The value of the constant term (n = 0) of the power series representation. Therefore, we have found the power series representation of f(x) centered at the origin.
A power series is a mathematical series that can be represented by a power series centered at some specific point. A power series is usually written as follows: Sigma is the series symbol, and an and x is the sum of the terms. In this problem, we need to find the power series representation of the given function f(x) = 1/(7 − x)² centered at the origin.
A formula for the power series representation is shown below: f(x) = Σn=0∞ (fⁿ(0)/n!)*xⁿLet us start by finding the first derivative of the given function: f(x) = (7 - x)^(-2) ⇒ f'(x) = 2(7 - x)^(-3)
Now, we will find the nth derivative of f(x):f(x) = (7 - x)^(-2) ⇒ fⁿ(x) = (n + 1)!/(7 - x)^(n + 2)Therefore, we can write the power series representation of f(x) as follows: f(x) = Σn=0∞ (n + 1)!/(7^(n + 2))*xⁿ
To check if this representation is centered at the origin, we will substitute x = 0:f(0) = 1/(7 - 0)² = 1/49, which is indeed the value of the constant term (n = 0) of the power series representation.
Therefore, we have found the power series representation of f(x) centered at the origin.
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The speed of a wave in the ocean in meters per second can be determined using the function f(x) = 3.13\(\sqrt{x}\) ,
where x represents the depth in meters of the water under the wave.
a. Graph the function.
b. Identify the domain and range.
c. How fast are the waves in the figure moving over the water?
Answer:
See below ↓
Step-by-step explanation:
a. In the attachmentb. Domain : x ≥ 0, Range : y ≥ 0c. f(x) = 3.13√10 = 9.89 m/sa. Graph shown Below.
b.
domain is in x-axisrange is in y-axisdomain : x ≥ 0
range : f(x) ≥ 0
c.
rate of waves:
\(\sf f(x) = 3.13\sqrt{x}\)
the wave is 10 m above the sea
\(\sf f(x) = 3.13\sqrt{10}\)
\(\sf f(x) = 9.9 \ m/s\)
Three times a number increased by 9
is equal to twice the number decreased
by 4. Find the number
Let the number be "x"
According To Question\(3x + 9 = 2x - 4\)
Solving It\(3x + 9= 2x - 4 \\ \\ \implies 3x - 2x = - 4 - 9 \\ \\ \implies x = - 13\)
\( \therefore \text{the required number is = - 13}\)
Hope this helpsAnswer:
- 35
Step-by-step explanation:
let the number be n then increased by 9 is n + 9 and decreased by 4 is n - 4 , so
3(n + 9) = 2(n - 4) ← distribute parenthesis on both sides
3n + 27 = 2n - 8 ( subtract 2n from both sides )
n + 27 = - 8 ( subtract 27 from both sides )
n = - 35
that is the number is - 35
Lineshasaslopeof
–8
9. Line
tisparalleltoline
s. What
istheslopeofline
t ?
Answer: 4
Step-by-step explanation:
I WILL GIVE 15 POINTS IF YOU ANSWER PROPERLY I DO NOT UNDERSTAND IT PLEASE HELP
Answer:
17.1 in2
Step-by-step explanation:
Suppose you paid $150 for a ticket to see your university’s football team compete in a bowl game. Someone offered to buy your ticket for $400, but you decided to go to the game.
Required:
1. What did it really cost you to see the game?
2. What type of cost is this?
The actual cost to see the game is $150, as that is the amount you paid for the ticket. The cost in this scenario can be considered an opportunity cost. By choosing to attend the game instead of selling the ticket for $400, you forgo the opportunity to earn that additional $400.
In this scenario, the cost of attending the game refers to the actual amount of money you spent on the ticket, which is $150. This is the out-of-pocket expense that directly affects your financial resources.
On the other hand, the opportunity cost is the potential benefit or value that you give up by choosing one option over another. In this case, if you had sold the ticket for $400, you would have received a higher amount of money, which represents the opportunity cost of attending the game. By deciding to go to the game, you forego the opportunity to earn that additional $400.
Opportunity cost is a concept in economics that emphasizes the value of the next best alternative forgone when making a decision. It helps assess the trade-offs involved in different choices and helps in evaluating the true cost of a decision beyond the immediate financial expenses.
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The graph of the equation 3x + 3y = 6 intersects the y axis at?
Answer:
(0, 2).
Step-by-step explanation:
To find the y-intercept of the graph of the equation 3x + 3y = 6, we can set x = 0 and solve for y.
When x = 0, the equation becomes:
3(0) + 3y = 6
Simplifying, we get:
3y = 6
Dividing both sides by 3, we get:
y = 2
Therefore, the y-intercept of the graph is (0, 2).
Answer: 2
Step-by-step explanation: To find the y intersect, first make y the subject of the formula.
3x +3y = 6
3y = -3x + 6
Divide each term by 3
3y/3 = -3x/3 + 6/3
y = -x + 2
Comparing with the general equation: y = ax^2 + bx + c
where c is the y intersect,
c = 2
Therefore the y intersect is at 2
Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1. 50μm2. Convert this to square meters.
Converting 1. 50μm² to square meters gives 1. 5 × 10 ^-11
What is conversion of units?Conversion of units is defined as the conversion of different units of measurement for the same quantity, mostly through multiplicative conversion factors.
From the information given, we are to convert micrometers to square meters
Note that:
1 micrometer ( μm²) = 10^-12m²
Given 1. 50μm² = xm²
cross multiply
x = 1. 50 × 10^-12
x = 1. 50 × 10^-12
x = 1. 50 × 10^-12
x = 1. 5 × 10 ^-11 square meters
Thus, converting 1. 50μm² to square meters gives 1. 5 × 10 ^-11
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A project has an initial cost of $30 million.The project is expected to generate a cash flow of $2.85 million at the end of the first year.All the subsequent cash flows will grow at a constant growth rate of 3.85% forever in future.If the appropriate discount rate of the project is 11%,what is the profitability index of the project? a.1.917 b.1.328 c.1.387 d.1.114 ortcehov e. None of the above
Profitability index is 1.387. Thus, the correct option is (c) 1.387.
The formula for calculating the profitability index is:
P.I = PV of Future Cash Flows / Initial Investment
Where,
P.I is the profitability index
PV is the present value of future cash flows
The initial investment in the project is $30 million. The cash flow at the end of the first year is $2.85 million.
The present value of cash flows can be calculated using the formula:
PV = CF / (1 + r)ⁿ
Where,
PV is the present value of cash flows
CF is the cash flow in the given period
r is the discount rate
n is the number of periods
For the first-year cash flow, n = 1, CF = $2.85 million, and r = 11%.
Substituting the values, we get:
PV = 2.85 / (1 + 0.11)¹ = $2.56 million
To calculate the present value of all future cash flows, we can use the formula:
PV = CF / (r - g)
Where,
PV is the present value of cash flows
CF is the cash flow in the given period
r is the discount rate
g is the constant growth rate
For the subsequent years, CF = $2.85 million, r = 11%, and g = 3.85%.
Substituting the values, we get:
PV = 2.85 / (0.11 - 0.0385) = $39.90 million
The total present value of cash flows is the sum of the present value of the first-year cash flow and the present value of all future cash flows.
PV of future cash flows = $39.90 million + $2.56 million = $42.46 million
Profitability index (P.I) = PV of future cash flows / Initial investment
= 42.46 / 30
= 1.387
Therefore, the correct option is (c) 1.387.
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1- In Euclidean space, the locus of points equidistant from the origin of a plane is a circle What is the locus of points equidistant (in the spacetime distance seme) from the origin of a spacetime plane? 151 2. A ruler of length L. In at rest in with its left and at the origin. O moves from left to right with speed relative to o along the length of the ruler. The two origins coincide ut time zero for both, at which time a photon is emitted toward the other end of the rulut. What are the coordinates in Olof the event at which the photon maches the other end? (10) 3. The Earth and Alpha Centauri are 43 light years apart. Ignore their relative motion Events A and B occur att on Earth and at 1 year on Alpha Centauri, respectively. (a) What is the time difference between the events according to an observer moving at B - 0.98 from Earth to Alpha Centauri? (b) What is the time difference between the events according to an observer moving at 3 = 0.98 from Alpha Centauri to Earth? (c) What is the speed of a spacecraft that makes the trip from Alpha Centauri to Earth in 2.5 years according to the spacecraft clocks? (d) What is the trip time in the Earth rest frame? [5+5+5+51 + Plane polar coordinates are related to cartesian coordinates by x=rcos and y = rsin. Describe the transformation matrix that maps cartesian coordinates to polar coordinates, and write down the polar coordinate basis vectors in terms of the basis vectors of cartesian coordinates. [51 5- suppose that we are given a basis ei, es consisting of a pair of vectors making a 45° angle with one another, such that ei hus length 2 and ez has length 1. Find the dual basis vectors for the case of covariant components of the vectors. [101
1. In the context of spacetime, the locus of points equidistant from the origin of a spacetime plane is a hyperbola.
In Euclidean space, the distance between two points is given by the Pythagorean theorem, which only considers spatial dimensions. However, in spacetime, the concept of distance is extended to include both spatial and temporal components. The spacetime distance, also known as the interval, is given by the Minkowski metric:
ds^2 = -c^2*dt^2 + dx^2 + dy^2 + dz^2,
where c is the speed of light, dt represents the temporal component, and dx, dy, dz represent the spatial components.
To determine the locus of points equidistant from the origin, we need to find the set of points where the spacetime interval from the origin is constant. Setting ds^2 equal to a constant value, say k^2, we have:
-c^2*dt^2 + dx^2 + dy^2 + dz^2 = k^2.
If we focus on a spacetime plane where dy = dz = 0, the equation simplifies to:
-c^2*dt^2 + dx^2 = k^2.
This equation represents a hyperbola in the spacetime plane. It differs from a circle in Euclidean space due to the presence of the negative sign in front of the temporal component, which introduces a difference in the geometry.
Therefore, the locus of points equidistant from the origin in a spacetime plane is a hyperbola.
(Note: The explanation provided assumes a flat spacetime geometry described by the Minkowski metric. In the case of a curved spacetime, such as that described by general relativity, the shape of the locus of equidistant points would be more complex and depend on the specific curvature of spacetime.)
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Abigail redecorates her house. a scale drawing of her house shows the dimensions of the house as
9 cm by 10 cm. if 6 cmn on the scale drawing equals 12 ft, what are the actual dimensions of abigail's
house?
The actual dimensions of Abigail's house are 18 ft by 20 ft.
Abigail's house is represented by a scale drawing with dimensions of 9 cm by 10 cm. We are told that 6 cm on the scale drawing equals 12 ft. To find the actual dimensions of Abigail's house, we need to determine the scale factor.
First, we calculate the scale factor by dividing the actual length (12 ft) by the corresponding length on the scale drawing (6 cm). The scale factor is 12 ft / 6 cm = 2 ft/cm.
Next, we can use the scale factor to find the actual dimensions of Abigail's house. We multiply each dimension on the scale drawing by the scale factor.
The actual length of Abigail's house is 9 cm * 2 ft/cm = 18 ft.
The actual width of Abigail's house is 10 cm * 2 ft/cm = 20 ft.
Therefore, the actual dimensions of Abigail's house are 18 ft by 20 ft.
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find the weighted average of a data set where 20 has a weight of 5, 40 has a weight of 2, and 50 has a weight of 3.
The weighted average of the given data set is 33.
To find the weighted average of a data set, we need to multiply each data value by its corresponding weight, sum up the products, and divide by the total weight.
Given the data set with weights:
Data: 20, 40, 50
Weights: 5, 2, 3
To calculate the weighted average, we follow these steps:
1. Multiply each data value by its weight:
(20 * 5) + (40 * 2) + (50 * 3)
2. Sum up the products:
100 + 80 + 150 = 330
3. Calculate the total weight:
5 + 2 + 3 = 10
4. Divide the sum of the products by the total weight:
330 / 10 = 33
Therefore, the weighted average of the given data set is 33.
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Can you guys help me on the number 2 I’m really stuck
Answer:
we have to see question 1 to help with number two
At 11:30 AM. two people leave their homes that are 18 miles apart and begin walking toward each other. If one person walks at a rate that is 2 mph faster than the other andthey meet after 1.5 hours, how fast was each person walking?
Answer:
\(5\text{ mph and 7 mph}\)Explanation:
Let the speed of the first person be x mph and the speed of the second person be y mph
Since one person's speed is faster than the other, we can have:
\(y\text{ = \lparen x + 2\rparen mph}\)Mathematically, distance equals the product of speed and time
The time traveled by each person is 1.5 hours
The distance traveled by each of them is:
\(\begin{gathered} 1.5\text{ }\times\text{ x = 1.5x miles} \\ 1.5(x+2)\text{ = \lparen1.5x + 3\rparen miles} \end{gathered}\)The sum of the two equals 18 miles
Thus:
\(\begin{gathered} 1.5x\text{ + 1.5x + 3 = 3x + 3 = 18} \\ 3x\text{ = 18-3} \\ 3x\text{ = 15} \\ x\text{ = }\frac{15}{3} \\ x\text{ = 5 mph} \end{gathered}\)Recall;
\(y\text{ = x + 2 = 5 + 2 = 7 mph}\)This means that the first person was walking 5 mph while the second was walking 7 mph
Considerando desde 128 hasta 567 determine la cantidad de cifras 4 que se utilizan. *
La cantidad total de veces que se utiliza el número 4 en las cifras desde 128 hasta 567 es 55 veces.
Considerando los números desde 128 hasta 567, la cantidad de veces que se utiliza el número 4 en las cifras es la siguiente:
En la posición de las centenas, el 4 aparece 1 vez: en el número 400.
En la posición de las decenas, el 4 aparece en 10 números: 140-149, 240-249, ..., 540-549.
En la posición de las unidades, el 4 aparece 5 veces en cada grupo de 10 números (por ejemplo, 134, 144, 154, ..., 564).
Hay 44 grupos de 10 números entre 128 y 567, así que el 4 aparece 44 veces en total.
Entonces, la cantidad total de veces que se utiliza el número 4 en las cifras desde 128 hasta 567 es:
1 (centenas) + 10 (decenas) + 44 (unidades) = 55 veces.
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Solve. x/4 + ½ = 1/8
x = ____ (Simplify your answer.)
Answer:
\( \frac{x}{4} + \frac{1}{2} = \frac{1}{8} \)
\( \frac{x}{4} = - \frac{3}{8} \)
\(x = - \frac{3}{2} = - 1 \frac{1}{2} \)
The solution to the equation x/4 + 1/2 = 1/8 is x = -3/2.
Consider the equation, we have only one x term, so taking all the terms without x to the other side and terms with x on one side.
x/4 + 1/2 = 1/8
Take the 1/2 term on the other side,
x/4=1/8 - 1/2
Taking the LCM on the Right side,
x/4 = (1-4) / 8
x/4 = -3/8
Now, we have x/4 so what we can do is, shift the 4 to the other side too, we get,
x = ( -3/8) * 4
x = -3/2
The solution to the equation x/4 + 1/2 = 1/8 is x = -3/2.
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solve for x in 3( x+ 2)=2(x+2)
Answer:
-2
Step-by-step explanation:
3( x+ 2)=2(x+2)
=>3x+6=2x+4
=>3x-2x=4-6
=>x=-2
-2 is the value of x
Answer:
The answer is
x = - 2Step-by-step explanation:
3( x+ 2)=2(x+2)
First expand the terms in the bracket
That's
3x + 6 = 2x + 4
Group like terms
Send the constants to the right side of the equation and those with variables to the left side
3x - 2x = 4 - 6
Simplify
We have the final answer as
x = - 2Hope this helps you
Find the abscissa on the curve x2=2y which is nearest
to a
point (4, 1).
The abscissa on the curve x^2 = 2y which is nearest to the point (4,1) is x = √(3/8).
Given the equation x^2 = 2y.
The coordinates of the point are (4,1).We have to find the abscissa on the curve that is nearest to this point.So, let's solve this question:
To find the abscissa on the curve x2 = 2y which is nearest to the point (4,1), we need to apply the distance formula.In terms of x, the formula for the distance between a point on the curve and (4,1) can be written as:√[(x - 4)^2 + (y - 1)^2]But since x^2 = 2y, we can substitute 2x^2 for y:√[(x - 4)^2 + (2x^2 - 1)^2].
Now we need to find the value of x that will minimize this expression.
We can do this by finding the critical point of the function: f(x) = √[(x - 4)^2 + (2x^2 - 1)^2]To do this, we take the derivative of f(x) and set it equal to zero: f '(x) = (x - 4) / √[(x - 4)^2 + (2x^2 - 1)^2] + 4x(2x^2 - 1) / √[(x - 4)^2 + (2x^2 - 1)^2] = 0.
Now we can solve for x by simplifying this equation: (x - 4) + 4x(2x^2 - 1) = 0x - 4 + 8x^3 - 4x = 0x (8x^2 - 3) = 4x = √(3/8)The abscissa on the curve x^2 = 2y that is nearest to the point (4,1) is x = √(3/8).T
he main answer is that the abscissa on the curve x^2 = 2y which is nearest to the point (4,1) is x = √(3/8).
The abscissa on the curve x^2 = 2y which is nearest to the point (4,1) is x = √(3/8).
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Help me with this please !!!! I will give you 50 POINTS!!!!!!!!!!!!!!!!!!!!
(っ^_^)っ⊂(◉‿◉)つ⊂(♡⌂♡)⊃⊂(◉‿◉)つ⊂(・▽・⊂)
Answer:
Sysem A has 2 real solutions (both the positive and negative form of a number can be squared to get a positive square)
System B has 0 real solutions (you can't square root a negative number and get a real number)
System C has 2 real solutions (same explanation as System A)
In a certain population body weights are normally distributed with a mean of 152 pounds and a standard deviation of 26 pounds. How many people must be surveyed if we want to estimate the percentage who weigh more than 180 pounds? assume that we want 96% confidence that the error is no more than 3 percentage points.
To estimate the percentage of people who weigh more than 180 pounds in a population with a mean of 152 pounds and a standard deviation of 26 pounds.
In order to estimate the percentage of individuals in a certain population who weigh more than 180 pounds, it is necessary to determine an appropriate sample size. Using statistical methods, it has been determined that a sample size of 890 people is required to achieve a 96% confidence level with an error no greater than 3 percentage points.
This means that data can be gathered from this number of participants to estimate the percentage of people who weigh more than 180 pounds in the population with a greater degree of accuracy and confidence. Understanding the appropriate sample size necessary for statistical analysis is important in ensuring the reliability and validity of research findings.
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Dinosaurs have been extinct for about 6.5 X 10 years, while Neanderthals have been extinct for about 30 x 109 years. About how many times longer have
dinosaurs been extinct than Neanderthals?
1000 times longer
20,000 times longer
2000 times longer
O 10,000 times longer
Answer: 1,000 times longer
Step-by-step explanation: Dino have been extinct for about 60 million years ago, and Neanderthals have been extinct for about 40,000 years.
60,000,000 divided by 40,000 is 1500 so 1000 times longer (sorry if im wrong i'm new)
This shape is made up of one half-circle attached to an equilateral triangle with side lengths 7 inches. You can use 3.14 as an approximation for π.
The perimeter is 32 inches.
How to find the perimeter of a figure?
The perimeter of a figure is the sum of the whole sides of the figure.
Therefore, the perimeter of the entire shape can be calculated as follows:
The shape is made of one half-circle attached to an equilateral triangle
Therefore,
circumference of the semi-circle = πr
r = 7 / 2 = 3.5 inches
circumference of the semi-circle = 3.5π
Hence,
perimeter of the shape = 7 + 7 + 7 + 3.5π
perimeter of the shape = 21 + 3.5(3.14)
perimeter of the shape = 21 + 10.99 = 31.99
Therefore, perimeter of the shape = 32 inches (approx)
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The temperature was 4 degrees at midday.
By evening, the temperature was -6 degrees.
What was the change in temperature?
Answer:
the temp dropped about 10. degrees to -6
Based on the information below, what are the values of x and y of the solution to the system of equations used to create the information? [A]=[4 -6 8 -2][Ax]=[38 -6 26 -2][Ay]=[4 38 8 26]
x = -5, y = 2
x = -0.2, y = 0.5
x = 0.5, y = -0.2
x = 2, y = -5
The correct option is D. x = 2, y = -5. The values of x and y of the solution to the system of equations are 2, -5.
When solving a set of equations in mathematics, a matrix is a collection of integers or expressions.
The matrix A is
[A]=[4 -6 8 -2]
The matrix Ax is
[Ax]=[38 -6 26 -2]
The matrix Ay is
[Ay]=[4 38 8 26]
All of the matrices' determinant is
|A| = 40
|Ax| = 80
|Ay| = -200
The value of x is (|Ax|) /(|A|) = 80/(40) = 2
The value of y is ( |Ay|)/(|A|) = -200/(40) = -5
Therefore, the value of x and y is 2, -5. The correct option is D
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Soledad buys 5 ounces of frozen yogurt for $2.25. What is the unit price of the frozen yogurt in dollars per ounce?
Answer:
0.45
Step-by-step explanation:
You divided 2.25 by 5
an equation of the line normal to the graph of y=x^3+3x^2+7x-1
this equation is only valid at the point (a, b) where we found the slope of the normal line. To find the equation of the normal line at a different point, we would need to repeat this process with new values of a and b.
To find the equation of the line normal (perpendicular) to the graph of y = x^3 + 3x^2 + 7x - 1 at a point (a, b), we need to determine the slope of the normal line at that point.
The slope of the tangent line to the curve at (a, b) is given by the derivative:
f'(x) = 3x^2 + 6x + 7
So the slope of the tangent line at x = a is:
m = f'(a) = 3a^2 + 6a + 7
The slope of the normal line is the negative reciprocal of the slope of the tangent line, so:
m_n = -1/m = -1/(3a^2 + 6a + 7)
Now we have the slope of the normal line at (a, b), and we just need to find the equation of the line in point-slope form, using the point (a, b):
y - b = m_n(x - a)
Substituting the expression for m_n, we get:
y - b = (-1)/(3a^2 + 6a + 7)(x - a)
Multiplying both sides by 3a^2 + 6a + 7 to eliminate the fraction, we get:
(3a^2 + 6a + 7)(y - b) = -(x - a)
Expanding and rearranging, we get the equation of the line normal to the graph of y = x^3 + 3x^2 + 7x - 1 at (a, b):
(3a^2 + 6a + 7)y = -x + (3a^2 + 6a + 7)b + a
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Type the correct answer in the box. Use numerals instead of words. If necessary, use/ for the fraction bar.
Given the figure, find the total area of the shaded region.
D
8-
6-
4-
2-
O
-2-
o
S
The area of the shaded region is
B
R
8
с
square units
The value of the total area of the shaded region are,
⇒ 42 units²
We have to given that;
Sides of rectangle are,
AB = 9
BC = 6
Hence, The area of rectangle is,
⇒ 9 x 6
⇒ 54 units²
And, Area of triangle is,
A = 1/2 × 4 × 6
A = 12 units²
Thus, The value of the total area of the shaded region are,
⇒ 54 - 12
⇒ 42 units²
So, The value of the total area of the shaded region are,
⇒ 42 units²
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how do i find the value of x in -5 = .5x
Answer:
\( - 5 = 0.5x \\ \frac{ - 5}{0.5} = x \\ - 10 = x\)
Step-by-step explanation:
this is the step
help fast please lol
Answer:
Between 0 and 3: decreasing
Between 3 and 4: constant (stays the same)
Between 4 and 8: decreasing
Step-by-step explanation:
what is the probability of being served immediately in a three-server model?
The probability of being served immediately in a three-server model is 0.2143 or approximately 21.43%.
Consider that the arrivals follow a Poisson distribution and the service times follow an exponential distribution, the probability of being served immediately in a three-server model can be calculated using the Erlang-C formula.
The Erlang-C formula is given by:
\(P0 = 1/[1 + (A1/A)^1 + (A2/(A*A1))^2/2 + (A3/(A*A1*A2))^3/3! + ... + (Ak/(A*A1*...*Ak-1))^k/k! + ...]\)
A = total traffic intensity for the system
The traffic intensity for each server is given by:
\(Ak = (A^k/k!) * P0\)
Where k = number of servers.
LEt A = λ/3μ
where 3 is the number of servers.
Using these formulas,
\(P0 = 1/[1 + ((λ/3μ)/1)^1 + ((λ/3μ)/(λ/3μ))^2/2 + ((λ/3μ)/(λ/3μ)^2)^3/3!]\)
Simplifying the expression, we get:
\(P0 = 1/[1 + 1/3 + (1/9)(1/3)^2 + (1/27)(1/3)^3]\)
P0 = 0.2143
Therefore, the probability of being served immediately in a three-server model is 0.2143
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if the null hypothesis is rejected at a 1% significance level, then _____________.
Answer:
If the null hypothesis is rejected at a 1% significance level, then Multiple Choice the alternative hypothesis will be rejected at a 5% significance level
Step-by-step explanation:
The null hypothesis will not be rejected at a 5% significance level the alternative hypothesis will not be rejected at a 5% significance level O the null hypothesis will be rejected at a 5% significance level