Factor 12b^2-9b^3
PLEASEEEEE HELP ILL MARK U BRAINLIEST

As per the given confidence interval, the value of P is lees than significant.

Confidence interval:

In statistics, a range around a measurement that conveys how precise the measurement is referred as confidence interval.

Given,

A precision instrument is guaranteed to read accurately to within 2 units. a sample of four instrument readings on the same object yielded the measurements 353, 351, 351, and 355. find a 90% confidence interval for the population variance.

Here we need to find the assumptions of the given situation,

From the given question we have identified the following,

Reading of instruments = 353, 351, 351, and 355.

Confidence interval = 90% = 0.09

Number of units = 2.

Based on these details, the standard deviation of this temple is 0.7.

So, the Z score is the same as the sample mean minus the population mean divided by the standard error, which is 2.857.

Therefore, P value was less than significant.

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Option A. The number of people riding on a bus. Option B. The number of concert tickets sold. Option D. The height of a person from a class of eight.

The random variables that are discrete are A, B, and D. The number of people riding on a bus, the number of concert tickets sold, and the height of a person from a class of eight are all examples of discrete random variables because they can only take on specific, countable values. The life span of a parakeet, on the other hand, is a continuous random variable because it can take on any value within a certain range, and there are an infinite number of possible values.

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Answer:

HEY ITS PROBABLY

Step-by-step explanation:

m<MSP = 120

Answer:

Step-by-step explanation:

Cosine is adjacent over hypotenuse.

So for Angle Z, the adjacent leg is 12 and the hypotenuse leg is 20.

The Cosine ratio is 12/20.

16 is not used and would be the opposite leg to Angle Z

Answer:

Two or more equations that share variables.

Step-by-step explanation:

Example:two equations that share the variables x and y:

x + y = 6

−3x + y = 2

Answer: No

Step-by-step explanation: "Triangle Inequality theorem"

The sum of the two sides of a triangle must be greater than the third side.

2 + 10 = 12 meaning is not greater than the side 12.

\(\tt Step-by-step~explanation:\)

In order to solve this, you should know this: the sum of the two shorter sides of the triangle should be greater than the longest side, or the hypotenuse.

a + b > c

\(\tt Steps:\)

The two smaller values, 10 and 2, could be a and b. 10 + 2 is 12, which is the hypotenuse, so these values cannot make up a triangle.

\(\Large\boxed{\tt Our~final~answer:~No}\)

Answer:

Actually...It's really easy

Step-by-step explanation:

All you have to do is put the numbers in order like this

                422

            x     18

_________________

             7,596

There you go! Hope it helps!

the rate of change of the quantity present at the time when t is 3 is approximately -55.4 grams per year. Therefore, the answer is OA. -55.4 grams per year.

To find the rate of change of the quantity present at the time when t is 3, we need to find the derivative of the function A(t) with respect to t and evaluate it at t = 3.

The given function is A(t) = 750\(e^{(-0.79t)\).

Taking the derivative of A(t) with respect to t, we get:

dA(t)/dt = d/dt [750\(e^{(-0.79t)\)]

To find this derivative, we can use the chain rule. The derivative of \(e^{(-0.79t)\) with respect to t is (-0.79)\(e^{(-0.79t)\).

Applying the chain rule, we have:

dA(t)/dt = (-0.79)(750)\(e^{(-0.79t)\)

Now, we can evaluate the derivative at t = 3:

dA(3)/dt = (-0.79)(750)\(e^{(-0.79(3))\)

Calculating this expression, we find:

dA(3)/dt ≈ -55.4

Rounding to the nearest tenth, the rate of change of the quantity present at the time when t is 3 is approximately -55.4 grams per year.

Therefore, the answer is OA. -55.4 grams per year.

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Complete question is below

Suppose that the amount, in grams, of a radioactive substance present at time t, in years, is given by A(t) = 750 \(e^{( -0.79t)\). Find the rate of change of the quantity present at the time when t is 3. Round to the nearest tenth.

A. -55.4 grams per year

B. 55.4 grams per year

C. -10.6 grams per year

D. 10.6 grams per year

Answer:

25 copies rented

Step-by-step explanation:

r = r1 - 5t, t is time in weeks, r is the number of copies rented, r1 how many people were renting at the start

we know on the 6 weeks passed and 4 copies were rented

4 = r1 - 5(6)

4 = r1 - 30; add 30 on both sides

34 = r1

r = 34 - 5t now plug t = 2 in for this function

r = 34 - 5(2)

r = 35 - 10

r = 25 copies rented

\(f(0) = 2 \cdot 0 - 3 = 0 - 3 = -3\\f(-2) = 2 \cdot (-2) - 3 = -4 - 3 = -7\\f(5) = 2 \cdot 5 - 3 = 10 - 3 = 7\)

The statement is false because the element 2 does not meet the criteria of being an integer greater than 13.

To determine if {2} is an element of the set of integers greater than 13, we need to analyze the statement.

The set of integers greater than 13 can be represented as {x | x ∈ ℤ, x > 13}. This set contains all integers that are greater than 13.

Now, let's check if the element 2 is in this set. Since 2 is not greater than 13, it does not satisfy the condition x > 13. Therefore, {2} is not an element of the set of integers greater than 13.

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Let r be a partial order on set S, and let t be a subset of S. If a and a' are both elements of t, where a is the greatest element and a' is a maximal element, then it can be proven that a = a'.

To prove that a = a', we consider the definitions of greatest and maximal elements. The greatest element in a set is an element that is greater than or equal to all other elements in that set. A maximal element, on the other hand, is an element that is not smaller than any other element in the set, but there may exist other elements that are incomparable to it.

Given that a is the greatest element in t and a' is a maximal element in t, we can conclude that a' is not smaller than any other element in t. Since a is the greatest element, it is greater than or equal to all elements in t, including a'. Therefore, a is not smaller than a'.

Now, to prove that a' is not greater than a, suppose by contradiction that a' is greater than a. Since a' is not smaller than any other element in t, this would imply that a is smaller than a'. However, since a is the greatest element in t, it cannot be smaller than any other element, including a'. This contradicts our assumption that a' is greater than a.

Hence, we have shown that a is not smaller than a' and a' is not greater than a, which implies that a = a'. Therefore, if a is the greatest element and a' is a maximal element in t, then a = a'.

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The answer is yes                                            ....................

Answer:

49 square metres

Step-by-step explanation:

The area of a square is the length of the side times itself.

The area is 7 x 7 = 49

The option (a) 12 ounces of beer (360ml) contain more alcohol

Alcohol content is something that is important to understand, especially if you are of legal drinking age. It can affect your health and your ability to make sound decisions.

First, let's start with 12 ounces of beer. A typical beer has an alcohol content of around 5%, which means that 12 ounces of beer contains 0.6 ounces (18 ml) of alcohol. This is the same as the fourth option.

Next, let's consider 4 ounces of wine. The alcohol content of wine varies depending on the type and brand, but a typical wine has an alcohol content of around 12%. This means that 4 ounces of wine contains 0.48 ounces (14.2 ml) of alcohol.

Finally, we have 1.5 ounces of spirits. The alcohol content of spirits is generally higher than beer and wine, with a typical range of 40-50%. For the sake of this comparison, let's assume the spirits have an alcohol content of 40%. This means that 1.5 ounces of spirits contains 0.6 ounces (18 ml) of alcohol, the same amount as 12 ounces of beer.

So, in summary, 12 ounces of beer and 1.5 ounces of spirits contain the same amount of alcohol, which is 0.6 ounces (18 ml). 4 ounces of wine contains less alcohol, with 0.48 ounces (14.2 ml).

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Decoding Forecast starting at 17:00Z:

Wind:

24014G23KT

Visibility:

5 statute miles

Weather:

Light rain showers

Clouds:

Overcast at 1500 feet

Temporary condition unknown.

The full decoded METAR report is:

Location:

KJAX (Jacksonville International Airport)

Date/Time:

10th at 23:20Z

Wind:

00000KT

Visibility:

More than 6 statute miles

Clouds:

Scattered at 3500 feet

Forecast starting at 11:00Z:

Wind:

00000KT

Visibility:

5 statute miles

Weather:

Mist

Clouds:

Broken at 1000 feet, Broken at 2000 feet

Forecast starting at 06:00Z:

Wind:

16003KT

Visibility:

2 statute miles

Weather:

Mist

Clouds:

Broken at 500 feet, Overcast at 1000 feet

Temporary condition between 08:00Z and 12:00Z:

Visibility:

1 statute mile

Weather:

Mist

Clouds:

Overcast at 300 feet

Forecast starting at 14:00Z:

Wind:

20010G18KT

Visibility:

More than 6 statute miles

Weather:

Showers in vicinity

Clouds:

Broken at 1500 feet, Overcast at 2500 feet

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The solution to the system of linear equations is (x, y) = (-2.25, 1.5).

To solve the system of linear equations using the Gauss-Jordan elimination method, we'll start by writing the augmented matrix of the system:

[ 2   6   | 7 ]

[ -4  6   | 13 ]

Now, we'll apply row operations to transform the augmented matrix into row-echelon form. The goal is to obtain a matrix with 1s in the leading coefficients and zeros below and above them.

Step 1: Swap rows if necessary to bring a non-zero coefficient to the top row.

[ 2   6   | 7 ]

[ -4  6   | 13 ]

Step 2: Perform row operation R2 = R2 + 2R1 to eliminate the coefficient below the leading coefficient in the first row.

[ 2   6   | 7 ]

[ 0   18  | 27 ]

Step 3: Divide the second row by its leading coefficient (18) to obtain a leading coefficient of 1.

[ 2   6   | 7 ]

[ 0   1   | 1.5 ]

Step 4: Perform row operation R1 = R1 - 6R2 to eliminate the coefficient above the leading coefficient in the second row.

[ 2   0   | -4.5 ]

[ 0   1   | 1.5 ]

Step 5: Divide the first row by its leading coefficient (2) to obtain a leading coefficient of 1.

[ 1   0   | -2.25 ]

[ 0   1   | 1.5 ]

The row-echelon form of the augmented matrix is obtained. Now, we'll perform back substitution to find the values of x and y.

From the row-echelon form, we have the following equations:

x = -2.25

y = 1.5

Therefore, the solution to the system of linear equations is (x, y) = (-2.25, 1.5).

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System of Equations

Solve the system

y = 0

x = 7

The solution of this system can be directly expressed as the ordered pair (7,0), but we can also draw the graph for both equations as follows.

The solution of the system is the black dot where both lines intersect, i.e. the point (7,0)

Answer:

The same line.

Step-by-step explanation:

We have to decide whether the lines are perpendicular, neither parallel nor perpendicular, parallel, or the same line. We can check if a line is perpendicular by finding the slope. The line is perpendicular if the slope of one line is the negative reciprocal of the second line.

Let's try to solve for the Y-intercept (where X = 0) of both of these functions.

y + 3x = -4

y + 3(0) = -4

y + 0 = -4

:. y = -4

And now the other one:

y = -3x-4

y = -3(0) - 4

:. y = -4

Since y = -4 in both cases, well, now we have our answer. The answer is it's the same line, so the fourth answer is correct. All the other ones - perpendicular, neither parallel nor perpendicular, and parallel - are incorrect by process of elimination. We don't actually have to keep going from here. But we can (although I won't).

Answer:

74

Step-by-step explanation:

let's say that your number is x

\(x\\\\x+3\\\\\frac{x+3}{7} \\\\=11\)

so we have

\(\frac{x+3}{7}=11\\\\7*\frac{x+3}{7}=11*7\\\\x+3=77\\\\x+3-3=77-3\\\\x=74\)

so your number was 74

The statements with respect to the depreciation of property under MACRS that incorrect is The cost of property to which the MACRS rate is applied is not reduced for estimated salvage value. The correct answer is D.

In MACRS (Modified Accelerated Cost Recovery System), the cost of property is reduced by the estimated salvage value before applying the depreciation rate.

The salvage value represents the estimated value of the property at the end of its useful life, and it is subtracted from the cost of the property to determine the depreciable basis. The depreciation is then calculated based on the depreciable basis using the MACRS rate. The correct answer is D.

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To answer this question, we need to know what absolute value is in the first place. ANSWERS ARE AT THE BOTTOM.

Absolute value represents how far something is from 0 in a number line.

For example, lets take 4.

4 is 4 units away from 0 on the number line, so the absolute value of 4 is 4.

Now lets look at another example, -4. -4 is also 4 units away from 0, just in the other direction. However, when calculating absolute value, we do not care about the direction. Therfore, the absolute value of -4 is also 4.

Now let's look at your problem.

You want the absolute value of 0 and -4/5

Following the same principle above about the distance from 0, here are your answers:

Absolute value of 0: 0

Absolute value of -4/5: 4/5

The equation of the function is −3<x<1. See the explanation below.

Given the graph of function f is a parabola,

Thus, equation of parabola  is y=(x+3)(x+1)

⇒y=x² +4x+3

⇒y−3+2²

= x²+2× x ×2+2²

⇒y+1=(x+2)²

We can rewrite this as

 (x+2)² =4× (1/4) ×(y+1)

Comparing the above equation to the equation of a parabola, (x−h)² =4a(y−k), where (h,k) is the coordinates of vertex of parabola, we have,

(h,k)≡(−2,−1)

Hence, the x coordinate of the vertex is −2 which lies in the interval −3<x<1

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Answer:

\(\sqrt{59}\)

Step-by-step explanation:

7^2 is 49 and 8^2 is 64, which means the square root of any number between 49 and 64 (exclusive) will be in between 7 and 8, and it's also going to be irrational, because it's not a perfect square.

One number between 49 and 64 is 59, so \(\sqrt{59}\) is an irrational number between 7 and 8

Answer

P=14.95c+39.99v

Answer = $124.83

Step-by-step exp

P = 14.95 ( 3 ) + 39.99 ( 2 )

P = 44.85 + 79.98

P = 124.83

So the the total cost of 3 CD's and 2 video games is $ 124.83

The expression the represents c CDs and v video games cost is 14.95c+39.99v.

Given that, the cost of a new CD is $14.95, and the cost of a video game is $39.99.

An expression is a combination of terms that are combined by using mathematical operations such as subtraction, addition, multiplication, and division.

Cost of c CDs and v video games is

14.95c+39.99v

Therefore, the expression the represents c CDs and v video games cost is 14.95c+39.99v.

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The graph of 3x-2y≤6 is the third graph, for 3x-2y<6 is the first graph, for 3x-2y>6 is the fourth graph and for 3x-2y≥6 is the second graph. The solution has been obtained using concept of linear inequality.

What is linear inequality?

A linear inequality is one that would produce a linear equation if the equals relation were used instead of the inequality. When multiplying or dividing both sides by a negative number in order to solve the inequality, the direction of the inequality is reversed. The entire set of solutions to an inequality is known as the solution set.

We are given for graphs, of which two graphs are dotted and two are simple straight line graphs.

The dotted graphs are drawn for the inequalities having < or >

Whereas the simple straight line graphs are drawn for the inequalities having ≤ or ≥.

Now, to notice the shaded pattern, we will see whether the equations are true for (0,0) or not

1. 3x-2y≤6

⇒ 0≤6

So, the equation is true for the point.

Hence, the third graph represents this equation.

2. 3x-2y<6

⇒ 0<6

So, the equation is true for the point.

Hence, the first graph represents this equation.

3. 3x-2y>6

⇒ 0>6

So, the equation is false for the point.

Hence, the fourth graph represents this equation.

4. 3x-2y≥6

⇒ 0≥6

So, the equation is false for the point.

Hence, the second graph represents this equation.

Hence, the graphs are matched with the inequalities.

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Since, there are multiple questions so, the question answered above is attached below.

Answer: if this doesn't help u let me know and i can explain more have a good day <3

x=−4 and y=3

Step-by-step explanation:

Step: Solvey=5x+23for y:

y=5x+23

Step: Substitute5x+23foryin−2x−y=5:

−2x−y=5

−2x−(5x+23)=5

−7x−23=5(Simplify both sides of the equation)

−7x−23+23=5+23(Add 23 to both sides)

−7x=28

−7x/−7=28/−7

(Divide both sides by -7)

x=−4

Step: Substitute−4 for x in y=5x+23:

y=5x+23

y=(5)(−4)+23

y=3(Simplify both sides of the equation)

Answer:

x=−4 and y=3

Answer:

\(v(t) = 2t - 5\)

Step-by-step explanation:

Given

\(s(t) = t^2 - 5t + 1\)

Required

The speed of the particle

To do this, we simply differentiate the position function

i.e.

\(v(t) = s'(t)\)

So, we have:

\(s(t) = t^2 - 5t + 1\)

Differentiate

\(s'(t) = 2t - 5 + 0\)

\(s'(t) = 2t - 5\)

So, the speed function is:

\(v(t) = 2t - 5\)