Fig. 62.7 A C₁2V 50 V 5₁ 30 (a) Calculate the readings of the ammeter and the voltmeter when the switches are as shown with S closed and S₂ open. Explain your calculations.

Answers

Answer 1

The reading on the ammeter will be 10 A.The reading on the voltmeter will be 50 V.

What is ammeter?

Generally, To solve this problem, we need to first analyze the circuit and determine the current and voltage at various points.

Starting at the left side of the circuit, we have a 50 V battery with its positive terminal connected to a resistor and its negative terminal connected to a switch. When the switch is closed, this allows current to flow from the battery through the resistor. The current will be given by Ohm's law:

I = V/R

Where I is the current, V is the voltage (50 V in this case), and R is the resistance of the resistor (5Ω in this case). Plugging in these values, we get:

I = 50 V / 5Ω = 10 A

Next, we need to determine the voltage across the resistor. This can be found using Ohm's law again:

V = IR

Where V is the voltage across the resistor, I is the current through the resistor (10 A in this case), and R is the resistance of the resistor (5Ω in this case). Plugging in these values, we get:

V = 10 A * 5Ω = 50 V

Since the voltage across the resistor is equal to the voltage of the battery, we know that the current through the resistor must be flowing in the same direction as the battery's current.

The ammeter in the circuit is connected in series with the resistor, so it will measure the current flowing through the resistor. Therefore, the reading on the ammeter will be 10 A.

The voltmeter is connected in parallel with the resistor, so it will measure the voltage across the resistor. Therefore, the reading on the voltmeter will be 50 V.

Related Questions

Three boxes are stacked on top of a cart. As the cart is moving, it comes to an abrupt stop. The boxes fall forward off of the cart. Explain why the boxes fell forward.

Answers

When your moving at a constant speed with boxes on top of each other in/on the cart and you stop the boxes will fall because 1- gravity, 2- the stop wasn't slow it was abrupt.

Drag each label to the correct location on the chart.
Sort the items based on whether they are simple machines or compound machines.

Answers

Answer:

whatttttttttttttttttttttttttttt are the items we have to classify into simple machines and compound machine

outline the reason for gay luccas law of volume

Answers

Gay-Lussac's law of volume states that for a fixed mass of an ideal gas kept at a fixed pressure, the volume and temperature are directly proportional.

What is Gay-Lussac's law about?

This means that if the temperature of a gas is increased, its volume will also increase, and vice versa.

The reason for Gay-Lussac's law of volume is that the average kinetic energy of the gas molecules is directly proportional to the temperature. As the temperature increases, the molecules move faster and collide with the walls of the container more often. This causes the pressure to increase. However, if the pressure is kept constant, the increase in pressure will cause the volume to increase.

Gay-Lussac's law of volume can be expressed mathematically as follows:

V₁ / T₁ = V₂ / T₂

where:

V₁ = initial volume of the gas

T₁ = initial temperature of the gas

V₂ = final volume of the gas

T₂ = final temperature of the gas

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Gay-Lussac's Law of Volume provides a useful relationship between the volumes of reactant and product gases, allowing for predictions and calculations in chemical reactions involving gaseous substances.

Understanding Gay-Lussac's Law of Volume

Gay-Lussac's Law of Volume, also known as the Law of Combining Volumes of Gases, states that "the volumes of gases involved in a chemical reaction at constant temperature and pressure are in the ratio of small whole numbers."

Reason for Gay-Lussac's Law of Volume

1. Avogadro's Law: According to Avogadro's Law, equal volumes of gases at the same temperature and pressure contain an equal number of particles (atoms, molecules, or ions). This law established the concept of the mole, which is a unit of measurement representing a fixed number of particles. Since the number of particles is the same, the volume occupied by these particles should also be the same.

2. Stoichiometry: Chemical reactions involve the rearrangement of atoms and molecules to form new substances. The coefficients in a balanced chemical equation represent the relative amounts of reactants and products. In the gaseous state, these coefficients can be directly related to the volumes of the gases involved. For example, if the balanced equation shows that two volumes of gas A react with three volumes of gas B to form four volumes of gas C, it implies that the gases react in simple volume ratios.

3. Gas Behavior: Gases follow certain ideal gas laws, such as Boyle's Law (pressure-volume relationship), Charles's Law (temperature-volume relationship), and Gay-Lussac's Law (pressure-temperature relationship). These laws describe how the physical properties of gases change under different conditions. Gay-Lussac's Law of Volume specifically relates the volumes of gases involved in a chemical reaction and shows that the volumes are proportional to each other.

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The index of refraction of quartz is 1.46. What is the velocity of light in quartz?

Answers

Answer:

Approximately $2.05 \times 10^{8}\; {\rm m\cdot s^{-1}}$.

Explanation:

The refractive index $n$ of a material is the ratio between the speed of light in vacuum $c$ and the speed of light $v$ in that material. In other words:

$\begin{aligned}n &= \frac{c}{v}\end{aligned}$.

The speed of light in vacuum is $c \approx 3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}$.

It is given that the refractive index is $n = 1.46$. Rearrange this equation to find $v$, the speed of light in this material:

$\begin{aligned}v &= \frac{c}{n} \\ &\approx \frac{3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}}{1.46} \approx 2.05 \times 10^{8}\; {\rm m\cdot s^{-1}}\end{aligned}$.

A horizontal force of 20 N just starts to move a box with weight80 N. Find the value of coefficient of static friction.

Answers

The static friction formula is

$\begin{gathered} F_s=\mu_sN \\ \mu_s=\frac{F_s}{mg} \end{gathered}$

As you can observe, the normal force is equal to the weight force.

$\mu_s=\frac{20N}{80N}=0.25$

Therefore, the value of the coefficient of static friction is 0.25.

Name 1. Consider positive and negative charges of a copper wire all moving horizontally within the time interval 10 us. What can you say about the magnitude and direction of the current?

Answers

When positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of charge movement.

In the given scenario, if positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds (10 μs), we can infer the following about the magnitude and direction of the current:

1. Magnitude of the Current: The magnitude of the current is determined by the total charge passing through a given point in the wire per unit time. Since both positive and negative charges are moving, the total charge passing through a point will be the sum of the magnitudes of the charges. If the number of positive and negative charges is equal, the magnitudes of their charges will also be equal. Therefore, the total charge passing through the point will be the sum of equal positive and negative charges, resulting in a net charge of zero. In this case, the magnitude of the current will be zero.

2. Direction of the Current: The direction of the current is determined by the flow of positive charges. In a copper wire, the positive charges are not free to move. Instead, it is the negatively charged electrons that are free to move. Due to conventional current flow convention, the direction of the current is considered opposite to the direction of the electron flow. Therefore, even though both positive and negative charges are moving horizontally, the direction of the current will be in the opposite direction to the movement of the charges.

In summary, in the given scenario, where positive and negative charges of a copper wire are moving horizontally within a time interval of 10 microseconds, the magnitude of the current is zero, and the direction of the current is opposite to the direction of the charge movement.

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A uniform electric field ai + bj intersects a surface of area A. What is the flux through this area if the surface lies (a) in the yz plane? (b) in the xz plane? (c) in the xy plane?

Answers

Answer:

Explanation:

The electric flux through a surface is given by the dot product of the electric field and the area vector of the surface:

Φ = E · A

where Φ is the electric flux, E is the electric field, and A is the area vector of the surface.

(a) If the surface lies in the yz plane, its area vector is in the x direction. Therefore, the area vector can be written as A = Ax i, where Ax is the magnitude of the area. The electric field is given as E = ai + bj. Therefore, the flux through the surface is:

Φ = E · A = (ai + bj) · (Ax i) = aAx

(b) If the surface lies in the xz plane, its area vector is in the y direction. Therefore, the area vector can be written as A = Ay j, where Ay is the magnitude of the area. The electric field is given as E = ai + bj. Therefore, the flux through the surface is:

Φ = E · A = (ai + bj) · (Ay j) = bAy

(c) If the surface lies in the xy plane, its area vector is in the z direction. Therefore, the area vector can be written as A = Az k, where Az is the magnitude of the area. The electric field is given as E = ai + bj. Therefore, the flux through the surface is:

Φ = E · A = (ai + bj) · (Az k) = 0

since the dot product of perpendicular vectors is zero.

A small 8.00 kg rocket burns fuel that exerts a time-varying upward force on the rocket (assume constant mass) as the rocket moves upward from the launch pad. This force obeys the equation F=A+Bt2. Measurements show that at t=0, the force is 100.0 N, and at the end of the first 2.00 s, it is 162.0 N.
A. Find the net force on this rocket at the instant after the fuel ignites.
B. Find the acceleration of this rocket at the instant after the fuel ignites.
C. Find the net force on this rocket 3.00 ss, after the fuel ignites.
D. Find the acceleration of this rocket 3.00 ss, after fuel ignition.
E. Suppose that you were using this rocket in outer space, far from all gravity. What would its acceleration be 3.00 ss, after fuel ignition?

Answers

a) The net force at the point of fuel ignition is F = A = 100 N.

b) Acceleration after fuel ignites is a = 12.5 m/s^2

c) The net force on the rocket at t=3.00 s is 403 N.

d) Acceleration of rocket 3.00 ss after fuel ignites is a = 50.4 m/s^2

e) Acceleration in outer space is a = 50.4 m/s^2

How the solution was obtained

A. The force at t=0 is given as 100 N, so A = 100 N. We can use the given information to find B:

F = A + Bt^2

162 N = 100 N + B(2.00 s)^2

B = (162 N - 100 N) / (2.00 s)^2

B = 31 N/s^2

Therefore, the net force on the rocket at t=0 is:

F = A = 100 N.

B. The acceleration of the rocket is given by Newton's second law:

F_net = ma

where F_net is the net force acting on the rocket, and a is the acceleration of the rocket. At t=0, the net force on the rocket is 100 N. Therefore, the acceleration of the rocket at t=0 is:

a = F_net / m

a = 100 N / 8.00 kg

a = 12.5 m/s^2

C. To find the net force on the rocket at t=3.00 s, we can simply plug in t=3.00 s into the force equation:

F = A + Bt^2

F = 100 N + 31 N/s^2 (3.00 s)^2

F = 403 N

Therefore, the net force on the rocket at t=3.00 s is 403 N.

D. To find the acceleration of the rocket at t=3.00 s, we can use the same equation as in part B:

F_net = ma

At t=3.00 s, the net force on the rocket is 403 N. Therefore, the acceleration of the rocket at t=3.00 s is:

a = F_net / m

a = 403 N / 8.00 kg

a = 50.4 m/s^2

E. In outer space, far from all gravity, the only force acting on the rocket is the force from the burning fuel. Therefore, the net force on the rocket is simply the force from the burning fuel:

F = A + Bt^2

F = 100 N + 31 N/s^2 (3.00 s)^2

F = 403 N

Using the same equation as in part B, the acceleration of the rocket is:

a = F_net / m

a = 403 N / 8.00 kg

a = 50.4 m/s^2

Therefore, the acceleration of the rocket in outer space would be the same as in part D.

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In an independent-measures experiment with three treatment conditions, all three treatments have the same mean, M1 = M2 = M3. For these data, what is the value for SSbetween treatments?
a. 3(5.50)
b. 0
c. 1.00
d. Cannot be determined from the information given

Answers

A is the answer 3(5.50) .Three of the treatment means in a two-factor experiment with two levels of factor A and two levels of factor B are almost identical, while one is significantly different from the others. What outcome (s) would this course of treatment achieve?

When analysing variance, the differences that exist when there are no treatment effects are measured using the variance within treatments. By summing the SS values across all treatments and dividing by the total of the df values across all treatments, this value is obtained. By summing the SS values across all treatments and dividing by the total of the df values across all treatments, this value is obtained. A study evaluating three therapies with a n = 10 sample size

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Discuss the circuits.
Name all the
components. What
will happen to bulb
B1 if the bulb B2 is
replaced with
connecting wire in
each circuit?

Answers

The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.

Circuits are basically the pathways that allow the flow of electric current. These circuits have different components. In this context, there are two circuits, the series circuit, and the parallel circuit. The series circuit has bulbs connected in a sequence where current flows through each bulb in turn. In contrast, the parallel circuit has bulbs connected to different branches. The current flows through each bulb separately.In a series circuit, the components are a power source, resistors, and wires. A power source can be a battery or a generator that is connected in a sequence with resistors and wires. The bulbs B1 and B2 are connected in series. If bulb B2 is replaced with a connecting wire, then the circuit will become incomplete, and bulb B1 will not light up. This is because in a series circuit, if one component is disconnected, the entire circuit becomes open, and the current stops flowing. Thus, if bulb B2 is replaced with a wire, the current will bypass the bulb, and the circuit will become incomplete. In a parallel circuit, the components are a power source, resistors, and branches. The bulbs B1 and B2 are connected in parallel. If bulb B2 is replaced with a connecting wire, the circuit will still work. This is because in a parallel circuit, each bulb has its branch, and the current flows through each bulb separately. Thus, if bulb B2 is replaced with a wire, the current will still flow through bulb B1, and it will light up.

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When two forces are the same strength but act in opposite direction , they are called

Answers

Balanced forces :) I think

The skin temperature of a person is 34o C and his body surface area is about 1.8 m2 . He is standing bare skin in a room where the air temperature is 24o C and the walls are 17o C. He is metabolizing food at a rate of 155 W, the emissivity of his skin is 0.97 and there is a 5mm thick dead layer (immobile) air next to his skin acting as an insulation. a./ at what rate his body is losing heat by conduction

Answers

Answer:

the rate at which his body is losing heat by conduction is 93.6 J/s

Explanation:

Given that;

surface area A = 1.8 m²

Skin temperature of the person Tp = 32°C = ( 34 + 273.15 ) = 307.15 K

Temperature of Air $T_{air}$ = 24°C = ( 24 + 273.15 ) = 297.15 K

Temperature of wall $T_{wall}$ = 17°C = ( 17 + 273.15 ) = 290.15 K

Length ( thick dead layer = 5 mm = 0.005 m

Skin emissivity = 0.97

Rate of metabolism = 155 W

rate his body is losing heat by conduction = ?

first we determine the difference in temperature between the skin and air

ΔT = 307.15 K - 297.15 K = 10 K

we know that; coefficient of thermal heat conductivity of air k = 0.026 W/mK

rate of heat loss by conduction Q/ΔT will be;

Q/ΔT = (KA/L)ΔT

so we substitute

= ( 0.026 × 1.8/ 0.005 )10

= 9.36 × 10

= 93.6 J/s

Therefore, the rate at which his body is losing heat by conduction is 93.6 J/s

The trajectory of a ball can be computed with
y = (tan 0)x
9
2v cos² 0.
-x² + Yo
where y the height (m), 0o = the initial angle (radians), vo = the initial velocity (m/s), g = the gravitational constant = 9.81 m/s²,
and yo the initial height (m). Use the golden-section search to determine the maximum height given yo = 2 m, vo = 20 m/s,
and 80=45°. Iterate until the approximate error falls below &s=10% using initial guesses of x/= 10 m and xu = 30 m. (Round
the final answer to three decimal places.)
The maximum height is
m.

The trajectory of a ball can be computed withy = (tan 0)x92v cos 0.-x + Yowhere y the height (m), 0o

Answers

We must define a function that accepts an input parameter x and returns the associated height y in order to use the golden-section search. By entering the specified numbers for yo, vo, 0o, g, and x into the formula.

How much learning error must be set?

The golden-section search algorithm can now be used to identify the value of x that maximises y. We begin by setting the error tolerance to 10% and starting with the basic hypotheses .

How can we determine the value of x that optimises y using the golden-section search algorithm?

Calculate the values of x2 and x3 using the golden ratio:Evaluate the function at x2 and x3:If y2 > y3, the maximum is between x1 and x3, so we set x4 = x3 and repeat from step 1. Otherwise, the maximum is between x2 and x4, so we set x1 = x2 and repeat from step.

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HELP PLS!!

What are open, closed and isolated systems?

Answers

Open systems allow energy and mass to pass across the system boundary. A closed system allows energy but not mass across its system boundary. An isolated system allows neither mass or energy to pass across the system boundary

A metallic circular plate with radius r is fixed to a tabletop. An identical circular plate supported from above by a cable is fixed in place a distance d above the first plate. Assume that dd is much smaller than r. The two plates are attached by wires to a battery that supplies voltage V.

A)What is the tension in the cable? Neglect the weight of the plate.

Express your answer in terms of the variables d, r, V, and constants ϵ0, π.

B)The upper plate is slowly raised to a new height 2d. Determine the work done by the cable by integrating ∫(from d to 2d) F(z)dz, where F(z) is the cable tension when the plates are separated by a distance z.

Express your answer in terms of the variables d, r, V, and constants ϵ0, π.

C)Compute the energy stored in the electric field before the top plate was raised.

Express your answer in terms of the variables d, r, V, and constants ϵ0, π.

D)Compute the energy stored in the electric field after the top plate was raised.
Express your answer in terms of the variables d, r, V, and constants ϵ0, π.

E)Is the work done by the cable equal to the change in the stored electrical energy? If not, why not?
a)The work done in separating the plates is equal to energy change in the plates.
b)The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates. The work done on the plates is positive but the plates lose energy. The plates are connected to the battery, so the potential difference across them remains constant as they are separated. Therefore charge is forced off of the plates through the battery, which does work on the battery.

Answers

Answer:

the tension in the cable is $\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}$

the work done by the cable is $\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}$

Explanation:

If we have two circular plate supported by a cable at a fixed distance, then the electric field formed between the two plate of the capacitor can be represented by the equation.

$\mathbf{E = \frac{voltage \ \ V}{distance \ \ d}}$

However; the net electric field i.e the sum of the electric filed produced is represented as:

$\mathbf{E' = \frac{E}{2}} \\ \\ \mathbf{E' = \frac{V}{2d}}$

So, if we assume that the lower plate and the upper plate possess the charge +q and -q respectively. Then, the tension of the cable which is the same as Force F can be written as:

$\mathbf{F = q* E'}$

$\mathbf{F = \frac{q*v}{2d}}$ ----- equation (1)

Also ; we know that

$\mathbf{C = \frac{q}{v}= \frac{E_oA}{d}}$

$\mathbf{\frac{q}{v}= \frac{E_o \pi r^2}{d}} \ \ \ \ \ \mathbf{since \ A = \pi r^2}$

$\mathbf{{q}= \frac{\pi E_o {v} r^2}{d}}$ ----- equation (2)

Replacing equation 3 into equation (2); we have:

$\mathbf{F = \frac{\pi E_o vr^2}{d}* \frac{v}{2d}}$

$\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}$

Therefore, the tension in the cable is $\mathbf{F = \frac{\pi E_o v^2r^2}{2d^2}}$

Assume that the upper plate is displaced by dz in an upward direction ; Then we can express the workdone by the tension as :

$\mathbf{dW = T *dz} \\ \\ \mathbf{dW = F*dz} \\ \\ \mathbf{dW = \frac{\pi E_o v^2r^2}{2z^2}dz }$

The net workdone to raise the plate from separation d to 2d is:

$\mathbf{W = \int\limits^{2d}_{2zd} {dw} = \frac{\pi E_ov^2r^2}{2} \int\limits^{2d}_d \frac{dz}{z^2} }$

$\mathbf{W= \frac{\pi E_ov^2r^2}{2} [-\frac{1}{z}]^{2d}_d }$

$\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{1}{2d}-\frac{1}{d}]}$

$\mathbf{W= - \frac{\pi E_ov^2r^2}{2} [\frac{-1}{2d}]}$

$\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}$

the work done by the cable is $\mathbf{W= \frac{\pi E_ov^2r^2}{4d}}$

C) To calculate the energy stored in the Electrical energy Capacitor before the top plate is raised ; we have:

$\mathbf{U_i = \frac{1}{2}Cv^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_oA}{d})v^2} \\ \\ \mathbf{U_i = \frac{1}{2}(\frac{E_o \pi r^2}{d})v^2} \\ \\ \mathbf{U_i = \frac{E_o \pi r^2 v^2}{2d}} }$

D) The energy stored in the plate after the the top plate was raised is as follows:

$\mathbf{U_f = \frac{1}{2}C'v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_oA}{2d})v^2} \\ \\ \mathbf{U_f = \frac{1}{2}(\frac{E_o \pi r^2}{2d})v^2} \\ \\ \mathbf{U_f = \frac{E_o \pi r^2 v^2}{4d}} }$

E) Yes, work done by the cable equal to the change in the stored electrical energy. The Difference in energy stored before and after the top plate is raised:

$\mathbf{U_i-U_f} = \mathbf{\frac{E_o \pi r^2 v^2}{2d}} }} - \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}$

$\mathbf{U_i-U_f}= \mathbf {\frac{E_o \pi r^2 v^2}{4d}} }}$

Thus;

b)The work done in separating the plates is equal to the magnitude of the energy change in the plates. This does not mean that the work done is equal to the change in the energy stored in the plates.

3. A car with a mass of 1600 kg has a kinetic energy of 125 000 J. How fast is it moving?

Answers

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * $v^2$

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the values , we have:

125,000 J = 1/2 * 1600 kg *$v^2$

Now, we can solve for v by rearranging the equation:

$v^2$ = (2 * 125,000 J) / 1600 kg

$v^2$ = 156.25 $m^2/s^2$

Taking the square root, we find:

v = √156.25$m^2/s^2$

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Very Important, I need the answer

Answers

Answer:

Explanation:

A constant velocity means the position graph has a constant slope. It's a straight line sloping up.

1. A ball is at rest on the top of a hill (see the figure).
At the top of the hill, the ball will have [the maximum value of its, no, the minimum value of its] gravitational potential energy and [no, the maximum value of its] kinetic energy. If the ball rolls down the hill then, its [gravitational potential energy, kinetic energy] is converted to [gravitational potential energy, kinetic energy] when it gets to the ground.

2. Get your stopwatch ready and prepare to drop the object from the height h you selected in the previous step. You should drop the object so its [bottom, top, middle] part is initially at the height h. The initial speed of the ball [zero, 9.8 m/s, 9.8 m/s^2, depends on the height h] You'll need to measure the time from when the ball leaves your hand to exactly when it hits the ground [ for the first time it bounces, after it bounces and then comes to rest, both the first time and then after it bounces; then average the two times]
.

Answers

1. At the top of the hill, the ball will have the maximum value of its gravitational potential energy and the minimum value of its kinetic energy. As the ball rolls down the hill, its gravitational potential energy is converted to kinetic energy when it gets to the ground.

2. When dropping the object, you should drop it so its top part is initially at the height h. The initial speed of the ball will be zero since it starts from rest. To measure the time it takes for the ball to hit the ground, you should start the stopwatch when the ball leaves your hand and stop it when the ball hits the ground for the first time. It is recommended to perform multiple trials and calculate the average time to minimize errors.

Why the circulatory system of a grasshopper does not need to carry gases to and from the grasshopper cells

Answers

Answer:

Explanation:

In vertebrates, the circulatory system is responsible for transporting oxygen to all the tissues and removing carbon dioxide from them. ... In the grasshopper, exchange of oxygen and carbon dioxide occurs in the tracheal system. Hemolymph plays no part in the process.

Given the list of items, select all that are considered to be matter:
music
heat
air
dreams
water
gasoline
love
bacteria
thoughts

Answers

From the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

What is matter?

Matter is a substance made up of various types of particles that occupies physical space and has inertia.

A matter must have mass and occupy space.

Examples of matter include the following;

heatairwatergasolinebacteria

Thus, from the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

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i need help question confuseing

Answers

Answer:

could you tell me what the question is pls, that way I can help you

Explanation:

A 1420-kg car moving east at 17.0 m/s collides with a 1880-kg car moving south at 15.0 m/s, and the two cars connect together.A. What is the magnitude of the velocity of the cars right after the collision? (m/s )B. What is the direction of the cars right after the collision? Enter the angle in degrees where positive indicates north of east and negative indicates south of east. (°)C. How much kinetic energy was converted to another form during the collision? (kJ)

Answers

Given,

The mass of the car moving east, m=1420 kg

The mass of the car moving south, M=1880 kg

The velocity of the car moving east, u₁=17.0 m/s

The velocity of the car moving south, u₂=-15.0 m/s

Here we assume that the eastward direction is the positive x-direction and the southward direction is the negative y-direction.

From the law of conservation of momentum, the momentum is conserved in both directions simultaneously and independently.

Considering the conservation of momentum in the x-direction,

$mu_1=(m_{}+M)v_x$

Where v_x is the x-component of the final velocity of the two cars.