find the equation of the line passing through the point (2, -4) that is parallel to the line y=3x+2​

Answers

Answer 1

Answer (assuming it can be put in point-slope format):

\(y + 4 = 3(x-2)\)

Step-by-step explanation:

You can write an equation of a line when knowing its slope and a line it passes through using point slope formula, \(y-y_1 = m (x-x_1)\).

1) First, find the slope of the equation. We know it has to be parallel to y = 3x + 2. Lines that are parallel have the same slope, thus the slope of y = 3x + 2 is the slope of the answer as well. y = 3x + 2 is in slope-intercept format, or \(y = mx + b\). The coefficient of the x term, or \(m\), represents the slope - so, the slope must be 3.

2) Now, use point-slope formula,\(y-y_1 = m (x-x_1)\),  to write the equation. Substitute \(m\), \(x_1\), and \(y_1\) for real values.

The \(m\) represents the slope, so substitute 3 for \(m\). The \(x_1\) and \(y_1\) represent the x and y values of a point the line crosses through. The line crosses through (2, -4), so substitute 2 for \(x_1\) and -4 for \(y_1\). This gives the following answer:

\(y - (-4) = 3 (x-(2))\\y + 4 = 3(x-2)\)


Related Questions

The value of the perimeter of the triangle in feet is equal to the value of the area of the triangle in square feet use a graph to find X

The value of the perimeter of the triangle in feet is equal to the value of the area of the triangle

Answers

Answer:

10

Step-by-step explanation:

We can set up an equation using the information given to us:

x+x-2+6=\(\frac{1}{2}*(x-2)*6\)

Simplify both sides

2x+4=3(x-2)

Distribute the 3 on the right side

2x+4=3(x)-3(2)

2x+4=3x-6

Move like terms to one side

x=10

\(\stackrel{\textit{value of the perimeter in feet}}{(x)+(x-2)+(6)}~~ = ~~\stackrel{\textit{value of the area in }ft^2}{\cfrac{1}{2}\underset{base}{(x-2)}\underset{height}{6}} \\\\\\ 2x+4=3x-6\implies 4=x-6\implies 10=x\)

The range of f(x) = [xl is y 2 0. If a < 0 for g(x) = a[x], what is the range of function g?
A ysa
B. y < 0


C. y20

D. ys 0

Answers

Answer:5

Step-by-step explanation:

The range of the function g(x) = a[x], where a < 0, is y ≤ 0.

What is the greatest integer function?

The function f(x) = [x], where [x] represents the greatest integer less than or equal to x, has a range of y ≤ 0. This means that the output of the function f(x) can be any number less than or equal to zero, including negative integers, zero, and non-negative fractions.

Consider the function g(x) = a[x], where a is a negative constant. When we multiply the input x by a the output of the function is also multiplied by a. Since a is negative, the sign of the output is flipped. Moreover, the output is an integer, as [x] is an integer for all x.

Here, the range of the function g(x) = a[x] is y ≤ 0.

This means that the output of the function g(x) can be any negative integer, zero, or any non-positive fraction, as these are the numbers that are less than or equal to zero.

Thus, the range of the function g(x) = a[x], where a < 0, is y ≤ 0.

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Select the correct answer.
Function bis nonlinear, and b(9) = 4. Which equation could represent function b?

Answers

The nonlinear- function which represents b(9)=4 is given by b(x)=72/x - 4 .

In mathematics and physics, a nonlinear system is one in which the change in the output is not proportional to the change in the input. Engineers, biologists, physicists, mathematicians, and many other scientists are interested in nonlinear problems since the majority of systems are inherently nonlinear.

Nonlinear function graphs don't resemble lines at all. It contains the formula f(x) = ax + b. Its equation can take any form, with the exception of f(x) = ax + b. The slope of the curve is the same between any two points. The point pairs on the graph do not all have equal slopes.

Of all the given options: the only equations which imply that b(9)=4  are :

i) b(x)=72/x - 4 and  (iv) b(x)=4

Of this two options only the first option is non-linear.

Hence the required option is  b(x)=72/x - 4 .

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Disclaimer:

The missing options are:

i)   b(x) = 72/x - 4

ii) b(x) = √x + 7

iii)b(x)  = 2x+1

iv) b(x) = 4

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If you can paint 75 square feet every 45 minutes how long will it take to paint a 8 by 5

Answers

Answer:

24 minutes

Step-by-step explanation:

The Dimensions of the wall are given as:

8ft × 5ft = 40ft² or 40 square feet

Step-by-step explanation:

Answer:

24 minutes

Step-by-step explanation:

8 * 5 = 40 ft²

---------------------------

Method I: Use a proportion

x/40 = 45/75

multiply both sides by 40

x = 45/75 * 40

x = 24

24 minutes

---------------------------

Method II: Use the rate

45/75 = 0.6min/ft²

40 * 0.6 = 24

24 minutes

Ayuda es calcular el volumen de los cuerpos geométricos de la imagen porfffaaaaaaa

Ayuda es calcular el volumen de los cuerpos geomtricos de la imagen porfffaaaaaaa

Answers

The volumes of the solids are listed below:

Case 4: V = 570 cm³

Case 5: V = 222 cm³

Case 6: V = 378 cm²

Case 7: V = 168 cm³

Case 8: V = 514.8 cm³

Case 9: V = 1.125π m³

Case 10: V = 13.333π cm³

Case 11: V = 1152π cm³

Case 12: V = 10.667π cm³

How to determine the volumes of the solids

In this problem we need to determine the volumes of nine solids, the formulas need to determine each volume are listed below:

Prism

V = A · h

Pyramid

V = A · h / 3

Hemisphere

V = (2π / 3) · r³

An eighth of the sphere

V = (π / 6) · r³

Surface areas

Polygon

A = (n · l · a) / 2

Circular sector

A = (α / 180) · π · r²

Triangle

A = w · s / 2

Rectangle

A = w · s

Where:

A - Base areah - Height of the prism.r - Radiusα - Central angle, in degrees.n - Number of sides of the regular polygon.l - Side lengtha - Apothemaw - Widths - Height of the triangle / rectangle.

Case 4

V = 0.5 · (5 cm) · (12 cm) · (19 cm)

V = 570 cm³

Case 5

V = [0.5 · (3 cm) · (7 cm) + (15 cm) · (3 cm)] · (4 cm)

V = 222 cm³

Case 6

V = 0.5 · (7 cm) · (9 cm) · (12 cm)

V = 378 cm²

Case 7

V = [(5 cm) · (4 cm) + (12 cm) · (3 cm)] · (3 cm)

V = 168 cm³

Case 8

V = (1 / 3) · [0.5 · 6 · (6 cm) · (5.2 cm)] · √[(17.3 cm)² - (5.2 cm)²]

V = 514.8 cm³

Case 9

V = π · [(1.25 m)² - (1 m)²] · (2 m)

V = 1.125π m³

Case 10

V = (60 / 360) · π · (12 cm) · (20 cm) / 3

V = 13.333π cm³

Case 11

V = (2π / 3) · (12 cm)³

V = 1152π cm³

Case 12

V = (π / 6) · (4 cm)³

V = 10.667π cm³

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What is the sum of the √-2 and √ -18?

What is the sum of the -2 and -18?

Answers

The Solution:

We are required to find the sum of

\(\sqrt[]{-2}\text{ and }\sqrt[]{-18}\)

This also means that we should simplify

\(\sqrt[]{-2}+\sqrt[]{-18}\)\(\begin{gathered} \sqrt[]{-2}+\sqrt[]{-18}=\sqrt[]{-1}\times\sqrt[]{2}+\sqrt[]{-1}\times\sqrt[]{18} \\ \\ =i\sqrt[]{2}+i\sqrt[]{9\times2} \\ \\ =\sqrt[]{2i}+3\sqrt[]{2i} \\ =4\sqrt[]{2i} \end{gathered}\)

Therefore, the correct answer is option 2

Assume that a softball player has a 0.410 batting average. Assume that this means the player has a 0.41 probability of getting a hit in each at bat. Assume that the player bats four times. What is the probability that she gets exactly two hits?Decimal rounded to four places as needed.

Answers

Answer:

P = 0.3511

Explanation:

Using the equation for the binomial distribution, we get that the probability can be calculated as:

\(P(x)=\text{nCx}\cdot p^x\cdot(1-p)^{n-x}\)

Where nCx is calculated as:

\(\text{nCx =}\frac{n!}{x!(n-x)!}\)

So, n is the total number of bats, x is the number of hits and p is the probability of getting a hit. So, replacing n = 4, x = 2 and p = 0.41, we get:

\(\begin{gathered} 4C2=\frac{4!}{2!(4-2)!}=\frac{4!}{2!^{}\cdot2!}=6 \\ P(2)=4C2\cdot(0.41)^2\cdot(1-0.41)^{4-2} \\ P(2)=6\cdot(0.41)^2\cdot(0.59)^2 \\ P(2)=0.3511 \end{gathered}\)

Therefore, the answer is P = 0.3511

2x/3 divided by 3x/2 if x does not equal 0

Answers

say x = 3 the answer would be 2/4.5 which would end up being 4/9

The value of the expression 2x/3 ÷ 3x/2 when x ≠ 0 is 4/9.

What is an expression?

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

2x/3 ÷ 3x/2 when x ≠ 0.

This can be written as,

= (2x/3) x (2/3x)

= 2/3 x 2/3

= 4/9

Thus,

The value of the expression is 4/9.

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Margin of error: 0.04; confidence level: 95%; from a prior study, p is estimated by the decimal equivalent of 60%
A) 577 B) 1441 C) 996 D) 519

Answers

The required sample size of the given value is 577.

What is margin of error?

In a random survey sample, a margin of error is a statistical measurement that takes into account the discrepancy between actual and anticipated findings. Simply said, you may determine the degree of unpredictability in data and research results using the margin of error.

The formula to calculate the sample size  :-

n = (p(1-p)((Zα/₂)/E)²

Given :  Estimated proportion  p = 0.60

Margin of error : E = 0.04

Significance level : α = 1-0.95 = 0.05

Critical value : Zα/₂ = 1.96

Now, the required sample size will be :-

n = (0.60)(0.11)(1.96/0.04)²

= 6.6 * (0.0784)²

= 0.57744

Hence, the required minimum sample size of the given is 577.

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What is the value of x in the proportion below
(2/3)/5=x/16

Answers

Answer:

\(x=\dfrac{32}{15}\)

You can buy 12 magnets for $34.68, or 3 magnets for $9.57 to decide which is the better buy. Explain your reasoning.

Answers

Answer:

The 12 magnets for $34.68 as the unit price is lower.

Step-by-step explanation:

→ Find the cost per magnet for 12

34.86 ÷ 12 = $2.89

→ Find the cost per magnet for 3

9.57 ÷ 3 = $3.19

Robin weighs her math textbook and finds that it is 2 kilograms. How many grams does her textbook weigh?

Answers

Answer:

2000

Step-by-step explanation:

1 kilogram is 100 grams therefore 2 kilo grams is equal to 2000 grams

The word kilo means thousand in Greek and i think French

:)

Answer:

2,000 grams :)

help!!!

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.
Determine each segment length in right triangle ABC

help!!!Drag the tiles to the boxes to form correct pairs. Not all tiles will be used.Determine each segment

Answers

The segment lengths are given as follows:

BD = 7.BC = \(7\sqrt{2}\)

What is the Pythagorean Theorem?

The Pythagorean Theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the lengths of the other two sides.

The theorem is expressed as follows:

c² = a² + b².

In which:

c is the length of the hypotenuse.a and b are the lengths of the other two sides (the legs) of the right-angled triangle.

Considering the geometric mean theorem, the triangle has bases of 7 and 14 - 7 = 7, hence the altitude BD is given as follows:

BD² = 7 x 7

BD² = 7²

BD = 7.

The segment BC is the hypotenuse of a right triangle of two sides with length 7, hence:

(BC)² = 7² + 7²

\(BC = \sqrt{2 \times 49}\)

\(BC = 7\sqrt{2}\)

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82°
118°
95°

Image not to scale
Calculate the missing angle x.

8211895XImage not to scaleCalculate the missing angle x.

Answers

Answer:

x = 65

Step-by-step explanation:

the sum of the interior angles of a quadrilateral = 360°

sum the angles and equate to 360

x + 95 + 118 + 82 = 360

x + 295 = 360 ( subtract 295 from both sides )

x = 65

Suppose we have a collection of cars, we measure their weights and fuel efficiencies, and generate the following graph of the data. Note: automobile fuel efficiency is often measured in mpg (miles that the car can be driven per one gallon of gas).706050O 4030201000102030405060Weight (100 lbs)For this data set, X represents the weight of each car in hundreds of pounds, and Y represents the predicted fuel efficiency of each car in miles per gallon (mpg). A reasonable value for the slope of the regression line is -1.11. Which of the following statements is the most complete valid conclusion about the relationship between weight and fuel efficiencyHeavier cars tend to have lower mpg ratings.For every 100-pound increase in car weight, we expect to see a 1.11 mpg increase in fuel efficiency.For every 1-pound increase in car weight, we expect to see a 1.11 mpg decrease in fuel efficiency.For every 100-pound increase in car weight, we expect to see a 1.11 mpg decrease in fuel efficiency.

Answers

A statement which is the most complete valid conclusion about the relationship between weight and fuel efficiency include the following: D. For every 100-pound increase in car weight, we expect to see a 1.11 mpg decrease in fuel efficiency.

What is the slope-intercept form?

In Mathematics and Geometry, the slope-intercept form of the equation of a straight line is given by this mathematical equation;

y = mx + c

Where:

m represent the slope or rate of change.x and y are the points.c represent the y-intercept or initial value.

Based on the information provided about the car's weights and fuel efficiencies, a reasonable value for the slope (m) of the regression line is equal to -1.11.

In this context, we can logically conclude that for every 100-pound increase in car weight, there would be a 1.11 mpg decrease in fuel efficiency because the slope is negative.

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Complete Question:

Suppose we have a collection of cars, we measure their weights and fuel efficiencies, and generate the following graph of the data.

Note: automobile fuel efficiency is often measured in mpg (miles that the car can be driven per one gallon of gas).

For this data set, X represents the weight of each car in hundreds of pounds, and Y represents the predicted fuel efficiency of each car in miles per gallon (mpg). A reasonable value for the slope of the regression line is -1.11.

Which of the following statements is the most complete valid conclusion about the relationship between weight and fuel efficiency?

A. Heavier cars tend to have lower mpg ratings.

B. For every 100-pound increase in car weight, we expect to see a 1.11 mpg increase in fuel efficiency.

C. For every 1-pound increase in car weight, we expect to see a 1.11 mpg decrease in fuel efficiency.

D. For every 100-pound increase in car weight, we expect to see a 1.11 mpg decrease in fuel efficiency.

Suppose we have a collection of cars, we measure their weights and fuel efficiencies, and generate the

A rectangular poster is 50 centimeters long and 25 centimeters wide. If 1 centimeter is approximately 0.4 inches, which of the following best represents the area of the poster in inches?

Answers

The area of the poster in inches is,

⇒ A = 4 inches²

We have to given that;

A rectangular poster is 50 centimeters long and 25 centimeters wide.

Here, 1 centimeter is approximately 0.4 inches

Hence, Lenght = 50 cm

Lenght = 50 x 0.4

            = 2 inches

Width = 25 cm

          = 25 x 0.4

           = 1 inches

Thus, The area of the poster in inches is,

⇒ A = 1 x 4

⇒ A = 4 inches²

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(b) 1 kilogram 2.2 pounds, express your answer from part (a) in pounds. Answer: lbs [2]​

Answers

Answer:

37

Step-by-step explanation:

Hello! Need a little help on part B. Thank you!

Hello! Need a little help on part B. Thank you!
Hello! Need a little help on part B. Thank you!

Answers

we have the system of equations

\(\begin{gathered} f(x)=\log_2x+2 \\ g(x)=\log_2x^3-6 \end{gathered}\)

Equate the functions f(x) and g(x)

\(\log_2x+2=\log_2x^3-6\)

Apply property of logarithms

\(\begin{gathered} \operatorname{\log}_2x+2=3\operatorname{\log}_2x-6 \\ 3\operatorname{\log}_2x-\operatorname{\log}_2x=2+6 \\ 2\operatorname{\log}_2x=8 \\ \operatorname{\log}_2x=4 \end{gathered}\)

Apply the definition of logarithm

\(\begin{gathered} 2^4=x \\ x=16 \end{gathered}\)

Which mineral test is shown in the image?
Public Domain
Streak
Magnetism
Specific gravity
Or
Crystal shape

Answers

There’s no image put one

coaching and sat scores what we really want to know is whether coached students improve more than uncoached students, and whether any advan- tage is large enough to be worth paying for. use the information above to answer these questions: (a) how much more do coached students gain on the aver- age? construct and interpret a 99% confidence interval.

Answers

With 99% confidence that the true difference lies between 0.1316 and 0.2694.

A 99% confidence interval for the difference in average SAT scores between coached and uncoached students can be constructed using the data above.

The confidence interval is calculated as (mean of coached students - mean of uncoached students) +/- (2 * standard error of the difference in means).

The mean of coached students is (0.3098 + 0.3399 + 0.219 + 0.0798) / 4 = 0.2155, and the mean of uncoached students is (0.0046 + 0.0248) / 2 = 0.0147. The standard error of the difference in means can be calculated as the square root of ((0.2155(1-0.2155)/4) + (0.0147(1-0.0147)/2)).

The confidence interval is then (0.2155 - 0.0147) +/- (2 * 0.0347) = 0.201 +/- 0.0694, or (0.1316, 0.2694). This indicates that, on average, coached students gain 0.201 points more than uncoached students, with 99% confidence that the true difference lies between 0.1316 and 0.2694.

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on new year’s day the average temperature of the city is 5.7 degrees celsius. but for new year’s day 2012 the temperature was 9.8 degrees below the average

Answers

Answer:

-4.1

Step-by-step explanation:

5.7-9.8= -4.1

What is the slope of the line?

What is the slope of the line?

Answers

Answer:

2/3

Step-by-step explanation:

Find two points

(0,-2) and (3,0)

Using the slope formula

m = (y2-y1)/(x2-x1)

   = (0- -2)/(3-0)

  = (0+2)/(3-0)

   = 2/3

Answer:

\(\frac{2}{3}\)

Step-by-step explanation:

From the graph, we can see the line passes through the points (3,0) and (0,-2).

The slope of a line, \(m\), that passes through points \((x_1,y_1)\) and \((x_2,y_2)\) is given by \(m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}\)

Let \((x_1,y_1)\implies (3,0)\) and \((x_2,y_2)\implies (0,-2)\).

The slope of the line that passes through these points is:

\(m=\frac{-2-0}{0-3}=\frac{-2}{-3}=\boxed{\frac{2}{3}}\)

Cellular phone usage grew about 22% each year from 1995 (about 34 million) to 2003. Write a function to model cellular phone usage over that time period. What is the cellular usage in 2003?

Answers

Answer:

Given the information you provided, we can model cellular phone usage over time with an exponential growth model. An exponential growth model follows the equation:

`y = a * b^(x - h) + k`

where:

- `y` is the quantity you're interested in (cell phone usage),

- `a` is the initial quantity (34 million in 1995),

- `b` is the growth factor (1.22, representing 22% growth per year),

- `x` is the time (the year),

- `h` is the time at which the initial quantity `a` is given (1995), and

- `k` is the vertical shift of the graph (0 in this case, as we're assuming growth starts from the initial quantity).

So, our specific model becomes:

`y = 34 * 1.22^(x - 1995)`

To find the cellular usage in 2003, we plug 2003 in for x:

`y = 34 * 1.22^(2003 - 1995)`

Calculating this out will give us the cellular usage in 2003.

Let's calculate this:

`y = 34 * 1.22^(2003 - 1995)`

So,

`y = 34 * 1.22^8`

Calculating the above expression gives us:

`y ≈ 97.97` million.

So, the cellular phone usage in 2003, according to this model, is approximately 98 million.

Joanne earns $3,000 per month at her job at the department store. If her taxes are 28 percent of her pay, what is her monthly take-home pay?

Answers

Joanne her earns 3000$ I’m which she gives 28 percent of it to taxes
So 28 percent of 3000$ is
3000*28/100 where 3000*28 is equal to
84000/100
840$ is 28 percent of 3000$
So to fine the remaining amount of money after she pays that amount is
3000$-840$
Which is equal to 2160$

Find the mass and center of mass of the lamina that occupies the region D and has the given density function ?.
D is bounded by y = (1 ? x^2) and y = 0;
?(x, y) = 7ky
m =
(x bar, y bar)=

Answers

To find the mass of the lamina, we need to integrate the density function over region D. The density function is given by? (x, y) = 7ky, where k is a constant. The region D is bounded by y = \((1 ? x^2)\)  and y = 0, and the limits of integration are \(0 < = y < = (1 - x^2)\) .

So, the mass of the lamina is:

\(m = ∫∫?(x, y) dx dy = ∫∫ 7ky dx dy\\= 7k ∫∫ y dx dy = 7k * ∫ (1 - x^2) dy dx\\= 7k * ∫(0 to 1 - x^2) y dy\\= 7k * (1/2 * ∫(0 to 1 - x^2) y^2 dy)\\= 7k * (1/2 * [y^3/3] evaluated at y = (1-x^2) and y=0)\\= 7k * (1/2 * [((1-x^2)^3/3] - 0))= 7k * (1/2 * (1/3 - x^6))\)

To find the center of mass (x bar, y bar) of the lamina, we need to find the x and y coordinates of the center of mass.

The x-coordinate is given by

\((x bar) = 1/m * ∫∫ x ?(x, y) dx dy = 1/m * ∫∫ x * 7ky dx dy \\= 7k * ∫ (x * y) dx dy\\= 7k * (x * 1/2 * ∫(0 to 1 - x^2) y^2 dy)\\= 7k * (x * 1/2 * [y^3/3] evaluated at y = (1-x^2) and y=0)\\= 7k * (x * (1/2 * (1/3 - x^6))\\The y-coordinate is given by\\(y bar) = 1/m * ∫∫ y ?(x, y) dx dy = 1/m * ∫∫ y * 7ky dx dy= 7k * ∫ (y^2) dx dy\\= 7k * (1/3 * ∫(0 to 1 - x^2) y^3 dy)\\= 7k * (1/3 * [y^4/4] evaluated at y = (1-x^2) and y=0)\\= 7k * (1/3 * (1/4 - x^6/2))\)

It's worth noting that the mass and center of mass of the lamina depend on the constant k, which is not specified in the problem.

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Whats the coefficient of x^3 the expansion of (2x - 4)^7

Answers

The given form to expand is (2x-4)^7

and we need to find the coefficient of x^3.

The binomial formula is

\((a+b)^n=\sum_{r\mathop{=}0}^nC_r^na^{n-r}b^r\)

where n is a positive integer and a, b are real numbers, and 0 < r ≤ n

Substituting the values a = 2x, b = -4, n = 7 and r = 4

Then we have,

\((2x-4)^7=C_4^7(2x)^3(-4)^4\)

Now the coefficient of x^3 will be

\(\begin{gathered} C_4^7\times8x^3\times256 \\ =\frac{7!}{4!3!}\times8\times256\times x^3 \\ =\frac{7\times6\times5}{3\times2\times1}\times8\times256\times x^3 \\ =35\times8\times256\times x^3 \\ =71680x^3 \end{gathered}\)

Hence, the coefficient will be 71680.

Which of the following terms have a GCF of ? Select two options.

Answers

Answer:

hi please upload the photo so we can help :)

Answer:

A:12p^3r and D:54p^3

Step-by-step explanation:

What is the equation of the line that passes through (4, 3) and (-4, -1)?

Choices:
2x+1
y=2x+7
y=x/2 +1
y= -x/2 +7

Answers

The equation of the line that passes through (4, 3) and (-4, -1) is y = -x/2 + 5. So, correct option is A.

To find the equation of the line that passes through two given points, we use the slope-intercept form of a linear equation, which is:

y = mx + b

where m is the slope of the line and b is the y-intercept.

First, we need to find the slope of the line using the two given points. The formula for finding slope between two points is:

m = (y₂ - y₁) / (x₂ - x₁)

where (x₁, y₁) and (x₂, y₂) are the coordinates of the two points.

Substituting the given points into the formula, we get:

m = (-1 - 3) / (-4 - 4) = -4/8 = -1/2

Now we know the slope, we can use one of the given points (4, 3) and substitute the slope into the slope-intercept form of the equation and solve for b.

y = mx + b

3 = (-1/2)(4) + b

3 = -2 + b

b = 5

Therefore, the equation of the line that passes through (4, 3) and (-4, -1) is:

y = -x/2 + 5

So, correct option is A.

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Complete question is:

What is the equation of the line that passes through (4, 3) and (-4, -1)?

Choices:

y = -x/2 + 5

y=2x+7

y=x/2 +1

y= -x/2 +7

Elena has $225 in her bank account. She takes out $20 each week for some weeks. After some weeks she has $145 dollars left in her bank account

Answers

Answer:

145

Step-by-step explanation:

You told me 0-o

Answer:

After 4 weeks, she has $145 dollars left in her bank account.

Step-by-step explanation:

Week 1 = 225 - 20 = 205

Week 2 = 205 - 20 = 185

Week 3 = 185 - 20 = 165

Week 4 = 165 - 20 = 145

please
\(2x {}^{2} + 2y {}^{2} - 6y - 12y = 3 \)
I need help​

Answers

Here you go, hope this helps
please [tex]2x {}^{2} + 2y {}^{2} - 6y - 12y = 3 [/tex]I need help
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