Answer:
Felipe dio un paso incorrecto de acuerdo con el sistema de valor posicional al sumar la suma de 1,000 a 39,200. La manera correcta en que Felipe debe abordar esto se muestra en la explicación a continuación.
Step-by-step explanation:
En el sistema de valor posicional; cada número representa una entidad particular; ya sea unidad, decenas, cientos, mil, diez mil etc. En la pregunta dada, el número 39200 indica que 9 está en el valor posicional de mil, es decir, 9000.
Entonces, si Felipe desea cambiar de 8 a 9, entonces necesita restar 9000-8000 = 1000
Sin embargo; si quiere cambiar 9 a cero; entonces restará 9000 de 9000; pero ya que 9 no funciona; Primero debe restar 8000 y luego restar 1000.
Question 6: A) If f(x, y, z) = 2xyz subject to the constraint g(x, y, z) = 3x2 + 3yz + xy = 27, then find the critical point which satisfies the condition of Lagrange Multipliers.
Given f(x, y, z) = 2xyz, and function f(x) g(x, y, z) = 3x^2 + 3yz + xy = 27. To find the critical point which satisfies the condition of Lagrange Multipliers
we need to use the method of Lagrange multipliers as follows. Let's define λ as the Lagrange Multiplier and write the Lagrangian L as:L = f(x, y, z) - λg(x, y, z)Now, substitute the given functions to the above equation.L = 2xyz - λ(3x^2 + 3yz + xy - 27)Taking the partial derivative of L with respect to x and equating it to zero, we get0 = ∂L/∂x = 2yz - 6λx + λyUsing the same method, we get0 = ∂L/∂y = 2xz - 3λz + λx0 = ∂L/∂z = 2xy - 3λyThe given function is such that it becomes more complicated to find x, y, and z using the partial derivative method since they are very mixed up. Thus, we have to use other methods such as substitution method or solving the system of equations. So, we need to solve the system of equations:2yz = 6λx - λy2xz = 3λz - λx2xy = 3λyTo do this, we need to eliminate the λ's. Dividing the first equation by 6 and then substituting λy for z in the second equation, we get:y = 4x/3Substituting this into the third equation and solving for λx, we get:λx = 8/3Substituting these values for x and λx into the first equation, we get:2yz = 8y/3So, z = 4/3Substituting these values into the second equation, we get:2x * (4/3) = 3λz - λx8x/3 = 12λ/3λ = 2/3So, x = 1 and y = 4/3.Thus, the critical point is (x, y, z) = (1, 4/3, 4/3).
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100 POINTS please help!!!!
Answer:
Standard deviation σ = 1.40 (2 d.p.)
Step-by-step explanation:
If a continuous random variable X is normally distributed with mean μ and variance σ², it is written as:
\(\boxed{X \sim\text{N}(\mu,\sigma^2)}\)
Given:
Mean μ = 13.9 g/dLP(X < 16.2) = 0.95Therefore, if the haemoglobin levels are normally distributed:
\(X \sim\text{N}(13.9,\sigma^2)\)
where X is the haemoglobin level.
Converting to the Z distribution:
\(\boxed{\textsf{If }\: X \sim\textsf{N}(\mu,\sigma^2)\:\textsf{ then }\: \dfrac{X-\mu}{\sigma}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)}\)
Transform X to Z:
\(\text{P}(X < 16.2)= \text{P}\left(Z < \dfrac{16.2-13.9}{\sigma}\right)= 0.95\)
According to the z-tables, when p = 0.95, z = 1.6449
\(\implies \dfrac{16.2-13.9}{\sigma}=1.6449\)
\(\implies \dfrac{2.3}{\sigma}=1.6449\)
\(\implies \sigma=\dfrac{2.3}{1.6449}\)
\(\implies \sigma=1.40\)
Hello help me find out what is 42-22
a university with a high water bill is interested in estimating the mean amount of time that students spend in the shower each day. in a sample of 11 students, the average time was 4.94 minutes and the standard deviation was 1.27 minutes. using this sample information, construct a 99% confidence interval for the mean amount of time that students spend in the shower each day. assume normality. a) what is the lower limit of the 99% interval? give your answer to three decimal places. b) what is the upper limit of the 99% interval? give your answer to three decimal places.
lower limit of the 99% interval = 3.7265
Upper limit of the 99% interval = 6.1535
What do you mean by standard deviation?
The standard deviation is a quantity that reveals the degree of variation (such as spread, dispersion, and spread) from the mean.
Number of students, n = 11
Averange time , mean , μ = 4.94
Standard deviation , \(s_{x}\) = 1.27
Significance level , α = 1 -= 0.99 = 0.01
Degree of freedom for t-distribution , d.f. = n - 1 = 11 - 1 = 10
Critical value = \(t_{\alpha /2,d.f\) = \(t_{0.005,10}\) = 3.169
Margin of error ,E = \(t_{\alpha /2,d.f\) × \(\frac{s_{x} }{\sqrt{n} }\) = 3.169 ×\(\frac{1.27}{\sqrt{11} }\) = 3.169 × 0.38292 = 1.21347
Limits of 99% confidence intervals are given by:
a) Lower limit = μ - E = 4.94 - 1.21347 = 3.7265
b) Upper limit = μ + E = 4.94 + 1.21347 = 6.1535
Therefore, lower limit of the 99% interval = 3.7265
Upper limit of the 99% interval = 6.1535
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Which statement is TRUE for a chemical change?
A
The identity of the substance does not change.
B
The mass is conserved.
C
The substance always changes from solid to liquid.
D
The particles are not rearranged.
Answer:
B. The mass is conserved
Step-by-step explanation:
A. The identity of the substance does not change. [FALSE]
B. The mass is conserved. [TRUE]
C. The substance always changes from solid to liquid. [FALSE]
D. The particles are not rearranged. [FALSE]
pa answer po plss plssss
29/32
Step-by-step explanation:
ng x value 32wrffddfddfffryufcjhfddxhjhddxffdssdtt
Evaluate the expression for the given value of the variables.
0.9g - 2.1h
g = 15, h=2
For the given values g = 15, h=2, the evaluation of the expression is obtained as 9.3.
What is an expression?It is defined as the combination of constants and variables with mathematical operators.
It is given that, the expression is 0.9g - 2.1h and g = 15, h=2.
Substitute the value of g and h in order to evaluate the expression,
=0.9g - 2.1h
=0.9(15)-2.1(2)
We have to apply the arithmetic operation in which we do the addition of numbers, subtraction, multiplication, and division. It has basic four operators that are +, -, ×, and ÷.
Thus, for the given values g = 15, h=2, the evaluation of the expression is obtained as 9.3.
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Help please I’ll give brainlest!!
For box plot data where Q1 = 200, Q2 = 250, and Q3 = 290, the
IQR
The value of IQR is 90 when box plot data where Q₁ = 200, Q₂ = 250, and Q₃ = 290.
Given that,
For box plot data where Q₁ = 200, Q₂ = 250, and Q₃ = 290
We have to find the data of IQR.
We know that,
IQR is define as the variation in the distribution of your data's middle quartile is measured by the interquartile range (IQR). It is the range that corresponds to your sample's middle 50%. Measure the variability where the majority of your numbers are by using the IQR.
IQR Formula is Q₃ - Q₁
So,
Q₃ = 290
Q₁ = 200
Then ,
IQR = Q₃ - Q₁
IQR = 290 - 200
IQR = 90
Therefore, The value of IQR is 90.
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how to determine the end behavior of a rational function
By analyzing the degrees and leading coefficients, you can determine how the rational function behaves at the extreme ends of the x-axis.
To determine the end behavior of a rational function, you need to examine the degrees of the numerator and denominator polynomials. The end behavior refers to how the function behaves as the input (x-values) approaches positive or negative infinity.
Here are the steps to determine the end behavior of a rational function:
1. Identify the highest power of x in the numerator and denominator. Let's call them n and m, respectively.
2. If n < m, the degree of the denominator is greater than the numerator. In this case, the function's end behavior is determined by the degree of the denominator.
- If m is even, the function approaches the horizontal axis (y = 0) as x approaches both positive and negative infinity.
- If m is odd, the function approaches opposite infinities: positive infinity as x approaches negative infinity and negative infinity as x approaches positive infinity.
3. If n = m, the degree of the numerator is equal to the denominator. In this case, the leading coefficients of the numerator and denominator determine the end behavior.
- The function approaches the ratio of the leading coefficients as x approaches both positive and negative infinity.
4. If n > m, the degree of the numerator is greater than the denominator. In this case, the function's end behavior is determined by the degree of the numerator.
- If n is even, the function approaches positive infinity as x approaches both positive and negative infinity.
- If n is odd, the function approaches opposite infinities: positive infinity as x approaches positive infinity and negative infinity as x approaches negative infinity.
By analyzing the degrees and leading coefficients, you can determine how the rational function behaves at the extreme ends of the x-axis.
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PLEASE HELP ME! Please do not comment nonsense, and actually comment the answer and the solution.
=================================================
Explanation:
For choice C, the x values are out of order, so it might be tricky at first. I recommend sorting the x values from smallest to largest to get -2, -1, 0, 1, 2. Do the same for the y values as well. Make sure the correct y values stay with their x value pairs. You should get the list of y values to be 4, 2, 1, 1/2, 1/4
Check out the attached image below for the sorted table I'm referring to
We can see the list of y values is going down as x increases. This is a good sign we have decay. Further proof is that we multiply each term by 1/2 to get the next one
4 times 1/2 = 2
2 times 1/2 = 1
1 times 1/2 = 1/2
1/2 times 1/2 = 1/4
and so on. Effectively we can say the decay rate is 50%
Triangle similarity and congruence! * Pic included
Answer:
Yes, beacuse the ratios of the corresponding sides are equal.
Step-by-step explanation:
12/36 = 0.33
10/30 = 0.33
15/45 = 0.33
For the following figure, can you conclude that /|| m? Select true or false.
Answer:
The answer is true
Step-by-step explanation:
Answer:
this question is true for the answer :)
find fx(1, 0) and fy(1, 0) and interpret these numbers as slopes for the following equation. f(x, y) = 4 − x2 − 3y2
Given, the equation:f(x,y)=4−x2−3y2To find the values of fx(1,0) and fy(1,0) and interpret these numbers as slopes. The formula for the partial derivative of the function with respect to x, that is fx is as follows:fx=∂f/∂x
Similarly, the formula for the partial derivative of the function with respect to y, that is fy is as follows:
fy=∂f/∂y
Now, we will find
fx(1,0).fx=∂f/∂x=−2x
At (1,0),fx=−2x=−2(1)=-2
Now, we will find
fy(1,0).fy=∂f/∂y=−6y
At (1,0),fy=−6y=−6(0)=0
Therefore, fx(1,0)=-2 and fy(1,0)=0.
Interpretation of the values of fx(1,0) and fy(1,0) as slopes: The value of fx(1,0)=-2 can be interpreted as a slope of -2 in the x direction, when y is held constant at 0. The value of fy(1,0)=0 can be interpreted as a slope of 0 in the y direction, when x is held constant at 1.We are given a function f(x,y) = 4 − x² − 3y² and are asked to find fx(1,0) and fy(1,0) and interpret these numbers as slopes. To calculate these partial derivatives, we first calculate fx and fy:fx=∂f/∂x=−2xandfy=∂f/∂y=−6yWhen we substitute (1,0) into these expressions, we get:fx(1,0) = -2(1) = -2andfy(1,0) = -6(0) = 0So the slopes are -2 in the x direction when y is held constant at 0, and 0 in the y direction when x is held constant at 1. This means that the function is steeper in the x direction than in the y direction at the point (1,0).
Therefore, the slopes are -2 in the x direction when y is held constant at 0, and 0 in the y direction when x is held constant at 1. This means that the function is steeper in the x direction than in the y direction at the point (1,0).
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what are 3 combinations of coins with the value of 30% of a dollar
The 3 combinations of coins with the value of 30% of a dollar are 2 dimes + 1 Nickel + 5 Pennies, 1 dime + 2 Nickels + 10 Pennies, 3 Nickels + 1 dime + 5 Pennies.
How many types of coins are there?
There are 4 types of coins. They are Quarter, Nickel, dime, and Penny.
1 Quarter = 25 cent
1 dime = 10 cents
1 Nickel = 5 cents
1 penny = 1 cent
Now calculate 30 percentage of a dollar.
1 dollar = 100 cents.
30% of 100 cents = (30/100) × 100 = 30 cents.
2 dimes + 1 Nickel + 5 Pennies = 20 cents + 5 cents + 5 cents = 30 cents
1 dime + 2 Nickels + 10 Pennies = 10 cents + 10 cents + 10 cents = 30 cents
3 Nickels + 1 dime + 5 Pennies = 15 cents + 10 cents + 5 cents = 30 cents
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Consider the equation 100% of $3 = $x. what is the value of x ________
pls help ^^
100% of $3=$x
1×$3=$x
$3/$=$x/$
3=x
x=3
Jesse recorded the temperatures at which two oils freeze: Oil Temperature Sesame oil −6.2 °C Peanut oil 3.1 °C Which statement about the temperatures at which these oils freeze is true? Sesame oil freezes at a higher temperature than peanut oil because −6.2 °C < 3.1 °C. Sesame oil freezes at a lower temperature than peanut oil because −6.2 °C < 3.1 °C. Sesame oil freezes at a higher temperature than peanut oil because −6.2 °C > 3.1 °C. Sesame oil freezes at a lower temperature than peanut oil because −6.2 °C > 3.1 °C. plzzz answer this for me ^w^
Answer: C. Sesame oil freezes at a lower temperature than peanut oil because −6.2 °C < 3.1 °C
Step-by-step explanation:
Given that:
Freezing point of sesame oil = - 6.2°C
Freezing point of peanut oil = 3.1°C
Comparing the two temperatures :
Freezing(when a substance turns to solid) usually occurs at low temperatures. The temperature of sesame oil(-6 2°C) is lower than that of peanut oil(3.1°C).
Hence, it can be concluded that Sesame oil freezes at lower temperature than peanut oil.
Mathematically,
-6.2°C < 3.1°C
Answer:
Answer: C. Sesame oil freezes at a lower temperature than peanut oil because −6.2 °C < 3.1 °C
Step-by-step explanation:
how many times do i have to fill upon diesel if i have a full gallon tank of 115 diesel and travel 808.1 miles?
Number of refills = Distance traveled / (Fuel efficiency x Tank capacity)
Substituting the given values, we get:
Number of refills = 808.1 / (20 x 1)
Number of refills = 40.41
Rounding up to the nearest whole number, we get:
Number of refills = 41
Therefore, the tank needs to be refilled 41 times.
How many times to refill the tank if I travel 808.1 miles with a full gallon tank of 115 diesel?To explain why we used the formula, we note that the problem requires us to find the number of times the tank needs to be refilled, given a full gallon tank of 115 diesel and a travel distance of 808.1 miles. To calculate this, we need to know the fuel efficiency of the vehicle in terms of miles per gallon. Assuming a constant fuel efficiency, we can use the formula that relates distance traveled, fuel efficiency, tank capacity, and the number of refills needed. By substituting the given values, we can find the number of refills needed to complete the journey, which turns out to be 41.Learn more about Distance
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Please explain the difference (in assumptions and when you use
them in practice) between the BIS, SPE, and WSE solution
concepts
BIS (Bayesian Nash Equilibrium with Incomplete Information) is used when players have private information that affects their decision-making. It assumes players have subjective beliefs about each other's types and use Bayes' rule to update their beliefs.
BIS incorporates uncertainty and provides a refined equilibrium concept.
SPE (Subgame Perfect Equilibrium) is used in dynamic games with multiple stages. It requires that strategies are optimal not only at each stage but also in every possible subgame. SPE helps predict players' actions by considering their ability to react to deviations in the game.WSE (Welfare-maximizing Social Equilibrium) aims to find an equilibrium that maximizes social welfare. It considers not only individual players' payoffs but also the overall welfare of society.
WSE incorporates fairness and efficiency considerations.BIS is used when players have private information, SPE is used in dynamic games to capture credible strategies, and WSE focuses on maximizing social welfare. Each concept serves different purposes in decision-making in game theory.
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in the special case of two degrees of freedom, the chi-squared distribution coincides with the exponential distribution
In the special case of two degrees of freedom, the chi-squared distribution does not coincide with the exponential distribution. The chi-squared distribution is a continuous probability distribution that arises in statistics and is used in hypothesis testing and confidence interval construction. It is defined by its degrees of freedom parameter, which determines its shape.
On the other hand, the exponential distribution is also a continuous probability distribution commonly used to model the time between events in a Poisson process. It is characterized by a single parameter, the rate parameter, which determines the distribution's shape.
While both distributions are continuous and frequently used in statistical analysis, they have distinct properties and do not coincide, even in the case of two degrees of freedom. The chi-squared distribution is skewed to the right and can take on non-negative values, while the exponential distribution is skewed to the right and only takes on positive values.
The chi-squared distribution is typically used in contexts such as goodness-of-fit tests, while the exponential distribution is used to model waiting times or durations until an event occurs. It is important to understand the specific characteristics and applications of each distribution to appropriately utilize them in statistical analyses.
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b. What does the standard deviation tell you about the trees at these
farms?
From the given dot plot, it is found that:
1. Farm 1 has mean of 8 inches and standard deviation of 1.15 inches, while Farm 2 has a mean of 8 inches but a standard deviation of 2.31 inches.
2. The lower standard deviation tells that the heights of the trees in Farm 1 are more uniform than in Farm 2.
What are the mean and the standard deviation of a data-set?The mean of a data-set is given by the sum of all values in the data-set, divided by the cardinality of the data-set, which is the number of values in the data-set.The standard deviation of a data-set is given by the square root of the sum of the differences squared between each observation and the mean, divided by the cardinality of the data-set.A dot plot shows the number of times that each observation appears in a data-set.
Hence, at farm 1, the measures are given as follows:
6, 7, 7, 8, 8, 8, 9, 9, 10.
The mean is given by:
M = (6 + 2 x 7 + 3 x 8 + 2 x 9 + 10)/9 = 8 inches.
The standard deviation is given by:
S = sqrt[((6-8)² + 2 x (7-8)² + 3 x (8-8)² + 2 x (9-8)² + (10-8)²)/9] = 1.15 inches.
For Farm 2, the measures are given as follows:
4, 6, 6, 8, 8, 8, 10, 10, 12.
Hence the mean and the standard deviation are given, respectively, by:
M = (4 + 2 x 6 + 3 x 8 + 2 x 10 + 12)/9 = 8 inches.S = sqrt[((4-8)² + 2 x (6-8)² + 3 x (8-8)² + 2 x (10-8)² + (12-8)²)/9] = 2.31 inches.Farm 1 trees' heights have a lower standard deviation than Farm 2 trees' heights, hence they have more uniform trees.
What is the missing information?The problem is missing and is given by the image at the end of the answer.
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A company has three sales departments (local, regional, and national) at each of several locations across the United
States. Each local sales department has 120 employees. The company wants to survey its employees to determine
the most effective sales method.
Which sample should the company use to arrive at the most reliable conclusion?
Answer:
Each local sales department has 120 employees. The company wants to survey its employees to determine the most effective sales method.
Step-by-step explanation:
Answer:
they should used a random sample including the staff members
Step-by-step explanation:
1)
A driver pulls into a gas station to fill up the fuel tank of their car. In order to do that they
pump 5 72 gallons of Regular Unleaded at $3.95/gallon. How much did they spend on their
debit/credit card for gasoline?
Answer:14
Step-by-step explanation:
is the answer or is adding or subtracting or multiply or divide i dont know
ECA is a semi equilateral triangle at C,
where EÂC= 30°
B is point on [AC] such that BC = 2cm
and BE = 3cm.
Calculate AE.
Answer: its 50
Step-by-step explanation:
information for questions 13-18: an insurance company determines that a linear relationship exists between the cost of fire damage in major residential fires and the distance from the house to the nearest fire station. a sample of 20 recent fires in a large suburb of a major city was selected. for each fire, the following variables were recorded: x
We can make predictions about the cost of fire damage based on the distance from the house to the nearest fire station. This information can be useful to insurance companies, fire departments, and homeowners in determining the risk of fire damage and the appropriate level of insurance coverage needed.
In this particular study, the insurance company has determined that a linear relationship exists between the cost of fire damage in major residential fires and the distance from the house to the nearest fire station. The cost of fire damage is the dependent variable, while the distance from the house to the nearest fire station is the independent variable.
For this study, a sample of 20 recent fires in a large suburb of a major city was selected. For each fire, the following variables were recorded:
- the cost of fire damage in thousands of dollars (the dependent variable)
- the distance from the house to the nearest fire station in miles (the independent variable)
It is expected that the cost of fire damage increases as the distance from the house to the nearest fire station increases. This is because, as the distance from the fire station increases, the response time also increases, which can result in more damage being done to the property.
To analyze this data, a linear regression model can be used. The model will help to determine the nature and strength of the relationship between the two variables. The model will generate an equation in the form of y = mx + b, where y is the cost of fire damage, x is the distance from the house to the nearest fire station, m is the slope of the line, and b is the y-intercept.
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You toss a coin and roll a number cube. Find P(heads and an even number.)
Answer:
The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).
The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒
The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒ P(head and an even number)
The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒ P(head and an even number) = P(head) × P(even number)
P(even number)Assuming a fair coin and a fair die:
P(even number)Assuming a fair coin and a fair die:P(head)
P(even number)Assuming a fair coin and a fair die:P(head) =50%
P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number)
P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50%
P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).
P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).P(head and even number)
P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).P(head and even number) =50%×50%=25%
Mabel and her friends went to a movie on Thursday afternoon. They left at 12:10 P.M. It took 30 minutes to drive to the theater. They arrived at the theater 1 hour and 5 minutes before the movie started. Once it started, the movie lasted for 2 hours and 30 minutes. What time was it when the movie ended?
Answer:
4:15
Step-by-step explanation:
12:10+30=12:40
12:40+65=1:45
1:45+ 150= 4:15
Answer:
4:15 PM
Step-by-step explanation:
12:10 PM + :30 Minutes = 12:40 PM (Driving to the theater)
12:40 + 1:05 Minutes = 1:45 PM (Waiting for the movie to start)
1:45 PM + 2:30 Minutes = 4:15 (Watching the movie)
Finished the movie at 4:15 PM exactly.
How punctual!
9. A random variable X is distributed according to X~ N(= 25,0² =9) (a) Determine such M so that P(X < M) = 0.95. (b) Determine the median.
The standard normal distribution has a mean of 0 and a standard deviation of 1. M ≈ 30.935. The median of the distribution is also 25.
(a) To find M, we first need to convert the given values of mean and standard deviation to the standard normal distribution. This can be done by using the formula Z = (X - μ) / σ, where Z is the Z-score, X is the value of interest, μ is the mean, and σ is the standard deviation. In this case, we have X ~ N(25, 9). Substituting the values into the formula, we get Z = (X - 25) / 3. Now we need to find the Z-score that corresponds to the desired probability of 0.95. Using a standard normal distribution table or a calculator, we find that the Z-score corresponding to a cumulative probability of 0.95 is approximately 1.645. Setting Z equal to 1.645, we can solve for X: (X - 25) / 3 = 1.645. Solving for X, we get X ≈ 30.935. Therefore, M ≈ 30.935.
(b) The median is the value that divides the distribution into two equal halves. In a normal distribution, the median is equal to the mean. In this case, the mean is given as 25. Therefore, the median of the distribution is also 25.
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The ratio of yellow marbles to purple marbles was 13 to 4. If there were 102 marbles in the bag, how many were yellow marbles?
The number of yellow marbles based on the given ratio will be 78.
What are the ratio and proportion?The ratio is the division of the two numbers.
For example, a/b, where a will be the numerator and b will be the denominator.
Proportion is the relation of a variable with another. It could be direct or inverse.
Suppose, the number of yellow marbles is Y while purple marbles are P.
As per the given,
The ratio Y/P = 13/4
Total Y + P = 102
(13/4)P + P = 102
13P + 4P = 408
17P = 408
P = 24
And, Y = 102 - 24 = 78
Hence "The number of yellow marbles based on the given ratio will be 78".
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Round 259.98991 to the nearest hundredth.
259.99
259.990
259.9899
260.00001