Answer:
area = 148.72 ft^2
Step-by-step explanation:
height =sin 55 x 16.5
height =0.8192 x 16.5
height = 13.52
area=0.5 x base x height
area = 0.5 x 22 x 13.52
area = 148.72 ft^2
Answer:
\(16\frac{1}{2}=16.5\)
S is the area of this triangle, we have:
\(S=\frac{1}{2}16,5. 22.sin55\) = 148,676
Step-by-step explanation:
Which set is closed under subtraction?
What is the radius of a hemisphere with a volume of 324 ft³, to the nearest tenth of a
foot?
SOND
Answer:the radius of the hemisphere with a volume of 324 ft³ is approximately 6.3 feet (to the nearest tenth).
Step-by-step explanation:
The formula for the volume of a hemisphere is:
V = (2/3) × π × r³, where V is the volume and r is the radius of the hemisphere.
We have been given the volume of the hemisphere as 324 ft³, so we can substitute this into the formula:324 = (2/3) × π × r³
To find the radius r, we need to solve for it. Dividing both sides by (2/3) × π gives:r³ = (324 / ((2/3) × π))r³ = (324 × 3) / (2 × π)r³ = 486 / π
Taking the cube root of both sides gives:r = (486 / π)^(1/3)
Using a calculator to evaluate this expression, we get:r ≈ 6.3
is 0.59 a repeating decimal
Answer:
No
Step-by-step explanation:
using the soil textural triangle and the example soil density gradient below, the soil type depicted is a _______________________.
Using the soil textural triangle and the example soil density gradient, we can determine the soil type depicted by analyzing the relative proportions of sand, silt, and clay in the soil sample.
The soil textural triangle is a graphical representation of soil types based on their percentages of sand, silt, and clay. By locating the point where the percentages of sand, silt, and clay intersect, we can identify the soil type.
The soil density gradient provides information about the distribution of particle sizes within the soil profile. It describes how the percentage of different-sized particles changes with depth. However, the specific values of the density gradient are not provided in the question.
To accurately determine the soil type depicted, we would need the exact values of sand, silt, and clay percentages as well as the density gradient information. Without this information, it is not possible to provide a definitive answer regarding the soil type.
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Suppose that 50% of the watches produced by a certain factory are defective. A store buys a box with 400 watches produced by this factory. Assume that this is a random sample.
If 50% of the watches produced by the factory are defective, and the store buys a random sample of 400 watches, we can expect approximately 200 of those watches to be defective.
Considering that 50% of the watches produced by the factory are defective, and assuming that the store's purchase of 400 watches represents a random sample, we can expect around 200 of those watches to be defective.
This estimation is based on the assumption that the proportion of defective watches in the sample aligns with the overall proportion in the factory's production. it's important to note that there might be some variability, and the actual number of defective watches in the sample could differ slightly from the expected 200.
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what is the total utility at 4 units and the marginal utility when jack goes from consuming three pop tarts to four pop tarts?
The total utility of 4 units is 50 and the marginal utility is 5
Total utility is the sum of satisfaction that is derived from the consumption of units of a good or service.
Total utility can be determined by adding the marginal utility of each unit that is consumed.
Total utility of consuming 4 units = marginal utility of the first unit + marginal utility of the second unit + marginal utility of the third unit + marginal utility of the fourth unit
20 + 15 + 10 + 5 = 50
Marginal utility is the change in total utility when consumption increases by unit. Marginal utility is 5
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* Let D and T be sets, and let X:D→T be a function from D to T. Let T be a σ-algebra of subsets of T, and define D={X−1(B):B∈T}, the collection of subsets A⊂D of the form A=X−1(B) for B∈T. (a) ∗ Show directly that D is a σ-algebra of subsets of D. [3 marks] Now let T=R and T=B, the Borel σ-algebra. Let Ω=D, let F be a σ-algebra of subsets of Ω, and let P be a probability measure on (Ω,F). (a) * Suppose that X is a random variable on the probability space (Ω,F,P). Show that D⊂F.
The set D, defined as D = {X^(-1)(B) : B ∈ T}, is a σ-algebra of subsets of D. If X is a random variable on a probability space (Ω, F, P), then D is a subset of the σ-algebra F.
To show that D is a σ-algebra of subsets of D, we need to verify three conditions:
1. D is non-empty: Since X is a function from D to T, the pre-image of the entire space T is D itself, so D is non-empty.
2. D is closed under complementation: For any set A ∈ D, there exists a corresponding set B ∈ T such that A = X^(-1)(B). Taking the complement of A, we have A^c = X^(-1)(B^c), where B^c is the complement of B in T. Since T is a σ-algebra, B^c ∈ T, and therefore A^c ∈ D.
3. D is closed under countable unions: Let {A_n} be a countable collection of sets in D, with corresponding sets {B_n} in T such that A_n = X^(-1)(B_n) for each n. Taking the union of all the A_n's, we have ∪A_n = X^(-1)(∪B_n), where ∪B_n is the union of all the B_n's in T. Since T is a σ-algebra, ∪B_n ∈ T, and therefore ∪A_n ∈ D.
Now, if X is a random variable on the probability space (Ω, F, P), it means that X is measurable with respect to the σ-algebra F. Since D is a σ-algebra of subsets of D, and X^(-1)(B) ∈ D for any B ∈ T, we can conclude that D ⊂ F.
Therefore, D is a subset of the σ-algebra F when X is a random variable on the probability space (Ω, F, P).
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Using complete sentences, explain how to find the product of 6 x 4.3 by applying the distributive property. Make sure to
include the product in your explanation.
Math
The product of 6 x 4.3 using the distributive property, first break down 4.3 into two parts: 4 and 0.3. Now, distribute the 6 to both parts: (6 x 4) + (6 x 0.3). Multiply each part separately: 24 + 1.8. Finally, add the results together: 24 + 1.8 = 25.8. Therefore, the product of 6 x 4.3 is 25.8.
To find the product of 6 x 4.3 by applying the distributive property, we need to break down 6 into two smaller factors that are easier to work with. One way to do this is to think of 6 as 5 + 1. So we can rewrite 6 x 4.3 as (5 + 1) x 4.3.
Now we can use the distributive property, which states that a x (b + c) = a x b + a x c. Applying this to our expression, we get:
(5 + 1) x 4.3 = 5 x 4.3 + 1 x 4.3
Simplifying this, we get:
(5 + 1) x 4.3 = 21.5 + 4.3
Therefore, the product of 6 x 4.3 using the distributive property is 25.8.
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Please help asap!!!
1)
5 - h -18____ = 25
2)
- 15 + 18_ z = - 23
3)
27 + r 2_____ = - 3
4)
26 + n -10______ = 18
5)
19 - b 15_____ = - 17
6)
f - 15 -9_____ = - 13
7)
v + 13 -11_____ = - 20
8)
- 16 - 8d = 10
9)
x - 2 19____ = 21
Answer:
1 2 3 4 5 6 7 8 9 the answer is 5
Triangle A'B'C' is the result of dilating ABC about point P by a scale factor of 3. Determine whether each claim about the properties of AABC about point P by a scale factor of 3
Dilating triangle ABC about point P by a scale factor of 3 results in a triangle A'B'C' with side lengths 3 times larger, the same angles, and an area 9 times larger than the original triangle.
Each claim about the properties of triangle A'B'C' (resulting from dilating triangle ABC about point P by a scale factor of 3) is true or not.
Claim 1: The side lengths of triangle A'B'C' are 3 times the side lengths of triangle ABC.
Answer: True.
When dilating a triangle by a scale factor of 3, the side lengths will be multiplied by that scale factor. S
o, if the side lengths of triangle ABC are a, b, and c, the side lengths of triangle A'B'C' will be 3a, 3b, and 3c.
Claim 2: The angles of triangle A'B'C' are the same as the angles of triangle ABC.
Answer: True. Dilations do not affect the angles of the shape, only the side lengths.
Therefore, the angles in both triangles will remain the same.
Claim 3: The area of triangle A'B'C' is 3 times the area of triangle ABC.
Answer: False. The area of triangle A'B'C' is actually 9 times the area of triangle ABC.
When a triangle is dilated by a scale factor of 3, the area is multiplied by the square of that scale factor (3^2 = 9).
In summary, dilating triangle ABC about point P by a scale factor of 3 results in a triangle A'B'C' with side lengths 3 times larger, the same angles, and an area 9 times larger than the original triangle.
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solve 7/t+8=6v-8u for t
Answer:
t=7/(6v-8u-8)
Step-by-step explanation:
Isolate t
7/t=6v-8u-8
7/6v-8u-8=6v-8u-8*t/6v-8u-8
t=7/(6v-8u-8)
You can simplify it
t=7/2(3v-4u-4)
Review the graph of 2x – 7 – 3 ≥ y.
On a coordinate plane, a curve goes through (0, negative 3) and increases up through (8.5, 0) and (10, 5). Everything below the line is shaded and is labeled 2 Superscript x minus 7 Baseline minus 3 greater-than-or-equal-to y.
What is the least integer value that satisfies the inequality 2x – 7 ≥ 3?
7
8
9
10
The least integer value that satisfies the inequality \(2^{x-7} - 3\) ≥ y is 7.
What is Exponential function?
Exponential function, as its name suggests, involves exponents. But note that, an exponential function has a constant as its base and a variable as its exponent but not the other way round.
Here, In the given function
Least possible value of 2ˣ⁻⁷ is 1
2ˣ⁻⁷ = 2⁰
On comparing both sides, we get
x-7 = 0
x = 7
Thus, The least integer value that satisfies the inequality 2ˣ⁻⁷-3≥ y is 7.
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Answer:
7
Step-by-step explanation:
edg 2022
4 2/5 + k = 3 2/11
What is K??
Answer:
K is -1 12/55
Step-by-step explanation:
You take 3 2/11 minus 4 2/5 to get -1 12/55. If you want to make sure, you add 4 2/5 and -1 12/55. The answer will be 3 2/11
The ratio of the measures of the sides of a triangle is 2:7:6. If the perimeter of the triangle is
345 yards, find the measures
of all of the sides.
Shortest Side =
Middle Side =
Longest Side =
Answer:
Shortest Side = 46
Middle Side = 161
Longest Side = 138
Step-by-step explanation:
2+7+6=15
345/15=23
Do 23 times all of the numbers in the ratio.
23*2=46
23*7=161
23*6=138
You can text 44 words in 1 minute. Write a proportion to help you find
how many words you can type in 4 minutes. Which choice sets up the
proportion correctly and has the correct solution?
Answer:
176 words
Step-by-step explanation:
1) well we want to find the amount of words we'd be able to type in 4 minutes. so, what i did was:
44 words = x
1 minutes = 4 minutes
2) now look at how i set up the proportion, notice how i left a variable of x for the value i didn't know.
3) we also know that 1 times 4 is 4, so it'd also make sense to also multiply the numerator by 4 too!!
4) multiplying 44 by 4 would get us our answer which is 176
im not the best at math but i this explanation helped <33
Find the AGI and taxable income:
$23,670 and $12,400
$12,400 and $11,270
$11,270 and $23,670
$23,670 and $11,270
The AGI and taxable income is $23,670 and $11,270
How to calculate AGI(Adjusted gross income) ?
The AGI calculation can be done as,
It is determined by subtracting specified deductions, or "adjustments," that you are qualified to claim from the total income you report that is subject to income tax, such as wages from a job or self-employment, dividends, and interest from a bank account.Before you take the standard or itemized deductions, which you record in later sections of your tax return, your AGI is computed.We have given that,
Gross income = $23670
1 Exemption = $12400
Adjustment = 0
Deduction = 0
Find AGI and Taxable income
AGI = Adjusted gross income
we know,
AGI = Total income - Any deduction or any adjustment
AGI = ($23,670 + $12400) - (0 + 0)
AGI = $36070
Now, Calculate taxable income
Taxable income = Gross income - 1 Exemption
= $23670 - $12400
= $11,270
Hence, the AGI and taxable income is $36,070 and $11,270
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Answer: D is the answer
Step-by-step explanation:
$23,670 and $11,270
Find equation of a line passing through the pair of points. Write the equation in the form Ax+By=C (-2,2)and(-3,-9)
Answer:
11x - y = - 24Step-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
To find the equation of the line first find the slope
Slope of the line using points
(-2,2)and(-3,-9) is
\(m = \frac{ - 9 - 2}{ - 3 + 2} = \frac{ - 11}{ - 1} = 11\)
Then use the formula
y - y1 = m(x - x1)
where
m is the slope
( x1 , y1) can be any of the points
Equation of the line using point (-2,2) and slope 11 is
y - 2 = 11 ( x + 2)
y - 2 = 11x + 22
11x - y = - 2 - 22
We have the final answer as
11x - y = - 24Hope this helps you
solve for x.
x²= 16
a-8
b-4
c-32
d-64
Answer:
a
Step-by-step explanation:
you can do 16 divided by 2 to get the answer
Determine if the 2 triangles are similar. Explain how you came up with your answer.
To determine if the triangles are congruent we are going to use the SAS theorem of similarity.
SAS stands for "side, angle, side" and means that we have two triangles where:
• the ratio between two sides is the same as the ratio between another two sides
,• and we we also know the included angles are equal.
Notice that the ratio between sides QW and SW is the same as the ratio between RW and ZW:
\(\begin{gathered} \frac{15}{45}=\frac{14}{42} \\ \frac{1}{3}=\frac{1}{3} \end{gathered}\)hence the first condition of the theorem is fullfil.
We also notice that angle W is the same for triangle SZW and QRW, therefore the second condition for the theorem is alsso fullfilled.
Therefore we concldue that the triangles are similar.
Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit represents one yard, what is the total length of Jamie's fence in yards?
6
B
4
с
-6
4
- 2
0
4
6x
-64
Previous
Pause
Next
Type here to search
ő
>
W
9
00
2:28 PM
9/22/2020
Answer:
26 yards
Step-by-step explanation:
The complete question is attached in the image below.
The distance between two points O(\(x_1,y_1\)) and P(\(x_2,y_2\)) is:
\(|OP|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
The location of the points of the polygon are as follows:
A(-5, 5), B(0. 5), C(4,2), D(1, -2), E(-2, -2), F(-5, 2). Therefore:
\(|AB|=\sqrt{(0-(-5))^2+(5-5)^2}=5\ yards \\\\|BC|=\sqrt{(4-0)^2+(2-5)^2}=5\ yards \\\\|CD|=\sqrt{(1-4)^2+(-2-2)^2}=5\ yards \\\\|DE|=\sqrt{(-2-1)^2+(-2-(-2))^2}=3\ yards\\ \\|EF|=\sqrt{(-5-(-2))^2+(2-(-2))^2}=5\ yards \\\\|FA|=\sqrt{(-5-(-5))^2+(2-5)^2}=3\ yards\)
The perimeter of the fence = |AB| + |BC| + |CD| + |DE| + |EF| + |FA| = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards.
The problem is the first one illustrated. There is 2 answers that I have received through different sources, I am wondering which one is the correct answer. They are illustrated underneath the problem.
Answer:
Explanation:
Here, we want to get the rational function
We look at each of the definitions given
a) We have vertical asymptote at x = -2 and x = 3
To get the horizontal asypmtote:
That simply means:
\(undefined\)For the following question, show representation, your initial equations, your algebra work, symbolic answer, and units check.
A dog is sitting at an initial position of D1= (50 m North, 10 m East) from her home. She moves in a straight line until she is at a final position of D2 = ( 5 m North, 35 m East) from her home. It takes her 15 seconds to move from the initial position to the final position; find the magnitude of her average velocity vector.
The magnitude of the average velocity vector is approximately 3.651 m/s.
To find the magnitude of the average velocity vector, we need to calculate the displacement and divide it by the time taken.
Representation:
Initial position: D1 = (50 m North, 10 m East)
Final position: D2 = (5 m North, 35 m East)
Time taken: t = 15 seconds
Equations:
Displacement vector (ΔD) = D2 - D1
Average velocity vector (\(V_{avg}\)) = ΔD / t
Algebra work:
ΔD = D2 - D1
= (5 m North, 35 m East) - (50 m North, 10 m East)
= (-45 m North, 25 m East)
|ΔD| = √((-45)^2 + 25^2) [Magnitude of the displacement vector]
\(V_{avg}\) = ΔD / t
= (-45 m North, 25 m East) / 15 s
= (-3 m/s North, 5/3 m/s East)
|\(V_{avg}\)| = √((-3)^2 + (5/3)^2) [Magnitude of the average velocity vector]
Symbolic answer:
The magnitude of the average velocity vector is approximately 3.651 m/s.
Units check:
The units for displacement are in meters (m) and time in seconds (s). The average velocity is therefore in meters per second (m/s), which confirms the units are consistent with the calculation.
Therefore, the magnitude of the average velocity vector is approximately 3.651 m/s.
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T/F : The cofactor expansion of det A along the first row of A is equal to the cofactor expansion of det A along any other row
True. The cofactor expansion of the determinant of a matrix A along any row or column will yield the same result.
The cofactor expansion of the determinant of a matrix A along a row or a column is given by the formula:
```
det(A) = a1j * C1j + a2j * C2j + ... + anj * Cnj
```
where `aij` is the element in the ith row and jth column of A, and `Cij` is the (i,j)-cofactor of A.
The (i,j)-cofactor of A is defined as `(-1)^(i+j) * Mij`, where `Mij` is the determinant of the (n-1) by (n-1) matrix obtained by deleting the ith row and jth column of A.
To see why the cofactor expansion is independent of the row or column chosen, consider the formula for the determinant of a matrix obtained by transposing A:
```
det(A^T) = det([a11, a21, ..., an1],
[a12, a22, ..., an2],
...,
[a1n, a2n, ..., ann])
```
By the cofactor expansion along the first row of A^T, we have:
```
det(A^T) = a11 * C11' + a12 * C12' + ... + a1n * C1n'
```
where `Cij'` is the (i,j)-cofactor of A^T.
Now note that `Cij' = (-1)^(i+j) * Mji`, where `Mji` is the determinant of the (n-1) by (n-1) matrix obtained by deleting the jth row and ith column of A. But this is precisely the (j,i)-cofactor of A. Therefore, we have:
```
det(A^T) = a11 * C11 + a21 * C21 + ... + an1 * Cn1
```
which is the cofactor expansion of det A along the first column of A. Since the transpose of a matrix has the same determinant as the original matrix, we conclude that the cofactor expansion of det A along any row is equal to the cofactor expansion along any other row.
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Antonio earned some Money doing odd jobs last summer and put it in a savings account that earns 5% interest compounded quarterly after 4 years there is 1,000.00 in the account how much did Antonio earn doing odd jobs
r = 5% = 0.05
t = 4 years
n = 4 (quarterly)
A = 1000
P = ?
1000 = P (1.2199) ==> P = 1000/1.2199 = 819.74
Answer:
$819.74
\(1000\text{ = P(1 + }\frac{0.05}{4})^{4(4)}=P(1+0.0125)^{16}=P(1.0125)^{16}\text{ = P(1.2199)}\)\(P\text{ = }\frac{1000}{1.2199}\text{ = 819.74}\)Tammy has a rectangular rug with an area of 28 square feet. The rug is 12 feet
longer than it is wide.
The equation to determine the length and width of the rug is
28 = w² + 12w
Since, the shape of the rug is rectangle, therefore area of rectangle has been used to obtain the solution.
What is a rectangle?
Rectangle is a flat, two-dimensional shape, having four sides and vertices with opposite sides being equal and parallel. We may easily represent a rectangle in an XY plane by using its length and breadth as the arms of the x and y axes, respectively.
Rectangles can also be referred to as parallelograms because their opposite sides are equal and parallel.
We are given a rectangular rug with an area of 28 square feet.
Also, the rug is 12 feet longer than it is wide.
So,
Let 'l' be the length of the rug and 'w' be the width of the rug
As given, Length is 12 feet longer than its width
Therefore, l = w + 12
We know Area of rectangle = Length * Width and area is given to be 28 square feet.
So,
⇒28 = (w + 12)w
⇒28 = w² + 12w
Hence, the equation to determine the length and width of the rug is
28 = w² + 12w.
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Question: Tammy has a rectangular rug with an area of 28 square feet. The rug is 12 feet longer than it is wide.
Create an equation to determine the length and the width of the rug.
A medical researcher is studying the effects of a drug on blood pressure. Subjects in the study have their blood pressure taken at the beginning of the study. After being on the medication for 4 weeks, their blood pressure is taken again. The change in blood pressure is recorded and used in doing the hypothesis test. Change: Final Blood Pressure - Initial Blood Pressure The researcher wants to know if there is evidence that the drug increases blood pressure. At the end of 4 weeks, 32 subjects in the study had an average change in blood pressure of 2.5 with a standard deviation of 4.8. Find the p -value for the hypothesis test.
Answer:
The p -value for the hypothesis test is 0.003.
Step-by-step explanation:
In this case, a paired t-test would be used to determine whether the drug increases blood pressure.
The hypothesis can be defined as follows:
H₀: The drug has no effect on blood pressure, i.e. d = 0.
Hₐ: The drug increases blood pressure, i.e. d > 0.
The information provided is:
\(n=32\\\bar d=2.5\\S_{d}=4.8\)
The test statistic is:
\(t=\frac{\bar d}{S_{d}/\sqrt{n}}\)
\(=\frac{2.5}{4.8/\sqrt{32}}\\\\=2.9463\\\\\approx 2.95\)
The degrees of freedom of the test is:
\(df=n-1=32-1=31\)
The p-value of the test is:
\(p-value=P(t_{31}>2.95)=0.003\)
*Use a t-table.
Thus, the p -value for the hypothesis test is 0.003.
A t-test is an inferential statistic that is used to see if there is a significant difference in the means. The p-value for the hypothesis test is 0.003.
What is a t-test?A t-test is an inferential statistic that is used to see if there is a significant difference in the means of two groups that are connected in some way.
As it is given that 32(n) subjects in the study had an average change in blood pressure of 2.5(\(\bar d\)) with a standard deviation of 4.8(\(S_d\)).
Now, in order to solve the problem we need to use t-test, the test will determine whether the blood pressure increases or not under the influence of the drug.
The hypothesis for the test can be defined as:
H₀: The drug has no effect on blood pressure, therefore, d = 0.
Hₐ: The drug has increased blood pressure, therefore, d>0.
The test static is:
\(t = \dfrac{\bar d}{\dfrac{S_d}{\sqrt n}}\\\\\\t = \dfrac{2.5}{\dfrac{4.8}{32}} = 2.946 \approx 2.95\)
Further, the degree of freedom of the test can be written as,
\(d_f=n-1 = 32-1=31\)
Thus, the p-value of the test is:
\(p-value = P(t_{31} > 2.95)\\\\\text{Using the t-table}\\\\p-value = 0.003\)
Hence, the p-value for the hypothesis test is 0.003.
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Consider the following function ou the interval | 8, 27)
f(x) = 3x^2/3 - x
Find the critical point
The critical point of the function f(x) on the interval (8, 27) is x = 1/8.
How to find the critical points of a function?To find the critical points of a function, we need to find the values of x where the derivative of the function is zero or undefined.
The derivative of the function \(f(x) = 3x^(2/3) - x\) is:
\(f'(x) = 2x^(-1/3) - 1\)
To find the critical point, we set the derivative equal to zero and solve for x:
\(2x^(-1/3) - 1 = 0\)
\(2x^(1/3) = 1\)
\(x^(1/3) = 1/2\)
\(x = (1/2)^3\)
x = 1/8
So the critical point of the function f(x) on the interval (8, 27) is x = 1/8.
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which measurement gives you the difference between the points on the scatterplot and the prediction line for the same value of x?
A. Slope
B. Intercept
C. Residual
D. Correlation coefficient
The measurement that gives you the difference between the points on the scatterplot and the prediction line for the same value of x is the residual. Therefore, the correct answer is C. Residual.
In regression analysis, the residual represents the vertical distance between the observed data points and the corresponding predicted values on the regression line. It is calculated by taking the difference between the actual observed value and the predicted value for a specific value of the independent variable (x). The residuals provide a measure of how well the regression line fits the data, with smaller residuals indicating a better fit.
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What is 16% of 78? Round to the nearest tenth.
What is 16% of 78? Round to the nearest tenth.
16% = 0.16
so:
0.16 * 78 = 12.48
round:
12.5
look at this equation 3(x+1)=3x=? which number can be placed in the box *the question mark* that would create an equation that has an infinite number of solutions
a.0
b.1
c.2
d.3