Find the length of x 3/5=6/x

Answers

Answer 1

3/5 = 6/x

3x = 30

x = 10

PLEASE pay attention in class, you basically asked every question on what seems to be homework

Answer 2

10 is the answer to this problem.


Related Questions

The equation a=180(n-2)/n represent the angle measures,a in a regular n-sided polygon. When the equation is Solved for n,n is equal to a fraction with a denominator of a-180. What is the numerator of the fraction.

Answers

Answer:

The

numerator is 360

Step-by-step explanation:

What we need to do here is make n the subject of the formula;

a = 180(n-2)/n

an = 180n-360

180n - an = 360

n(180-a) = 360

n = 360/(180-a)

Angel buys a two-pint bottle of juice for $3.84. What is the unit rate of the cost of the juice per fluid ounce?
How many fluid ounces of juice did Angel buy?

Answers

Answer:

I believe it is $0.12

Step-by-step explanation:

there are 16 oz in a pint and because there are 2 pints double that to equal 32 and then divide the price by the quantity which in this case would be 3.84/32 which is equal to 0.12, so it should be $0.12

Answer: the unit rate or how much each fl ounce cost would be $0.12

becuase she bought 32 fl oz

Step-by-step explanation:

Suppose that, in an alternate universe, the possible values of m
l

are the integer values including 0 ranging from −l−1 to l+1 (instead of simply −l to +l ). How many orbitals would exist in each of the following subshells? A. p subshell B. d subshell Which atomic orbitals have values of n=3 and I=1 ?

Answers

A. In the alternate universe, the p subshell would have 5 orbitals.

B. In the alternate universe, the d subshell would have 10 orbitals.

In the alternate universe where the possible values of mℓ range from -l-1 to l+1, the number of orbitals in each subshell can be determined.

A. For the p subshell, the value of l is 1. Therefore, the range of mℓ would be -1, 0, and 1. Including the additional values of -2 and 2 from the alternate universe, the total number of orbitals in the p subshell would be 5 (mℓ = -2, -1, 0, 1, 2).

B. For the d subshell, the value of l is 2. In the conventional universe, the range of mℓ would be -2, -1, 0, 1, and 2, resulting in 5 orbitals. However, in the alternate universe, the range would extend to -3 and 3. Including these additional values, the total number of orbitals in the d subshell would be 10 (mℓ = -3, -2, -1, 0, 1, 2, 3).

Therefore, in the alternate universe, the p subshell would have 5 orbitals, and the d subshell would have 10 orbitals.

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Which of the following is equivalent to the expression below?
3(5-2i)

Answers

Answer: 15 - 6i

Step-by-step explanation:

3(5-2i)

3×5+3×(−2i)

Do the multiplications.

15−6i

Ferris wheel in London; England It stands 135 meters tall with a The London Eye iS a giant diamederof 120 meters: It takes half an hour to complete one revolution form hlt) = A cos( Br D t0 model the height; h (in meters). Find cosine funclion of the (in minutes). Assume the passenger passenger riding the London Eye as a function of time 0. Sketch the graph of one period on the next page and is at the bottom of the wheel at time use it to help you answer the following questions and create your function What is a rider' height at m = 0 minutes? (Hint: It is not 0 meters) 2. How long does it take for a rider to reach the top? What is the rider's height at that time? What is the period of this function? Use the period to find What is the vertical shift and amplitude of this function? 5 . Find The Equation Of Your Cosine Function, Use your function to find a rider's height at =21minutes. Sketch the graph ofyour function (This helps to answer the previous questions)

Answers

The height of a rider on the London Eye Ferris wheel in London can be modeled by the function h(t) = A * cos(B * t), where t represents time in minutes. The Ferris wheel stands 135 meters tall with a diameter of 120 meters. It takes half an hour (30 minutes) to complete one revolution.

1. At t = 0 minutes, the rider is not at the bottom of the wheel but at the midpoint of the wheel's diameter, so the rider's height is equal to the radius of the wheel, which is half of its diameter. Therefore, the rider's height at t = 0 minutes is 120/2 = 60 meters.

2. To determine the time it takes for the rider to reach the top, we need to find the period of the cosine function. The period (T) is the time it takes for one complete cycle of the function. In this case, the period is equal to the time it takes for the Ferris wheel to make a full revolution, which is 30 minutes. So, the rider reaches the top after half of the period, which is T/2 = 30/2 = 15 minutes. At that time, the rider's height is equal to the sum of the radius of the wheel and its height, which is 60 + 135 = 195 meters.

3. The period of the cosine function is T = 30 minutes.

4. The vertical shift of the function represents the average height of the rider throughout one complete cycle. In this case, the average height is the sum of the radius and the height of the Ferris wheel divided by 2, which is (60 + 135)/2 = 97.5 meters. Therefore, the vertical shift of the function is 97.5 meters. The amplitude of the function is half of the vertical distance between the maximum and minimum values, which is (135 - 60)/2 = 37.5 meters.

5. The equation of the cosine function is h(t) = 97.5 + 37.5 * cos((2π/30) * t). To find the rider's height at t = 21 minutes, we substitute t = 21 into the equation: h(21) = 97.5 + 37.5 * cos((2π/30) * 21) ≈ 185.11 meters.

In summary, the rider's height at t = 0 minutes is 60 meters. It takes 15 minutes for the rider to reach the top, at which point their height is 195 meters. The period of the function is 30 minutes. The vertical shift is 97.5 meters, and the amplitude is 37.5 meters. Using the cosine function, the rider's height at t = 21 minutes is approximately 185.11 meters.

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Does anyone know the answer?
Mathematics question:

A school dedicated 20% of the courtyard area for students to start a garden. The students want to know how much of the 950-square-foot space they will be able to use.​

Answers

The part of 950 foot² space the students can use is,

⇒ 190 foot²

Since,

Suppose the value of which a thing is expressed in percentage is "a'

Suppose the percent that considered thing is of "a" is b%

Then since percent shows per 100 (since cent means 100), thus we will first divide the whole part in 100 parts and then we multiply it with b so that we collect b items per 100 items(that is exactly what b per cent means).

Thus, that thing in number is

a x b / 100

Students can use 20% of 950-sq.foot.

Now, 20% of 950-sq.-foot is derived as:

= 20 x 950/100

= 190 foot²

Thus, the part of 950 foot² space the students can use is: 190 foot².

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Record the length of the gray rectangle in units of centimeters?!

Record the length of the gray rectangle in units of centimeters?!

Answers

I’d round it off to about 1.38 centimeters

Suppose that particles enter a system as a Poisson process at a rate of λ per second. Each particle in the system at time t has probability μh+o(h) of leaving the system in the interval (t,t+h] seconds. Any particle in the system at time t has probability θh+o(h) of being spontaneously split (hence creating a new particle, in addition to the original particle) in the interval (t,t+h] seconds. The resulting new particle behaves in the same way as any other particle, as does the original particle: either of these can leave or spontaneously split at the same rates given above. There is no restriction on the number of times that a particle can split. Particles enter the sytem, leave the system, or spontaeneously split independently of one another and the probability of two or more of these occurring in (t,t+h] seconds is o(h). The parameters λ,μ,θ are all positive. Let X
t denote the number of particles in the system at time t seconds. a. Write down the first five columns and rows of the generator matrix for the process X
t. b. Compute the expected time until we have seen two brand new particles entering the system (that is, the new particles are not due to the splitting of particles).

Answers

The expected time until two brand new particles enter the system is 2/λ.The goal is to determine the generator matrix for the process and compute the expected time until two new particles enter the system.


In this scenario, particles enter a system as a Poisson process, with a certain rate of arrival. The particles can either leave the system or spontaneously split into new particles, according to specific probabilities.
(a) The generator matrix captures the transition rates between different states of the system. In this case, the states are represented by the number of particles in the system at a given time. The first five columns and rows of the generator matrix for the process X_t would provide the transition rates between states 0, 1, 2, 3, and 4. The matrix elements will depend on the arrival rate λ, leaving probability μ, and splitting probability θ.
(b) To compute the expected time until two brand new particles enter the system, we need to consider the arrival, leaving, and splitting processes. The expected time can be determined by analyzing the transitions between states and their respective rates. The specific calculations will depend on the values of λ, μ, and θ.
By addressing these two parts, we can establish the generator matrix for the process and calculate the expected time until two new particles enter the system, providing insights into the dynamics of the particle system.The expected time until two brand new particles enter the system is 2/λ.

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Pls help solve this question... I will mark branliest for best answer...

Pls help solve this question... I will mark branliest for best answer...

Answers

Answer:

115 cm

Step-by-step explanation:

Total length of ribbon required to wrap a rectangular gift is given by -

Length of ribbon = 2l + 2b + 4t + extra

Length of ribbon = 2×30 + 2×20 + 4×2 + 15

Length of ribbon = 115 cm

Calculate the length of line AB.

Calculate the length of line AB.

Answers

Answer:

Step-by-step explanation:

i can't see the image.. brother so how can i figure it out what problem you are facing .

what grade in the us takes advanced single-variable quadratic equations and complex numbers

Answers

Advanced single-variable quadratic equations and complex numbers are advanced topics studied in high school mathematics curricula in the US. The specific grade at which they are introduced and studied may vary depending on the state, district, or school.

In general, single-variable quadratic equations are usually introduced in the 9th or 10th grade in high school, but some schools may introduce them in earlier grades.

These equations are a type of polynomial equation of degree two that can be written in the form

ax² + bx + c = 0,

where a, b, and c are constants and x is a variable. The study of quadratic equations includes topics such as factoring, completing the square, and the quadratic formula.

Complex numbers are usually introduced in high school algebra 2 courses. Algebra 2 is a 10th or 11th-grade course in the US that builds on the concepts learned in algebra 1. Complex numbers are numbers that can be expressed in the form a + bi, where a and b are real numbers and i is the imaginary unit, which is defined as the square root of -1. The study of complex numbers includes topics such as complex arithmetic, the complex plane, and the quadratic formula for complex numbers.In conclusion, advanced single-variable quadratic equations and complex numbers are typically studied in high school math courses in the US. The specific grade at which they are studied may vary, but they are usually introduced in the 9th or 10th grade for quadratic equations and the 10th or 11th grade for complex numbers.

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Suppose there are three urns. Urn 1 contains two red balls and two black balls. Urn 2 contains one red ball and three black balls. Urn 3 contains two red balls and one black ball. A ball is drawn at random from Urn 3. If it is red, a second ball is drawn at random from Urn 2, but if it is black, the second ball is drawn at random from Urn 1.

a) What is the probability of the second ball being drawn from Urn 2?

b) What is the probability that the second ball is black, given that it is drawn from Urn 2?

c) What is the probability that the second ball is black?

d) What is the probability that the second ball was drawn from Urn 1, given that it is black?

e) What is the probability that the first ball drawn was red, given that the second ball drawn is black?

f) What is the probability that both balls drawn are red?

Answers

a) The probability of the second ball being drawn from Urn 2 is 2/3.

b) The probability that the second ball is black given that it is drawn from Urn 2 is 3/4.

c) The probability that the second ball is black is 11/24.

d) The probability that the second ball was drawn from Urn 1 given that it is black is 4/11.

e) The probability that the first ball drawn was red, given that the second ball drawn is black is 4/11.

f) The probability that both balls drawn are red is 1/6.

Given that Urn 1 contains two red balls and two black balls, the probability of drawing one ball is 1/2. Urn 2 contains one red ball and three black balls, the probability of drawing one ball is 1/4. Urn 3 contains two red balls and one black ball, the probability of drawing one ball is 1/3.

Let R1 and R2 represent the events of drawing a red ball from Urn 1 and Urn 2, respectively.

Also, let B1 and B2 represent the events of drawing a black ball from Urn 1 and Urn 2, respectively.

For this probability problem, we need to consider the three conditional events: drawing a second ball from Urn 2 if the first ball is red from Urn 3, drawing a second ball from Urn 1 if the first ball is black from Urn 3, and the overall probability of drawing a second ball that is black.

a) If the first ball is red from Urn 3, then there are two possible scenarios. Either the second ball is drawn from Urn 1, or it is drawn from Urn 2. The probability of the second ball being drawn from Urn 2 is 2/3, and the probability of it being drawn from Urn 1 is 1/3.

b) The probability that the second ball is black given that it is drawn from Urn 2 is 3/4.

c) If we consider all possible scenarios, the probability that the second ball is black is

(1/3)×(1/2)+(2/3)×(3/4) = 11/24.

d) The probability that the second ball was drawn from Urn 1 given that it is black is P(B1)×P(1|B1) / P(B),

where P(B1) is the probability of drawing a black ball from Urn 1, P(1|B1) is the probability of drawing from Urn 1 given that the first ball is black, and P(B) is the probability of drawing a black ball regardless of which urn it is drawn from. Plugging in the values,

we get (1/2)×(1/2) / (11/24) = 4/11.

e) The probability that the first ball drawn was red given that the second ball drawn is black is P(R1|B2) = P(B2|R1)×P(R1) / P(B2), where P(R1) is the probability of drawing a red ball from Urn 1, and P(B2|R1) is the probability of drawing from Urn 2 given that the first ball is red. Plugging in the values, we get (3/4)×(1/2) / (11/24) = 4/11.

f) The probability that both balls drawn are red is P(R1)×P(R2|R3) = (1/2)×(1/4) = 1/8.

Therefore, the probability of the second ball being drawn from Urn 2 is 2/3. The probability that the second ball is black given that it is drawn from Urn 2 is 3/4. The probability that the second ball is black is 11/24. The probability that the second ball was drawn from Urn 1 given that it is black is 4/11. The probability that the first ball drawn was red given that the second ball drawn is black is 4/11. The probability that both balls drawn are red is 1/6.

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2. What are the last 2 digits of 1 + 2 + 3 + + 2005 2006​

Answers

Let S be the sum. So you have

S = 1 + 2 + 3 + … + 2004 + 2005 + 2006

as well as

S = 2006 + 2005 + 2004 + … + 3 + 2 + 1

Then

2S = (1 + 2006) + (2 + 2005) + … + (2005 + 2) + (2006 + 1)

2S = 2007 + 2007 + … + 2007 + 2007

2S = 2006 × 2007

S = (2006 × 2007)/2

S = 2,013,021

which makes the last two digits 21.

I need help answering that I’m lost and it’s a 3 step problem

I need help answering that Im lost and its a 3 step problem

Answers

hi hi hi i believe 32

variables employed in a regression model can be quantitative or qualitative. true or false?

Answers

True. Variables employed in a regression model can be both quantitative and qualitative.

Quantitative variables represent numerical data, while qualitative variables represent non-numerical data that fall into distinct categories or groups. Including both types of variables in a regression model allows for examining the relationship between the dependent variable and various predictors.

In regression analysis, variables used in the model can be quantitative or qualitative. Quantitative variables, also known as continuous variables, are measured on a numeric scale and represent quantities or magnitudes. Examples include age, income, temperature, or height. These variables can be used as predictors in regression models to analyze their impact on the dependent variable.

On the other hand, qualitative variables, also known as categorical or discrete variables, represent non-numeric data that fall into distinct categories or groups. Examples include gender, ethnicity, occupation, or education level. These variables can also be used in regression models by encoding them as dummy variables or indicator variables, allowing for the examination of their relationship with the dependent variable.

Including both quantitative and qualitative variables in a regression model provides a comprehensive analysis of the factors that influence the dependent variable. It allows for understanding the impact of numerical factors as well as the categorical characteristics on the outcome variable, facilitating a more thorough understanding of the relationship being studied.

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What are 3 numbers multiplied to get -24 and added to get -12.

Need help ASAP please

Answers

(-3)(-8)(-1)= -24

(-3)+(-8)+(-1)= -12

The triangle below is equilateral. Find the length of side x in simplest radical form with a rational denominator.

The triangle below is equilateral. Find the length of side x in simplest radical form with a rational

Answers

Answer:

x = 8

Step-by-step explanation:

If a triangle is equilateral, each vertex has an angle that is equal to 60 degrees

As we can see, we have two sets of similar right triangles

The value x faces the right angle and that makes it the hypotenuse

Also, the side measure 4 is the adjacent side to the angle 60

The trigonometric identity that relates the hypotenuse and the adjacent is the cosine

it is the ratio of the adjacent to the hypotenuse

Mathematically;

cos 60 = 4/x

x = 4/cos 60

x = 8

Write the coordinates of the vertices after a reflection over the y-axis.

Write the coordinates of the vertices after a reflection over the y-axis.

Answers

To reflect a figure over the y-axis, we simply change the sign of its x-coordinates while keeping the y-coordinates the same. So, the coordinates of the vertices after a reflection over the y-axis would be:

A'(-2, 1), B'(-1, 3), C'(1, 2), D'(2, 0)

When we reflect a figure over the y-axis, we are essentially flipping the figure horizontally along a vertical line passing through the origin.

This means that every point on the original figure is reflected across this vertical line, resulting in a new figure that is a mirror image of the original.

Thus, the coordinates of the vertices after a reflection over the y-axis are A'(-2, 1), B'(-1, 3), C'(1, 2), and D'(2, 0).

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The proportion of red marbles to blue marbles in a jar is 3 to 8. If there are 56 blue marbles in the jar, how many red marbles are there?

Answers

Answer:

21

Step-by-step explanation:

3:8

8x7 = 56

3x7 = 21

Five and nine tenths in expanded form and standard

Answers

Answer:

5×1 +9×0.15.9

Step-by-step explanation:

The verbiage "five and nine tenths" can refer to the mixed number 5 9/10, or to the decimal in standard form, 5.9. Simply converting the phrase to a decimal gets you the standard form.

The expanded form can be written a number of ways, depending on how you like to show the place value multipliers. The simplest expanded form is simply the sum of the digits:

  5 + 0.9

You can show the multipliers in standard form:

  5×1 + 9×0.1

Or, you can show the multipliers in exponential form:

  5×10⁰ +9×10⁻¹

The daily changes in the barometric pressure for four days are −0.05, 0.09, −0.04, and −0.08 inches. The mean change after five days is −0.01 inch. What is the change on the fifth day? Write your answer as a decimal.

Answers

The change on the fifth day is 0.03.

What is a mean?

A mean simply means the average of.a set of numbers.

Based on the information given, let the change in the fifth day be x. This will be illustrated as:.

= (-0.05 + 0.09 - 0.04 - 0.08 + x)/ 5 = -0.01

Crops multiply

-0.08 + x = -0.05

Collect like terms

x = -0.05 + 0.08

x = 0.03

The change is 0.03.

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What is the greatest struggle you’ve overcome?

Answers

Answer:

elemantary school

Step-by-step explanation:

I need help with this question it’s due today!

I need help with this question its due today!

Answers

Answer:

15

Step-by-step explanation:

4:5

4 x 3 = 12 girls

5 x 3 = 15 boys

12:15

Answer:

D. 15

Step-by-step explanation:

4:5

4/5×3/3=12/15

12/15.....12 girls, 15 boys

:) ur welcome


A full-service salon charges $15.00 for a haircut and $0.45 per hair roller used in a perm. What is the minimum number of hair rollers that your
budget will allow if you must spend more than $34.00, but less than $50.00 on the haircut and perm?

Answers

Answer:

43 hair rollers.

Step-by-step explanation:

The cost of the haircut ($15.00) and the hair rollers (0.45*43) would equal $34.35, just passing the minimum amount of $34.00.

find the area of the surface. the part of the plane 13x + 5y + z = 65 that lies in the first octant

Answers

the area of the surface that corresponds to the part of the plane 13x + 5y + z = 65 lying in the first octant is 32.5 square units.

To find the area of the surface that corresponds to the part of the plane 13x + 5y + z = 65 lying in the first octant, we need to find the equation of the portion of the plane that lies in the first octant and then calculate the surface area of that portion.

First, we need to find the intercepts of the plane with the x, y, and z-axes. Setting x = 0, we get:

5y + z = 65

Setting y = 0, we get:

13x + z = 65

Setting z = 0, we get:

13x + 5y = 65

Solving these three equations simultaneously, we get:

x = 5, y = 13, z = 0

So the plane intersects the x-axis at (5,0,0), the y-axis at (0,13,0), and the z-axis at (0,0,65).

The part of the plane that lies in the first octant is bounded by the x-axis, the y-axis, and the line connecting (5,0,0) and (0,13,0). This triangular region has a base of length 5 and a height of 13, so its area is (1/2)513 = 32.5.

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Porter read 20% of the Star Wars book. He read 8 pages of the book. Write the number of pages in the Star Wars book

Answers

Answer: 40 pages in total

Explanation: Porter has read 20% of the book and this translates to 8 pages of the book.

20% = 8 pages

Assume the total number of pages is x:

20% * x = 8

0.2x = 8

x = 8 / 0.2

x = 40 pages in total

Answer:

40 pages in the book

Step-by-step explanation:

8/40 = .20

3
All 25 students in our class were surveyed about what their favorite food is. 11 students chose pizza. What
percentage of the class chose pizza?

Answers

Easy

\( \frac{11}{25} \times 100 = \frac{11}{25} \times 25 \times 4 \\ \)

\( = 11 \times 4 = 44 \: \: percent\)

So %44 of your class students chose pizza.

The percentage of the class chose pizza = 44%

What is percentage?

"It is a number or ratio that can be expressed as a fraction of 100."

For given example,

Total number of students = 25

the number of students who chose pizza as their favorite food = 11

So, the percentage of the class chose pizza would be,

⇒ (11/25) × 100 = 44%

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A 15 year variable rate mortgage offers a first year teaser rate of 3.11%. After that the rate starts at 5% adjusted based on actual interest rates. If the mortgage is $325,000 compute the monthly payment during the second year, if the interest rate increases to 5%

Answers

The monthly payment during the second year of the mortgage, when the interest rate increases to 5%, is approximately $1,654.58. To compute the monthly payment during the second year of a variable rate mortgage, we need to consider the loan amount, the interest rate, and the loan term.

Loan amount: $325,000

First-year teaser rate: 3.11%

Rate for the second year: 5%

To calculate the monthly payment during the second year, we can use the formula for calculating the fixed monthly payment on a mortgage:

Monthly payment = (Loan amount * Monthly interest rate) / (1 - (1 + Monthly interest rate)^(-n))

Where:

Loan amount = $325,000

Monthly interest rate = Annual interest rate / 12

Annual interest rate for the second year = 5%

n = Total number of monthly payments (12 payments in a year)

First, we calculate the monthly interest rate for the second year:

Monthly interest rate = 5% / 12 = 0.4167%

Next, we substitute the values into the formula:

Monthly payment = ($325,000 * 0.4167%) / (1 - (1 + 0.4167%)^(-12))

Using a calculator, we can evaluate this expression:

Monthly payment ≈ ($325,000 * 0.4167%) / (1 - (1 + 0.4167%)^(-12)) ≈ $1,654.58

Therefore, the monthly payment during the second year of the mortgage, when the interest rate increases to 5%, is approximately $1,654.58.

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find the area to the nearest hundredth use 3.14 for π​

find the area to the nearest hundredth use 3.14 for

Answers

Answer:

50.24

Step-by-step explanation:

you can use pi r^2

A backpack at the store cost $24.49. A pack of markers at the same store cost $3.82. You pay for both the backpack and pack of markers with a $50 bill. How much change will you receive?

Answers

Answer:

You will receive $21.69, assuming there's no tax ;).

I added the 24.49 to the 3.82 and got 28.31, then subtracted that from 50.

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