Explain why can't everyone become a bodybuilder, even if they tryed train hard enough.

The conversion factor to change the mass of glucose from pounds (lb) to milligrams (mg).

Thus, A pound is equal to 453.6 grams. 1000 milligrams make up one gram (g). Let's first translate pounds into grams: 37.79488 g = 0.0833 lb * 453.6 g/lb

Let's convert glucose into gram to miligram, 1000 mg/g times 37.79488 g equals 37,794.88 mg.

As a result, the typical daily intake of glucose equals to 37,794.88 mg.

Thus, The conversion factor to change the mass of glucose from pounds (lb) to milligrams (mg).

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Answer:

because the side walk is at high temperature

Answer:

Shear Modulus = 2500 Pa = 2.5 KPa

Explanation:

The shear modulus is defined as the ratio between the shear stress and the shear strain. Hence, the shear modulus, in this case, can be calculated by the use of the following formula:

\(Shear\ Modulus = \frac{Shear\ Stress}{Shear\ Strain}\\\)

we have,

shear stress = 20 N/m²

shear strain = 0.008

Therefore,

\(Shear\ Modulus = \frac{20\ N/m^2}{0.008}\\\\\)

Shear Modulus = 2500 Pa = 2.5 KPa

The magnitude of the acceleration of the body is approximately 1.802 m/s^2 when forces of magnitude 5 Newton and 4 Newton act on a body of mass 4.0 kg at a right angle to each other.

To determine the magnitude of the acceleration of a body when two forces act on it at a right angle, we can use the Pythagorean theorem and Newton's second law of motion.Newton's second law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F = ma). In this case, the net force is the vector sum of the two forces acting on the body.Using the Pythagorean theorem, we can find the magnitude of the net force. Let's call the force with magnitude 5 Newton as F1 and the force with magnitude 4 Newton as F2. The net force (Fnet) can be calculated as the square root of the sum of the squares of the individual forces: Fnet = sqrt(F1^2 + F2^2).Now we can substitute the net force into Newton's second law to find the acceleration (a). Rearranging the formula, we have a = Fnet / m.Plugging in the values, Fnet = sqrt(5^2 + 4^2) = sqrt(25 + 16) = sqrt(41) Newtons. The mass (m) is given as 4.0 kg.

Finally, the magnitude of the acceleration of the body is calculated as a = Fnet / m = sqrt(41) / 4.0 ≈ 1.802 m/s^2.

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Answer:

Solution:

Explanation:

Here, mass of body ( m)=12kg.

velocity (v)=37.5 m/s. momentum = mass× velocity = 12kg×37.5m/s =450kgm/s ans.

Answer:

Once

Explanation:

The time between new moon and the end of the cycle of the moons is about 29.53 days, which is roughly a month

The velocity with which will move the body when released from height of 500m is 100m/s

The vertical acceleration is known to be a constant g.

d^2y/dt^2=−g

After integrating, we'll refer to our constant as v0.

dy/dt=v0−gt

That's our time-dependent vertical velocity. In our situation, the starting velocity v0=0, implying that we began at rest at time t=0.

dy/dt=−gt

Let us integrate once more, with the integration constant. y0.\s

y=y0−1/2gt^2

We have

y0=500 and want t when y=0.

2=1000

t=√1000g

We frequently employ the assumption g=10m/s2, which yields t=10

At t=10t=10, how fast is it moving?

dy/dt=−gt=−(10)(10)=−100

DOWN, 100 meters per second.

Gravity's acceleration is always constant and downward, although the amplitude and direction of velocity change. The ball has zero velocity at its greatest point in its trajectory, and the magnitude of velocity increases as the ball descends back toward the earth.

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The distance traveled during the driver's reaction time is 7.5 meters, the distance traveled while decelerating is 22.5 meters And  the total stopping distance is 30 meters.

To determine the distance the driver travels before applying the brakes, we can use the following steps:

1. Calculate the distance traveled during the driver's reaction time.

  Given:

  Reaction time (t_reaction) = 0.50 seconds

  Initial velocity (v_initial) = 15 m/s

The distance traveled during the reaction time can be calculated using the formula,

  d_reaction = v_initial * t_reaction

 d_reaction = 15 m/s * 0.50 s

  d_reaction = 7.5 meters

Therefore, the distance traveled during the driver's reaction time is 7.5 meters.

2. Calculate the distance traveled while decelerating.

  Given:

  Maximum deceleration (a_deceleration) = -5.0 m/s^2 (negative because it represents deceleration)

  Final velocity (v_final) = 0 m/s (since the car comes to a stop)

  The distance traveled while decelerating can be calculated using the formula:

  d_deceleration = (v_final^2 - v_initial^2) / (2 * a_deceleration)

  d_deceleration = (0^2 - 15^2) / (2 * (-5.0))

  d_deceleration = (-225) / (-10)

  d_deceleration = 22.5 meters

Therefore, the distance traveled while decelerating is 22.5 meters.

3. Calculate the total stopping distance.

  The total stopping distance is the sum of the distance traveled during the reaction time and the distance traveled while decelerating.

Total stopping distance = d_reaction + d_deceleration

Total stopping distance = 7.5 meters + 22.5 meters

Total stopping distance = 30 meters

Therefore, the total stopping distance is 30 meters.

In summary, considering a reaction time of 0.50 seconds and a maximum deceleration of 5.0 m/s^2, the driver would travel 7.5 meters during her reaction time and an additional 22.5 meters while decelerating, resulting in a total stopping distance of 30 meters.

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Answer:

16 N Forward

Explanation:

I took the test

The net force acting on the box has a magnitude of 12.47 N and is at an angle of 49.3 degrees above the positive x-axis.

To find the x- and y-components of F1, we can use trigonometry:

\(Fx1 = F1 cos(30) = 12 N cos(30) = 10.39 N\)

\(Fy1 = F1 sin(30) = 12 N sin(30) = 6 N\)

Similarly, to find the x- and y-components of F2, we have:

To find the x- and y-components of F1, we can use trigonometry:

\(Fx2 = F2 cos(120) = 4 N cos(120) = -2 N\)

\(Fy2 = F2 sin(120) = 4 N sin(120) = 3.46 N\)

Now add x- and y-components of  forces to find net force:

\(Fx_net = Fx1 + Fx2 = 10.39 N - 2 N = 8.39 N\)

\(Fy_net = Fy1 + Fy2 = 6 N + 3.46 N = 9.46 N\)

The net force acting on the box is the vector sum of the x- and y-components:

\(F_net = sqrt(Fx_net^2 + Fy_net^2) = sqrt((8.39 N)^2 + (9.46 N)^2) = 12.47 N\)

\(theta = arctan(Fy net / Fx net) =\)\(arctan(9.46 N / 8.39 N) = 49.3 degrees\)

Therefore, the net force acting on the box has a magnitude of 12.47 N and is at an angle of 49.3 degrees above the positive x-axis.

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Answer: the father of the nuclear physics is Ernest Rutherford

Explanation:

Answer:

Option (4)

Explanation:

Given polynomial is,

P(x) = 1x³ - 7x² + 2x + 40

If (x - 5) is a factor of the given polynomial,

Synthetic division by x = 5,

5 |  1    -7     2     40

    ↓    5   -10   -40

     1    -2    -8      0

Therefore, factored form of the polynomial will be,

P(x) = (x - 5)(x²- 2x - 8)

Now we further factorize the expression (x² - 2x - 8),

(x² - 2x - 8) = x²- 4x + 2x - 8

                  = x(x - 4) + 2(x - 4)

                  = (x + 2)(x - 4)

Now fully factored form of the polynomial will be,

P(x) = (x - 5)(x + 2)(x - 4)

Therefore, remaining factors of the polynomial other than (x - 5) are (x - 4)(x + 2)

Option (4) will be the correct option.

Answer:

I think your answer would be D

Explanation:

Answer: Musical theater is like acting in a musical.

Explanation: Other dance styles don't involve singing.

Since the radius of the circular path is inversely proportional to the mass and directly proportional to the charge of the particle, we can conclude that the electron will have a smaller radius of circular path compared to the proton when both particles enter the same magnetic field region at right angles to the field. Therefore, the radius of the circular path will be smaller for the electron.

Proton: An atom's nucleus contains a proton, a subatomic particle. It has a mass of roughly 1 atomic mass unit (amu), carries a positive electric charge represented by +1 elementary charge, and is positively charged. Along with neutrons and electrons, protons are one of the basic particles that make up an atom.

A subatomic particle called an electron revolves around the atomic nucleus of an atom. It has a mass of roughly 1/1836 amu, which is substantially less than the mass of a proton or neutron, and bears a negative electric charge, indicated by the elementary charge -1. As fundamental particles, electrons are essential in determining the chemical and electrical characteristics of atoms.

Charge is a fundamental feature of matter that gives birth to electric forces and interactions. It is referred to as charge in physics. It could be favorable or unfavorable. Electric charge is discrete, or quantized, and is made up of elementary charges. A proton or electron carries an elementary charge that is roughly 1.602 x 10-19 coulombs in size. The strength and direction of a charged particle's interaction with another charged particle via electromagnetic forces depends on its charge.

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Answer:

Is this psychology or something?

Answer:

0.39 J/g°c

Explanation:

= heat / unit of mass × unit of temperature

986.75J/16.75g

= 58.9 J/g

∆T=175°c - 25°c = 150°c

986.75 / 150°c = 6.578

986.75 / 16.75g.150°c = 0.30 j/g°c

Answer:

Clouds are made up of tiny water droplets. ... As more and more droplets join together they become too heavy and fall from the cloud as rain. Warm air can hold more moisture than cool air. When the warmer air is cooled and the moisture condenses, it often rains more heavily.

Explanation:

hope it helps

Answer:

The volume of water displaced by the raft is 0.233 m³

Explanation:

The question relates to Archimedes' principle which states that the buoyant force experienced by an object immersed in a fluid is equal to the weight of (the force of gravity on) the displaced fluid

The given parameters are;

The combined mass of the person and the raft, m = 233 kg

The liquid on which the raft is located = Water

The density of water, \(\rho _{water}\) = 1000 kg/m³

Weight = Mass, m × g

Where;

m = The mass of the object

g = The acceleration due to gravity = 9.8 m/s²

Given that the raft is on the surface of the water (floating), the buoyant force is equal to the combined weight of the person and the raft = 233 kg

The combined weight of the person and the raft, \(W_{combined}\) = 233 kg × 9.8 m/s² = 2,283.4 N

Therefore;

The buoyant force = 2,283.4 N = The weight of the water displaced

The mass of the water displaced, \(m_{water}\), = 2,283.4 N/(9.8 m/s²) = 233 kg

Density = Mass/Volume

The volume of water displaced by the raft = The mass of the water displaced/(The density of the water) = 233 kg/(1,000 kg/m³) = 0.233 m³.

Answer:

the volume displaced by the raft = 0.233 m3

Explanation:

correct for Acellus

the answer is 104 atm I hope this helps!

Answer:

looking at this triggered my fight or flight.

Explanation:

Answer: See Below

Explanation:

A reflective glass mirror will reflect all the components of white light and not allow visible light to pass through.

A transparent glass block will allow light to pass through with some refraction.

The frequency of an x-ray having a wavelength of 2.5×10⁻⁷ cm is 1.2×10¹⁷ Hz

We'll begin by converting the value of the wavelength from cm to m. Details below:

100 cm = 1 m

Therefore

2.5×10⁻⁷ cm = (2.5×10⁻⁷ cm × 1 m) / 100

2.5×10⁻⁷ cm = 2.5×10⁻⁹ m

Finally, we shall determine the frequency of the x-ray. This is shown below:

Velocity (v) = wavelength (λ) × frequency (f)

3×10⁸ = 2.5×10⁻⁹ × frequency

Divide both sides by 2.5×10⁻⁹

Frequency = 3×10⁸ / 2.5×10⁻⁹ m

Frequency = 1.2×10¹⁷ Hz

Thus, from the above calculation, we can conclude, the frequency is1.2×10¹⁷ Hz

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When a ray of light passes from one medium to another, it changes direction due to a change in speed. This phenomenon is known as refraction. The angle of refraction can be determined using Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the speeds of light in the two media.

In this case, the angle of incidence is 48.5 degrees. Assuming the index of refraction of air is 1, the index of refraction of lucite can be found in a table or by using a refractometer. Let's assume it is 1.5. Using Snell's law, we can calculate the angle of refraction to be approximately 32.9 degrees. Therefore, when a ray of light passes from air into the surface of a lucite block at an angle of 48.5 degrees, the angle of refraction is approximately 32.9 degrees.

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Answer: frequency

Explanation:

amplitude is the max height at which the wave reaches
wavelength distance b/w two waves

the speed at which the wave is oscillating

frequency is no. of oscillations of  a wave per unit length

Based on the nature of variables, none of the evidence card should be eliminated because they all represent variables.

Variables refers to any quantity that can have various values.

Variables include age, time , distance, height, speed, etc.

Variables can either be independent, dependent or constant.

There, none of the evidence card should be eliminated because they all represent variables.

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The weight of the transformer is 138.46 N.

Weight can be calculated by dividing workdone by height

To calculate the weight of the transformer, we use the formula below.

Formula:

Where:

Substitute these values into equation 1

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The power-line interference the student observes is 0.0063 V.

Given, the data;Z1 = 1 MΩ, Z2 = 20 kΩ, Z3 = 10 kΩ, ZG = 30 kΩ, idb = 0.5 μA

First, we need to calculate the common-mode voltage gain (Acm).

The formula for Acm is given by;

Acm = (Z2 / Z1) + (Z4 / Z3)

Acm = (20 / 1000) + (30 / 10,000)

Acm = 0.02 + 0.003

Acm = 0.023

The common-mode voltage gain (Acm) is 0.023.

Now, we need to calculate the common-mode voltage (Vcm)

The formula for Vcm is given by;Vcm = Vg * Acm

Where Vg = 120 V (given)∴

Vcm = 120 * 0.023

Vcm = 2.76 V

Therefore, the common-mode voltage (Vcm) is 2.76 V

Next, we need to calculate the common-mode rejection ratio (CMRR).

The formula for CMRR is given by;

CMRR = Ad / Acm

Where

Ad = differential gain

Ad = (Z3 / Z1)

Ad = 10,000 / 1000

Ad =10

The differential gain (Ad) is 10∴CMRR = 10 / 0.023CMRR = 434.78

The common-mode rejection ratio (CMRR) is 434.78.

Now, we need to calculate the interference voltage (Vinterference). The formula for Vinterference is given by;

Vinterference = Vcm / CMRR

Where Vcm = 2.76 V, and CMRR = 434.78∴

Vinterference = 2.76 / 434.78

Vinterference = 0.0063 V

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