find all values of x that are not in the domain of f. if there is more than one value, separate them with commas.

If the average annual stock return is 11. 3%, the average holds a portfolio of $8600 worth 30 years.

It's the ratio of two integers stated as a fraction of a hundred parts. It is a metric for comparing two sets of data, and it is expressed as a percentage using the percent symbol.

The usage of percentages is widespread and diverse. For instance, numerous data in the media, bank interest rates, retail discounts, and inflation rates are all reported as percentages. For comprehending the financial elements of daily life, percentages are crucial.

It is given that, the average annual stock return is 11. 3% and you begin your investment portfolio with $2,000,

Suppose the amount he earns in one year is x,

x=  11. 3%. of $2,000

x=220

The portfolio be worth 30 years if the average holds are,

=220 × 30

=$ 6600

The net cost is the sum of the return and the initial investment,

=$ 6600 + $ 2000

=$8600

Thus, if the average annual stock return is 11. 3%, the average holds a portfolio of $8600 worth 30 years.

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A. From the statistical results, Jack can conclude that there is a statistically significant difference between the life satisfaction of older adults and middle-aged adults. This is evidenced by the t-value of 2.03 and p-value of .047, which fall below the standard cutoffs for statistical significance. The 95% confidence interval also supports this conclusion, as it does not include zero.

B. Based on these results, Jack should reject the null hypothesis and accept the alternative hypothesis that there is a difference in life satisfaction between older adults and middle-aged adults.

C. The "t(58) = 2.03" indicates the t-value of the statistical test, which is a measure of the difference between the means of the two groups divided by the standard error of that difference. In this case, the t-value of 2.03 suggests that the difference in life satisfaction between the two groups is larger than would be expected by chance.

D. The confidence interval tells us that there is a 95% chance that the true difference in life satisfaction between the two groups falls within the range of 0.01 to 1.59. This suggests that the difference between the two groups is likely not due to chance.

E. The effect size (d = .52) tells us that the difference in life satisfaction between the two groups is moderate in magnitude. This suggests that the difference is not only statistically significant but also practically meaningful.

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Answer:

10,

Step-by-step explanation:

The bottom right angle is 45 degrees so the top left must also be 45 degrees (180 - 45 - 90 = 45). This means that x is the same as the left side: 10.

The triangle is right angled so we can use pythagoras on it: x^2 + 10^2 = y^2 = 200

y = √200 = √100√2=10√2

Answer:

X^8 / 256y^20

Step-by-step explanation:

First to make your life easier with this problem reduce the fraction 5/20 = 1/4

x^3/x = x^3-1= x^2

Then you apply the outer exponent

X^2*4 = X^8

4^4= 256

y^5*4 = y^20

X^8 / 256y^20

Answer: Stem and leaf plots have one advantage over histograms-- they display the original data, while histograms merely summarize them.

Step-by-step explanation:

​Stem-and-leaf plots contain original data values while histograms do not.

In order to categorise discrete or continuous variables, a stem and leaf plot, also known as a stem plot, is used. Data collection and organisation are done using a stem and leaf plot.

A bar graph is a good analogy for a stem and leaf plot. Because every number in the data is divided into a stem and a leaf, the name stem and leaf was chosen. The number's entirety - all but the final digit—is contained in the stem. There will always be one digit in the number's leaf. A stem and leaf plot's main benefit is the grouping of the data and the display of all the original data.

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Answer:

This should be 0,1

Step-by-step explanation:

I can barely see the graph bit it should be 0,1

Answer:

145.17 minutes.

Step-by-step explanation:

I divided 1000/3 and got 33.34. Then I divided 4,840 by 33.34. This made me get 145.17 minutes so that will be your answer :)

Answer:

24,200 acres .

Step-by-step explanation:

4840 times 5 = 24,200

The mean of this sample of car prices can be calculated by adding all the prices and dividing by the total number of dealers:

($35,700 x 2) + ($35,900 x 1) + ($36,200 x 3) + ($37,400 x 2) + ($37,900 x 2) = $326,500

$326,500 / 10 dealers = $32,650 (mean price)

To calculate the standard deviation, we first need to find the variance:

1. Subtract the mean from each individual price:

($35,700 - $32,650) = $3,050
($35,700 - $32,650) = $3,050
($35,900 - $32,650) = $3,250
($36,200 - $32,650) = $3,550
($36,200 - $32,650) = $3,550
($36,200 - $32,650) = $3,550
($37,400 - $32,650) = $4,750
($37,400 - $32,650) = $4,750
($37,900 - $32,650) = $5,250
($37,900 - $32,650) = $5,250

2. Square each of these differences:

$3,050^2 = $9,302,500
$3,050^2 = $9,302,500
$3,250^2 = $10,562,500
$3,550^2 = $12,602,500
$3,550^2 = $12,602,500
$3,550^2 = $12,602,500
$4,750^2 = $22,562,500
$4,750^2 = $22,562,500
$5,250^2 = $27,562,500
$5,250^2 = $27,562,500

3. Add up all of these squared differences:

$9,302,500 + $9,302,500 + $10,562,500 + $12,602,500 + $12,602,500 + $12,602,500 + $22,562,500 + $22,562,500 + $27,562,500 + $27,562,500 = $167,052,500

4. Divide the total by the number of dealers minus 1 (this is called the sample variance):

$167,052,500 / 9 = $18,561,388.89

5. Take the square root of the sample variance to get the standard deviation:

√$18,561,388.89 = $4,307.17 (standard deviation)

So the mean price of this sample of car prices is $32,650 and the standard deviation is $4,307.17.

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The Wronskian of the given solutions is W = 6e7t - e7t.

The Wronskian is a determinant used to determine the linear independence of a set of functions. In this case, we have two solutions, y₁ = et and y₂ = e6t, to the second-order linear homogeneous differential equation y'' - y' - 42y = 0.

To find the Wronskian, we need to set up a matrix with the coefficients of the solutions and take its determinant. The matrix would look like this:

| et     e6t   |

| et      6e6t |

Expanding the determinant, we have:

W = (et * 6e6t) - (e6t * et)

 = 6e7t - e7t

Therefore, the Wronskian of the given solutions is W = 6e7t - e7t.

Learn more about the Wronskian:

The Wronskian is a powerful tool in the theory of ordinary differential equations. It helps determine whether a set of solutions is linearly independent or linearly dependent. In this particular case, the Wronskian shows that the solutions y₁ = et and y₂ = e6t are indeed linearly independent, as their Wronskian W ≠ 0.

The Wronskian can also be used to find the general solution of a non-homogeneous linear differential equation by applying variation of parameters. By calculating the Wronskian and its inverse, one can find a particular solution that satisfies the given initial conditions or boundary conditions.

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Step 3:

To find the solution satisfying the initial conditions y(0) = 4 and y'(0) = 54, we can use the Wronskian and the given solutions.

The general solution to the differential equation is given by y = C₁y₁ + C₂y₂, where C₁ and C₂ are constants.

Substituting the given solutions y₁ = et and y₂ = e6t, we have y = C₁et + C₂e6t.

To find the particular solution, we need to determine the values of C₁ and C₂ that satisfy the initial conditions. Plugging in y(0) = 4 and y'(0) = 54, we get:

4 = C₁(1) + C₂(1)

54 = C₁ + 6C₂

Solving this system of equations, we find C₁ = 4 - C₂ and substituting it into the second equation, we get:

54 = 4 - C₂ + 6C₂

50 = 5C₂

C₂ = 10

Substituting C₂ = 10 into C₁ = 4 - C₂, we find C₁ = -6.

Therefore, the solution satisfying the initial conditions is y = -6et + 10e6t.

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The CPI increased by 2.78%.

Thus, the purchasing power of household income decreased between 2007 and 2008. Therefore, the correct option is D. 1.02%; fell.

Between 2007 and 2008, the cost of living in this economy increased by 2.78% (choose the closest answer), and the purchasing power of household income decreased between 2007 and 2008.

What is CPI:

CPI stands for consumer price index.

It is a measure of the change in prices of a specified set of goods and services in a particular country.

It calculates the change in prices of goods and services purchased by households.

CPI is calculated by comparing the prices of a basket of goods in a base year to their prices in the current year.

Therefore, the increase in CPI from 180 to 185 means that the price level of the basket of goods and services consumed in the economy increased by 2.78 percent (calculated as [(185-180)/180] x 100).

The household income rose by 3% in this period.

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Model reef can sustain 20% net fishing  because the species didn’t increase as much as it did with the other net fishing method.

Explanation:

What is reef fishing ?

Reef fishing is commonly called “Bottom Bouncing” where anglers using heavy 60-100lb handline and rod techniques to target such prized eating fish as Coral Trout, Red Emperor and Nannygai.

What is net fishing ?

A fishing net is a net used for fishing. Nets are devices made from fibers woven in a grid-like structure. Some fishing nets are also called fish traps, for example fyke nets.

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Answer:

I THINK is (57°) if it wrong im sorry.

Answer:

$16

Step-by-step explanation:

20% is the same as 0.2 in decimal form, since its decreasing you multiply $20 by 0.8 to get 16. If it was increasing, it would be 20 times 1.2

Answer:

$16.00

Step-by-step explanation:

This is the answer because:

1) Since the price decreases by 20%, we have to first figure out what 20% of $20 is:

20% of $20 = 4

2) Next, we just have to subtract 4 from 20 so we can find out how much the cost is:

$20.00 - 4 = $16.00

Therefore, the answer is $16.00.

Hope this helps! :D

Yes, there exists a function f that satisfies the given conditions: f(0) = 21, f(2) = 4, and f(9(x)) < 2 for all x.

f(x) = { 21, if x = 0
        4, if x = 2
        (2/9)x, otherwise

To construct this function, we can use piecewise linear functions. Let's define the function f as follows:
f(x) = { 21, if x = 0
        4, if x = 2
        g(x), otherwise
where g(x) is a function that satisfies the inequality f(9(x)) < 2 for all x.
Step 1: Define a function g(x) for the inequality f(9(x)) < 2 for all x:
Since we need f(9(x)) < 2 for all x, we can define g(x) as a linear function with a slope less than 2/9.
g(x) = (2/9)x
Step 2: Combine f(x) and g(x) to create the desired function:
Now, we can redefine our function f(x) by combining the conditions for f(0), f(2), and g(x):
f(x) = { 21, if x = 0
        4, if x = 2
        (2/9)x, otherwise
This function satisfies all the given conditions. It has f(0) = 21, f(2) = 4, and f(9(x)) = (2/9)(9x) = 2x < 2 for all x (since x can be any real number).

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Answer:

Step-by-step explanation:

\(\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(1,\:-2\right),\:\\\left(x_2,\:y_2\right)=\left(3,\:6\right)\\\\m=\frac{6-\left(-2\right)}{3-1}\\\\m = \frac{6+2}{3-1}\\ \\m = \frac{8}{2} \\\\Simplify\\\\Slope = m = 4\)

Based on the given information, Mrs. Cheng's class lost fewer pencils overall based on the data displayed.

The reason behind this is:

Range: The range is the difference between the highest and lowest values in the data.

In Mrs. Cheng's class, the range is 50 - 5 = 45 pencils, while in Mr. Johnson's class, the range is 45 - 7 = 38 pencils. Since the range is smaller in Mrs. Cheng's class, it indicates a narrower spread of data.

2. Median: The median is the middle value in the data when it is arranged in ascending order.

In Mrs. Cheng's class, the median is 16 pencils, while in Mr. Johnson's class, the median is 11 pencils. Since the median is smaller in Mr. Johnson's class, it suggests a smaller value at the center of the data.

Therefore, based on the smaller range and smaller median value, Mrs. Cheng's class lost fewer pencils overall according to the displayed data.

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Answer:

10yd x 14 yd x 3yd = 420yd ^3

Step-by-step explanation:

When calculating for the volume you multiply all three numbers. That’s why when you write your answer you cube it.

The first endpoint is (3, 2), the two control points are P1 = (4.370, 1.628) and P2 = (7.167, 4.379), and the last endpoint is (8, 5).

To find the endpoints and control points of a Bézier curve, we need to use the parametric equations of the curve:

x(t) = 3 + 4t - t^2 + 2t^3

y(t) = 2 - t + t^2 + 3t^3

The first endpoint of the curve is simply the starting point of the curve, which is (x(0), y(0)):

Endpoint 1: (3, 2)

The last endpoint of the curve is the ending point of the curve, which is (x(1), y(1)):

Endpoint 2: (8, 5)

To find the control points, we can use the fact that a cubic Bézier curve has two control points. We can use the following formula to find the control points:

P1 = (x(1/3), y(1/3))

P2 = (x(2/3), y(2/3))

Control Point 1: P1 = (4.370, 1.628)

Control Point 2: P2 = (7.167, 4.379)

Therefore, the first endpoint is (3, 2), the two control points are P1 = (4.370, 1.628) and P2 = (7.167, 4.379), and the last endpoint is (8, 5).

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The number of different min heaps that can be made using the set of integers {88, 2, 9, 36} is 3.

To determine the number of different min heaps that can be made using the set of integers {88, 2, 9, 36}, we can use the concept of factorial.

Step 1: Arrange the integers in ascending order: 2, 9, 36, 88.

Step 2: Count the number of distinct permutations of the remaining three integers (9, 36, 88).

Number of permutations = 3! = 3 × 2 × 1 = 6.

Therefore, there are 6 different permutations of the remaining three integers.

Step 3: Determine the number of distinct min heaps by dividing the number of permutations by the number of ways the remaining three integers can be arranged within each heap.

Since there are 3 integers remaining, and for each heap, the root is fixed (the smallest integer), there are 2 choices for the placement of the remaining two integers.

Number of distinct min heaps = Number of permutations / Number of ways remaining integers can be arranged

= 6 / 2

= 3.

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(a)The class width = 3

(b) The class midpoint of the first class = 51

(c) The class boundaries of the first class =  (49.5, 52.5)

Consider the frequency distribution in the following image.

We know that in  frequency distribution the class width is nothing but the distance between the lower limits of consecutive classes.

Whereas the range is the difference between the maximum and minimum data entries.

The smallest number is 50, and the largest is 62.

So the range is 62 - 50 = 12

We know that the formula for the class width:

Class width= upper limit – lower limit +1

So, the class width = 52 - 50 + 1

                               = 3

The formula for the midpoint of each class:

midpoint = (lower limit of class + upper limit of class)/2

Let us assume that m be the midpoint of the first class.

Using above formula of midpoint:

m = (50 + 52)/2

m = 51

We know that the class boundaries are nothing but the end points of an open interval which contains the class interval.

So, the class boundaries of the first class = (49.5, 52.5)

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(a) The graph of the linear functions is as attached.

(b) The equation of the linear function in slope-intercept form is; y = x

(c) The equation of the transformed function in slope-intercept form is;

y = x + 2 and y = x - 3

Functions are defined as the relationship between sets of values. For example, in the function; y = f(x), for every value of x there exists a set of y values.

x is the independent variable.

y is the dependent variable.

If the linear function is; y = x,

The equation of the transformation in slope-intercept form is given as;

For translation of 2 units up, we have;

y = x + 2

For a translation of 3 units down, we have;

y = x - 3

Thus, the required graph has been attached and the solution is determined.

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The derivative of \(r\) with respect to \(\theta\) can be found using the chain rule. Let's proceed with the differentiation:

\frac{dr}{d\theta} = \frac{d}{d\theta}\left(\cos\left(\frac{\theta}{3}\right)\right)

To differentiate \(\cos\left(\frac{\theta}{3}\right)\), we treat \(\frac{\theta}{3}\) as the inner function and differentiate it using the chain rule. The derivative of \(\cos(u)\) with respect to \(u\) is \(-\sin(u)\), and the derivative of \(\frac{\theta}{3}\) with respect to \(\theta\) is \(\frac{1}{3}\). Applying the chain rule, we have:

\frac{dr}{d\theta} = -\sin\left(\frac{\theta}{3}\right) \cdot \frac{1}{3}

Now, let's evaluate this derivative at \(\theta = \pi\):

\frac{dr}{d\theta} \bigg|_{\theta=\pi} = -\sin\left(\frac{\pi}{3}\right) \cdot \frac{1}{3}

The value of \(\sin\left(\frac{\pi}{3}\right)\) is \(\frac{\sqrt{3}}{2}\), so substituting this value, we have:

\frac{dr}{d\theta} \bigg|_{\theta=\pi} = -\frac{\sqrt{3}}{2} \cdot \frac{1}{3} = -\frac{\sqrt{3}}{6}

Therefore, the slope of the tangent line to the polar curve \(r = \cos(\theta / 3)\) at the point specified by \(\theta = \pi\) is \(-\frac{\sqrt{3}}{6}.

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Using central limit theorem, the probability that the class of 20 students will have a mean completion time greater than 60 minutes on the unit 5 test is 0.00017332

We can use the Central Limit Theorem (CLT) to approximate the distribution of the sample mean completion time for the class. According to CLT, the distribution of the sample mean is approximately normal, with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size.

In this case, the population mean is given as 48 minutes, the population standard deviation is given as 15 minutes, and the sample size is 20. Therefore, the mean of the sample mean completion time is also 48 minutes, and the standard deviation of the sample mean completion time is 15/√20 ≈ 3.3541 minutes.

To find the probability that the class mean completion time is greater than 60 minutes, we can standardize the distribution of the sample mean completion time using the z-score formula:

z = (x - μ) / (σ / √n)

where x is the value we want to find the probability for (in this case, x = 60), μ is the population mean, σ is the population standard deviation, and n is the sample size.

Plugging in the values, we get:

z = (60 - 48) / (15 / √20) = 3.5777

Using a standard normal distribution table (or calculator), we can find the probability that a z-score is greater than 3.5777.

P = 0.00017332

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Length of the golf club where Bruce plays = 7,040 yards

Solution:

1. Let's convert 7,040 yards to miles:

1 yard = 0.000568182 mile

Now, we can use Direct Rule of Three, as follows:

Yards Miles

1 0.000568182

7,040 x

2. Solve for x:

1 * x = 0.000568182 * 7,040

x = 4 miles

Answer:

9 x 2 + 7x

18 + 7x - 6

18 - 6 = 12

12 + 7x

Is your simplified expression

Answer:

12 + 7x

Step-by-step explanation: there

A linear function models the number of calories a 150-lb person burns from walking at a pace of 3 mph for x minutes  we can write the linear function:y = 3.76x - 0.4

In this scenario, Kevin weighs about 150 lb and walks at a pace of about 3 mph. When he walks for 15 min, he burns 56 Cal and when he walks for 60 min, he burns 225 Cal. From this information, we can write a linear function that models the number of calories a 150-lb person burns from walking at a pace of 3 mph for x minutes.

Linear function is an equation that represents a straight line on a graph. The general form of a linear function is y = mx + b, where y is the dependent variable, x is the independent variable, m is the slope of the line, and b is the y-intercept.

The information given in the scenario that enables us to write a linear function is the rate at which Kevin burns calories while walking for different durations. Since Kevin burns 56 Cal in 15 min and 225 Cal in 60 min, we can use these two data points to find the slope of the line.

Slope (m) = (y₂ - y₁) / (x₂ - x₁)where (x₁, y₁) = (15, 56) and (x₂, y₂) = (60, 225)Slope (m) = (225 - 56) / (60 - 15)Slope (m) = 169 / 45Slope (m) = 3.76 (approximately)Therefore, the slope of the line that models the number of calories a 150-lb person burns from walking at a pace of 3 mph is 3.76.

Now we need to find the y-intercept (b). We can use any of the two data points to find the y-intercept. Let's use the first data point (15, 56).y = mx + by = 3.76x + b56 = 3.76(15) + bb = 56 - 56.4b = -0.4 (approximately)Therefore, the y-intercept of the line that models the number of calories a 150-lb person burns from walking at a pace of 3 mph is -0.4.

Now we can write the linear function:y = 3.76x - 0.4This function models the number of calories a 150-lb person burns from walking at a pace of 3 mph for x minutes.

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