Answer:
(y−10)(y−2)
Step-by-step explanation:
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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Find the image vertices for a dilation with center (0,0) and a scale factor of 4.
Quadrilateral with vertices at A left parenthesis negative 3 comma 1 right parenthesis, B left parenthesis
4 comma negative 3 right parenthesis, C left parenthesis 2 comma 3 right parenthesis, D left parenthesis
negative 1 comma 4 right parenthesis.
The image vertices for a dilation with center (0,0) and a scale factor of 4 are given as follows:
A'(-12, 4), B'(16, -12), C'(8, 12) and D'(-4,16).
What is a dilation?A dilation can be defined as a transformation that multiplies the distance between every point in an object and a fixed point, called the center of dilation, by a constant factor called the scale factor.
The vertices of the original figure are given as follows:
A(-3,1), B(4,-3), C(2,3) and D(-1, 4).
The scale factor of the dilation is given as follows:
k = 4.
Hence the vertices of the dilated figure are the vertices of the original figure multiplied by 4, as follows:
A'(-12, 4), B'(16, -12), C'(8, 12) and D'(-4,16).
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a delivery truch travels 21 blocks north , 16 blockd east, and 26 blocks south. what is its displacment form the oriringo
Displacement from the origin will be 16.76 block
Pythagoras Theorem:
Pythagoras theorem can be used to find the unknown side of a right-angled triangle.Theorem stats that,
c² = a² + b²
where 'c' is the hypotenuse and 'a' and 'b' are the two legs.
In figure,
O is origin,
First travel 21 block north that means OA = 21 block.
then,
travel 16 block East that means AB = 16 block.
again finally,
travel 26 block South that means BC = 26 block.
Join OC,
OC = 16 block
CD = 5 block
we have to find the value of OD
Apply Pythagoras theorem,
OD² = OC² + CD²
OD = √(OC² + CD²)
OD =√(16² + 5²)
OD =√(256 + 25)
OD = √(256 + 25)
OD = √281 block
OD = 16.76 block
Thus,
Displacement from the origin will be 16.76 block
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An artist is designing a website to showcase his 15-inch-wide paintings. The website will include scaled-down images of the paintings called thumbnails. For ease of viewing and to keep the thumbnail images large enough to show some detail, the artist decides to put three thumbnail images in a row so that any two adjacent images are separated by a space of 40 pixels, as shown in the figure above. If the website is 800 pixels wide, what should be the scaled size (in pixels per inch of painting) of the thumbnails?
The scaled size of the thumbnails is 16 pixels per inch of painting
How to determine the scaled size?The given parameters are:
Width = 15 inchesWebsite = 800 pixelsThe space between adjacent images is 40 inches.
Given that there are two spaces, the remaining space is:
Remaining = 800 - 2 * 40
Remaining = 720
Given that there are three samples of image, the width of each image is:
Image = 720/3
Divide
Image = 240 pixels
The scaled size is then calculated using:
Scale = Image scale width/actual width
This gives
Scale = 240/15
Evaluate
Scale = 16
Hence, the scaled size of the thumbnails is 16 pixels per inch of painting
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5/6 x 3/4 multiplying fractions
SOLUTION:
=) 5/6 × 3/4
=) 5/2 × 1/4
=) 5/8
The product of the fraction is 15/24
Data;
5/63/4Multiplying FractionsTo solve this question, we just have to multiply the fractions together
\(\frac{5}{6} * \frac{3}{4} = \frac{15}{24}\)
All we have to do is multiply the numerator together and denominators together
The product of the fraction is 15/24
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Sydney is considering two jobs. One job pays $45,000 per year. The other job pays a
weekly salary of $950. Which job pays better?
Answer:
The first job pays more
Step-by-step explanation:
950 x 3 = One month pay = 2,850
2,859 x 12 = One year = 34,308 Per Year
Comparing them both
$45,000 One Year, First Job
$34,308 One Year, Second Job
The test scores for the students in Mr. Miller’s math class are shown here.
52, 61, 69, 76, 82, 84, 85, 90, 94
What is the range of the test scores?
The range of the test scores in Mr. Miller's math class is 42.
What is the range?Mathematically, the range refers to the difference between the highest value and the lowest value in a data set.
The range is computed by subtraction of the lowest value from the highest value.
Mr. Miller can use the range to measure the spread or dispersion of the test scores.
Test Scores:
52, 61, 69, 76, 82, 84, 85, 90, 94
Highest score = 94
Lowest score = 52
Range = 42 (94 - 52)
Thus, we can conclude that for the math students in Mr. Miller's class, the range of their test scores is 42.
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The cost of 7 chairs and 2 tables is equal.If the cost of 6 chairs and 5 tables is 10575, find the cost of 12 chairs.
Answer:
5400
Step-by-step explanation:
Let x represent the cost of a chair and y represent the cost of a table. We can use this to set up a system of equations:
7x=2y
6x+5y=10575
We can solve this system using substitution.
Start by rewriting the first equation in terms of x.
\(7x=2y\\\text{Divide both sides by 7}\\x=\frac{2}{7}y\)
Substitute this into the second equation:
\(6(\frac{2}{7}y)+5y=10575\\\frac{12}{7}y+5y+10575\\\frac{12}{7}y+\frac{35}{7}y=10575\\\frac{47}{7}y=10575\)
Multiply both sides by 7
\(47y=74025\)
Divide both sides by 47
\(y=1575\)
This means...
\(7x=2(1575)\\7x=3150\)
Divide both sides by 7
\(x=450\)
One chair costs 450. Now, multiply this number by 12 to find the cost of 12 chairs.
\(450*12=5400\)
12 chairs cost 5400.
Solve each system by graphing y = -3x - 4,y = 1/2 x + 3
Answer:
answer is x=-2, y=2
Step-by-step explanation:
y=-3x-4,
y=1/2x+3
now plug in any points for x for both equations. I will plug in both x as 0.
y=-3(0)-4
y=-4
(0,-4)
y=1/2(0)+3
y=3
(0,3)
We have points now to plot on a graph.
Continue what I did. Maybe plug in 1 for x for both equations.
Hope this helps!
Answer:
x= \(\frac{-8y -6}{7}\)
Step-by-step explanation:
Step 1: Add (-1)/2x to both sides.
−3x − 4y + \(\frac{-1}{2}\) x = \(\frac{1}{2}\) x + \(\frac{-1 }{2}\) x
Step 2: Add 4y to both sides.
\(\frac{-7}{2}\) x - 4y + 4y = 3 + 4y
\(\frac{-7}{2}\) x = 4y + 3
Step 3: Divide both sides by (-7)/2.
\(\frac{-7 }{2}\) x
= 4y+3
\(\frac{-7}{2}\) \(\frac{-7}{2}\)
oranges sell for $0.38 per pound. How much will 192 oranges cost?
$0.38×192=$72.96
So the answer is $72.96
A package of dried fruit weighs 3/4 of a pound. If one serving size is 1/6 of a pound, how many servings would be in the package?
Answer:
0.125
Step-by-step explanation:
3/4 / 1/6
Given: QS bisects ∠TQR; TQ ≅ RQ. Prove: ΔQRS ≅ ΔQTS Triangles Q T S and Q R S are connected at side Q S. Line Q S bisects angle T Q R. The lengths of sides Q T and Q R are congruent. Complete the missing parts of the paragraph proof. Proof: We know that segment QS bisects angle TQR because . By the definition of angle bisector, angle TQS is congruent to angle . We see that segment QS is congruent to segment SQ by . Therefore, we can conclude that triangles QRS and QTS are congruent by .
Answer: it is given, RQS, the reflexive property, and SAS
Step-by-step explanation: just did it
Answer:
We know that segment QS bisects angle TQR because IT IS A GIVEN. By the definition of angle bisector, angle TQS is congruent to angle RQS. We see that segment QS is congruent to segment SQ by the REFLEXIVE PROPERTY. Therefore, we can conclude that triangles QRS and QTS are congruent by SAS.
Step-by-step explanation:
May I have brainliest please? :)
The measure of an angle is 34 greater than its supplement. Find the measure of both angles
Sheldon works in sales and makes a weekly base salary plus a commission based on his sales each week. He earned an extra $120 in commissions from $1,500 in sales last week. Which percent of sales is Sheldon's commission?
Answer:
8%
Step-by-step explanation:
If he earned $120 out of $1500, just do 120/1500 which will give you 0.08 which is 8 percent.
Given the function g(x)=2x and the domain {0, 2, 4), what is the range? {0, 1, 2} {2, 4, 8) {1, 2, 3) {0, 4, 8}
According to the question we get the following outputs For x = 0, g(0) = 0 , For x = 2, g(2) = 4 , For x = 4, g(4) = 8. the range of the function g(x) = 2x, with the given domain {0, 2, 4}, is {0, 4, 8}.
The range of the function g(x) = 2x, with the given domain {0, 2, 4}, can be determined by evaluating the function for each value in the domain.
For x = 0: g(0) = 2(0) = 0
For x = 2: g(2) = 2(2) = 4
For x = 4: g(4) = 2(4) = 8
Therefore, the range of the function is {0, 4, 8}.
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Identify an equation in standard form for an ellipse with its center at the origin, a vertex at (9, 0), and a co-vertex at (0, 1).
The equation in standard form for the given ellipse is: \(\frac{x^2}{81} + {y^2} = 1\) To identify an equation in standard form for an ellipse with its center at the origin, a vertex at (9, 0), and a co-vertex at (0, 1),
we can use the following steps:
Step 1: Determine the values for a and b.
The distance between the center and the vertex is the value of a, which in this case is 9. The distance between the center and the co-vertex is the value of b, which in this case is 1.
Step 2: Use the values of a and b to write the equation in standard form.
The equation for an ellipse with its center at the origin can be written in standard form as:
\(\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\)
Substituting the values of a = 9 and b = 1, the equation becomes:
\(\frac{x^2}{81} + \frac{y^2}{1} = 1\)
Simplifying further, we get:
\(\frac{x^2}{81} + {y^2} = 1\)
Therefore, the equation in standard form for the given ellipse is:
\(\frac{x^2}{81} + {y^2} = 1\)
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The marginal cost function is given by C'(x) = 3x2 + 8x + 4 and the overhead cost is $6. Find the total cost function.
To find the total cost function, we need to integrate the marginal cost function. Since the overhead cost is given as a constant, we can add it after integrating.
C'(x) = 3x^2 + 8x + 4 (marginal cost function)
Integrating with respect to x, we get:
C(x) = ∫(3x^2 + 8x + 4)dx
C(x) = x^3 + 4x^2 + 4x + K (where K is the constant of integration)
To find the value of K, we need to use the information that the overhead cost is $6. When x = 0, the total cost should be equal to the overhead cost.
C(0) = 6
0^3 + 4(0)^2 + 4(0) + K = 6
K = 6
Therefore, the total cost function is:
C(x) = x^3 + 4x^2 + 4x + 6
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What is the equation of the line that has a slope of 4 and passes through the point (3,-10)?
O C y = 4x - 43
O D.y = 4x + 43
O B. y = 4x + 22
O A y = 4x - 22
Answer:
Step-by-step explanation:
it’s ask a freind
Carla attempted 12 free throw shots on a basketball court. She made 9 out of the shots. What is the experimental probability of Carla making a shot?
Answer:
75%
Step-by-step explanation:
9 ÷ 12 = 0.75
0.75 x 100 = 75 = 75%
Answer:
3/4
Step-by-step explanation:
Experimental probability, is the probability determined according to the results of an "experiment" or a trial. In Carla's "experiment", she attempted 12 total shots and made 9 shots. The probability that she made a shot would be 9/12, or 3/4.
In one oty, the cost for water is $8.64 per 100 cubic feet of water. According to a study, the average shower in this city lasts 72 minutes and uses 19.1 gallons. A person showers once a day for a year. Find the total cost per year. Use theconversion factor of 7.48 gallons per cubic footThe total cost per year is $(Simplify your answer. Round to the nearest cent as needed. Do not include the $ symbol in your answer.)Enter your answer in the answer box
What do we know?
100 ft³ of water costs $8.64
The average shower in this city uses 19.1 gallons
A person showers once a day for a year.
7.48 gallons = 1 ft³
Cost per year = ?
Procedure
We first want to know how many gallons are equivalent to 100 ft³
Since 1 ft³ = 7.48 gallons if we multiply by 100 both sides, then
100 ft³ = 748 gallons
Then, 748 gallons of water costs $8.64
Secondly, we are finding how much a single shower costs.
Since the average shower uses 19.1 gallons, we find the cost of 19.1 gallon
We have the equivalences, then we divide both sides:
\(\frac{19.1}{748}=\frac{\text{?}}{8.64}\)then, clearing the unknown quatity
\(\begin{gathered} ?=8.64\cdot\frac{19.1}{748} \\ \text{?}=0.221 \end{gathered}\)Then, the cost of one shower is $0.221
Multiply (3)x(−4)x(2).
Answer:
-24x²
Step-by-step explanation:
remove the parentheses, multiply the numbers, apply exponent rule and add the numbers
just the no. d) Anyone have goosebumps to solve it?
Answer:
which number to solve, it kinda seem difficult
The United States us 17.5 times richer than Kenya: what fraction of this factor is due to differences in capital per person and what fraction is due to differences in TFP
Answer:
The fraction of the factor of 17.5 which is due to differences in capital per person is approximately 4.375, and the fraction due to differences in TFP is approximately 13.125.
Step-by-step explanation:
Based on the given information, we know that one-fourth (1/4) of the differences in per capita GDP across countries are due to differences in capital per person, and three-fourths (3/4) are due to differences in TFP.
Now, let's calculate the fractions for the United States and Kenya, given that the United States is 17.5 times richer than Kenya.
Let's represent the fraction due to differences in capital per person as "f_capital" and the fraction due to differences in TFP as "f_TFP".
Given:
f_capital = 1/4
f_TFP = 3/4
The factor of difference in wealth = 17.5
We need to determine the fractions of this factor of 17.5 that are due to each component.
The fraction due to differences in capital per person (f_capital) can be calculated as:
f_capital = (1/4) / (1/4 + 3/4)
f_capital = (1/4) / (4/4)
f_capital = 1/4
The fraction due to differences in TFP (f_TFP) can be calculated as:
f_TFP = (3/4) / (1/4 + 3/4)
f_TFP = (3/4) / (4/4)
f_TFP = 3/4
Now, to determine the fraction of the factor of 17.5 that is due to each component, we multiply each fraction by the factor:
Fraction due to differences in capital per person = f_capital * factor
= (1/4) * 17.5
= 4.375
Fraction due to differences in TFP = f_TFP * factor
= (3/4) * 17.5
= 13.125
Therefore, the fraction of the factor of 17.5 that is due to differences in capital per person is approximately 4.375, and the fraction due to differences in TFP is approximately 13.125.
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Correct Question:
That about one-fourth of the differences in per capita GDP across countries were due to differences in capital per person and about three-fourths were due to differences in TFP. Carry out this, calculation for Kenya. The United States is 17.5 times richer than Kenya; what fraction of this factor of 175 is due to differences in capital per person and what fraction is due to differences in TFP?
When cooper was 15 years old, he scored an 85 on an iq test. he took the test again when he was 35 years old and scored an 85 again. this indicates that the iq test is highly: __________
Answer:
When cooper was 15 years old, he scored an 85 on an iq test. he took the test again when he was 35 years old and scored an 85 again. this indicates that the iq test is highly: __________
Reliable
Because his scores were so close together the test would be considered as Reliable.
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Simplify: 3.2/0.4 •2• 0.4/0.1
option 1) 64
option 2) 16
option 3) 6.4
option 4) 1.6
Answer:
1
Step-by-step explanation:
3.2/0.4=8
8×2=16
16×0.4=6.4
6.4÷0.1=64
A car was purchased for $20,000. The car depreciates by 27% each year. What is the value of the car when it is 12 years old?
Answer:
Below
Step-by-step explanation:
Losing 27 % of value each year means it retains 73% each year
we need to multiply 20 000 x .73 x .73 x .73 .... .73 (twelve times )
or re-written as 20 000 * .73^12 = value =$ 458.04
What is the domain of the step function f(x) = [2x]- 1?
O {x|x2-1}
O {x|x ≥ 1}
O x x is an integer}
O {x|x is a real number}
Domain: {x | x is a real number}
Option D, "{x | x is a real number}" accurately represents the domain of the function.
The domain of the step function f(x) = [2x] - 1, where [2x] represents the greatest integer less than or equal to 2x, can be determined by considering the restrictions on the input values.
In this case, the step function is defined for all real numbers. However, the greatest integer function imposes a restriction. Since the greatest integer function only outputs integers, the input values (2x) must be such that they produce integer outputs.
For any real number x, the greatest integer less than or equal to 2x will always be an integer. Therefore, the domain of the function f(x) = [2x] - 1 is:
Domain: {x | x is a real number}
Option D, "{x | x is a real number}" accurately represents the domain of the function.
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The value of a car is deprecting at the rate of 12% Find the correct value of car when cost of car was rs 350000
please i need help
Answer:
The cost of the car is $ RS 308,000.
Step-by-step explanation:
Given that the value of a car is deprecting at the rate of 12%, to find the correct value of car when cost of car was $ RS350,000 last year, the following mathematical calculation must be performed:
100 - 12 = 88
88/100 = 0.88
350,000 x 0.88 = X
308,000 = X
Therefore, the cost of the car is $ RS 308,000.
Mr. Kusakye has a wife with six Children and his total income in 2019 was GH¢ 8,500.00. He was allowed the following free of tax Personal - GHC 1200.00 Wife - GH¢ 300.00 each child - GHC 250.00 for a maximum of 4 Dependent relative - 400.00 Insurance - 250.00 The rest was taxed at 10% calculate: his total allowances
(2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i)
Answer:
50+50iStep-by-step explanation:
Given the expression (2 + i)(3 - i)(1 + 2i)(1 - i)(3 + i), we are to take the product of all the complex values. We must note that i² = -1.
Rearranging the expression [(3 - i)(3 + i)] [(2 + i)(1 - i)](1 + 2i)
On expansion
(3 - i)(3 + i)
= 9+3i-3i-i²
= 9-(-1)
= 9+1
(3 - i)(3 + i) = 10
For the expression (2 + i)(1 - i), we have;
(2 + i)(1 - i)
= 2-2i+i-i²
= 2-i+1
= 3-i
Multiplying 3-i with the last expression (1 + 2i)
(2 + i)(1 - i)(1 + 2i)
= (3-i)(1+2i)
= 3+6i-i-2i²
= 3+5i-2(-1)
= 3+5i+2
= 5+5i
Finally, [(3 - i)(3 + i)] [(2 + i)(1 - i)(1 + 2i)]
= 10(5+5i)
= 50+50i
Hence, (3 - i)(3 + i)(2 + i)(1 - i)(1 + 2i) is equivalent to 50+50i
please help!!! find N and M write as simplified rations :D
Answer: n=6, m=12
Step-by-step explanation:
Since the triangle is a 30-60-90 triangle, the ratio of its sides is \(2 : \sqrt{3} : 1\).
Since one side is 6\(\sqrt{3}\), n is 6 and m is 12, according to the ratio.
We can solve this using sin/cos/tan, too.