Fill in the ladder diagram, I added the photo of the diagram.

Fill In The Ladder Diagram, I Added The Photo Of The Diagram.

Answers

Answer 1

Answer:

Step-by-step explanation:

2   I 500              500 ÷ 2 = 250

      2 I 250          250÷2 = 125

            5 I 125         125 ÷ 5 = 25

                 5 I 25

                      5  I 5

                            1


Related Questions

Olga walks 5 blocks to school her friend Louis walks 1/3 of that distance how many blocks does Louis walk to school

Answers

Answer:

Louis walks 1 and 2/3 blocks.

Step-by-step explanation:

To figure this out, what you want to do is multiply 1/3 by 5.

woman bought 1.8 kg of chicken and 1.6 kg of meat. The chicken cost N5.40 and the meat cost #6.40. If she had bought 2.4 kg of chicken and 2 kg of meat, how much would she have had to pay?

Answers

The amount the women would pay for 2.4 kg of chicken and 2 kg of meat in total is $15.2

What is the unit price?

The meaning of unit price is a price quoted in terms of so much per agreed or standard unit of product or service

Given that, a woman bought 1.8 kg of chicken and 1.6 kg of meat. The chicken cost $5.40 and the meat cost $6.40,

We need to find, if she had bought 2.4 kg of chicken and 2 kg of meat, how much would she have had to pay,

To find the same, we will first find the unit price of each,

Unit price = total price / total quantity

Since, 1.8 kg of chicken costs $5.40,

Therefore, 1 kg will cost = 5.40 / 1.8 = $3

Similarly,

If 1.6 kg of meat costs $6.40,

Therefore, 1 kg will cost = 6.40 / 1.6 = $4

Now, to find the cost of 2.4 kg of chicken and 2 kg of meat, we will multiply the unit prices to the required quantities,

Therefore,

2.4 kg of chicken will cost = 2.4 x 3 = $7.2

2 kg of meat will cost = 2 x 4 = $8

In total, she had to pay = 8+7.2 = $15.2

Hence, the amount the women would pay for 2.4 kg of chicken and 2 kg of meat in total is $15.2

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You deposit $300 in an account that earns simple interest at an annual rate of 6.5%.

If no other deposits or withdrawals were made, what is the total amount of money in the account at the end of 8 years?

Answers

Total amount of money in the account will be $456.

How much money will be in the account after 8 years?

Simple interest is an interest charge that borrowers pay lenders for a loan. It is calculated using the principal only and does not include compounding interest.

The formula for simple interest is: Simple Interest = Principal × Rate × Time

Principal (P) is $300

Rate (R) is 6.5%

Time (T) is 8 years.

Simple Interest = $300 × 0.065 × 8

Simple Interest = $156

Total Amount = Principal + Simple Interest

Total Amount = $300 + $156

Total Amount = $456.

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Please help, I don't understand, please
5+(-5)

Answers

Answer: 0

Step-by-step explanation: To make this easier, ignore the addition sign (for this one, at least), so just do 5-5

Answer: 0

Step-by-step explanation:

Simply the expression by combining like terms 6x+9+2x+4

Answers

8x+13 is the simplified version

Amtrak's annual passenger revenue for the years 1985 - 1995 is modeled approximately by the formulaR = -60|x- 11| +962where R is the annual revenue in millions of dollars and x is the number of years after 1980. In what year was the passenger revenue $722 million?In the years ____ and ___, the passenger revenue was $722 million.

Amtrak's annual passenger revenue for the years 1985 - 1995 is modeled approximately by the formulaR

Answers

ANSWER

1987 and 1995

EXPLANATION

The revenue is modeled by:

\(R=-60|x-11|+962\)

To find the years that the revenue was $722 million, we have to solve for x when R is 722.

That is:

\(\begin{gathered} 722=-60|x-11|+962 \\ \Rightarrow722-962=-60|x-11| \\ -240=-60|x-11| \\ \Rightarrow|x-11|=\frac{-240}{-60} \\ |x-11|=4 \end{gathered}\)

We can split the absolute value equation into two different equations because the term in the absolute value is equal to both the positive and the negative of the term on the other side of the equality.

That is:

\(\begin{gathered} x-11=4 \\ x-11=-4 \end{gathered}\)

Solve for x in both:

\(\begin{gathered} x=11+4 \\ \Rightarrow x=15 \\ x=11-4 \\ \Rightarrow x=7 \end{gathered}\)

That is to say 7 and 15 years after 1980.

Therefore, in the years 1987 and 1995, the revenue was $722 million.


13-18 Express the quantity as a single logarithm.
18. \(\ln b+2 \ln c-3 \ln d\)

Answers

Is this what you want?
13-18 Express the quantity as a single logarithm.18. [tex]\ln b+2 \ln c-3 \ln d[/tex]

Evaluate the expression 2y + 3.5. Evaluate the expression for y=1.8, y=4, y=6.9. (there should be three answers)

Answers

Answer:

1. 7.1

2. 11.5

3. 24.2

Step-by-step explanation:

you use P.E.M.D.A.S. for all the equations.

so you do thr multiplication and then the addition

1. 2(1.8)+3.5= 3.6+3.5= 7.1

2. 2(4)+3.5= 8+3.5=11.5

3.2(6.9)+3.5= 13.8+3.5= 24.2

hope this helps

will give brainliest

will give brainliest

Answers

The equation of a hyperbola is  \(x^{2}\)/9 - \(y^{2}\)/4 = 1

What are the steps to Hyperbola equation ?

To find the equation of hyperbola, the following steps must be taken. You need to identify;

The coordinate of the centerThe coordinate of the verticesThe coordinate of the foci

The general equation of a hyperbola can be expressed as

\(x^{2}\)/\(a^{2}\) - \(y^{2}\)/\(b^{2}\) = 1

From the graph, we have the following parameters

a = 3

\(a^{2}\) = \(3^{2}\) = 9

b = 2

\(b^{2}\) = \(2^{2}\) = 4

The equation of a hyperbola can be expressed as

\(x^{2}\)/9 - \(y^{2}\)/4 = 1

The vertices = V(+/-a,0) = (+/-3,0)

The center = C(0,0)

The focus = F(+/-C, 0)

Where \(C^{2}\) = \(a^{2}\)  + \(b^{2}\)

C = \(\sqrt{9 + 4}\)

C = \(\sqrt{13}\)

Focus = F(+/- \(\sqrt{13}\), 0)

The general equation for asymptote = +/- b/a X

= +/-2/3X

Therefore, the equation of a hyperbola can be expressed as

\(x^{2}\)/9 - \(y^{2}\)/4 = 1

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Find the local and absolute maximum and minimum points in (x, y) format for the

function f(x) = 3/5x^5 - 9x^3 + 2 on the closed interval [-4,5]. Answer the following

questions.

a) Find all critical numbers (x- coordinates only)

b) Find the intervals on which the graph is increasing Mark critical numbers

c) Find the intervals on which the graph is decreasing.

d) Find all local maximum points.

e) Find all local minimum points.

f) Find all absolute maximum points.

g) Find all absolute minimum points.

Answers

To find the local and absolute maximum and minimum points of the function f(x) = (3/5)x^5 - 9x^3 + 2 on the closed interval [-4,5], we need to follow these steps:

a) Find all critical numbers (x-coordinates only):

To find the critical numbers, we need to identify where the derivative of the function is zero or undefined. Let's find the derivative of f(x) first:

f'(x) = 3x^4 - 27x^2

Now, set the derivative equal to zero and solve for x:

3x^4 - 27x^2 = 0

Factoring out a common factor of 3x^2, we get:

3x^2(x^2 - 9) = 0

This equation is satisfied when either 3x^2 = 0 or x^2 - 9 = 0.

For 3x^2 = 0, we have x = 0.

For x^2 - 9 = 0, we have x = -3 and x = 3.

Therefore, the critical numbers (x-coordinates) are 0, -3, and 3.

b) Find the intervals on which the graph is increasing (mark critical numbers):

To determine the intervals of increasing, we need to analyze the sign of the derivative on each side of the critical numbers. We create a sign chart for f'(x):

Interval (-∞, -3): Choose a test point x < -3, e.g., x = -4

f'(-4) = 3(-4)^4 - 27(-4)^2 = 768 > 0

The derivative is positive, indicating the graph is increasing.

Interval (-3, 0): Choose a test point x between -3 and 0, e.g., x = -1

f'(-1) = 3(-1)^4 - 27(-1)^2 = -24 < 0

The derivative is negative, indicating the graph is decreasing.

Interval (0, 3): Choose a test point x between 0 and 3, e.g., x = 1

f'(1) = 3(1)^4 - 27(1)^2 = -24 < 0

The derivative is negative, indicating the graph is decreasing.

Interval (3, ∞): Choose a test point x > 3, e.g., x = 4

f'(4) = 3(4)^4 - 27(4)^2 = 768 > 0

The derivative is positive, indicating the graph is increasing.

Therefore, the graph is increasing on the intervals (-∞, -3) and (3, ∞).

c) Find the intervals on which the graph is decreasing (mark critical numbers):

From the analysis above, we can see that the graph is decreasing on the intervals (-3, 0) and (0, 3).

d) Find all local maximum points:

To find the local maximum points, we need to examine the points where the graph changes from increasing to decreasing. By observing the sign changes in the derivative, we can identify potential local maximum points.

From our analysis in part b, we can see that the graph changes from increasing to decreasing at x = -3 and x = 0. Therefore, these are the local maximum points.

e) Find all local minimum points:

To find the local minimum points, we need to examine the points where the graph changes from decreasing to increasing. By observing the sign changes in the derivative, we can identify potential local minimum points.

From our analysis in part c, we can see that the graph changes.

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To evaluate whether customers enjoy the barista’s new smoothie, a restaurant manager surveys every other customer who orders the new smoothie. The manager determines that customers enjoy the new smoothie. Select all the statements that are true about the sampling method.

Answers

The sampling method used by the restaurant manager allows for efficient data collection and a representative sample, it may introduce bias and lacks randomization.

Based on the information provided, we can identify the following statements that are true about the sampling method used by the restaurant manager to evaluate customer satisfaction with the new smoothie:

1. The manager uses systematic sampling: The manager surveys every other customer who orders the new smoothie. This systematic approach involves selecting every second customer, providing a consistent and organized sampling method.

2. The sample is representative: By surveying every other customer who orders the new smoothie, the manager ensures that the sample includes a variety of customers, reflecting the customer population as a whole.

3. The sample size may be smaller than the total customer base: Since the manager surveys every other customer, the sample size may be smaller compared to surveying every customer. This allows for efficient data collection and analysis.

4.The sampling method may introduce bias: The manager may inadvertently introduce bias by only surveying every other customer. Customers who are skipped in the survey may have different preferences or opinions, leading to a potential bias in the results.

5. The sampling method lacks randomization: Randomization is not employed in this sampling method, as the manager systematically selects customers. This could potentially introduce bias or exclude certain types of customers from the sample.

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please answer this question


please answer this question

Answers

Answer:

\(\dfrac{dy}{dx}=\cot x+\dfrac{1}{x}\)

Step-by-step explanation:

\(\boxed{\begin{minipage}{6 cm}\underline{Product\:Rule}\\\\$\dfrac{d}{dx}[f(x)g(x)]=f(x)g'(x)+f'(x)g(x)$\\\\\\\underline{Chain\:Rule}\\\\$\dfrac{dy}{dx}=\dfrac{dy}{du} \times \dfrac{du}{dx}$\\\end{minipage}}\)

\(\textsf{Given}:y=\log (x \sin x)\)

\(\textsf{Let }u=x \sin x \implies y=\log(u)\)

Using the product rule, differentiate y with respect to \(u\):

\(\textsf{If }y=\log(u) \implies \dfrac{dy}{du}=\dfrac{1}{u}\implies \dfrac{dy}{du}=\dfrac{1}{x \sin x}\)

----------------------------------------------------------------------------------------

Differentiate \(u=x \sin x\) with respect to x using the product rule:

\(\implies \textsf{Let }f(x)=x \implies f'(x)=1\)

\(\implies \textsf{Let }g(x)=\sin x \implies g'(x)=\cos x\)

\(\implies \dfrac{du}{dx}=x \cos x + \sin x\)

----------------------------------------------------------------------------------------

Use the chain rule to differentiate y with respect to x:

\(\implies \dfrac{dy}{dx}=\dfrac{dy}{du} \times \dfrac{du}{dx}\)

\(\implies \dfrac{dy}{dx}=\dfrac{1}{x \sin x} \times (x \cos x + \sin x)\)

\(\implies \dfrac{dy}{dx}=\dfrac{x \cos x + \sin x}{x \sin x}\)

\(\implies \dfrac{dy}{dx}=\dfrac{x \cos x}{x \sin x}+\dfrac{\sin x}{x \sin x}\)

\(\implies \dfrac{dy}{dx}=\cot x+\dfrac{1}{x}\)

Answer:

\(\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{1}{x\ln 10} + \dfrac{\cot x}{\ln 10}}\)

Step-by-step explanation:

Given:

\(\displaystyle \large{y=\log (x\sin x)}\)

Recall the (common) logarithmic differentiation & chain rules:

\(\displaystyle \large{\dfrac{d}{dx}[\log (u)] = \dfrac{u'}{u\ln 10}}\)

Let \(\displaystyle \large{u=x\sin x}\) then:

\(\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{(x\sin x)'}{x\sin x \ln 10}}\)

Recall product rules:

\(\displaystyle \large{[f(x)g(x)]' = f'(x)g(x)+f(x)g'(x)}\)

Hence:

\(\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{(x)'\sin x + x(\sin x)'}{x\sin x \ln 10}}\\\\\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{\sin x + x\cos x}{x\sin x \ln 10}}\\\\\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{\sin x}{x \sin x \ln 10} + \dfrac{x \cos x}{x\sin x \ln 10}}\\\\\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{1}{x\ln 10} + \dfrac{\cot x}{\ln 10}}\)

From above, recall that:

\(\displaystyle \large{\dfrac{d}{dx}(\sin x) = \cos x}\\\\\displaystyle \large{\dfrac{A\pm B}{C} = \dfrac{A}{C} \pm \dfrac{B}{C}}\\\\\displaystyle \large{\dfrac{\cos x}{\sin x} =\cot x}\)

Hence, the answer is:

\(\displaystyle \large{\dfrac{d}{dx}[\log(x\sin x)] = \dfrac{1}{x\ln 10} + \dfrac{\cot x}{\ln 10}}\)

The Kwon family has a rainwater catchment system they use to water their garden. The
storage tank is 80 inches deep. After 3 hours of rain, the depth of water in the tank is 37
inches. After 5 hours, the depth is 60 inches. If the rain continues to fall at the same rate,
how many hours will it take to fill the tank? Round your answer to the nearest tenth.
N
hours

Answers

Answer:

about 7 hours

Step-by-step explanation:

i smart


In the diagram a person who is ft tall is standing on the ground ft away from point . A line segment drawn from the top corner of the building to point creates two similar triangles.

Answers

The height of the building, using similar triangles, is given by:

36 feet.

What are similar triangles?

Similar triangles are two triangles that share these two features, which are listed as follows:

Same angle measures.Proportional side lengths.

The second bullet point, regarding proportional side lengths, is especially relevant in the context of this problem, as a proportional relationship is built to find the height h of the building.

From the similar triangles, the equivalent side lengths are presented as follows:

3 ft and 18 ft.6 ft and h ft.

Hence the proportional relationship that models this situation is presented as follows:

3/18 = 6/h.

Applying cross multiplication, the height of the building is obtained as follows:

3h = 18 x 6

h = 6 x 6 (simplifying by 3)

h = 36 feet.

Missing Information

The diagram is given by the image shown at the end of the answer.

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In the diagram a person who is ft tall is standing on the ground ft away from point . A line segment

Ed needed to extend the string on his kite. The current string was nine and three fourths feet. He cut a piece of string that measured 2.5 feet and added it to the existing string. What is the new length of the string?

twelve and one fourth feet
eleven and three fourths feet
seven and one half feet
seven and one fourth feet

Answers

Answer:

Twelve and one fourth feet

Step-by-step explanation:

9 and 3/4 feet =9.75

2 and 2/4 feet =2.50

9.75 + 2.50

= 12.25/12 and 1/4 feet

how many half's are in a whole

Answers

2

1/2 plus 1/2 = 1

Hope this helps and have a nice day!!!

(If it is right don’t forget to mark branliest :) )

Answer:

Two

Step-by-step explanation:

Because 1/2 plus 1/2 equals 1 witch would be the final half to make one whole

A circle of sunflowers is planted in Stanford's central Park. The circle has a diameter of 12 feet. What is the circle's radius?​

Answers

Answer:

Step-by-step explanation:

radius = ½×diameter = 6 ft

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil for a 2-year period. The maximum penetration (in mils) for each specimen is then measured, yielding a sample average penetration of x= 53.8 and a sample standard deviation of s = 4.3. The conduits were manufactured with the specification that true average penetration be at most 50 mils. They will be used unless it can be demonstrated conclusively that the specification has not been met. What would you conclude?
State the rejection region(s) for an α =0.05 test. If the critical region is one-sided, enter NONE for the unused region. Round your answers to two decimal places.
z≤_____
z≥_____
Compute the test statistic value. Round answer to 2 decimal places.
z = _____

Answers

Statistic value t = 5.975 ≈6

p-value: < 0.00002.

The corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Maximum penetration of a steel conduit.

The data of the sample :

n= 45

sample mean X[bar]= 53.4

sample standard deviation , S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

\(t_{n -1; 1 - \alpha }\) =  \(t_{44; 0.95} = 1.68\)

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= \(\frac{53.8 - 50}{\frac{4.3} \sqrt{45} }\)

t= 5.9375 ≈ 6

The calculated value is greater than the critical value, the decision is to reject the null hypothesis.

p-value:

P(t ≥ 5.93) = 1 - P(t < 5.93) = < 0.00002.

The p-value is less than α. Thus, the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

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What postulate or theorem allows you to state that angle DEF is congruent to angle GHJ

Answers

Then you can state that angle DEF is congruent to angle GHJ.

The postulate or theorem that allows you to state that angle DEF is congruent to angle GHJ is the Angle-Angle (AA) Postulate.

This postulate states that if two angles of one triangle are congruent to two angles of another triangle, then the third pair of angles must also be congruent.

In this case, if you have two triangles, one with angles DEF and the other with angles GHJ, and

you know that angle D is congruent to angle G and angle E is congruent to angle H, then by the AA Postulate, you can conclude that angle F is congruent to angle J.

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what a subcategory of a polygon

Answers

Three or more line segments that only intersect at their ends form closed, two-dimensional shapes known as polygons.

What is a polygon?

A polygon is a closed, two-dimensional shape with straight sides that is flat or plane. It has straight sides. Polygons are a different category that belongs to the category of two-dimensional figures because two-dimensional (2D) figures are flat because they lack volume.

Polygons are flat 2D shapes that have straight lines and all lines are closed, meaning that they don't have any disconnected lines. Polygons are a subcategory of 2D figures because they carry all traits of 2D figures but also have special ones of their own. Examples of polygons are squares, rectangles, and triangles. Examples of nonpolygons but still are 2D figures are circles, ovals, and any other flat shape.

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Complete question

How can polygons be considered a subcategory of two-dimensional figures?

what is 6% of 3125 ​

Answers

Answer:

187.5

Step-by-step explanation:

6% of 3125 ​

=> 6/100 x 3125

=> 18750/100

=> 187.5

The odds against an event are 19 to 12 find the probability that The event will occur

Answers

Answer:

the event is odds against an event of the 19 to 12 is probability is the 19

The probability of occurring the event is 12/31.

What is probability?

Probability is the chance of occurrence of a certain event out of the total no. of events that can occur in a given context.

We know if the odds against an event is a : b then the probability of occurring the event is b/(a + b).

Given, The odds against an event are 19 to 12.

∴ The probability of occurring the event is 12/(19 + 12) = 12/31.

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3х + 5x
Pls help (sorry if this question got deleted)

Answers

Answer:

8x

Step-by-step explanation:

3x+5x=8x

3+5=8

x is the same variable.

ln the given ration 3:4 the consequent is 7,4,3

Answers

\(\\ \rm\longmapsto 3:4\)

Convert to fraction

\(\\ \rm\longmapsto \dfrac{3}{4}\)

4 is the consequent

Note.

The first term of the ratio is called consequent.

Answer:

Loading...

Step-by-step explanation:

what is 999.09344471 rounded to the nearest square kilometer?

Answers

The nearest kilometers to 999.09344471 km is 1000 km.

Given value is 999.09344471 Km.

We have to calculate the round off value to the nearest kilometers. we know that after the decimal if the value of tenth place is 5 or bigger than 5 then we add 1 to the tens place digit, this is the fundamental rule of rounding off.

Now on following this rule from the very right hand side up to the tenth place digit we come to the conclusion that only  the value after the decimal (934) is to be rounded off which is (900).

So 999.09344471 km is finally becomes 999.900 km after rounding of to nearest hundredth value.

Again rounding off 999.900 km to nearest km so it becomes 1000 km.

The nearest kilometers to 999.09344471 km is 1000 km.

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Find what minimum population size you need to have if you have a 99% confidence, 100 standard deviation and want a size 3 margin of error

Answers

A minimum population size of approximately 7373 to achieve a 99% confidence interval with a margin of error of 3 and a known standard deviation of 100.

How to calculate the minimum population size?

To calculate the minimum population size required to achieve a 99% confidence interval with a margin of error of 3 and a known standard deviation of 100, we can use the following formula:

n = [(z-value × SD) / ME]²

Where:

n = the minimum sample size required

z-value = the critical value for the desired confidence level (99% in this case)

SD = the known standard deviation (100 in this case)

ME = the desired margin of error (3 in this case)

First, we need to determine the z-value for a 99% confidence level. Using a standard normal distribution table, we find that the z-value for a 99% confidence level is approximately 2.576.

Substituting the values into the formula, we get:

n = [(2.576 × 100) / 3]²

Simplifying this expression, we get:

n = 7373.08

Therefore, we would need a minimum population size of approximately 7373.

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Colah Company purchased $2,000,000 of Jackson, Inc., 6% bonds at par on July 1, 2021, with interest paid semi-annually. Colah determined that it should account for the bonds as an available-for-sale investment. At December 31, 2021, the Jackson bonds had a fair value of $2,300,000. Colah sold the Jackson bonds on July 1, 2022 for $1,800,000.


Required:
1. Prepare Colah’s journal entries for the following transactions:

The purchase of the Jackson bonds on July 1.
Interest revenue for the last half of 2021.
Any year-end 2021 adjusting entries.
Interest revenue for the first half of 2022.
Any entries necessary upon sale of the Jackson bonds on July 1, 2022, including updating the fair-value adjustment, recording any reclassification adjustment, and recording the sale.
2. Complete the following table to show the effect of the Jackson bonds on Colah’s net income, other comprehensive income, and comprehensive income for 2021, 2022, and cumulatively over 2021 and 2022.

Answers

If Colah Company purchased $2,000,000 of Jackson, Inc., 6% bonds at par on July 1, 2021. The journal entries for the purchase of the Jackson bonds on July 1 is: Debit Available-for-sale securities $2,000,000

Credit Cash $2,000,000.

What is journal entry?

Journal entry is used by companies to record their day to day business transaction.

July 1 2021

Debit Available-for-sale securities $2,000,000

Credit Cash $2,000,000

December 31 2021

Debit Cash $60,000

Credit Interest income  $60,000

(6% ×$2,000,000 / 2)

December 31 2021

Debit Available-for-sale securities $300,000

Unrealized Gain - Other comprehensive income $300,000

($2,000,000 - $2,300,000)

June 30 2022

Debit Cash $60,000

Credit Interest income  $60,000

(6% ×$2,000,000 / 2)

The entry necessary upon sale of the Jackson bonds on July 1, 2022 is:

July 1 2022

Debit Available-for-sale securities  $2,300,000

Unrealized Gain-Other comprehensive income account $300,000

Credit Cash $1,800,000

Credit Realized Loss on the sale of Available-for-sale securities $200,000  

[$1,800,000 - $2,000,000= $200,000 (Realized Loss)]

2. Table to show the effect of the Jackson bonds on Colah’s net income,

                             2021                   2022                       Total

Net Income       $60 ,000        ($140,000)              ($80,000)

( 60,000 - $200,000= -$140,000)

OCI                       $300,000                                         $300,000

Comprehensive Income $360,000 ($140,000) $220,000

Therefore the  journal entries for the purchase of the Jackson bonds on July 1 is: Debit Available-for-sale securities $2,000,000

Credit Cash $2,000,000.

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an entomologist expects an insect population to increase by about 20% each month from may 1 to spetember 1

Answers

The insects population expected after 4 months is 414.

What is an equation?

An equation is an expression that contains numbers and variables linked together by mathematical operations of addition, subtraction, multiplication, division and exponents. An equation can either  be linear, quadratic, cubic, depending of the degree of the variable.

The standard form of an exponential function is:

y = abˣ

where a is the initial value and b is the multiplication factor.

An entomologist expects an insect population to increase by about 20% each month from may 1 to September 1.

Let us assume that the population of insect on May first was 200. If y represent the population of insects x months after May 1, hence:

y = 200(1.2)ˣ

At September 1; after 4 months:

y = 200(1.2)⁴ = 414

The insects population after 4 months is 414.

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Can anyone help me on this one

Can anyone help me on this one

Answers

Hello !

Answer :

\({x}^{ - \frac{8}{3} }\)\(\sqrt[3]{ {x}^{ - 8} }\)\(\sqrt[3]{ ({x}^{ 4}) {}^{ - 2} }\)

Explanation :

\( \to \boxed{ ({x}^{a}) {}^{b} = {x}^{ab} } \)

\( \to \boxed{ {x}^{ \frac{1}{n} } {}^{} = \sqrt[n]{x} } \)

\( ({x}^{4} ) {}^{ - \frac{2}{3} } = {x}^{- \frac{2}{3} \times 4} \\ \boxed{= {x}^{ - \frac{8}{3} } } \\ \boxed{= \sqrt[3]{ {x}^{ - 8} }} \\ \boxed{ = \sqrt[3]{ ({x}^{ 4}) {}^{ - 2} }}\)

Have a nice day ;)

Choose as many answers as apply.
According to the lesson, things you can do to help you decide on a bank include:
compare interest rates
determine which bank has the most attractive buildings
ask friends where they bank
visit two or three branch office

Answers

Some things you can do to help you decide on a bank include:

Ask friends where they bankVisit two or three branch officesCompare interest rates

Why are these important?

When trying to locate a bank that offers competitive returns on savings and favorable borrowing costs, consider comparing interest rates.

To gather additional information about certain banks, why not solicit feedback from acquaintances? People who have personal experience with a particular bank can provide valuable insights into their satisfaction levels with regards to customer service, for example.

Finally, taking the time to visit branch offices can offer valuable clues regarding convenience level and overall atmosphere.

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