Step-by-step explanation:
T1=a
T2=ar
r=T2÷T1
r=--18÷6
r=-3
T11=ar^10
T11=6×-3^10
T11=-354294
Answer:
354294
Step-by-step explanation:
a11=6*(-3)10=354294
My brain is a rasin so yeah, help a g a i n
Answer:
Combined time: 55.316 seconds
The difference in times: 0.856 seconds
Tips:
It is addition and subtraction. A basic calculator should help with any other questions such as this one!
1/2 < -< 4/5
choose the fraction that goes in the blank
1/3
2/4
2/3
5/6
The fraction 2/3 satisfies this condition. We can confirm this by cross-multiplying 2/3 and 4/5. The result is (2 * 5) and (3 * 4), which simplifies to 10 and 12, respectively. Since 10 is less than 12, we can see that 2/3 is indeed less than 4/5.
The fraction that goes in the blank is 2/3. To understand why, let's compare the given fractions step by step.
We start with 1/2 and -< 4/5. Here, -< is used as a symbol to represent the less than sign (<). To compare fractions, we need to make sure they have a common denominator. The common denominator of 2 and 5 is 10.
So, we rewrite the fractions with a common denominator: 1/2 = 5/10 and 4/5 remains as 4/5.
Now, let's compare 5/10 and 4/5. We can do this by cross-multiplying. Cross-multiplying involves multiplying the numerator of one fraction by the denominator of the other fraction.
Cross-multiplying 5/10 and 4/5, we get (5 * 5) and (4 * 10), which simplifies to 25 and 40, respectively.
Since 25 is less than 40, we can conclude that 5/10 is less than 4/5. Therefore, the blank should be filled with a fraction that is greater than 5/10 but less than 4/5.
Out of the given options, the fraction 2/3 satisfies this condition. We can confirm this by cross-multiplying 2/3 and 4/5. The result is (2 * 5) and (3 * 4), which simplifies to 10 and 12, respectively. Since 10 is less than 12, we can see that 2/3 is indeed less than 4/5.
In conclusion, the fraction that goes in the blank is 2/3.
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Plss solve this problem... will mark brainiest
suppose there is a nonzero vector x ∈ r m such that t(x) = 0. is it possible that t is one-to-one? give an example, or explain why it’s not possible
No, it is not possible that t is one-to-one if there is a nonzero vector x ∈ Rm such that t(x) = 0.
This is because a one-to-one transformation means that each input has a unique output. If t(x) = 0 for a nonzero vector x, then there must be another vector y such that t(y) = 0 as well, since the zero vector is always in the range of a transformation. This means that t is not one-to-one, as there are multiple inputs that have the same output.
For example, consider the transformation t(x) = Ax, where A = [[1, -1], [1, -1]]. Then, for the vector x = [1, 1], t(x) = [0, 0], and for the vector y = [2, 2], t(y) = [0, 0] as well. This shows that t is not one-to-one, as there are multiple vectors that have the same output.
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Find s(t), where s(t) represents the position function, v(t) represents the velocity function, and a(t) represents the acceleration function. a(t)=−18t+8, with v(0)=1 and s(0)=7 s(t) = ___
The s(t) position function, we need to integrate the acceleration function a(t) = -18t + 8 twice with respect to t and apply the initial conditions v(0) = 1 and s(0) = 7.
Given the acceleration function a(t) = -18t + 8, we need to find the position function s(t) by integrating the acceleration function twice.
We integrate a(t) with respect to t to find the velocity function v(t):
v(t) = ∫ a(t) dt = ∫ (-18t + 8) dt = -9t^2 + 8t + C1.
We apply the initial condition v(0) = 1 to determine the constant C1:
v(0) = -9(0)^2 + 8(0) + C1 = C1 = 1.
The velocity function becomes:
v(t) = -9t^2 + 8t + 1.
We integrate v(t) with respect to t to find the position function s(t):
s(t) = ∫ v(t) dt = ∫ (-9t^2 + 8t + 1) dt = -3t^3 + 4t^2 + t + C2.
We apply the initial condition s(0) = 7 to determine the constant C2:
s(0) = -3(0)^3 + 4(0)^2 + 0 + C2 = C2 = 7.
The position function is:
s(t) = -3t^3 + 4t^2 + t + 7.
Hence, the position function s(t) represents the particle's position at time t.
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Find the value of x.
Step-by-step explanation:
Well....AD and AB are equal in length
2x+3 = 11
2x = 8
x = 4 units
1. Solve for x
X - 10 = 15
What is the slope of the line shown below?
A. -2/3
B.-3/2
C. 3/2
D. 2/3
Answer:
-2/3
Step-by-step explanation:
Una presa se construye en un rio. El nivel del agua del estanque esta dado por n = 4,5t + 28, dónde t es el tiempo en años. Traza la gráfica y determina el nivel del agua que tenía la presa al ser construida. (ayuda por favor)
The initial water level is given as follows:
28 units.
How to define a linear function?The slope-intercept representation of a linear function is given by the equation shown as follows:
y = mx + b
The coefficients m and b have the meaning presented as follows:
m is the slope of the function, representing the increase/decrease in the output variable y when the input variable x is increased by one.b is the y-intercept of the function, representing the numeric value of the function when the input variable x has a value of 0. On a graph, it is the value of y when the graph of the function crosses or touches the y-axis.The function for this problem is defined as follows:
n = 4.5t + 28.
The intercept is of b = 28, representing the initial amount of water.
The graph is given by the image presented at the end of the answer.
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What is the quotient of 3.243 x 10^8 and 7.05 x 10^2
Answer:
4,600,000,000
Step-by-step explanation:
Don't forget the order of operations
3.243 × 10⁸/7.05
= 46,000,000 × 10²
= 4,600,000,000
or 4.6 × 10⁹
Answer:
4.6x10 to the power of 5
Step-by-step explanation:
7.05×10
2
3.243×10
8
Divide them.
\frac{3.243}{7.05}\times \frac{10^8}{10^2}
7.05
3.243
×
10
2
10
8
Divide numbers and 10's separeately.
0.46\times 10^6
0.46×10
6
Subtract exponents.
(4.6\times 10^{-1})\times 10^6
(4.6×10
−1
)×10
6
Rewrite as a number bigger than 1
4.6\times (10^{-1}\times 10^6)
4.6×(10 −1 ×10 6 )
Associate
4.6\times 10^5
4.6×10 5
Add exponents
A, B, and Care the centers of the 3 circles. Select all thesegments that are congruent to AB.
The congruent segments are the sides of the small triangles, then the congruent segments are: HA, BD and BF.
Therefore the answer are B, E and F.
2 1/7:(15a)=5/14:(0.8)
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
Draw 3 parallel streets. Change the color of all three streets to RED
Draw two lines that Intersect the RED lines but are NOT perpendicular to them. Make the slope of one positive and the other negative. Change these colors to blue
Draw two lines that ARE perpendicular to the parallel lines. Change the colors of both of these lines to ORANGE.
Pls help
One line slope upwards with a positive slope, and the other slope downwards with a negative slope. Color both lines blue.
To draw three parallel streets, use a ruler or a straight edge and draw three straight lines that are equidistant from each other and have the same slope.
Then, using a red marker, color all three of the streets red.
Draw three parallel lines horizontally across the page and color them red.
Draw two diagonal lines that intersect the red lines at different angles, but are not perpendicular.
Make one line slope upwards with a positive slope, and the other slope downwards with a negative slope. Color both lines blue.
Draw two vertical lines that intersect the red lines at right angles.
These lines should be perpendicular to the parallel lines. Color both lines orange.
Next, to draw two lines that intersect the red lines but are not perpendicular to them, you can draw two diagonal lines. One of these lines should have a positive slope, and the other should have a negative slope.
Use a blue marker to color both of these lines blue.
Finally,
To draw two lines that are perpendicular to the parallel streets, you can use a T-square or another tool that helps you draw perpendicular lines.
Draw two straight lines that are perpendicular to the parallel streets, one on each side. Use an orange marker to color both of these lines orange.
In summary,
To complete this task, you will need a ruler or a straight edge, a blue marker, a red marker, and an orange marker. Follow these steps to draw three parallel streets, intersecting lines that are not perpendicular, and two perpendicular lines, making sure to use the appropriate colors for each line.
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What is the length of the hypotenuse of a triangle with vertices at(6,−9),(6,−10),and(10,−10)?
A. 10.82
B. 4.12
C. 3.61
D. 5.1
Answer:4.12
Step-by-step explanation: I need brainliest for next rank I’d appreciate it
Are these congrent? Based, on the picture.
A. BE≅DE
B. ∠BEC≅∠DEC
C. △AEB≅△AED
D. BE≅CE
Answer:
Step-by-step explanation:
The answer is B I think
What is the dependent variable
Answer:
The independent variable is the depth of the submarine
Step-by-step explanation:
Hope this helps
If is between 4 and 5, then x is _____. greater than 2 and less than 3 greater than 4 and less than 5 greater than 8 and less than 10 greater than 16 and less than 25
Answer:
between 4 and 5, also 4<5
=>4<x<5
=>greater than 4 and less than 5
Answer:
I think its 6
Step-by-step explanation:
If 4 less than 5 then 6 is Greater than 3.
So 6 is the blank
Hope this helps
Calculate.
о Са
9
Note: Cr = (-)!
n!
n
\(_9C_4=\dfrac{9!}{4!5!}=\dfrac{6\cdot7\cdot8\cdot9}{2\cdot3\cdot4}=126\)
A grocery store purchases cantaloupes from two warehouses, A and B. The
distribution of the diameters from Warehouse A is approximately normal with a
mean of 120 mm and standard deviation of 6 mm.
(a) For a cantaloupe selected at random from Warehouse A, what is the
probability that the cantaloupe will have a diameter greater than 127 mm?
A randomly selected cantaloupe from Warehouse B has the probability of 0.763
that it will have a diameter greater than 127 mm. The grocery store purchases
40% of their cantaloupes from Warehouse B.
(b) For a cantaloupe selected at random from the grocery store, what is the
probability that the cantaloupe will have a diameter greater than 127 mm?
(c) If the randomly selected cantaloupe's diameter is greater than 127 mm, what
is the probability the cantaloupe came from Warehouse B?
A: The probability of cantaloupe having dia. more than 127 is 0.12167.
B: Cantaloupe selected at random from the warehouse, then the probability that has a diameter of more than 127 mm is 0.3782.
C: The probability that the cantaloupe will be from warehouse B given randomly selected cantaloupe's diameter is greater than 127 mm, is 0.8069.
What is probability?The probability formula is defined as the possibility of an event happening being equal to the ratio of the number of favorable outcomes and the total number of outcomes. Probability is a measure of the likelihood of an event occurring. Also, the favorable number of outcomes cannot be negative.
Given two warehouses, A and B
mean for warehouse A = μ = 120 mm
The standard deviation for warehouse A = σ = 6mm
A: a cantaloupe selected at random from Warehouse A
to find the probability of cantaloupe having a diameter greater than 127 mm = P(x > 127)
P(x > 127) = 1 - P(x ≤ 127)
P(x ≤ 127) = P((x - μ)/σ)
P(x ≤ 127) = P((127 - 120)/6)
P(x ≤ 127) = P(z ≤ 1.66)
P(x ≤ 127) = 0.87833
P(x > 127) = 1 - P(x ≤ 127)
P(x > 127) = 1 - P(x < 127) = 0.12167
probability of cantaloupe having dia. more than 127 is 0.12167.
B: Let event A for distributor A and let event B for distributor B
and event C for a diameter greater than 127 mm.
and given A randomly selected cantaloupe from Warehouse B has a probability of 0.763 that it will have a diameter greater than 127 mm,
and the percentage of cantaloupe provided by B is 40%
rest 60% for A,
therefore, for cantaloupe selected at random, the probability of having a diameter greater than 127 mm is
P(C) = P(C|A)P(A) + P(C|B)P(B)
= 0.12167(0.6) + 0.763(0.4)
= 0.073 + 0.3052
P(C) = 0.3782
cantaloupe selected at random from the warehouse, then the probability that has a diameter of more than 127 mm is 0.3782.
C: the probability the cantaloupe came from Warehouse B, given that the randomly selected cantaloupe's diameter is greater than 127 mm,
P(B|C) = P(B ∩ C)/P(C)
P(B|C) = (P(C|B)P(B))/P(C)
substitute values
P(B|C) = ((0.763)(0.4))/0.3782
P(B|C) = 0.3052/0.3782
P(B|C) = 0.8069
The probability that the cantaloupe will be from warehouse B given randomly selected cantaloupe's diameter is greater than 127 mm, is 0.8069.
Hence the probabilities are,
A; 0.12167
B; 0.3782
C; 0.8069.
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Two angles form a linear pair. The measure of one angle is x and the measure of the other angle is 1.4 times x plus 12∘ . Find the measure of each angle.
Answer:
70° and 110°
Step-by-step explanation:
If two angles forms a linear pair, this means that the sum of the angles is 180°. If the measure of one angle is x and the measure of the other angle is 1.4 times x plus 12∘
Let A be the first angle = x°
Let B be the second angle = (1.4x+12)°
Since they form a linear pair, then
A+B = 180°
x + 1.4x+12 = 180°
2.4x = 180-12
2.4x = 168
x = 168/2.4
x = 70°
The measure of angle A = 70°
The measure if angle B = 1.4x+12
B = 1.4(70)+12
B = 98+12
B = 110°
The measure of both angles are 70° and 110°
9. Name the four basic logic gates.
The four basic logic gates are AND, OR, NOT, and XOR.
1. AND Gate: This gate takes two or more inputs and produces an output of 1 (true) only if all the inputs are 1 (true).
2. OR Gate: This gate takes two or more inputs and produces an output of 1 (true) if at least one of the inputs is 1 (true).
3. NOT Gate (Inverter): This gate has only one input and inverts it, producing an output of 1 (true) if the input is 0 (false) and vice versa.
4. XOR Gate (Exclusive OR): This gate takes two inputs and produces an output of 1 (true) if either, but not both, of the inputs are 1 (true).
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the length of each side of a square is 3 inches more than the length of each side of a smaller square. the sum of the areas of the squares is 149 inches squared. find the length of the side of the smaller square.
The length of the side of the smaller square is 7 inches.
Let x be the length of the side of the smaller square.
The length of each side of a square is 3 inches more than the length of each side of a smaller square. Thus the length of the side of the larger square is
(x + 3) inches.
The area of the smaller square is
x^2 square inches.
The area of the larger square is
(x + 3)^2 square inches.
We can set up the equation:
x^2 + (x + 3)^2 = 149
Expanding and simplifying the equation gives:
x^2 + x^2 + 6x + 9 = 149
Combining like terms:
2x^2 + 6x - 140 = 0
Using the quadratic formula, we can solve for x:
x = (-b ± √(b^2 - 4ac)) / 2a
x = (-6 ± √(6^2 - 4 * 2 * (-140))) / 2 * 2
x = (-6 ± √(36 + 1120)) / 4
x = (-6 ± √(1156)) / 4
x = (-6 ± √(596)) / 4
x = (-6 ± 34) / 4
x = -10 or x = 7
The side length of the smaller square can't be negative, so x = 7 inches.
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A certain factory manufactures parts with an unknown defect rate of p. Inspectors take a small sample of parts and find a total of 2 defective parts and 8 working parts.
(a) What is the Beta distribution that you would use to model p, the true defect rate?
(b) Using the distribution you found, find P(.15 ≤p ≤.25).
(c) The inspectors take another sample. In this sample, they find 1 defective part and 9 working parts. Combining this sample with the previous inspection, what is the new Beta distribution that you would use to model p?
(d) Repeat part (b) for this new Beta distribution.
(a) The Beta distribution that is commonly used to model the true defect rate p is the Beta-Binomial distribution.
It is a combination of the Beta distribution, which represents the uncertainty in the true defect rate, and the Binomial distribution, which represents the number of defectives in a fixed sample size. The parameters of the Beta distribution, α and β, determine the shape of the distribution and can be estimated based on the observed data.
(b) To find P(0.15 ≤ p ≤ 0.25), we need to calculate the cumulative distribution function (CDF) of the Beta distribution with the given parameters α and β. The CDF represents the probability that the true defect rate is less than or equal to a certain value. By evaluating the CDF at p = 0.25 and subtracting the CDF at p = 0.15 from it, we can obtain the desired probability.
(c) When combining the two samples, the new Beta distribution for modeling p can be obtained by updating the parameters α and β based on the additional observations. In this case, with a total of 3 defective parts and 17 working parts (2 + 1 defective and 8 + 9 working), we can calculate the new values of α and β.
(d) Similar to part (b), we can use the updated parameters of the Beta distribution to calculate the probability P(0.15 ≤ p ≤ 0.25) for the new distribution. By evaluating the CDF of the updated Beta distribution at p = 0.25 and subtracting the CDF at p = 0.15 from it, we can determine the probability of the true defect rate falling within the specified range.
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4(46 + 3) + 2b = 3 (6 - 11)
Answer:
\(4(46 + 3) + 2b = 3(6 - 11) \\ 184 + 12 + 2b = 18 - 33 \\ 196 + 2b = - 15 \\ 2b = - 15 - 196 \\ \frac{2b}{2} = \frac{ - 211}{2} \\ b = - 105.5\)
The table shows the length, in inches, of fish in a pond.
11 19 9 15
7 13 15 28
Determine if the data contains any outliers. If so, list the outliers.
There is an outlier at 28.
There is an outlier at 7.
There are outliers at 7 and 28.
There are no outliers.
In the table that shows the length, in inches, of fish in a pond, there are no outlier.
we know, a value that differs significantly from the other values in a dataset is an outlier in mathematics. Measurement errors, data entry errors, or extreme results that are actually outliers from the majority of the data can all lead to outliers.
Here according to question,
A box-and-whisker plot, which depicts the distribution of a dataset by presenting the minimum, first quartile, median, third quartile, and maximum values, is one method for identifying outliers.
Thus, there are no outlier.
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The side lengths 7, 10, 16 will form a triangle?
True or False
Answer:
true that you pretty but, dont date me bc i have a gf
Step-by-step explanation:
Answer:
true( I'm sowwie if this is wrong):(
the total weight of 3 puppies is 2 pounds 4 ounces. how much does puppy weight in ounces. convert to ounces
Answer:
60 ounces
Step-by-step explanation:
there are 16 ounces in a pound plus the extra 4 ounces times 3 is 60 ounces in total
Chase wants to earn at least $900 this month in commission. What is the minimum amount he needs to sell in order to earn $900 if he earns a 3.3% commission on everything he sells? Round to the nearest dollar.
Answer:
$27,272.73= sales
Step-by-step explanation:
Giving the following information:
Desired commission= $900
Commission rate= 3.3% = 0.033 of sales
To calculate the sales required, we need to use the following formula:
Commission= sales*commission rate
900= sales*0.033
900/0.033= sales
$27,272.73= sales
Answer: $27,273
Step-by-step explanation: 900a=3.3100 Write the proportion. Let a represent the amount he needs to sell.
900a=3.3100 Because 3.3×272.72=900 , multiply 100 by 272.72 to find a.
90027.271=3.3100 100 × 272.72 ≈ 27,273, so a = 27,273.
Chase needs to sell $27,273 to earn $900 in commission.
exponent rules: (6m⁸n⁹) (4mn⁷) = ?
please help
The value of the given equation is, (6m⁸n⁹) (4mn⁷) =\($$=24 m^9 n^{16}$$\)
What is exponent rules?(am)n = am*n is the exponent power rule. Exponent times power is how you raise a number with an exponent to a power. The x-n = 1/xn Negative Exponent Rule. A negative exponent can become positive by inverting the base. According to the first law, adding the exponents will multiply two exponential functions with the same base. According to the second law, we must subtract the exponents when dividing two exponential functions with the same base. The third law indicates that we must multiply the exponents in order to increase a power to a new power.Simplify\($\left(6 m^8 n^9\right)\left(4 m n^7\right): \quad 24 m^9 n^{16}$\)
steps
\($$\left(6 m^8 n^9\right)\left(4 m n^7\right)$$\)
Apply exponent rule: \($a^b \cdot a^c=a^{b+c}=0^{\prime}=$\)
\(& m^8 m=m^{8+1} \\\)
\(& =6 n^9 \cdot 4 m^{8+1} n^7\)
\end{aligned}
Add the numbers: \($8+1=9$\)
\(=6 n^9 \cdot 4 m^9 n^7\)
Apply exponent rule: \($a^b \cdot a^c=a^{b+c}$\)
\(& n^9 n^7=n^{9+7} \\\)
\(& =6 \cdot 4 m^9 n^{9+7}\)
Add the numbers: \($9+7=16$\)
\($$=6 \cdot 4 m^9 n^{16}$$\)
Multiply the numbers: 6 - \($4=24$\)
\($$=24 m^9 n^{16}$$\)
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Choose the histogram that has the smallest variance.
The histogram first represents the smallest variance option first is correct.
What is a histogram?It is defined as the depiction of numerical data in a graph using a bar with no space. The histogram depicts the approximate distribution of the data.
We have four histograms shown in the picture.
As we know in a histogram, the curves that resemble hills show groupings of statistics that are close collectively, leading to low variation.
Whenever the taller bars are farther away from the mean in a histogram, the variability is greater, and when the taller bars are closer to the mean, the variability is less.
In the histogram first, there is very less variability.
Thus, the histogram first represents the smallest variance option first is correct.
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