explain why clay having been fired
at elevated temperature Loses its
hydroplasticity.

Answer:

Water enters and leaves the 6-cm diameter pipe bend in Fig. P3.45 at an average velocity of 8.5 m/s. The horizontal force to support the bend against momentum change is 300 N. Find (a) the angle ϕ; and (b) the vertical force on the bend.

a) The angle \(\phi\) is 62.06°.

b) The vertical force on the bend is 180.47 N.

The weight of the water and the reaction force must be considered to determine the vertical force exerted on the bend. This analysis provides valuable insights into the behavior and structural requirements of the pipe bend in relation to the fluid flow, ensuring its proper functioning and structural integrity.

The objective is to determine two key parameters: the angle of deflection QQ of the pipe bend and the vertical force acting on it. By applying principles of fluid mechanics and equilibrium, the solution requires calculating the change in momentum of the water passing through the bend and equating it to the known horizontal force required to support the bend.

Given that,

The diameter (d)= 6 cm

The average velocity (v)=8.5 m/s

Consider the rate of change of momentum along the x-direction.

\(F_x=mass \times (\frac{Intial \ velocity-Final \ Velocity}{time})\)

\(F_x=m'[(V-(-Vcos\phi)]\)

\(F_x=\rho AV^2[1+cos\phi]\)

\(300=100\times(\frac{\pi}{4}(0.06)^2)\times(8.5)^2[(1+cos\phi)]\)

\([(1+cos\phi)]=1.4685\)

\(cos\phi=0.4685\)

\(\phi=cos^{-1}(0.4685)\)

\(\phi=62.06^{^\circ}\)

(b) Calculate the vertical force on the bend.

Consider the rate of change of momentum along the y-direction.

\(F_y=mass \times (\frac{Intial \ velocity-Final \ Velocity}{time})\)

\(F_y=m'[(0-(V-Vsin\phi)]\)

\(F_y=\rho AVsin\phi\)

\(F_y=(1000)\times(\frac{\pi}{4}(0.06)^2)\times(8.5)^2\times sin62.06^{\circ}\)

\(F_y=180.47 \ N\)

Therefore,

a) The angle \(\phi\) is 62.06°.

b) The vertical force on the bend is 180.47 N.

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Transmural myocardial ischemia that causes myocardial damage or necrosis is known as an acute ST-elevation myocardial infarction (STEMI). [1] As of 2018, the clinical definition of myocardial infarction (MI) calls for aberrant cardiac biomarkers to confirm the myocardial ischemia injury.

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Answer:

No matter what u post on a football page, some fatherless dude will either say "pessi" or "penaldo"

Answer: jay is traveling at 4 miles per hour :)

Explanation:

Answer:

The Coast Guard is the nation's oldest continuous seagoing service with responsibilities including search and rescue (SAR), maritime law enforcement (MLE), aids to navigation (ATON), ice breaking, environmental protection, port security and military readiness.

Explanation:

there

The capacity of the window air conditioner required to achieve the desired objective is approximately 1.61 kW

In cooling load calculations, the loads are categorized into three categories: Sensible load, Latent load, and Ventilation load.

Sensible Load: This includes the heat gained or lost through walls, floors, and ceilings. It accounts for cooling needed to counteract heat sources such as solar radiation, occupants, lighting, and electrical equipment.

Wall and roof heat transfer rate per hour: Qwall = Uwall x Awall x (Tdb,wall - Ti)

Qwall = 0.0706 x 72 x (40-22) = 90.76 kJ/hr

Qroof = Uroof x Aroof x (Tdb,roof - Ti)

Qroof = 0.0706 x 18 x (40-22) = 22.69 kJ/hr

Total wall and roof heat transfer rate = Qwall + Qroof = 90.76 + 22.69 = 113.45 kJ/hr

Heat transfer rate through the glass: Qglass = Uglass x Aglass x (Tdb,inside - Tdb,outside)

Qglass = 5.52 x 1.8 x (22-40) = -198.72 kJ/hr (negative sign indicates heat loss)

Sensible heat gain due to lights: Qlight = n x P x BF

Qlight = 5 x 40 x 1.20 = 240 kJ/hr

Sensible heat gain from people: Qpeople = n x Qmet

Qpeople = 10 x 500 = 5000 kJ/hr

Total sensible heat gain: QSensible = Qwall + Qroof + Qglass + Qlight + Qpeople

QSensible = 113.45 - 198.72 + 240 + 5000 = 5154.73 kJ/hr

Latent Load: This accounts for the heat gained or lost due to humidity variations.

Sensible heat gain from occupants: qmet = n x Qmet

qmet = 10 x 58 = 580 kJ/hr

Infiltration load: Qinfil = 13.5 x 0.34 x (Tdb - Twb)

Qinfil = 13.5 x 0.34 x (40 - 26) = 65.52 kJ/hr

Total latent heat gain: QLatent = Qmet + Qinfil

QLatent = 580 + 65.52 = 645.52 kJ/hr

Ventilation Load: This is the heat required to keep the room ventilated.

Ventilation load: QVentilation = n x Qvent

QVentilation = 10 x 7.1 x 10^(-3) x 3600 = 255.6 kJ/hr

Total Heat Load: QTotal = QSensible + QLatent + QVentilation

QTotal = 5154.73 + 645.52 + 255.6 = 6055.85 kJ/hr

To convert kJ/hr to kW:

kW = kJ/hr / 3600

kW = 6055.85 / 3600 = 1.68 kW (approximately)

Therefore, a window air conditioner with a capacity of approximately 1.61 kW would be required to achieve the desired objective.

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Consequently, it will take about 46,134.21 ft. lb. of labour to pump the entire pool's water out.

The volume in cubic feet is obtained by dividing that number by the depth. As there are 7.5 gallons in every cubic foot, multiplying the pool's cubic feet by 7.5 will give you the pool's volume in gallons.

V_sides = πr²h

= π(12 ft)²(5 ft)

= 2,262.74 ft³

V_water = πr²h

= π(8 ft)²(24 ft)

= 6,079.63 ft³

V = V_sides - V_water

= 2,262.74 ft³ - 6,079.63 ft³

= -3,816.89 ft³

W = Fd

F = mg

m = ρV

= 0.075 lb/ft³ × 3,816.89 ft³

= 286.29 lb

F = mg

= 286.29 lb × 32.2 ft/s²

= 9,226.84 ft·lb/s² = 9,226.84 N

W = Fd

= 9,226.84 ft·lb/s² × 5 ft

= 46,134.21 ft·lb

Consequently, it will take about 46,134.21 ft. lb. of labour to pump the entire pool's water out.

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Answer:

A ultra 4. that would be amazing to have that.

Answer:

I have know idea

Explanation:

Economic activities can occur during and between different stages of various processes.

Here are some examples:

Production Stage: During the production stage, economic activities can include the purchase of raw materials, labor costs, and the use of machinery and equipment.

Distribution Stage: During the distribution stage, economic activities can include transportation costs, warehousing costs, and marketing costs.

Consumption Stage: During the consumption stage, economic activities can include the purchase of goods and services by consumers.

Recycling Stage: During the recycling stage, economic activities can include the collection and processing of waste materials, the production of recycled materials, and the sale of these materials to manufacturers.

Innovation Stage: Economic activities during the innovation stage can include research and development expenses, patents, and intellectual property rights.

Service Stage: During the service stage, economic activities can include the provision of services to customers, such as consulting, repair, and maintenance services.

Investment Stage: During the investment stage, economic activities can include the purchase of securities, property, and other assets.

Overall, economic activities occur throughout various stages of a process, from the production of goods and services to their consumption and beyond.

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Answer:

The world's oldest dress called the Tarkhan Dress is at 5,100 to 5,500 years of age.

Does that help? Or do you need something else? I can change my answer if this is not what you need! :D

Explanation:

Answer:

It only detects errors if an odd number of bit flips have occurred.

Explanation:

Parity is a measure of how even or odd a string of digits (for example, a string of binary units is).  It is obtained by calculating the value of all the bits. Parity is used in error detection. A parity error is detected when the parity and the odd number of bits are incorrectly propagated.

A problem commonly associated with the parity bits is that they can only detect an odd number of bit errors. This means that if a digit is corrupted in the even binary digits there would be an incorrect detection of errors.

Electric

Answer

Explain

Home safety and security is an electric process as there are some devices that have electric involvement.

The systems in house safety are which consist of sensors and regular cameras or sirens, are armed via way of means of inputting a code at the keypad, the usage of a voice command, urgent a key fob, or doing it via an app.

Electronic protection gadget refers to any digital device that might carry out protection operations like surveillance, get right of entry to manage, alarming or an intrusion manage to a facility or a place which makes use of energy from mains and additionally an energy backup like a batter.

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Answer:

In the second half of the 18th century the steam-engines invented by Thomas Newcomen and James Watt became the main way water was removed from mines. Mine-owners were always looking for cheaper and more effective ways of removing water from their mines. ....

From the information, let us list the parameters given to solve for the diameter of the pipe.

Given that:

= 2600 kg/m³

Using the standard conversion rates:

Since 1 lbf/in² = 6894.76 N/m²

∴

From the given information, let's start by determining the volumetric flow rate of the liquid in the pipe:

\(\mathbf{The \ volumetric \ flow \ rate \ ( Q) = \dfrac{mass \ flow \ rate}{density \ of \ the \ liquid}}\)

\(\mathbf{Q = \dfrac{0.882 \ kg/s}{2600 \ kg/m^3}}\)

Q = 0.00034 m³/s

In a cylindrical flow pipe, using the formula for the pressure drop to estimated the pipe diameter, we have:

\(\mathsf{\dfrac{\Delta P}{\rho g}= \dfrac{8fLQ^2}{\pi^2gd^5}} --- (1)\)

where (f) can be computed as;

\(f = \dfrac{64}{\dfrac{\rho vd}{\mu}}\)

\(f = \dfrac{64}{\dfrac{\rho Qd}{A\mu}}\)

replacing the values from the above-listed parameters, we have:

\(f = \dfrac{64}{\dfrac{2600 \times 0.00034 \times d}{\dfrac{\pi}{4}(d)^2 \times 0.002}}\)

\(f = \dfrac{64}{2600 \times 0.00034 \times d} \times \dfrac{\dfrac{\pi}{4}(d)^2 \times 0.002}{1}\)

f = 0.1137d

From equation (1), Recall that:

\(\mathsf{\dfrac{\Delta P}{\rho g}= \dfrac{8fLQ^2}{\pi^2gd^5}}\)

\(\mathsf{\dfrac{\Delta P}{\rho }= \dfrac{8fLQ^2}{\pi^2d^5}}\)

Replacing the values, we have;

\(\mathsf{\dfrac{1261.74}{2600}= \dfrac{8\times 0.1173(d) \times (2784) \times (0.00034)^2}{\pi^2(d)^5}}\)

\(\mathsf{0.48528= \dfrac{2.966\times 10^{-5}}{(d)^4}}\)

\(\mathsf{d^4= \dfrac{2.966\times 10^{-5}}{0.48528}}\)

\(\mathsf{d^4= 6.11193538 \times 10^{-5}}\)

\(\mathbf{d = \sqrt[4]{ 6.11193538 \times 10^{-5}}}\)

d = 0.0884 m

d = 88.4 mm

since 1 mm = 0.0393701 inch

∴

88.4 mm will be = 3.48 inches

Therefore, we can conclude that the diameter of the pipe = 3.48 inches

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In crow's foot style E-R diagrams, a hash mark (#) across the relationship line near an entity indicates a minimum cardinality of mandatory and a maximum cardinality of one (option B).

The crow's foot notation is a graphical representation used in E-R diagrams to represent the cardinality of the relationships between entities.

In this notation, an entity is represented as a rectangle, and a relationship is represented as a line connecting two entities.

The crow's foot notation uses various symbols to represent the cardinality of the relationship, including a hash mark (#).

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The forces in members BC and FG of the loaded symmetrical truss can be determined by using one section and two equations, each of which contains only one of the two unknowns.

What is Force?
A force is an effect that can alter an object's motion according to physics. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction. It is calculated using the newton SI unit (N). Force is denoted by the letter F. (formerly P).
The net force acting on an object is equal to the rate at which its momentum varies over time, according to Newton's second law in its original formulation.



The forces in members BC and FG of the loaded symmetrical truss can be determined by using one section and two equations, each of which contains only one of the two unknowns. By using the section, the force in member BC can be determined. By using the equation, the force in member FG can be determined.

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The capitalized cost of the permanent roadside historical marker is $116,386.30.

Capitalized cost

The capitalized cost is an assessment of the cost of the investment. Capitalized cost is a useful metric in cost accounting, particularly in the case of business assets. In the case of permanent roadside historical markers, we need to calculate the capitalized cost given the first cost and maintenance cost of $90,000 and $3,100 respectively that is done every 5 years.

Assuming the interest rate of 10% per year. We can use the following formula to calculate the capitalized cost.

C = P * (i / (1 - (1 + i)^(-n)))

Where,

C = Capitalized cost

P = First cost

i = Interest rate per year

n = Total number of years

To calculate the capitalized cost of the permanent roadside historical marker, we need to calculate the present value of the investment. We are given that the first cost of the historical marker is $90,000 and the maintenance cost of $3,100 is incurred once every 5 years at an interest rate of 10% per year.

The total number of years n = 20 years (4 maintenance cycles of 5 years each).

Therefore, using the formula, we have,

C = $90,000 + $3,100 * (PVIFA10%,20)

$3,100 * (PVIFA10%,20) = 8.513 (calculated using Excel or tables)

C = $90,000 + $3,100 * 8.513

C = $90,000 + $26,386.30 = $116,386.30.

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The engineer is considering various types of marble for the fountain design. One important factor to consider is the density of the marble, which can provide insights into its strength and durability. To determine the density of each marble sample, we can use the formula:

Density = Mass / Volume

Given that the mass of each sample is 1066.32 grams, we need to calculate the volume of each sample to find its density.

For a rectangular prism, the volume can be calculated using the formula:

Volume = Length x Width x Height

Using the dimensions provided (width = 4 inches, length = 6 inches, height = 1 inch), we can calculate the volume and density for each marble sample.

Sample 1:

Volume = 4 inches x 6 inches x 1 inch = 24 cubic inches

Density = 1066.32 grams / 24 cubic inches

Sample 2:

Volume = 4 inches x 6 inches x 1 inch = 24 cubic inches

Density = 1066.32 grams / 24 cubic inches

Sample 3:

Volume = 4 inches x 6 inches x 1 inch = 24 cubic inches

Density = 1066.32 grams / 24 cubic inches

By performing the calculations, you can determine the density of each marble sample, which will help the engineer make an informed decision about the type of marble to use for the fountain design.

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The code only saves the first uppercase letter encountered because the index increment (j++) is placed outside the if condition, causing subsequent letters to overwrite the previous ones in the acronym array.

The issue in the given code is that the index `j` is incremented for each iteration of the loop, which causes subsequent letters to overwrite the previous letters in the `userAcronym` array.'

To resolve this issue, the increment of `j` should only occur when an uppercase letter is encountered. By moving the `j++` statement inside the `if` condition, the code will correctly save only the uppercase letters to the `userAcronym` array without overwriting them.

void CreateAcronym(char userPhrase[], char userAcronym[]) {

   int i;

   int j = 0;

   for (i = 0; i < strlen(userPhrase); ++i) {

       if (isupper(userPhrase[i])) {

           userAcronym[j] = userPhrase[i];

           j++;

       }

   }

   printf("%s", userAcronym);

}

```

This modification ensures that each uppercase letter encountered in the `userPhrase` will be saved in consecutive positions of the `userAcronym` array, allowing the full acronym to be correctly displayed.

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The average cost per share is $0.0031 per share

To calculate the average cost, divide the total purchase amount by the number of shares purchased to figure the average cost per share.

The average cost share method is commonly used by investors for mutual fund tax reporting.

Therefore average cost per share = Total cost/ total share owned.For example, an investor that has $1000in an investment and owns 500 shares would have an average cost basis of $2 i.e ($10,00 / 500).

Similarly,The total cost =$ 2.80+ $1.90 = $4.70

The total share owned = 500+ 1000 = 1500

average cost = 4.70/1500 = $0.0031 per share.

Therefore the average cost per share is $0.0031 per share.

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I =1000 x s [ square root of three x v]

Explanation:

Answer:

To calculate full load current, divide the full load power by the product of the full load voltage times 1.723

A strategy that may help a visual learner process data is a pie chart or histogram.

The common workplace for both science and math pathways, with engineering and technology in laboratories and ships. Thus, option A is correct.

A workplace is given as the location or the place at which the employee are performing their jobs and tasks.

The science or technology-mediated employees are related to research where they perform the tests in laboratories, as well as the ships are the location for the engineering and the math candidates for the analysis of the studies and to perform the job.

Hence, the location in the workplace common for both engineering and technology candidates has been the laboratories and the ships. Thus, option A is correct.

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You get a result immediately from Euler's formula:

e ^(i π/2) = cos(π/2) + i sin(π/2) = 0 + i * 1 = i

Answer:

genorator- electrical to mechanical

motor- mechanical to electrical

Answer:

ABS: Antilock Braking System – Prevents the wheels from locking during emergency braking.

ACC: Adaptive Cruise Control – Monitors traffic ahead and reduces or increases the car's speed based on the flow of traffic.

AEB: ...

AWD: ...

BHP: ...

CVT: ...

DDI: ...

DFI:

Explanation:

hope it helpssss

Answer:

ABS: Antilock Braking System – Prevents the wheels from locking during emergency braking.

ACC: Adaptive Cruise Control – Monitors traffic ahead and reduces or increases the car's speed based on the flow of traffic.

AEB: ...

AWD: ...

BHP: ...

CVT: ...

DDI: ...

DFI:

The alterations in the following quantities are as follows:

The regenerative cycle may be characterized as any stationary gas turbine which significantly recovers heat from the gas turbine exhaust gases to preheat the inlet combustion air to the gas turbine.

In an ideal regenerative Rankine cycle, steam enters the turbine at the boiler pressure and expands isentropically to an intermediate pressure. Some steam is extracted at this state and routed to the feedwater heater, while the remaining steam continues to expand isentropically to the condenser pressure.

Therefore, the alterations in the following quantities are well described above.

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