The diagram shows an open rectangular box ABCDEFGH.
A straight stick AGM rests against A and G and extends outside the box to M.
a. Calculate the angle between the stick and the base of the box.
b. AM= 30 cm.
Show that GM= 4.8 cm, correct
to 1 decimal place.
The angle between the stick and the base of the box is 77. 9 degrees
How to determine the angleTo determine the angle between the stick and the base, we have to know the trigonometric identities.
These identities are;
sinecosinecotangenttangentsecantcosecantFrom the information given, we have;
sin A = FB/AB
Given that;
GB = 14.5cm
AB = 18. 6cm
substitute for the length of the sides, we have;
sin A = 14.5/18. 6
Divide the values, we have;
sin A = 0. 7796
Find the inverse sine
A = 77. 9 degrees
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Given the following formula, solve for y. W = x-y/2 - z
A.) Y= 2(w + z) - x
B.) y = x– (2w + z)
C.) Y = x – (2W + z)
D.) Y= 2w + 2 - z - x
Answer:
the answer is B. y=x-(2w+z)
Step-by-step explanation:
The solution to the given expression is y = x - 2(W + z).
What is an expression ?An expression is a mathematical expression formed by numbers and mathematical operations.There are many types of expressions like trigonometric expressions,Algebraic expressions, logarithmic expressions and many more.
According to the given question we have to solve for y for the given expression W = (x-y)/2 - z.
W = (x-y)/2 - z.
2W = x - y - 2z.
y = x - 2W - 2z.
y = x -2( W + z).
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The integral of [(x^2)(y^2)dx + x y dy] where C consists of the arc of the parabola y = x^2 from (0,0) to (1,1) and the line segments from (1,1) to (0,1) using line integral and Green theorem please
The line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1, 1), and the line segment from (1,1) to (0,1) is equal to 2/5.
What is integral?
The value obtained after integrating or adding the terms of a function that is divided into an infinite number of terms is generally referred to as an integral value.
To evaluate the line integral using Green's theorem, we need to find a vector field F = (P, Q) such that ∇ × F = Qₓ - Pᵧ, where Qₓ represents the partial derivative of Q with respect to x, and Pᵧ represents the partial derivative of P with respect to y.
Let's consider F = (P, Q) = (x²y², xy).
Now, let's calculate the partial derivatives:
Qₓ = ∂Q/∂x = ∂(xy)/∂x = y
Pᵧ = ∂P/∂y = ∂(x²y²)/∂y = 2x²y
The curl of F is given by ∇ × F = Qₓ - Pᵧ = y - 2x²y = (1 - 2x²)y.
Now, let's find the line integral using Green's theorem:
∫[C] (Pdx + Qdy) = ∫∫[R] (1 - 2x²)y dA,
where [R] represents the region enclosed by the curve C.
To evaluate the line integral, we need to parameterize the curve C.
The arc of the parabola y = x² from (0, 0) to (1, 1) can be parameterized as r(t) = (t, t²) for t ∈ [0, 1].
The line segment from (1, 1) to (0, 1) can be parameterized as r(t) = (1 - t, 1) for t ∈ [0, 1].
Using these parameterizations, the region R is bounded by the curves r(t) = (t, t²) and r(t) = (1 - t, 1).
Now, let's calculate the line integral:
∫∫[R] (1 - 2x²)y dA = ∫[0,1] ∫[t²,1] (1 - 2t²)y dy dx + ∫[0,1] ∫[0,t²] (1 - 2t²)y dy dx.
Integrating with respect to y first:
∫[0,1] [(1 - 2t²)(1 - t²) - (1 - 2t²)t²] dt.
Simplifying:
∫[0,1] [1 - 3t² + 2t⁴] dt.
Integrating with respect to t:
[t - t³ + (2/5)t⁵]_[0,1] = 1 - 1 + (2/5) = 2/5.
Therefore, the line integral ∫[C] (Pdx + Qdy) over the given curve C consisting of the arc of the parabola y = x² from (0,0) to (1,1), and the line segment from (1,1) to (0,1) is equal to 2/5.
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Please look at the image and help me out (maths)
a) The coordinates of point A are given as follows: (-4,1).
b) The point B is plotted in red on the image given for this problem.
c) The coordinates of point C are given as follows: (-4,-2).
How to define the ordered pair?The general format of an ordered pair is given as follows:
(x,y).
In which the coordinates are given as follows:
x is the x-coordinate.y is the y-coordinate.Then the coordinates of point C are given as follows:
x = -4 -> same x-coordinate of point A.y = -2 -> same y-coordinate of point B.Hence the ordered pair is given as follows:
(-4, -2).
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1. (5 pts) The (per hour) production function for bottles of coca-cola is q=1000K L
, where K is the number of machines and L is the number of machine supervisors. a. (2 pts) What is the RTS of the isoquant for production level q? [Use the following convention: K is expressed as a function of L b. (1 pt) Imagine the cost of operating capital is $40 per machine per hour, and labor wages are $20/ hour. What is the ratio of labor to capital cost? c. (2 pts) How much K and L should the company use to produce q units per hour at minimal cost (i.e. what is the expansion path of the firm)? What is the corresponding total cost function?
The RTS of the isoquant is 1000K, indicating the rate at which labor can be substituted for capital while maintaining constant production. The labor to capital cost ratio is 0.5. To minimize the cost of producing q units per hour, the specific value of q is needed to find the optimal combination of K and L along the expansion path, represented by the cost function C(K, L) = 40K + 20L.
The RTS (Rate of Technical Substitution) measures the rate at which one input can be substituted for another while keeping the production level constant. To determine the RTS, we need to calculate the derivative of the production function with respect to L, holding q constant.
Given the production function q = 1000KL, we can differentiate it with respect to L:
d(q)/d(L) = 1000K
Therefore, the RTS of the isoquant for production level q is 1000K.
The ratio of labor to capital cost can be calculated by dividing the labor cost by the capital cost.
Labor cost = $20/hour
Capital cost = $40/machine/hour
Ratio of labor to capital cost = Labor cost / Capital cost
= $20/hour / $40/machine/hour
= 0.5
The ratio of labor to capital cost is 0.5.
To find the combination of K and L that minimizes the cost of producing q units per hour, we need to set up the cost function and take its derivative with respect to both K and L.
Let C(K, L) be the total cost function.
The cost of capital is $40 per machine per hour, and the cost of labor is $20 per hour. Therefore, the total cost function can be expressed as:
C(K, L) = 40K + 20L
To produce q units per hour at minimal cost, we need to find the values of K and L that minimize the total cost function while satisfying the production constraint q = 1000KL.
The expansion path of the firm represents the combinations of K and L that minimize the cost at different production levels q.
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a poll shows that 70\p% of all voters approve of the mayor's work. on three separate occasions a pollster selects a voter at random. what is the probability that on exactly one of these three occasions the voter approves of the mayor's work?
The chance that the voter will endorse the mayor's work on one of these three occasions is 0.189.
Given that,
Considering that 70% of voters support the mayor's efforts, 30% of voters oppose those efforts.
Formula for the binomial distribution
\(nCx. p^{x}.(1-p)^{n-x}\)
We find the number of ways only 1 person approves nCx of the mayor multiplied by the probability 1 person approves P^x and 2 people disapprove (1-p)^{n-x}
Only one person approves of in how many ways is
= nCx. p^{x}.(1-p)^{n-x}
= 3C1. 7^1.(1-7)^(3-1)
By solving we get,
= 0.189
Hence, the probability that on exactly one of these three occasions the voter approves of the mayor's work is 0.189
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The global minimum of the function f(x)
This line plot shows the daily rainfall amounts during the month of May.
On June 1, the rainfall amount was 1/2 of the greatest daily rainfall that fell in May.
What was the rainfall amount on June 1?
Enter your answer in the box as a fraction in simplest form.
Answer:
Rainfall amount on June 1 = ¾ inch
Step-by-step explanation:
Greatest daily rainfall in May = 1½
Rainfall amount in June 1 = ½ of 1½
Thus:
rainfall amount in June = ½ × 1½
= ½ × ³/2
= (1*3)/(2*2)
= ¾
Rainfall amount on June 1 = ¾ inch
5'2 + 11 - 2
2'1
Please help me
Answer:16'3
Step-by-step explanation:
enlarge the shape by scale factor 2 using P as the centre of enlargement
Enlarging the shape by scale factor 1/2 using P as the centre of enlargement
let's start from bottom left point is given.
How to explain diagramWe have to calculate position from P to that point as below
it is 2 units up and 11 units left
so as scale factor is 1/2
We have to shift that point to 1 unit up and 5.5 units left
Pink point corresponding to it is denoted below
We have to do the same process for all the five points to cover the total figure
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Complete question
Enlarge the shape by scale factor 1/2 using P as the centre of enlargement
I got the first part but i dont onow how to get the other ones
The value of x for this problem is given as follows:
x = 5.
Hence the angle measures are given as follows:
m < CAB = 32º.m < FDE = 32º.How to obtain the value of x?
We have that angles A and D are congruent for this problem, meaning that they have the same measure.
Hence the value of x is obtained as follows:
7x - 3 = 5x + 7
2x = 10
x = 5.
Hence the angle measures are given as follows:
m < CAB = 7(5) - 3 = 35 - 3 = 32º.m < FDE = 5(5) + 7 = 32º.More can be learned about angle measures at https://brainly.com/question/25716982
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Write the number 0.00004 in scientific notation.
Answer:
4.0 x 10^-5
Step-by-step explanation:
Answer:
4*10^-5
Step-by-step explanation:
Start by counting the zeros to the right of the decimal if 0<x<1. Stop when you hit a digit between 1 and 9Add 1 to the number of zerosThis is the powerExpress the number as one between 1 and 9 The power is changed to a negative, if 0<x<10.00004 has 4 zeros. Add 1 = 5
The power on 10 becomes negative (-5)
4 is a number between 1 and 9 inclusive.
4 * 10^-5
suppose a jar contains 19 red marbles and 25 blue marbles. if you reach in the jar and pull out 2 marbles at random, find the probability that both are red. write your answer as a reduced fraction.
The probability that both marbles are red is 9/23.
To find the probability of both marbles being red, follow these steps:
1. Calculate the total number of marbles in the jar: 19 red + 25 blue = 44 marbles.
2. Determine the probability of picking a red marble on the first draw: 19 red marbles / 44 total marbles = 19/44.
3. After picking one red marble, there are 18 red marbles and 43 total marbles left. Calculate the probability of picking a red marble on the second draw: 18 red marbles / 43 total marbles = 18/43.
4. Multiply the probabilities from steps 2 and 3 to find the overall probability: (19/44) x (18/43) = 342/1892.
5. Simplify the fraction: 342/1892 = 9/23.
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What is the sale price of a shirt that was originally $25 but that has been marked down by 33 percent?
$8. 25
$8. 50
$16. 50
$16. 75
16.75
Hope i could help
Help me shoe work on this question please
The line /TV/ that we have been asked to find from the information is the question is obtained as 7.
What is the sine rule?The sine rule, also known as the law of sines, is a trigonometric formula used to find an unknown side or angle in a triangle. It states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is equal for all three sides of the triangle.
We know that the missing angle U is obtained from;
180 - (58.3 + 80)
= 41.7°
Then;
8.9/Sin 58.3 = /TV//Sin 41.7
/TV/ = 8.9 Sin 41.7/Sin 58.3
/TV/ = 5.9/0.85
= 7
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I need to know the answer for this question. Which por portion could be used to find the value of x
Answer:
\(\dfrac{9}{6}=\dfrac{8}{v}\)
Step-by-step explanation:Similar polygons:Similar polygons are two polygons with same shape and different size.
In similar polygons
Corresponding angles are congruent.Corresponding sides are proportional.To find the value f 'x'
\(\dfrac{ED}{E'D'} = \dfrac{CD}{C'D'}\\\\\dfrac{9}{6}=\dfrac{8}{v}\)
Given the following information, determine which lines, if any, are parallel. State the postulate or theorem that justifies your answer. (Lesson 3-5)
∠1 ≅∠ 4
Lines with angles 5 and 6 are parallel.
Given the information that ∠1 is congruent to ∠4, let us determine which lines are parallel.
Postulate: If a transversal intersects two parallel lines, then the corresponding angles are congruent. Since the corresponding angles are congruent, and the corresponding angles are the angles that are in the same position, i.e., on the same side of the transversal in relation to the two parallel lines, then this is the result:
∠1 is congruent to ∠4 (given)
∠1 is a corresponding angle to ∠5
∠4 is a corresponding angle to ∠6
Since ∠1 is congruent to ∠4, then ∠5 must be congruent to ∠6.
If lines are parallel, the corresponding angles are congruent. Therefore, the lines with angles 5 and 6 are parallel.
Therefore, the postulate that justifies the answer is "If a transversal intersects two parallel lines, then corresponding angles are congruent."
Conclusion: Lines with angles 5 and 6 are parallel.
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Leah Deposited $7000 in an account that earns 2% interest compounded annually. How much interest will she have earned after 6 years?
Answer:
840
Step-by-step explanation:
7000×2×6 ÷ 100. since it is 2%
= 840
Maria is camping when she starts to smell smoke. She turns on her radio and hears
that a forest fire is heading her way. How can Maria's organ systems interact to help
keep her safe? Include at least five organ systems in your response.
Maria's organ systems interact to help keep her safe Nervous system, Respiratory system, Endocrine System, Integumentary System and Muscular System.
What are the organ systems?The organ systems is the system of body which consist of different organs of the body. These organs help to work the body freely.
Maria is camping when she starts to smell smoke. She turns on her radio, to get the news that a forest fire is heading her way. The organs which help her to keep safe from fire are listed below:
Nervous system- It helps to react the body against the hazard.Respiratory system-This organ system help Maria to keep breath with increasing the breathing rate.Integumentary System-This system help to protect her inner body from external environment.Endocrine System- It will help to maintain energy level. Muscular System-This system will help to run and do physical task in the fire.Thus, Maria's organ systems interact to help keep her safe Nervous system, Respiratory system, Endocrine System, Integumentary System and Muscular System.
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What are the degree and leading coefficient of the polynomial? 23-x^(6)+x^(5)+12x
The coefficient of the x^6 term is -1 (since the coefficient in front of x^6 is -1). Therefore, the leading coefficient of the polynomial is -1.
The degree of a polynomial is the highest power of the variable in the polynomial. In this case, the polynomial is:
P(x) = 23 - x^6 + x^5 + 12x
The highest power of the variable x is 6, so the degree of the polynomial is 6.
The leading coefficient is the coefficient of the term with the highest power. In this case, the coefficient of the x^6 term is -1 (since the coefficient in front of x^6 is -1). Therefore, the leading coefficient of the polynomial is -1.
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NO one helps me on this app
using the net calculate and label the area of each face of the prism. Add the areas of each face to find the surface area of the prism
Answer:
just add all of the numbers that are around the shape and you will have your answer!
Answer:
so far if u add everything it should equal to 126
If a bus traveled 200 miles in 4 hours, what was the average speed of the bus in miles per hour?
Answer:
that means it traveled 50 miles in a one hour or 50 mph
Hope This Helps!!!
Answer:
ure def not in high school but elemantarty. Its 50 mph bc 20 divided by 4= 5
Step-by-step explanation:
Julie had $150. She needed to spend $3.00 for lunch every day. How much money will she have left after 20 days?
Answer:
$90.00
Step-by-step explanation:
The equation would be 150-3(20), or 150-60, which equals $90.00
Answer:
she will have $90 after 20 days
Step-by-step explanation:
3 times 20 = 60
60-150=90
Four kids: Aaron, Bessy, Carl and Dawn play with beads. They start with 200 beads in all. Aaron gave Bessy 26 beads, Bessy gave Carl 36 beads, Carl gave dawn 32 beads, and Dawn gave Aaron 4 beads. They end up with the same number of beads as each other. How many beads did Aaron have at the beginning?
Answer:
72 beads
Step-by-step explanation:
Let's call the the inicial number of beads Aaron has 'A', Bessy has 'B', Carl has 'C' and Dawn has 'D'.
First, we have A + B + C + D = 200
Aaron gives 26 and receives 4, so Aaron has A' = A - 22
Bessy gives 36 and receives 26, so Bessy has B' = B - 10
Carl gives 32 and receives 36, so Carl has C' = C + 4
Dawn gives 4 and receives 32, so Dawn has D' = D + 28
And in the end we have A' = B' = C' = D'.
The total number of beads is still 200, so we have:
A' + B' + C' + D' = 200
A' + A' + A' + A' = 200
A' = 50
A - 22 = 50
A = 72 beads
Please help me!
[One Step Inequalities]
Answer:
d≥24
Step-by-step explanation:
19≤−5+d
Swap sides so that all variable terms are on the left hand side. This changes the sign direction.
−5+d≥19
Add 5 to both sides.
d≥19+5
Add 19 and 5 to get 24.
d≥24
Answer:
c
Step-by-step explanation:
Determine the range of the following graph
Answer:
left to right (-11, 1) up and down (3,-6)
ASAP
- WILL MARK BRIANLISt
answer:
A, D, E
step-by-step explanation:
in order to find the range, you have subtract the smallest number from the largest number in the set of values you are givenA — 13 - 1 = 12
B — 15 - 7 = 8
C — 12 - 12 = 0
D — 28 - 16 = 12
E — 36 - 24 = 12
F — 29 - 25 = 4
i took each of the set of values and subtracted the smallest from the largest and got that A, D and E give me 12 for the rangeGiven m|n, find the value of x.
т
(6x+4)
(4X-14)
Step-by-step explanation:
Here Is Your Answer........ please Make me as brainliest
true or false: if you are given a graph with two shiftable lines, the correct answer will always require you to move both lines.
False. if you are given a graph with two shif table lines, the correct answer will always require you to move both lines.
In a graph with two shiftable lines, the correct answer may or may not require moving both lines. It depends on the specific scenario and the desired outcome or conditions that need to be met.
When working with shiftable lines, shifting refers to changing the position of the lines on the graph by adjusting their slope or intercept. The purpose of shifting the lines is often to satisfy certain criteria or align them with specific points or patterns on the graph.
In some cases, achieving the desired outcome may only require shifting one of the lines. This can happen when one line already aligns with the desired points or pattern, and the other line can remain fixed. Moving both lines may not be necessary or could result in an undesired configuration.
However, there are also situations where both lines need to be shifted to achieve the desired result. This can occur when the relationship between the lines or the positioning of the lines relative to the graph requires adjustments to both lines.
Ultimately, the key is to carefully analyze the graph, understand the relationship between the lines, and identify the specific criteria or conditions that need to be met. This analysis will guide the decision of whether one or both lines should be shifted to obtain the correct answer.
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determine the values of the following quantities. (round your answers to three decimal places.) (a) t0.10, 10 (b) t0.05, 10 (c) t0.05, 21 (d) t0.05, 60 (e) t0.005, 60
These values are based on the t-distribution table and represent critical values for the given probabilities and degrees of freedom.
To answer this question, we need to use a t-table. The values we are looking for are the t-values associated with specific probabilities and degrees of freedom.
(a) t0.10, 10 = 1.372 (from the t-table, using 10 degrees of freedom and the probability of 0.10)
(b) t0.05, 10 = 1.812 (from the t-table, using 10 degrees of freedom and the probability of 0.05)
(c) t0.05, 21 = 1.721 (from the t-table, using 21 degrees of freedom and the probability of 0.05)
(d) t0.05, 60 = 1.671 (from the t-table, using 60 degrees of freedom and the probability of 0.05)
(e) t0.005, 60 = 2.660 (from the t-table, using 60 degrees of freedom and the probability of 0.005)
Note that we round all answers to three decimal places, as specified in the question. The values we have found are the t-values for the specified probabilities and degrees of freedom. These values can be used in calculations involving t-distributions.
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