1 point
Does the following equation represent a proportional relationship?
y=2x-2
the equation y = 2x - 2 represents a linear relationship but not a proportional relationship.No, the equation y = 2x - 2 does not represent a proportional relationship.
A proportional relationship is a type of linear relationship where the ratio of the dependent variable (y) to the independent variable (x) remains constant. This means that if we increase or decrease x by a certain factor, the value of y will also increase or decrease by that same factor.
In the equation y = 2x - 2, the coefficient of x is 2, which means that as x increases by 1, y will increase by 2. However, the constant term of -2 means that the relationship is not proportional. If we plug in x = 0, we get y = -2, which is not on the same line as the other points.
Therefore, the equation y = 2x - 2 represents a linear relationship but not a porportional relationship.
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Can someone pleas Help me with this I don't get it. And Thank you o much if you helped me.
Answer: 20=96 40=192 60=288
Step-by-step explanation:
Answer:
20 shirts cost 96.00
40 shirts cost 192.00
60 shirts cost 288.00
Step-by-step explanation:
Multiply 4.80( per shirt) with the amount of shirts you have
Plz brainly
write the taylor series for f(x)=exf(x)=ex about x=2x=2 as ∑n=0[infinity]cn(x−2)n.
The Taylor series for f(x)=ex about x=2 is given by ∑n=0[infinity]cn(x−2)n where cn = fⁿ(2)/n! = e²/2! e²/3! ... e²/n!.
The Taylor series is a way to represent a function as an infinite sum of terms that involve the function's derivatives evaluated at a specific point.
In this case, we want to find the Taylor series for f(x)=ex about x=2. To do this, we first need to find the derivatives of f(x) at x=2.
We have fⁿ(x) = ex for all n, so fⁿ(2) = e² for all n. We can then use this to find the coefficients cn in the Taylor series.
We have cn = fⁿ(2)/n! = e²/2! e²/3! ... e²/n!.
We can then substitute these coefficients into the Taylor series to get ∑n=0[infinity]cn(x−2)n = ∑n=0[infinity] e²/2! e²/3! ... e²/n!(x−2)n, which is the Taylor series for f(x)=ex about x=2.
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Brandon bought a pair of sneakers for $55
that had a regular price of $90.
Answer:
brandon paid $35 more than retail value.
Answer:
Dirty 5 more than retail value
help please
h - (-2) ≥ 10
Answer:
answer
Step-by-step explanation:
h+2 ≥ 10
h ≥ 10 - 2
h ≥ 8
Which property is used in the problem below?
2(x+4)= 2x+8
O the associative property
O the commutative property
O the distributive property
O the additive identity property
Answer:
Your Answer is C
Answer:
C. the distributive property
Step-by-step explanation:
took the unit test on edge
MARKING BRAINIEST!!!
Answer:
y=-0.5ˣ
Step-by-step explanation:
each time the x-value is increased by one, the y-value is cut in half compared to the previous point
Answer:
y=-0.5ˣ
Step-by-step explanation:
each time the x-value is increased by one, the y-value is cut in half compared to the previous
A factory can make 3 x 104 t-shirts in one day.How many t-shirts will it make in 2.5 x 102 days?
7.5 × 10 ^6
hope it helps!
cansomeone explain radical expressions for math plz
Answer:
A radical expression in algebra is an expression that has a radical, or root. These are inverse operations to exponents.
Step-by-step explanation: That is
Solve for x.
8.7 +X = 7
1.1
X = [?]
Answer:
X = 1.7
Step-by-step explanation:
To solve for x, you can subtract 8.7 from both sides of the equation.
8.7 + X = 7
-8.7 -8.7
X = -1.7
So X = -1.7
\(8.7+x=7\)
Rearrange:
\(x+8.7=7\)
Subtract 8.7 from both sides:
\(x+8.7-8.7=7-8.7\)
\(\fbox{x = -1.7}\)
Jim drove 715miles in 11 hours.
At the same rate, how many miles would he drive in 9
hours?
585 miles per 9 hours
Step-by-step explanation:
715miles per 11 hours
/11 to determine miles per hour
65 miles per 1 hour
× 9 to determine miles per 9 hours
585 miles per 9 hours
Bradley cut a square hole out of a block of wood in wood shop. If the block was cube-shaped with side lengths of 11 inches, and the hole had side lengths of 5 inches, how much wood was left after the hole was cut out?
Note: Figure is not drawn to scale.
A.
1,206 cubic inches
B.
1,331 cubic inches
C.
1,056 cubic inches
D.
96 cubic inches
The volume of the cube-shaped = 1,331 volume of the hole cut out of the block = 125 cubic inches Subtract 1331 - 125 = 1206, the correct option is A
volume of the hole cut out of the block = 5 inches x 5 inches x 5 inches
volume of the hole cut out of the block = 125 cubic inches.
volume of the cube-shaped block = 11 inches x 11 inches x 11 inches
volume of the cube-shaped block = 1,331
To find the volume of the wood remaining after the hole is cut out, we can subtract the volume of the hole from the volume of the block:
1,331 cubic inches - 125 cubic inches = 1,206 cubic inches
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Water flows through a pipe at a rate of 5 fluid ounces per minute. Express this rate of flow in gallons per hour. Round your answer to the nearest hundredth. help!!!
Answer:
2.34 gallons per hour
Step-by-step explanation
5 fluid ounces = 0.0390625 gallons
60 min = 1 hour
0.0390625 x 60min = 2.34 gallons per hour
2x+y=3
Зу = 18 -6x
On a graph please
Please help!
Write the sum, and then write an equivalent expression by collecting like terms and removing parentheses whenever possible.
Answer:
The opposite of -10·t and t - 10·t is t
Step-by-step explanation:
1) The opposite of 4·x and -5 + 4·x is given as follows;
-4·x + (-5 + 4·x) = -4·x -5 + 4·x = -4·x + 4·x - 5 = 0 - 5 = -5
2) The opposite of -10·t and t - 10·t is given as follows;
-(-10·t) + (t - 10·t) = 10·t + t - 10·t = 10·t - 10·t + t = 0 + t = t
3) The opposite of (-7 - 4·v) and -4·v is given as follows;
-(-7 - 4·v) + (-4·v) = -1 × (-7 - 4·v) - 4·v = 7 + 4·v - 4·v = 7 + 0 = 7
Write the point slope form of the equation of the line that passes through the point (2, 1) with m = 4.
y+2= 4(x+1)
y-1 = 4(x-2)
A company produces and sells homemade candles and accessories. Their customers commonly order a large candle and a matching candle stand. The weights of these candles have a mean of 500 g and a standard deviation of 15 g. The weights of the candle stands have a mean of 200 g and a standard deviation of 8 g. Both distributions are approximately normal. Let T the total weight of a randomly selected candle and a randomly selected stand, and assume that the two weights are independent. = If the total weight T of the two items exceeds 717 g, the company has to pay for additional shipping. Find the probability that the total weight exceeds 717 g. You may round your answer to two decimal places. P(T> 717) ≈
The probability that the total weight exceeds 717 g is 0.1587. Therefore, the correct answer is:P(T > 717) ≈ 0.16.
A company produces and sells homemade candles and accessories.
Their customers commonly order a large candle and a matching candle stand.
The weights of these candles have a mean of 500 g and a standard deviation of 15 g.
The weights of the candle stands have a mean of 200 g and a standard deviation of 8 g. Both distributions are approximately normal. We need to find the probability that the total weight exceeds 717 g.
The total weight of the candle and the stand, T = Wc + Wswhere Wc is the weight of the candle and Ws is the weight of the stand.Now, we need to find the mean and variance of T.
Mean of T, μT = μc + μs = 500 + 200 = 700 g
Variance of T, σ\(T^2\) = σ\(c^2\) + σ\(s^2\)
= \(15^2\)+ \(8^2\) = 289 \(g^2\)
The standard deviation of T, σT = √289 = 17 gNow, we need to find the probability that the total weight exceeds 717 g. Mathematically, P(T > 717) = P(Z > (717 - 700) / 17) = P(Z > 1)
The probability that Z is greater than 1 can be found using a standard normal table or calculator.
The value of P(Z > 1) is 0.1587 approximately.
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Can some one help me with this question its hard :( down below ill give brainliest
Answer: The answer would be C
Step-by-step explanation:
You want to divide. 15/3= 5 and then a^3 is basically being divided by 1 so your completed answer would be 5a^3
What is the equation of the line that passes through the point (-4, 2) and has a
slope of 1/4?
Answer: The equation of the line is y=1/4x + 3
Step-by-step explanation:
To get the equation, you have to set it up:
y=1/4x + b
Plug in the coordinates (-4, 2) next:
2=1/4(-4) + b
Solve:
2= -1 + b
add one on both sides:
3= b
Use the information to get the equation:
y=1/4x + 3
I hope this helps!!
Answer:
dfjhbgvdsasdfgf
Step-by-step explanation:
Answer choices: | Please help!
50 cm; 42 cm2
50 cm; 54 cm2
34 cm; 54 cm2
34 cm; 42 cm2
The perimeter and area of the given composite figure are:
Area = 50 cm²
Perimeter = 42 cm
How to find the area of the composite figure?To find the total surface area of the composite figure, we will find the area of each individual surfaces and then add them together.
Formula for area of a triangle is:
Area = ¹/₂ * base * height
Formula for area of a rectangle is:
Area = Length * Width
Thus:
T.S.A = 2(¹/₂ * 4 * 5) + (10 * 3)
T.S.A = 20 + 30
T.S.A = 50 cm²
The perimeter will be the sum of the entire boundary length. Thus:
Perimeter = 3 + 10 + 10 + 3 + 3 + 3 + 5 + 5
Perimeter = 42 cm
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Can anyone become my math tutor please?
4x + 2x − 7 = 3x − 7
Answer:
3x=0 or x=0
Step-by-step explanation:
4x+2x-7=3x-7
4x+2x=3x
6x=3x
6x-3x=0
what is x/4 - 3 = 8
Answer
x = 44
Step-by-step explanation:
\(\frac{x}{4} -3=8\\\frac{x}{4}-3+3=8+3\\\frac{x}{4}=11\\\frac{x}{4} *4=11*4\\\)
x=44
hope it's helpful
THANK YOU.
For the linear regression y = ẞ1 + ẞ2x + e, assuming that the sum of squared errors (SSE) takes the following form:
SSE = 382 +681 +382 + 18ẞ1ẞ2
Derive the partial derivatives of SSE with respect to B1 and B2 and solve the optimal values of these parameters.
a. B₁ = B1
b. B₂ =
The optimal values of these parameters are:
a. β₁ = 0
b. β₂ = 0
The linear regression y = β1 + β2x + e, assuming that the sum of squared errors (SSE) takes the following form:
SSE = 382 + 681 + 382 + 18β1β2
Derive the partial derivatives of SSE with respect to β1 and β2 and solve the optimal values of these parameters.
Given that SSE = 382 + 681 + 382 + 18β1β2 ∂SSE/∂β1 = 0 ∂SSE/∂β2 = 0
Now, we need to find the partial derivative of SSE with respect to β1.
∂SSE/∂β1 = 0 + 0 + 0 + 18β2 ⇒ 18β2 = 0 ⇒ β2 = 0
Therefore, we obtain the optimal value of β2 as 0.
Now, we need to find the partial derivative of SSE with respect to β2. ∂SSE/∂β2 = 0 + 0 + 0 + 18β1 ⇒ 18β1 = 0 ⇒ β1 = 0
Therefore, we obtain the optimal value of β1 as 0. Hence, the partial derivative of SSE with respect to β1 is 18β2 and the partial derivative of SSE with respect to β2 is 18β1.
Thus, the optimal values of β1 and β2 are 0 and 0, respectively.
Therefore, the answers are: a. β₁ = 0 b. β₂ = 0
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Someone please help?
Answer:
I think it's C the third answer choice
Step-by-step explanation:
ABCE is a trapezium
AD is parallel to BC
DE = 4cm
Area of ABCE = 60cm^2
Area of ABCD = 48cm^2
Work out the values of f and g
The values of f and g that has been worked out is given as 6 and 8
How to solve the trapeziumThis is a question that would examine the combination of two shapes into one.
We have area of a triangle = base * height / 2
this would give
f * 4 / 2 = 60 - 48
2f = 12
divide through by 2
f = 12 / 2
f = 6
we have f * g = 48
given that the value of f = 6
g * 6 = 48
6g = 48
Divide through by 6 to get the value of f
6 g / 6 = 48 / 6
g = 8
Hence the value of f is given as 6 and the value of g is given as 8
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the yellow cab company charges a flat fee of $3.50 and an additional $2.50 per mile. the relaxicab company charge $2.30 per mile and a $4.54 fee. at how many miles do the two companies charege the same amount? write a system of equations that computes the cost of the cabs. use for the miles, and for the cost.
Step-by-step explanation:
Since the initial fee is fixed, we can assume it is a constant and the succeeding mile fee is the variable as it changes for every mile covered.
Let x = distance (mile)
let y = total charge (dollars)
Yellowcab company equation for cost calculation; 3.50 + 2.5x = y
laxicab company equation for cost calculation; 4.54+2.3x = z
the two companies charge the same amount when y = z
; 3.50 + 2.5x = 4.54+2.3x
x = 5.2 miles
COST CALCULATION
;3.50 + 2.5x = ?
if x = 5.2;
; 3.50 + 2.5(5.2) =$16.50
OR
; 4.54+2.3x = ?
; 4.54 + 2.3(5.2) = $16.50
if 0 < 0 < pi/2, as 0 increases, the value of cos0 and the value of sin0
As the angle increases from 0 to π/2, the value of sine increases, and the value of cosine decreases.
Trigonometry is a branch of mathematics that deals with the relationships between angles and sides of triangles.
Let us first understand the concept of sine and cosine. In a right-angled triangle, the sine of an angle is defined as the ratio of the length of the side opposite to the angle and the length of the hypotenuse. Similarly, the cosine of an angle is defined as the ratio of the length of the adjacent side and the length of the hypotenuse.
As the angle θ increases from 0 to π/2, the length of the opposite side (the numerator in sine) of the triangle increases, and the length of the hypotenuse (the denominator in sine) remains the same. Therefore, the value of sine increases as θ increases.
On the other hand, as the angle θ increases from 0 to π/2, the length of the adjacent side (the numerator in cosine) decreases and the length of the hypotenuse (the denominator in cosine) remains the same. Therefore, the value of cosine decreases as θ increases.
This behavior is consistent with the fact that sine is an increasing function, while cosine is a decreasing function within this range of angles.
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Complete Question:
If 0< θ <π/2, as Theta increases, the value of
cos(θ) [Decreases/Increases/Remains The Same]
and the value of sin(θ) [Decreases/Increases Remains The Same]
PLEASE HELP ASAP!!!!!!!!!!!!
Ari mixed 2 1/4
cups of red grapes with 1/2 cups of green grapes. He then divided the grapes into bags with 3/4 cup of mixed grapes in each. How many bags of grapes will Ari have?
Answer:
3
Step-by-step explanation:
Pls help and explain because I don’t really understand
9514 1404 393
Answer:
see attached
Step-by-step explanation:
When a transversal line crosses parallel lines, it creates 8 angles. If the transversal crosses at right angles, every one of those angles is a right angle.
If the transversal does not cross at right angles, it creates 4 acute angles and 4 obtuse angles. The acute and obtuse angles are supplementary to each other, since they form linear pairs.
All of the acute angles are congruent, as are all of the obtuse angles. [this is the simplicity of it — only true if the lines are parallel]
__
Different pairs of angles have names. Angles on opposite sides of a point of intersection are "vertical" angles. Angles between the parallel lines are "interior" angles, and those outside are "exterior" angles. Angles on the same side of the transversal are called "same-side" or "consecutive" angles. Angles on opposite sides of the transversal are called "alternate" angles.
Angles in the same direction from the points of intersection (upper-left, for example) are called "corresponding" angles.
__
Angle relationships are often described in the terms described above. For example, every pair of "corresponding angles" is congruent, as are "alternate interior" or "alternate exterior" angles. In any geometry (not just one like this), "vertical angles" are congruent.
_____
You are given the measure of angle 4 (122°). This tells you every obtuse angle in the figure is 122°, and every acute angle in the figure is 180°-122° = 58°. All you need to do to find the angle measures is identify the angle as acute or obtuse.
For justification, you may be expected to determine the relationship of the requested angle to angle 4.
7. ∠8 — part of linear pair; supplementary to ∠4
8. ∠5 — alternate exterior; congruent to ∠4
9. ∠2 — corresponding; congruent to ∠4
10. ∠1 — consecutive exterior; supplementary to ∠4
11. ∠6 — vertical to ∠1*, so the same measure as ∠1
12. ∠7 — vertical to ∠4; congruent to ∠4
__
* angles 1 and 4 have no named relationship. angle 2 is corresponding to angle 4, and angle 5 is alternate exterior with respect to angle 4. Each of those is supplementary to angle 6, so angle 6 is supplementary to angle 4.
The Transportation Security Administration (TSA) is responsible for airport security. On some flights, TSA officers randomly select passengers for an extra security check before boarding. One such flight has 76 passengers (12 in first class and 64 in coach). TSA officers selected an SRS of 10 passengers for screening. Let p-hat be the proportion of first class passengers in this sample. So, assuming that you are checking for the probability of choosing a first class passenger out of all passengers on the flight. Is the 10% condition met in this case? Justify your answer. (POS 447#31)
- Yes, 10 passengers out of 76 is less than 10% of the population of the flight.
- yes, 10 passengers out of all passengers on all flights is less than 10% of the population
- No, 10 passengers is the population being studied and is not less than 10% of the 10 total
- No, 10 passengers out of 76 is more than 10% of the population of the flight.