figure C is the result of a transformation of figure B. which transformation would accomplish this.

a. a reflection over the y axis

b. a rotation 180 counterclockwise about the orgin

c. a reflection over the x axis

d. a translation 4 units up

Answer: A scale model is a representation or copy of an object that is larger or smaller than the actual size of the object being represented. Very often the scale model is smaller than the original and used as a guide to making the object in full size.

Answer:

x=2/3

Step-by-step explanation:

Most of that information is unnecessary. Just plug in the values of f(x) and g(x) into the equation where they are equal to each other and solve.

-3x+4=2

-3x=-2

3x=2

x=2/3

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Write the method of getting possible options.

When asked to find the number of possible options, this is a permutation problem. Therefore, we use the permutation formula.

STEP 2: Solve the first question

There are 85140 possible options.

STEP 3: Solve the second question

There are 2520 possible options.

STEP 4: Solve the third question.

There are 19958400 possible options.

STEP 5: Solve the fourth question

There are 116280 possible options

Answer:

Step-by-step explanation:

3x(5x-y) is equal to

3x(5x)+3x(-y) is equal to

15x^2-3xy

Answer:

answer in explanation!

Step-by-step explanation:

3(5−)

15^2−3

hope this helps you out! i would apreciate brainlyest too!!

a. The expected dividends for t = 1 to t = 5 are as follows:
D₁ = $2.24
D₂ = $2.58
D₃ = $2.97
D₄ = $3.41
D₅ = $3.92

b. To calculate the estimated intrinsic value of the stock today (P₀), we need to find the present value of the dividends expected at t = 1 to t = 5 and the present value of the stock price at t = 5. Using the constant growth equation, we find:
P₂ = D₆ / (r - g) = D₅ * (1 + g) / (r - g) = $3.92 * (1 + 0.03) / (0.12 - 0.03) = $53.52
Now, we can find the present value of the dividends and the stock price:
P₀ = D₁ / (1 + r) + D₂ / (1 + r)² + D₃ / (1 + r)³ + D₄ / (1 + r)⁴ + D₅ / (1 + r)⁵ + P₂ / (1 + r)⁵
   = $2.24 / (1 + 0.12) + $2.58 / (1 + 0.12)² + $2.97 / (1 + 0.12)³ + $3.41 / (1 + 0.12)⁴ + $3.92 / (1 + 0.12)⁵ + $53.52 / (1 + 0.12)⁵
   = $2.00 + $2.14 + $2.17 + $2.04 + $2.07 + $33.48
   = $43.90

c. For the first year (t = 1), we can calculate the expected dividend yield (D₁ / P₀), the capital gains yield (expected total return minus the dividend yield), and the expected total return as follows:
Expected dividend yield = D₁ / P₀ = $2.24 / $43.90 = 0.051 (or 5.1%)
Capital gains yield = Expected total return - Expected dividend yield = 0.12 - 0.051 = 0.069 (or 6.9%)
Expected total return = Expected dividend yield + Capital gains yield = 0.051 + 0.069 = 0.12 (or 12.0%)

For t = 5:
Expected dividend yield = D₅ / P₀ = $3.92 / $43.90 = 0.089 (or 8.9%)
Capital gains yield = Expected total return - Expected dividend yield = 0.03 - 0.089 = -0.059 (or -5.9%)
Expected total return = Expected dividend yield + Capital gains yield = 0.089 - 0.059 = 0.03 (or 3.0%)

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Step-by-step explanation:

Four bought a book at $6

4 x $6 = $24

8 x $x = $8x

Expression

$24 + $8x

The correct classification for antibodies is d) immunoglobulins.

Antibodies are proteins that are produced by the immune system in response to the presence of foreign substances (antigens) in the body. They play a crucial role in the immune response by recognizing and binding to specific antigens, thereby helping to neutralize or eliminate them.

Immunoglobulins, also known as antibodies, are composed of amino acids and are classified as glycoproteins. They are not amino acids themselves but are made up of amino acid chains. Therefore, option d) immunoglobulins is the correct classification for antibodies.

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True. Post-implementation evaluation refers to the process of evaluating the performance and effectiveness of a new system after it has been implemented.

It involves assessing the extent to which the system meets the intended objectives, as well as its overall quality and impact on the organization. The evaluation can be carried out through various methods such as user feedback, performance metrics, and system testing.

Therefore, post-implementation evaluation is primarily concerned with assessing the quality of a new system and its ability to deliver the expected benefits to the organization.

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Answer:

2x-3=-21.

2x=-21+3.

2x=-18.

x=-18/2.

x= -9.

Answer:

\(\Huge \boxed{2x-3=-21}\)

Step-by-step explanation:

Let the number be x.

The difference of two values is the result from subtracting them.

\(2x-3=-21\)

Add 3 to both sides.

\(2x=-18\)

Divide both sides by 2.

\(x=-9\)

The number is -9.

The mean greater than median when skewed right, because the median is not affected by having much larger values.

We know that the skewness is nothing but the measure of the asymmetry of a distribution.  A distribution can have right skewness (also called positive skewness), left skewness (or negative), or zero skewness. A distribution is said to be asymmetrical when its left and right side are not mirror images.

As we know, in a perfectly symmetrical distribution, the mean and the median are the same.

In case of right skewness, the mode is often less than the median, which is less than the mean. It's because the median is not affected by having much larger values but there would be increase in the mean.

For example {1, 2, 3, 4, 5} both the mean and the median equal 3  

But in case of {1, 2, 3, 4, 50} the median is still 3 and the mean is 12

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Answer:

you cant put test questions on here

Step-by-step explanation:

Interval notation for increasing and decreasing functions is written as (x, y) where x < y for increasing functions, and (x, y) where x > y for decreasing functions.

To write interval notation for increasing and decreasing functions, you need to analyze the behavior of the function's graph.

For an increasing function, as you move from left to right along the x-axis, the y-values of the function's graph increase. In interval notation, you would write this as:

(x, y) where x < y

For example, if the function is increasing from -3 to 5, the interval notation would be (-3, 5).

On the other hand, for a decreasing function, as you move from left to right along the x-axis, the y-values of the function's graph decrease. In interval notation, you would write this as:

(x, y) where x > y

For example, if the function is decreasing from 7 to -2, the interval notation would be (7, -2).

It's important to note that for both increasing and decreasing functions, the parentheses indicate that the endpoints are not included in the interval.

Remember, when using interval notation, always write the x-value first and then the y-value. This notation helps us understand the direction and range of a function.

In conclusion, interval notation for increasing and decreasing functions is written as (x, y) where x < y for increasing functions, and (x, y) where x > y for decreasing functions.

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Answer:

20x/100=3x

cross multiple

300x=20x

Divide both side by 20x

15

Answer:47791.31

Step-by-step explanation:

The probability level used by researchers to indicate the cutoff probability level (highest value) that will allow them to reject the null hypothesis is called the alpha level.

Alpha level refers to a threshold value which is used to determine if a test statistic is statistically significant.  In a statistical test, it demonstrates an acceptable probability of a Type I error. As alpha corresponds to a probability, it lies in the range of 0 to 1. The alpha level denoted as alpha or α refers to the probability of rejecting the null hypothesis when it is true. For example, a alpha level of 0.05 demonstrate a 5% risk of concluding that a difference exists when there is no actual difference.

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Answer:

Step four

Step-by-step explanation:

When solving equations you have to flip the sign when you divide negative integers.

Answer:

from my observation there is no mistake but here is my solution

Step-by-step explanation:

-2n+6-5>9

-2n+1>9

-2n>9-1

-2n>8

divide both sides by-2

n>-4

Answer:

9 13

a_. b=_

3 3

Step-by-step explanation:

it's that because you can devid 9 by 3

The scale factor that was used to create triangle J′K′L′ is 1/3.

The size by which the shape is enlarged or reduced is called as its scale factor. It is used when we need to increase the size of a 2D shape, such as circle, triangle, square, rectangle, etc.

Given the graph, we have the following highlights:

KL = 3

K'L' = 1

The scale factor (k) from JKL to J'K'L is calculated as:

\(\text{Scale factor} = \dfrac{\text{K'L'}}{\text{KL}}\)

This gives

\(\text{k} = \dfrac{1}{3}\)

Therefore, the scale factor that was used to create triangle J’K’L’ is 1/3.

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The estimated total cost of the clothes in your cart is $104.

Estimated costs are approximate projections of future costs associated with producing goods or completing a project. This includes both fixed and variable costs such as labor, materials and capital. Cost forecasting is very important for project-based companies. Upon notice, the parties must comply with the Fixed Price Agreement. Based on the prices you provided, the estimated cost of the items in your cart would be:

$23 (shirt) + $38 (trousers) + $17 (sweatshirt) + $26 (shoes) = $104

Therefore, the estimated total cost of the clothes in the cart is $104. However, please note that this is only an approximation and actual costs may vary due to factors such as sales tax and applicable discounts. 

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Answer:

x = 2 or x = -2

Step-by-step explanation:

5x² - 15 = 5​

⇌

5x² = 15 + 5

⇌

5x² = 20

⇌

x² = 20/5 = 4

⇌

x² = 2²

⇌

x² - 2² = 0

⇌

(x - 2)(x + 2) = 0

⇌   we use the zero product property

x - 2 = 0 or x + 2 = 0

⇌

x = 2 or x = -2

Answer:102

Step-by-step explanation:

The interior angles of a triangle have to measure 180 degrees, which is an isosceles triangle, and 39+39=78.

180-78=102.Therefore the  answer is 102

Answer:

PEMDAS

Step-by-step explanation:

USE PEMDAS

4 wont be the answer. answer is 3.42

Answer:

Medimos el perímetro en unidades lineales, que representan una sola dimensión. Ejemplos de unidades de medida de longitud son pulgadas, centímetros, ... Encontrar el perímetro de un triángulo con lados que miden 6 cm, 8 cm, y 12 cm. ... P = 2l + 2w, donde l es el largo del rectángulo y w l ancho del rectángulo. espe

==============================================================

Explanation:

C is at (0,0). Ignore the other points.

Reflecting over y = 1 lands the point on (0,2) because we move 1 unit up to arrive at the line of reflection, and then we keep going one more unit (same direction) to complete the full reflection transformation. I'll call this point P.

Then we reflect point P over the line x = 2 to arrive at the location Q = (4,2). Note how we moved 2 units to the right to get to the line of reflection, and then keep moving the same direction 2 more units, then we have applied the operation of "reflect over the line x = 2"

So we have started at C = (0,0), moved to P = (0,2) and then finally arrived at the destination Q = (4,2). This is the location of C' as well.

All of this is shown in the diagram below.

The main difference between the reciprocal and inverse of a function is their definition and properties. The reciprocal of a function f(x) is defined as 1/f(x), while the inverse of a function f(x) is a function f^(-1)(x) such that \(f(f^(-1)(x))=x and f^(-1)(f(x))=x\) for all x in their respective domains.

The domains of sine, cosine, and tangent functions need to be restricted to define their inverse functions because they are not one-to-one functions. In order to have an inverse, a function must be both one-to-one (each output has only one input) and onto (each output value is mapped by at least one input value).

For example:
- sine: restricted domain to [-π/2, π/2] to define its inverse, arcsin (sin^(-1))
- cosine: restricted domain to [0, π] to define its inverse, arccos (cos^(-1))
- tangent: restricted domain to (-π/2, π/2) to define its inverse, arctan (tan^(-1))

These restrictions ensure that the functions become one-to-one and onto, making it possible to define their inverses uniquely.

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The number of contractions performed before the randomized min cut algorithm terminates in a connected graph G with 100 vertices, each of degree 10, and 500 edges is not deterministic and can vary.

The randomized min cut algorithm, also known as the Karger's algorithm, works by repeatedly contracting randomly chosen edges until two super vertices remain, representing the two merged components. The algorithm terminates when there are only two vertices left in the graph. In this case, the graph G has 100 vertices, each with degree 10, which means it has a total of 500 edges. During each contraction step, an edge is chosen uniformly at random and contracted. Since there are 500 edges in the graph, the algorithm will perform a maximum of 500 contractions before terminating. However, it's important to note that the actual number of contractions performed can be much lower than the maximum. The algorithm's termination depends on the random choices made during the contraction steps, and it is possible to find the min cut with significantly fewer contractions. The expected number of contractions required to find the min cut in a connected graph is typically much smaller than the number of edges.

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