Find the allowed energies of the half-harmonic oscillator (a quantum spring which can be stretched but not compressed). The corresponding potential is:

Answers

Answer 1

The specific form and values of the potential will determine the allowed energies of the half-harmonic oscillator.

A half-parabolic potential may be used to explain the potential energy function for a half-harmonic oscillator, commonly referred to as a quantum spring that can be expanded but not crushed.

We solve the Schrödinger equation for the specified potential in order to determine the system's permitted energies. However, it is not feasible to give a precise description of the permitted energies in the absence of specified characteristics or boundary conditions. The half-harmonic oscillator's energy levels and related wavefunctions will depend on the precise shape and values of the potential.

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The complete question is attached below.

Find The Allowed Energies Of The Half-harmonic Oscillator (a Quantum Spring Which Can Be Stretched But

Related Questions

HELP THIS IS DUE TODAY who ever answers first (correctly and gives explanation will get brainly)


How much power does a cordless phone use if it draws 0.50 A of current at 6.0 V?
i need it in watts so please write it in forms of Watt

Answers

Answer:

3.0 W

I actually had this question before BUT I have no clue how to explain it. I haven't done this in so long. I apologize but that is the correct answer.

Answer:3.0 W

Explanation:

P=VI

P= (6.0 V) (5.0 A)

P= 3.0 W

The resistance of a very fine aluminum wire with a 18 μm × 18 μm square cross section is 1200 Ω . A 1200 Ω resistor is made by wrapping this wire in a spiral around a 3.5-mm-diameter glass core

Answers

The total length of the wire required to make the 1200 Ω resistor by wrapping it in a spiral around the glass core is approximately 1.27 × 10^(-3) m + 3.5π × 10^(-3) m.

To solve this problem, we need to calculate the length of the aluminum wire used to make the 1200 Ω resistor.

Given:

Resistance of the wire (R_wire) = 1200 Ω

Cross-sectional area of the wire (A_wire) = (18 μm) × (18 μm)

Diameter of the glass core (d_core) = 3.5 mm

To find the length of the wire, we can use the formula for the resistance of a wire:

R_wire = (ρ_wire * L_wire) / A_wire

where ρ_wire is the resistivity of aluminum and L_wire is the length of the wire.

To calculate the resistivity of aluminum (ρ_wire), we can use the known resistivity value for aluminum, which is approximately 2.65 × 10^(-8) Ω·m.

Now let's rearrange the formula to solve for L_wire:

L_wire = (R_wire * A_wire) / ρ_wire

Substituting the given values:

L_wire = (1200 Ω * (18 μm) * (18 μm)) / (2.65 × 10^(-8) Ω·m)

Before calculating, we need to convert the micrometer (μm) to meters (m) to ensure consistent units:

1 μm = 1 × 10^(-6) m

L_wire = (1200 Ω * (18 × 10^(-6) m) * (18 × 10^(-6) m)) / (2.65 × 10^(-8) Ω·m)

= (1200 * 18 * 18) / (2.65 × 10^(-8))

≈ 1.27 × 10^(-3) m

Now that we have the length of the wire, we can calculate the total length required to make the 1200 Ω resistor by wrapping it in a spiral around the glass core.

The length of the wire required is equal to the circumference of the spiral, which can be calculated using the formula:

Circumference = π * d_core

Substituting the given value for the diameter of the glass core:

Circumference = π * 3.5 mm

Again, we need to convert millimeters (mm) to meters (m) for consistent units:

1 mm = 1 × 10^(-3) m

Circumference = π * (3.5 × 10^(-3) m)

= 3.5π × 10^(-3) m

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When is there a decrease in air pressure on top of a plane's wing?
A)as the plane's speed decreases
B)as the plane's fuel runs low
C)as the plane's speed increases

Answers

Answer: Option C.

Explanation:

As the speed of plane increases and it moves forward it allows to push air on the bottom of the wings of the plane which results in increasing the pressure

The fact of air pressure on top of planes wing decreases with the increase bin plane's speed is based on Bernoulli’s Principle which states that with the fast moving air, the pressure decreases.

Therefore,n when the plane moves up it's wing pushes air down and on the same time the air pressure decreases at the top of the wing, this difference between the high and low pressure allows the flight to lift up.

Hence, the correct option is C.

What type of landform is depicted here? a. a mountain b. a depression c. a valley​

What type of landform is depicted here? a. a mountain b. a depression c. a valley

Answers

Answer:

b.mountain the correct answer

Explanation:

what type of ladform ids depicted here? a.a b. mountain b. a depression c. avaley

An appliance is in a room repeatedly making the same sound all day. As the room heats up from 25 degrees Celsius to 35 degrees Celsius, what changes?


A. The sound wave's velocity decreases

B. The sound wave's frequency decreases

C. The sound wave's frequency increases

D. The sound wave's velocity increases

Answers

An appliance is in a room repeatedly making the same sound all day. As the room heats up from 25 degrees Celsius to 35 degrees Celsius is

B) The sound wave's frequency decreases

As the temperature of the room increments, the speed of sound waves within the discussed increments.

In any case, the recurrence of the sound wave created by the machine remains steady. This implies that the wavelength of the sound wave changes as the speed of the wave changes.

Agreeing with the wave condition, the speed of a wave is rise to its recurrence increased by its wavelength.

Subsequently, in the event that the speed of the wave increments and the recurrence remains steady, the wavelength must diminish. This results in a diminish within the recurrence of the sound wave, making it lower pitched. 

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Answer:

Its A the other person is wrong

Explanation:

How can the direction of a tensional force be changed without diminishing the force?

Answers

Given what we know, we can confirm that the tensional force of a system can in theory be changed without diminishing its force through the use of an ideal pulley.

What is an ideal pulley?A pulley is a small wheel through which a string or chain is run. These are used in order to change the direction of a force. An ideal pulley would be one in which there is no friction and the pulley itself would have no mass. Therefore, the force would be able to change directions without giving part of its force to the pulley system.

Therefore, we can confirm that the only known way to change the direction of a force without diminishing its value would be through the use of a frictionless and massless pulley system otherwise known as an ideal pulley.

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thermal energy is the _____ of the kinetic and potential energies of all particles in an object.

Answers

thermal energy is the force of the kinetic and potential energies of all particles in an object

he event that marks the end of a star's evolutionary life before becoming a white dwarf is
a. helium flash
b. a nova
c. a Type I supernova
d. the depletion of hydrogen in the core
e. a planetary nebula

Answers

The event that marks the end of a star's evolutionary life before becoming a white dwarf is a planetary nebula. So, option E is correct.

A planetary nebula is characterized by cosmic rays of gas and dust surrounding a dying star. This dying star becomes a white dwarf after the complete depletion of hydrogen in the core.

It gets its name from a scientist who described the gases to be looking like two planets around a dying star. Thus, it's called planetary nebulae. This marks the final stage of a dying star that becomes a white dwarf. It consists of the outer layers of the star.

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What is the method of charging called?

Answers

The answer is conduction

An unknown sample has a mass of 38.00 g and a volume of 56.39 ml. Calculate the density in g/ml. Provide your answer with 2 decimals. Show your work​

Answers

The density of the unknown sample is 0.67 g/ml.

To calculate the density, we use the formula:

Density = Mass / Volume

Mass = 38.00 g

Volume = 56.39 ml

Substituting the values into the formula:

Density = 38.00 g / 56.39 ml

Dividing the mass by the volume, we find:

Density = 0.674 g/ml

Rounding to two decimal places, the density of the unknown sample is 0.67 g/ml.

Density is a measure of how much mass is contained within a given volume. In this case, we are given the mass of the unknown sample as 38.00 g and its volume as 56.39 ml. To find the density, we divide the mass by the volume. By performing the calculation, we obtain a density of 0.674 g/ml.

When rounding the value to two decimal places, the density of the unknown sample is 0.67 g/ml. This means that for every milliliter of the sample, there is 0.67 grams of mass. Density is an important property in chemistry and materials science as it can help identify substances and determine their behavior in various applications.

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Questions

1. From your data, what factor(s) affect the speed of a wave? Explain your reasoning.

2. The pitch made by a musical instrument is dependent on the frequency of the wave. Frequency is the inverse of period. What impact do you think the frequency of a wave has on the wave speed?

3. What happens to wave speed as it moves from a medium of low density to one of high density? Explain your response with respect to this lab.

4. When a stringed instrument is out of tune, the player with tighten or loosen the string. If the instrument is initially flat, should they tighten or loosen the string? In the context of this experiment, explain your reasoning.

Present Your Findings or Questions

Using data and observations, answer the questions and provide your data tables in the essay box below.​

Answers

Answer:

Initial velocity describes how fast an object travels when gravity first applies force on the object. On the other hand, the final velocity is a vector quantity that measures the speed and direction of a moving body after it has reached its maximum acceleration.

Explanation:

Answer:

1. The speed of the wave is affected by wavelength frequency because waves travel through a medium and sound, ocean waves and seismic waves, etc. are the physical properties of the medium that determines the speed of the mechanical waves.

2. I think the frequency of the wave doesn't have any effect on the wave speed. Only the characteristics of the medium the wave is traveling through determines its speed.

3. As a wave moves from a medium of low density to a higher density the wave speed increases and when a wave moves from a higher density to a medium density the wave speed decreases because the wave length shortens causing the wave speed to lower.

4.If the instrument is initially flat they should tighten it because once it is tightened there is going to be force applied to the gears, and after you've reached the correct pitch the gears won't be able to move. So ultimately, you will be able to meet the intended pitch you were going for.

A boy of mass 40kg and a girl of mass 30kg play on a see-saw of negligible weight. If the boy sits 270 cm from the pivot of the see-saw, where must the girl sit to make it balance.
Please show the steps....I will follow you if you do.

Answers

Hi there!

To solve, we can use a summation of torques.

For the see-saw to balance, the sum of torques must equal 0, so:

∑τ = 0

Recall that:

τ = rFsinθ

r = distance from pivot (meters)

F = force (N)

In this case, the forces are the weight of the children. Also, we can leave the distance in centimeters for this type of problem, but others do require a conversion to meters.

Multiply each mass by 10 (g ≈ 10 m/s²) to get the weight:

Στ = 270(400) - x(300) = 0

270(400) = 300x

Solve for 'x', the distance in cm away from the fulcrum:

108000/300 = 360 cm

When there is an increasing unbalanced force applied in the opposite direction as the motion, speed will ___________________ and acceleration will ________________________.

Answers

When there is an increasing unbalanced force applied in the opposite direction as the motion, speed will decrease and acceleration will increase.

What is Acceleration?

This is defined as the rate of change of velocity with time and the unit is metres per seconds.

An unbalanced force will lead to the speed of the object decreasing as a result of the distance reached being on a decline. However, the acceleration will increase due to the applied force in which they have a direct relationship.

This is therefore the reasons why they were chosen as the most appropriate choice.

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Moby has a mass of 145 kilograms while Tim has a mass of 45 kilograms. Which one needs more force to accelerate? Explain your reasoning.

Answers

Answer:

Moby

Explanation:

Newton's 2nd Law:  F = ma

a = F/m

Acceleration and mass are inversely proportional.  So if Moby and Tim want to accelerate at the same rate, Moby, with the greater mass, would need more force to accelerate at the same rate as Tim.

Hair sticking to a balloon after it
has been rubbed on a girl's head is
an example of

Answers

Answer:

Friction

Explanation:

Answer:

It causes electrostatic charging, which makes it stick to your hair,

GUYS PLEASE HELPPPP


Q. A body is thrown at an angle of 30 degree with velocity of 30m/s downward, if the height of the tower is 15m find:

1) the time when body reaches the ground
2) displacement vector
3) angle when body hits the ground
4) max height?

Answers

1. y = v₀y * t + (1/2) * a * t²

-15 = (30 * sin(30)) * t - (1/2) * 9.8 * t²
t ≈ 3.04 seconds.
2. x = v₀x * t
x = (30 * cos(30)) * 3.0

Simplifying the equation, we find that the horizontal displacement is approximately x ≈ 157.47 meters.

3. Angle when the body hits the ground:
Since the launch angle is 30 degrees downward, the angle when the body hits the ground will be 180 degrees minus the launch angle. Therefore, the angle when the body hits the ground is 180 - 30 = 150 degrees.

4. Maximum height:

y = v₀y * t + (1/2) * a * t²
y = (30 * sin(30)) * 3.04 - (1/2) * 9.8 * (3.04)²
y ≈ 15.57 meters.

1. To find the time when the body reaches the ground, we can use the vertical motion equation:

h = v₀y * t + (1/2) * g * t²

where:

h = height of the tower = 15m

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time

Plugging in the values:

15 = (30 * sin(30°) * t) + (0.5 * 9.8 * t²)

Simplifying the equation:

15 = 15t * 0.5t² + 4.9t²

Combining like terms:

15 = 7.5t² + 4.9t²

Simplifying further:

15 = 12.4t²

Dividing both sides by 12.4:

t² = 15 / 12.4

Taking the square root of both sides:

t = √(15 / 12.4)

Calculating the value:

t ≈ 1.01 seconds

Therefore, the time it takes for the body to reach the ground is approximately 1.01 seconds.

2. To find the displacement vector, we need to calculate the horizontal and vertical components separately.

Horizontal component:

The horizontal displacement can be calculated using the formula:

x = v₀x * t

where:

v₀x = initial horizontal velocity = v₀ * cos(θ) = 30m/s * cos(30°)

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀x = 30m/s * cos(30°)

t = 1.01 seconds

Calculating the value:

v₀x ≈ 26.02 m/s

Vertical component:

The vertical displacement can be calculated using the formula:

y = v₀y * t + (1/2) * g * t²

where:

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

t = time is taken to reach the ground (previously calculated as approximately 1.01 seconds)

Plugging in the values:

v₀y = 30m/s * sin(30°)

t = 1.01 seconds

Calculating the value:

v₀y ≈ 15 m/s

Now we have the horizontal and vertical components of the displacement vector:

Horizontal component: x ≈ 26.02 m/s

Vertical component: y ≈ 15 m/s

Therefore, the displacement vector of the body is approximately (26.02 m/s, 15 m/s).

3. To find the angle when the body hits the ground, we can use the vertical and horizontal components of the velocity.

The horizontal component of the velocity, v₀x, can be calculated using the formula:

v₀x = v₀ * cos(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀x = 30m/s * cos(30°)

Calculating the value:

v₀x ≈ 26.02 m/s

The vertical component of the velocity, v₀y, can be calculated using the formula:

v₀y = v₀ * sin(θ)

where:

v₀ = initial velocity = 30m/s

θ = angle of projection = 30 degrees

Plugging in the values:

v₀y = 30m/s * sin(30°)

Calculating the value:

v₀y ≈ 15 m/s

Now, to find the angle when the body hits the ground, we can use the inverse tangent function:

θ = arctan(v₀y / v₀x)

Plugging in the values:

θ = arctan(15 m/s / 26.02 m/s)

Calculating the value:

θ ≈ 30.96 degrees

Therefore, the angle when the body hits the ground is approximately 30.96 degrees.

4. To find the maximum height, we can use the vertical motion equation:

h = v₀y² / (2 * g)

where:

h = maximum height

v₀y = initial vertical velocity = v₀ * sin(θ) = 30m/s * sin(30°)

g = acceleration due to gravity = 9.8m/s²

Plugging in the values:

h = (30 * sin(30°))² / (2 * 9.8)

Calculating the value:

h ≈ 27.55 meters

Therefore, the maximum height reached by the body is approximately 27.55 meters.

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calculate the heat of television if:
light-119J
Sound-1J
electricity-200J
heat-?
quickly pls​

Answers

Answer:

002 bc eause iy is

An eastbound car travels a displacement of 80.0 Km in 45 minutes. What is the velocity

of this car in both Km/h and m/s?

Answers

Explanation:

d= 80km = 8000m

t = 45 min = 45/60 h

= 0.75 h

V= ?

we know that,

V = d /t

or,V= 80 km / 0.75 h

or, V= 106.67 km/hr

or,V= 106.67×1000m / 3600 s

2. or, V= 29.63 m/s

If light is incident on glass at 0 degrees from perpendicular, what angle from perpendicular will it emerge

Answers

If light is incident on glass at 0 degrees from perpendicular (i.e., normal incidence), it will emerge at the same angle from perpendicular.

When light passes through a medium with a different refractive index, such as glass, the angle at which it bends is determined by Snell's law. According to Snell's law, the ratio of the sines of the angles of incidence (θ₁) and refraction (θ₂) is equal to the ratio of the refractive indices of the two media.

For normal incidence, when light is incident at 0 degrees from perpendicular, the angle of incidence (θ₁) is 0 degrees. In this case, the sine of 0 degrees is 0. Therefore, according to Snell's law, the sine of the angle of refraction (θ₂) is also 0.

Since the sine of 0 degrees is 0, it means that the angle of refraction is also 0 degrees. This implies that the emerging light will be parallel to the normal, maintaining the same angle from perpendicular.

When light is incident on glass at 0 degrees from perpendicular (normal incidence), it will emerge at the same angle from perpendicular. The angle of refraction will also be 0 degrees, resulting in the emerging light being parallel to the normal.

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what element has the same number of valence electrons as tin?

Answers

Answer:

The element manganese has seven valence electrons. A tin atom has 50 electrons. Tin has 5 energy level because it is in the 5th row of the periodic table

Explanation:

because the internet said so

an intersection that has signals or signs to assign the right of way is called
a. a registered intersection.
b. an unregistered intersection.
c. a controlled intersection.
d. an uncontrolled intersection.

Answers

A controlled intersection is one that contains signals or signs to designate the right of way.

Describe signal.

An electrostatic or electric current known as a signal is used to transfer information from one device or networks to another. Although it can sometimes take other dimensions, such as current, a signal in electronics frequently consists of a time-varying temperature that is also a electromagnet carrying information.

What characteristics do signals have?

They can be deterministic or random, deterministic or agnostic, continuous or continuous time, both analog and digital, periodic or nonstationary, finite or infinite. They can also be separated into groups based on the causality and symmetry of those groups. An optimum impulse signal is one that is 0 everywhere else but infinitely high at the origin.

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At this rate, what fraction of its mass would io lose in 4. 5 billion years?.

Answers

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

Equation

An equation is an expression used to show the relationship between two or more variables and numbers.

Given that:

Io loses about a ton (1000 kilograms) of sulfur dioxide per second to Jupiter's magnetosphere.

In 4.5 billion years, amount of mass lost = 1000 kg/s * (4.5 * 10⁹ * 365 * 60 60 * 24) = 1.41912 * 10¹⁷ kg.

In 4.5 billion years, the amount of mass lost is 1.41912 * 10¹⁷ kg.

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A ball is thrown straight upward with a velocity of 39 m/s. How much time passes before the ball strikes the ground? (Disregard air resistance.) A. 4.0 s B. 1.2 s C. 2.4 s D. 8,0

Answers

A ball is thrown straight upward with a velocity of 39 m/s,  the total time taken for the ball to strike the ground is approximately 2*(3.98) = 7.96 seconds, which is closest to option D (8.0 s).

The problem can be solved using the kinematic equations of motion. Since the ball is thrown straight upward, we can assume that its initial velocity is positive, and its acceleration due to gravity is negative. Therefore, we can use the following equation to find the time it takes for the ball to reach its maximum height:

v_f = v_i + a*twhere v_f is the final velocity (which is zero when the ball reaches its maximum height), v_i is the initial velocity (39 m/s), a is the acceleration due to gravity (-9.8 m/s^2), and t is the time taken.

Substituting the values, we get:

0 = 39 - 9.8*t

Solving for t, we get:

t = 39/9.8 ≈ 3.98 s

Therefore, the time it takes for the ball to reach its maximum height is approximately 3.98 seconds.

Next, we can use the same equation to find the total time taken for the ball to strike the ground. This time, however, we need to use the final velocity as negative (since the ball is moving downward), and the initial velocity as zero (since the ball starts falling from rest). Therefore, we get:

-39 = 0 - 9.8*t

Solving for t, we get:

t = 39/9.8 ≈ 3.98 s

Therefore, the total time taken for the ball to strike the ground is approximately 2*(3.98) = 7.96 seconds, which is closest to option D (8.0 s).

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A ball is dropped from the rest from a high window of a tall building and called for 4 seconds. Neglecting air resistance, the final velocity of the ball is ____ m/s. (g=-9.8m/s^2)

Answers

Answer:

-39.2m/s

Explanation:

Given that :

t = 4secs

g = -9.8m/s^2

v = ?

u = 0m/s ( since it was at rest )

V = u +at............. 1

Where v is the final velocity

a = -g = -9.8m/s^2 since the ball was dropped from a height which will eventually make it move against gravity

t = 4secs

Substitute the values into 1

v = 0 - 9.8×4

v = -39.2m/s

Hai điện tích hút nhau bằng một lực 2,7N. Khi chúng dời xa nhau thêm 12cm thì lực hút là 0,3N. Khoảng cách ban đầu giữa chúng

Answers

Answer:

6 cm hoặc 0,06m

Explanation:

\(F=k\frac{q_{1} q_{2} }{r^{2} }\)

nên \(q_{1} q_{2} =\frac{F.r^{2} }{k}\)

Ban đầu:

\(F_{1} =k\frac{q_{1} q_{2} }{r^{2} }=2,7\)

---> \(q_{1} q_{2} =\frac{2,7.r^{2} }{k}\)

Lúc sau:

\(F_{2} =k\frac{q_{1} q_{2} }{(r+0,12)^{2} }=0,3\)

---->\(q_{1} q_{2} =\frac{0,3.(r+0,12)^{2} }{k}\)

Suy ra:

\(2,7.r^{2} = 0,3.(r+0,12)^{2}\)

Giải pt đc 2 nghiệm là 0,06 và -0,03

loại nghiệm âm được 0,06m

Mr. Mangan is in freefall on Planet Y. His velocity increases from rest to 30 m/s in 1.2 s. If his mass is 86 kg, what is his weight on Planet Y? What is the gravitational field strength on Planet Y?

Answers

Explanation:

First, we need to calculate the gravitational field strength g on Planet Y. So, we will use the following e

If an object is being pulled toward
the center, what force is acting on
it?
A. It pulls objects to the center.
B. It pulls objects to the surface.
C. It pushes objects away.
D. It causes objects to bounce off each other.

Answers

A is the answer since the question asks “if an object is being pulled toward the center”.

which of theres is the correct unit for speed? a) m/s- meters per second b) j- joules c) n- newtons

Answers

a)m/s

Since the speed formula is = Distance / time

speed = distance /time

speed = metre/ seconds

speed = m/s

Answer:

a) m/s- meters per second

Explanation:

Recall that m/s (meters per second) is the official derived SI unit for speed. That is, it is length (meters) over time (second), hence m/s.

It can't be joules (J), since that is the SI unit for work & energy.

It also can't be newtons (N), since that is the SI unit for force.

Therefore, the correct answer is a) m/s- meters per second.

I hope this made sense to you, if not, feel free to let me know and I can try to provide further assistance.

Two small nonconducting spheres have a total charge of Q=Q
1

+Q
2

=94.0μC,Q
1

2

. When placed 31.0 cm apart, the force each exerts on the other is 11.5 N and is repulsive. What would Q
1

be if the force were attractive? Express your answer to three significant figures and include the appropriate units. Part D What would Q
2

be if the force were attractive? Express your answer to three significant figures and include the appropriate units.

Answers

The value of Q₁ would be -65.6 μC if the force were attractive.

Given that Q₁ + Q₂ = 94.0 μC and the force between the spheres is repulsive with a magnitude of 11.5 N, we can determine the charges on the spheres.

Since the force is repulsive, the charges on the spheres must have the same sign. Let's assume Q₁ is positive, so Q₂ will also be positive.

According to Coulomb's law, the force between two charges is given by F = k * (|Q₁| * |Q₂|) / r², where k is the electrostatic constant and r is the distance between the charges.

Given F = 11.5 N and r = 31.0 cm (which is 0.31 m), we can solve for |Q₁ * Q₂|:

11.5 N = (8.99 × 10⁹ N m²/C²) * (|Q₁| * |Q₂|) / (0.31 m)²

Simplifying the equation, we find |Q₁ * Q₂| = 4.093 × 10⁽⁻⁷⁾C²

Since Q₁ + Q₂ = 94.0 μC, we can express Q₂ in terms of Q₁: Q₂ = 94.0 μC - Q₁

Substituting Q₋ in terms of Q₁ in the equation |Q₁ * Q₂| = 4.093 × 10⁽⁻⁷⁾ C², we can solve for Q₁:

|Q₁ * (94.0 μC - Q₁)| = 4.093 × 10⁽⁻⁷⁾ C²

Solving this quadratic equation, we find two possible solutions: Q₁ = 65.6 μC or Q₁ = -29.4 μC.

Since Q₁ represents the charge of the larger sphere and it is given that the force is repulsive, Q₁ must be positive. Therefore, Q₁ = 65.6 μC.

For part D, we need to find Q₂. Since Q₂ = 94.0 μC - Q1, we can substitute the value of Q₁ to find Q₂:

Q₂ = 94.0 μC - 65.6 μC = 28.4 μC

So, Q₂ would be 28.4 μC if the force were attractive.

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A vehicle is traveling at a velocity of 30 meters per second. Exactly 5 seconds later, its velocity has changed by a factor of 0.6. What was the vehicles average acceleration over that time period?

Answers

Answer:

-2.4 m/s²

Explanation:

avg accel = Δv/Δt

v-i = 30 m/s

v-f = (30 m/s)(0.60) = 18 m/s

Δt = 5.0 sec

avg accel = (18 m/s - 30 m/s) / 5.0 s = (- 12 m/s) / 5 s = -2.4 m/s²

negative sign means it's slowing down

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