Answer: The concentration of hydroxide ions in the solution is 2.2 x 10^(-5) M.
Explanation:
To determine the concentration of hydroxide ions in the aqueous solution of methylamine, we can use the equation for the base dissociation reaction of methylamine in water:
CH3NH2 + H2O ⇌ CH3NH3+ + OH-
The equilibrium constant expression for this reaction is:
Kb = [CH3NH3+][OH-] / [CH3NH2]
Here, the concentration of methylamine ([CH3NH2]) is 0.050 M and the Kb value is 4.4 x 10^(-4), we can rearrange the equation and solve for [OH-]:
[OH-] = (Kb * [CH3NH2]) / [CH3NH3+][OH-]
= (4.4 x 10^(-4) * 0.050) / 1[OH-] = 2.2 x 10^(-5) M
Therefore, the concentration of hydroxide ions in the solution is 2.2 x 10^(-5) M.
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HURRRY ASAP!!
An important consideration of the medical use of radioisotopes is how long they're active. Technetium-99 is a short-lived isotope of technetium with a half-life of 6 hours. If a patient is treated with technetium-99 for a PET scan, when will the patient have less than 1 percent of the original technetium-99 present?
A)
3 days
B)
40 hours
C)
6 hours
D)
0.00116 hours
What does a reaction energy diagram represents
Answer:
The energy changes that occur during a chemical reaction can be shown in a diagram called a potential energy diagram, or sometimes called a reaction progress curve. A potential energy diagram shows the change in potential energy of a system as reactants are converted into products.
Explanation:
Answer:
The answer is the changes in energy during a reaction. Have a good day.:)
Organisms on earth are
th-based Ilfe forms.
hydrogen
oxygen
carbon
Hurryyyy!!
Answer:
carbon...?
Explanation:
Answer:
Carbon
Explanation:
Carbon makes up most of the building blocks of life. Hope that is right. Good luck
2
Is the molecule with the formula Br
an element mixture or compound?
How do you know this?
Answer:
i do not know
Explanation:
You have a substance with a half-life of 9 days. How much of it will be left after 36 days?
Answer:
A half life is the amount of time it takes for half of a mass of a given radioactive element to decay to something else. 36 days is 4 1/2 life cycles, so by running 1/2*4 , we get how much of the original substance would be left. That would be 1/16 of the original substance left.
Explanation:
Of course, this is not always perfect, and can vary. In addition, if less than 16 atoms of the original substance are present, there is instead a 1/16∗a chance of at least one remaining.
The amount of substance left after 39 days will be 1/16th of the original amount.
What is the half-life of a radioactive element?The half-life period of the radioactive material can be defined as the time required to reduce its actual amount to half after disintegration. The half-life period of a radioactive substance is independent of the initial amount of the substance.
Consider that N₀ is the initial amount of the substance
Consider that 'n' is the number of half-lives of given substance.
The time for which substance decay, t = 36 days
Half-life of substance (t½) = 9 days
t = n ×t½
36 = n × 9
n = 4 days
Assume that N is the amount of the substance after decay for 39 days.
N ×2⁴ = N₀
N × 16 = N₀
N = N₀/16
Therefore, one-sixteenth of the initial amount of the substance will be left after 39 days.
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What is the equilibrium constant of pure water at 25°C
A mixture of 90.0grams of CH4 and 10.0grams of argon gas a pressure of 250torr under conditions of constant temperature and volume. The partial pressure of CH4 in torr is?
Answer:
The partial pressure of methane CH₄ is 239.4 torr.
Fill in the [?]:
1,516,000,000 nm = [?]m
Give your answer in standard form.
Answer:
1nm = 1000000 mm 1cm=10mm 1m=100cm
Explanation:
so
1,516,000,000 nm = divided by 1000000 is 1516 mm divided by 10 = 151.6 cm divided by 100 = 0.1516 m
0.1516 = 1.516 x 10 -1
because it is 10 less than 1.516
a Disscuss different types of frictions b Explain friction is necessary evil c Why should friction be reduced
The Types of Friction are;
Static FrictionKinetic FrictionRolling FrictionWhat is the frictionsStatic Friction is a type of friction that stops objects from moving when a force is added and they aren't moving.
Kinetic friction happens when two things are rubbing against each other while they are moving. It tries to stop things from moving too fast.
Rolling friction happens when something rolls on a surface. Like a wheel moving on the ground. When objects move, it is easier for them to keep going because rolling friction (friction when something rolls) is usually less than kinetic friction (friction when something slides).
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\({\huge{\underline{\underline{\tt{\green{Answers}}}}}}\)
______________________________________
Answer a.The different types of friction are:
static frictionsliding frictionrolling frictionfluid friction.______________________________________
Answer b.Friction is often called a necessary evil because it can be both helpful and harmful. On the one hand, friction is what allows us to walk, drive, and write, and it prevents objects from slipping and sliding out of our hands. On the other hand, friction can cause wear and tear on machines and vehicles, generate heat that can damage materials, and slow down or stop moving objects.
______________________________________
Answer c.Friction should be reduced in certain situations to increase efficiency and reduce wear and tear. For example, reducing friction in engines and machines can increase fuel efficiency and decrease maintenance costs. However, friction should not be reduced in situations where it is necessary for safety, such as in car brakes or shoes.
______________________________________
6. For each of the following sets of atoms, rank the atoms from smallest to largest atomic radius.
a. Li, CF
b. Li, Na, K
c. Ge, P, O
d. C, N, AI
e. AI, CI, Ga
Answer:
a (F < C < Li)
b (Li < Na < K)
c (Ge < P < O)
d (C < N < Al)
e (Ga < Cl < Al)
Water and salt are compounds made of the combination of more than one type of atom. Which statement is false?
Answer:
This statement is correct
Explanation:
Water is made up of 2 hydrogen atoms and 1 oxygen atom while salt is made up of 1 atom of sodium and 1 atom of chloride
:)
Match up the characteristics below with the type of molecular bond they describe. Bonds found in Halite (between Na+ and Cl-) Bonds found between Si and O in the Si-O tetrahedron Bonds inside the water molecule (between the H and O ) Bonds that exist between two water molecules Strongest bond type Weakest bond type Bonds that are used by water to dissolve sal
The characteristics and the type of molecular bond they describe:
1. Bonds found in Halite (between Na⁺ and Cl⁻): Ionic bond
2. Bonds found between Si and O in the Si-O tetrahedron: Covalent bond
3. Bonds inside the water molecule (between the H and O): Covalent bond
4. Bonds that exist between two water molecules: Hydrogen bond
5. Strongest bond type: Covalent bond
6. Weakest bond type: Van der Waals bond
7. Bonds that are used by water to dissolve salt: Ionic bond
The ionic bond is a type of molecular bond found in halite (between Na⁺ and Cl⁻). The Si-O tetrahedron is held together by a covalent bond. The bond inside the water molecule (between the H and O) is also a covalent bond. The hydrogen bond is the type of bond that exists between two water molecules. The covalent bond is the strongest bond type, while the van der Waals bond is the weakest bond type. Water uses the ionic bond to dissolve the salt.
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T/F: it requires more water to produce one gallon of gasoline than it does to produce one gallon of ethanol
True, it requires more water to produce one gallon of gasoline than it does to produce one gallon of ethanol.
Water consumption is a critical aspect of fuel production, and ethanol has shown to be less water-intensive than gasoline. Ethanol is typically made from crops such as corn, and the water used in the production process is largely consumed by the plant. In contrast, gasoline is produced from crude oil, which requires a significant amount of water to extract and refine. Therefore, ethanol is a more water-efficient alternative to gasoline. However, it is important to note that the overall environmental impact of ethanol production depends on various factors, including the source of the crops used and the energy required in the production process.
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What makes up a Solar System?
Answer: It's just the Primary planets and the dwarf planets and the sun, The orbit courses, and the gravitational pull that keeps them orbiting.
Explanation: Make me brainliest, please Help me out
What are 5 examples of covalent bonds?
Five substances have covalent bonds: hydrogen (H2), oxygen (O2), nitrogen (N2), water (H2O), and methane (CH4).
An illustration would be "Water, H2O," which is created when hydrogen and oxygen share electrons (which are both non-metals). Carbon dioxide, CO2, is another example of a covalent bond.
A covalent bond is defined by Lewis as a shared electron pair. In hydrogen chloride, a hydrogen atom and a chlorine atom create the following bond: The shared electron pair between the hydrogen and chlorine ions is shown as a line in a Lewis structure of a covalent molecule. Molecular compounds are another name for covalent compounds. Organic substances like lipids, proteins, nucleic acids, and carbohydrates
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a student wants to prepare 0.13 m nano3 for a lab experiment in 250-ml volumetric flask. how many grams of nano3 need to be weighted out to dissolve in the volumetric flask?
In order to prepare 0.13 m nano3 for a lab experiment in a 250-ml volumetric flask, a student needs to weigh out 2.76gof nano3 to dissolve in the flask.
A form of laboratory glassware used to produce solutions is a volumetric flask. A volumetric flask is a bulb with a flat bottom and an extended neck that is calibrated to retain a specific volume at a mark on the neck. The flask can also be referred to as a graduated flask. The volume of the NaNO3 solution is 250 mL, and its molarity is 0.13 M. 250 mL of 0.15 M NaNO3 is calculated as (250/1000)L * (0.13 mol/L) = 0.0325 mol. Weight of 0.0375 mol is required since the molar mass of NaNO3 is 85 g/mol. 2.76g of NaNO3 are equal to 0.0325 mol*(85 g/mol). It is necessary to weigh 2.76 g of NaNO3.
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3. Svante Arrhenius developed a definition of acids and bases
which stated...
A. acids produce OH+ ions and bases produce H ions
B. acids produce H+ ions and bases produce OH ions
STAT
C. acids and bases are the same
D. acids have a high pH and bases have a low pH
pls help
btw any links will be reported.
Consider the titration of a 40.0 mL of 0.227 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH.a)Consider the titration of a 40.0 mL of 0.227 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. What is the pH of the solution before any base has been added?b)Consider the titration of a 40.0 mL of 0.227 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. What would be the pH of the solution after the addition of 20.0 mL of LiOH?c)Consider the titration of a 40.0 mL of 0.227 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. How many mL of the LiOH would be required to reach the halfway point of the titration?d) Consider the titration of a 40.0 mL of 0.227 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. What is the pH of the solution at the equivalence point?e)Consider the titration of a 40.0 mL of 0.227 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. What would be the pH of the solution after that addition of 100.0 mL of LiOH?
The pH of a solution is defined as a measure of hydrogen ion concentration which in turn is a measure of its acidity.
A. pH is 4.10.
B. pH is 6.81
C. 45.8 ml of lithium hydroxide would be required
D. pH is 9.87
E. pH of the solution is 11.78
A. The equation, HA + OH- ==> A- + H2O creates a buffer consisting of the weak acid HA and the conjugate base A.
Ka = [H+][A-]/[HA]
=> 2.7x10-8 = (x)(x) / 0.229
x2 = 6.18x10-9
x = [H+] = 7.9x10-5 M
pH = -log [H+] = 4.10
The pH of the solution before any base has been added is 4.10.
B. we can use the Henderson Hassel Balch equation.
=> pH = pKa + log [conjugate base]/[acid]
[conjugate base] = 0.002 mole/0.06 L = 0.0333 M
[acid] = 0.00716 mole/0.06 L = 0.119 M
pKa = -log Ka = -log 2.7x10-8 = 7.57
pH = 7.57 + log (0.0333/0.119) = 7.57 - 0.756
pH = 6.81
The pH of the solution after the addition of 20.0 mL of Lithium hydroxide is 6.81.
C. 0.00458 moles Li OH x 1 L / 0. 1mols = 0.0458 L = 45.8 moles Li OH
45.8 ml of the Lithium hydroxide would be required to reach the
halfway point of the titration.
D. x = [OH-] = 7.35x10-5 and pOH = -log 7.35x10-5 = 4.13
pH = 14 - 4.13
pH = 9.87
9.87 is the pH of the solution at the equivalence point.
E. pOH = -log 0.006 = 2.22
pH = 14 - 2.22 = 11.78
11.78 is the pH of the solution after that addition of 100.0 mL of halfway point of the titration.
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The question is incomplete.
Consider the titration of a 40.0 mL of 0.229 M weak acid HA
(Ka = 2.7 x10⁻⁸) with 0.100 M Lithium hydroxide.
A. What is the pH of the solution before any base has been added?
B. What would be the pH of the solution after the addition of 20.0 mL of
Lithium hydroxide?
C. How many mL of the Lithium hydroxide would be required to reach the halfway point of the titration?
D. What is the pH of the solution at the equivalence point?
E. What would be the pH of the solution after that addition of 100.0 mL of
halfway point of the titration?
Which causes genetic variations and can result in different alleles? O predation rate O random mutations O competition o environmental changes
Answer:
B
Explanation:
Answer:
BBBBBBBBB
Explanation:
Which substance in this redox reaction is the oxidizing agent
Cu+2AgNo3 = 2Ag + Cu(NO3)2
A. N
B. AgNO3
C. Cu
D. NO3-
E. Cu(NO3)2
B. AgNO₃ is the oxidizing agent
Further explanationOxidation is an increase/increase in oxidation number, while reduction is a decrease/decrease in oxidation number.
In the redox reaction, it is also known
Reducing agents are substances that experience oxidation
The oxidizer is a substance that is reduced
Reaction
Cu+2AgNO₃ ⇔ 2Ag + Cu(NO₃)₂
Oxidizing reaction :
Cu⇒Cu²⁺+2e⁻ (oxidation number from 0 to +2)
Reducing reaction
2Ag⁺+2e⁻⇒Ag (oxidation number from +1 to 0)
the oxidizing agent ⇒a substance that is reduced , so that is AgNO₃
Answer:
B. AgNO3
Explanation:
Identify the type of energy this object possesses. A girl roller-skating Kinetic energy Potential energy
A girl roller-skating has kinetic energy.
Kinetic energy is the energy of motion. It is the energy possessed by an object due to its movement. In this case, the girl roller-skating has kinetic energy because she is moving.
Potential energy is the energy an object possesses due to its position or configuration. It is the energy an object has stored within it, ready to be released. An object at rest has potential energy because it has the potential to be set in motion and does work.
So, in this case, the girl roller-skating has kinetic energy because she is moving, and not potential energy because she is not at rest.
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Some vitamins and dietary supplements are stored in opaque, darkened
bottles to protect them from UV light because UV light would cause a
reaction. Which word could be used to describe UV light in this situation?
O A. Catalyst
B. Enzyme
C. Solvent
D. Reactant
The correct option for the given question about Harmfull effect of UV light is Option D) Reactant.
Why UV light is so harmfull for some vitamins?In general, temperature, oxygen, and light impacts on vitamins and minerals are sensitive. A nutrient can lose its biological potency if its molecular structure is slightly altered.Numerous vitamins, including vitamin A, vitamin B2 (riboflavin), vitamin B6, vitamin B12, and folic acid, are known to be particularly susceptible to UV radiation oxidation.Additionally, light speeds up the negative interactions between vitamins.For instance, the combination of riboflavin and light together speeds up the breakdown of both folic acid and vitamin C. This is what causes milk that has been exposed to light to lose vitamin C.Thus to conclude we can say that UV light damages some vitamins by reacting with them.
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Wiith the parameters given and hydraulic retention time= 1d, change the question to :
1) what is the BODL concentration in the aerated lagoon?
2) what is the concentration of volatile suspended solids (Xv) in the lagoon?
1. An industry has a soluble wastewater that contains a BODL of 2,000mg/l. They wish to produce an effluent BODL of 1,000mg/l. Pilot studies showed that the appropriate kinetic parameters are: q^KbYfd=27mgBODL/mgVSSa−d=10mgBODL/l=0.2/d=0.5mgVSSa/mgBODL=0.8 The industry wants to treat the wastewater with an aerated lagoon, which can be considered a chemostat with θ=1 d. Will they likely meet the desired effluent quality if they supply adequate O2 ? Recall that the effluent BODL will be comprised of organized substrate, active cell mass, and products. About C HAPTER 7 - Lagoons how much aerator capacity is needed (in kW/1,000 m3 of tank volume), if the field oxygen transfer efficiency is 1 kgO2/kWh ?
The concentration of volatile suspended solids (Xv) in the lagoon to assess the effluent quality. However, the specific aerator capacity needed cannot be determined without additional information or equations.
To determine if the industry will likely meet the desired effluent quality, we can calculate the BODL concentration in the aerated lagoon and the concentration of volatile suspended solids (Xv) in the lagoon.
BODL concentration in the aerated lagoon:
The BODL concentration in the lagoon can be calculated using the equation:
BODL_lagoon = BODL_influent - q * Xv * θ
where BODL_influent is the initial BODL concentration (2,000 mg/l), q is the specific oxygen utilization rate (27 mgBODL/mgVSSa-d), Xv is the concentration of volatile suspended solids (to be determined), and θ is the hydraulic retention time (1 day).
Concentration of volatile suspended solids (Xv) in the lagoon:
The concentration of volatile suspended solids can be calculated using the equation:
Xv = BODL_influent / (q * θ)
where BODL_influent is the initial BODL concentration (2,000 mg/l), q is the specific oxygen utilization rate (27 mgBODL/mgVSSa-d), and θ is the hydraulic retention time (1 day).
By substituting the given values into the equations, we can calculate the BODL concentration in the lagoon and the concentration of volatile suspended solids.
Regarding the aerator capacity needed, the question asks for the amount of aerator capacity in kW/1,000 m3 of tank volume. To calculate this, we need the field oxygen transfer efficiency (1 kgO2/kWh). However, the equation or method to determine the aerator capacity based on the given information is not provided. Without additional information or equations, it is not possible to calculate the specific aerator capacity needed in this scenario.
In summary, we can calculate the BODL concentration in the aerated lagoon and the concentration of volatile suspended solids (Xv) in the lagoon to assess the effluent quality. However, the specific aerator capacity needed cannot be determined without additional information or equations.
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1. On a piece of paper (by hand) - draw the structure of glycerol and the reactions used to get it into the Krebs cycle. They have to draw all the structures corresponding to these reactions, but not those of the Krebs cycle.
2. Calculate how many net ATP are produced from the complete oxidation of glycerol to CO2 and H2O.
3. Calculate how many net ATP are produced from the complete oxidation of a fully saturated 6-carbon fatty acid to CO2 and H2O.
1. Glyceraldehyde 3-phosphate enters the Krebs cycle as part of the glycolysis pathway.
2.The complete oxidation of glycerol results in the production of 15 ATP molecules. This includes the ATP generated from glycolysis, the Krebs cycle, and the electron transport chain.
3.This is because each round of beta-oxidation of a 6-carbon fatty acid generates 4 ATP molecules (one FADH2 yields 2 ATP, and one NADH yields 3 ATP), and two rounds of beta-oxidation are required for complete oxidation of a 6-carbon fatty acid.
1. Glycerol is a three-carbon molecule with the chemical formula C3H8O3. It can enter the Krebs cycle after undergoing several reactions. Here are the reactions involved:
Glycerol → Glycerol 3-phosphate
Glycerol 3-phosphate → Dihydroxyacetone phosphate
Dihydroxyacetone phosphate → Glyceraldehyde 3-phosphate
Glyceraldehyde 3-phosphate enters the Krebs cycle as part of the glycolysis pathway.
2. The complete oxidation of glycerol results in the production of 15 ATP molecules. This includes the ATP generated from glycolysis, the Krebs cycle, and the electron transport chain.
3. The complete oxidation of a fully saturated 6-carbon fatty acid (such as stearic acid) to CO2 and H2O produces a total of 146 ATP molecules. This is because each round of beta-oxidation of a 6-carbon fatty acid generates 4 ATP molecules (one FADH2 yields 2 ATP, and one NADH yields 3 ATP), and two rounds of beta-oxidation are required for complete oxidation of a 6-carbon fatty acid.
In summary, the net ATP produced from the complete oxidation of glycerol to CO2 and H2O is 15 ATP molecules. For a fully saturated 6-carbon fatty acid, the net ATP produced from its complete oxidation is 146 ATP molecules. These calculations take into account the ATP generated from glycolysis, the Krebs cycle, and the electron transport chain.
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1. Glycerol undergoes reactions to enter the Krebs cycle in the glycolysis pathway.
2. The complete oxidation of glycerol results in the production of 15 ATP molecules.
3. The net ATP produced from the complete oxidation of a fully saturated 6-carbon fatty acid is 146 ATP molecules.
What is the explanation for the above?1. Glycerol, a three-carbon molecule,undergoes a series of reactions to enter the Krebs cycle as part of glycolysis, contributing toATP production. This metabolic pathway allows glycerol to be utilized for energy generation in cells.
2. The complete oxidation of glycerol, encompassing glycolysis, the Krebs cycle, and the electron transport chain,results in the production of 15 ATP molecules. These processes efficiently extract energy from glycerol and convert it into ATP, the primary energy currency of cells.
3. The complete oxidation of a fully saturated 6-carbon fatty acid, such as stearic acid, involves beta-oxidation,yielding a net of 146 ATP molecules. This energy production arises from the successive breakdown of fatty acid molecules,generating ATP through various steps, including the electron transport chain. The oxidation of fatty acids plays a crucial role in meeting cellular energy demands.
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When a plant experiences heat, what part of a plant allows for the response to take place?
If only 0.500 mol of NO2(g) is placed in a 1.0 L container and the reaction is allowed to come to equilibrium, 0.186 mol of N2O4(g) is formed. Find the value of Keq.
Solve using ICE table.
The equilibrium constant of the system is 11.3.
What is the value of Keq?We know that the equilibrium constant shows the extent to which reactants are converted into products.
Now;
2NO2 ⇄ N2O4
[NO2] = 0.500 mol /1 L = 0.500 M
[N2O4] = 0.186 mol /1 L = 0.186 M
The ICE table is;
2NO2 ⇄ N2O4
I 0.5 0
C -2x +x
E 0.5 - 2x 0.186
The concentration of NO2 at equilibrium = 0.5 - 2(0.186) = 0.128
Keq = 0.186/( 0.128)^2
Keq = 11.3
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If a bond cleave next to the heteroatoms such as oxygen, sulfur and nitrogen generates a resonance stabilized cation. For instance, breaking the bond among carbon after alcohol radical generates a carbocation which is stabilized by resonance. This is named alpha cleavage and it is usually found in alcohols.
The Alpha cleavage of the alcohols is when a bond will cleave next to the heteroatoms to generates the resonance stabilization of the cation. This cleavage generally found in the alcohols.
The bond cleavage next to the heteroatoms like as oxygen, sulfur and the nitrogen will generates the cations that is resonance stabilize. The cleavage of bond in between the carbon and the carbon that is next to atom generated the cation and it is resonance stabilized. This Alpha bond cleavage is generally found in the alcohols.
Thus, the alpha bond cleavage is breaking of the carbon - carbon bond that is adjacent to carbon attached to the functional group.
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a weak species is titrated with a strong acid or base. was the species a weak acid or a weak base and what is the corresponding pka or pkb?
If a weak species is titrated with a strong acid, the species is likely a weak base. Conversely, if a weak species is titrated with a strong base, the species is likely a weak acid.
During the titration of a weak base with a strong acid, the pH of the solution will decrease as the acid is added, and the base will be neutralized. The equivalence point of the titration will occur when all of the base has been neutralized, and the pH of the solution will be equal to the pH of the conjugate acid of the weak base. The pKa of the weak base can be calculated from this pH using the Henderson-Hasselbalch equation:
pKa = pH + log([A-]/[HA])
where [A-] is the concentration of the conjugate base and [HA] is the concentration of the weak acid.
Similarly, during the titration of a weak acid with a strong base, the pH of the solution will increase as the base is added, and the acid will be neutralized. The equivalence point of the titration will occur when all of the acid has been neutralized, and the pH of the solution will be equal to the pKb of the conjugate base of the weak acid. The pKb can be calculated from this pH using the equation:
pKb = pKw - pKa
where pKw is the ionization constant of water (pKw = 14.0 at 25°C).
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A sample of tin (Cp = 0.227 J/g•°C) is placed in a freezer. Its temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy. What is the mass of the sample? Round your answer to three significant figures.
The mass of a sample of tin whose temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy is 478.4g.
How to calculate mass?The mass of a substance that underwent release of energy can be calculated using the following formula:
Q = mc∆T
Where;
Q = quantity of heat absorbed or releasedm = massc = specific heat capacity∆T = change in temperature543 = m × 0.227 × 5
543 = 1.135m
m = 543/1.135
m = 478.4g
Therefore, the mass of a sample of tin whose temperature decreases from 15.0°C to –10.0°C as it releases 543 J of energy is 478.4g.
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An object's mass is a measure of how much matter makes it up. An object's weight is a measure of the gravitational force that acts
on it. An object's mass is always its weight
OA
equal to
ОВ.
proportional to
C.
double
OD
half of
Answer:
its a
Explanation:
Answer:
c
Explanation: