Find the critical t-value that corresponds to 90% confidence and n = 15. O A. 1.345 OB. 2.145 O c. 2.624 OD. 1.761

Answer:

oyebro  

Step-by-step explanation:

mira si ten soy sincero no c la respuesta solo necesito los puntos perdon bro

Answer:

a

Step-by-step explanation:

it LOST 950, which make the integer negative. in the second part of the answer, look for "earn", because to undo loss, you must gain.

Happy new years!

Answer:

Answer is A

ywwww

Step-by-step explanation:

The range in the average rate of change in temperature of the substance is from a low temperature of 1 F to a high of -11 F.

The conversion formula for a temperature that is expressed on the Celsius (°C) scale to its Fahrenheit (°F) ;

°F = (9/5 × °C) + 32.

Given function:

f(x)= -6 sin(7/3 x+ 1/6) -5

The function will be maximum at the 7/3 x +1/6= 3π/2

So, the maximum temperature will be

= -6 sin (3π/2) -5

= 6 -5

= 1 F

The function will be minimum at the 7/3 x +1/6= π/2

Therefore, the maximum temperature will be

= -6 sin (π/2) - 5

= -6 -5

= -11 F

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he mean of the zero-modified distribution with PM = 1/6 is 1.

The zero-modified distribution is a variation of the geometric distribution where, instead of counting the number of trials until the first success, we only count the number of trials starting from the second trial. In other words, if the first trial is a success (i.e., the event of interest occurs on the first trial), we ignore it and start counting from the second trial.

To find the mean of the zero-modified distribution with PM = 1/6, we need to modify the formula for the mean of the geometric distribution:

μ = 1/p

where p is the probability of success on each trial. Since we are only counting trials starting from the second one, the probability of success on each trial is no longer equal to the original probability of success, which we denote by q. Instead, the new probability of success is:

p* = q / (1 - q)

This is because, conditional on the event of interest not occurring on the first trial, the remaining trials follow the same distribution as in the original problem, with probability of success q.

We are given that the mean of the original geometric distribution is 2, so we have:

q = 1 / (1 + μ) = 1 / (1 + 2) = 1/3

Therefore, the new probability of success is:

p* = q / (1 - q) = (1/3) / (1 - 1/3) = 1/2

Finally, we can use the formula for the mean of the modified geometric distribution:

μ* = (1-p*) / p* = (1 - 1/2) / (1/2) = 1

So the mean of the zero-modified distribution with PM = 1/6 is 1.

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Particle moves with its position given by x= cos(2t) and y= sin (t), where positions are given in feet from the origin and time t is in seconds. The speed of the particle at any time t is v = \(\sqrt\)(4sin²(2t) + cos²(t)).

For the speed of the particle, we can calculate the magnitude of its velocity vector.

The velocity vector can be obtained by differentiating the position vector with respect to time.

We have the position of the particle as x = cos(2t) and y = sin(t), we can differentiate these equations to find the corresponding velocity components:

vx = dx/dt = -2sin(2t)

vy = dy/dt = cos(t)

The magnitude of the velocity vector (v) is given by the square root of the sum of the squares of its components:

\(\sqrt\)(vx² + vy²) = \(\sqrt\)((-2sin(2t))² + (cos(t))²)

Simplifying this expression:

v = \(\sqrt\)(4sin²(2t) + cos²(t))

This is the speed of the particle at any given time t.

Note that the speed is not constant but varies with time due to the periodic nature of the sine and cosine functions.

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Answer:

24 cm or h= 1/2 cm , b= 1 1/3 cm, l = 3cm

Step-by-step explanation:

3 x 4 x 2 = 12

Answer:

1. 2

2. 6

3. 15

4. 16

Step-by-step explanation:

:>

Step-by-step explanation:

to find a similar ratios, they should be multiplied by the same number.

let's start with 14 and 21 . 14 and 21 are the multiples of 7.

7×3 =21

so first right box is 3

to find first left box 14÷7= 2

to find 2nd left blank

3×3=9

so 2×3 =6

to find 3rd blank:

we know 2×5 =10

so 3×5 =15

to find last one:

we know 3×8 =24

so 2×8 =16

The series ∑[n=1 to ∞] \(8e^n\) / (3n(n+1)) is convergent.

To determine whether the series ∑[n=1 to ∞] \(8e^n\) / (3n(n+1)) is convergent or divergent, we can apply the ratio test.

Using the ratio test, we calculate the limit as n approaches infinity of the absolute value of the ratio of the (n+1)-th term to the n-th term:

lim(n→∞) |\((8e^(^n^+^1^) / (3(n+1)(n+2))) / (8e^n / (3n(n+1)))\)|

Simplifying the expression:

lim(n→∞) |\((8e^(^n^+^1^) * 3n(n+1)) / (8e^n * 3(n+1)(n+2))\)|

The common factors cancel out:

lim(n→∞) |e * n / (n+2)|

As n approaches infinity, the ratio tends to e, which is a finite non-zero value.

Since the ratio is a constant (e), which is less than 1, the series is convergent by the ratio test.

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Answer:

3.3

Step-by-step explanation:

The .2 is the tenths place, so you use the hundredths place (the 6A) to turn the .2 into a .3

Answer:

3.3

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

Let x be his speed at the morning, in miles per hour.

Then his speed after lunch was (x+10) mph.

2x + 3(x+10) = 220.

2x + 3x + 50 = 220

Out of 41 observations, 60% were successes. H0: p = 0. The correct option is a.2.974.

Based on the given information, we know that out of 41 observations, 60% were successes. This means that there were 24.6 successes (60% of 41).

The null hypothesis (H0) states that the true proportion of successes (p) is 0.49.

To test this hypothesis, we can use a one-sample proportion z-test. The formula for this test statistic is:

z = (p^ - p) / sqrt(p * (1 - p) / n)

where p^ is the sample proportion (in this case, 0.6), p is the hypothesized proportion (0.49), and n is the sample size (41).

Plugging in these values, we get:

z = (0.6 - 0.49) / sqrt(0.49 * 0.51 / 41)
z = 2.974

This means that our test statistic is 2.974.

To find the p-value associated with this test statistic, we can use a standard normal distribution table or calculator. The p-value for a z-score of 2.974 is approximately 0.0029.

Since this p-value is less than the typical alpha level of 0.05, we would reject the null hypothesis and conclude that there is sufficient evidence to suggest that the true proportion of successes is not 0.49.

Therefore, our answer is (a) 2.974.
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a) Numbers lying between 61^2 and 62^2 = 122

b) Numbers lying between 90^2 and 91^2 = 180

We have to find the numbers lying between the given numbers.

a) 61^2 and 62^2

61^2 = 3721

62^2 = 3844

We have to find the difference of the squares:

That is,

3844 – 3721 = 123

Numbers lying between 61^2 and 62^2 = 123 – 1 = 122

b) 90^2 and 91^2

90^2 = 8100

91^2 = 8281

We have to find the difference of the squares:

That is,

8281 – 8100 = 181

Numbers lying between 90^2 and 91^2 = 181 – 1 = 180

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Answer:

Every input can have only one output. But an output can have multiple inputs. Basically an x coordinate can have the same y coordinate as another ordered pair but not the same x coordinate. This is why d) does not represent a function.

Step-by-step explanation:

(4,-2)

(4,2)

4 is mentioned twice and every input( x value) can have only one output ( y-value)

By completing squares, we will see that the radius is 12 units and the center is (-8, 1).

The circle of center (x₁, y₁) and radius r is written as:

(x - x₁)² + (y - y₁)² = r²

Now we go to our equation:

x² + 16x + 64 + y² - 2y + 1 = 144

Now we need to complete squares:

(a + b)² = a² + 2ab + b²

Then we can rewrite:

(x² + 2*8*x + 8*8) + (y² - 2y + 1) = 12²

(x + 8)² + (y - 1)² = 12²

So the center is the point (-8, 1) and the radius is 12 units.

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hello

30/42 = x /49

42 x = 1 470

x =  35

30 /42 =  40/ 40 + y

30 y + 1200 = 1 680

30 y = 1 680 - 1 200

30 y = 480

y =  16

Answer:

x = 35

y = 16

Step-by-step explanation:

Both the triangles are similar by AA test of similarity.

\( \implies \: \frac{30}{30 + 12} = \frac{40}{40 + y} = \frac{x}{49} \\ \\ \implies \: \frac{30}{42} = \frac{40}{40 + y} = \frac{x}{49} \\ \\ \implies \: \frac{5}{7} = \frac{40}{40 + y} = \frac{x}{49} \\ \\ \implies \: \frac{5}{7} = \frac{x}{49} \\ \\ \implies \: x = \frac{5 \times 49}{7} \\ \\ \implies \huge \red {\boxed{ \: x = 35}}\\ \\ \implies \: \frac{5}{7} = \frac{40}{40 + y} \\ \\ 5(40 + y) = 280 \\ \\ \implies \: 200 + 5y = 280 \\ \\ \implies \: 5y = 280 - 200 \\ \\ \implies \: 5y = 80 \\ \\ \implies \: y = \frac{80}{5} \\ \\ \implies \: \huge { \orange{ \boxed{ y = 16}}}\)

x = -1

y = 3

2x + y = 1 (eq no 1)

3x - y = -6 (eq no 2)

solve eq no 1

y = 1 - 2x (eq no 3)

enter eq no 3 into eq no 2

3x - ( 1 - 2x ) = -6

3x - 1 + 2x = -6

5x = -5

x = -5/5

x = -1

enter x = -1 into eq no 1

2 (-1) + y = 1

-2 + y = 1

y = 3

Answer:

A. (-1,3)

Hope this helps :D

It will take approximately 95.53 seconds for the partial pressure of NH₃ to decrease from 0.100 atm to 0.00625 atm.

To solve this problem, we can use the first-order reaction equation: ln(P₁/P₂) = -kt,

where P₁ and P₂ are the initial and final pressures, respectively, k is the rate constant, and t is the time.

First, let's find the rate constant (k) using the half-life (t₁/₂) given. The half-life formula for a first-order reaction is: t₁/₂ = ln(2)/k,

Substituting the given half-life (t₁/₂ = 200s), we can solve for k: 200s = ln(2)/k. Solving for k: k = ln(2)/200s ≈ 0.003465 s⁻¹.

Now we can use this rate constant to find the time (t) required for the partial pressure of NH₃ to decrease from 0.100 atm to 0.00625 atm. Rearranging the first-order reaction equation: ln(P₁/P₂) = -kt,

we can substitute the values: ln(0.100/0.00625) = -0.003465 s⁻¹ * t.

Solving for t: t = ln(0.100/0.00625) / -0.003465 s⁻¹.

Evaluating this expression: t ≈ 95.53 seconds.

Therefore, it will take approximately 95.53 seconds for the partial pressure of NH₃ to decrease from 0.100 atm to 0.00625 atm.

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Answer:

∠FDE or ∠GDA

Step-by-step explanation:

The adjacent angle refers to the angle which lies right next to an angle, and the sum of the angles is 180, meaning they are supplementary.

Here, in this diagram, there are 2 adjacent angles for ∠FDG :

A system of linear equations is created when two or more linear equations are put together.

Systems involving two linear equations in two unknowns will be the main topic of discussion in this section. In a subsequent chapter of this book, we will solve larger systems of equations.

Below is an illustration of a system of two linear equations. A brace is used to demonstrate how the two equations are combined to form a system of equations.

x-2y=6

2x+y=7

A two-variable linear equation like 2x+y=7 has an endless number of solutions. It has a linear graph.

Always keep in mind that every point on the line represents a solution to the problem, and vice versa.

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Answer:

Step-by-step explanation:

Consider the line y=4/3x + 3

-

Find the equation of the line that is perpendicular to this line and passes through the point (-9, -5)

Find the equation of the line that is parallel to this line and passes t

The two numbers that satisfy the given conditions are -2 and 3. When multiplied, they equal -6, and when added, they equal 1.

To find two numbers that, when multiplied, equal -6 and when added, equal 1, we can set up a quadratic equation.

Assume that x and y are the two numbers.

We can write two equations based on the given conditions:

x * y = -6

x + y = 1

We can use the substitution or elimination method to resolve this system of equations.

Let's solve it using the substitution method.

From equation 2), we can express one variable in terms of the other.

Let's solve for x:

x = 1 - y

Now change x in equation 1 to this expression:

(1 - y) * y = -6

Expanding the equation:

y - \(y^2\) = -6

Rearranging the equation to form a quadratic equation:

\(y^2\) - y - 6 = 0

Now we can factorize or use the quadratic formula to solve for y.

Factoring the quadratic equation gives us:

(y - 3)(y + 2) = 0

Setting each factor equal to zero:

\(y - 3 = 0 - > y = 3\\ y + 2 = 0 - > y = -2\)

So, we have two possible values for y: 3 and -2.

Substituting these values back into equation 2) to find the corresponding values of x, we get:

For \(y = 3: x = 1 - 3 = -2\)

For \(y = -2: x = 1 - (-2) = 3\)

Therefore, the two numbers that satisfy the given conditions are -2 and 3.

When multiplied, they equal -6, and when added, they equal 1.

In summary, the two numbers that satisfy the conditions are -2 and 3.

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The given points, only the point (4, -9, -8) lies on line 1.

To determine whether certain points lie on the line 1, which is perpendicular to the plane x - 2y - 4z = 5 and contains the point (2, -5, 0), we can check if the coordinates of those points satisfy the equation of the line.

The direction vector of the line 1 is perpendicular to the plane and can be determined from the coefficients of x, y, and z in the plane equation. In this case, the direction vector of the line is (1, -2, -4).

Now, we can write the parametric equation of the line l as:

x = 2 + t * 1

y = -5 + t * (-2)

z = 0 + t * (-4)

To check if a point (x₀, y₀, z₀) lies on the line 1, we need to find a value of t that satisfies the parametric equations.

Let's consider the following points and determine if they lie on line 1:

Point (3, -6, -4)

To check if this point lies on line 1, we substitute the coordinates (x₀, y₀, z₀) = (3, -6, -4) into the parametric equations:

x₀ = 2 + t * 1 --> 3 = 2 + t --> t = 1

y₀ = -5 + t * (-2) --> -6 = -5 - 2 --> t = -1

z₀ = 0 + t * (-4) --> -4 = 0 - 4t --> t = 1

The value of t is not consistent across all equations, so the point (3, -6, -4) does not lie on line 1.

Point (2, -5, 0)

This point is given as the point that line 1 contains. Therefore, it lies on line 1.

Point (4, -9, -8)

To check if this point lies on line 1, we substitute the coordinates (x₀, y₀, z₀) = (4, -9, -8) into the parametric equations:

x₀ = 2 + t * 1 --> 4 = 2 + t --> t = 2

y₀ = -5 + t * (-2) --> -9 = -5 - 2t --> t = 2

z₀ = 0 + t * (-4) --> -8 = 0 - 8t --> t = 1

The value of t is consistent across all equations, so the point (4, -9, -8) lies on line 1.

Therefore, among the given points, only the point (4, -9, -8) lies on line 1.

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The complete question is:

Let l be the line perpendicular to the plane x - 2y - 4z = 5 and containing the point (2, -5, 0). determine whether the following points lie on line l.

Answer:

$541.67 per month

Step-by-step explanation:

Tuition and other expenses = $8,250 per semester.

There are two semesters in a year

She has 4 years to spend

Total semester=4years*2semesters

=8 semesters

4 years in college which is a total of 8 semesters.

Total Tuition and other expenses = $8,250 * 8

= $66,000

She needs a total of $66,00 to complete her college

Assistance from parents=$15,000

Financial aid(per semester)=$4750

Total financial aid=$38,000

Total assistance=

Assistance from parents+ financial aid

=$15000+$38,000

=$53,000

Total savings=Total amount needed - Total assistance

=$66,000 - $53,000

=$13,000

She needs to save $13,000 in two years

There are 12 months in one year

2 years=2*12=24 months

Monthly savings=Total savings/24 months

=$13,000/24

=$541.666666

To the nearest cent

=$541.67

Answer: $541.67

Step-by-step explanation: Got it right on TTM.

Answer:

The given graph is not a direct variation.

Step-by-step explanation:

A direct variation occurs when the rate of change between any two points on a graph is always the same. In this sense, direct variation only occurs when a graph is linear. The given graph is parabolic; its equation is \(y = x^2\). Therefore, it does not exhibit direct variation, as the slope between consecutive points continually changes.

If you want to prove this claim, show that the slope changes between the given points: the rate of change from (2,4) to (3,9) is greater than the rate of change from (0,0) to (2,4).

The possible sources of inaccuracy that could have an impact on your results are -

While conducting a scientific experiment, numerous errors—either systematic or random—could happen.

Thus, more measuring is done when the bias is smaller and more measuring is done when the uncertainty is smaller.

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The probability that Alex takes out three red apples is 1/30.

The probability that Alex takes out one green apple and two red apples is 1/10.

The probability that Alex takes out three red apples = (number of red apples / total number of apples) x (number of red apples - 1 / total number of apples - 1) x (number of red apples - 2 / total number of apples - 2)

4/10 x 3/9 x 2 /8 = 1 / 30

The probability that Alex takes out one green apple and two red apples = (number of green apples / total number of apples) x (number of red apples / total number of apples - 1) x (number of red apples - 1 / total number of apples - 2)

6/10 x 4/9 x 3/8 = 1 / 10

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To determine which offer will provide a greater total income after 5 years, we need to calculate the total amount of income earned from each offer over the 5-year period.

For Offer A:
Annual interest rate = 5%
Principal amount = $10,000
Time period = 5 years

Total amount earned = Principal x (1 + Annual interest rate)^Time period
= $10,000 x (1 + 0.05)^5
= $12,762.82

Total income earned = Total amount earned - Principal
= $12,762.82 - $10,000
= $2,762.82

For Offer B:
Annual interest rate = 4%
Principal amount = $12,000
Time period = 5 years

Total amount earned = Principal x (1 + Annual interest rate)^Time period
= $12,000 x (1 + 0.04)^5
= $14,612.52

Total income earned = Total amount earned - Principal
= $14,612.52 - $12,000
= $2,612.52

Therefore, Offer B will provide a greater total income after 5 years, with a total income earned of $2,612.52, compared to Offer A's total income earned of $2,762.82.

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The coordinates of the midpoint of EF is equal to \((\frac{xE +xF}{2} , \frac{yE + yF}{2} )\)

What is coordinates ?

A pair of numbers that use the separations between the two reference axes to define the location of a point on a coordinate plane. usually represented by the x- and y-values, respectively, (x, y).

In geometry, a coordinate system is a method for determining how to place points or other geometrical objects on a manifold, such Euclidean space, uniquely using one or more numbers, or coordinates.

Any one of a group of integers that are used to define where a point is on a surface, on a line, or in space. coordinates in terms of latitude and longitude.

The formula to calculate the midpoint between two points is equal to

\(M = (\frac{x_{1} + x_{2} }{2} , \frac{y_{1} + y_{2} }{2} )\)

In this problem we have

(x1 , y1) = (xE , yE)

(x2 , y2) = (xF , yF)

Substitute the value in the formula

we get ;

\(M = (\frac{xE +xF}{2} , \frac{yE + yF}{2} )\)

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