Answer:
The function rule for g(x) can be obtained by performing the transformations described on the function f(x) = -6x.
First, we need to stretch the graph of f(x) vertically by a factor of 7. This means that the y-values of the points on the graph of g(x) will be 7 times the y-values of the points on the graph of f(x). We can achieve this by multiplying the y-values of the function f(x) by 7.
Next, we need to reflect the graph of g(x) in the x-axis. This means that the y-values of the points on the graph of g(x) will be the negative of the y-values of the points on the graph of f(x). We can achieve this by multiplying the y-values of the function f(x) by -1.
Applying these transformations to the function f(x) = -6x, we get the function rule for g(x) as follows:
g(x) = (-1) * (7) * (-6x)
= (-1) * (-42x)
= 42x
Therefore, the function rule for g(x) is g(x) = 42x.
The pendulum of an antique clock has been damaged and needs to be
replaced. If the original pendulum completed one swing every 1.5 seconds,
how long should the new pendulum be? Use the formula:
T= 2.
1980
OA. 351 centimeters
OB. 0.25 centimeters
O C. 55.9 centimeters
O D. 234.8 centimeters
If the original pendulum completed one swing every 1.5 seconds. How long should the new pendulum be is: C. 55.9 centimeters.
How long should the new pendulum be
Using this formula
T=2π√I/g
Where:
T=1.5 seconds
l =length of pendulum
g= acceleration of gravity=9.8m/s²
Let plug in the formula
1.5 seconds=2π√I/9.8
l/9.8=0.05699
l=0.05699×9.8
l=0.5585
l=55.9 centimeters (Approximately)
Therefore How long should the new pendulum be is: C. 55.9 centimeters.
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fill in the blank 3(2+7a)=6+
Answer:
\(3(2+7a)=6+\)
\(6 + 21a = 6\)
\(21a + 6 = 6 + 21a\)
answer is 21a
A line that models the data is given by the equation y= 1.62x 18 , where y represents the wait time, and x represents the number of staff available. the slope of the line is -1.62. what does this mean in this situation?
The slope of the line represents the rate of change between the independent variable (number of available staff) and the dependent variable (number of available staff) (wait time).
The slope of the line in this case is -1.62, which means that for every one unit increase in the number of staff available, the wait time decreases by 1.62 units.
In this case, a negative slope indicates that as the number of staff available increases, so does the wait time, indicating a positive relationship between the two variables. In other words, as the number of employees available increases, the wait time decreases.
It is important to remember that the equation models this relationship, and that actual wait times in the real world may not always follow this exact relationship due to other factors that influence wait times.
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Find the area of the circle .Round your answers the nearest whole number if necessary.use 3.14 or 22/7
Please help
Find the area of a triangle with a =17, b =13, and c =19.
solve the following system of equations using the substitution method. –6x 2y = 8 y = 3x 4 question 9 options: a) no solution b) (0, 4) c) infinitely many solutions d) (8, 8)
The correct answer is option c) infinitely many solutions..
To solve the system of equations using the substitution method, we'll substitute the value of y from the second equation into the first equation and solve for x.
Given:
-6x + 2y = 8 ---(1)
y = 3x + 4 ---(2)
Substitute equation (2) into equation (1):
-6x + 2(3x + 4) = 8
Simplify:
-6x + 6x + 8 = 8
8 = 8
We obtained a true statement (8 = 8), which means the two equations are equivalent. This solution shows that the system has infinitely many solutions.
Therefore, the correct answer is option c) infinitely many solutions..
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Number 3 please I need it real quick
Answer
D
Step-by-step explanation:
Let C be a simple closed curve in R?, enclosing a region A. The integral SL. (+*+y) do dý, is equal to which of the following integrals over C? O $ (zyºdr – z* du) fe (" - dr dy + 3x dy de) *** O
The integral of (x^2 + y) dA over the region A enclosed by a simple closed curve C in R^2 is equal to the integral ∮C (zy dx - zx dy + 3x dy), where z = 0.
To calculate this, we can use Green's theorem, which states that the line integral of a vector field around a simple closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve.
In this case, the vector field F = (0, zy, -zx + 3x) and its curl is given by:
curl(F) = (∂(−zx + 3x)/∂y - ∂(zy)/∂z, ∂(0)/∂z - ∂(−zx + 3x)/∂x, ∂(zy)/∂x - ∂(0)/∂y)
= (-z, 3, y)
Applying Green's theorem, the line integral over C is equivalent to the double integral of the curl of F over the region A:
∮C (zy dx - zx dy + 3x dy) = ∬A (-z dA) = -∬A z dA
Therefore, the integral of (\(x^2\) + y) dA is equal to the integral ∮C (zy dx - zx dy + 3x dy), where z = 0.
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Which of the following is a root of the polynomial shown below?
f(x) = x2 + 2x2 - x-2
O A. 1
OB. 3
O c. O
O D. 2
Answer:
We conclude that option A is true as x = 1 is the root of the polynomial.
Step-by-step explanation:
Given the polynomial
\(f\left(x\right)\:=\:x^2\:+\:2x^2\:-\:x-2\)
Let us determine the root of the polynomial shown below.
\(\:0=\:x^2\:+\:2x^2\:-\:x-2\)
\(0=3x^2-x-2\)
switch sides
\(3x^2-x-2=0\)
as
\(3x^2-x-2=\left(3x+2\right)\left(x-1\right)\)
so the equation becomes
\(\left(3x+2\right)\left(x-1\right)=0\)
Using the zero factor principle
\(3x+2=0\quad \mathrm{or}\quad \:x-1=0\)
solving
\(3x+2=0\)
\(3x=-2\)
\(\frac{3x}{3}=\frac{-2}{3}\)
\(x=-\frac{2}{3}\)
and
\(x-1=0\)
\(x=1\)
The possible roots of the polynomial will be:
\(x=-\frac{2}{3},\:x=1\)
Therefore, from the mentioned options, we conclude that option A is true as x = 1 is the root of the polynomial.
in math, what is 7 -5 ?
Answer:
2
Step-by-step explanation:
You have 7, and you take away five, which leaves you with 2
here is a drawing:
l l l l l l l
x x x x x l l
Blake rolls a number cube ten times and it lands on the number 5 three times.
What should Blake do to have his experimental probability equal or come closer to the theoretical probability of the number cube landing on 5?
Answer:
Do more rolls of the number cube.
Step-by-step explanation:
Please help, I think it`s quick math, but I can`t figure it out. Thank you!!
Answer:
22
Step-by-step explanation:
116-28
88/4
(ab² + 13b - 4a) + (3ab² + a +7b)
Answer:
4ab² + 20b - 3a
Step-by-step explanation:
This question most likely asks us to simplify the expression, as factoring is not possible...
(ab² + 13b - 4a) + (3ab² + a + 7b),
ab² + 13b - 4a + 3ab² + a + 7b,
ab² + 3ab² + 13b + 7b - 4a + a,
Solution : 4ab² + 20b - 3a
3. Jeff Hittinger is a founder and brewmaster of the Octonia Stone Brew Works in Ruckersville, Virginia. He is contemplating the purchase of a particular type of malt (that is, roasted barley) to use in making certain types of beer. Specifically, he wants to know whether there is a simple linear regression relationship between the mashing temperature (the temperature of the water in which the malted barley is cooked to extract sugar) and the amount of maltose sugar extracted. After conducting 12 trials, he obtains the following data, expressed in terms of (temperature in Fahrenheit, maltose sugar content as a percentage of the total sugar content in the liquid):
(155,25),(160,28),(165,30),(170,31),(175,31),(180,35),(185,33),(190,38),(195,40),
(200,42),(205,43),(210,45)
(a) Calculate the least squares estimators of the slope, the y-intercept, and the variance based upon these data. (b) What is the coefficient of determination for these data? (c) Conduct an upper-sided model utility test for the slope parameter at the 5% significance level. Would you reject the null hypothesis at that significance level?
a) The least square estimator is 2.785221. b) The coefficient of determination is 0.9960514. c) We would reject the null hypothesis at the 5% significance level.
To calculate the least squares estimators of the slope, the y-intercept, and the variance, we can use the method of simple linear regression.
(a) First, let's calculate the least squares estimators:
Step 1: Calculate the mean of the temperature (x) and maltose sugar content (y):
X = (155 + 160 + 165 + 170 + 175 + 180 + 185 + 190 + 195 + 200 + 205 + 210) / 12 = 185
Y = (25 + 28 + 30 + 31 + 31 + 35 + 33 + 38 + 40 + 42 + 43 + 45) / 12 = 35.333
Step 2: Calculate the deviations from the means:
xi - X and yi - Y for each data point.
Deviation for each temperature (x):
155 - 185 = -30
160 - 185 = -25
165 - 185 = -20
170 - 185 = -15
175 - 185 = -10
180 - 185 = -5
185 - 185 = 0
190 - 185 = 5
195 - 185 = 10
200 - 185 = 15
205 - 185 = 20
210 - 185 = 25
Deviation for each maltose sugar content (y):
25 - 35.333 = -10.333
28 - 35.333 = -7.333
30 - 35.333 = -5.333
31 - 35.333 = -4.333
31 - 35.333 = -4.333
35 - 35.333 = -0.333
33 - 35.333 = -2.333
38 - 35.333 = 2.667
40 - 35.333 = 4.667
42 - 35.333 = 6.667
43 - 35.333 = 7.667
45 - 35.333 = 9.667
Step 3: Calculate the sum of the products of the deviations:
Σ(xi - X)(yi - Y)
(-30)(-10.333) + (-25)(-7.333) + (-20)(-5.333) + (-15)(-4.333) + (-10)(-4.333) + (-5)(-0.333) + (0)(-2.333) + (5)(2.667) + (10)(4.667) + (15)(6.667) + (20)(7.667) + (25)(9.667) = 1433
Step 4: Calculate the sum of the squared deviations:
Σ(xi - X)² and Σ(yi - Y)² for each data point.
Sum of squared deviations for temperature (x):
(-30)² + (-25)² + (-20)² + (-15)² + (-10)² + (-5)² + (0)² + (5)² + (10)² + (15)² + (20)² + (25)² = 15500
Sum of squared deviations for maltose sugar content (y):
(-10.333)² + (-7.333)² + (-5.333)² + (-4.333)² + (-4.333)² + (-0.333)² + (-2.333)² + (2.667)² + (4.667)² + (6.667)² + (7.667)² + (9.667)² = 704.667
Step 5: Calculate the least squares estimators:
Slope (b) = Σ(xi - X)(yi - Y) / Σ(xi - X)² = 1433 / 15500 ≈ 0.0923871
Y-intercept (a) = Y - b * X = 35.333 - 0.0923871 * 185 ≈ 26.282419
Variance (s²) = Σ(yi - y)² / (n - 2) = Σ(yi - a - b * xi)² / (n - 2)
Using the given data, we calculate the predicted maltose sugar content (ŷ) for each data point using the equation y = a + b * xi.
y₁ = 26.282419 + 0.0923871 * 155 ≈ 39.558387
y₂ = 26.282419 + 0.0923871 * 160 ≈ 40.491114
y₃ = 26.282419 + 0.0923871 * 165 ≈ 41.423841
y₄ = 26.282419 + 0.0923871 * 170 ≈ 42.356568
y₅ = 26.282419 + 0.0923871 * 175 ≈ 43.289295
y₆ = 26.282419 + 0.0923871 * 180 ≈ 44.222022
y₇ = 26.282419 + 0.0923871 * 185 ≈ 45.154749
y₈ = 26.282419 + 0.0923871 * 190 ≈ 46.087476
y₉ = 26.282419 + 0.0923871 * 195 ≈ 47.020203
y₁₀ = 26.282419 + 0.0923871 * 200 ≈ 47.95293
y₁₁ = 26.282419 + 0.0923871 * 205 ≈ 48.885657
y₁₂ = 26.282419 + 0.0923871 * 210 ≈ 49.818384
Now we can calculate the variance:
s² = [(-10.333 - 39.558387)² + (-7.333 - 40.491114)² + (-5.333 - 41.423841)² + (-4.333 - 42.356568)² + (-4.333 - 43.289295)² + (-0.333 - 44.222022)² + (-2.333 - 45.154749)² + (2.667 - 46.087476)² + (4.667 - 47.020203)² + (6.667 - 47.95293)² + (7.667 - 48.885657)² + (9.667 - 49.818384)²] / (12 - 2)
s² ≈ 2.785221
(b) The coefficient of determination (R²) is the proportion of the variance in the dependent variable (maltose sugar content) that can be explained by the independent variable (temperature). It is calculated as:
R² = 1 - (Σ(yi - y)² / Σ(yi - Y)²)
Using the calculated values, we can calculate R²:
R² = 1 - (2.785221 / 704.667) ≈ 0.9960514
(c) To conduct an upper-sided model utility test for the slope parameter at the 5% significance level, we need to test the null hypothesis that the slope (b) is equal to zero. The alternative hypothesis is that the slope is greater than zero.
The test statistic follows a t-distribution with n - 2 degrees of freedom. Since we have 12 data points, the degrees of freedom for this test are 12 - 2 = 10.
The upper-sided critical value for a t-distribution with 10 degrees of freedom at the 5% significance level is approximately 1.812.
To calculate the test statistic, we need the standard error of the slope (SEb):
SEb = sqrt(s² / Σ(xi - X)²) = sqrt(2.785221 / 15500) ≈ 0.013621
The test statistic (t) is given by:
t = (b - 0) / SEb = (0.0923871 - 0) / 0.013621 ≈ 6.778
Since the calculated test statistic (t = 6.778) is greater than the upper-sided critical value (1.812), we would reject the null hypothesis at the 5% significance level. This suggests that there is evidence to support a positive linear relationship between mashing temperature and maltose sugar content in this data set.
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what is the arcsin of 3
The value of the arcsin of 3 is 90 - 100.998i
From the question, we are to determine the inverse sine or arcsine of the given number
The given number is 3
All the values for the sine of angles are less than or equal to 1
That is,
Given an angle θ,
sinθ ≤ 1
From this, we can infer that the arcsine of 3 will be an imaginary number.
The arcsine of 3 is
sin⁻¹(3) = 90 - 100.998i
Hence, the value of the arcsin of 3 is 90 - 100.998i
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In Problems 1 through 16, transform the given differential equation or system into an equivalent system of first-order differential equations.x(3)−2x′′+x′=1+tet.
The equivalent system of first-order differential equations for the given problem is: 1. dv1/dt = v2 2. dv2/dt = v3 3. dv3/dt = 2v2 - v1 + 1 + t*e ^t
Given differential equation: x''' - 2x'' + x' = 1 + t*e ^t
Step 1: Define new variables.
Let's introduce new variables:
v1 = x'
v2 = v1'
v3 = v2'
Now we have:
v1 = x'
v2 = v1'
v3 = v2'
Step 2: Rewrite the given equation using new variables.
Substitute the new variables into the given differential equation:
v3 - 2v2 + v1 = 1 + t*e ^t
Step 3: Write the equivalent system of first-order differential equations.
Now we have the following equivalent system of first-order differential equations:
dv1/dt = v2
dv2/dt = v3
dv3/dt = 2v2 - v1 + 1 + t*e ^t
So, the equivalent system of first-order differential equations for the given problem is:
1. dv1/dt = v2
2. dv2/dt = v3
3. dv3/dt = 2v2 - v1 + 1 + t*e ^t
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Jessica purchased a prepaid phone card for $25. Long distance calls cost 19 cents a minute using this card. Jessica used her card only once to make a long
distance call. If the remaining credit on her card is $16.26, how many minutes did her call last?
Answer: 27.27 seconds?
Step-by-step explanation:
25 - 16.26 = 8.74
19/8.74 = 2.2 (Rounded up)
60/2.2 = 27.27
Agnes pays state income tax equal to 3.75% of her federal taxable income. she pays federal income tax equal to 28.4% of her federal taxable income. this year, she paid $15,449.60 in federal income tax. how much did agnes pay in state income tax? a. $573.36 b. $4,387.69 c. $1,170.04 d. $2,040.00 please select the best answer from the choices provided a b c d
Based on the information the amount that Agnes paid as state income tax is $2,040.
What is the federal income?Federal Income Tax is the tax system in the United States, levied and governed by Internal Revenue Services (IRS) which helps determine the tax that is charged on the income earned by individuals, corporates, and various other legal entities.
The first step is to calculate Agnes' federal taxable income.
Federal taxable income=$15449.60/0.284
Federal taxable income= $54,400
The second step is to calculate Agnes' state income tax.
State income tax=0.0375 ×$54,400
State income tax=$2,040
Hence, the amount that Agnes paid as state income tax is $2,040.
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Answer:
its d
Step-by-step explanation:
In order for a candy company to claim that a bridge mix is mostly chocolate stars, a proportion of at least 0.8 of the packages must contain 3 ounces or more of chocolate stars. Quality control tests a random sample of 50 packages to determine if the proportion is less than 0.8 at a significance level of 0.05.
4.014612
2.639621
3.450417
3.358356
2.84696
2.780427
3.300524
3.553771
3.260947
3.840587
2.860518
3.006942
The Z-value is Z=-2.121 < Zcritical and the p-value will be equal to 0.0169 when the percentage of at least 0.8 of the packages should include 3 ounces.
Given that percentage of at least 0.8 of the packages must include 3 ounces or more of chocolate stars for a candy producer to assert that a bridge mix is predominantly chocolate stars.
Since a random sample of 50 packages are tested by quality control to see if the proportion is less than 0.8 at a significance level of 0.05.
We have to calculate p, the z-score, and the p-value, using Sheet 6 of the Excel document.
We know that,
N=50
n=34
Proportion pbar = n/N=34/50=0.68
H₀: p≥0.8
H₁: p<0.8
Z=pbar-p/√(p(1-p)/N
Z=0.68-0.8/√0.8(1-0.8)/50
Z=-2.121
α=0.05
Reject H₀ if Z<-Zcritical
Z critical for one -tailed (Left) = -1.6449
Z=-2.121<Zcritical
Reject H₀
P(Z < -2.121) = 0.0169
p-value = 0.0169
Since the p-value is less than the significance level of 0.05 the null hypothesis is rejected.
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The variance of a distribution of means of samples of more than one is
A) smaller than the original population variance.
B) the same as the original population variance.
C) greater than the original population variance.
D) unrelated to the original population variance.
The variance of a distribution of means of samples of more than one is A) smaller than the original population variance.
When considering the distribution of means of samples, the central limit theorem states that as the sample size increases, the sampling distribution approaches a normal distribution regardless of the shape of the population distribution. Additionally, the standard error of the mean decreases as the sample size increases.
The variance of a population is denoted by σ^2.
The variance of the distribution of sample means, also known as the sampling distribution, is denoted by σ^2/N, where N is the sample size.
As the sample size (N) increases, the denominator increases, leading to a smaller value for the variance of the distribution of sample means (σ^2/N). Thus, the variance of the distribution of means of samples is smaller than the original population variance.
The variance of a distribution of means of samples of more than one is smaller than the original population variance. This is due to the central limit theorem and the decrease in standard error as the sample size increases.
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what percent of a group do i have to randomly sample in order to get a rough estimate for the entire group
Which ordered pairs make both inequalities true y <- X 1 Y X?
The ordered pair (-2, 2) satisfies both inequalities y < -x + 1 and y > x.
The correct option is A: (-2, 2).
To determine which ordered pairs satisfy both inequalities y < -x + 1 and y > x, we need to check each pair's coordinates in both inequalities.
Let's test each ordered pair:
A: (-2, 2)
For y < -x + 1: 2 < -(-2) + 1 → 2 < 3 (True)
For y > x: 2 > -2 → 2 > -2 (True)
B: (1, 1)
For y < -x + 1: 1 < -(1) + 1 → 1 < 0 (False)
For y > x: 1 > 1 → 1 > 1 (False)
C: (0, 0)
For y < -x + 1: 0 < -(0) + 1 → 0 < 1 (True)
For y > x: 0 > 0 → 0 > 0 (False)
D: (-1, -1)
For y < -x + 1: -1 < -(-1) + 1 → -1 < 2 (True)
For y > x: -1 > -1 → -1 > -1 (False)
From the above calculations, we can see that only the ordered pair (-2, 2) satisfies both inequalities y < -x + 1 and y > x. Therefore, the correct answer is option A: (-2, 2).
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The complete question:
Which ordered pairs make both inequalities y < -x + 1 and y > x true?
A: (2, 2)
B: (1, 1)
C: (0,0)
D: (-1, -1)
Natural gas is to be produced from a geologic formation confined on the top and bottom by impervious shale layers. Let φ=0.3, b=100 m,αp=4×10−9 Pa−1 and; rho=0.1hp Where rho gas density (kg/m3),hp pressure head expressed as meters of water (m). Calculate the gas mass produced if the pressure head is reduced from 100 m to 30 m over an area of 10,000 m2.
Answer:
Step-by-step explanation:
To calculate the gas mass produced, we can use Darcy's Law, which relates the flow of gas through a porous medium to the pressure gradient. The formula for Darcy's Law is:
Q = -k * A * (dP/dx)
Where:
Q is the flow rate (m^3/s)
k is the permeability of the medium (m^2)
A is the cross-sectional area (m^2)
dP/dx is the pressure gradient (Pa/m)
Given:
φ = 0.3
b = 100 m
αp = 4 × 10^(-9) Pa^(-1)
ρ = 0.1 hp (gas density)
Pressure head (initial) = 100 m
Pressure head (final) = 30 m
Area (A) = 10,000 m^2
First, we need to calculate the permeability (k) using the porosity (φ) and the compressibility (αp) as follows:
k = φ² * αp
k = 0.3² * (4 × 10^(-9) Pa^(-1))
k = 9 × 10^(-11) m^2
Next, we can calculate the pressure gradient (dP/dx) by subtracting the final pressure head from the initial pressure head and dividing it by the distance (b):
dP/dx = (Pressure head (final) - Pressure head (initial)) / b
dP/dx = (30 m - 100 m) / 100 m
dP/dx = -0.7 Pa/m
Now, we can calculate the flow rate (Q) using Darcy's Law:
Q = -k * A * (dP/dx)
Q = -9 × 10^(-11) m^2 * 10,000 m^2 * (-0.7 Pa/m)
Q = 6.3 × 10^(-4) m^3/s
Finally, we can calculate the gas mass (m) using the flow rate (Q) and the gas density (ρ):
m = Q * ρ
m = 6.3 × 10^(-4) m^3/s * 0.1 kg/m^3
m = 6.3 × 10^(-5) kg/s
Therefore, the gas mass produced when the pressure head is reduced from 100 m to 30 m over an area of 10,000 m^2 is approximately 6.3 × 10^(-5) kg/s.
To calculate the gas mass produced, Using Darcy's Law and the given values, we can determine the gas mass produced when the pressure head is reduced from 100 m to 30 m over an area of 10,000 m2.
The gas mass produced can be calculated by first determining the permeability (k) using the given values of porosity (φ), compressibility (αp), gas density (ρ), and thickness (b). With the obtained value of k, we can then use Darcy's Law to calculate the gas flow rate. However, since the time period is not specified, we cannot directly calculate the gas mass produced. The gas flow rate obtained from Darcy's Law represents the volume of gas flowing per unit time. To calculate the gas mass produced, we need to integrate the flow rate over time. Without the time component, we cannot determine the exact gas mass produced. Therefore, the calculation of the gas mass produced requires information about the time period or additional data.
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When Iris subtracted-16-(-16), she got a difference of 32. Is her answer
correct? If not, what mistake did she make? Explain
Answer:
Hope this helps
Step-by-step explanation:
-16 - (-16) cab also be written as -16 + 16 which is 0. Iris was not correct because she didn't realize that the first 16 was negative.
simplify the monomials
Answer:
\((4a)^{-3}*^{-4}\)
\(x^m*x^n=x^{m+n}\)
\((4a)^{-3}*a^{-4}\)
\((-4)^{-3}\: a^{-3}*a^{-4}\)
\(4^{-3}\:a^{-3-4}\)
\(\cfrac{1}{4^3} \:a^{-7}\)
\(\boxed{\frac{1}{64a^{7}} }\)
~
\((3xy)^2*(-4x^3y^2)^3\)
\(9x^2y^2*(64x^9y^6)\)
\(\boxed{-576x^{11}y^8}\)
~
\((4a^{-1}b^5c^{-3})^3\)
\((4)^3(a^{-1})^3(b^5)^3(c^{-3})^3\)
\((4*4*4)\:a^{-1*3}\:b^{5*3}\:c^{-3*3}\)
\(64\:a^{-3}b^{15}c^{-9}\)
\(\boxed{\frac{64b^{15}}{a^3c^9}}\)
which equation is closest to the line of best fit in the graph below ?
Answer: B
Step-by-step explanation:
3.4 Puzzle Time What Did The Pelican Say When It Finished Shopping? Write the letter of each answer in the box containing the exercise number. Answers Find the slope of the line that passes through the given points. 1. (-10, -12), (-8, -8), (-6. - 4), (-4, 0) 1. m = M. m = 6, 6 = -4 2. (-4, 2), (0, 1), (4,0), (8, -1) 3. (-7, -7), (0, -8), (7, -9), (14,-10) U. m3 4. (-2, 2), (0, 3), (2, 4), (4, 5) N. m = -4, b = -1 5. (2. -11), (4, -25), (6,-39), (8, -53) P. m = -4, b = 6 I m = -7 6. (-11, -38), (-5, -14), (1, 10), (7, 34) L. m = 16=2 Find the slope and the y-intercept of the graph of the linear equation. 7. y = - 4x + 6 . m = 2 L. m = 4 8. y = - T. m = 0,6 = A 9. 4r + y = -1 B. m = 8,5 = 50 10. y = 6.r - 4 Y m = - 11. -r - 4y + 8 = 0 = -1 T. ms, 12. 2.r - 12y + 10 = 0 13. The function C(x) = 8.0 + 50 represents the cost C (in dollars) of towing a vehicle, where x is the number of miles the vehicle is towed. Identify the slope and y-intercept 6 11 3 13 10 9 1 8 7 2. 12 5 Ideas Learning, LLC
The slope is the rate of change of the y-value, which is the coefficient of
x when the coefficient of y is 1.
Response:
m = 2m = \(-\frac{1}{4}\)m = \(-\frac{1}{7}\)m = \(\frac{1}{2}\)m = -7m = 4m = -4, b = 6m = 0, b = \(-\frac{1}{4}\)m = -4, b = -1m = 6, b = -4m = \(-\frac{1}{4}\), b = 2m = \(\frac{1}{6}\), b = \(\frac{5}{6}\)m = 8, b = 50What the Pelican said was; PUT IT ON MY BILLWhich methods are used to find the slope and intercept of a line?The slopes are;
1. The common difference between the y-values is constant, therefore,
the points are points on a straight line, which gives;
\(Slope, \ m = \dfrac{-8 - (-12)}{-8 - (-10)} = \dfrac{4}{2} = \underline{2}\)
2. The slope of the line is found as follows;
\(Slope, \ m = \dfrac{1 - 2}{0 - (-4)} = \underline{-\dfrac{1}{4}}\)
\(3. \hspace{0.15 cm} Slope, \ m = \dfrac{-8 - (-7)}{0 - (-7)} = \underline{-\dfrac{1}{7}}\)
\(4. \hspace{0.15 cm} Slope, \ m = \dfrac{3 - 2}{0 - (-2)} = \underline{ \dfrac{1}{2}}\)
\(5. \hspace{0.15 cm} Slope, \ m = \dfrac{-25 - (-11)}{4 - 2} = -\dfrac{14}{2} = \underline{-7}\)
\(6. \hspace{0.15 cm} Slope, \ m = \dfrac{-14 - (-38)}{-5 - (-11)} = \dfrac{24}{6} = \underline{4}\)
The value of the slope, m, and the y-intercept, b, are the coefficient of x and
the constant when the coefficient of y is 1.
Which gives;
7. The slope, m = -4, the y-intercept, b = 6
8. The slope, m = 0, the y-intercept, b = \(\underline{-\frac{1}{4}}\)
9. The slope, m = -4, the y-intercept, b = -1
10. The slope, m = 6, the y-intercept b = -4
11. The slope, m = \(\underline{-\frac{1}{4}}\), the y-intercept is b = 2
12. The slope, m = \(\underline{\frac{1}{6}}\), the y-intercept b = \(\underline{\frac{5}{6}}\)
13. The slope, m = 8, the y-intercept, b = 50
In the possible letter code from a similar question, we have;
\(\begin{array}{ccccccccccccccccc}7&2&12&&5&8&&1&9&&10&3&&13&4&11&6\\P&U&T&&I&T&&O&N&&M&Y&&B&I&L&L\end{array}\right]\)
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Given x = sin(t), y = csc(t), 0
The given parametric equations define a relationship between the variable t and the coordinates (x, y) in a two-dimensional plane. The equation x = sin(t) represents the x-coordinate of a point on the graph, while y = csc(t) represents the y-coordinate. The restriction 0 < t < pi ensures that the values of t lie within a specific range.
In more detail, the equation x = sin(t) indicates that the x-coordinate of a point is determined by the sine function of the corresponding value of t. The sine function oscillates between -1 and 1 as t varies, resulting in a periodic pattern for the x-values.
On the other hand, the equation y = csc(t) represents the reciprocal of the sine function, known as the cosecant function. The cosecant function is defined as the inverse of the sine function, so the y-coordinate is the reciprocal of the corresponding sine value. Since the sine function has vertical asymptotes at t = 0 and t = pi, the cosecant function has vertical asymptotes at those same points, restricting the range of y.
Together, these parametric equations describe a curve in the xy-plane that is determined by the values of t. The specific shape of the curve depends on the range of t and the behavior of the sine and cosecant functions.
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Camden put $25,000 in an investment 10 years ago. The investment increased in value by 5.6% per year. What is the value of the investment now?
Answer:
$26,000
Step-by-step explanation:
5.6% of $25,000
=$1400
$1400+$25,000= $26,000
Miguel went for a drive in his new car. He drove at a speed of 53 miles per hour for 84.8 miles
Time taken by Miguel car to drive is, 1.6 hour.
What is Division method?Division method is used to distributing a group of things into equal parts. Division is just opposite of multiplications. For example, dividing 20 by 2 means splitting 20 into 2 equal groups of 10.
We have to given that;
Miguel went for a drive in his new car. He drove at a speed of 53 miles per hour for 84.8 miles.
We know that;
⇒ Speed = Distance / Time
⇒ Time = Distance / Speed
Here, Speed = 53 miles per hour
Distance = 84.8 miles
Hence, We get;
⇒ Time = 84.8 / 53
⇒ Time = 1.6 hour
Thus, Time taken by Miguel car to drive is, 1.6 hour.
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