find the intercepts or the line that corresponds to the table of values.

I have a photo to go with it :)​

Answer:

A(4,5) (-2,2)

Step-by-step explanation:

8a)Y=x+2- 4 over x

X-2y+6 = 0 (simultaneous equation)

X-2(x+2-4 over x) + 6 =0 (solve for x)

8 over x - x + 2 = 0

X squared - 2x - 8 = 0

(x-4)(x+2) = 0

X=4 or x=-2

X1 =4 y1=5

X2=-2 y2=2

Coordinate (4,5) and (-2,2)

The number of ways choosing an even number using factorial can occur is 6! or 720.

Describe a factorial.

In mathematics, a factorial is a function that is applied to a non-negative integer, represented by the exclamation mark (!) symbol. The result of applying the factorial function to a number n, written as n!, is the product of  integers from 1 to n.

For example, 4! is equal to 4 x 3 x 2 x 1, which equals 24.

Now,

Given number are 1,2,3,4,5,6,7,8,9,10,11,12

from these numbers even numbers are 2,4,6,8,10,12

total even numbers=6

then, number of ways of selecting a even number=6! or 6*5*4*3*2*1

=720

Hence,

          The number of ways choosing an even number using factorial can occur is 6! or 720.

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Answer:

identify

Step-by-step explanation:

The following is the expected value of a number of books a student buys at the next book fair is 2.404 books.

The random variable b's expected value is then calculated as follows:

E(X) = 1 x 0.285 + 2 x 0.333 + 3 x 0.168 + 4 x 0.136 + 5 x 0.063 + 6 x 0.015 E(X)  = 2.404 books.

Thus, the expected value of discrete probability distribution is 2.404 books.

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The graph for the question is attached.

The population of interest is all students at the school, not just the 30 students in the statistics class who were surveyed.

The average hours of television per day in the sample is likely not representative of the average hours of television watched per day in the population. This is because the sample only consists of 30 students from the statistics class, which may not be a diverse and random representation of the entire school population.

The parameter of interest is the average hours of television watched per day by all students at the school.

The numeric value of the statistic corresponding to the above parameter is 12 hours.

The variable measured on each student is the number of hours of television watched per day.

The variable is quantitative, as it involves numerical values.

Two statistics that the student could use to summarize the variable are mean and median. The mean would give the average hours of television watched per day, while the median would provide the middle value in the data, which can help understand the central tendency of the data.

One graph that the student could use to summarize the variable is a histogram. A histogram would show the distribution of the data, which can help visualize how the hours of television watched per day are spread across the sample.

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The monthly rate for the given loan is 1.0118%.The annual rate for this loan is 12.1423%.

Given loan: $150,000

Payment per month: $1,770

Duration of loan: 10 years

Interest = ?

The formula for monthly payment is given by:

\(PV = pmt x (1 - (1 + r)^-n) / r\)

Where, PV is the present value, pmt is the payment per period, r is the interest rate per period and n is the total number of periods.Solving the above formula for r will give us the monthly rate for the loan.

r = 1.0118%The monthly rate for the given loan is 1.0118%.The annual rate can be calculated using the following formula:

Annual rate = \((1 + Monthly rate)^12 - 1\)

Annual rate = 12.1423%

The annual rate for this loan is 12.1423%.The effective annual rate can be calculated using the following formula:

Effective annual rate =\((1 + r/n)^n - 1\)

Where, r is the annual interest rate and n is the number of times interest is compounded per year.If interest is compounded monthly, then n = 12

Effective annual rate = (1 + 1.0118%/12)^12 - 1

Effective annual rate = 12.6801%

The effective annual rate for this loan is 12.6801%.

Total amount paid after 10 years = Monthly payment x Number of payments

Total amount paid after 10 years = $1,770 x 120

Total amount paid after 10 years = $212,400

The total amount paid after 10 years is $212,400.

The future value for this loan can be calculated using the following formula:

FV = PV x (1 + r)^n

Where, PV is the present value, r is the interest rate per period and n is the total number of periods.If the loan is paid off in 10 years, then n = 120 (12 payments per year x 10 years)

FV = $150,000 x (1 + 1.0118%)^120

FV = $259,554.50

The future value for this loan is $259,554.50.

Thus, the monthly rate for the loan is 1.0118%, the annual rate for this loan is 12.1423%, the effective annual rate for this loan is 12.6801%, the total amount paid after 10 years is $212,400 and the future value for this loan is $259,554.50.

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Answer:

it c

Step-by-step explanation:

Answer:

One number line increases by 1, and the other increases by 6

Step-by-step explanation:

Answer:

1 : 4 = 1 / 4

Step-by-step explanation:

this is actually a concept

if two triangles are scaled copy and their sides are in 1 : 2 ratio, then their area will be in 1 : 4 ratio.

here, in the figure that triangle's sides ratio is 6 : 12 = 1 : 2

therefore, the scale factor will be 1 /4 ( 1 : 4 )

The space would cost at, $833.34 per month.

:: Total area = 1000 square feet

:: Cost per feet per year = $10

Therefore,

Total cost per year would be, equal to the product of total area and cost per unit area per year.

That is,

Total cost per year = 1000 x $10

That is, $10,000.

Now, we know, there are 12 months in an year.

So, cost per month is, ( total cost per year / 12 )

That is, therefore,

Cost per month = ($10,000 / 12)

Which equals to, $833.34 per month. (rounded off)

So,

The space cost at, $833.34 per month.

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The space cost you $833.33. per MONTH

To calculate the monthly cost, we first need to determine the annual cost of the space.

Given that the cost is $10 per square foot per year, we know, there are 12 months in an year and the space is 1,000 square feet, the annual cost of the space would be:

Annual cost = the space  * cost

Annual cost = 1,000 square feet * $10/square foot = $10,000

To convert this to monthly cost, we divide the annual cost by 12 (the number of months in a year):

Monthly cost = $10,000 / 12 = $833.33

Therefore, the monthly cost of the 1,000 square feet of space in the new building would be $833.33.

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The problem involves finding dh/dt, the rate of change of height of a cone given dV/dt (rate of change of volume) and dr/dt (rate of change of radius). Using the formula for the volume of a cone and differentiating it with respect to time, we can obtain an equation

To solve this problem, we need to use the formula for the volume of a cone: V = (1/3)πr²h, where V is the volume, r is the radius, and h is the height.

We're given dV/dt (rate of change of volume) = 0.5 m³/s, and dr/dt (rate of change of radius) = 0.1 m/s. We need to find dh/dt (rate of change of height).

First, differentiate the volume formula with respect to time (t):

dV/dt = (1/3)π(2r dr/dt h + r² dh/dt)

Now, plug in the given values (dV/dt = 0.5, dr/dt = 0.1):

0.5 = (1/3)π(2r(0.1)h + r² dh/dt)

To find dh/dt, you would need additional information about the cone's dimensions (radius and height) at that specific moment. With that information, you could solve for dh/dt and find the rate of change of volume with respect to height.

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Answer:

ysh what do you need?

Step-by-step explanation:

Answer:

the answer is 1.713 x 106

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

To find the geometric mean of two numbers, just find the product of those numbers and take the square root!

5 x 9.8 = 49

√49 = 7

I hope this helped!

Sincerely,

Rekifromsk8theinfinity

:D

Answer:

X,y=83/52 ,45/26

Step-by-step explanation:

just  look up your answer and you will find the step by step. Hopefully this helped :)

Answer:

12.5 cm

Step-by-step explanation:

An equalateral triangle is one with all the sides the same length.

Answer:

Step-by-step explanation:

Use the law of cosines:

Here

Apply law of cosines

\(\ \ \sf\longmapsto cosB=\dfrac{a^2+b^2+c^2}{2ac}\)

\(\ \ \sf\longmapsto cosB=\dfrac{22^2+21^2+16^2}{2(22)(16)}\)

\(\ \ \sf\longmapsto cosB=\dfrac{484+441+256}{704}\)

\(\ \ \sf\longmapsto cosB=\dfrac{1181}{704}\)

\(\ \ \sf\longmapsto cosB=0.42\)

\(\ \ \sf\longmapsto B=cos^{-1}(0.42)\)

\(\ \ \sf\longmapsto B=64.8°\)

Answer:

A and C

Step-by-step explanation:

the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

To write the system of ordinary differential equations (ODEs) for the transition probabilities Pᵢⱼ(t) of the given continuous-time Markov chain, we need to consider the rate at which the system transitions between different states.

Let Pᵢⱼ(t) represent the probability that the Markov chain is in state j at time t, given that it started in state i at time 0.

The ODEs for the transition probabilities can be written as follows:

dP₁₂(t)/dt = q₁₂ * P₁(t) - q₂₁ * P₂(t)

dP₁₃(t)/dt = q₁₃ * P₁(t) - q₃₁ * P₃(t)

dP₂₁(t)/dt = q₂₁ * P₂(t) - q₁₂ * P₁(t)

dP₂₃(t)/dt = q₂₃ * P₂(t) - q₃₂ * P₃(t)

dP₃₁(t)/dt = q₃₁ * P₃(t) - q₁₃ * P₁(t)

dP₃₂(t)/dt = q₃₂ * P₃(t) - q₂₃ * P₂(t)

where P₁(t), P₂(t), and P₃(t) represent the probabilities of being in states 1, 2, and 3 at time t, respectively.

Now, let's consider the second part of the question: Suppose that the initial state is 1. We want to find the probability that after the first transition, the process X(t) enters state 2.

To calculate this probability, we need to find the transition rate from state 1 to state 2 (q₁₂) and normalize it by the total rate of leaving state 1.

The total rate of leaving state 1 can be calculated as the sum of the rates to transition from state 1 to other states:

total_rate = q₁₂ + q₁₃

Therefore, the probability of transitioning from state 1 to state 2 after the first transition can be calculated as:

P(X(t) enters state 2 after the first transition | X(0) = 1) = q₁₂ / total_rate

In this case, the transition rate q₁₂ is 1, and the total rate q₁₂ + q₁₃ is 1 + 2 = 3.

Therefore, the probability of transitioning from state 1 to state 2 after the first transition is:

P(X(t) enters state 2 after the first transition | X(0) = 1) = 1 / 3

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The perimeter of triangle is 66.24 units.

What is triangle?

In Euclidean geometry, any 3 points, once non-collinear, verify a unique triangle and at the same time, a unique plane

Main body:

according to question :

c = 28

let the vertices be A,B,C

∠A= 30°

by using trigonometric ratios,

BC/ AB = sin30°

AB = C = 28

BC/28 = sin30°

BC = 28*sin30°

BC= 28*(1/2)

BC = 14

similarly

AB /CA = cos 30°

28/CA = √3/2

CA = 28*√3/2

CA = 14/√3

CA = 24.24

Hence , perimeter = AB +BC +CA = 28+14+24.24

                              =66.24 units

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Answer:

angleB = 41.4°

Step-by-step explanation:

✨ Trigonometry✨

cos theta = adj / hyp

theta = inverse-cos adj / hyp

theta = inverse-cos 12 / 16

theta = inverse-cos .75

theta = 41.4°

*theta is the 0 with a line through it

Answer:

122.5

Step-by-step explanation:

Answer:

Sierra would have 16 points

Step-by-step explanation:

5×4=20

8×\(\frac{1}{2}\)=4

20-4=16

Answer:

-5/4

Step-by-step explanation:

To find the slope, we have to use this formula:

\(\frac{y2-y1}{x2-x1}\)

in this case -2 is your first x

5 would be your first y

2 would be your second x

and 0 is your second y

so:

0 - 5

-------    = -5/4

2 - (-2)

Answer: 4/81

Step-by-step explanation:

You multiply 2/9 by 2/9 equaling 4 for the numerator and 81 for the denominator.

BRAINLIEST PLEASE!! :>

Hope it helps.

Answer:

\(length \: cant \: be \: negative \: but \\ change \: can \: negative \\ if \: length \: decreases \: then \: \\ change = final \: - initial \: will \: be \: negative \\ thank \: you\)

1. The values which the given number sentences true are:

a) 11 b) 5 c) 36

2. After substituting the value of  x we get the value for y as :

a) 6 b) 0 c) 7 d) 15

3. The number sentences are :

a) x ₋ y = 25

b) 5 × p = q ÷ 2

c) 2y ₋ 14 = 6

d) 15 × 4 = 4 ₋ (x₊y)

Given in the first bit we need to find the variables:

a) h ₊ 8 = 19

arrange the constants on one side.

h = 19 ₋ 8

h = 11

b) 2p ₋ 6 = 4

arrange the constants on one side.

2p = 4 ₊ 6

2p = 10

p = 10/2

p = 5

c) 1/3 y = 12

cross multiply.

y = 36

Now in the second exercise we are asked to substitute the x value and get the value of y.

a) y = 3x ₊ 2 if x =8

substitute x value in the equation.

y = 3(8) ₊ 2

y = 24 ₊ 2

y = 26

b) y = 4x ₋ 1 if  x = 1/4

y = 4(1/4) ₋ 1

y = 1 ₋ 1

y = 0

c) y = 0.2x ₊ 5 if x = 10

y = 0.2(10) ₊ 5

y = 2 ₊ 5

y = 7

d) y = 10x ₊ 12 if x = 0.3

y = 10(0.3) ₊ 12

y = 3 ₊ 12

y = 15

In the last third bit we need to frame equations for the given word problems.

a) The difference between two numbers is 25.

let the two numbers be x and y.

x ₋ y = 25.

b) The product of 5 and p is equal to quotient of q and 2.

5 × p = q ÷ 2

c) The difference between 14 and 2y is equal to 6.

2y ₋ 14 = 6

d) The product of 15 and 4 is equal to four less than the sum of x and y.

15 × 4 = 4 ₋ (x₊y)

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