Find the coordinates of the midpoint of a segment with the given endpoints:
J4, ) and F(5, -2).

After making payments for 15 years, the amount still owed on the mortgage would be approximately $145052.36.

To determine how much will still be owed after making payments for 15 years, we can use the formula for the remaining balance on a mortgage:

Remaining balance = P ((1 + r)ⁿ - (1 + r)ᵇ) / ((1 + r)ⁿ - 1)

where:

P = the initial loan amount (in this case, $219,000)

r = the monthly interest rate (which is the annual interest rate divided by 12)

n = the total number of monthly payments (which is 30 years times 12 months per year, or 360 months)

b = the number of monthly payments made so far (which is 15 years times 12 months per year, or 180 months)

First, we need to calculate the monthly interest rate:

r = 4.5% / 12 = 0.00375 = 0.375%

Next, we can plug in the values to get:

Remaining balance = $219,000 ((1 + 0.00375)³⁶⁰- (1 + 0.00375)¹⁸⁰) / ((1 + 0.00375)³⁶⁰ - 1)

= $145052.36

To learn more about loan calculations;

https://brainly.com/question/28244942

#SPJ1

In mathematics, a sequence is an ordered list of elements, often denoted by brackets or parentheses.

The term "a sequence of length n" refers to a sequence that contains a specific number of elements, where the number of elements is denoted by "n."

When the domain of a function is the set of natural numbers (N), it is called an infinite sequence. An infinite sequence can be thought of as an ordered list that continues indefinitely.

Read more on sequences here https://brainly.com/question/6561461

#SPJ1

Answer:

the EOQ cost function \(\mathbf{g(Q)= \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}}\)

Step-by-step explanation:

Given that:

\(g(Q) = \dfrac{h}{2 \lambda Q} \begin {pmatrix} Q- \sqrt{\dfrac{2 K \lambda}{h}} \end {pmatrix}^2 + \sqrt{\dfrac{2 Kh}{\lambda}}\)

Total cost = Purchase Cost + Ordering Cost + Holding Cost

i.e

T = \(P \lambda + h \dfrac{Q}{2}+\dfrac{\lambda K}{Q}\)

By differentiating with respect to Q and equating to zero, we have:

\(0 = 0 +\dfrac{h}{2}- \dfrac{\lambda K}{Q^2}\)

\(Q* = \sqrt{\dfrac{2 k \lambda}{h}}\)

Now;

\(T = P \lambda + \dfrac{h}{2Q}(Q-Q^*)^2 + hQ^*\)

\(T = \dfrac{h}{2Q}(Q- \sqrt{\dfrac{2 \lambda K}{h}})^2 + \sqrt{2 hK \lambda } + P \lambda\)

\((\dfrac{T - P \lambda}{\lambda }) = \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}\)

Therefore:

the EOQ cost function \(\mathbf{g(Q)= \dfrac{h}{2 \lambda Q}( Q- \sqrt{\dfrac{2 \lambda K }{2}})^2 + \sqrt{\dfrac{2 h K}{\lambda}}}\)

Answer:

Step-by-step explanation:

Since a total of 96 people have entered the store and 32 of them have bought 2 or more items, it is clear that the next person entering the store has a probability of 32/96 or 1/3 that he/she will buy 2 or more items.

From the given price function, we have;

(a) \( \frac{dp}{dq} = - 13\)

(b) The point elasticity of demand is 0.0256; inelastic demand

(c) $46.6

(d) Increase

a. The given function is presented as follows;

\(p = 50 \times (151 - q) ^{0.02 \times \sqrt{q + 19} } \)

Differentiating the above function with a graphing calculator and setting q = 150 gives;

\( \frac{dp}{dq} = - 13\)

b. The point elasticity of demand is given by the formula;

\( e \: = \frac{dq}{dp} \times \frac{p}{q} \)

When q = 150, we have;

P = 50

Which gives;

\(e \: = \frac{1}{13} \times \frac{50}{150} = 0.0256\)

The point elasticity of demand, E = 0.0256

c. If the quantity demanded decreases from 150 to 140 units, we have;

\(0.0256 \: = \frac{1}{13} \times \frac{p}{140} = \)

Which gives;

p = 46.6

d. Given that increase in price, from 46.6 to 50, increases the quantity demanded from 140 to 150, therefore;

R = p × q

Learn more about elasticity of demand here;

https://brainly.com/question/19141990

The the length of LJ is approximately 3.5.OptionD) is correct.

To find the length of LJ, we can use the Law of Sines, which states that the ratio of the length of a side of a triangle to the sine of the angle opposite that side is the same for all sides of the triangle.

Let's denote the length of JL as x. Then, we can set up the following proportion:

sin(23°) / LJ = sin(89°) / KL

where KL is given as 9.

We can simplify this proportion by using the fact that sin(89°) = cos(1°) (since the sine of the complement of an angle is equal to the cosine of the angle), and by using a calculator to find the values of sin(23°) and cos(1°):

0.3919 / LJ = 0.0175 / 9

Multiplying both sides by x and then dividing both sides by 0.0175, we get:

LJ = 0.3919*9/ 0.0175

x ≈ 3.5

Therefore, the length of LJ is approximately 3.5.OptionD) is correct.

To know more about triangle visit:

brainly.com/question/2773823

#SPJ1

\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,0){\vector(1,0){4}}\put(0,0){\vector(0,1){4}}\put(0,0){\vector(2,2){4}}\end{picture}\)

View it from web.

Answer:

-6 < -1 or -1 > -6

How do you know?

Well since the starting point of it is:

-6

And it goes to -1.

Which is also 5 digits away.

-1 is the closest to 0, How?

-1 is one digit away from 0.

-6 is six digits away form 0.

Therefore -6 being further.

Hope this helps and have a lovely day!

The art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper for proper distribution.

To determine the largest number of identical kits the art teacher can make using all the crayons and drawing paper, we need to find the greatest common divisor (GCD) of the quantities.

The GCD represents the largest number that can divide all the quantities without leaving a remainder.

The GCD of the quantities of crayons can be found by considering the prime factorization:

72 = 2³ × 3²

48 = 2⁴ × 3

48 = 2⁴ × 3

48 = 2⁴ × 3

The GCD of the crayons is 2³ × 3 , which is 24.

Now, we need to find the GCD of the quantity of drawing paper:

120 = 2³ × 3 × 5

The GCD of the drawing paper is also 2³ × 3 , which is 24.

Since the GCD of both the crayons and drawing paper is 24, the art teacher can make a maximum of 24 identical kits using all the crayons and drawing paper.

Each kit would contain an equal distribution of crayons and drawing paper.

Learn more about distribution here:

brainly.com/question/30034780

#SPJ1

Answer:

\( \frac{1}{2} \times 6 = 3 \\ \)

Yep

Answer:

(10)(3/5)=6

The parentheses is multiplication

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

10÷2=5

So you would divide your answer by 2

7×5 is 35 also btw

7×10 is 70

Step-by-step explanation:

a) 24÷12= 2 each person gets 2 cereal bar

b) 24÷6= 4 each person gets 4

c )0 There is no one there

d) Zero is undefined

Answer:

Since \(\sqrt{1} \\\) = 1 and \(\sqrt{4}\) = 2, it is known that \(\sqrt{2}\) is between 1 and 2.

Answer:

Since the square root of \(\sqrt1\\\) = 1 and the square \(\sqrt\\ 4\) = 2 it is known that \(\sqrt{2}\) is between 1 and 4

Step-by-step explanation:

Since you are trying to get the square root of 2, you have to find the two perfect squares that are closer to the square root of 2. These are 1 (1) and 4 (2).

Considering the vertex of the quadratic equation, it is found that the value of b is of b = 3.

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

\((x_v, y_v)\)

In which:

The axis of symmetry is of \(x = x_v\). In this problem, we have that a = 0.25 and x_v = 6, hence:

b/2a = 6.

b/0.5 = 6

b = 6 x 0.5

b = 3.

The value of b is of b = 3.

More can be learned about the vertex of a quadratic equation at https://brainly.com/question/24737967

#SPJ1

Point H is the ortho-center of our given triangle and option c is the correct choice.

We have been given an image of a triangle. We are asked to find the term that describes point H.

We can see that point H is the point, where, all the altitudes of our given triangle EFF are intersecting.

We know that ortho-center of a triangle is the point, where all altitudes of triangle intersect. Therefore, point H is the ortho-center of our given triangle and option c is the correct choice.

for such more question on ortho-center

https://brainly.com/question/7552525

#SPJ8

Answer:

67.52

Step-by-step explanation:

281.4 divided by 15 equals 18.76

15+15=30

18.76+18.7=37.52

30+37.52=67.52

Answer:

If we start facing South and turn clockwise to face east, then we have to make 3/4 of a revolution.

Helpful?

Answer:

Step-by-step explanation:

x^2 + 20^2 = 25^2

x^2 + 400 = 625

625-400=225

sqrt(225) = 15

x = 15

Given:

Required: Equivalent in degree

Solution:

Let the equivalent of

be represented as X.

Thus,

But

This implies that

By cross-multiplication, we have

Divide both sides by the coefficient of X.

The coefficient of X is π.

Thus,

Hence, the equivalent of

is 135°

9514 1404 393

Answer:

  C(3, -2)

  D(1, 7)

Step-by-step explanation:

It looks like your tool will do the rotation for you and give you the coordinates. The image(s) should look like the attached.

Answer: 81.25

Step-by-step explanation:

Answer:

Armando lost 65 coins each level.

Step-by-step explanation:

Given information,

→ Armando lost 975 coins playing his favorite video game.

→ He lost the same number of coins in each of the 15 levels he played.

Forming the equation,

→ 15x = 975

Now required value of x will be,

→ 15x = 975

→ x = 975/15

→ [ x = 65 ]

Hence, he lost 65 coins each level.

Answer:13/24

Step-by-step explanation:

Answer:

26/48 is the answer

Step-by-step explanation:

Because 3/8 equals 18/48 and 1/6 equals 8/48 so add 18/48 + 8/48 to get 26/48.

Answer:

Option A is the right answer mate...

Answer:

The total spent on each student was $24.62. That is the pass and lunch

Step-by-step explanation:

$688.95÷45= $15.31 each oass

$391.02÷42=$9.31

15.31+931=$24.62

Each number in the sum is even, so we can remove a factor of 2.

2 + 4 + 6 + 8 + ... + 78 + 80 = 2 (1 + 2 + 3 + 4 + ... + 39 + 40)

Use whatever technique you used in (a) and (b) to compute the sum

1 + 2 + 3 + 4 + ... + 39 + 40

With Gauss's method, for instance, we have

S = 1 + 2 + 3 + ... + 38 + 39 + 40

S = 40 + 39 + 38 + ... + 3 + 2 + 1

2S = (1 + 40) + (2 + 39) + ... + (39 + 2) + (40 + 1) = 40×41

S = 20×21 = 420

Then the sum you want is 2×420 = 840.