Find midpoint of 1,-3 and -1,-1

The csc(theta) = 1/sin(theta) = 1/(-2/√13) = -√13/2. So, the cosecant of theta is -√13/2.

To find the cosecant (csc) of theta when a point (-3, -2) lies on its terminal side, we need to determine the hypotenuse (r) of the right triangle formed by this point.

Using the Pythagorean theorem, r^2 = (-3)^2 + (-2)^2. So, r^2 = 9 + 4 = 13, and r = √13.

The csc(theta) is the reciprocal of sin(theta). Sin(theta) is calculated as the ratio of the opposite side (y-coordinate) to the hypotenuse, or sin(theta) = -2/√13.

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Answer:

x=4

x=-9

Step-by-step explanation:

Answer:

See below

Step-by-step explanation:

$ (585.25 -54) / 4.25  hr   = x = $ 125 / hr

Answer:

angle L is 35 degrees

angle A is 55 degrees

Step-by-step explanation:

angle L is congruent to angle C, and it is given that angle C is 35

angle A is congruent to angle N, and it is given that angle C is 55

Answer:

domain: -7, -1, 0, 1

Range: -1, 0, 1, 2, 7

Step-by-step explanation:

I don't know the drop-down menu choices so I can't answer that one for you sorry :(

But I hope this helps :)

Answer:

Here you go

Ans is in pictures.

Answer:

D.

Step-by-step explanation:

This is the only one that sounds correct

Answer:

i  cant read it oh i zoomed in B

Step-by-step explanation:

Answer:

The answer is b. 35.5

Step-by-step explanation:

angle bisector always bisects an angle in to half amd in the question you have been told to tell the value of one half of the angle abc so the half of 71 would be 35.5

Answer:

15% of 25

Step-by-step explanation:

Given the following questions:

25% of 15
15% of 25

We find the answer by using the formula to calculate percentage for both questions.

Question one:
\(\frac{p\times n}{100}\)
\(\frac{25\times15}{100} =25\times15=375\div100=3.75\)
\(=3.75\)

25% of 15 is 3.75

Question two:
\(\frac{p\times n}{100}\)
\(\frac{15\times 25}{100}=15\times25=375\div100=3.75\)
\(=3.75\)

15% of 25 is 3.75

Finally:
\(3.75=3.75\)

\(15-3.75=11.25\)
\(25-3.75=21.25\)
\(11.25 < 21.25\)

Which means 15% of 25 is "greater than" 25% of 15.

Hope this helps.

The new coordinate of point D is Option A which is ( -6 , -4 )

The coordinates of point D from the figure is (-4,-4)

The all possible cases to move the figure 2 units is as following:

If the figure is moved two units right point D will be (-2,-4)

If the figure is moved two units left point D will be (-6,-4)

And if it is moved two units up point D will be (-4,-2)

also if it is moved two units down point D will be (-4,-6)

By checking the given options, we will find that:

The options b , c and d is not at the previous possible cases

So, the answer is option a. (-6,-4)

Which mean the figure is moved two units left

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Answer: Line c is a transversal line.

Step-by-step explanation: A transversal is a line that crosses at least two other lines. In this case, line c crosses lines a and b.

Answer:

Step-by-step explanation:

x-intercept is where the line cuts the x-axis. That is, when y=0.

Substitute y=0 and we get:

       \(0=\frac{1}{3} x-1\)

       \(1=\frac{1}{3} x\)

       \(x=3\)

So x-intercept is the point (3,0).

Answer:

26

Step-by-step explanation:

A (+) and a (-) will always be a minus, so 48+(-22) becomes 48 - 22, which equals 26.

Answer:

26.

Step-by-step explanation:

48 - 22 = 26.

Answer:

5/6

Step-by-step explanation:

Answer:

x+x+3+3

Step-by-step explanation:

You have to cancel out the variables and numbers.

Answer:

$506

Step-by-step explanation:

We know that 1 concert ticket is $23

Multiply 23 by 22 to get 506

They spend $506 in total for the tickets.

The total cost for a group of 22 people is $506 if a concert ticket costs $23. , the answer is $506.

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

A concert ticket costs $23.

Let x be the total cost for the group of 22 people:

The value of x can be found as follows:

The linear equation in one variable:

x = 23×22

x = $506

Thus, the total cost for a group of 22 people is $506 if a concert ticket costs $23. , the answer is $506.

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Answer:

Angle B and Angle D are both 101 degrees

Step-by-step explanation:

Consecutive Angles in a parallelogram are supplementary (add up to 180 degrees).

Given that fact, we can deduce the measure of angle B.

180-79=101.

Angle D has the same setup since Angle D and C are consecutive along with Angle C and B.

180-79=101.

Therefore, both Angle B and D are 101 degrees.

Answer:t=5

Step-by-step explanation:

Distribute, add numbers and rearrange terms.

Answer:

9t-27=10t+5-6t+18

9t-10t-27-5= -6t+18

-t-32= -6t+18

5t-50=0

5(t-10)=0

therefore, t=5

Answer:

36

Step-by-step explanation:

Angles in a triangle sum to 180 degrees.

The angle in the bottom left will equal 180 - (3x + 6) as angles along a staight line also sum to 180 degrees.

180 - ( 3x + 6)

180 - 3x - 6   [expand bracket]

174 - 3x

Now we can add up all the angles and equate them to 180 to solve for x.

24 + 2x + 18 + 174 - 3x = 180

216 - x = 180

216 = 180 + x

x = 36

We have proved that the Newton-Raphson iteration formula for solving the equation\(x^k e^x = 0\) is given by \(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.\)

To prove that the Newton-Raphson method for solving the equation \(x^k e^x = 0\), where k is a constant, is given by the formula

\(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n,\)

we can start by considering the iterative process of the Newton-Raphson method.

Given an initial guess \(x_n\), we want to find a better approximation \(x_{n+1}\)that is closer to the root of the equation \(x^k e^x = 0.\)

The Newton-Raphson method involves the following steps:

Calculate the function value \(f(x_n) = x_n^k e^x_n\) and its derivative \(f'(x_n) = k x_n^(k-1) e^x_n.\)

Find the next approximation x_{n+1} by using the formula:

\(x_{n+1} = x_n - f(x_n) / f'(x_n)\)

Let's apply these steps to our equation \(x^k e^x = 0\):

Calculate the function value and its derivative:

\(f(x_n) = x_n^k e^x_n\\f'(x_n) = k x_n^(k-1) e^x_n\)

Find the next approximation x_{n+1} using the formula:

\(x_{n+1} = x_n - f(x_n) / f'(x_n)\)

Substituting the function value and its derivative:

\(x_{n+1} = x_n - (x_n^k e^x_n) / (k x_n^(k-1) e^x_n)\\= x_n - (x_n^k / k)\)

Simplifying the expression by combining like terms:

\(x_{n+1} = x_n - (x_n^k / k)\\= x_n - x_n^k / k\\= (k - 1) x_n + x_n^2 / k + x_n\)

Therefore, we have proved that the Newton-Raphson iteration formula for solving the equation\(x^k e^x = 0\) is given by \(x_{n+1} = (k - 1) x_n + x_n^2 / k + x_n.\)

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The value of x in the angles is 19.

When lines intersect, angle relationships are formed such as vertically opposite angles, adjacent angles etc.

Therefore, let's find the value of x in the intersecting lines.

Hence,

7x - 8 = 6x + 11 (vertically opposite angles)

Vertically opposite angles are congruent and they share the same vertex point.

Hence,

7x - 8 = 6x + 11

subtract 6x from both sides of the equation

7x - 8 = 6x + 11

7x - 6x - 8 = 6x - 6x + 11

x - 8 = 11

add 8 to both sides of the equation

x - 8 + 8 = 11 + 8

x = 19

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Answer:

-78-(-34)+(-14)

Step-by-step explanation:

-78+(+34)+(-14)

-78-14

-92+34

-58

And thats the answer needed there for it would be the last expression.

The graph of the function y = 5|x - 4| is added as an attachment

From the question, we have the following parameters that can be used in our computation:

y = 5|x - 4|

The above function is an absolute value function that has been transformed as follows

Next, we plot the graph using a graphing tool by taking not of the above transformations rules

The graph of the function is added as an attachment

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The length of the third side of the triangle, to the nearest hundredth, is approximately 54.75 units.

1. We have a triangle with two known side lengths: 43 and 67 units.

2. The angle included between these sides measures 27 degrees.

3. To find the length of the third side, we can use the Law of Cosines, which states that \(c^2 = a^2 + b^2\) - 2ab * cos(C), where c is the third side and C is the included angle.

4. Plugging in the known values, we get \(c^2 = 43^2 + 67^2\) - 2 * 43 * 67 * cos(27).

5. Evaluating the expression on the right side, we get \(c^2\) ≈ 1849 + 4489 - 2 * 43 * 67 * 0.891007.

6. Simplifying further, we have \(c^2\) ≈ 6338 - 5156.898.

7. Calculating \(c^2\), we find \(c^2\) ≈ 1181.102.

8. Finally, taking the square root of \(c^2\), we get c ≈ √1181.102 ≈ 34.32.

9. Rounding to the nearest hundredth, the length of the third side is approximately 34.32 units.

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An order-preserving function is one where x < y implies f(x) < f(y). An isomorphism is a one-to-one order-preserving function between two partially ordered sets, while an automorphism is an isomorphism of a set to itself.

In the given excerpt, it explains the concepts of order-preserving functions, isomorphisms, and automorphisms in the context of partially ordered sets.

Order-Preserving Function:

A function f: P -> Q, where P and Q are partially ordered sets, is said to be order-preserving if for any elements x and y in P, if x < y, then f(x) < f(y). In other words, the function preserves the order relation between elements in P when mapped to elements in Q.

Increasing Function:

If P and Q are linearly ordered sets, then an order-preserving function is also referred to as an increasing function. It means that for any elements x and y in P, if x < y, then f(x) < f(y).

Isomorphism:

A one-to-one function f: P -> Q is called an isomorphism of P and Q if it satisfies two conditions:

a. f is order-preserving: For any elements x and y in P, if x < y, then f(x) < f(y).

b. f is onto (surjective): Every element in Q has a pre-image in P.

When an isomorphism exists between (P, <) and (Q, <), it means that the two partially ordered sets have a structure that is preserved under the isomorphism. In other words, they have the same ordering relationships.

Automorphism:

An automorphism of a partially ordered set (P, <) is an isomorphism from P to itself. It means that the function f: P -> P is both order-preserving and bijective (one-to-one and onto). Essentially, an automorphism preserves the structure and order relationships within the same partially ordered set.

These concepts are fundamental in understanding the relationships and mappings between partially ordered sets, particularly in terms of preserving order, finding correspondences, and exploring the symmetry within a set.

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