The absolute maximum value of the function on the interval [-3, 1] is approximately 28.97, and the absolute minimum value is approximately 3.84.
To find the absolute maximum and minimum values of the function f(x) = 31/3 - 3x2/3 on the interval [-3, 1], we need to evaluate the function at its critical points and endpoints.
First, let's find the critical points by taking the derivative of the function:
f'(x) = (2/3)(31/3)(-3x^(-1/3)) = -2(31/3)(1/x^(1/3)) = -62/x^(1/3)
To find the critical points, we set f'(x) equal to zero and solve for x:
-62/x^(1/3) = 0
This equation has no solutions since the numerator is always non-zero.
Next, we evaluate the function at the endpoints of the interval:
f(-3) = 31/3 - 3(-3)^(2/3) ≈ 3.84
f(1) = 31/3 - 3(1)^(2/3) ≈ 28.97
Finally, we compare the values of the function at the critical points and endpoints to determine the absolute maximum and minimum:
Absolute maximum: f(1) ≈ 28.97
Absolute minimum: f(-3) ≈ 3.84
Therefore, the absolute maximum value of the function on the interval [-3, 1] is approximately 28.97, and the absolute minimum value is approximately 3.84.
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For what value n is 1P3 =nP4?
Answer:
I don't know if this helps, just a picture not a link
Use the table to work out the values of a , b , c , and d. X y = 2 x + 1 − 3 a − 2 − 3 − 1 b 0 1 1 c 2 d a = b = c = d =
By Using the table to work out the values of a , b , c , and d. X y = 2 x + 1 − 3 a − 2 − 3 − 1 b 0 1 1 c 2 d a = b = c = d =
Therefore, The solutions are : a = -3, b = 0, c = 6, d = 9
Equation:
In mathematics, an equation is an expression that indicates equality of two expressions by connecting them with the equal sign = . The word "equation" and related words in other languages can have slightly different meanings. For example, in French an equation is defined as containing one or more variables, whereas in English a well-formed formula consisting of two expressions connected by an equal sign is an equation.
Given:
This table;
x y = 3x+3
-3 -6
-2 a
-1 b
0 3
1 c
2 d
To Find:
Values of a, b, c and d
Consider the 2nd row,
x = -2, y = a
Putting the values in the equation,
we get,
a = 3(-2) + 3
⇒ a = -3
Consider the 3rd row,
x = -1, y = b
Putting the values in the equation,
we get,
b = 3(-1) + 3
⇒ b = 0
Consider the 5th row,
x = 1, y = c
Putting the values in the equation,
c = 3(1) + 3
⇒ c = 6
Consider the 6th row,
x = 2, y = d
d = 3(2) + 3
⇒ d = 9
The final answer is,
a = -3, b = 0, c = 6, d = 9.
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What is the domain:
What is the range:
Answer:
Domain: [-4,4]
Range: [-4,6]
Step-by-step explanation:
To domain pertains to the x-coordinates, while the range pertains to the y-coordinates.
Looking at the graph, we can see that the farthest point to the left is (-4,3) and the farthest point to the right is (4,6). Now, we know that the domain is [-4,4].
Looking at the graph, we can see the highest point is (4,6) and the lowest point is (0,-4). Now, we know the range is [-4,6].
Now, we know that the domain is [-4,4] and the range is [-4,6].
7. Ifa = 3an * db = - 2 . find the values of: (a + b)ab
The Values of (a+b)ab are undefined.
Given that, a = 3an and db = -2We need to find the values of (a+b)
Now, we have a = 3an... equation (1)Also, we have db = -2... equation (2)From equation (1), we get: n = 1/3... equation (3)Putting equation (3) in equation (1), we get: a = a/3a = 3... equation (4)Now, putting equation (4) in equation (1), we get: a = 3an... 3 = 3(1/3)n = 1
From equation (2), we have: db = -2=> d = -2/b... equation (5)Multiplying equation (1) and equation (2), we get: a*db = 3an * -2=> ab = -6n... equation (6)Putting values of n and a in equation (6), we get: ab = -6*1=> ab = -6... equation (7)Now, we need to find the value of (a+b).For this, we add equations (1) and (5),
we get a + d = 3an - 2/b=> a + (-2/b) = 3a(1) - 2/b=> a - 3a + 2/b = -2/b=> -2a + 2/b = -2/b=> -2a = 0=> a = 0From equation (1), we have a = 3an=> 0 = 3(1/3)n=> n = 0
Therefore, from equation (5), we have:d = -2/b=> 0 = -2/b=> b = ∞Now, we know that (a+b)ab = (0+∞)(0*∞) = undefined
Therefore, the values of (a+b)ab are undefined.
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Use the given information to find the number of degrees of freedom, the critical values x and x, and the confidence interval estimate of o. It is reasonable to assume that a simple random sample has been selected from a population with a normal distribution.
Platelet Counts of Women 80% confidence; n=29, s=65.7.
Click the icon to view the table of Chi-Square critical values.
df 28 (Type a whole number.)
x2=□
(Round to three decimal places as needed.)
The number of degrees of freedom is 28, the critical values x are approximately ±1.310, and the critical value x2 is approximately 37.652. The confidence interval estimate of σ can be calculated using the given sample size and standard deviation.
To find the number of degrees of freedom, critical values x and x2, and the confidence interval estimate of σ (standard deviation), we have the following information: sample size (n) = 29, sample standard deviation (s) = 65.7, and confidence level = 80%. Since it is mentioned that a simple random sample has been selected from a population with a normal distribution, we can use the t-distribution and the formula for confidence interval estimate of σ to calculate the required values.
The number of degrees of freedom (df) for this problem is equal to the sample size minus 1, which gives us df = 29 - 1 = 28.
To determine the critical values x, we need to find the t-value corresponding to an 80% confidence level with 28 degrees of freedom. Looking up the t-distribution table or using statistical software, we find that the critical values for a two-tailed test at this confidence level are approximately ±1.310.
The critical value x2 represents the chi-square value for a 80% confidence level with 28 degrees of freedom. Referring to the chi-square distribution table, we find that the critical value for a chi-square distribution with 28 degrees of freedom and an 80% confidence level is approximately 37.652.
Finally, to calculate the confidence interval estimate of σ (standard deviation), we use the formula:
CI = (s * √(n - 1)) / √(χ2α/2, n - 1)
Substituting the given values, we have:
CI = (65.7 * √(29 - 1)) / √(37.652/2, 29 - 1)
Evaluating this expression, we can calculate the confidence interval estimate of σ.
In summary, the number of degrees of freedom is 28, the critical values x are approximately ±1.310, and the critical value x2 is approximately 37.652. The confidence interval estimate of σ can be calculated using the given sample size and standard deviation.
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function rule to find f(1)
By evaluating the function in x = 1, we will get:
f(1) = 4
How to find the value of f(1)?Here we have the following absolute value function:
f(x) = 11 - 7*|x|
We want to find f(1), this just means that we need to evaluate the function in x = 1.
That means that we need to replace the variable in the equation by the number 1, so let's do that:
f(1) = 11 - 7*|1|
Now we just simplify that, we will get:
f(1) = 11 - 7*|1|
= 11 - 7
= 4
f(1) = 4
That is the value we wanted to find.
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Determine the solution to the equation. 8+4x=2x+8+2x A Infinite B One Solution C No Solution
After solving the given equations the answer is an Infinite solution. Hence, option A is correct
What is an equation?Mathematical expressions with two algebraic symbols on either side of the equal (=) sign are called equations.
This relationship is illustrated by the left and right expressions being equal to one another. The left-hand side equals the right-hand side is a basic, straightforward equation.
As per the given equation in the question,
8 + 4x = 2x + 8 + 2x
Firstly, let's write the given equation in a simplified manner,
8 + 4x = 8 + 4x
As we can see that LHS = RHS, which means that both equations are the same then which means they will give infinite solutions.
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Solve this problem. 98-5^2-35= *
someone help plz
Answer:
28
Step-by-step explanation:
used a calculator
find the square root of each by division method:
a) 225 b) 961 c) 3969 d) 10404
If you can give the correct answer first, I'll mark the brainliest.
Refer to the attachment
Answer:
\(\sqrt[2]{225} =15\), \(\sqrt[2]{961} =31\), \(\sqrt[2]{3969} =69\), \(\sqrt[2]{10404} =102\)
Step-by-step explanation:
\(\sqrt[2]{225} =\sqrt{15*15}=15\)
\(\sqrt[2]{961}=\sqrt{31*31} =31\)
\(\sqrt[2]{3969} =\sqrt{69*69} =69\)
\(\sqrt[2]{10404} =\sqrt{102*102}=102\)
Can someone please help me.
Rectangular prism B is the image of rectangular prism A after dilation by a scale factor of 1/3. If the surface area of rectangular prism B is 14^2 find the surface area of rectangular prism A, the preimage.
.\(SA_A = 2LW + 2LH + 2WH = 2(LW + LH + WH) = 2(882) = 1764\) The surface area of rectangular prism A is 1764 square units.
What are rectangular prism?A three-dimensional object called a rectangular prism has six rectangular faces, each of which has four right angles and the two opposing faces are congruent and parallel. It is sometimes referred to as a rectangular box or a parallelepiped.
Let's start by defining some variables. Let the length, width, and height of rectangular prism A be denoted by L, W, and H, respectively. Similarly, let the length, width, and height of rectangular prism B be denoted by l, w, and h, respectively.
Since rectangular prism B is a dilation of rectangular prism A by a scale factor of 1/3, we have:
\(l = (1/3)L\)
\(w = (1/3)W\)
\(h = (1/3)H\)
The surface area of a rectangular prism is given by the formula:
SA = 2lw + 2lh + 2wh
Therefore, the surface area of rectangular prism B is:
\(SA_B = 2lw + 2lh + 2wh\)
\(= 2((1/3)L(1/3)W) + 2((1/3)L(1/3)H) + 2((1/3)W(1/3)H)\)
\(= (2/9)LW + (2/9)LH + (2/9)WH\)
\(= (2/9)(LW + LH + WH)\)
We are given that the surface area of rectangular prism B is 14^2, so we have:
\(SA_B = (2/9)(LW + LH + WH) = 14^2\)
Simplifying this equation, we get:
\(LW + LH + WH = (9/2)14^2 = 882\)
Therefore, the surface area of rectangular prism A is:
\(SA_A = 2LW + 2LH + 2WH = 2(LW + LH + WH) = 2(882) = 1764\)
Therefore, the surface area of rectangular prism A is 1764 square units.
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In Mrs. Ramon's class, the ratio of boys to girls is 2 to 3. The class has 30
students. How many girls are in Mrs. Ramon's class?
Answer:
10 girls
Step-by-step explanation:
Because 2/3 of 30 is 20 making the other 10 girls
describe each of the following sets by listing its elemesnts. {x|x ∈ n and x^2 - 2x - 8 = 0}
The set {x|x ∈ N and x^2 - 2x - 8 = 0} can be described as {4}.
To describe the given set by listing its elements, we first need to solve the quadratic equation x^2 - 2x - 8 = 0 for x, keeping in mind that x ∈ N (x is a natural number).
Using the quadratic formula, we get:
x = [2 ± √(2^2 - 4 * 1 * (-8))] / (2 * 1)
x = [2 ± √(4 + 32)] / 2
x = [2 ± √36] / 2
x = [2 ± 6] / 2
This gives us two possible values for x:
x1 = (2 + 6) / 2 = 8 / 2 = 4
x2 = (2 - 6) / 2 = -4 / 2 = -2
Now, we need to check which of these values belong to the set of natural numbers (N). Since natural numbers include only positive integers, only x1 = 4 is a natural number.
So, the set {x|x ∈ N and x^2 - 2x - 8 = 0} can be elaborated as {4}.
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Guys I need help and like super fast, I don’t know what to dooooooooo
Answer:
translation
i just got done learning about this a couple of weeks ago
Write six different iterated triple integrals for the volume of the tetrahedron cut from the first octant by the plane 12x+4y+3z=12.(a) Evaluate the first integral.(b) Write an integral that represents the volume in the order dx dy dz.
The first integral to evaluate the volume of the tetrahedron is \(\int\limits\int\limits \int\limits R dV\). The integral that represents the volume in the order dx dy dz is \(\int\limits\int\limits \int\limits R dz dy dx\).
(a) Evaluating the integral ∫∫∫ R dV:
The limits of integration for z will be determined by the intersection of the plane and the coordinate axes. When x = 0 and y = 0, we have 12(0) + 4(0) + 3z = 12, which gives z = 4. When z = 0, we have 12x + 4y + 3(0) = 12, which gives 12x + 4y = 12. Dividing by 4, we get 3x + y = 3, which represents the line in the xy-plane.
To find the limits of integration for y, we need to consider the bounds of this line. When x = 0, we have y = 3; when x = 1, we have y = 0.
Finally, the limits of integration for x will be 0 to 1, as we are in the first octant.
So, the first integral to evaluate the volume is \(\int\limits^1_0 \int\limits^0_3 \, \int\limits^{({12-3x-4y} )}_4 \, dz dy dx.\)
(b) Writing the integral in the order dx dy dz:
The limits of integration for x will be determined by the intersection of the plane and the coordinate axes.
When y = 0 and z = 0, we have 12x + 4(0) + 3(0) = 12, which gives x = 1.
When x = 0, we have 12(0) + 4y + 3z = 12, which gives 4y + 3z = 12.
Dividing by 4, we get \(y + (\frac{3}{4})z = 3\), which represents the line in the yz-plane.
To find the limits of integration for y, we need to consider the bounds of this line. When z = 0, we have y = 3; when z = 4, we have y = 0.
Finally, the limits of integration for z will be 0 to 4, as we are in the first octant. Therefore, the integral that represents the volume in the order dx dy dz is:
\(\int\limits^1_0\int\limits^{4(1-(3/4)z}_{3}\int\limits^{12-4y-(3/4)z}_0 \, dx dy dz\).
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PLEASE HURRY!!!!
Write the equation of the line in fully simplified slope-intercept form.
The slope intercept form of the equation is y = -3x - 20.
Slope intercept form
The standard form of the slope intercept equation is
y=mx + c
y = y coordinate
m = slope
x = x coordinate
c = y intercept
Given,
Here we have the graph. And through the graph we have to identify the equation in slope intercept form.
To identify the slope intercept form equation, then we have to find two things from the given graph.
They are,
1) slope
2) intercept.
Slope is identified by simply select any two points of the line and use the formula in order to find the slope of the line.
Here we take the points (-6,-2) and (-5, -5)
When we apply the value on the formula, then we get,
m = (-5-(-2))/(-5-(-6))
m = -3/1
Therefore, the slope of the line is -3.
Now, we have to calculate the intercept by using the point (-6,-2) and the slope value,
Thus,
-2 = -3(-6) + c
-2 = 18 +c
c = -20
Therefore, when we apply these known value on the slope intercept form equation, then we get the equation as,
y = -3x - 20.
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Katie wants to buy a bicycle that costs $200. This is
$20 more than twice what she saved last month. How
much did she save last month?.
Find the number.
Step-by-step explanation:
Multiply both the numbers
200 × 20
(4000) Answer
Can someone translate these into equations?!?
Answer:
11. n+5=9
12. x+3=19
13. p-7=30
14. 15k = 75
15. 3y+5 = 47
Step-by-step explanation:
evaluate the iterated integral by converting to polar coordinates. 1 0 2 − y2 9(x + y) dx dy y
In the polar coordinate system, the region R corresponds to 0 ≤ r ≤ (2 - 9sin(θ))/(9cos(θ) + 9sin(θ)) and 0 ≤ θ ≤ π/2.
To evaluate the given iterated integral ∫∫R (1 - y²)/(9(x + y)) dA, where R is the region in the xy-plane bounded by the curves x = 0, y = 1, and 9(x + y) = 2, we can convert it to polar coordinates for easier computation.
In polar coordinates, we have x = rcos(θ) and y = rsin(θ), where r represents the distance from the origin and θ is the angle measured counter clockwise from the positive x-axis.
The integral becomes ∫∫R (1 - r²sin²(θ))/(9(rcos(θ) + rsin(θ))) r dr dθ. In the polar coordinate system, the region R corresponds to 0 ≤ r ≤ (2 - 9sin(θ))/(9cos(θ) + 9sin(θ)) and 0 ≤ θ ≤ π/2.
In the given integral, we substitute x and y with their respective polar coordinate representations. The numerator becomes 1 - r²sin²(θ), and the denominator becomes 9(rcos(θ) + rsin(θ)). Multiplying the numerator and denominator by r, we have (1 - r²sin²(θ))/(9(rcos(θ) + rsin(θ))) = (1 - r²sin²(θ))/(9r(cos(θ) + sin(θ))). We then rewrite the double integral as two separate integrals: the outer integral with respect to θ and the inner integral with respect to r. The limits of integration for θ are 0 to π/2, while the limits for r are determined by the curve 0 = (2 - 9sin(θ))/(9cos(θ) + 9sin(θ)).
We can simplify this curve to 2cos(θ) - 9sin(θ) = 9, which represents an ellipse in the xy-plane. The limits of r correspond to the radial distance within the ellipse for each value of θ. By evaluating the double integral using these limits, we can determine the result of the given iterated integral.
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a leather store performs an observational survey of women walking through a mall. there were 30 women that walked by in an hour. of those women, 18 were carrying purses, 12 were wearing belts, and 6 were both carrying purses and wearing belts. what is the probability that a woman was wearing a belt, given that the woman was also carrying a purse?
The probability that a woman was wearing a belt given that she was also carrying a purse is 0.333 or 33.3%.
To find the probability that a woman was wearing a belt given that she was also carrying a purse, we need to use conditional probability.
We know that out of the 30 women observed, 18 were carrying purses and 6 were both carrying purses and wearing belts.
This means that the number of women carrying purses who were also wearing belts is 6.
Therefore, the probability that a woman was wearing a belt given that she was also carrying a purse is:
P(wearing a belt | carrying a purse) = number of women wearing a belt and carrying a purse / number of women carrying a purse
P(wearing a belt | carrying a purse) = 6 / 18
P(wearing a belt | carrying a purse) = 0.333
Given the information provided, we can determine the probability of a woman wearing a belt, given that she is also carrying a purse.
First, we need to find the number of women carrying a purse and wearing a belt, which is 6. There are 18 women carrying purses in total.
So, to find the probability, we will use the formula:
P(Belt | Purse) = (Number of women wearing belts and carrying purses) / (Number of women carrying purses)
P(Belt | Purse) = 6 / 18
P(Belt | Purse) = 1/3 or approximately 0.33
Therefore, the probability that a woman was wearing a belt, given that she was also carrying a purse, is 1/3 or approximately 0.33.
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What is the equation of the line that is parallel to the given line and has an x-intercept of â€""3? y = Two-thirdsx 3 y = Two-thirdsx 2 y = Negative three-halvesx 3 y = â€""Three-halvesx 2.
Equation of the line is the way to represent the line in the linear equation form by the given set of the points in the graph.The correct equation for the given problem is,
\(y=\dfrac{2}{3}x +2\)
Given-Required equation is parallel to the given line and has an x- intercept of -3.
In the graph given the two point shown are (0,-1) and (3,1).
Equation of the lineEquation of the line is the way to represent the line in the linear equation form by the given set of the points in the graph.
Here in these points the value of x changes 3 with the change in y is 2.
Thus change in y to change in x is 2/3, which is the slope of the given line. Thus slope of the given line is 2/3.
The equation the line x with b as the intercept of y and the m as the slope of the line, can be given as,
\(y=mx+b\)
As the y intercept of the given line is -3.
Thus the value of b is -3. Put the value of m and b in the above equation to solve it further,
\(y=\dfrac{2}{3}x -3\)
Now as the line is parallel, this will need to have the same slope. At x-intercept of (-3,0) y is zero.
Put this values in above equation to solve further,
\(0=\dfrac{2}{3}\times(-3) -b\)
\(b=-2\)
With this value of b we get,
\(y=\dfrac{2}{3}x +2[\)
Thus, the correct equation for the given problem is,
\(y=\dfrac{2}{3}x +2\)
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Most elements exist as components of compounds rather than in a free state. Explain why?
Most elements exist as components of compounds rather than in a free state because of their tendency to form chemical bonds with other elements.
Elements in their free state have a higher energy state and are typically more reactive. By forming compounds, elements can achieve a more stable configuration and lower their energy level.
Compounds are formed when elements chemically combine with each other through sharing, gaining, or losing electrons. This process allows the elements to achieve a full outer electron shell, which is the most stable electron configuration. This stability is achieved by following the octet rule, which states that elements tend to gain, lose, or share electrons to have eight electrons in their outermost shell (except for hydrogen and helium, which require only two electrons).
Additionally, compounds often have different properties and characteristics compared to the individual elements. This is because the chemical bonds between the elements in a compound create new structures and arrangements of atoms, resulting in unique properties. These properties make compounds valuable for various purposes, such as in medicine, technology, and industry.
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Suppose a survey of 580 women in the United States found that more than 64% are the primary investor in their household. Which part of the survey represents the descriptive branch of statistics? Make an inference based on the results of the survey.64% of women in the sample are the primary investor in their household.
There is an association between U.S. women and being the primary investor in their household.
The sentence "64% of women in the sample are the principal investor in their household" serves as an example of descriptive statistics.
What will the inference be?This sentence provides a summary of the survey's data and a descriptive statistic (percentage) that characterizes the sample's characteristics.
According to the survey's findings, "there is a correlation between American women and being the principal investor in their household." The sample data are used to draw this conclusion about the population. Despite the fact that the sample is not representative of all American women, the findings indicate that a sizable number of the women in the sample are the principal investors in their households.
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Write the slope-intercept form of the equation of the line through the given point with the givenslope.8) through: (4,4), slope = 27) through: (3,-1), slope = -2/3
Let's begin by listing out the information given to us:
slope-intercept form of the equation of the line is given by:
A company of 250 cars found that the emissions systems of 7 out of 22 they tested failed to meet pollution control guidelines.Is this evidence that more than 20% of the fleet might be out of compliance
Yes, this is evidence that more than 20% of the fleet might be out of compliance with pollution control guidelines, since the probability of observing 7 or more cars failing to meet the guidelines is less than the significance level of 0.05.
To determine if this is evidence that more than 20% of the fleet might be out of compliance, we can use a hypothesis test.
Let's assume that the null hypothesis is that 20% or fewer cars in the fleet are out of compliance with pollution control guidelines. The alternative hypothesis would be that more than 20% of the cars are out of compliance.
We can use a one-tailed hypothesis test with a significance level of 0.05.
Under the null hypothesis, we can use a binomial distribution with p = 0.20 to calculate the probability of observing 7 or more cars out of 22 failing to meet the pollution control guidelines:
P(X >= 7) = 1 - P(X <= 6)
Where X is the number of cars out of 22 that fail to meet the pollution control guidelines.
Using a binomial distribution calculator, we find:
P(X >= 7) = 0.0168
Since this probability is less than the significance level of 0.05, we can reject the null hypothesis and conclude that there is evidence that more than 20% of the fleet might be out of compliance with pollution control guidelines. However, we should note that this conclusion is based on a single sample and further testing would be needed to confirm this result.
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A shipping company uses a formula to determine the cost for shipping a package: c = 2.79 + 0.38p, where c is the cost of shipping and p is the number of pounds. What is the cost of shipping a package that weighs 8 pounds?
Using the formula they gave us:
Cost of shipping = 2.79 + 0.38(8)
Cost of shipping = 2.79 + 3.04
Cost of shipping = 5.83(currency unit)
is the standard deviation of the numbers x, y, and z equal to the standard deviation of 10, 15, and 20 ?
This matches the placement of 10, 15, and 20 and hence the standard deviation will be the same in the two cases.
What is the standard deviation?
The standard deviation in statistics is a measure of the amount of variation or dispersion in a set of values. A low standard deviation indicates that the values are close to the set's mean, whereas a high standard deviation indicates that the values are spread out over a wider range.
Standard deviation determines how far numbers deviate from the mean. The Standard deviation of the two sets will be the same if the numbers from the respective means are placed in the same order.
This is what 10, 15, and 20 will be on a number line
10_ _ _ _15 _ _ _ _20
(15 is the mean and 10 and 20 are 5 steps away from the mean)
i) Z - X = 10
This is what Z and X will be on the number line
X _ _ _ _ _ Z
ii) Z - Y = 5
This is what Z and Y will on the number line.
Y_ _ _ _ _ Z
Together, their relative placement on the number line:
X _ _ _ _ _ Y _ _ _ _ _ Z
This matches the placement of 10, 15, and 20 and hence the standard deviation will be the same in the two cases.
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Find the solution to the initial value problem 2y
′′
−5y
′
−3y=0;y(0)=−3,y
′
(0)=1 and sketch a graph of the solution. Using a graphing utility for making sketches is fine, but you must show all work in determining the solution to receive credit.
The solution to the initial value problem 2y'' - 5y' - 3y = 0, with initial conditions y(0) = -3 and y'(0) = 1, is given by \(y(x) = 2e^{3*x}-3e^{-x}\) The graph of the solution will exhibit exponential growth and decay.
To solve the given initial value problem, we assume the solution has the form \(y(x)=e^{rx}\) and substitute it into the differential equation. We obtain the characteristic equation:
\(2r^{2} - 5r -3 =0\)
Factoring the quadratic equation, we get:
(2r + 1)(r - 3) = 0
Solving for r, we find two distinct roots: r = \(-\frac{1}{2}\) and r = 3.
Therefore, the general solution to the differential equation is given by:
\(y(x) = c_{1} e^{1/2x} + c_{2} e^{3x}\)
To find the particular solution, we use the initial conditions. Applying y(0) = -3, we have:
c₁ + c₂ = -3 (Equation 1)
Next, we differentiate y(x) to find y'(x):
\(y'(x) = -\frac{1}{2} c_{1} e^{-\frac{1}{2x} } + 3c_{2} e^{3x }\)
Applying y'(0) = 1, we have:
\(-\frac{1}{2} c_{1} + 3c_{2} =1\) (Equation 2)
Solving Equations 1 and 2 simultaneously, we find c₁ = -2 and c₂ = -1.
Therefore, the particular solution is:
\(y(x) = -2e^{(-1/2x)} - e^{3x}\)
Simplifying further, we get:
\(y(x)=2e^{3x}-3e^{-x}\)
The graph of the solution will exhibit exponential growth as the term \(2e^{3x}\) dominates and exponential decay as the term \(-3e^{-x}\) takes effect.
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The results of a poll show that the percent of people who want a new restaurant is in
the interval (32%, 63%). There are 220,190 people in the city.
What is the interval for the number of people who are likely to want this restaurant
in their city?
Round to the nearest person
Enter your answer in the boxes.
The interval for the number of people who are likely to want the restaurant in their city is (70,453, 138,650).
To find the interval for the number of people who are likely to want the restaurant in their city, we need to calculate the range of values based on the given percentage range and the total population.
We have,
Percentage range: (32%, 63%)
Total population: 220,190 people
So, Lower bound = 0.32 x 220,190 = 70,452.8
and, Upper bound = 0.63 x 220,190 = 138,649.7
Therefore, the interval for the number of people who are likely to want the restaurant in their city is (70,453, 138,650).
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Annabel is comparing the distances that two electric cars can travelafter the battery is fully charged
After the battery is fully charged, Car B can go further than Car A. Car B, as compared to Car A, had lower variability measurements. After the battery is completely charged, Car B can go further than Car A since Car A has a lower mean and median. Option D is Correct.
The median splits the data in half. A lower median indicates that Car A has less mileage than Car B.
Two measurements exist.
The measure of centre reveals how closely or widely the data are dispersed around the centre.
The measurements of centre are mean, median, and mode.
Car A travelled less since it had a lower mean and median.
We can find out how data changes with a single value using the measure of variability. The data is denser at the mean when the MAD is less. The MAD in Car B is lower. Data that is closer to the centre of the data set has a smaller IQR.
IQR is lower in Car B.
Consequently, automobile B travelled steadily since its IQR and MAD were lower. Option D is Correct.
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Correct Question:
Annabel is comparing the distances that two electric cars can travel after the battery is fully charged. Car A (miles) Car B (miles) Mean 145 200 Median 142 196 IQR 8 4 MAD 6 2 Part A Use the measures of center to make an inference about the data. Use the drop-down menus to complete your answer. Car A can travel further than Car B after the battery is fully charged. Part B Based on the data, which car performs most consistently? Explain. A. Car A because the measures of center are smaller for Car A than for Car B. B. Car B because the measures of center are smaller for Car B than for Car A. C. Car A because the measures of variability are smaller for Car A than for Car B. D. Car B because the measures of variability are smaller for Car B than for Car A.