients. The formula for calculating the number of combinations is C(n, k) = n! / (k!(n-k)!), where n is the total number of objects and k is the number of objects we want to select.
In this case, we have 26 children in total, and we want to select 6 boys and 20 girls. Plugging these values into the formula, we get C(26, 6) = 26! / (6!(26-6)!) = 230,230. Therefore, there are 230,230 different combinations of 6 boys and 20 girls that can exist among the 26 children born in the hospital on that given day.
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The position of a car at time t is given by the function p (t) = t2 + 4t − 17. Where will the car be when it moves at a velocity of 10? Assume t ≥ 0.
Final Answer: The position of car is at 4.
Here position of car is given by p(t) = \(t^2+4t-17\)
Velocity is rate of change of function so we will calculate derivative of
p(t).
\(dp/dt = 2t+4\)
We want to find the position of car when it moves at a velocity of 10.
so dp/dt = 10
2t +4 = 10
2t = 6
t = 3
Hence at t = 3 the position of car will be determined.
p(3) = 3^2 + 4*3 -17
p(3) = 4.
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Which of the following is the graph of f(x) = log(x + 1) - 4?
Option C is correct
Explanation:The given logarithmic equation is:
f(x) = log(x + 1) - 4
For a logarithmic equation of the form:
f(x) = log(a + b) - c
the y-intercept = -c
Comparing the two equations above:
The y-intercept = -4
Taking note of the point above, the logarithmic function f(x) = log(x + 1) - 4 is plotted below
for the following 3 questions: a study obtained data on the amount of time 28 randomly selected high school students and 31 randomly selected college students spend on their cell phones each day. the investigator is interested in determining whether there is evidence that the amount of time students spend on their cell phone is different between high school and college Let H= time spent on phone by high school students; C= Time spent on phone by college students; and d=H−C
The data are not paired because: o All of these are true o Each element in a sample is measured once: time spent on cell phone o The conclusion pertains to the difference of two independent population means o There are two samples
The correct answer is
H₀ : μh - μc = 0
H₀ : μh - μc ≠ 0
Given that,
Regarding the subsequent 3 inquiries: A study collected information on how much time 28 randomly chosen high school students and 31 randomly chosen college students spent each day on their cellphones. The researcher is interested in learning whether there is proof that students use their phones for varying amounts of time in high school and college.
Because the samples of college and high school students are independent, the independent samples t-test should be utilized.
The study's research (Claim) aims to ascertain whether students' cell phone usage patterns alter between high school and college.
For the independent samples t-test and the stated claim, the proper null and alternate hypotheses are,
H₀ : μh - μc = 0
H₀ : μh - μc ≠ 0
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The proper null and alternative hypotheses are
\(H_{0}\) : μh = μc
\(H_{A}\) : μh - μc
The study's research wants to ascertain whether difference between the time spent by high school students and college students.
The actual test begins by considering two hypothesis i.e. null hypothesis and alternative hypothesis.
Let, H= time spent on the phone by high school students;
C= Time spent on the phone by college students; and
d=H−C
For the independent samples t-test and the stated claim, the proper null and alternate hypotheses are,
\(H_{0} :\) μh = μc (time spent by high school students is equal to college students)
\(H_{A} :\) μh - μc (difference between the time spent by high school students and college students)
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