Find the measure of angle TUY

Answer:

2t+4s=$50

Step-by-step explanation:

2 t=2 t-shirts

4s=4 shorts

Add them together, and thats what you get

Answer:

slope of line =y2-y1/ x2-x1

according to the given figure.

y is 3

and x Is 5

then, slope of AB= Y/X

slope of AB=3/5

Answer:  The temperature gradient is a dimensional quantity expressed in units of degrees (on a particular temperature scale) per unit length. The SI unit is kelvin per meter (K/m).

Step-by-step explanation:

Answer:

kelvin per meter (K/M)

Step-by-step explanation:

ik ik.. weird answer

the Temperature Gradient is a dimensional quantity expressed of units of degrees (on a particular temperature scale) per unit length. the SI unit is kelvin per meter (K/M).

Answer:

Step-by-step explanation:

Remark

The purple lines cross but once. A solution to a set of functions counts how many times the functions cross. Since these two lines cross but once, there is only 1 solution.

If the lines are parallel, they never cross. That means there are no solutions.

If you are given 2 equations and one is the same line as the second one, then there are an infinite number of solutions.

Hi!

Solutions to systems of equations are only where the lines intersect at a point.

That means that if the lines cross over at any point, they have a solution. Lines that don't have a solution -- parallel lines -- do not cross over.

In this graph, we can see that it crosses over at only one point.

That means that this system of equations has exactly one solution.

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Step-by-step explanation:

You multiply all your answers by 4. For example: 1×4= 4 ; 4×4=16; 16×4= 64... proceeding like that.

Answer:

x=100

Step-by-step explanation:

a=5√(2)

2a=2√(2x)

Multiply the first equation by 2 on both sides to get:

2a=2*5√(2)=10√(2)

Now, since we have 2a on the left sides of both equations, we can solve this.

10√(2)=√(2x)

We can rewrite √(2x) as √(2) * √(x) and divide by √(2) on both sides.

10=√(x)

Square on both sides to get:

100=x

So x=100. Hope I could help you!

Answer:

Its option C

As,

x+8=3x

8= 3x-x

8=2x

8/2=x

4=x

#x=4

Answer

40m

Step-by-step explanation:

Multiply 32m by 2 or add 32m add 32m

You will get 64m

Subtract 64m from 144m

You will get 80m

Divide 80m by 2

You will get a length of 40m

A rectangular compound is 32m broad and its perimeter is 144m .Find its length.

— — — — — — — — — —

Based on the problem, a rectangle compound is 32 m broad and its perimeter is 144.

so,

Therefore, the length measures 40 meters.

_______________∞_______________

Answer:

1 st year = $320

2nd year $128

320p - 192t = $128

Step-by-step explanation:

Jesse's ranking is 25th percentile.

Jesse's ranking can be calculated using the following formula:

Percentile = (Jesse's ranking / Total number of students in class) x 100

In this case, Percentile = (45/180) x 100 = 25th Percentile

Therefore, Jesse's ranking is 25th percentile.

To calculate percentile, we divide the rank of the student with the total number of students in the class and then multiply the result with 100. In this case, Jesse was ranked 45th in a class of 180 students and so his percentile is 25%. Percentile is a measure that helps us to compare individuals in a group. It helps us to know the relative performance of a person in a given group of people. Generally, a higher percentile indicates better performance than the other students in the group.

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Q=nΔH & Q=mCΔT, R=8.314 J/(mol•K), water density = 1 g/mL or 1000 kg/m³, Hess's Law involves known enthalpy changes.

Q = mCΔT represents the formula for calculating heat (Q) by using the mass of the substance (m), its specific heat capacity (C), and the change in temperature (ΔT). This formula is used for calculating the heat absorbed or released during a physical change or phase transition. The gas constant (R) has a value of 8.314 J/(mol·K) and is used in gas law equations such as PV = nRT and PV = (nRT)/V. The density of water is 1 g/mL or 1000 kg/m³.

A full Hess's Law example involves calculating the enthalpy change for a chemical reaction by using a series of other reactions with known enthalpy changes.

For example, to calculate the enthalpy change for the reaction:

2H₂(g) + O₂(g) → 2H₂O(g)

We can use the following reactions with known enthalpy changes:

2H₂(g) + O₂(g) → 2H₂O(l) ΔH = -572 kJ

2H₂O(l) → 2H₂O(g) ΔH = +40.7 kJ

By reversing and scaling the second reaction and adding it to the first reaction, we can get the target reaction:

2H₂(g) + O₂(g) → 2H₂O(g) ΔH = -531.3 kJ.

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We have shown that the inequality 2x1 + 3x2 + 4x3 + 2y1 + 6y2 ≤ 0 is a valid Gomory cut for the given feasible region.

To prove that the inequality 2x1 + 3x2 + 4x3 + 2y1 + 6y2 ≤ 0 is a valid Gomory cut for the given feasible region, we need to show two things:

1. The inequality is satisfied by all integer solutions of the original system.

2. The inequality can be violated by some non-integer point in the feasible region.

Let's consider each of these points:

1. To show that the inequality is satisfied by all integer solutions, we need to show that for any values of x1, x2, x3, y1, y2 that satisfy the original system of inequalities, the inequality 2x1 + 3x2 + 4x3 + 2y1 + 6y2 ≤ 0 holds.

Since the original system of inequalities is given by:

4x1 + x2 + 2x3 + 3y1 + 4y2 ≤ 4

5x1 + 9x2 + 12x3 + y1 + 3y2 ≤ 5

9x1 + 12x2 + 34x3 + y1 + 4y2 ≤ 9

We can substitute the values of y1 and y2 in terms of x1, x2, and x3, based on the Gomory cut inequality:

y1 = -x1 - x2 - x3

y2 = -x1 - x2 - x3

Substituting these values, we have:

2x1 + 3x2 + 4x3 + 2(-x1 - x2 - x3) + 6(-x1 - x2 - x3) ≤ 0

Simplifying the inequality, we get:

2x1 + 3x2 + 4x3 - 2x1 - 2x2 - 2x3 - 6x1 - 6x2 - 6x3 ≤ 0

-6x1 - 5x2 - 4x3 ≤ 0

This inequality is clearly satisfied by all integer solutions of the original system, since it is a subset of the original inequalities.

2. To show that the inequality can be violated by some non-integer point in the feasible region, we need to find a point (x1, x2, x3) that satisfies the original system of inequalities but violates the inequality 2x1 + 3x2 + 4x3 + 2y1 + 6y2 ≤ 0.

One such point can be found by setting all variables equal to zero, except for x1 = 1:

(x1, x2, x3, y1, y2) = (1, 0, 0, 0, 0)

Substituting these values into the original system, we have:

4(1) + 0 + 2(0) + 3(0) + 4(0) = 4 ≤ 4

5(1) + 9(0) + 12(0) + 0 + 3(0) = 5 ≤ 5

9(1) + 12(0) + 34(0) + 0 + 4(0) = 9 ≤ 9

However, when we substitute these values into the Gomory cut inequality, we get:

2(1) + 3(0) + 4(0) + 2(0) + 6(0) = 2 > 0

This violates the inequality 2x1 + 3x2

+ 4x3 + 2y1 + 6y2 ≤ 0 for this non-integer point.

Therefore, we have shown that the inequality 2x1 + 3x2 + 4x3 + 2y1 + 6y2 ≤ 0 is a valid Gomory cut for the given feasible region.

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If the overall percentage of defective panels from the two plants was 2%, then the number of panels did plant B produce is 2000

Let's assume that plant B produced x panels.

The number of defective panels produced by plant A is 1% of 4000, which is 0.01 x 4000 = 40 panels.

The number of defective panels produced by plant B is 4% of x, which is 0.04x panels.

The total number of defective panels produced by both plants is 2% of the total number of panels produced, which is 0.02 (4000 + x) panels.

Therefore, we can write the equation

40 + 0.04x = 0.02 (4000 + x)

Simplifying and solving for x, we get

40 + 0.04x = 80 + 0.02x

0.02x = 40

x = 2000

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The given question is incomplete, the complete question is:

Two factory plants are making tv panels. Yesterday, plant A produced 4000 panels. One percent of the panels from plant A & 4% of the panels from plant B were defective. How many panels did plant B produce, if the overall percentage of defective panels from the two plants was 2%?

No, the given value of h=2 is not a solution of the equation 1/3h=6.

The examples of Lightweight Directory Access Protocol (LDAP) directory server software include:

A. OpenLDAP

D. MS Active Directory

Software is a collection of computer programs, documentation, and data. This is in contrast to hardware, which is the foundation of the system and does the actual work. A set of instructions, data, or programs used to operate computers and carry out specific tasks is referred to as software. It is the inverse of hardware, which describes a computer's physical components. Software is a catch-all term for applications, scripts, and programs that run on a device.

Lightweight directory access protocol (LDAP) is a protocol that allows users to find information about organizations, people, and other entities. The primary goals of LDAP are to store data in the LDAP directory and to authenticate users to access the directory.

The Lightweight Directory Access Protocol (LDAP) is an acronym for Lightweight Directory Access Protocol. LDAP, which was created in 1993, is still widely used in businesses and organizations around the world for directory-based authentication.

In conclusion, the options are A and D.

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Answer:

4

Step-by-step explanation:

\(3x+2+3x+3=5x+9 \\ \\ 6x+5=5x+9 \\ \\ x=4\)

Step-by-step explanation:

\(x = \frac{4}{3} \)

\(1. \: 6x + 6 = 5 + 9 \\ 2. \: 6x + 6 = 14 \\ 3. \: 6x = 14 - 6 \\ 4. \: 6x = 8 \\ 5. \: x = \frac{8}{6} \\ 6. \: x = \frac{4}{3} \)

a) The rental rates for approximately 95% of rentals fall between $550 and $650.

b) The approximate probability that a rental rate is between $525 and $650 is 0.8413.

c) A rate of $630 is 0.12 standard deviations above the mean.

a) To find the rental rates for approximately 95% of rentals, we can use the empirical rule, also known as the 68-95-99.7 rule. This rule states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, approximately 95% of the data falls within two standard deviations of the mean, and approximately 99.7% of the data falls within three standard deviations of the mean.

Therefore, for this distribution with a mean of $600 and a standard deviation of $25, we can find the rental rates for approximately 95% of rentals as:

Lower Bound: $600 - (2 × $25) = $550

Upper Bound: $600 + (2 × $25) = $650

b) To find the approximate probability that a rental rate is between 525 and 650, we can use the standard normal distribution table to find the area under the curve between those two values. Since the standard deviation is known, we can standardize the values by subtracting the mean and dividing by the standard deviation.

P(525<x<650) = P( (525-$600)/$25 < (x-$600)/$25 < (650-$600)/$25) = P(-1.2<z<1.2)

The area under the standard normal curve between -1.2 and 1.2 is approximately 0.8413. Therefore, the approximate probability that a rental rate is between $525 and $650 is 0.8413.

c) To find how many standard deviations from the mean is a rate of $630, we can use the formula:

(x - mean) / standard deviation

In this case:

(630 - 600) / 25 = 3/25

So a rate of $630 is 0.12 standard deviations above the mean.

To summarize, the rental rates for approximately 95% of rentals fall between $550 and $650, the approximate probability that a rental rate is between $525 and $650 is 0.8413, and a rate of $630 is 0.12 standard deviations above the mean.

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The question is -

The monthly apartment rental rates near Enterprise College approximate a symmetrical, bell-shaped distribution. The sample means the rental rate is $600; the standard deviation is $25.

a) what are the rental rates for approximately 95% of rentals?

b) what is the approximate probability that a rental rate is between 525 and 650 days?

c) how many standard deviations from the mean is a rate of $630?

The expression simplifies to: -7y^2 - y, in this simplified form.

Combining like terms involves grouping the terms with the same variables and adding or subtracting their coefficients.

In the given expression, we have -3y^2 - 7y - 9 - 4y^2 + 6y + 9

To combine like terms, we add or subtract the coefficients of the terms with the same variable. For the terms with y^2, we have -3y^2 and -4y^2, which can be combined as (-3 - 4)y^2 = -7y^2.

For the terms with y, we have -7y and +6y, which can be combined as (-7 + 6)y = -y. Finally, we combine the constant terms -9 and 9, which cancel each other out.

Therefore, the expression simplifies to: -7y^2 - y

In this simplified form, the like terms have been combined, and the expression is in its most concise form.

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Given:

The expression is

\((-8)^3\cdot (-8)^4\)

To find:

The expression in repeated multiplication form and then write the expression as a power.

Solution:

We have,

\((-8)^3\cdot (-8)^4\)

The repeated multiplication form of this expression is

\(=[(-8)\cdot (-8)\cdot (-8)]\cdot [(-8)\cdot (-8)\cdot (-8)\cdot (-8)]\)

\(=(-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\)

Clearly, (-8) is multiplied seven times by itself. So,

\(=(-8)^7\)

Therefore, the repeated multiplication form of the given expression is \((-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\cdot (-8)\) and the expression as single power is \((-8)^7\).

If the first number is not allowed to be "0", we will have that the aviable numbers will be:

So, we will have 9 posibilites, now:

First, we will have that the biggest number of 7 digits that we will be able to write will be 9 999 999 and the smallest is 1 000 000.

Now, we will have that the total number of aviable values is:

Then, the total number of possible is:

Answer:

\(\textsf{A)}\quad y=-\sqrt{x}+2\)

Step-by-step explanation:

Parent function:

\(y = \sqrt{x}\)

The properties of the parent function are:

From inspection of the graph, as the x-values increase, the y-values decrease. Therefore there has been a reflection in the x-axis.

The y-intercept is now at (0, 2), therefore the function has been translated 2 units up.

Translations

For a > 0

\(y=-f(x) \implies f(x) \: \textsf{reflected in the} \: x \textsf{-axis}\)

\(f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}\)

Therefore:

Reflected in the x-axis:  \(-f(x)=-\sqrt{x}\)

Then translated 2 units up:  \(-f(x)+2=-\sqrt{x}+2\)

So the equation that represents the transformed function is:

\(y=-\sqrt{x}+2\)

Answer:

Let's check this!

Obtuse triangle formula:

c² < b² + a²

Next fill in the formula:

7² < 5² + 4²

Then simplify:

49 < 25 + 16
Then add:

49 < 41

^^49 is not greater than 41 so therefore the triangle is not obtuse.

When the hypotenuse is bigger than the legs of the triangle it is an acute triangle.

Acute triangle formula:

c² > b² + a²

7² > 5² + 4²

49 > 25 + 16

49 > 41 ✔

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The three sides of a triangle of lengths 4, 5, and 7 are not obtuse triangles.

The triangle is an obtuse triangle if the sum of the squares of the smaller sides is less than the square of the largest side.

The three sides of a triangle of lengths 4, 5, and 7.

An obtuse triangle is a triangle in which one of the interior angles is greater than 90°.

The sides of a triangle are not an obtuse triangle as determined in the fooling step given below.

Obtuse triangle formula:

c² < b² + a²

7² < 5² + 4²

49 < 25 + 16

49 < 41

Here; 49 is not greater than 41 so therefore the triangle is not obtuse.

Hence, the three sides of a triangle of lengths 4, 5, and 7 are not obtuse triangles.

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Answer:

The segment that connects the midpoints of the legs of a trapezoid is called the median of the trapezoid.

Step-by-step explanation:

Answer:

There are 11 cows and 8 ducks

Step-by-step explanation:

x will represent number of cows and (19-x) will represent ducks

\(4x+2(19-x)=60\)

multiply 2 with (19-x)

\(4x+38-2x=60\)

add your x's

\(2x+38=60\)

subtract 38 on both sides

\(2x=22\)

then divided 2 on both sides

\(x=11\) cows

now to find ducks subtract

\(19-11\)

your answer will be 8

So there are 11 cows and 8 ducks

to double check do this

\(11*4 + 8*16\\=44+16\\=60\)

Answer:

Factor GCF: 3x(2x⁴ - 5x + 4)

Step-by-step explanation:

Simply take out the greatest variable first and then take out the GCF of the numbers to find out factored GCF.

Answer:

The combination of linear equations is

x+y = 75

y+15 = x

Step-by-step explanation:

x = representation of minutes Jack jogs

y = representation of minutes Jack bikes

Sum of 75 minutes for biking and jogging

x+y = 75

The combination of linear equations is

x+y = 75

y+15 = x

He bikes for 15 minutes higher than he jogs

y+15 = x

Questions regarding the time spent by Jack jogging and bike riding are needed to be answered.

The equations are \(x+y=75\), \(y=15+x\)

Time spent jogging is 30 minutes

The total time would be \(45+60=105\) minutes which is not equal to 75 minutes.

Let \(x\) be the time spent jogging

\(y\) be the time spent bike riding

\(x+y=75\)

\(y=15+x\)

\(x+15+x=75\\\Rightarrow 2x+15=75\\\Rightarrow x=\dfrac{75-15}{2}=30\)

Time spent jogging is 30 minutes

\(y=60\)

\(x+y=75\)

If he rides his bike 15 minutes longer than he jogs then he would have to jog \(60-15=45\) minutes.

So, the total time would be \(45+60=105\) minutes which is not equal to 75 minutes.

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Answer:

y = 7 - 5x

Step-by-step explanation:

20x + 4y = 28

4y = 28 - 20x

y = 28/4 - 20x/4

y = 7 - 5x

-TheUnknownScientist

Answer:

It is Linear

Step-by-step explanation:

We know the regular Linear equation is y = mx + b. In this case, the mx and the b switched places, but the equation still works the same way. y = -2x + 3

Answer:

yes

Step-by-step explanation:

Linear equations look like this

y=mx+b

where m is the slope

and b is the y intercept

if we switch -2x and the 3 we have the following

y= -2x+3

which looks like our y=mx+b

The solution x(t) of the equation x = rx + x', where r > 0 is fixed, approaches infinity in finite time starting from any initial condition x = 0.

We can solve the differential equation x' = rx + x using separation of variables. Rearranging the equation, we get:

x' - rx = x

This is a linear first-order differential equation with integrating factor e^(-rt). Multiplying both sides by e^(-rt), we obtain:

e^(-rt)x' - re^(-rt)x = e^(-rt)x

Using the product rule for derivatives, the left-hand side becomes:

(d/dt)[e^(-rt)x] = e^(-rt)x'

Substituting this into the equation, we get:

(d/dt)[e^(-rt)x] = e^(-rt)x

This equation can be integrated to obtain:

e^(-rt)x = C

where C is a constant of integration. Solving for x, we get:

x = Ce^(rt)

Since r > 0, the exponential function e^(rt) grows without bound as t approaches infinity. Therefore, the solution x(t) of the differential equation also grows without bound in finite time starting from any initial condition x = 0. This means that x(t) approaches infinity as t approaches a certain finite value, which depends on the value of r.


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