Complete Question
The diagram for this question is shown on the first uploaded image
Explain why the interconnection is not valid.
i A valid interconnection would require the 3 A and 4 A sources to supply different currents in the same direction, which they do not.
ii A valid interconnection would require the 3 A and 4 A sources to supply different currents in opposite directions, which they do not.
iii A valid interconnection would require the 3 A and 4 A sources to supply the same current in opposite directions, which they do not.
iv A valid interconnection would require the 3 A and 4 A sources to supply the same current in the same direction, which they do not
Answer:
The correct option is iv
Explanation:
Looking at the diagram we see that the current source are connected in series, generally the current flowing through two source that are connected in series is suppose to be the same but in this case it is not so
i.e \(4A \ne 3 A\) hence Kirchhoff's law is broken or not followed in this circuit which means the interconnection is not valid
also another reason why the interconnection is not valid is because the current are flowing in the different directions
Sometimes earthquakes occur at a boundary between the Indian and Eurasian Plates. The collisions of these two continental plates formed the Himalayan mountain range.
Based on this information, which type of boundary exists between the Indian and Eurasian Plates?
continental-continental convergent
continental-continental divergent
oceanic-continental divergent
oceanic-continental convergent
Answer:
Continental Continental convergent.
Explanation:
Continental Continental convergent is a type of earthquakes that occur between boundaries of two continents in which the tectonic plates move closer to each other or converge.
Eurasian plates refers to tectonic plates that is found in the Continent of Eurasia which include Asian and Europe excluding India subcontinent.
From the question, the earthquake occur between boundaries of two continents India and Eurasia and this converging and collision of the two continental plates formed the Himalayan mountain range.
Therefore, it is continental continental convergent.
Answer:
A
Explanation:
A bicyclist steadily speeds up from rest to 6.00m/s in 7.30s.
How far did she travel during this time?
Answer:
21.899 m
Explanation:
The explanation here is a little differe because we are starting from rest. So, everyone does physics a little differently, but what I would start with is trying to find the accelaration. I've given the formula, now you are able to plug this into the displacement formula where you Velocity Initial = 0m/s (Since you are starting from rest) and V final = 6.00 m/s...
You just plug numbers into the formula after solving for accelaration and do some simple algebra! I hope this helps! I am attaching a new pdf for visuals! If you can't open it let me know! Also there is a star by accelaration because I didn't know if I spelled it right, sorry!
Tropical, dry, and polar are types of _______.
A. elevation
B. weather
C. climate zones
D. precipitation
Answer:
Answer C: Climate Zones
Explanation:
Describing the common conditions someplace is called climate zones
Answer:
c- They are types of climate zones
an experienced astronomer can take one look at the h-r diagram of a star cluster and immediately estimate its age. select the statement that explains how this is possible.
The most massive stars remaining on the main sequence indicate the cluster's age.
What is the approximate age of the star cluster in the HR diagram quizlet?
Spectral types O and B main sequence stars have a core hydrogen supply that is enough for around 350 million years; types A and F, for about 2 billion years; type G, for about 10 billion years; and types K and M, for about 30 billion years.
Astronomers can establish the age of a globular cluster by plotting the stars in the cluster on a Hertzprung-Russell diagram and comparing the main sequence turnoff point with stellar evolution models.
Similar to our Sun, main sequence stars consume hydrogen. The upper left of the strip is home to hotter, more massive main sequence stars. Cooler, less massive stars can be observed at bottom right. Massive stars swiftly exhaust all of their hydrogen in a few of million years.
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Explain why adding globes in parallel makes no difference to their brightness? What did you notice about the current?
(immediate response please)
Adding globes in parallel makes no difference to their brightness because all the bulbs glowed with the same brightness indicating that the current flowing through the bulbs had the same value.
The current in each light bulb was the same.
What is electric current?An electric current is a flow of electrons as a result of a potential difference between two points in conductor.
Electrons are negatively-charged particles that are one of the fundamental particles of an atom. The flow of electrons through a conductor is able to do work.
Two or more globes in a simple parallel circuit do not experience any drop in the voltage, thus allowing the maximum flow of electric current. Also, connecting devices in a parallel circuit ensures that if one of the component lops is disconnected, the flow of current through the other loops remains intact.
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How many days are required for a radioactive sample, with a half-life of 5.7 days and an initial activity
of 1.07 × 105 Bq, to decay to an activity of 100 Bq?
It takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.
The formula for radioactive decay is \(A = A0 * (1/2)^{(t/t1/2)}\) where: A is the final activity A0 is the initial activity is the time elapsed t1/2 is the half-life of the sample
In this problem, the initial activity A0 is given as 1.07 x 105 Bq and the final activity A is given as 100 Bq.
The half-life of the sample is given as 5.7 days.
Substituting these values into the formula, we get: \(100 = 1.07 \times 105 * (1/2)^{(t/5.7)}\)
Dividing both sides by 1.07 x 105, we get:
\(0.000934579 = (1/2)^{(t/5.7)}\)
Taking the natural logarithm of both sides, we get:\(-7.072737 = (t/5.7) * ln(1/2)\)
Dividing both sides by ln(1/2), we get:
\(t = -7.072737 \div ln(1/2) * 5.7t \approx 28.3\) days
Therefore, it takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.
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Two forces, one of 10 N and the other of 6 N, act on a body. The directions of the forces are not known.
(a) What is the minimum magnitude of the resultant of these forces? (b) What is the maximum magnitude?
a. The minimum magnitude of the resultant is 4 N.
b. The maximum magnitude of the resultant is 16 N.
Steps
The minimum magnitude of the resultant of the forces occurs when the forces are acting in opposite directions. The maximum magnitude of the resultant of the forces occurs when the forces are acting in the same direction.
(a) To find the minimum magnitude of the resultant, we subtract the smaller force from the larger force:
Resultant = Larger force - Smaller force
Resultant = 10 N - 6 N
Resultant = 4 N
Therefore, the minimum magnitude of the resultant is 4 N.
(b) To find the maximum magnitude of the resultant, we add the forces together:
Resultant = 10 N + 6 N
Resultant = 16 N
Therefore, the maximum magnitude of the resultant is 16 N.
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Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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Six identical cells with an EDS of 3 V connected in a battery. Resistors R₁ and R₂=16Ω are connected to the battery, the total resistance of the external circuit is R=6Ω and the current flowing in it is 1 A. Determine the resistance of the first resistor and the EDS and internal resistance of the battery.
- The resistance of the first resistor (R₁) is 12 Ω.
- The electromotive force (EMF) of the battery is 18 V.
- The internal resistance of the battery is 12 Ω.
To solve the given problem, we can apply Kirchhoff's laws and Ohm's law to determine the resistance of the first resistor (R₁) and the electromotive force (EMF) and internal resistance of the battery.
Let's start by calculating the resistance of the first resistor (R₁):
1. Apply Ohm's law to find the voltage drop across the external circuit:
V = I * R
V = 1 A * 6 Ω
V = 6 V
2. The voltage drop across the external circuit is equal to the EMF minus the voltage drop across the internal resistance of the battery:
V = E - Ir
6 V = E - (1 A * r) (where r is the internal resistance of the battery)
3. We also know that the EMF of the battery is the sum of the voltage drops across each cell in the battery:
E = 6 cells * 3 V/cell
E = 18 V
4. Substitute the value of E in the equation from step 2:
6 V = 18 V - r
r = 12 Ω
Therefore, the resistance of the first resistor (R₁) is 12 Ω.
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During which sequence of phases does the moon's visibility increase
During the "waxing" phases, the two weeks immediately following the New Moon.
New Moon ==> waxing crescent ==> First Quarter ==> waxing gibbous ==> Full Moon
The phase of the moon decides the moon's visibility. The sequence of phases does the moon's visibility increases is; the waxing crescent, first quarter, waxing gibbous, full Moon.
What is the moon phase?The moon changes shape every day. This is due to the fact that the celestial body has no light of its own and can only reflect sunlight.
Only the side of the moon facing the sun can reflect this light and seem bright. The opposite side appears black. this is a full moon.
We can only see the black section when it lies between the sun and the earth when a new moon occurs. We witness intermediate phases like a half-moon and crescent in between these two extremes.
Following are the sequence of phases does the moon's visibility increase is;
1. Waxing crescent
2. First Quarter
3. Waxing gibbous
4. Full Moon
The phase of the moon decides the moon's visibility. Hence the visibility changes with the change in the phase of the moon.
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what is the orbital speed for a satellite 3.5 x 10^8m from the center of mars? Mars mass is 6.4 x 10^23 kg
Answer:
v = 349.23 m/s
Explanation:
It is required to find the orbital speed for a satellite \(3.5\times 10^8\ m\) from the center of mass.
Mass of Mars, \(M=6.4\times 10^{23}\ kg\)
The orbital speed for a satellite is given by the formula as follows :
\(v=\sqrt{\dfrac{GM}{r}} \\\\v=\sqrt{\dfrac{6.67\times 10^{-11}\times 6.4\times 10^{23}}{3.5\times 10^8}} \\\\v=349.23\ m/s\)
So, the orbital speed for a satellite is 349.23 m/s.
What color will result when subtract cyan from white light?
blue & green
green
blue
red
Answer:
Green
Explanation:
Cyan, Magenta and Yellow are the subtractive primary colors. Each one absorbs one of additive primary colors : Cyan absorbs Red, Magenta absorbs Green and Yellow absorbs Blue. Adding two subtractive primary colors filters together will transmit one of the primary additive colors.
Guys please help. I need this question
If a runner has a speed of 8.66m/s and runs for 46.2s what distance is covered? tv = d
v=
d=
t=
Answer:
\(\text{Using the formula: }v=\frac{d}{t}\\\therefore vt=d\\\text{Plug and chug:}46.2(8.66)=400.092\text{ metres}\)
A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?
The answer is that the time the diver was in the air is 1.13 seconds.
To determine the time the diver was in the air, we can use the kinematic equation:
Δy = viΔt + 1/2at²,
where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0
m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²
Simplifying, we get:
4.9t² + 5.5t - 3.0 = 0
We can solve for t using the quadratic formula:
t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s
Since time cannot be negative, the time the diver was in the air is 1.13 seconds.
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Nina and Jon are practicing an ice skating routine. Nina is standing still. Jon, who is twice as heavy as Nina, skates toward her, pushing Nina away with force f. Assuming the system is closed, which statement is correct about this system? A. Nina experiences a force equal to f. B. Nina experiences a force equal to f/2.
If the system is closed, Nina will experience only a force equal to F exerted by Jon.
According to Newton's third law of motion, action and reaction is equal and opposite. That is the force applied to a stationary object is equal to the reaction exerted by the stationary object.
Applying this law, the force Jon applied on Nina is equal to the reaction Nina exerts on Jon.
If Jon exerts a force of F magnitude on Nina, consequently, Nina will experience the force of equal magnitude and exert equal reaction in opposite direction towards Jon.Also, if the system is closed, no additional force will be experienced by Nina, except the force applied by Jon.Thus, assuming the system is closed, Nina will experience only a force equal to F exerted by Jon.
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URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally insulated chamber. For water L = 3.33 x 105 J/kg. The specific heat of ice is 2090 J/(kg°C) and of water 4186 J/(kg°C). How much does the ice heat up in order to bring the water down to 0°C?
A. 0.04°C
B. 0.4°C
C. 4°C
D. 10°C
E. 20°C
Answer:
Explanation:
heat lost by water will be used to increase the temperature of ice
heat gained by ice
= mass x specific heat x rise in temperature
1 x 2090 x t
heat lost by water in cooling to 0° C
= mcΔt where m is mass of water , s is specific heat of water and Δt is fall in temperature .
= 1 x 2 x 4186
8372
heat lost = heat gained
1 x 2090 x t = 8372
t = 4°C
There will be a rise of 4 degree in the temperature of ice.
The increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
The given parameters;
mass of the ice, m₁ = 1 kgtemperature of the ice, t₁ = -20°Cmass of the water, m₂ = 1 kgtemperature of the water, t₂ = 2 °CApply the principle of conservation of energy to determine the increase in the temperature of the ice to bring the water to 0 °C.
Heat absorbed by the ice = Heat lost by water
\(Q_{ice} = Q_{w}\\\\mc\Delta t_{ice} = mc \Delta t_{w}\\\\1 \times 2090 \times \Delta t = 1 \times 4186 \times (2-0)\\\\2090\Delta t = 8372\\\\\Delta t = \frac{8372}{2090} \\\\\Delta t = 4 \ ^0C\)
Thus, the increase in the temperature of the ice to bring the water to 0 °C is 4 ⁰C.
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Do this for alot of points
1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness
A Motorcycle Jump. You are planning to make a jump with your motorcycle by driving over a ramp that will launch you at an angle of 30.0° with respect to the horizontal. The front edge of the ramp on which you are supposed to land, however, is 25.0 ft lower than the edge of the launch ramp (i.e., your launch height).
(a) Assuming a launch speed of 55.0 mph, at what horizontal distance from your launch point should the landing ramp be placed?
(b) In order to land smoothly, the angle of the landing ramp should match the direction of your velocity vector when you touch down. What should be the angle of the landing ramp?
a. the landing ramp should be placed at 276.298 ft horizontally from the launch point.
(b) the angle of the landing ramp is 30°.
How do we calculate?(a)
Launch speed = 55.0 mph * (1.467 ft/s)
= 80.685 ft/s
Horizontal distance = Launch speed * Time of flight
Vertical velocity = Launch speed * sin(30.0°)
Time to reach maximum height = Vertical velocity / g
Vertical distance = (1/2) *g * t²
and Time = √(2 * Vertical distance / g)
Total time of flight = 2 * Time to reach maximum height + Time for descent
Horizontal distance = Launch speed * Total time of flight
The Vertical velocity = 80.685 ft/s * sin(30.0°)
= 40.3425 ft/s
Time to reach maximum height = 40.3425 ft/s / 32.2 ft/s²
Time to reach maximum height = 1.253 s
Time of descent = √(2 * 25.0 ft / 32.2 ft/s²)
Time of descent = 0.913 s
Total time of flight = 2 * 1.253 s + 0.913 s
Total time of flight = 3.419 s
In conclusion, the horizontal distance = 80.685 ft/s * 3.419 s
horizontal distance = 276.298 ft
b.
the angle of the landing ramp is 30.0 be the same as the launch angle.
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A pelican flying along a horizontal path drops
a fish from a height of 5.0 m. The fish travels
8.5 m horizontally before it hits the water
below.
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s^2
Answer in units of m/s.
The initial velocity of the pelican, given that it dropped a fish from a height of 5.0 m is 8.5 m/s
How do I determine the initial velocity of the pelican?We'll begin by obtaining the time taken for the fish to hit the water. This can be obtained as follow:
Height (h) = 5.0 mAcceleration due to gravity (g) = 9.81 m/s²Time (t) =?h = ½gt²
5 = ½ × 9.81 × t²
5 = 4.905 × t²
Divide both side by 4.905
t² = 5 / 4.905
Take the square root of both side
t = √(5 / 4.905)
t = 1 second
Finally, we shall determine the initial velocity of the pelican. Detail below:
Horizontal distance (s) = 8.5 mTime (t) = 1 secondInitial velocity of pelican (u) = ?s = ut
8.5 = u × 1
u = 8.5 m/s
Thus, we can conclude that the initial velocity is 8.5 m/s
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a barrel will rupture when the gauge pressure within it reaches 350 kpa. it is attached to the lower end of a vertical pipe, with the pipe and barrel filled with oil \rho
The pipe will be 40.1 meter if the barrel is not to rupture.
What is fluid pressure?The pressure exerted by a fluid at equilibrium at any point due to the force of gravity is known as fluid pressure.
Given that: fluid pressure is: p = 350 kPa = 350 * 1000 Pa = 350000 Pa.
Density of fluid is: ρ = 890 kg/m^3.
Let the height of the pipe is h.
Hence, from the formula of P = hρg we get: the height of the pipe is:
h = P/ρg
= 350000/(890×9.8) m
= 40.1 meter.
So, the pipe is 40.1 m long.
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4. What impulse occurs when a cart that is originally at rest experiences an average force of 10N
for 2.5s? (include unit) * (T)
The drawing shows two situations in which charges are placed on a and y axes. They are located at the same distance if 6.80cm from the origin O. For each of the situations in the drawing, determine the magnitude of the net electric field at the origin
The electric field strength from the origin is 1.95 x 10¹² q ( N/C ).
What is electric field?
The electric field of a charged particle is the region of space where the influence of electric force is felt.
Mathematically, the formula for electric field strength is given as;
E = kq / r²
where;
k is the Coulomb's constantq is the magnitude of the charger is the position of the chargeThe electric field strength from the origin is calculated as follows;
E = ( 9 x 10⁹ x q ) / ( 0.068 m )²
E = 1.95 x 10¹² q ( N/C )
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A car moves with an average speed of 45 miles/hour. How long does the car take to travel 90 miles?
A.
2 minutes
B.
2 hours
C.
45 minutes
D.
45 hours
E.
90 minutes
Answer:
B
Explanation:
45+45=90
45 per hour
so, 2 hours
Answer:
B.
2h
Explanation:
If you are going 45 miles per hour, you will travel 45 miles in 1 hour. It will take you 2 hours to travel 90 miles at a speed of 45 miles per hour.
to make it easier multiply 45 by 2 = 90
45 x 2 = 90
What I need help with is attached below
Answer:
Explanation:
3. answer is d.
Displacement increases b/c slopes of both lines are positive. Spring 1 displaces more than Spring 2 per unit force applied. Graphs are straight lines, so the increase is proportional.
4. Fnet = 5 - 30 - 5 = -30 N Positive direction is to the right, negative direction is to the left.
answer is d. 30 N to the LEFT
AC power switches direction at a frequency of 60 Hz. What is the period of this oscillation?
When the direction of a current changes 60 times in a second, the current is said to be 60 Hz.
An AC power grid with a 60 Hz frequency has a period, what is it?While the passing current does not affect the wavelength, the operating frequency does.A sine wave's period, which is defined as the interval between two identical spots on the wave, will be roughly 16.6 milliseconds at a rate of 60Hz (60 oscillations per second), as depicted in the diagram.
Describe a 60 Hz AC?A frequent word for 60 cycles per second, or more commonly 60 Hertz, is the frequency of dc power (Hz).In honor of German physicist Heinrich Hertz, who established the transmission and presence of electric oscillations, the latter unit is used.
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Pls help!!
Which situation describes a system with increasing gravitational potential energy?
a boy jumping down from a tree limb
a girl stretching a horizontal spring
a bicyclist riding up a steep hill
a train speeding up on a flat track
C) a bicyclist riding up a steep hill
The metaphor for a system with rising gravitational potential energy is "a bicyclist riding up a steep hill." Let's get into greater detail:
A cyclist faces resistance from gravity as they ride up a steep slope. The cyclist's elevation, or height above the ground, rises as they cycle and climb uphill. Gravity is pulling the cyclist down the hill by exerting downward force. The cyclist must apply force to the pedals in order to move forward and overcome the pull of gravity. In order to do this, the bicyclist must transform chemical energy from their body into mechanical energy. The distance of the cyclist from the centre of the Earth grows as they ride up the hill. The height and mass of an object affect its gravitational potential energy. In this scenario, as the bicyclist's height rises, their gravitational potential energy also rises.
Due to the higher elevation, the energy input from the biker is stored as increased potential energy. When the bicycle descends the hill or does work, this potential energy can be transformed back into kinetic energy or other types of energy.
A single Oreo cookie provides 53 kcal of energy. An athlete does an exercise that involves repeatedly lifting (without acceleration) a 100-pound weight two-feet above the ground with an energy efficiency of 25%. How many repetitions can she do with the energy supplied from a single Oreo cookie? What happens to the number of repetitions that can be done if the efficiency increases?
The number of times the athlete can lift the weight with single energy supplied by the Oreo cookie is 204 times and this number of times will increase if the efficiency increases.
Energy used by the athleteThe energy used by the athlete is calculated as follows;
E = Fd
where;
F is the applied force = 100 lb weight = 444.82 Nd is the distance = 2 ft = 0.61 mE = 444.82 x 0.61 = 271.34 J
Input energyThe Input energy of the athlete = 53 kcal = 221752 J
Number of times the athlete can lift the weight\(E = \frac{0utput \ energy}{1nput \ energy} \\\\0.25 = \frac{n(271.34)}{221752} \\\\271.34n = 55483\\\\n = \frac{55483}{271.34} \\\\n = 204\)
Thus, the number of times the athlete can lift the weight with single energy supplied by the Oreo cookie is 204 times and this number of times will increase if the efficiency increases.
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How do for-profit and nonprofit fitness centers compare with each other?
For-profit centers offer more luxury services than nonprofit centers.For-profit centers offer more luxury services than nonprofit centers. , ,
For-profit centers have lower membership fees than nonprofit centers.For-profit centers have lower membership fees than nonprofit centers. , ,
For-profit centers place more emphasis on weight lifting than nonprofit centers.For-profit centers place more emphasis on weight lifting than nonprofit centers. , ,
For-profit centers are more common in low-income communities than nonprofit centers.
Comparison of For-profit and Non-profit Fitness Centers
This is how they compare with each other: For-profit centers offer more luxury services than nonprofit centers.
For-profit fitness centers are fitness centers that offer their services to cover their costs and make some profits. They are business entities that generate income for their shareholders. Their fees are based on cost plus profit. This approach enables them to remain sustainable as business ventures.
They are not like non-profit fitness centers, which may offer their services for free or at cost. Sometimes, the nonprofit centers may not even cover their fixed and operational costs. They are usually located in low-income communities, unlike for-profit fitness centers, which are mainly located in rich-income communities.
Considering their clientele, for-profit centers provide modern and better facilities to satisfy their rich-income clients.
Thus, these for-profit centers offer more luxury services than their non-profit counterparts.
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A cyclist travels a distance S from A to B consisting of three segments: s = S1 + $2 + $3, Time and speed over the segments are t1, t2, t3 and v1= 20(km/h), v2 = 15(km/h), V3= 10(km/h). Calculate the average speed over the distance s. Consider two cases: a) s1=s2=s3 b) t1=t2=t3
The average speed over the distance s consisting of three segments s1, s2, and s3 in first case a) s1 = s2= s3 is 13.85 km/h and in the second case b) t1 = t2 = t3 is 15 km/h.
In the first case where the distance for three intervals is the same a) s₁ = s₂ = s₃, the average speed for three segments is calculated by the formula:
Average speed = 3 ÷ ( 1/v₁ + 1/v₂ +1/v₃)
Average speed = 3 ÷ ( ¹/₂₀ + ¹/₁₅ + ¹/₁₀)
Average speed = 13.85 km/h
In the second case where the time taken for all three intervals is the same b) t₁ = t₂ = t₃, the average speed for three segments is calculated by the formula:
Average speed = (v₁ + v₂ +v₃) ÷ 3
Average speed = (20 + 15 + 10) ÷ 3
Average speed = 15 km/h
Learn about the equation of average speed at:
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