Find the dividend when :

Divisor = 36 , Quotient = 6352 , Remainder = 28​

Answer:

They are being multiplied by 2 each time.

Step-by-step explanation:

The X values are going up by 1 and every time X goes up by 1, Y doubles. So (1,2) goes to (2,4) and then (3,8) etc.

Answer:

Step-by-step explanation:

Formula

V = pi r^2 h

h = V/ pi * r^2

But the volume is given as

h = 50*pi / (pi * 5^2)

h = 50 * pi / (25 * pi)

h = 2

The formula for height is given above. That pretty much makes sure there is only 1 answer.

Answer:

7

Step-by-step explanation:

Answer:

$72 is the retail price

Step-by-step explanation:

100 x (100-28)/100

based on the hypothesis test at a 0.05 level of significance, the doctor's claim is supported, and it can be concluded that the proportion of patients who do not return to work within 3 months after knee replacement surgery is higher than 25%.

To test the doctor's claim that more than 25% of patients who undergo knee replacement surgery do not return to work within 3 months, a hypothesis test is conducted at a 0.05 level of significance.

A sample of 40 patients who had the surgery was analyzed, and it was found that 15 of them did not return to work within 3 months. Based on the test results, we either reject or fail to reject the doctor's claim. The doctor's claim can be formulated as follows: Null hypothesis (H0): The proportion of patients who do not return to work within 3 months after knee replacement surgery is 25% or less.

Alternative hypothesis (H1): The proportion of patients who do not return to work within 3 months after knee replacement surgery is greater than 25%.

To test this claim, a hypothesis test is conducted using the sample data. The sample proportion of patients who did not return to work is 15/40 = 0.375.

Next, the test statistic is calculated. Since we are comparing a sample proportion to a hypothesized proportion, we can use the z-test. The test statistic is given by:

z = (sample proportion - hypothesized proportion) / sqrt((hypothesized proportion * (1 - hypothesized proportion)) / sample size)

Plugging in the values, we get:

z = (0.375 - 0.25) / sqrt((0.25 * (1 - 0.25)) / 40) ≈ 1.84

The critical value for a one-tailed test at a 0.05 level of significance is approximately 1.645.

Since the calculated test statistic (1.84) is greater than the critical value (1.645), we reject the null hypothesis. This indicates that there is sufficient evidence to support the doctor's claim that more than 25% of patients do not return to work within 3 months after knee replacement surgery.

In conclusion, based on the hypothesis test at a 0.05 level of significance, the doctor's claim is supported, and it can be concluded that the proportion of patients who do not return to work within 3 months after knee replacement surgery is higher than 25%.

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The combinations of four objects taken two at a time are: xy, xz, xs, yz, ys, and zs. The correct answer is option B.

To find the combinations of four objects taken two at a time (4C2), we need to list all the possible pairs of the objects. The objects are x, y, z, and s.

The combinations are:

xy, xz, xs, yz, ys, zs

These are all the possible pairs that can be formed by selecting two objects at a time from the given set of four objects.

Therefore, the correct answer is option B) xy, xz, xs, yz, ys, zs.

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Simplify the given expression as follows:

The missing numbers are - 5 and - 4.

The probabilities of the given events involving red marbles, blue marbles, odd-numbered marbles, and even-numbered marbles.

(a) The probability that the marble is red is \(\frac{3}{8}\). To find this, you need to divide the number of red marbles (6) by the total number of marbles (16). So, \(\frac{6}{16}=\frac{3}{8}\).

(b) The probability that the marble is odd-numbered is \(\frac{1}{2}\). To find this, count the odd-numbered marbles: 3 red (1, 3, 5) and 5 blue (1, 3, 5, 7, 9). So, there are 8 odd-numbered marbles. Divide this by the total number of marbles (16), giving \(\frac{8}{16}=\frac{1}{2}\).

(c) The probability that the marble is red or odd-numbered is \(\frac{11}{16}\). First, find the number of marbles that are red or odd-numbered: all 6 red marbles plus the 5 odd-numbered blue marbles (subtract 1 as blue marble number 1 was counted twice). This results in 10 unique marbles. So, the probability is \(\frac{5}{8}\) .

(d) The probability that the marble is blue or even-numbered is \(\frac{1}{2}\). This is complementary to the probability found in (c). Since the marble can only be red or odd-numbered, or blue or even-numbered, the probabilities must sum to 1. So, \(1 - \frac{5}{8}  = \frac{1}{2}\).

Your corrected answers are: (a) \(\frac{3}{8}\), (b) \(\frac{1}{2}\), (c) \(\frac{5}{8}\), and (d) \(\frac{1}{2}\).

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Answer:

B) 175

Step-by-step explanation:

Same thing as before:

To get from 1.4 to 7 and to get from 7 to 35, you have to multiply by 5.

To get from 35 to the next sequence, you also have to multiply by 5.

35·5

=175

Hope this helps! :)

Answer:

7=1.4n

n=7÷1.4

n=5

next term =35×5

=175 B

Answer:

x  ≈ 10.7 ft.

Step-by-step explanation:

Given triangle in the picture is a right triangle.

By applying Pythagoras Theorem in this triangle.

(Hypotenuse)² = (Leg 1)² + (Leg2)²

(14)² = x² + 9²

x² = (14)² - 9²

\(x=\sqrt{196-81}\)

\(x=\sqrt{115}\)

x = 10.72

x  ≈ 10.7 ft.

The graph that represents the inequality is graph b

From the question, we are to graph the given inequality

The given inequality is

y ≥ |x+5|-3

To graph the inequality, we will write the inequality as an equation and we will find some of the points on the line

When x = 0

y = |x+5|-3

y = |0+5|-3

y = |-3

When y = 0

y = |x+5|-3

0 = |x+5|-3

0 = (x + 5) - 3 and 0 = -(x + 5) -3

3 = x + 5

x = 3- 5

x = -2

and

0 = -(x + 5) -3

x + 5 = -3

x = -3 - 5

x = -8

The graphs that has the points above are graphs b and d.

Since the inequality sign is ≥ when y is the subject, the solution to the inequality is above the lines.

Hence, the graph of the inequality is graph b.

The graph of the inequality is shown below

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Answer:

12173

Step-by-step explanation:

    1 21  73      

3 | 365²19

Long division:

Starting from the first digit of the number being divided (i.e. 36519), move along dividing each digit by 3;

If the digit cannot be divided by 3 perfectly, the remainder should be in the next position of value to the next digit in the sequence, so for the above calculation:

First digit is 3, 3/3 = 1, so write the number 1 above;

There is no remainder so simply move to next digit;

The second digit in the number is 6, 6/3 = 2, so write 2 above, next to the previous 1;

Once again, no remainder so move on;

Third digit is 5, 5/3 = 1 with a remainder of 2, so we write 1 above, next to the previous 2 and the remainder of 2 will be placed before the next digit in the number, which is 1;

Understand, this 2 is not to be added to the digit, like 1 + 2, but rather should be added at the next higher position of value (i.e. multiplied by 10), so it will be 1 + 20, which is 21;

Now, we continue as previously, 21/3 = 7, so 7 should be written above, next to the 1;

There is no remainder, so move on;

Last digit is 9, 9/3 = 3 so this written next to the 7 above;

There is no remainder;

There are no more digits and no remainder to deal with so the division is complete;

The number above is the answer.

The profit percent for the pencils is equal to 10%.

If C is the cost and P is the price, then the formula for the profit percent is:

p = 100%*(P - C)/C

Here we know that the selling price of 10 pencils is equal to the cost price of 11 pencils, then we can write the eqation:

10*P = 11*C

We can solve this for P.

P = (11/10)*C = 1.1*C

Replacing that in the given formula we will get:

p = 100%*(1.1*C - C)/C

p = 100%*(1.1 - 1)*C/C

P = 10%

The profit percent is 10%.

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The amount of Simon's income left over after setting aside taxes for the three-month period is $1817.20.

We need to calculate the total earnings, total taxes, and subtract the taxes from the total earnings.

First, let's calculate the total earnings:

Simon's income for the three-month period is $860 + $680 + $720 = $2260.

He set aside 18% of his earnings each month for income taxes, so he set aside 18% * $2260 = $406.80 for income taxes.

He also set aside an additional 5% of his March income for other taxes, so he set aside 5% * $720 = $36 for other taxes.

The total amount of taxes he set aside is $406.80 + $36 = $442.80.

Finally, let's calculate the amount of income left over after setting aside taxes:

The amount of his income left over after setting aside taxes is $2260 - $442.80 = $1817.20.

Therefore, the amount of Simon's income left over after setting aside taxes for the three-month period is $1817.20.

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To find the probability distribution for Y, the number of errors detected by the auditor, we can use the binomial distribution formula. The binomial distribution is used when there are only two possible outcomes, success or failure, and each trial is independent.

In this case, the probability of success (detecting an error) is 5% or 0.05, and the probability of failure (not detecting an error) is 1 - 0.05 = 0.95.

a. To find the probability distribution for Y, we can use the formula for the binomial distribution:

P(Y = y) = (nCk) * p^k * (1-p)^(n-k)

where n is the number of trials (3 in this case), k is the number of successes (errors detected), p is the probability of success (0.05), and (nCk) is the combination formula.

For y = 0:
P(Y = 0) = (3C0) * (0.05)^0 * (0.95)^(3-0) = (1) * (1) * (0.95)^3 = 0.857375

For y = 1:
P(Y = 1) = (3C1) * (0.05)^1 * (0.95)^(3-1) = (3) * (0.05) * (0.95)^2 = 0.135375

For y = 2:
P(Y = 2) = (3C2) * (0.05)^2 * (0.95)^(3-2) = (3) * (0.05)^2 * (0.95)^1 = 0.007125

For y = 3:
P(Y = 3) = (3C3) * (0.05)^3 * (0.95)^(3-3) = (1) * (0.05)^3 * (0.95)^0 = 0.000125

So the probability distribution for Y is:
Y = 0 with probability 0.857375
Y = 1 with probability 0.135375
Y = 2 with probability 0.007125
Y = 3 with probability 0.000125

b. To construct a probability histogram for p(y), you can create a bar graph where the x-axis represents the number of errors detected (Y) and the y-axis represents the probability (P(Y = y)). Each bar will have a height corresponding to the probability.

c. To find the probability that the auditor will detect more than one error, we need to calculate the sum of the probabilities for Y = 2 and Y = 3:

P(Y > 1) = P(Y = 2) + P(Y = 3) = 0.007125 + 0.000125 = 0.00725

Therefore, the probability that the auditor will detect more than one error is 0.00725.

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I believe the answer is ASA

The quotient of the number 32 × 10⁻²² and 8 × 10⁻²² will be 4 × 10⁰. Then the correct option is D.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

The numbers are given below.

32 × 10⁻²² and 8 × 10⁻²²

The quotient of the number 32 × 10⁻²² and 8 × 10⁻²² will be given as,

⇒ (32 × 10⁻²²) / (8 × 10⁻²²)

⇒ 32 / 8

⇒ 4 × 10⁰

The quotient of the number 32 × 10⁻²² and 8 × 10⁻²² will be 4 × 10⁰. Then the correct option is D.

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The complete question is attached below.

Answer:

C

Step-by-step explanation:

Move 2x to the right side of the equation and it becomes -7y= -2x + 24 and then divide by -7 and then it becomes y = 2/7 x -24/7

Answer:

2x - 7y = 24

2x - 24 = 7y

7y = 2x - 24

y = (2x - 24)/7

= 2/7x - 24/7

Answer:

Step-by-step explanation:

a.)

\(4880.76=4000(1+.04/4)^{4x}\\\\1.22019=1.01^{4x}\\\frac{\ln{1.22019}}{\ln{1.01}}=4x\\x= 4.999999= 5\)

b.)

\(5395.4=4000(1+x/12)^{12*5}\\1.34885=(1+x/12)^{60}\\\sqrt[60]{1.34885} =1+x/12\\x= 0.0599999772677= .06\)

c.)

\(\i)\\100*(1+.1255)= 112.55\\\\2)\\100*(1+.1218/2)^2= 112.550881= 112.55\)

The probability of the teacher selecting one green popsicle can be calculated by dividing the number of green popsicles in the box (4) by the total number of popsicles in the box (24). The probability of selecting one green popsicle is: P(green) = 4/24 = \(1/6 ≈ 0.1667\)

This means that there is a 16.67% chance of the teacher selecting a green popsicle from the box. To describe this simple event, we can say that the teacher will randomly select one popsicle from the box and the probability of that selected popsicle being green is 1/6.

If the teacher repeated this experiment many times (selecting one popsicle at a time), we would expect to see a green popsicle selected approximately once in every six trials.

It's important to note that this probability assumes that all the popsicles in the box are equally likely to be selected and that the teacher is selecting the popsicle at random without any bias or preference towards any specific color.

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The points on the curve where the tangent line has a slope of -1 are (2/√3, -(2/√3)) and (-2/√3, 2/√3). None of the given answer choices matches this solution, so the correct option is (E) None of the above.

For the points on the curve where the tangent line has a slope equal to -1, we need to find the points where the derivative of the curve with respect to x is equal to -1. Let's find the derivative:

Differentiating both sides of the equation x^2 - xy + y^2 = 4 with respect to x:

2x - y - x(dy/dx) + 2y(dy/dx) = 0

Rearranging and factoring out dy/dx:

(2y - x)dy/dx = y - 2x

Now we can solve for dy/dx:

dy/dx = (y - 2x) / (2y - x)

We want to find the points where dy/dx = -1, so we set the equation equal to -1 and solve for the values of x and y:

(y - 2x) / (2y - x) = -1

Cross-multiplying and rearranging:

y - 2x = -2y + x

3x + 3y = 0

x + y = 0

y = -x

Substituting y = -x back into the original equation:

x^2 - x(-x) + (-x)^2 = 4

x^2 + x^2 + x^2 = 4

3x^2 = 4

x^2 = 4/3

x = ±sqrt(4/3)

x = ±(2/√3)

When we substitute these x-values back into y = -x, we get the corresponding y-values:

For x = 2/√3, y = -(2/√3)

For x = -2/√3, y = 2/√3

Therefore, the points on the curve where the tangent line has a slope of -1 are (2/√3, -(2/√3)) and (-2/√3, 2/√3).

None of the given answer choices matches this solution, so the correct option is:

E) None of the above.

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You would earn $2,857.93 more from your Third Street Bank account at the end of 10 years compared to your Second Union Bank account.

For Second Union Bank:

The interest rate is 5% simple interest, which means it is applied only to the initial deposit each year. The interest earned per year would be 5% of $22,000, which is $1,100. Over 10 years, the total interest earned would be $1,100 per year x 10 years = $11,000.

For Third Street Bank:

The interest rate is 5% compounded annually, which means the interest is added to the account balance each year and then earns interest in subsequent years. To calculate the total amount at the end of 10 years, we can use the formula for compound interest:

A = P(1 + r/n)^(n*t)

Where:

A = Total amount at the end of the period

P = Principal amount (initial deposit)

r = Annual interest rate (in decimal form)

n = Number of compounding periods per year

t = Number of years

In this case, the principal amount (P) is $22,000, the annual interest rate (r) is 5% (or 0.05 in decimal form), the compounding is done annually (n = 1), and the number of years (t) is 10.

Using the formula, we can calculate the total amount (A) at the end of 10 years:

A = $22,000(1 + 0.05/1)^(1*10)

A ≈ $34,857.93

Therefore, the total amount earned from the Third Street Bank account after 10 years is approximately $34,857.93 - $22,000 = $12,857.93.

The difference in earnings between the Third Street Bank account and the Second Union Bank account would be $12,857.93 - $11,000 = $2,857.93.

Hence, you would earn $2,857.93 more from your Third Street Bank account at the end of 10 years compared to your Second Union Bank account.

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Answer:

224ft^3

Step-by-step explanation:

l*w*h= volume

Answer:

The Volume is 224

Step-by-step explanation:

w * h * l

Answer:

(-1,1)

Step-by-step explanation:

the answer is where the two lines intersect.

Answer:

14.04

Step-by-step explanation:

2.4 x 4.5 = 10.8

10.8 x 1.3 = 14.04

Hope this helps :)

Answer:

D

Step-by-step explanation:

Answer:

-3, 3

Step-by-step explanation: