find the magnitude and direction of the weakest magnetic field required to levitate a wire of length 5.30 cm and mass 1.80 g, carrying a current of 8.16 a.

Answer:

C

Explanation:

..

Answer:The conclusion is valid for the data recorded

Explanation:

Answer:

D

Explanation:

Well, light travelling in a year is a light year.

Answer:

D: Lightyear

Explanation:

One lightyear (ly) is the distance traveled by light in year time.

It is equal to \(9.46 * 10^{15} \ m\).

Answer:

a 30kg

Explanation:

a 30kg

Answer:Mars is about half the size of Earth by diameter and has a much thinner atmosphere, with an atmospheric volume less than 1% of Earth's. The atmospheric composition is also significantly different: primarily carbon dioxide-based, while Earth's is rich in nitrogen and oxygen.

Explanation:

Answer:The atmosphere of Mars is much thinner than Earth's. The average surface pressure is only about 610 pascals (0.088 psi) which is less than 1% of the Earth's value. The currently thin Martian atmosphere prohibits the existence of liquid water at the surface of Mars, but many studies suggest that the Martian atmosphere was much thicker in the past.

Explanation:

(a) The acceleration of the masses is determined as 1.1 m/s² in the direction of the 5 kg mass.

(b) The tension in the string in terms of gravity is T = g.

(a) The acceleration of the masses is calculated by applying Newton's second law of motion.

F(net) = ma

where;

(5 kg x 9.8 m/s² ) - (1 kg + 3 kg )9.8 m/s² = ma

9.8 N = (5kg + 1 kg + 3 kg )a

9.8 = 9a

a = 9.8 / 9

a = 1.1 m/s² in the direction of the 5 kg mass.

(b) The tension in the string in terms of gravity is calculated as follows;

T = ( 5kg)g - (1 kg + 3 kg ) g

T = 5g - 4g

T = g

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Answer:

b

Explanation:

because the metalloids are the thing in the middle

Type of supernova:

1. Type Ia supernova

2. Type II supernova

3. Type Ib/c supernova

Type Ia supernova is characterized by the explosion of a white dwarf star in a binary system, where the white dwarf accretes matter from its companion star until it reaches a critical mass, triggering a runaway nuclear fusion. These supernovae have a consistent peak brightness, making them useful for measuring cosmic distances and studying dark energy.

Type II supernova occurs when a massive star runs out of fuel and undergoes gravitational collapse. The core collapse leads to an explosion, ejecting outer layers into space. Type II supernovae exhibit hydrogen lines in their spectra, indicating the presence of hydrogen in the star's outer envelope.

Type Ib/c supernova involves the collapse of a massive star that has already lost its outer envelope of hydrogen. These supernovae lack hydrogen lines in their spectra but show evidence of helium (Type Ib) or helium and other elements (Type Ic). They are associated with the core collapse of a Wolf-Rayet star or a stripped-envelope star.

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Type Ia supernovae are useful as standard bulbs for determining distances on a large scale. They occur when a white dwarf exceeds the Chandrasekhar limit and explodes. Type II supernovae are less luminous than type Ia supernovae and are only seen in galaxies with recent, massive star formation.

A type Ia supernova occurs when a white dwarf accretes enough material from a companion star to exceed the Chandrasekhar limit and then collapses and explodes. These supernovae reach nearly the same luminosity at maximum light, making them useful as standard bulbs for determining distances on a large scale. They can be observed at very large distances due to their extreme brightness.

In contrast, type II supernovae are about 5 times less luminous than type Ia supernovae and are only seen in galaxies with recent, massive star formation. Type II supernovae are also less consistent in their energy output during the explosion and can have a range of peak luminosity values.

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The catch in this one is:  We don't know how much force the student used to push the bike.  

It wasn't necessarily the 100N.  That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium.  The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push.  That's what's so great about wheels !  That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel".  I looked at it, I turned it over and I looked on all sides. I thought it was too simple.  I didn't know then it was elegant. I threw him out.  I was so dumb.  I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ?  Stay tuned:

-- The bike covered 15 meters in 5 seconds.  Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.  

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

Power = 36.73 watts

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 18 × 1.62

We have the final answer as

Hope this helps you

According to Newton's laws, the net force on a satellite in an elliptical orbit is given by the following formula:

\(F = (GMm) / r^2\)

where F is the net force, G is the gravitational constant, M is the mass of the central body (e.g., Earth), m is the mass of the satellite, and r is the distance between the center of the central body and the satellite.

To determine the location of the satellite at any given point in time, we need to know its position and velocity. The motion of the satellite can be described by Kepler's laws of planetary motion, which state that the orbit of a planet (or satellite) is an ellipse with the central body at one of the foci.

Given the position and velocity of the satellite at one point in time, we can use numerical methods (such as Euler's method or the Runge-Kutta method) to calculate its position and velocity at any subsequent point in time. These methods involve calculating the net force on the satellite at each point in time and using it to update the satellite's position and velocity.

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An iron nail, when it loses its magnetism, often iron behaves as a magnet when electric current flows only through the coil of insulated wire wrapped around it. There is therefore, a way to use this principle to create a motor.

If a current flows through a wire, electrical energy is said to be converted into different kinds of energy such as  heat in a heating element, etc. The electric current could also be transformed or made to create a mechanical energy, which is what happens in an electric motor.

A motor is simply known as a generator working in reverse. This can be liken to a motor when a wire is put in between the two paper clips that are connected to the battery.

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Explanation:

The sun gravity keeps the solar system i.e planets in its place and orbits if there is no sun the planets would flying off and  It would be complete and utter chaos in our solar system

Answer: a = 8.10 m/s^2

Explanation:

The car starts at rest, so:

V0= 0m/s

t= 5.21m/s

S = 110.0 m

Using one of the five uniformly accelerated motion formulas

S= V0t + 1/2 at^2

but V0 = 0 m/s

S = 1/2 at^2

a= 2S/ t^2

a = 2(110m)/ (5.21 s)^2

a = 8.10 m/s^2

none of them

Explanation:

the horizontal speed doesn't matter and if i got it right both of them started from the same height and both of them fell to the water (none of the jumped *higher only farther) and that's the only thing that matters. so they'll both end up there at the same time cause only gravity is affecting their movement process among the way.

Answer:

TRUMP KILLED 223,000 PEOPLE AND HE STILL DOES NOT CARE! HE SAYS WE ARE ROUNDING THE CORNER. HE CAN NOT EVEN HAND OUT STIMULUS TO DYING BUISNESSES AND AIRLINES!

Explanation:

TRUMP KILLED 223,000 PEOPLE AND HE STILL DOES NOT CARE! HE SAYS WE ARE ROUNDING THE CORNER. HE CAN NOT EVEN HAND OUT STIMULUS TO DYING BUISNESSES AND AIRLINES!

The overall reaction is balanced by the transfer of electrons between the electrodes, leading to a change in the oxidation states of the species involved in the reaction. Gas produced at this electron is hydrogen.

At the negative electrode, electrons are supplied to the electrode. This process is called reduction, as it involves the addition of electrons to a species in the solution. The species that accepts the electrons will be reduced and will have a lower oxidation state. The gas that is produced at the negative electrode depends on the reaction that occurs at the electrode. For example, if the reaction is the reduction of water to hydrogen, then hydrogen gas will be produced at the negative electrode. If the reaction is the reduction of a metal ion, then the metal will be deposited on the electrode and the corresponding gas will not be produced. In general, the reaction at the negative electrode is chosen such that it provides electrons to the overall electrochemical reaction that is taking place, while the reaction at the positive electrode (the anode) consumes electrons. The overall reaction is balanced by the transfer of electrons between the electrodes, leading to a change in the oxidation states of the species involved in the reaction.

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Answer:

Explanation:

Use the following equation:

\(E=\frac{q}{F}\) and solve for F:

\(F=\frac{q}{E}\) and filling in:

\(F=\frac{.0600}{1500}\)

F = 4.0 × \(10^{-4\) N

An element of atomic number 88 decays radioactively to an element of atomic number 82. The emissions that achieve this result is one alpha particle. The correct option is D. The emission that achieves this result is one alpha particle. The correct option is C.

To determine the emissions that achieve the radioactive decay from an element with atomic number 88 to an element with atomic number 82, we need to consider the changes in atomic number and mass number during the decay process.

In a radioactive decay, the atomic number decreases by the emission of a particle, and the mass number decreases by a specific amount as well.

Atomic number of initial element = 88

Atomic number of final element = 82

From this information, we can conclude that the decay process involves the emission of an alpha particle.

The emission of an alpha particle corresponds to the emission of a helium nucleus, which consists of two protons and two neutrons. This emission reduces the atomic number by 2 and the mass number by 4.

Therefore, the emission that achieves this result is C, one alpha particle.

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I = 0.00744 A (Amps)

Hi there !

Ohm's law formula

I = V/R

I = 3.5V/470Ω

I = 0.00744 A

Good luck !

Zeolite thermal storage held its heat longer.

or it can be water also

Biomass, Fossil Fuels, Hydroelectric, Solar Energy

Answer: 1. Spinning a magnet inside a coil. Electromagnetic induction IOW

2. Photo electricity

3. Thermo electricity

Answer:

4?

Explanation:

Within the subject of technology, radiogenic heat may be described because of the type of warmth that is released when radioactive isotopes disintegrate. consequently, we say that the thermal strength is launched by means of the nuclear disintegration of the radioactive isotopes.

Approximately 50% of the Earth's inner warmness originates from radioactive decay. four radioactive isotopes are chargeable for the general public of radiogenic warmness because of their enrichment relative to different radioactive isotopes uranium-238 (238U), uranium-235 (235U), thorium-232 (232Th), and potassium-40 (40K).

Radioactive heating refers back to the power dissipated within the interiors of planets, satellites, or asteroids as a consequence of the radioactive decay of radioactive isotopes (see radiochemistry). Radioactive isotopes are characterized by their decay energies and their half-lives.

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A car moves around a wide turn going 45 miles / hour the whole time. The car has a constant acceleration, therefore the correct answer is option D.

It is defined as motion when the object is moving in a circle with a constant speed and its velocity is changing with every moment because of the change of direction.

As given in the problem if a car moves around a wide turn going 45 miles/hour the whole time,

Even if the speed of the car is constant but the direction of the motion is changing continuously resulting in constant acceleration.

Thus, an automobile makes a wide turn while traveling at a constant 45 miles per hour. The right response is D since the automobile accelerates continuously.

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Answer:

A-to determine how tempreture affects bounce height.

This is an exercise in Rectilinear Uniformly Varied Motion (MRUV) is a type of motion in which an object moves in a straight line and experiences changes in its velocity at a constant rate. In this type of motion, the acceleration of the object remains constant over time.

The distinctive feature of the MRUV is that the velocity of the object changes uniformly, that is, its velocity increases or decreases by a constant amount in each unit of time. If the object experiences a positive acceleration, its velocity increases with time. On the other hand, if the object experiences a negative acceleration, its speed decreases.

In an MRUV, constant acceleration has a direct impact on displacement and the time it takes for the object to reach a certain speed. Also, the direction of the acceleration determines whether the object is accelerating or decelerating relative to its initial motion.

This type of movement is found in various situations of daily life, such as the launch of an object upwards and its subsequent fall, the movement of cars on a road with acceleration or braking, or even the study of bodies in free fall.

Vf = V₀ + a × t

Where:

In this case, the initial velocity (vi) is 1 m/s, the acceleration (a) is -1 m/s^2 (negative because it indicates deceleration), and the time (t) is 4 seconds.

Substituting these values into the formula, we get:

Vf = V₀ + a × t

Vf = 1 m/s + (-1 m/s²) × 4 s

Vf = 1 m/s - 4 m/s

Vf = -3 m/s

The direction of the angular momentum vector can be determined by using the right-hand rule.

If the fingers of the right hand are curled in the direction of the rotation (clockwise in this case), then the thumb points in the direction of the angular momentum vector. Therefore, the answer is option E, counterclockwise. The angular momentum vector is perpendicular to both the axis of rotation and the direction of the velocity of the rotating disc. In this case, since the disc is rotating clockwise, the angular momentum vector is directed counterclockwise, which means that it is coming out of the plane of the page towards the observer. It is important to note that angular momentum has direction, and it is a vector quantity.This means that it has both magnitude and direction, and it follows the laws of vector addition and subtraction.

Therefore, it is important to correctly determine the direction of the angular momentum vector in order to accurately describe the motion of rotating objects.

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When an object is spinning around its center, as you move out from the center and the radius increases: the angular velocity decreases

The fact that the angular velocity of an object that is spinning around its center decreases as the object moves away from the center is due to the fact that as it moves away from the center the radius increases and because the relationship between radius and angular velocity is inversely proportional, as the radius increases the angular velocity decreases.

When an object is in uniform circular motion, the angle described by the radius in each unit of time is known as angular velocity. It is measured in units of (rad/s) (revolutions/s).

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According to the statement, on the ball thrown upward from the ground, it will reach the ground at time t=12 seconds.

The ball will reach the ground at time t when its vertical displacement is zero. We can use the equation for vertical displacement, \(y = v0t - (1/2)gt^2\), where v0 is the initial velocity, g is the acceleration due to gravity, and t is the time. Plugging in the given values, we get:

\(0 = 60t - (1/2)(10)t^2\)

Rearranging the equation and factoring out t, we get:

t(60 – 5t) = 0

This gives us two possible values for t: 0 and 12 seconds. Since the ball is thrown at t=0, the time when it reaches the ground is t=12 seconds.

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Answer: Physical fitness can be defined as the ability of a person to perform daily routine tasks without any ailment.

Explanation:

Dance workouts can help in improving the physical fitness of the person.

This may involve improvement of the cardiovascular strength.

This may also help in improving the strength and endurance of a person.

This improves the stamina, flexibility, and composition of the body.

The dance also helps in maintaining balance and attaining the correct posture.