Form tolerances regulate the "form" of features and are frequently used as a size refinement, thus they do not need a datum reference.
Describe what you mean by a substance.The substance(s) from which a thing is created or composed: A long-lasting substance is stone. something that is utilized or created as crude or raw material: Paper is created using wood pulp as the main ingredient. any component component. a kind of cloth used to make dresses.
What kind of material is it?Metals, polymers, and ceramics have historically been the three main kinds of materials. Steel, fabric, and ceramics are a few examples. Typically, the sources, traits, and uses of these classes are very diverse.
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Somebody, please help me with these by April 6 I'm about to fail my class
1. Describe specific heat capacity and its use in calorimetry.
2. Define latent heat and how it is different than specific heat capacity.
3. Describe how a phase diagram changes when changing from a solid to a liquid.
4. Describe how work is done is related to a change in the volume of a fluid.
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5. What is the relationship of change in internal energy, work, and heat? Explain the significance in terms of energy.
6. As succinctly as possible, explain why it is impossible to have an engine that is 100% efficient.
7. Describe the application of Archimedes principle in everyday terms.
Practice
8. 50 grams of a substance increases its temperature by 10 degrees when 100 J of heat is added. What is the specific heat capacity of the substance?
9. Ten kilograms of a substance has a latent heat of 1000 J/kg. How much energy does it take to change the phase of this substance?
—Continue on the next page—
10. The work done by a piston is measured to be 1000 J. If the pressure is a constant 1000 Pa, what is the change in volume of the piston?
11. Is the process described in #10 isovolumetric? Explain.
12. Is it possible for a substance to change the temperature in an isovolumetric and adiabatic process? Explain.
13. A substance is heated with 1000 J and does 700 J of work on the atmosphere. What is the change in the internal energy of the substance?
14. An engine causes a car to move 10 meters with a force of 100 N. The engine produces 10,000 J of energy. What is the efficiency of this engine?
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15. If a ball of radius 0.1 m is suspended in water, density = 997 kg/m^3, what is the volume of water displaced and the buoyant force?
16. A 10 kg ball of volume = 0.005 m3 is set on a lake. Describe what will happen to the ball.
Application
A group of physics students heats a vial of water, which has a balloon at the top that traps the water vapor and air.
17. Describe how much the internal energy is changed if the students are adding heat to the water via a Bunsen burner. No need to calculate anything.
18. If 50 grams of water start to boil, then how much heat must be added to completely boil off the water? The latent heat of vaporization is 2,260,000 J/kg
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19. Assume this process is 10% efficient, how much work is done by the gas expanding into the atmosphere?
20. Assuming the atmospheric pressure to be constant at 101,325 Pa, by what amount does the volume of the balloon change?
Answer:
im sorry i would help but thats too much
Exercise II: A ball (C) of small dimensions of mass m=2kg is launched from A without initial speed, the force of friction exerted on (C) between A and B is f-IN. Take g=10m/s. (C) 0-30° B a) Applying Newton's second law between A and B, determine the nature of motion and the value of AB such that V 3m/s. b) Between B and C the force of friction fexerted on (C) is supposed to be constant. Determine its value such that Vc=2m/s and BC-2.5m. GOODWORK C
A) The nature of motion is decelerating motion and the value of AB = 5m. B) Between B and C the force of friction fexerted on 2.5m and the force of friction exerted on (C) between B and C is 17.6N
(a) Applying Newton's second law between A and B, determine the nature of motion and the value of AB such that V=3m/s.
From A to B, the ball experiences a force of friction and the gravitational force acting downwards. The force of friction opposes the motion of the ball, while the gravitational force acts in the direction of motion.
Since the ball is launched from A without any initial speed, it will initially move downwards due to the force of gravity until it reaches its lowest point at B. To determine the value of AB such that V=3m/s, we can use the conservation of energy principle.
The potential energy at A is zero, and the kinetic energy at B is (1/2)mv^2, where m is the mass of the ball and v is the velocity at B. The work done by the force of friction is fABd, where d is the distance from A to B. The work done by the gravitational force is -mg(h/2), where h is the height difference between A and B. Thus, we have (1/2)mv^2 = fABd - mg(h/2).
Since the ball is moving upwards at B, the net force acting on it is in the upward direction. Using Newton's second law, we have fAB - mg = ma, where a is the acceleration of the ball. Since the ball is moving upwards, a = -g. Solving these equations simultaneously, we obtain AB = 5m and the nature of motion is a decelerating motion.
(b) Between B and C, the force of friction f exerted on (C) is supposed to be constant. Determine its value such that Vc=2m/s and BC=2.5m.
Between B and C, the ball moves upwards due to the force of friction and the gravitational force acting downwards. To determine the force of friction f, we can use the conservation of energy principle again. The potential energy at B is mgh/2, where h is the height difference between A and B.
The kinetic energy at C is (1/2)mv^2, where v is the velocity at C. The work done by the force of friction is fBCd, where d is the distance from B to C. Thus, we have (1/2)mv^2 = fBCd + mgh/2. Using Newton's second law, we have fBC - mg = ma, where a is the acceleration of the ball. Since the ball is moving upwards, a = -g. Solving these equations simultaneously and substituting the given values, we obtain f = 17.6N. Therefore, the force of friction exerted on (C) between B and C is 17.6N.
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PLEASE HELP ME
Of the listed activities, which does NOT use rhythmic patterns of movement in a team setting?
1.100 m dash
2.couple’s figure skating
3.football
4.synchronized swimming
Answer:
football
Explanation:
it is played on zig-zay way/form
Answer:
2.couple’s figure skating
Explanation:
couple’s figure skating
The best way to prepare for a workout is to stretch key muscles first and follow the stretching with a jog to get the blood flowing to the muscles.
Explanation:
stretching out and daily exercise
Answer:
false
Explanation:
If you pick a mass of 14.4 kg from the ground up to 1.26 m above the ground and it takes 1.10 s to do so, how much power is expended?
We will determine the power as follows:
We know that work is force times distance and power is work over time, so we will have that:
\(\begin{gathered} P=\frac{(14.4kg)(9.8m/s^2)(1.26m)}{1.10s}\Rightarrow P=161.6465455...W \\ \Rightarrow P\approx161.65W \end{gathered}\)So, the power is approximately 161.65 Watts.
24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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478 J of work must be done to compress a gas to half its initial volume at constant temperature. How much work must be done to compress the gas by a factor of 12.0, starting from its initial volume?
I was thinking of using PV = W formula. Like
478 = P(V/2)
956 = PV
W = P(V/12)
12W/V = P
956 = (12W/V)(V)
956 = 12W
W = 79.66667 J
is this correct? could someone please help?
Answer:
Explanation:
I don't think so. Think about it. To compress the volume by a factor of 2 it takes 956 Joules.
Now you come along and you want to get the pressure for 1/12 of the volume. It's going to take a huge pressure to do that.
I would suggest that you have to use a modified form of the formula.
PV = 956
You need to compress the volume by 1/6
P(V/6) = 956
6 * PV/6 = 6 * 956
PV = 5736 J
Why did I only take 1/6? Because. 956 represents the pressure needed for 1/2 the volume. You need to multiply 1/2 * 1/6 to get 1/12
Difference between balanced and unbalanced force
Which model below describes the processes of Gamma radiation?
A
B.
C.
D.
Answer:
C
Explanation:
The graph below shows the heating curve for a substance as it changes from solid to gas.
a. Answer the questions in the table below.
The melting point of the substance in the heating curve is 20°C.
1) The melting point of the substance is the temperature at the point where, the substance is having a phase change from solid state to liquid. So, the temperature at point B, 20°C is its melting point.
2) The boiling point of the substance is the temperature at the point where, the substance is having a phase change from liquid state to gaseous state. So, the temperature at point D, 90°C is its boiling point.
3) The point A is where the substance is at solid state.
4) The substance is at liquid state at the point C.
5) The substance is at gaseous state at the point E.
6) At point B, solid state is changing to liquid state.
7) At point D, liquid state is changing to gaseous state.
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A simple pendulum of length 5.5 m makes 10.0 complete swings in 25 s what is the acceleration due to gravity at the location of the pendulum ?
Answer:
The acceleration due to gravity at the location of the pendulum is 34.74 m/s².
Explanation:
Given that,
The length of a simple pendulum, l = 5.5 m
It makes 10.0 complete swings in 25 s.
Frequency of pendulum,
\(f=\dfrac{10}{25}\\\\f=0.4\ Hz\)
The time period of a simple pendulum is given by :
\(T=2\pi \sqrt{\dfrac{l}{g}}\)
Frequency,
\(f=\dfrac{1}{T}\\\\f=\dfrac{1}{2\pi \sqrt{\dfrac{l}{g}} }\\\\f=\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}}\)
g is the acceleration due to gravity at the location where the pendulum is placed. So,
\(f^2=\dfrac{g}{4\pi^2l}\\\\g=f^2\times 4\pi^2l\\\\g=0.4^2\times 4\pi^2\times 5.5\\\\g=34.74\ m/s^2\)
So, the acceleration due to gravity at the location of the pendulum is 34.74 m/s².
PLZ help asap :-/
............................
Explanation:
[16]\(\underline{\boxed{\large{\bf{Option \; A!! }}}} \)
Here,
\(\rm { R_1} \) = 2Ω\(\rm { R_2} \) = 2Ω\(\rm { R_3} \) = 2Ω\(\rm { R_4} \) = 2ΩWe have to find the equivalent resistance of the circuit.
Here, \(\rm { R_1} \) and \(\rm { R_2} \) are connected in series, so their combined resistance will be given by,
\(\longrightarrow \rm { R_{(1,2)} = R_1 + R_2} \\ \)
\(\longrightarrow \rm { R_{(1,2)} = (2 + 2) \; Omega} \\ \)
\(\longrightarrow \rm { R_{(1,2)} = 4 \; Omega} \\ \)
Now, the combined resistance of \(\rm { R_1} \) and \(\rm { R_2} \) is connected in parallel combination with \(\rm { R_3} \), so their combined resistance will be given by,
\(\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \dfrac{1}{R_{(1,2)}} + \dfrac{1}{R_3} } \\ \)
\(\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{1}{4} + \dfrac{1}{2} \Bigg ) \;\Omega} \\ \)
\(\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{1 + 2}{4} \Bigg ) \;\Omega} \\ \)
\(\longrightarrow \rm {\dfrac{1}{ R_{(1,2,3)}} = \Bigg ( \dfrac{3}{4} \Bigg ) \;\Omega} \\ \)
Reciprocating both sides,
\(\longrightarrow \rm {R_{(1,2,3)}= \dfrac{4}{3} \;\Omega} \\ \)
Now, the combined resistance of \(\rm { R_1} \), \(\rm { R_2} \) and \(\rm { R_3} \) is connected in series combination with \(\rm { R_4} \). So, equivalent resistance will be given by,
\(\longrightarrow \rm {R_{(1,2,3,4)}= R_{(1,2,3)} + R_4} \\ \)
\(\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{4}{3} + 2 \Bigg ) \; \Omega} \\ \)
\(\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{4 + 6}{3} \Bigg ) \; \Omega} \\ \)
\(\longrightarrow \rm {R_{(1,2,3,4)}= \Bigg ( \dfrac{10}{3} \Bigg ) \; \Omega} \\ \)
\(\longrightarrow \bf {R_{(1,2,3,4)}= 3.33 \; \Omega} \\ \)
Henceforth, Option A is correct.
_________________________________[17]\(\underline{\boxed{\large{\bf{Option \; B!! }}}} \)
Here, we have to find the amount of flow of current in the circuit. By using ohm's law,
\( \longrightarrow \) V = IR
\( \longrightarrow \) 3 = I × 3.33
\( \longrightarrow \) 3 ÷ 3.33 = I
\( \longrightarrow \) 0.90 Ampere = I
Henceforth, Option B is correct.
____________________________\( \tt \purple{Hope \; it \; helps \; you, Army! \heartsuit } \\ \)
Ajani is trying to experimentally measure Planck's constant h. He does this by shining different wavelengths of monochro- matic (i.e., single-wavelength) EM radiation on a metal plate with unknown work function W, and then measuring the stop- ping voltage required to bring the ejected electrons to a halt. When he uses λ1= 400 nm, he finds that a stopping voltage of V1 = 0.7 V is required. When he uses λ2 = 500 nm, he finds that a stopping voltage of V2= 0.2 V is required. Based on these two data points, what is Ajani's measurement of Planck's constant?
Answer:
h = 1.01 x 10⁻³⁴ J.s
Explanation:
The energy applied by the voltage must be equal to the energy associated with the wavelength of light:
\(eV = \frac{hc}{\lambda}\\\)
where,
e = charge on electron = 1.6 x 10⁻¹⁹ C
V = stopping potential
h = Planck's Constant = ?
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of light
For λ = 400 nm = 4 x 10⁻⁷ m, V = 0.7 V:
\((1.6\ x\ 10^{-19}\ C)(0.7\ V) = \frac{h(3\ x\ 10^8\ m/s)}{4\ x\ 10^{-7}\ m}\\\)
h = 1.49 x 10⁻³⁴ J.s
For λ = 500 nm = 5 x 10⁻⁷ m, V = 0.2 V:
\((1.6\ x\ 10^{-19}\ C)(0.2\ V) = \frac{h(3\ x\ 10^8\ m/s)}{5\ x\ 10^{-7}\ m}\\\)
h = 0.53 x 10⁻³⁴ J.s
Taking average of both values:
\(h = \frac{(0.53+1.49)\ x\ 10^{-19}\ J.s}{2}\)
h = 1.01 x 10⁻³⁴ J.s
PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant?
Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
A sample of vegetable oil with density 913 kg/m3 is found to have a mass of 0.0365 kg. Find the volume of this sample
The volume of the vegetable oil is 0.00003998 m³.
The density of vegetable oil,
ρ = 913 kg/m³
The mass of vegetable oil,
m = 0.0365 kg
To find: The volume of the vegetable oil, V Solution: The density of any substance is defined as the mass of the substance per unit volume.
The formula for density is:
ρ = m/V
where, ρ is the density of the substancem is the mass of the substance V is the volume of the substance We can rearrange the above formula to find the volume of the substance:
V = m/ρSubstituting the given values of mass and density in the above formula,
We get:
V = 0.0365 kg / 913 kg/m³ = 0.00003998 m³ (approx)
Therefore, the volume of the vegetable oil is approximately 0.00003998 m³.
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A(n)_____ planet is composed of rocky material, has no rings, and is closer to the sun.
Answer:
A terrestrial planet.
Explanation:
Terrestrial planets (Inner planets) are closer to the sun then outer planets. No inner planet has rings and they are all composed of rocky material.
A terrestrial planet planet is composed of rocky material, has no rings, and is closer to the sun.
What is terrestrial planet?Terrestrial planets are Earth-like planets having a hard surface consisting of rocks or metals. A molten heavy-metal core, few moons, and topographical features like valleys, volcanoes, and craters are also characteristics of terrestrial planets.
Mercury, Venus, Earth, and Mars are the four terrestrial planets in our solar system, and they also happen to be the four nearest to the sun.
There may have been more terrestrial planetoids during the solar system's formation, but they either combined or were obliterated.
The planets are not entirely terrestrial. Gas giants, also referred to as Jovian planets, include Jupiter, Saturn, Uranus, and Neptune in our solar system.
Hence, a terrestrial planet planet is composed of rocky material, has no rings, and is closer to the sun.
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A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2
. Calculate
the length of this wire required to make a 10 Ω coil.
Answer:
the length of the wire is 134.62 m.
Explanation:
Given;
resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm
cross-sectional area of the wire, A = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²
resistance of the wire, R = 10Ω
The length of the wire is calculated as follows;
\(R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m\)
Therefore, the length of the wire is 134.62 m.
A person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a
height of 52 m and it lands a distance of 35 m from the base of the cliff. What is the speed at
which the rock was initially kicked?
The time will be the same for both horizontal and vertical component. The initial speed is 10.7 m/s
What is Speed ?Speed is a distance travel per time taken. It is a scalar quantity and it is measured in m/s
Given that a person standing at the edge of a seaside cliff kicks a rock horizontally of the cliff from a height of 52 m and it lands a distance of 35 m from the base of the cliff.
The rock will move vertically downward with initial velocity = 0. The time taken will be constant. That is, same horizontally.
Let us first calculate the time by using the formula
h = ut + 1/2gt²
Where
h = 52 mu = 0Range R = 35 mg = 9.8 m/s²Substitute all the necessary parameters into the formula
52 = 0 + 1/2 × 9.8 × t²
52 = 4.9t²
t² = 52/4.9
t² = 10.6
t = √10.6
t = 3.26 s
The speed at which the rock was initially kicked can be found by
R = Ut
35 = U × 3.26
U = 35/3.26
U = 10.7 m/s
Therefore, rock was initially kicked at a speed of 10.7 m/s
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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The block A and attached rod have a combined mass of 50 kg and are confined to move along the guide under the action of the 796-N applied force. The uniform horizontal rod has a mass of 15 kg and is welded to the block at B. Friction in the guide is negligible.
Required:
Compute the bending moment M exerted by the weld on the rod at B. The bending moment is positive if counterclockwise, negative if clockwise.
Answer:
The bending moment is 459.16 N.m
Explanation:
From the given information;
Let's assume that the angle is 66°
Then, the free body diagram is draw and attached in the file below.
Now, the calculation of the acceleration from the first part of the free body diagram is:
\(\sum F_x = ma_x \\ \\ 796 - 50(9.81) sin 66=50a \\ \\ 796 - 448.094 = 50 a \\ \\ a = \dfrac{347.906}{50} \\ \\ a = 6.96 \ m/s^2\)
Bending moment M:
From the second part of the diagram:
\(\sum M_B = mad \\ \\ M - (15 \times 9.81) (1.5) = (25 \times 6.96)(1.5 sin 66) \\ \\ M - 220.725 = 238.435 \\ \\ M = 238.435 + 220.725 \\ \\ \mathbf{M = 459.16 \ N.m}\)
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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Name:.
Date:
Homework: Writing an Argument About
Australia's Skin Cancer Rate
G
4
You now have enough evidence to explain why Australia's skin cancer rate is so high. Review your
argument from Chapter 2 and think about how you will convince the AHA that both Claim 2 and
Claim 3 are accurate. You will use your completed Reasoning Tool from Activity 3 to revise and add to
your argument.
Question: Why is the skin cancer rate in Australia so high?
If an object weighs 2500 n on earth what is the weight of the object on a planet half the mass of the Earth and 6 times the radius?
Answer: 7327 n
Explanation: Simple
During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ± 0.001) kg with a speed of (3.2 ± 0.01) ms-1. The second trolley is moving away with a distance of (2.5 ± 0.01) ms-1.
What is the absolute uncertainty of the ratio of momentum of the two trolleys X/Y?
Answer:
P = 1 (14,045 ± 0.03 ) k gm/s
Explanation:
In this exercise we are asked about the uncertainty of the momentum of the two carriages
Δ (Pₓ / Py) =?
Let's start by finding the momentum of each vehicle
car X
Pₓ = m vₓ
Pₓ = 2.34 2.5
Pₓ = 5.85 kg m
car Y
Py = 2,561 3.2
Py = 8,195 kgm
How do we calculate the absolute uncertainty at the two moments?
ΔPₓ = m Δv + v Δm
ΔPₓ = 2.34 0.01 + 2.561 0.01
ΔPₓ = 0.05 kg m
Δ\(P_{y}\) = m Δv + v Δm
ΔP_{y} = 2,561 0.01+ 3.2 0.001
ΔP_{y} = 0.03 kg m
now we have the uncertainty of each moment
P = Pₓ / \(P_{y}\)
ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²
ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²
ΔP = 0.006 + 0.0026
ΔP = 0.009 kg m
The result is
P = 14,045 ± 0.039 = (14,045 ± 0.03 ) k gm/s
1. What is the heat energy when 114.32g of water ( c = 4.18 J/g °C) at 14.85°C is raised to
18.00°C?
Select the correct answer.
Which statement is true for a series circuit?
• A.
The voltage is the same
across all resistors in the circuit.
O B. As more resistors are added, the current will increase.
O C. The average of the voltage drops will be the total voltage in the circuit.
O D.
The current is the same across all resistors in the circuit.
O E.
The equivalent resistance will be less than the
resistance of each individual resistor.
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Answer:
D. The current is the same across all resistors in the circuit.
Explanation:
In a series circuit, all circuit elements are connected so that there is exactly one current path. That path goes through each of the elements of the circuit.
The current is the same through all resistors in a series circuit.
Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Answer:
Which feature is created when a block of rock dropped down in relation to the block of rock beside it?
Explanation:
Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.
given the height, in meters, of an object above the ground, for (seconds), what are the units of the average rate of change of the object on the interval . (assume the ball has not hit the ground before time .)
It is important to note that the average rate of change is a scalar quantity.
How will you explain that.The average rate of change is a measure of how quickly an object's height is changing over a certain period of time. To calculate the average rate of change, you need to know the height of the object at two different times, t1 and t2, and the difference between those two heights (change in height) and the difference between those two times (change in time).
The formula for average rate of change is: (change in height)/(change in time).
The units for the average rate of change are determined by the units of the change in height and the change in time. Since the height is given in meters and the time is given in seconds, the units of the average rate of change would be in meters per second (m/s). This means that for every second, the object's height is changing by a certain number of meters. It' is important to note that the average rate of change is a scalar quantity, it doesn't give information about direction of motion.
Learn more about Scalar Quantity here
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What direction do all planets rotate BUT Venus?
Answer:
Southernpole
Explanation:
Answer:
Venus' rotation and orbit are unusual in several ways. Venus is one of just two planets that rotate from east to west. Only Venus and Uranus have this "backwards" rotation. It completes one rotation in 243 Earth days — the longest day of any planet in our solar system, even longer than a whole year on Venus.
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