find the fundamental units involved in derived units
newton
watt
joule
pascal
cubic meter ​

The distance traveled by the rollercoaster during the deceleration is 16.1 m.

The distance traveled by the rollercoaster during the deceleration is calculated by applying the following formula.

v² = u² + 2as

where;

When the rollercoaster stops, the final velocity, v = 0

0 = u² + 2as

-2as = u²

s = u² / -2a

s = (15 m/s) ² / (-2 x - 7 m/s²)

s = 225 / 14

s = 16.1 m

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The normal stress in portion AB is σ₁ = 79.48 psi and the normal stress in portion BC is σ₂ = 47.69 psi.

We can start by drawing a free body diagram of the polystyrene rod and identifying the unknown reactions at A and C:

|-------- 6 kips --------|

          A                       C

          |-----------------------|

          |                       |

          |          BC           |

          |          σ₂           |

          |          L₂           |

          |                       |

          |-----------------------|

          |                       |

          |          AB           |

          |          σ₁           |

          |          L₁           |

          |                       |

          |-------- 6 kips --------|

Where σ₁ and σ₂ are the normal stresses in portions AB and BC of the rod, respectively.

Next, we can use the equations of static equilibrium to solve for the reactions at A and C. Taking moments about point A, we have:

6 kips * L₂ + 6 kips * (L₁ + L₂) - Cz = 0

where z is the distance from A to the line of action of the force at C. Since the rod is symmetric about the midpoint of portion BC, we can take z = L₁ + L₂/2. Substituting the given values, we have:

6 kips * L₂ + 6 kips * (L₁ + L₂) - C(L₁ + L₂/2) = 0

Solving for C, we get:

C = (12 kips * L₁ + 18 kips * L₂) / (3 L₁ + 2 L₂)

Taking vertical forces, we have:

A + C - 12 kips - 6 kips - 6 kips = 0

Substituting the value of C we just obtained, we get:

A = 12 kips - C - 6 kips - 6 kips = 0.4 kips

Therefore, the reactions at A and C are A = 0.4 kips and C = 11.6 kips.

Next, we can calculate the normal stresses in each portion of the rod. Using the formula for normal stress, we have:

σ₁ = P₁ / A₁ = A₂ / A₁ * σ₂

where P₁ and A₁ are the axial load and cross-sectional area of portion AB, and A₂ is the cross-sectional area of portion BC. Since the rod is of uniform diameter and the areas of the cylindrical portions are proportional to their lengths, we have:

A₂ / A₁ = L₂ / L₁

Substituting this into the equation for σ₁, we get:

σ₁ = (L₂ / L₁) * σ₂

Substituting the given values, we have:

σ₂ = P₂ / A₂ = 6 kips / (π/4 * (0.6 in)^2) = 47.69 psi

σ₁ = (2.5 ft / 1.5 ft) * 47.69 psi = 79.48 psi

Therefore, the normal stress in portion AB is σ₁ = 79.48 psi and the normal stress in portion BC is σ₂ = 47.69 psi.

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To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:

F = I * L * B * sin(θ)

where:

F is the magnetic force,

I is the current in the wire,

L is the length of the wire,

B is the magnitude of the magnetic field, and

θ is the angle between the wire and the magnetic field.

In this case, the values are:

I = 30 A (current in the wire)

L = 2.0 m (length of the wire)

B = 55 mT = 0.055 T (magnitude of the magnetic field)

θ = 20° (angle between the wire and the magnetic field)

Substituting the values into the formula:

F = 30 A * 2.0 m * 0.055 T * sin(20°)

Calculating sin(20°):

F = 30 A * 2.0 m * 0.055 T * 0.3420

F ≈ 1.5714 N

Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.

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The conditions that determine which process occurs in a cell are largely based on the environment and the needs of the cell.

A cell is the basic unit of life. It is the smallest unit of an organism that is capable of independent functioning. Cells are composed of a variety of molecules, including proteins, lipids, carbohydrates, and nucleic acids. Cells are able to carry out functions such as energy production, metabolism, growth and division, movement, and communication.

These conditions include the availability of nutrients, the presence or absence of specific signaling molecules, the amount of oxygen, and the temperature. In addition, the genetic makeup of the cell and its response to internal and external cues can also determine which processes occur.

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(a) The first block  moves at 4.0 m/s in the same direction right after colliding.

(b) the system's total kinetic energy changes by  28.75 J

(c) the system's total kinetic energy changes by -1.25 J

Given;

First block's mass, m1, is 5 kg.

u1 = 3.0 m/s is the first block's starting speed.

m2 weight of the second block is 10.0 kg.

u2 = 2.0 m/s is the second block's initial speed.

v2 = 2.5 m/s is the second block's final speed.

Immediately following the impact, the first block block's Part (A) velocity is as follows:

Apply the law of conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2, where v1 is the speed of the first block after it collides.

(5 x 3.0) + (10 x 2.0) = 5.0v₁ + (10 x 2.5) (10 x 2.5)

35= 2.5v₁ + 25

2.5v₁ = 35-25

2.5v₁ = 10

v₁ = 10/2.5

v₁ = 4

2.5 m/s in the same direction for v1.

Change in the system's overall kinetic energy, part (B):

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

ΔK = (1/2m1v1^2 + 1/2m2v2^2) - (1/2m1u1^2 + 1/2m2u2^2)

ΔK is equal to (1/2 x 5 x 4^2 + 1/2 x 10 x 2.5^2) – (1/2 x 5 x 3^2 + 1/2 x 10 x 2^2).

ΔK = 71.25 J - 42.5 J

ΔK = 28.75 J

Change in part (C) of the system's total kinetic energy if the second block accelerates to 5.2 m/s

Determine the final speed of the first block using the conservation of linear momentum: m1u1 + m2u2 = m1v1 + m2v2 (5 x 3.0) + (10 x 2.0) = 5v1 + (10 x 4)

35 = 2.5v₁ + 40

2.5v₁ = -5

2.5v₁ = - 5 v₁ = - 5 / 2.5 \s v₁ = -2 m/s

Final kinetic energy minus beginning kinetic energy equals the change in kinetic energy.

K = (1/2m1v12 + 1/2m2v22) - (1/2m1u12 + 1/2m2u22)

K is equal to (1/2 x 5 x 22 + 1/2 x 10 x 2.52) - (1/2 x 5 x 3 + 1/2 x 10 x 2).

ΔK = 41.25 - 42.5 J

ΔK = -1.25 J

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Answer:

Cheetah cubs are in danger from predators like lions and hyenas which can track their prey by scent and so the mother and her cubs leave an area when their scent is too strong so that they are not hunted and the cubs survive.

Mother Cheetahs also train their cubs to hunt so that they may get food for themselves which will ensure their survival as well thus showing that both of these practices can impact on reproductive success.

The amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

To calculate the energy required to lift a 2.5 kg object through a vertical distance, we need to consider the gravitational potential energy formula:

Potential energy (PE) = mass (m) × gravity (g) × height (h)

Where:

m = 2.5 kg (mass of the object)

g = 9.8 m/s² (acceleration due to gravity on Earth)

h = ? (height)

First, let's find the height (h) by rearranging the formula:

h = PE / (m × g)

Now, let's calculate the potential energy (PE) needed to lift the object. We are given that the power of the bulb is 0.20 kW, and we want to find the energy required for one minute. To convert kilowatts (kW) to joules (J), we multiply by the conversion factor of 3,600 (60 seconds × 60 minutes):

Energy (E) = power (P) × time (t)

E = 0.20 kW × 1 min × 3,600 J/kW

Now, we can substitute the values into the equation to find the height:

h = (0.20 kW × 1 min × 3,600 J/kW) / (2.5 kg × 9.8 m/s²)

Calculating the expression on the right side:

h ≈ 0.20 × 1 × 3,600 / (2.5 × 9.8) ≈ 29.03 meters (rounded to two decimal places)

Therefore, the amount of energy needed to power a 0.20 kW bulb for one minute would be just sufficient to lift a 2.5 kg object through a vertical distance of approximately 29.03 meters.

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Answer:

Explanation:

Let R5 be the resistance between R3 and R4

R3 and R4 are in series

R5=R3+R4 = 9+8=17

R1, R2 and R5 are in parallel

Resistance R between A and B is :

1/R= 1/R1+1/R2+1/R5=1/7+1/10+1/17=170+119+70/1190=359/1190

1/R=359/1190

R=1190/359=3.314 Ω

Rounding to nearest hundredth we get 3.31Ω

The nucleons have less mass, because matter is converted into binding energy. Option D is correct.

During the process of combining a neutron and a proton to form a nucleus, a small amount of mass is converted into binding energy. This is due to the strong nuclear force that holds the nucleus together. The mass of the nucleus is slightly less than the sum of the masses of the individual nucleons, and the difference in mass is referred to as the mass defect.

This mass defect is related to the binding energy of the nucleus through Einstein's famous equation E=mc², where E is energy, m is mass, and c is the speed of light. The mass defect represents the amount of mass that is converted into binding energy to hold the nucleus together. Option D is correct.

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The normal force on the block is approximately 20.05 N.

Force describes the interaction between objects or between an object and its environment. It causes a change in the motion of the body it acts upon.

The normal force, which counteracts the force of gravity dragging the block downward, is the force generated by the slope acting perpendicular to its surface. As the incline has no friction, there is no force acting parallel to its surface.

To ascertain the parts of the force of gravity pulling on the block, we can apply trigonometry. There are two parts to the force of gravity: one that is parallel to the incline's surface and the other that is perpendicular to it. The weight of the block, mg, where m is its mass and g is its gravitational acceleration, is equal to the component of gravity perpendicular to the inclination. mg sin θ, where is the angle of the incline, is the component of gravity that is parallel to the incline.

To calculate the acceleration of the block moving down the incline, we can apply Newton's second law, F = ma. The component of gravity parallel to the inclination, or mg sin θ, represents the net force exerted on the block. As a result, we have:

\(mg sin(theta) = ma\)

To solve for a, we obtain:

\(a = g sin(theta)\)

Substituting the given values, we get:

\(a = 9.8 m/s^2 * sin(27°)\) ≈ \(4.69 m/s^2\)

Now that we know the normal force acting on the block, we can use Newton's second law once more. The component of gravity's force perpendicular to the incline is equal in magnitude to the normal force and moves in the opposite direction. As a result, we have:

\(mg cos(theta) = N\)

Inputting the values provided yields:

\(N = 2.3 kg * 9.8 m/s^2 * cos(27°)\) ≈ \(20.05 N\)

Therefore, the normal force on the block is approximately 20.05 N.

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Answer:

Let the plane be flying east (to the right) and the wind north

Vx = 650 km/hr i                 speed to East

Vy = 75 km/hr j                    speed to North

V = (650^2 + 75^2)^1/2 = 654 km/hr       net speed

tan θ = Vy / Vx = 75 / 650 = .115        θ = 6.58 deg N of E

Answer:

for reasoning you could put -> the line is at the top at the left handed sided of the chart (also the beginning) slopes down towards the very bottom right handed side of the chart, symbolising less force as distance goes.

Answer:

Explanation:

It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.

Answer:

it is D and B because they are both indicators

A 100kg man jumping off a 10m high building in 10 seconds has a power of 1000 Watts.

When the man jumps off the building, he initially possesses potential energy due to his position above the ground. As he falls, this potential energy is converted into kinetic energy, which is the energy of motion. The work done by the man is equal to the change in potential energy.

The potential energy (PE) can be calculated using the formula PE = mgh, where m represents the mass, g represents the acceleration due to gravity, and h represents the height. In this case, the mass is given as 100kg, the acceleration due to gravity is 10 m/s², and the height is 10m.

Substituting these values into the formula, we get PE = 100kg * 10m/s² * 10m = 10,000 Joules. This means that the work done by the man while jumping off the building is 10,000 Joules.

Power is defined as the rate at which work is done. In this scenario, we divide the work (10,000 Joules) by the time taken (10 seconds) to obtain the power. Therefore, Power = Work/Time = 10,000 J / 10 s = 1000 Watts.

Hence, the power of the 100kg man who jumps off the 10m high building in 10 seconds is calculated to be 1000 Watts. Power represents the rate at which energy is transferred or work is done, indicating how quickly the man transformed potential energy into kinetic energy during the jump.

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Answer:

I believe the answer is specific gravity

Explanation:Hope this helps :)

Answer:

so how much heat is there at 0 C? That's zero. But for every degree above that you have 4.184 J. You take it from there. Remember q = mc*delta T.

You’re in luck!

Answer:

It would rise for about 19.2 meters or a little more than half a meter before falling back to the ground, though an observer on the Moon would be able to see it rise for nearly 46 meters. Why? A new measure of gravity called "g" can help us figure this out. Let's first start with a quick review of Newton's second law of motion: force equals mass times acceleration, or "F=ma." When you throw an object up vertically on Earth, the acceleration due to gravity is 9.8m/s/s--or as we know from earlier gradeschool physics, 32ft/s squared at sea level on Earth. If there were no air resistance and the ball weighed 10 grams, then it would take .45 seconds to reach the top of its arc, where it will be moving at 10m/s (or 22.7 mph, which is about how fast you'd have to throw the ball straight up to get it back down in .45 seconds). If there were no gravity, however, the ball would just keep going faster and faster as it moved away from Earth's surface. As an object reaches lower orbital speeds farther away from Earth, docking takes relatively longer--which brings us back to our question about the Moon. The gravitational force between any two objects drops off according to a very simple formula: one over the distance squared. So even though g on Earth is 9.8 m/s/s near sea level, at the height of one meter above the ground, g is approximately 9.81m/s/s--just a tiny bit less than sea level value due to the very small distance between an object and its center of mass (the Earth). On the Moon, however, gravity drops off quite rapidly because there's no atmosphere to slow down objects in low orbit around it (so you'd have to throw something really fast to keep it orbiting around), and it has almost no mass compared with Earth.

**ANSWER BY AN AI**

The planet that has ⅒ of the earth's gravity is the moon.

Gravity is the force exerted by any object with mass on any other object with mass.

Gravity is the force on Earth's surface, of the attraction by the Earth's masses, and the centrifugal pseudo-force caused by the Earth's rotation, resulting from gravitation.

The gravity on the planet Earth is 1 with a acceleration due to gravity of 9.8m/s². One-tenth of this is 0.1 (0.98m/s²).

The planet with the above gravity is the moon with a gravity of 0.166.

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Answer:

a) 4.0816s

b) -9.8 ms^-1

c) 81.63265m

Answer:

the liquid state

Explanation:

because the particles can move about freely, a liquid has no definite shape and takes a shape dictated by its container.

The mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.

When anything is moving, its velocity tells us how rapidly that something's location is changing from a certain vantage point and as measured by a particular unit of time.

If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.

Given:

The mass of the cannonball, m = 5 kg,

The velocity of the cannon, v = 550 m/s,

The recoil speed of the cannon, vₐ = 1.3 m / s,

Then by using momentum conservation calculate the mass of the cannon,

\(m \times v = m_{a} \times v_{a}\)

Here mₐ is the mass of the cannon,

Substitute the values,

5 × 550 = mₐ × 1.3

mₐ = 2115.4 kg

Therefore, the mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.

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The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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Answer:

b.

Explanation:

The resulting wave pattern when the centers of the two pulses meet is undergo constructive interference.

Waves are pulses of energy that propagate through space periodically. When two waves overlap in the same region of space, interference occurs, which results in another wave with different intensity. These variations in the intensity of the resulting wave are called interference fringes.

The two pulses propagate with the same phase and in opposite directions, when they meet, they suffer constructive interference, which will cause the sum of the amplitudes. After interference, each wave goes its way as if nothing happened.

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The direction of the prevailing winds from the mountain range is,

The left side of the mountain is the windward side,

The right side of the mountain is the leeward side,

The lake effect can be cold air moving over a body.

The process which explains the island's windward side and leeward side through the movement of winds through hills and mountains is known as Orographic effect.

Windward side:

The windward side of the mountain is the side which is facing the sea. This side acts as a natural barrier to produce the warm and moist air masses. So that they condensate receives a lot of precipitation. Because of that the windward side have much more vegetation.

Leeward side:

The leeward side is the side of the mountain that is on the opposite side of the sea. The leeward side is receiving very little precipitation, and usually it only gets downward and the wind was very dry. So that this side of the mountain looks much drier and having much less vegetation.

Lake effect side:

The lake effect occurs when you have cold air moving over a warm body of water. The lake effect will have a temperature difference between the air and body of water at around 850 milli-bars (about a mile above the surface) is more than 10 degrees Celsius.

So, The direction of the prevailing winds from the mountain range is,

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Answer:

25.5 pounds per square inch are equivalent to 1.735 atmospheres.

Explanation:

An atmosphere equals 14.695 pounds per square inch. We find the equivalent of given pressure in atmospheres by means of simple rule of three:

\(x = 25.5\,\frac{lb}{in^{2}} \times \frac{1\,atm}{14.695\,\frac{lb}{in^{2}} }\)

\(x = 1.735\,atm\)

25.5 pounds per square inch are equivalent to 1.735 atmospheres.

Answer:

\(12\:\mathrm{N}\)

Explanation:

Force is given by the equation \(F=ma\).

Plugging in given values, we have:

\(F=ma=2.6\cdot 4.5=11.7=\fbox{$12\:\mathrm{N}$}\) (two significant figures).

electricity

Explanation:

the position (2,o

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

b

Explanation:

when a ball falls from the sky, it falls down fast due to no friction.