Fill in the blank to make the statement true: -18 ___ -19

<

=

>

Answer:

Step-by-step explanation:

the solutions are options: 2, 3, 4

Exponential, triangular, Weibull, beta, Erlang, gamma, and lognormal distributions are often referred to as continuous theoretical distributions.

In most simulations, a queue is important for keeping an entity when it cannot move.

Exponential, triangular, Weibull, beta, Erlang, gamma, and lognormal distributions are all examples of continuous theoretical distributions. These distributions are used to model random variables that take on continuous values, such as time, length, or volume. They are characterized by probability density functions that describe the likelihood of different values occurring within a given range.

In simulation modeling, a queue is an important construct used to manage entities or objects that need to wait or be processed in a specific order. When an entity cannot move or proceed further in the simulation, it is typically placed in a queue until the conditions allow it to progress. Queues are commonly used in various simulation scenarios, such as modeling service systems, production lines, or network traffic.

Global variables and attributes are generally used to store and manage data within a simulation, but they do not specifically address the concept of keeping an entity when it cannot move. Resources, on the other hand, are entities that are required or consumed by other entities in the simulation, such as equipment or personnel, but they do not directly handle the situation of entities being unable to move.

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The probability of a bill exceeding $300 is 0.0091.

A probability distribution that is symmetric about the mean is the normal distribution, also referred to as the Gaussian distribution. It demonstrates that data that are close to the mean occur more frequently than data that are far from the mean. The normal distribution appears as a "bell curve" on a graph.

For normal distribution z score = (X-μ)/σ

here mean= μ = 196

std deviation  = σ = 44.0000

probability of a bill exceeding

$300  = P(X>300)

          =P(Z>(300-196)/44)  

          =P(Z>2.36)

          =0.0091

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Step-by-step explanation:

0.5 I think because 5 ÷10 is o.5 but u dont know how much water the tree got.

Answer:

0.5 = because 5 ÷10 is 0.5  

Step-by-step explanation:

5 divided by 10 give you 0.5

So each plant will be getting 0.5 gallons of water

Answer:

Let 2n = the first of three consecutive even numbers, where n is an integer.

Let 2n + 2 = the second of three consecutive even numbers, and

Let 2n + 4 = the third of three consecutive even numbers.

We're given that "sum of three consecutive even numbers is 552." We can translate this English sentence mathematically into the following equation to be solved for n:

2n + (2n + 2) + (2n + 4) = 552

Removing the parentheses, we have:

2n + 2n + 2 + 2n + 4 = 552

Now, by the Commutative Law of Addition, i.e., a + b = b + a, we have on the left side of the equation:

2n + 2n + 2n + 2 + 4 = 552

Now, collecting like-terms on the left, we get:

6n + 6 = 552

To solve for the variable n, We now begin isolating n on the left side by subtracting 6 from both sides as follows:

6n + 6 - 6 = 552 - 6

6n + 0 = 546

6n = 546

Now, divide both sides by 6 to finally solve for n:

(6n)/6 = 546/6

(6/6)n = 546/6

(1)n = 91

n = 91

Therefore, the first of three consecutive even numbers, 2n, is:

2n = 2(91)

= 182

The second of three consecutive even numbers is:

2n + 2 = 2(91) + 2

= 182 + 2

= 184

The third of three consecutive even numbers is:

2n + 4 = 2(91) + 4

= 182 + 4

= 186

CHECK:

2n + (2n + 2) + (2n + 4) = 552

182 + 184 + 186 = 552

552 = 552

Therefore, the desired and first of three consecutive even numbers is indeed 2n = 182.

The Maclaurin series expansion of a function f is the Taylor series expansion of the function about x=0. The expression for f(x) that corresponds to this Maclaurin series is: a) cosx

In other words, it is the power series representation of the function centered at x=0. The coefficients of the terms in the Maclaurin series expansion of a function f can be obtained using the formula:

an = f^(n)(0)/n!

where f^(n)(0) is the nth derivative of f evaluated at x=0.

Given the Maclaurin series expansion of a function f as 1+x^2/2!+x^4/4!+x^6/6!+...+x^2n/(2n)!, we can see that the nth coefficient an is given by x^(2n)/(2n)!.

Comparing this to the known Maclaurin series expansions of the given options, we see that the Maclaurin series expansion of option d) 1/2 (e^x+e^-x) matches the given Maclaurin series expansion of f(x).

Therefore, the expression for f(x) is 1/2 (e^x+e^-x).
A function f has a Maclaurin series given by 1+x^2/2!+x^4/4!+x^6/6!+...+x^2n/(2n)!. The expression for f(x) that corresponds to this Maclaurin series is:

a) cosx

The Maclaurin series for cos(x) is given by the sum of alternating even powers of x divided by their respective factorials, which matches the given series.

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Answer:

The correct answer is B. 20,000

Step-by-step explanation:

To determine the man's total monthly salary, we can set up a simple equation using the given information. Let's denote the total monthly salary as "x."

According to the information provided, 33% of the man's monthly salary is equal to Birr 6600. We can express this relationship mathematically as:

0.33x = 6600

To solve for "x," we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by 0.33:

x = 6600 / 0.33

Evaluating the right side of the equation gives:

x ≈ 20,000

Therefore, the man's total monthly salary is approximately Birr 20,000.

Hence, the correct answer is B. 20,000.

Answer:

D

Step-by-step explanation:

Since the point C is (-4,-4) on quadrant 3 it will aways be a negative and a negative so it being dilated would be point (-8,-8)

the area increasing is dA/dt = 31  in²/ sec when  the length of its base is decreasing at the rate of 4 m/sec and its height is increasing at the rate of 3m/sec

The area of the rectangle is:

A(t)  = length * breadth     where  b is the base and h the height

Differentiation on both sides of the equation we obtain

dA/dt  =  (1/2)* db/dt * h + (1/2)* dh/dt * b   (1)

db/dt  = 4 in/sec

dh/dt =  3 n/sec

b =  6 in

h = 2 in

By substitution in (1)

dA/dt =  0,5* 3*14 +  0,5* 2*10

dA/dt =  21 in² /sec + 10 in²/sc

dA/dt = 31  in²/ sec

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a.we get, `A = √(2α³/π)`.

b.`⟨H⟩ = (3/4)hω - (h²/4ma²)` where `a = α/√(mω/h)`.

c.we can say that the variational principle is valid in this case.

(a) Let's find the normalization constant A.

We know that the integral over all space of the absolute square of the wave function is equal to 1, which is the requirement for normalization.  `∫⟨ψ|ψ⟩dx= 1`

Hence, using the given trial wavefunction, we get, `∫⟨ψ|ψ⟩dx = ∫ |A/(x^2+α²)|²dx= A² ∫ dx / (x²+α²)²`

Using a substitution `x = α tan θ`, we get, `dx = α sec² θ dθ`

Substituting these in the above integral, we get, `A² ∫ dθ/α² sec^4 θ = A²/(α³) ∫ cos^4 θ dθ`

Using the identity, `cos² θ = (1 + cos2θ)/2`twice, we can write,

`A²/(α³) ∫ (1 + cos2θ)²/16 d(2θ) = A²/(α³) [θ/8 + sin 2θ/32 + (1/4)sin4θ/16]`

We need to evaluate this between `0` and `π/2`. Hence, `θ = 0` and `θ = π/2` limits.

Using these limits, we get,`⟨ψ|ψ⟩ = A²/(α³) [π/16 + (1/8)] = 1`

Therefore, we get, `A = √(2α³/π)`.

Hence, we can now write the wavefunction as `ψ(x) = √(2α³/π)/(x²+α²)`.  

(b) Using the wave function found in part (a), we can now determine the expectation value of energy using the time-independent Schrödinger equation, `Hψ = Eψ`. We can write, `H = (p²/2m) + (1/2)mω²x²`.

The first term represents the kinetic energy of the particle and the second term represents the potential energy.

We can write the first term in terms of the momentum operator `p`.We know that `p = -ih(∂/∂x)`Hence, we get, `p² = -h²(∂²/∂x²)`Using this, we can now write, `H = -(h²/2m) (∂²/∂x²) + (1/2)mω²x²`

The expectation value of energy can be obtained by taking the integral, `⟨H⟩ = ⟨ψ|H|ψ⟩ = ∫ψ* H ψ dx`Plugging in the expressions for `H` and `ψ`, we get, `⟨H⟩ = - (h²/2m) ∫ψ*(∂²/∂x²)ψ dx + (1/2)mω² ∫ ψ* x² ψ dx`Evaluating these two integrals, we get, `⟨H⟩ = (3/4)hω - (h²/4ma²)` where `a = α/√(mω/h)`.

(c) Since we have an approximate ground state wavefunction, we can expect that the expectation value of energy ⟨H⟩ should be greater than the true ground state energy.

Hence, the value obtained in part (b) should be greater than the true ground state energy obtained by solving the Schrödinger equation exactly.

Therefore, we can say that the variational principle is valid in this case.

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A system of inequalities to represent the constraints of this problem are x ≥ 0 and y ≥ 0.

A graph of the system of inequalities is shown on the coordinate plane below.

In order to write a system of linear inequalities to describe this situation, we would assign variables to the number of HD Big View television produced in one day and number of Mega Tele box television produced in one day respectively, and then translate the word problem into algebraic equation as follows:

Since the HD Big View television takes 2 person-hours to make and the Mega TeleBox television takes 3 person-hours to make, a linear equation to describe this situation is given by:

2x + 3y = 192.

Additionally, TVs4U’s total manufacturing capacity is 72 televisions per day;

x + y = 72

For the constraints, we have the following system of linear inequalities:

x ≥ 0.

y ≥ 0.

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When conducting a chi-squared test, the categories of your variable(s) must be a) mutually exclusive. This means that each observation can only fall into one category, and there should be no overlap or ambiguity in assigning observations to categories.

In a chi-squared test, we analyze the association between two categorical variables to determine if there is a significant relationship. To perform this test, it is essential that the categories of the variable(s) are mutually exclusive. This means that each observation should belong to only one category, and there should be no overlap or ambiguity in assigning observations to categories. If the categories are not mutually exclusive, it becomes difficult to accurately assess the relationship between variables.

The options b) dependent, c) less than five in total, and d) more than three in total do not accurately describe the requirements for conducting a chi-squared test. Option b) dependent refers to the relationship between variables, which is assessed through statistical measures other than the chi-squared test. Options c) less than five in total and d) more than three in total relate to the minimum number of expected counts per cell rather than the categories themselves.

In summary, when conducting a chi-squared test, the categories of your variable(s) must be mutually exclusive to ensure accurate analysis of the association between categorical variables.

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If you perform a two-sided t-test with 120 degrees of freedom, what is the chance that ∣t∣ > 2.358 is approximately 2%.

If you perform a two-sided t-test with 120 degrees of freedom, you can use the t-distribution table or a statistical calculator to find the probability that the absolute value of the t-statistic is greater than 2.358.

To find this probability, you would compare the critical value of 2.358 to the values in the t-distribution table or use a statistical calculator.

The critical value represents the cutoff point beyond which we consider the t-statistic to be significant.

Using the t-distribution table or a statistical calculator, you can determine that with 120 degrees of freedom, the chance that ∣t∣ > 2.358 is approximately 2%.

Therefore, the correct answer is 2%.

Please note that the exact value may vary slightly depending on the level of precision used in the calculations.

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Step-by-step explanation:

we know,

volume of pyramid = 1/3 × base area × height

so,

→ 1/3 × 120 × 9

→ 40 × 9 = 360 ft

so the volume of the pyramid is 360 ft².

base area = length × slant height

so, 12 × 10 = 120

hope this answer helps you dear....take care and may u have a great day ahead dear !

Question 11

1) \(\overline{BA} \cong \overline{FA}\), \(\angle 1 \cong \angle 2\) (given)

2) \(\angle A \cong \angle A\) (reflexive property)

3) \(\triangle AEB \cong \triangle ACF\) (ASA)

4) \(\overline{AC} \cong \overline{AE}\) (CPCTC)

Question 12

1) Isosceles \(\triangle ACD\) with \(\overline{AC} \cong \overline{AD}\), \(\overline{BC} \cong \overline{ED}\) (given)

2) \(\angle ACD \cong \angle ADC\) (angles opposite congruent sides in a triangle are congruent)

3) \(\angle ACB\) and \(\angle ACD\) are supplementary. \(\angle ADC\) and \(\angle ADE\) are supplementary (angles that form a linear pair are supplementary)

4) \(\angle ACB \cong \angle ADE\) (supplements of congruent angles are congruent)

5) \(\triangle ABC \cong \triangle AED\) (SAS)

6) \(\overline{AB} \cong \overline{AE}\) (CPCTC)

7) \(\triangle ABE\) is an isosceles triangle (a triangle with two congruent sides is isosceles)

Note: I changed the names of the segments in Question 11 because of the word filter.

Answer:

2

Step-by-step explanation:

the rate of change is basically the slope. In this equation the coefficient of x is the slope. The coefficient of x is 2. So 2 is your slope

Answer:

There are 7 fish in each tank.

Step-by-step explanation:

We know that there are 3 tanks and 21 fish and that each tank has the same number of fish. We need to divide the 21 fish evenly into the three tanks, so we use division for this problem. 21÷3=7

Answer: (2x+6y)^2 = (2x+6y)(2x+6y) = 4x^2 +12xy + 12yx + 36y^2 = 4x^2 + 24xy + 36y^2

So the result of (2x+6y)^2 is 4x^2 + 24xy + 36y^2

The  equation of the line is y =  x + 6.

In mathematics, the slope or gradient of a line is a number that describes both the direction and the steepness of the line.

here, we have,

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given

4x + y = 7 ( subtract 4x from both sides )

y = - 4x + 7 ← in slope- intercept form

with slope m = - 4

given a line with slope m then the slope of a line perpendicular to it is

= 1/-m  =1/ 4  

then,

y =  x/4 + c ← is the partial equation of the perpendicular line

to find c substitute )- 4, 5 ) into the partial equation

5 = - 1 + c ⇒ c = 5 + 1 = 6

hence, y =  x/4 + 6 ← equation of perpendicular line.

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In rectangles P and Q, where the area of rectangle Q is 10% less than the area of rectangle P, we have the ratio of x:y = 25:18.

The area of a rectangle is the product of its length and its width.

In the question, we are given two rectangles:-

Rectangle P:

length = 40 cm,

width = x cm,

Thus, the area = length * width = 40x.

Rectangle Q:

length = 25% more than the length of P = 40 + 25% of 40 = 40 + 0.25*40 = 40 + 10 = 50 cm.

width = y cm,

Thus, the area = length * width = 50y.

Now, we are given that, the area of rectangle Q is 10% less than the area of rectangle P.

Thus, we can write that,

Area of rectangle Q = Area of rectangle P - 10% of the area of rectangle P,

or, 50y = 40x - 10% of 40x,

or, 50y = 40x - 0.10*40x,

or, 50y = 40x - 4x,

or, 50y = 36x,

or, y = 36x/50.

We are asked to find the ratio of x:y = x/y.

Substituting y = 36x/50, we get,

x/y = x/(36x/50) = 50x/36x = 25/18.

Thus, the ratio x:y = 25:18.

Thus, in rectangles P and Q, where the area of rectangle Q is 10% less than the area of rectangle P, we have the ratio of x:y = 25:18.

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Answer:

44 or 45

Step-by-step explanation:

400 divided by nine

Answer:

51 sessions

Step-by-step explanation:

9x - 59 >= 400

9x >= 400 + 59

9x >= 459

x >= 459/9

x >= 51

The probability that a dancer performs first in the talent competition can be calculated by dividing the number of favorable outcomes (a dancer performing first) by the total number of possible outcomes (all possible orderings of the acts). The answer is a simplified fraction.

There are a total of 20 acts consisting of 4 instrumentalists, 10 singers, and 6 dancers. Since we want to find the probability of a dancer performing first, we can consider the first act as the dancer, and the remaining acts can be arranged in any order.

The total number of possible orderings of the 20 acts is 20!, which represents the factorial of 20 (20 factorial).

The number of favorable outcomes is 6 * 19!, which means fixing one dancer as the first act and arranging the remaining 19 acts in any order.

Therefore, the probability can be calculated as:

Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

= (6 * 19!) / 20!

The expression (6 * 19!) / 20! can be simplified by canceling out the common factors:

Probability = 6 / 20

Hence, the probability that a dancer performs first is 6/20, which simplifies to 3/10.

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Answer:

Sorry Bro I can't understand

The principal advantage of the Dodge-Romig tables is their simplicity. Therefore, the correct answer is D. simplicity.

The Dodge-Romig tables are statistical sampling tables used in quality control to determine the acceptance or rejection

of a production lot based on sample size and the number of defects found in the sample.

The principal advantage of the Dodge-Romig tables is their simplicity.

They provide a quick and easy method for determining the acceptability of a production lot, without the need for

extensive calculations or statistical knowledge.

This means that they can be used by personnel with limited training in quality control.

The principal advantage of the Dodge-Romig tables is their simplicity. While they can be used for receiving inspection,

their main benefit is in minimizing inspection time and effort by providing clear guidelines for lot sampling and

acceptance based on size and level of defects.

Additionally, their use can facilitate smaller lot sizes and more efficient quality control processes.

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Answer:

4 in 5 days

Step-by-step explanation:

Answer:

what problem  baby girl

Step-by-step explanation:

A graph of the given quadratic equation is shown below.

The axis of symmetry is equal to 3.

The vertex is equal to (3, -1).

In Mathematics and Geometry, the graph of a quadratic function would always form a parabolic curve because it is a u-shaped. Based on the graph of this quadratic function, we can logically deduce that the graph is an upward parabola because the coefficient of x² is positive and the value of "a" is greater than zero (0).

Since the leading coefficient (value of a) in the given quadratic function y = x² - 6x + 8 is positive 1, we can logically deduce that the parabola would open upward and the solution would be on the x-intercepts. Also, the value of the quadratic function f(x) would be minimum at -1.

In conclusion, the axis of symmetry is 3 while the vertex is given by the ordered pair (3, -1).

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