Fill in the blank with the correct rule

Answer: -3.11 x 10^ 1

Step-by-step explanation: - 3

3.11 X 10 = -31.1, in decimal form -3.11 x 10^ 1

I

No, the inference is not valid because it excluded those who were not online and so did not see the poll.

To improve the poll, the news show could have conducted it in a more representative manner by surveying a larger sample of people from a variety of backgrounds

How to improve the poll ?

The poll's results may have been influenced by various factors, including but not limited to the order in which the comedians were presented, the demographics of the respondents, and the fact that it was conducted online, possibly excluding those without internet access. Overall, the poll's representative accuracy is questionable.

To enhance the accuracy of the survey, the broadcast could have implemented a more inclusive method by polling a wider range of individuals from diverse backgrounds. An alternate method for conducting the poll would have been by personal or telephonic means, enabling individuals without internet connectivity to participate.

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Answer: sexual regulations, reproduction, economic cooperation and socialization/education.

Step-by-step explanation:

I’m not sure if that’s right

After emphasizing the universal character of the family, the anthropologist George Murdock (1949) argued that the family has four basic social functions: sexual regulations, reproduction, economic cooperation and socialization/education.

The maximum value of the objective function is 31.787

How to maximize the function?

The given parameters are:

Objective function:

Max P = 4x + 5y + 21

Subject to:

y- x < 1

21x + 7y < 25

x>-2,  y>-4

Rewrite the inequalities as equation

y - x = 1

21x + 7y =  25

Add x to both sides in y - x = 1

y = x + 1

Substitute y = x + 1 in 21x + 7y =  25

21x + 7x + 7 =  25

Evaluate the like terms

28x = 18

Divide both sides by 28

x = 0.643

Substitute x = 0.643 in y = x + 1

y = 0.643 + 1

y = 1.643

So, we have:

Max P = 4x + 5y + 21

This gives

P = 4 * 0.643 + 5* 1.643 + 21

Evaluate

P = 31.787

Hence, the maximum value of the objective function is 31.787

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Answer, step-by-step explanation:

A. With the previous exercise we can deduce that there is the situation of a number of sales in a grocery store, the relative frequency for the number of units sold, is shown below:

units sold. relative frequency. Acumulative frequency. interval of random numbers

30. 0.16. 0.16. 0.00 <0.16

40. 0.24. 0.4. 0.16 <0.4

50. 0.3. 0.7. 0.4 <0.7

60. 0.2. 0.9. 0.7<09

70. 0.1. 1. 0.9<1

B. For the next point, they give us some random numbers and then it is compared with the simulation of 10 days in sales:

random Units

number. sold

0.12. 30

0.96. 70

0.53. 50

0.80. 60

0.95. 70

0.10. 30

0.40. 50

0.45. 50

0.77. 60

0.29. 40

the two lists are compared so that opposite each one is the result of the simulation

Answer:

To find the volume of the shipping box in cubic feet, we need to convert the dimensions from inches to feet and then calculate the volume.

Given:

Length = 36 inches

Width = 24 inches

Height = 18 inches

Converting the dimensions to feet:

Length = 36 inches / 12 inches/foot = 3 feet

Width = 24 inches / 12 inches/foot = 2 feet

Height = 18 inches / 12 inches/foot = 1.5 feet

Now, we can calculate the volume of the box by multiplying the length, width, and height:

Volume = Length * Width * Height

Volume = 3 feet * 2 feet * 1.5 feet

Volume = 9 cubic feet

Therefore, the shipping box can hold 9 cubic feet.

Step-by-step explanation:

First convert the units because it's asking for the cubic feet but they give us the measurements in inches.

To convert inches to feet we divide the number by 12.

36 ÷  12 = 3

24 ÷  12 = 2

18 ÷ 12 = 1.5

Now to find the volume, we multiply it all together.

3 × 2 × 1.5 = 9

It can hold 9 cubic feet.

Hope this helped!

Answer:

Can you import the progress report picture please

Step-by-step explanation:

So we can solve it

Answer:

Given:

Two angles of a triangle are of measures  53 & 44.

We need to find the measure of the unknown angle.

According to the angle sum property, Sum of all angles of a triangle is 180°

Thus, 44°+53°+m∠1=180°

⇒ 97 + m∠1 = 180°

⇒ m∠1 = 180° - 97°

⇒ m∠1 = 83°

Therefore (B) 83 is the correct answer

Do you are do me are you di I number 285g72

Answer:

option D

the set of all points that are a fixed distance from a given point

hope it helps

To graph the function g(x) = 7x + 10, we shift the graph of f(x) = 7x vertically by adding a constant term of +10. This means every y-coordinate on the graph increases by 10 units. The slope of the line remains the same at 7. The resulting graph is a straight line passing through (0, 10) with a slope of 7.

To graph the function g(x) = 7x + 10, you need to make the following change to the graph of f(x) = 7x:
1. Translation: The graph of f(x) = 7x can be shifted vertically by adding a constant term to the equation. In this case, the constant term is +10.
Here's how you can do it step by step:
1. Start with the graph of f(x) = 7x, which is a straight line passing through the origin (0,0) with a slope of 7.
2. To shift the graph vertically, add the constant term +10 to the equation. Now, the equation becomes g(x) = 7x + 10.
3. The constant term of +10 means that every y-coordinate of the points on the graph will increase by 10 units. For example, the point (0,0) on the original graph will shift to (0,10) on the new graph.
4. Similarly, if you take any other point on the original graph, such as (1,7), the corresponding point on the new graph will be (1,17) since you add 10 to the y-coordinate.
5. Keep in mind that the slope of the line remains the same, as only the y-values are affected. So, the new graph will still have a slope of 7.
By making this change, you will have successfully graphed the function g(x) = 7x + 10.

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Answer:

34(8)

Step-by-step explanation:

Thomas' installment payment that he pays in one fortnight is approximately k523.08.

To calculate Thomas' installment payment, we need to consider the principal amount (k10,000) and the interest rate (36%).

First, let's calculate the total amount to be repaid at the end of the year, including the interest. The interest is calculated as a percentage of the principal amount:

Interest = Principal × Interest Rate

= k10,000 × 0.36

= k3,600

The total amount to be repaid is the sum of the principal and the interest:

Total Amount = Principal + Interest

= k10,000 + k3,600

= k13,600

Now, we need to calculate the number of fortnights in a year. There are 52 weeks in a year, and since each fortnight consists of two weeks, we have:

Number of Fortnights = 52 weeks / 2

= 26 fortnights

To find the installment payment for each fortnight, we divide the total amount by the number of fortnights:

Installment Payment = Total Amount / Number of Fortnights

= k13,600 / 26

≈ k523.08

Therefore, Thomas' installment payment that he pays in one fortnight is approximately k523.08.

It's important to note that this calculation assumes equal installment payments over the course of the year. Different repayment terms or additional fees may affect the actual installment amount. It's always advisable to consult with the bank or financial institution for accurate information regarding loan repayment.

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In order to apply the dilation, just multiply by 2 each coordinate of the given point (1,4):

(1 , 4) => (1x2 , 4x2) = (2 , 8)

Hence, the image point is (2,8)

Answer:

x=44/43

Step-by-step explanation:

Subtract 1 from both sides

Simplify

Divide both sides by the same term

Cancel terms that are in both the numerator and the denominator

Answer: 20% of 160 is 32.

Step-by-step explanation:

The percentage is from the word percent which means one part in a hundred. It is a part of the base or the whole determined by the rate. Usually, the percentage is smaller than the base. However, there are also cases where the percentage is greater than the base. This happens when the percent is greater than 100%.

To find the percentage, you have to multiply the base and the rate. The base is the 100% or original amount or the whole while the rate is the ratio of the percentage to the base and it has the percent sign (%). Remember that you have to convert the rate to a decimal number by moving the decimal point twice to the left.

Let us now find the 20% of 160.

20% = 0.2

percentage = 160 × 0.2

= 32

Answer:

b

Step-by-step explanation:

bc when you add the last 2 numbers (on the bottom) you get 8568 but then u have to add find the decimal places which would be 2 so it is b, 85.68

The charges will be equal when each car travels 2000 miles. To find the charge for that distance, we substitute x = 2000 into either equation.

To determine the number of miles at which the charges for the two car services, A and B, are equal, we can set up an equation based on the given information.

Let's represent the charge for car service A as y_A and the charge for car service B as y_B. We can set up the following equations:

For car service A: y_A = 0.60x + 300 (in cents)

For car service B: y_B = 0.75x (in cents)

To find the number of miles at which the charges are equal, we set y_A equal to y_B and solve for x:

0.60x + 300 = 0.75x

Subtracting 0.60x from both sides:

300 = 0.15x

Dividing both sides by 0.15:

x = 300 / 0.15

x = 2000

Therefore, the charges will be equal when each car travels 2000 miles. To find the charge for that distance, we substitute x = 2000 into either equation. Let's use the equation for car service A:

y_A = 0.60(2000) + 300

y_A = 1200 + 300

y_A = 1500 cents or $15.00

So, when each car travels 2000 miles, the charges will be equal at $15.00.

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The length of BD is 18.5 units.

In the given right triangle ABC, with altitude BD drawn to hypotenuse AC, we are given the lengths AD = 22 and DC = 15. We need to find the length of BD.

Let's consider triangle ABD. Since BD is the altitude, it divides the right triangle ABC into two smaller right triangles: ABD and CBD.

In triangle ABD, we have the following sides:

AB = AD = 22 (given)

BD = ?

Now, let's consider triangle CBD. In this triangle, we have the following sides:

BC = DC = 15 (given)

BD = ?

Since triangles ABD and CBD share the same base BD, and their heights are the same (BD), we can say that the areas of these triangles are equal.

The area of triangle ABD can be calculated as:

Area(ABD) = (1/2) * AB * BD

Similarly, the area of triangle CBD can be calculated as:

Area(CBD) = (1/2) * BC * BD

Since the areas of ABD and CBD are equal, we can equate their expressions:

(1/2) * AB * BD = (1/2) * BC * BD

We can cancel out the common factor (1/2) and solve for BD:

AB * BD = BC * BD

Dividing both sides of the equation by BD (assuming BD ≠ 0), we get:

AB = BC

In triangle ABC, the lengths AB and BC are equal, which implies that triangle ABC is an isosceles right triangle. In an isosceles right triangle, the leg's length are congruent, so AB = BC = AD = DC.

BD is equal to half of the hypotenuse AC:

BD = (1/2) * AC

Substituting the given values, we have:

BD = (1/2) * (AD + DC) = (1/2) * (22 + 15) = (1/2) * 37 = 18.5

Therefore, the length of BD is 18.5 units.

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Answer:

the 4th statement

Step-by-step explanation:

Answer:

all numbers greater than 8

Step-by-step explanation:

simply pick any number greater than 8, since the > symbol is in front of 8. By the way, you cannot pick 8. :) I hope this helps!

The correct value of 2f(a-1) is 2a^2 - 12a + 10.

To find the value of 2f(a-1), we need to substitute (a-1) into the function f(x) and then multiply the result by 2.

Given: f(x) = x^2 - 4x

Substituting (a-1) into the function:

f(a-1) = (a-1)^2 - 4(a-1)

Expanding and simplifying:

f(a-1) = (a^2 - 2a + 1) - (4a - 4)

f(a-1) = a^2 - 2a + 1 - 4a + 4

f(a-1) = a^2 - 6a + 5

Now, we multiply the result by 2:

2f(a-1) = 2(a^2 - 6a + 5)

Expanding:

2f(a-1) = 2a^2 - 12a + 10

Therefore, the value of 2f(a-1) is 2a^2 - 12a + 10.

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Answer:

\(-4x^{2} +11\) is a parabola. The coefficient in front of the highest term (-4 in front of the \(x^{2}\)) is negative, meaning both of the ends go towards negative infinity (point downward). So, as x approaches positive or negative infinity, y approaches negative infinity.

The end behavior of the function is being divergent for \(x \to \pm \infty\).

According to theory of limits and differential calculus, all polynomial functions are continuous and differentiable function with no limits for \(x \to \pm \infty\). Therefore, we can conclude that function \(h(x) = -4\cdot x^{2}+11\) diverges to \(-\infty\) for \(x > 0\) or \(x < 0\).

That is,

\(x \to +\infty\)

\(\lim_{x \to +\infty} -4\cdot x^{2} + 11 = -4 \cdot \lim_{x \to +\infty} x^{2} + \lim_{x \to +\infty} 11\)

\(\lim_{x \to +\infty} -4\cdot x^{2} + 11 = N.E. + 11\)

\(\lim_{x \to +\infty} -4\cdot x^{2} + 11 = N.E.\)

\(x \to -\infty\)

\(\lim_{x \to -\infty} -4\cdot x^{2} + 11 = -4 \cdot \lim_{x \to -\infty} x^{2} + \lim_{x \to -\infty} 11\)

\(\lim_{x \to -\infty} -4\cdot x^{2} + 11 = N.E. + 11\)

\(\lim_{x \to -\infty} -4\cdot x^{2} + 11 = N.E.\)

Hence, the end behavior of the function is being divergent for \(x \to \pm \infty\).

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The mean of a distribution is 217, while the median is 217.The statements is likely to be true about the distribution is  option  D. It is not symmetrical.

The distribution is likely to be asymmetrical if the mean and median have different values. If the mean and median of a distribution are equal, it is likely that the distribution is symmetrical, which means it has equal tail sizes on both sides. However, if the mean and median are not equal, it indicates that the distribution is skewed.

A negatively skewed distribution means that the mean is less than the median, whereas a positively skewed distribution means that the mean is greater than the median.In this case, since the mean and median of the distribution are equal, it is likely to be symmetrical. Since none of the options say "symmetrical," option D, "It is not symmetrical," is the correct answer.

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Answer:

b < 3

Step-by-step explanation:

3 ( b - 5 ) < - 2b

3 ( b ) - 3 ( 5 ) < - 2b

3b - 15 < - 2b

3b + 2b < 15

5b < 15

b < 15/5

b < 3

First add the 5 over.
3(b-5)<-2b
3b<-2b+5
Add the 2b over.
5b<5
Divide by 5.
b<1
Check by plugging in.
3(1-5)<-2(1)
3(-4)<-2
-12<-2
1 is a possibly solution to the inequality.

Let's start by setting up a proportion with the information given.

25% = 75/x

To solve for x, we can cross-multiply:

0.25x = 75

Then, we can divide both sides by 0.25:

x = 300

Therefore, there are 300 6th-grade students in total.

Answer:

where are the options??

Answer:

x = − 1 ± i

Step-by-step explanation:

Answer:

50 cards

Step-by-step explanation:

We can start by saying that his total card collection has x cards in it, meaning that 28% or 28/100 of his total cards, x, is equal to 14. Next, we can divide by 28/100 on both sides, and dividing is the same as multiplying by the reciprocal. The reciprocal of 28/100 is 100/28, so 14 * 100/28 is equal to 100/2, which is 50. We can say that 50 cards were in his card collection initially.

Answer:

\(\displaystyle f'(1) = \frac{3}{2}\)

\(\displaystyle f''(1) = \frac{3}{4}\)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Algebra II

Exponential Rule [Rewrite]:                                                                            \(\displaystyle b^{-m} = \frac{1}{b^m}\)Exponential Rule [Root Rewrite]:                                                                   \(\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}\)

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Property [Addition/Subtraction]: \(\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]\)

Derivative Rule [Product Rule]:                                                                             \(\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)\)

Derivative Rule [Quotient Rule]:                                                                           \(\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}\)

Step-by-step explanation:

Step 1: Define

f(x) = x√x

f'(1) is x = 1 for 1st derivative

f''(1) is x = 1 for 2nd derivative

Step 2: Differentiate

[1st Derivative] Product Rule:                                                                       \(\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[\sqrt{x}]\)[1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         \(\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[x^{\frac{1}{2}}]\)[1st Derivative] Basic Power Rule:                                                                 \(\displaystyle f'(x) = (1 \cdot x^{1 - 1})\sqrt{x} + x(\frac{1}{2}x^{\frac{1}{2}-1})\)[1st Derivative] Simply Exponents:                                                               \(\displaystyle f'(x) = (1 \cdot x^0)\sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})\)[1st Derivative] Simplify:                                                                                 \(\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})\)[1st Derivative] Rewrite [Exponential Rule - Rewrite]:                                 \(\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2x^{\frac{1}{2}}})\)[1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         \(\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2\sqrt{x}})\)[1st Derivative] Multiply:                                                                                 \(\displaystyle f'(x) = \sqrt{x} + \frac{x}{2\sqrt{x}}\)[2nd Derivative] Rewrite [Exponential Rule - Root Rewrite]:                     \(\displaystyle f'(x) = x^{\frac{1}{2}} + \frac{x}{2x^{\frac{1}{2}}}\)[2nd Derivative] Basic Power Rule/Quotient Rule [Derivative Property]: \(\displaystyle f''(x) = \frac{1}{2}x^{\frac{1}{2} - 1} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{(2x^{\frac{1}{2}})^2}\)[2nd Derivative] Simplify/Evaluate Exponents:                                           \(\displaystyle f''(x) = \frac{1}{2}x^{\frac{-1}{2}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}\)[2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}\)[2nd Derivative] Basic Power Rule:                                                             \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^{1 - 1})(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{1}{2} - 1})}{4x}\)[2nd Derivative] Simply Exponents:                                                             \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^0)(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}\)[2nd Derivative] Simplify:                                                                             \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}\)[2nd Derivative] Multiply:                                                                             \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(x^{\frac{-1}{2}})}{4x}\)[2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{x^{\frac{1}{2}}})}{4x}\)[2nd Derivative] Multiply:                                                                             \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - \frac{x}{x^{\frac{1}{2}}}}{4x}\)[2nd Derivative] Simplify:                                                                             \(\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{x^{\frac{1}{2}}}{4x}\)[2nd Derivative] Rewrite [Exponential Rule  - Root Rewrite]:                     \(\displaystyle f''(x) = \frac{1}{2\sqrt{x}} + \frac{\sqrt{x}}{4x}\)

Step 3: Evaluate

[1st Derivative] Substitute in x:                                                                     \(\displaystyle f'(1) = \sqrt{1} + \frac{1}{2\sqrt{1}}\)[1st Derivative] Evaluate Roots:                                                                     \(\displaystyle f'(1) = 1 + \frac{1}{2(1)}\)[1st Derivative] Multiply:                                                                                 \(\displaystyle f'(1) = 1 + \frac{1}{2}\)[1st Derivative] Add:                                                                                       \(\displaystyle f'(1) = \frac{3}{2}\)[2nd Derivative] Substitute in x:                                                                   \(\displaystyle f''(1) = \frac{1}{2\sqrt{1}} + \frac{\sqrt{1}}{4(1)}\)[2nd Derivative] Evaluate Roots:                                                                 \(\displaystyle f''(1) = \frac{1}{2(1)} + \frac{1}{4(1)}\)[2nd Derivative] Multiply:                                                                             \(\displaystyle f''(1) = \frac{1}{2} + \frac{1}{4}\)[2nd Derivative] Add:                                                                                     \(\displaystyle f''(1) = \frac{3}{4}\)