Explain why your PE and KE are usually not both high at the same time (If PE is high then usually KE is low)

1. Gas particles move randomly and rapidly in all directions and collide with each other and the walls of the container, creating pressure, 2. Liquids and solids have more ordered and restricted motion compared to gases, 3. Solids have fixed positions, liquids can move around each other, and gases move rapidly in all directions, and 4. The phase diagram shows the relationships between the states of matter at different temperatures and pressures and is important for predicting the behavior of substances and optimizing chemical reactions.

A phase diagram is a graph that shows the relationships between the different states of matter of a substance at different temperatures and pressures, providing information on the behavior of the substance under different conditions. It is an essential tool in understanding the behavior of materials in various conditions and in designing chemical processes that operate efficiently under different conditions.

1. Gas Properties simulation allows you to observe the behavior of gas particles. When you put a little gas into the box using the pump, you can see that the gas particles move randomly and rapidly in all directions. They collide with each other and with the walls of the box, creating pressure. When you pump in some lighter particles, such as helium, you can observe that they move faster and more chaotically than the heavier particles. They also bounce off the walls of the box more easily than the heavier particles. Changing the temperature of the gas affects the behavior of the particles. When the temperature increases, the particles move faster and collide more frequently, creating a higher pressure. When the temperature decreases, the particles move slower and collide less frequently, creating a lower pressure.

Based on the observations, a gas can be described as a state of matter in which the particles are widely spaced, move rapidly and randomly in all directions, and are not held together by any significant forces. The gas particles have a large amount of kinetic energy and exhibit rapid motion.

2. States of Matter simulation allows you to see how well liquids and solids match the description of gas particles. When you compare the behavior of gas particles to that of liquids and solids, you can see that liquids and solids have much more ordered and restricted motion than gases. In liquids, the particles are close together and move more slowly, while in solids, the particles are tightly packed and vibrate in fixed positions.

3. The motion of particles in solids, liquids, and gases can be explained using diagrams. In a solid, the particles are packed closely together in a regular pattern and vibrate in fixed positions. In a liquid, the particles are also close together but are not in a fixed pattern and can move around each other. In a gas, the particles are widely spaced and move rapidly in all directions. To create a diagram, you can use circles to represent the particles and arrows to show their motion.

The similarities between the three states of matter include the fact that the particles that make up each state are constantly in motion. The differences lie in the level of motion and the degree of freedom of the particles. Solids have the least amount of freedom, followed by liquids, and gases have the most freedom. Liquids and solids have definite shapes and volumes, while gases have neither definite shape nor definite volume.

4. The phase diagram is a graph that shows the relationships between the different states of matter at different temperatures and pressures. It is important in structure analysis and chemical reaction as it provides information on the behavior of substances at different temperatures and pressures. The phase diagram can help to predict the behavior of a substance under different conditions and can be used to identify the different phases that exist at different points. The phase diagram is also used in industrial processes to optimize chemical reactions and to design chemical processes that operate efficiently under different conditions. Understanding the phase diagram is essential in chemistry and materials science as it provides insight into the behavior of materials under various conditions.

Therefore, 1. Pressure is created when gas particles collide with one another and the container walls while moving randomly and quickly in all directions, 2. Compared to gases, the motion of liquids and solids is more controlled and ordered 3. While liquids can move around one another and gases move quickly in all directions, solids have fixed positions, and 4. The phase diagram is crucial for predicting the behavior of substances and optimizing chemical reactions because it depicts the relationships between the states of matter at various temperatures and pressures.

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Answer:

See below.

Explanation:

Here using F = ma , we need to derive the fire and second equation of motion.

\(\displaystyle \longrightarrow F = ma \dots(i) \)

As we know that the rate of change of velocity is called acceleration. Therefore,

\(\displaystyle \longrightarrow F = m\dfrac{dv}{dt} \)

From equation (i) we have,

\(\displaystyle \longrightarrow ma = m\dfrac{dv}{dt} \)

If the mass is constant,

\(\displaystyle \longrightarrow a =\dfrac{dv}{dt}\\ \)

\(\displaystyle \longrightarrow dv = a.dt \)

On integrating both sides,

\(\displaystyle \longrightarrow \int dv = \int a .dt \)

LHS will be integrated from v₀ to v and RHS will be integrated from 0 to t , as ;

\(\displaystyle \longrightarrow\int^v_{v_0} dv =\int^t_0 a .dt \)

Here a is constant , so ;

\(\displaystyle \longrightarrow v|^v_{v_0}= a \int^t_0 dt\\\)

\(\displaystyle \longrightarrow v - v_0= a(t-0)\)

Adding v₀ both sides,

\(\displaystyle \longrightarrow

\underline{\underline{ v =v_0+at}} \)

Hence we have derived the First equation of motion.

For second , as we know that ,

\(\displaystyle \longrightarrow v =\dfrac{dx}{dt}\\ \)

\(\displaystyle \longrightarrow dx = v.dt \)

Integrating both sides, we have;

\(\displaystyle \longrightarrow \int dx =\int v.dt\\\)

Putting the limits,

\(\displaystyle \longrightarrow \int^x_{x_0} dx =\int_0^t v.dt \)

From first equation,

\(\displaystyle \longrightarrow x|^x_{x_0}= \int^t_0 ( v_0+at).dt \)

Distribute ,

\(\displaystyle \longrightarrow x - x_0= \int^t_0 v_0dt +\int^t_0 at.dt\\ \)

\(\displaystyle \longrightarrow x-x_0= v_0(t-0)+a\bigg[\dfrac{t^2}{2}\bigg]^t_0\\\)

Simplify,

\(\displaystyle \longrightarrow \underline{\underline{ x-x_0= v_0t +\dfrac{1}{2}at^2}}\)

Therefore we have derived the second equation of motion.

And we are done!

The rolling disk's initial angular momentum is mR√[2(gR + v²)]/2

Using the law of conservation of energy, the initial mechanical energy E of the disk equals its final mechanical energy E' as it climbs the step.

So, E = E'

1/2Iω + 1/2mv² + mgh = 1/2Iω' + 1/2mv'² + mgh'

where I = rotational inertia of disk = 1/2mR² where m = mass of disk and R = radius of disk, ω = initial angular speed of disk, v = initial velocity of disk, h = initial height of disk = 0 m, ω' = final angular speed of disk = 0 rad/s (assumung it stops at the top of the step), v' = final velocity of disk = 0 m/s (assumung it stops at the top of the step), and h' = final height of disk = R/2.

Substituting the values of the variables into the equation, we have

1/2Iω² + 1/2mv² + mgh = 1/2Iω'² + 1/2mv'² + mgh'

1/2(1/2mR² )ω² + 1/2mv² + mg(0) = 1/2I(0)² + 1/2m(0)² + mgR/2

mR²ω²/4 + 1/2mv² + 0 = 0 + 0 + mgR/2

mR²ω²/4 + 1/2mv² = mgR/2

R²ω²/4 = gR/2 + 1/2v²

R²ω²/4 = (gR + v²)/2

ω² = 2(gR + v²)/R²

ω² = √[2(gR + v²)/R²]

ω = √[2(gR + v²)]/R

Since angular momentum L = Iω, the rolling disk's initial angular momentum is

L = 1/2mR² ×√[2(gR + v²)]/R

L = mR√[2(gR + v²)]/2

the rolling disk's initial angular momentum is mR√[2(gR + v²)]/2

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(a) The position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

(b) The size of the image is 1.8.

The position of the coin placed next to the convex side of a thin spherical glass shell is calculated as follows;

1/d = 1/f - 1/d'

where;

Focal length = r/2 = 17 cm / 2 = 8.5 cm

1/d = 1/8.5 - (-1/6.5)

1/d = 1/8.5 + 1/6.5

1/d = 0.1176 + 0.1538

1/d = 0.2714

d = 1/0.2714

d = 3.68 cm

Magnification, M = d'/d

M = (6.5)/(3.68)

M = 1.8

Thus, the position of the coin placed next to the convex side of a thin spherical glass shell is 3.68 cm.

The size of the image is 1.8.

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Answer:

c- Time

Explanation:

The time will tell depending on the person who is exercising, the rate of time, the  workout time. & limits on weights....

Answer:

The guy above me is wrong the real answer is D

Explanation:

Answer:

According to different sources Edwin Hubble observed red light of galaxies directly proportional to the distance of the galaxy from earth.

I hope it helps and follow me for more good answer♥️♥️

We can calculate the time taken by the compass to hit the ground by using kinematic equations of motion. The motion of the compass is a free-fall motion since it is only under the influence of gravity. When the compass is dropped, it is initially at rest.

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Answer:

Law of independent assortment

Explanation:

This is because law of independent assortment state that alleles of two or more genes when two organisms mate will be inherited or pass down to gametes which are in one way or the other independent of each other or each of the alleles. Therefore parent can have up to three different traits and the alleles can be inherited by the gametes.

Answer:

three different traits

Explanation:

just because it is.

Answer:

The y-value  is  z = 0.759 m

Explanation:

From the question we are told that

     The position of the first y-axis is  \(y_1 = 0.300 \ m\)

     The current on the first wire is  \(I_ 1 = 26.0 \ A\)

      The force per unit length on each wire is  \(\frac{F}{l} = 295 \mu N/m = 295 * 10^{-6} \ N/m\)

Generally the force per unit length on first wire is mathematically represented as

                \(\frac{F}{l} = \frac{\mu_o * I_1 * I_2 }{2*\pi* y_1}\)

Where  \(\mu _o\) is the permeability of free space with value  \(\mu_o = 4\pi * 10^{-7} N/A^2\)

    substituting values

                    \(295 *10^{-6} = \frac{ 4\pi * 10^{-7} * 26.0 * I_2 }{2 *3.142* 0.300}\)

                \(I_2 = \frac{295 *10^{-6 } * 0.300 * 2* 3.142 }{ 4\pi * 10^{-7} * 26 }\)

                 \(I_2 = 17.0 \ A\)

Now the at the point where the magnetic field is zero the magnetic field of each wire are equal , let that point by z meters from the second wire on the y-axis  so

             \(\frac{\mu_o I_2}{2 * \pi * y_1} = \frac{\mu_o I_1}{2 * \pi * (y_1-z)}\)

          \(I_2 (y_1 - z) = I_1 * y_1\)

substituting values

         \(17.0 ( 0.300 - z) = 26 * 0.300\)

         z = 0.759 m

Answer:

\(22.84\ \text{N}\)

Explanation:

\(\rho\) = Density = \(7800\ \text{kg/m}^3\)

h = Length of rod = 95 cm

d = Diameter of rod = 2 cm

r = Radius = \(\dfrac{d}{2}=1\ \text{cm}\)

g = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)

V = Volume of rod = \(\pi r^2h\)

Mass is given by

\(m=V\rho\)

Weight is given by

\(w=mg=V\rho g\\\Rightarrow w=\pi r^2h\rho g\\\Rightarrow w=\pi\times (1\times 10^{-2})^2\times (95\times 10^{-2})\times 7800\times 9.81\\\Rightarrow w=22.84\ \text{N}\)

The weight of the rod is \(22.84\ \text{N}\).

The magnitude of the acceleration experienced by Purley is -1749.82 m/s²

We'll begin by converting 173 Km/h to m/s. This can be obtained as follow:

3.6 Km/h = 1 m/s

Therefore,

173 Km/h = (173 Km/h × 1 m/s) / 3.6 Km/h

173 Km/h = 48.06 m/s

The following data were obtained from the question:

The acceleration can be obtained as follow:

v² = u² + 2as

0² = 48.06² + (2 × a × 0.66)

0 = 2309.7636 + 1.32a

Collect like terms

1.32a = 0 - 2309.7636

1.32a = -2309.7636

Divide both sides by 1.32

a = -2309.7636 / 1.32

a = -1749.82 m/s²

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Answer:

It seems like c or d I'll say c

Answer:

I believe the answer to be D, search for more evidence. You have to gather evidence while it's still fresh

The kinetic energy of the book after it is slids a distance of 2 meters will be 10 Joules.

The work-energy theorem states that "the work done on an object is the change in its kinetic energy".

Hence;

Kinetic energy = work done

Note that: work-done is expressed as:

Work done = f × d

Where f is force applied and d is distance traveled.

Given that:

Force applied f = 5 newton

Distance d = 2 meters

Work done = ?

Plug these values into the above formula and solve for the workdone.

Work done = f × d

Work done = 5N × 2m

Work done = 10Nm

Work done = 10 Joules

Therefore, the kinetic energy is 10 Joules.

Option B) 10 J is the correct answer.

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Answer:

(a) T = 2987.6 k

(b) T = 19986.2 k

Explanation:

The temperature of a star in terms of peak wavelength can be given by Wein's Displacement Law, which is as follows:

\(T = \frac{0.2898\ x\ 10^{-2}\ m.k}{\lambda_{max}}\)

where,

T = Radiated surface temperature

\(\lambda_{max}\) = peak wavelength

(a)

here,

\(\lambda_{max}\) = 970 nm = 9.7 x 10⁻⁷ m

Therefore,

\(T = \frac{0.2898\ x\ 10^{-2}\ m.k}{9.7\ x\ 10^{-7}\ m}\)

T = 2987.6 k

(b)

here,

\(\lambda_{max}\) = 145 nm = 1.45 x 10⁻⁷ m

Therefore,

\(T = \frac{0.2898\ x\ 10^{-2}\ m.k}{1.45\ x\ 10^{-7}\ m}\)

T = 19986.2 k

Consider,

\({:\implies \quad \displaystyle \sf \langle p\rangle =m\langle v(t)\rangle=m\int_{-\infty}^{\infty}x\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial t}\Psi (x,t)+\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial t}\bigg\}dx}\)

Multiply both sides by ih and simplification will yield

\({:\implies \quad \displaystyle \sf ih\langle p\rangle =m\int_{-\infty}^{\infty}x\bigg[\Psi (x,t)\bigg\{\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi^{*}(x,t)}{\partial x^2}-V(x)\Psi^{*}(x,t)\bigg\}+\Psi^{*}(x,t)\bigg\{V(x)\Psi (x,t)-\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}\bigg\}\bigg]dx}\)

Some simplification, Then Integrate by parts and then knowing the fact that the wave function vanishes for \({\bf x\to \pm \infty}\) will yield:

\({:\implies \quad \displaystyle \sf \langle p\rangle =\dfrac{ih}{2}\int_{-\infty}^{\infty}\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial x}\Psi (x,t)-\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}\bigg\}dx}\)

Integrating by parts and knowing the same fact by some simplification will yield:

\({:\implies \quad \displaystyle \sf \langle p\rangle =-ih\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}dx}\)

The momentum is thus contained within the wave function, so we can then deduce that:

\({:\implies \quad \sf p\rightarrow -ih\dfrac{\partial}{\partial x}}\)

\({:\implies \quad \sf p^{n}\rightarrow \bigg(-ih\dfrac{\partial}{\partial x}\bigg)^{n}}\)

\({:\implies \therefore \quad \displaystyle \sf \langle p^{2}\rangle =-h^{2}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}\)

Now the kinetic energy

\({:\implies \quad \displaystyle \sf \langle K\rangle =\dfrac{\langle p^{2}\rangle}{2m}=\dfrac{-h^2}{2m}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}\)

The classical formula for the total energy

\({:\implies \quad \sf \dfrac{p^2}{2m}+V(x)=E}\)

Multiplying this equation by \({\sf \Psi (x,t)=\psi (x)exp\bigg(\dfrac{-iEt}{h}\bigg)}\) and use the above equations and simplify it we will be having

\({:\implies \quad \boxed{\bf{\dfrac{-h^2}{2m}\dfrac{d^{2}\psi (x)}{dx^{2}}+V(x)\psi (x)=E\psi (x)}}}\)

This is the Famous Time-Independent Schrödinger wave equation

Note:- If I write all the explanation then the Answer box willn't allow me to submit the answer

As a result, the cannon's post explosion velocity is -0.68 m/s, which indicates that it is moving backwards at a rate of 0.68 m/s.

y(t)=−12gt2+sin(θ)stx(t)=cos(θ)st. Thus, the ball's range, or the value of x when y=0, is the horizontal distance it travels before contacting the ground.

Utilizing momentum conservation, we can find a solution to this issue. Prior to the explosion, the system's (cannon and ball) momentum is:

p_before = (m_cannon + m_ball) * v_before

Following the explosion, the system's momentum is:

p_after = m_cannon * v_cannon + m_ball * v_ball

Because momentum is conserved, we can state:

p_before = p_after

Substituting the expressions for p_before and p_after, we get:

(m_cannon + m_ball) * v_before = m_cannon * v_cannon + m_ball * v_ball

Now, we can solve for v_cannon:

v_cannon = (m_cannon + m_ball) / m_cannon * v_before - m_ball / m_cannon * v_ball

Substituting the given values, we get:

v_cannon = (3.5 + 0.52) / 3.5 * 1.27 - 0.52 / 3.5 * 75

v_cannon = -0.68 m/s

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Answer:

2.57 seconds  (rounded to 2.6 Seconds)

Step-by-step explanation:

Great question, it is always good to ask away and get rid of any doubts that you may be having.

Before we can solve this question we need to create a formula that calculates the final speed. The formula will be the following,

Where:

Vf is the final Velocity

Vi is the initial velocity

A is the acceleration

t is the time in seconds

Now that we have the formula we can plug in the values given to us in the question and solve for the amount of time (t).

Finally, we can see that it would take the cyclist 2.57 seconds (approximately) to reach a speed of 18 m/s

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

Answer:

.7934\(m/s^{2}\)

Explanation:

Acceleration = change in velocity / change in time

A = 10.98\(m/s\) / 13.84\(s\)

A = .7934\(m/s^{2}\)

Answer:0.8 m/s^2

Explanation:

initial velocity(u)=18.54m/s

Final velocity(v)=29.52m/s

Time(t)=13.84 sec

Acceleration =(v-u)/t

acceleration =(29.52-18.54)/13.84

Acceleration =10.98/13.34

Acceleration=0.8 m/s^2

Answer:

920000

Explanation:

Each kg contains 1,000 grams

Answer:

Explanation:

It is not very likely that the total amount of water at Earth’s surface has changed significantly over geologic time. Based on the ages of meteorites, Earth is thought to be 4.6 billion years old. The oldest rocks known are 3.9 billion to 4.0 billion years old, and these rocks, though altered by post-depositional processes, show signs of having been deposited in an environment containing water. There is no direct evidence for water for the period between 4.6 billion and 3.9–4.0 billion years ago. Thus, ideas concerning the early history of the hydrosphere are closely linked to theories about the origin of Earth.

Earth is thought to have accreted from a cloud of particles around the Sun. This gaseous matter condensed into small particles that coalesced to form a protoplanet, which in turn grew by the gravitational attraction of more particulates. Some of these particles had compositions similar to that of carbonaceous chondrite meteorites, which may contain up to 20 percent water. Heating of this initially cool, unsorted conglomerate by the decay of radioactive elements and the conversion of kinetic and potential energy to heat resulted in the development of Earth’s liquid iron core and the gross internal zonation of the planet (i.e., differentiation into core, mantle, and crust). It has been concluded that Earth’s core formed over a period of about 500 million years. It is likely that core formation resulted in the escape of an original primitive atmosphere and its replacement by one derived from the loss of volatile substances from the planetary interior (see evolution of the atmosphere).

The equivalent resistance between the point A and B is 0.95 ohm.

Define resistance ?

Resistance means the degree to which a substance or device opposes the passage of an electric current, causing energy dissipation. It is measured in ohms, symbolized by the Greek letter omega (Ω). Resistance is also defined as the opposition offered by a body or substance to the passage through it of a steady electric current.

What is meant by ohms law?

Ohm's law is a formula used to calculate the relationship between voltage, current and resistance in an electrical circuit. It states that the current through a conductor between two points is directly proportional to the voltage across the two points. The law is named after Georg Simon Ohm, a German physicist who discovered it,

Solving for R3, R4, and R5 since they are in parallel formation. Their equivalent resistance could be

                           1 / R = (1 /R3) + (1 / R4) + (1 / R6)

                                   = (1 / 4.4) + (1 / 3.5) + (1 / 6.6)

                           1 / R = 0.79

                                R = 1.43 ohm.

Next solving R6 and leg of this resistance which are in series connection,

                                 r = R + R6

                                   = 1.43 + 7.1)

                                 r = 8.53 ohm.

Finally the three resistance R1, R2 and the leg resistance which are in parallel connection,

                             1 / r = (1 / 1.9) + (1 / 2.5) + (1 / 8.53)

                                    = 1.04 ohm

Equivalent resistance R eq = 1 / 1.04 = 0.95 ohm.

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Circular disc's moment of inertia around axis passing through mass and parallel to disc Icm=MR22

The phrase "moment of inertia" in physics refers to the precise calculation of a body's inertia with respect to rotation, or the resistance a body exhibits when a torque is applied to alter its rate of rotation around an axis (turning force).

It is a broad (additive) property: the moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. Because it resists rotational motion, the moment of inertia is referred to as such and not as a moment of force.

Moment of inertia is the propensity of an object to continue rotating at a constant speed or in a condition of rest. More torque is needed to shift this state the higher the moment of inertia.

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Answer:

Kepler's first law of planetary motion states that planets orbit the Sun in elliptical orbits, with the Sun located at one focus (option b)

Explanation:

Kepler's laws or laws of planetary motion are scientific laws that describe the movement of the planets around the Sun. The fundamental contribution of Kepler's laws was to show that the orbits of the planets are elliptical and not circular as was previously believed.

Kepler's laws are kinetic laws. This means that its function is to describe the planetary motion.

Kepler formulated three laws:

An ellipse is a closed curve that has two symmetrical axes, called foci or fixed points. In simpler words, an ellipse can be described as a flattened circle.

The degree of flattening of a closed curve is called eccentricity. When the eccentricity is equal to 0, the curve forms a perfect circle. On the other hand, when the eccentricity is greater than 0, the sides of the curve are flattened to form an ellipse.

Kepler's first law of planetary motion states that planets orbit the Sun in elliptical orbits, with the Sun located at one focus (option b)

The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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Answer:

All planets including the outer larger planets were formed at the same time somewhere around 4.5 Billion years ago.

Explanation:

the young sun drove away most of the gas from the inner solar system, leaving behind the rocky cores also known as the terrestrial planets.

We have that the Time  is mathematically given as

t=0.33h

From the question we are told

Generally the equation for the Time   is mathematically given as

\(t=\frac{d}{va+vb}\\\\Therefore\\\\t=\frac{12}{30+6}\)

t=0.33h

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Answer:

6.75×10³⁰ N.

Explanation:

Applying Newron's Law of universal gravitation.

From the question,

F = Gm₁m₂/r²................................................................. Equation 1

Where F = Gravitational force between the sun and Neptune, m₁ = mass of Neptune, m₂ = mass of the sun, r = distance bewteen the sun and Neptune, G = gravitational constant.

Given: m₁ = 1.99×10⁴⁰ kg, m₂ = 1.03×10²⁶ kg, r = 4.50×10¹² m

Constant: G = 6.67×10⁻¹¹ Nm²kg⁻².

Substitute these values into equation 1

F = [(6.67×10⁻¹¹)( 1.99×10⁴⁰)(1.03×10²⁶)]/(4.50×10¹²)²

F = (13.67×10⁴⁰⁺²⁶⁻¹¹)/(20.25×10²⁴)

F = (13.67×10⁵⁵)/(20.25×10²⁴)

F = 0.675×10⁵⁵⁻²⁴

F = 0.675×10³¹

F = 6.75×10³⁰ N.

In the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

The Five-factor model is a scientific theory that states traits of the personality of an individual are due to its biology and therefore they respond to adaptations, which are central in the biology field.

In conclusion, in the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

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Answer:

6400km is the closest

Explanation: