Could someone explain how to this, it would be much appreciated!
Answer:
First do \(\frac{12-6}{4-2}\), then simplify it into \(\frac{6}{2}\), then, divide 6 by 2 to get 3. 3 is your rate of change.
Formula for slope/rate of change: \(\frac{y2-y1}{x2-x1}\)
Hope this helped!
Which expression has a solution of 56 if r = 8?
8r
7r
6 r
9 r
Answer:
7r is the correct answer
Step-by-step explanation:
7 x 8 = 56
what two positive real numbers whose product is 92 have the smallest possible sum?
This can be achieved by minimizing (a+b). That is to say, we can equate (a+b) to\(2√(ab)\)and then substitute the value of ab to get an equation in terms of either a or b. Let us suppose b is the smaller of the two numbers.
Then, a = (92/b). So now, we have:\($$\begin{aligned} a+b &= \frac{92}{b} + b \\ &= \frac{92}{b} + \frac{b}{2} + \frac{b}{2} \end{aligned}$$\) Applying AM-GM inequality to the right side of the above equation, we have:\($$\begin{aligned} \frac{92}{b} + \frac{b}{2} + \frac{b}{2} &\geqslant 3\sqrt[3]{\frac{92}{b} \cdot \frac{b}{2} \cdot \frac{b}{2}} \\ &= 3\sqrt[3]{\frac{46}{2}} \\ &= 3\sqrt[3]{23} \end{aligned}$$\)
Since the sum of the two positive real numbers is greater than or equal to\(3√23\), to find the smallest possible sum, the sum must be equal to \(3√23.\) This is achieved when:\($\frac{92}{b} = \frac{b}{2}$So,$b^2 = 184 \Right arrow b = 2\sqrt{46}$\)Substituting the value of b to get the value of a, we have:\($a = \frac{92}{b} = \frac{92}{2\sqrt{46}} = \sqrt{184}$\)Therefore, the two positive real numbers whose product is 92 and the smallest possible sum is\($a+b=\sqrt{184}+2\sqrt{46}$.\)
Answer:\(sqrt{184}+2\sqrt{46}$.\)
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SOMEONE HELP ME PLEASE
The estimated probability of an amateur golfer hitting at least 6 times in his next 10 attempts is 20%. The Option A.
What is the estimated probability of an amateur golfer hitting at least 6 times?To simulate the situation, we can use the table of random numbers by selecting the first two digits of each number as a random sample. Let's consider hitting the ball as a success, and missing it as a failure.
So, the amateur golfer has a probability of success of 0.48 and a probability of failure of 0.52. We want to calculate the probability of having at least 6 successes in 10 attempts, which means we need to add up the probabilities of having 6, 7, 8, 9, or 10 successes.
Using binomial probabilities, we can calculate these probabilities as follows:
P(X ≥ 6) = P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10); X is the number of successes in 10 attempts.
Using the binomial formula, we can calculate each probability as:
P(X = k) = (10 choose k) * (0.48)^k * (0.52)^(10-k). By adding up these probabilities, we get P(X ≥ 6) = 0.196 or approximately 20%.
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Let X1,X2.X3.X4 be independent zero-mean, unit-variance Gaussian random variables that are processed as follows: Y = X + X2, Y = X2 + X3; Y3 = X3 + X4 - Find the covariance matrix of Y = (Yi,Yz, Y3)_ b) Find the joint PDF of Y_ Find the joint PDF of Yi and Y2; Yi and Y3;
The covariance matrix of Y is given by
Cov (Y) =
[[1, 1, 0],
[1, 2, 1],
[0, 1, 2]]
The joint PDF of Y can be obtained as
fY(y1,y2,y3) = (1/√(2π))^3 * exp ( -1/2 * [y1^2 + y2^2 + y3^2 - 2y1y2 - 4y2y3 - 2y1y3])
The joint PDFs of Yi and Y2, Yi and Y3 and Y2 and Y3 are given by:
fY1Y2(y1,y2) = (1/√(2π))^2 * exp(-1/2 * (y1^2 + y2^2 - 2y1y2))
fY1Y3(y1,y3) = (1/√(2π))^2 * exp(-1/2 * (y1^2 + y3^2 - 2y1y3 - 4y2y3))
fY2Y3(y2,y3) = (1/√(2π))^2 * exp(-1/2 * (y2^2 + y3^2 - 4y2y3))
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question a3 suppose f(x) is differentiable, where f(0) = 3, f'(0) = 4, and f''(x) < 0 for all x. which of these could be true?
The statement "f(x) is increasing for all x" could not be true. The correct answer is (A) f(1) > 7.
Since f''(x) is negative for all x, f(x) is a concave-down function. Given that f(0) = 3 and f'(0) = 4, we know that the graph of f(x) is increasing at a decreasing rate at x=0, and f(x) is below its tangent line at x=0. Thus, we can conclude that f(x) < 4x + 3 for all x.
Now, if f(1) ≤ 7, we have f(1) < 4(1) + 3 = 7, which contradicts the given fact that f(x) < 4x + 3 for all x. Therefore, we must have f(1) > 7. The other answer choices are false. For instance, if f(1) = 7, then f(1) = 4(1) + 3, and the tangent line to f(x) at x=1 has slope 4, which implies that f''(x) = 4 > 0 for some x near 1, contradicting the given information that f''(x) < 0 for all x.
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Madison claims that two data sets with the same median will have the same variability. Which data set would provide good
support for whether her claim is true or false?
O Her claim is true and she should use these data sets to provide support.
0
1 2
3 4
5 6
7 8 9 10 11
+
+
+
+
+
+
+
+
0
1
2
3
4
5
6
7
8
9 10 11
O
Her claim is true and she should use these data sets to provide support.
+
6
0
3
+
7
1
4
2
5
+ + +
9 10 11
8
Complete Question:
Madison claims that two data sets with the same median will have the same variability. Which data set would provide good support for whether her claim is true or false?
A. Her claim is true and she should use these data sets to provide support. A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7. A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 6.
B. Her claim is true and she should use these data sets to provide support. A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7. A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 5 to 8. A line divides the box at 7.
C. Her claim is false and she should use these to show that two data sets with the same median can have different variability. A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7. A box-and-whisker-plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 5 to 8. a line divides the box at 7.
D. Her claim is false and she should use these to show that two data sets with the same median can have different variability. A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7. A box-and-whisker-plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 5 to 8. a line divides the box at 5.5.
Answer:
C. Her claim is false and she should use these to show that two data sets with the same median can have different variability. A box-and-whisker plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 4 to 9. A line divides the box at 7. A box-and-whisker-plot. The number line goes from 0 to 11. The whiskers range from 2 to 11, and the box ranges from 5 to 8. a line divides the box at 7.
Step-by-step explanation:
The median of a box plot is indicated by the line that divides the rectangular box into 2.
Also, the interquartile range is a measure of variability. And this is indicated or represented on a box plot by the range of the box. That is the difference between one end of the box and the beginning of the other end to our left.
The data set that can be used to show that Madison claim is false is a data set showing 2 box plots with the same median value but different interquartile range.
Therefore, C is the right option. Both data set in the drop box would have a median of 7. The interquartile range of one of the drop box would be = 9-4 = 5, while the other would be = 8-5 = 3.
This shows 2 data set with the same median can have different variability.
I WILL GIVE YOU BRAINLIEST FOR THIS ONE
-
Triangle ABC lies on the
coordinate plane with vertices
located at A (8,6), B (2,-5), and
C (-5, 1). The triangle is
< transformed using the rule
(x,y) - (x + 3,2y) to create
triangle A'B'C'.
Determine the coordinates of
triangle A'B'C'.
Using translation concepts, the coordinates of triangle A'B'C' are given as follows:
A' (11, 12), B' (5,-10), C (-2, 2).
What is a translation?A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s range(involving values of y) or in it’s domain(involving values of x). Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis, or rotations of a degree measure around the origin.
For this problem, the translation rule is given as follows:
(x,y) -> (x + 3, 2y).
Applying the rule to each vertex, we have that:
A': (8 + 3, 2(6)) = (11, 12).B': (2 + 3, 2(-5)) = (5, -10).C': (-5 + 3, 2(1)) = (-2, 2).Hence the coordinates of triangle A'B'C' are given as follows:
A' (11, 12), B' (5,-10), C (-2, 2).
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2.07 unit conversions
Answer:
Step-by-step explanation:
A list is made of all possible 2-digit whole numbers that result from using only the digits 1,3,5, and 7 in both the
ones and tens place, with duplications allowed. How many whole numbers in the list are prime numbers?
A.6
B.7
C.8
D.9
E.10
-2x2 + 1 for x = -3
Answer:
Step-by-step explanation:
-2(-3) *2+1
6*2+1
12+1
13
Answer:
- 17
Step-by-step explanation:
Evaluate 1 - 2 x^2 where x = -3:
1 - 2 x^2 = 1 - 2×(-3)^2
Hint: | Evaluate (-3)^2.
(-3)^2 = 9:
1 - 29
Hint: | Multiply -2 and 9 together.
-2×9 = -18:
-18 + 1
Hint: | Subtract 18 from 1.
1 - 18 = -17:
Answer: -17
what is the probability of picking a red ball from the bag and getting heads upon flipping a fair coin? a.) 3 over 16 b.) 7 over 8 c.) 3 over 4 d.) 1 over 8
the probability of picking a red ball from the bag and getting heads upon flipping a fair coin is 1/2 * 1/2 = 1/8.
There are two independent events, and therefore the probability of both occurring is calculated by multiplying the probability of each event. The probability of picking a red ball from the bag is 1/2, and the probability of getting heads upon flipping a fair coin is also 1/2. Therefore, the probability of picking a red ball from the bag and getting heads upon flipping a fair coin is 1/2 * 1/2 = 1/8.
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in calculating the surface area of the box. (Round your answee to one decimal ptace.) cm 2
The estimated maximum error in calculating the surface area of the box is approximately 50.4 cm².
To estimate the maximum error in calculating the surface area of the box, we can use differentials. The surface area of a rectangular box is given by:
S = 2lw + 2lh + 2wh
where
l= length
w= width
h= height
Let's consider the differentials of the dimensions:
dl = 0.2 cm
dw = 0.2 cm
dh = 0.2 cm
Using differentials, we can calculate the differential of the surface area:
dS = 2w(dl) + 2h(dw) + 2l(dh)
Substituting the given values:
dS = 2(63 cm)(0.2 cm) + 2(24 cm)(0.2 cm) + 2(79 cm)(0.2 cm)
Calculating the value:
dS ≈ 50.4 cm²
Therefore, the estimated maximum error in calculating the surface area of the box is approximately 50.4 cm².
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The question is:
The dimensions of a closed rectangular box are ensured as 79cm, 63cm, and 24cm respectively with a possible error of 0.2cm in each dimension. Use differentials to estimate the maximum error in calculating the surface area of the box. (Round your answer to one decimal place.)
a group of 202 202202 people went on an overnight camping trip, taking 60 6060 tents with them. some of the tents held 2 22 people each, and the rest held 4 44 people each. assuming all the tents were filled to capacity and every person got to sleep in a tent, exactly how many of the tents were 2 22-person tents?
The answer to the question is that there were 101.1010 2-person tents.
The formula to solve this problem is: (202 ÷ 2) + (202 ÷ 4) = number of tents.
To calculate the number of 2-person tents, we need to divide the number of people (202) by 2, and then add the result to the number of tents we get when we divide the number of people by 4.
So, (202 ÷ 2) + (202 ÷ 4) = 60.6060 tents.
To find out how many of these tents are 2-person tents, we need to divide the number of people (202) by 2. This gives us the result of 101.1010. This is the number of 2-person tents.
So, to summarise, the answer to the question is that there were 101.1010 2-person tents.
The answer to the question is that there were 101.1010 2-person tents.
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Sam types 44 words per minutes. How long does it take Sam to type 1,232 words?
Answer:
28 minutes
Step-by-step explanation:
1232w * ((1m) / (44w))
1232m / 44 = 28m
The part in italics is just the ratio of 44 words per minute
Which Angel number supplementary to angel to AED
Answer:
Angle number 5
Step-by-step explanation:
The sum of supplementary angles equal 180°.
Angle AED, in the diagram given is labelled angle 4.
The angle labelled 4 forms a linear pair with the angle labelled 5.
Since a linear pair of angles = 180°, therefore:
m<AED + m<AEI = 180°.
That is:
m<4 + m<5 = 180°.
Both angles are supplementary.
Therefore, angle number 5 is supplementary to angle AED.
write an integral that quantifies the increase in the volume of a sphere as its radius r quadruples from r unit to 4r units.
The expression of the integral that quantifies the increase in volume of a sphere as its radius r quadruples from r to 4·r is therefore;
∫dV/dr, r, r, 4·r = 84·π·r³
What is an integral?An integral is a function which when differentiated, yields a specified function.
The volume of the sphere with radius r is V = (4/3) × π × r³
The increase in volume with a change in radius from r to 4·r is the difference between the volume at r and the volume with a radius of 4·r, as follows;
ΔV = ∫dV/dr, r, r, 4·r = \(V_{final}\) - \(V_{initial}\)
Therefore;
ΔV = ∫dV/dr, r, r, 4·r = ∫4·π·r², r, r, 4·r = (4/3) × π × (4·r)³ - (4/3) × π × r³ = 84·π·r³
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Describe the quantities an operations you use to find how much time Rollin split on the planned activities which quantities and operations will you use to find how much free time Rollin had
The free time of rollin's will be 16 hours.
To find how much time Rollin spent on planned activities, we would need to have a list of all the planned activities and the duration of each activity. Then, we would add up the duration of all the activities to get the total time spent on planned activities.
we will add the time he spent playing, reading, having meals, and watching TV, which is 2 + 2 + 1 + 3 = 8 hours.
To find how much free time Rollin had, we would need to know the total amount of time available and subtract the time spent on planned activities from the total amount of time.
Therefore, we need to know the duration of each day (24 hours) and the duration of all planned activities. The free time can be calculated as
Free time = Total time available - Time spent on planned activities
So, Rollin's free time will be 24 - 8 = 16 hours.
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--The given question is incomplete, the complete question is given
"Describe the quantities an operations you use to find how much time Rollin split on the planned activities which quantities and operations will you use to find how much free time Rollin had. activites are playing, reading, meals, watching tv with time of 2hrs, 2 hrs, 1 hr, 3 hrs. "--
Help answer the question please.
Answer:
49
Step-by-step explanation:
He recieved 8 ticket (even number) per day for 7 days. 8×7=56
56 tickets ÷ 7 days
would equal to him receiving 8 tickets every one of the 7 days.
OK so how do we do this
Evaluate the following. ||13|-|14-6||
please help
5 is the correct value using Mathematical operations of the given expression.
To evaluate the expression ||13| - |14 - 6||, we need to follow the order of operations and simplify it step by step.
The absolute value function can also be understood geometrically as the distance between a number and zero on the number line. Regardless of whether the number is positive or negative, its distance from zero is always positive is a Mathematical operations.
First, let's evaluate the innermost absolute values:
|13| = 13
|14 - 6| = |8| = 8
Now, substitute these values back into the expression:
||13| - |14 - 6|| = ||13 - 8||
Next, evaluate the remaining absolute value:
|13 - 8| = |5| = 5
Therefore, the final result is 5.
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a deck of cards contains red cards numbered 1,2,3,4,5,6,7,8,9, blue cards numbered 1,2,3,4,5 and green cards numbered 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15. if a single card is picked at random, what is the probability that the card is green?
The deck of cards contains a total of 29 cards, of which 15 are green. Therefore, the probability of picking a green card at random can be calculated by dividing the number of green cards by the total number of cards, giving:
P(green) = 15/29
This probability can also be expressed as a decimal or a percentage. As a decimal, it would be 0.5172, and as a percentage, it would be 51.72%. This means that there is a slightly higher than 50% chance of picking a green card at random from this deck.
It is important to note that this probability assumes that the deck is well-shuffled and that all cards have an equal chance of being picked. If the deck is not well-shuffled or if some cards are missing or duplicated, the probability of picking a green card would be affected.
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Write the linear equation in slope intercept form
\(y= - \frac{1}{3} z +2\) is slope intercept form of given equation.
How do you write slope intercept form?Y = mx+b, where m is the slope and b is the y-intercept, is the formula for the slope-intercept form (the point where the line crosses the y-axis). Using y=mx+b to graph a line is typically simple. The standard form and the point-slope form are other formats for linear equations.Y equals mx plus b is actually the slope intercept form. Because it provides both a slope and an intercept, the form is known as a slope intercept form.Given liner equation :
\(\frac{1}{3} z + y = 2\)
\(y = 2 - \frac{1}{3} z\)
\(y= - \frac{1}{3} z +2\)
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What operation is needed to solve this problem: There will be 460 people at the sport’s award banquet. If each table seats 8 people, how many tables are needed?
subtraction
multiplication
division
addition
Observe the table. How many times greater must the acceleration of Object B be than the acceleration of Object A to make the table true? Enter your answer as a whole number, like this: 4 Mass Acceleration Force Object A 20 kg 9 m/s2 180 N Object B 40 kg 1800 N
The acceleration of Object B should be 5 times the acceleration of Object A in order to make the table true.
What is Acceleration?We have a table that gives the values of mass, acceleration and force of object A and object B.
We have to find by how many times greater must the acceleration of Object B be than the acceleration of Object A to make the table true.
The formula to calculate the force is -
F = m x a
From the table,
Mass = 40 Kg
Force = 1800 N
By substitution
a =F/m = 1800/40 = 45 m/s²
The acceleration of Object A is 9m/s² . On comparing the acceleration of both the objects, we can see that the acceleration of Object B is 5 times the acceleration of Object A.
Hence, the acceleration of Object B should be 5 times the acceleration of Object A in order to make the table true.
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Write the equation of the line that passes through the points (-4,3) and (-8,8). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line.
We have to use the slope formula first
\(m=\frac{y_2-y_1}{x_2-x_1}\)Let's replace the given points
\(m=\frac{8-3}{-8-(-4)}=\frac{5}{-8+4}=-\frac{5}{4}\)Then, we use the point-slope formula to find the equation
\(y-y_1=m(x-x_1)\)Let's replace a point and the slope,
\(\begin{gathered} y-3=-\frac{5}{4}(x-(-4) \\ y-3=-\frac{5}{4}(x+4) \\ y=-\frac{5}{4}x-5+3 \\ y=-\frac{5}{4}x-2 \end{gathered}\)Hence, the equation is\(y=-\frac{5}{4}x-2\)I will give brainliest
Answer:
y=-1/2x+2
Step-by-step explanation:
2 = 0 +b
2=b
y=-1/2x+2
Answer:
y = -1/2x + 2
Step-by-step explanation:
Follow the y = mx + b. B stands for the y-intercept, which is 2 in this case. M stands for the slope, which is the constant -1/2. Pls brainliest i want to level up ty!!!!!
If EG = 28 and F is the midpoint of
segment EG, the length of EF =
E
F.
G
Write an inequality for the graph below.
Answer:
i cant see anything
Step-by-step explanation:
.