Find the difference.
(16m+3)-(4m-5)

Answer:

yes it represents it because the linear equation

here are the solutions to the distance problems:

To find the distance between the two points (0,1) and (0,6), we can use the distance formula:

Distance = √[(y2 - y1)² + (x2 - x1)²]

Substituting the values, we get:

Distance = √[(6 - 1)² + (0 - 0)²] = √25 = 5

Therefore, the distance between the two points is 5 units.

To find the distance between the two points (2,1) and (5,6), we can use the distance formula:

Distance = √[(y2 - y1)² + (x2 - x1)²]

Substituting the values, we get:

Distance = √[(6 - 1)² + (5 - 2)²] = √34 ≈ 5.8

Therefore, the distance between the two points is approximately 5.8 units (rounded to the nearest tenth).

To find the distance between the two points (4,6) and (-2,-2), we can use the distance formula:

Distance = √[(y2 - y1)² + (x2 - x1)²]

Substituting the values, we get:

Distance = √[(-2 - 6)² + (-2 - 4)²] = √80 ≈ 8.9

Therefore, the distance between the two points is approximately 8.9 units (rounded to the nearest tenth).

Answer:

18/40

Step-by-step explanation:

Answer:

Step-by-step explanation:

Subtract the equations. We get

13y = 52

y=4

SUBSTITUTE y in 1st equation and find x

-3x+8(4) =11

-3x = 11-32

-3x = -21

x=7

Step-by-step explanation:

that is really, really simple.

h(-3) means that we put the argument (-3) into the formula of the function everywhere where there is x.

h(x) = -3x - 10

so,

h(-3) = -3×-3 - 10 = 9 - 10 = -1

Answer:

-1

Step-by-step explanation:

h(x) = -3x - 10    

h(-3)            means to replace the x in the problem with the value of -3 and  

                   solve.

h(-3) = -3(-3) - 10

h(-3) =  9 - 10

h(3) = -1

Answer:

what was the first one.....the first song part

Step-by-step explanation:

Answer:

Lil NasX

Step-by-step explanation:

a) The magnitude of an earthquake that has an intensity that is 39.25 is 5.6 unit.

b) The magnitude of earthquake that has intensity of 4.4 is 4.64 units.

Magnitude:

Magnitude is a measure of the amount of energy released in an earthquake. It is often described using the Richter scale. To calculate the magnitude, measure the amplitude of the waves on the seismometer and correct for the distance between the recorder and the epicenter of the earthquake.

The magnitude of an Earthquake can be calculated by the following formula -

M = log ( I / S )

Where ,

M = magnitude

I = Intensity

S = standard earthquake intensity i.e. 10 ⁻⁴

Hence ,

To calculate the magnitude of the earthquake of intensity = 32.75 ,

The above formula is used as -

M = log ( I / S )

M = log ( 39.25/  10 ⁻⁴ )

M = log ( 39.25 × 10⁴ )

M = log ( 3925000 )

M = 5.59 ≈5.6

Hence , the value of magnitude is 5.6.

b) To calculate the magnitude of the earthquake of intensity = 32.75 ,

The above formula is used as -

M = log ( I / S )

M = log ( 4.4/  10 ⁻⁴ )

M = log ( 4.4 × 10⁴ )

M = log ( 44000 )

M = 4.64

Hence , the value of magnitude is 4.64.

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The radius of the cylinder is of 17 inches.

The volume of a cylinder of radius r and height h is given by the equation presented as follows:

V = πr²h.

The parameters for this problem are given as follows:

V = 289π in³, r = 1 in.

Hence the radius of the cylinder is obtained as follows:

r² = 289

\(r = \sqrt{289}\)

r = 17 inches.

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Answer:

Multiply 2 by 9, and then 2 by 11, and add it up all together. 18+22=40

Step-by-step explanation:

Fred owes $14,250 in credit card debt.

We must total up all of Fred's assets and liabilities, then subtract them to arrive at the amount he owes on his credit cards.

Let's figure it out:

Total Assets:

House (current value) = $105,900

Checking Account = $375

Vehicle (current value) = $13,500

Savings Account Value = $1,275

Total Liabilities:

Credit Card Debt = ?

Student Loans = $32,000

Personal Loans = $800

Total Assets - Total Liabilities = Net Worth

105,900 + 375 + 13,500 + 1,275 - (Credit Card Debt + 32,000 + 800) = 74,000

Solving for Credit card debt =

Credit Card Debt = 74,000 - 88,250

Credit Card Debt = -14,250 [The negative sign identifies it as a liability, as you can see.]

Therefore, Fred owes $14,250 in credit card debt.

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To find the distance that the Earth travels in slx days in its path around the sun, we need to calculate the circumference of the circular path followed by the Earth.

Given:

Radius of the Earth's path around the sun = 93 million miles

Number of days = slx (slx is not defined, so let's assume it means 365)

The circumference of a circle is given by the formula:

Circumference = 2πr

Substituting the radius value, we have:

Circumference = 2π * 93 million miles

To calculate the distance traveled by the Earth in slx days, we multiply the circumference by the fraction of slx days out of a year (365 days).

Distance traveled = (Circumference / 365) * slx

Calculating the distance traveled:

Distance traveled = (2π * 93 million miles / 365) * slx

Now, we can evaluate this expression using the given values.

Please provide the value of slx (365 or any other value) to proceed with the calculation.

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The volume of sphere in the diagram by entering the given radius into the volume formula is 36π cubic units.

Given that the volume of sphere is (4/3)×π×r³ and the radius is 3 units.

We want to the find the volume of sphere.

As we are given that the radius is 3 units and the volume of the sphere is (4/3)πr³.

So, firstly, we will substitute the value r=3 in the above formula, we get

V=(4/3)×π×(3)³

Now, we will simplify the above expression, we get

V=4π×9

V=36π cubic units

Hence, the volume of the sphere by entering the given radius into the volume formula for a sphere is 36π cubic units.

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(a) The equivalent capacitance of the combination is 17.0 µF.
(b) The potential difference across each capacitor is: C1 = 9V, C2 = 9V.
(c) The charge stored on each capacitor is: C1 = 54.0 µC, C2 = 99.0 µC.

(a) To find the equivalent capacitance \((C_eq)\) of capacitors connected in parallel, you can use the following formula:
\(C_eq = C1 + C2\)
\(C_eq = 6.00 \mu F + 11.0 \mu F\)
\(C_eq = 17.0 \mu F\)
(b) In a parallel connection, the potential difference (V) across each capacitor is equal to the voltage of the battey.

So,
\(V_C1 = V_{battery}  = 9V\)
\(V_{C2} = V_{battery}  = 9V\)
(c) To find the charge (Q) stored on each capacitor, you can use the following formula:
Q = C × V
For C1:
\(Q_{C1 } = C1 \times  V_{C1 }\)
\(Q_C1 = 6.00 \mu F \times  9V\)
Q_C1 = 54.0 µC
For C2:
\(Q_{C2}  = C2 \times  V_{C2 }\)
\(Q_C2 = 11.0 \mu F \times  9V\)
\(Q_{C2}  = 99.0 \mu C.\)

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(a) The equivalent capacitance of the combination is 17.0µF

(b) The potential difference across each capacitor is 9V.

(c) The charges stored on each capacitor are  54.0 µC and 99.0 µC

Given that

c₁ = 6.00 µF

c₂ = 11.0 µF

Battery = 9v

We have the equivalent capacitance of the combination to be

Equivalence = c₁ + c₂

So, we have

Equivalence = 6.00 µF + 11.0 µF

Evaluate

Equivalence = 17.0 µF

This is calculated as

Potential difference = battery

So, we have

Potential difference = 9v

This is calculated as

Q = C * V

So, we have

Q₁ = C₁ * V                           Q₂ = C₂ * V

= 6.00 * 9                                 = 11.0  * 9

= 54.0                                        = 99.0

Hence, the charges stored on each capacitor are  54.0 µC and 99.0 µC

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Answer:

Step-by-step explanation:

TU=8

WU=10

TX=5

TV=10

I THINK

Answer:

Step-by-step explanation:

\(\sqrt{(-3-4)^2+(-7-3)^2\)

\(\sqrt{(-7)^2+(-10)^2\)

\(\sqrt{49+100\)

\(\sqrt{149\)

The length of the other diagonal of the rhombus is 24 units.

A rhombus is a parallelogram with four equal sides. Since the sides of the rhombus are 12 units long, all the sides are equal in length. One of the angles of the rhombus measures 60 degrees.

In a rhombus, the diagonals bisect each other at right angles, dividing the rhombus into four congruent right-angled triangles. The angle between the two diagonals is 60 degrees, which means that each right-angled triangle in the rhombus has a 30-degree angle.

To find the length of the other diagonal, we can use trigonometry. In a right-angled triangle with a 30-degree angle, the ratio of the length of the side opposite the angle to the length of the hypotenuse is 1/2. In this case, the side opposite the 30-degree angle is half the length of the diagonal we are trying to find.

Let's denote the length of the other diagonal as "d". Using trigonometry, we can set up the following equation:

sin(30 degrees) = (d/2) / 12

Simplifying the equation, we have:

1/2 = (d/2) / 12

Cross-multiplying, we get:

d/2 = 12 * 1/2

d/2 = 6

Multiplying both sides by 2, we find:

d = 12

Therefore, the length of the other diagonal of the rhombus is 24 units.

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The average value of F(x, y, z) = z over the region bounded below by the xy-plane, on the sides by the sphere \(x^2 + y^2 + z^2 = 36\), and bounded above by the cone ϕ = (pi/3) is -ρ\(^4 / 2304.\)

To find the average value of the function F(x, y, z) = z over the given region, we need to compute the triple integral of F(x, y, z) over the region and divide it by the volume of the region.

The region is bounded below by the xy-plane, on the sides by the sphere \(x^2 + y^2 + z^2 = 36\), and bounded above by the cone φ = (π/3).

In spherical coordinates, the sphere can be represented as ρ = 6, and the cone can be represented as φ = (π/3).

To set up the integral, we need to determine the limits of integration for each variable. Since the region is symmetric with respect to the xy-plane, we can integrate over one-half of the region and multiply the result by 2.

Let's integrate over the region in spherical coordinates:

0 ≤ ρ ≤ 6

0 ≤ φ ≤ (π/3)

0 ≤ θ ≤ 2π

The integral to compute the average value is:

2 * ∫∫∫ F(ρsin(φ)cos(θ), ρsin(φ)sin(θ), ρcos(φ)) ρ\(^2 sin\)(φ) dρ dφ dθ

Now, we substitute F(x, y, z) = z into the integral:

2 * ∫∫∫ ρcos(φ) ρ\(^2sin\)(φ) dρ dφ dθ

Evaluate the innermost integral first:

∫[0 to 6] ρ\(^3cos\)(φ)sin(φ) dρ = (1/4)ρ\(^4cos\)(φ)sin(φ)

Now, integrate with respect to φ:

∫[0 to π/3] (1/4)ρ\(^4cos\)(φ)sin(φ) dφ = (1/4)ρ\(^4[-(cos\)(φ))\(^2]\) [0 to π/3]

                                                      = (1/4)ρ\(^4(-1/4)\)

                                                      = -ρ\(^4/16\)

Now, integrate with respect to θ:

∫[0 to 2π] -ρ\(^4/16\) dθ = -ρ\(^4/16\) * 2π

                               = -πρ\(^4/8\)

Finally, we divide this result by the volume of the region to find the average value:

Volume of the region = (1/2) * Volume of the sphere

                                   = (1/2) * (4/3) * π * (\(6^3\))

                                   = 288π

Average value = (-πρ\(^4/8\)) / (288π)

                        = -ρ\(^4 / (2304)\)

Therefore, the average value of F(x, y, z) = z over the given region           is -ρ\(^4 / 2304.\)

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Answer:

NULL ; TRUE

Step-by-step explanation:

The sampling distribution is on the assumption that the null hypothesis is true .

The null hypothesis is a general statement that states that there

is no relationship between two phenomenon's under

consideration or that there is no association between two groups.

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The sampling distribution is based on the assumption that the null hypothesis is TRUE.  

A null hypothesis is a general statement that something is. There is no relationship between the two phenomena under or consider that there is no relationship between the two groups.  

The sampling distribution is based on the assumption that the null hypothesis is TRUE.

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2/3 + 1/4 = 11/12

Fractions are very important in many areas such as math, physics, engineering, chemistry and many more, understanding how to add fractions with unlike denominators is a fundamental skill that will help you in many aspects of your life.

Adding fractions with unlike denominators can be a bit tricky, but with the right understanding and techniques, it's definitely doable.

When we add fractions with unlike denominators, we need to first find a common denominator. A common denominator is a number that is a multiple of both denominators. Once we have a common denominator, we can add the fractions as usual by adding the numerators and keeping the denominator the same.

Here are a few examples of adding fractions with unlike denominators:

2/3 + 1/4

We can find a common denominator by finding the least common multiple (LCM) of 3 and 4. The LCM of 3 and 4 is 12.

So, we can convert 2/3 to 8/12 by multiplying the numerator and denominator by 4.

We can convert 1/4 to 3/12 by multiplying the numerator and denominator by 3.

Now we can add the fractions by adding the numerators: 8/12 + 3/12 =

1/5 + 2/7

We can find a common denominator by finding the least common multiple (LCM) of 5 and 7. The LCM of 5 and 7 is 35.

So, we can convert 1/5 to 7/35 by multiplying the numerator and denominator by 7.

We can convert 2/7 to 10/35 by multiplying the numerator and denominator by 5.

So, we can convert 3/4 to 9/12 by multiplying the numerator and denominator by 3.

We can convert 1/3 to 4/12 by multiplying the numerator and denominator by 4.

Now we can add the fractions by adding the numerators: 9/12 + 4/12 = 13/12

So, 3/4 + 1/3 = 13/12

It's important to note that when adding fractions, it's also important to simplify the final result if possible.

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The value of a from -4√10 to 4√10 will make the trinomial x² + a = 40 factorable.

The equation we are provided with is a quadratic equation because it has the highest degree as 2.

x² + ax = 40

We can write is as,

x² + ax - 40 = 0

This equation will have two values of x for which the equality will hold true,

For real value of x. The discriminant of the equation will be positive.

= D>0

D = b² - 4tc.

Here,

t = 1,

b = a and

c = 40

= (a)² - 4(1)(40) > 0

= a² - 160 > 0

= a² > 160

= a > √160

Hence,

a > 4√10 and a > -4√10

So we know now, the value of a.

-4√10 < a < 4√10

Hence the value of a belongs to (-4√10,4√10)

Here the closed bracket "()" represent that the end values should not be counted.

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The given information consists of a series of equations involving variables b1, b3, and b4, as well as the constant values 8, 9, and 10. The objective is to calculate the value of b3.

To find the value of b3, we need to analyze the given equations and use algebraic techniques to solve for the unknown variable.
From the equations given, we can observe that b1 = 10, b4 = 9, and 62 = 8. These values provide fixed points of reference.
Next, we examine the equations involving b3. We have two equations: b3 - a = 15 and b3 - b = 10. However, there is no information provided about the values of a and b. Without additional information or constraints, we cannot determine the specific value of b3.
It is important to note that the solution to the problem depends on having all the necessary information or additional equations that can be used to solve for the unknowns. In this case, the lack of information about the values of a and b prevents us from calculating the exact value of b3.

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Answer:

15,000

Step-by-step explanation:

You can't round it upwards, so it remains the same.

It would just be 15,000 right?  

Step-by-step explanation: Because if its in the thousands place the 4 is less than the 7

2 to the power of 5 can be written as

\($2^{5}\) = 2 2 2 2 2 2 = 32.  Power is defined as a base number multiplied by its exponent, where the base number is the factor multiplied by itself and the exponent is the number of times the same base number is multiplied.

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Answer:

i just need points srry

Step-by-step explanation:

Answer:

Probability of drawing an odd number.

Number of odd numbers = 5

Number of numbers in the set = 10

So it's a 5 in 10 chance or 1 in 2 chance.

Probability of drawing a multiple of 3.

Multiples of 3 in the set = 3, 6 and 9 = 3 multiples of 3

Number of numbers in the set = 10

So it's a 3 in 10 chance

Answer:

Step-by-step explanation:

\(A=(5+2x)(7+2x)\\ \\ A=4x^2+24x+35\)

Answer: Yes

Step-by-step explanation:

Given

Kwasi earned \(\$60\) in babysitting

He spends 40% of the money in buying drinks

Money spend is given by

\(\Rightarrow 60\times 40\%\\\Rightarrow \$24\\\text{Remaining amount is}\\\Rightarrow 60-24=\$36\)

So, Kwasi has enough money left to buy a skateboard.

Answer:

7.834 × 10^-8

Step-by-step explanation:

= 7.834 × 10^-8

(scientific notation)

= 7.834e-8

(scientific e notation)

= 78.34 × 10^-9

(engineering notation)

(billionth; prefix nano- (n))

= 0.00000007834

(real number)

^ means the number after is exponent.