Explain why Al is a metal and N is not.

Answer:There are total four forces acting on the bicyclist namely, gravitational force, normal force, pushing force and air drag.

The magnitude of net force acting on the bicyclist is 165 N.

The required magnitude of force generated for the pedaling is of 225 N.

Given data:

The mass of bicyclist is, m = 75.0 kg.

The magnitude of acceleration is, .

The magnitude of drag force is, F = 60.0 N.

(1)

There are in total 4 forces acting on the bicyclist:

The gravitational force on the bicyclist, acting vertically downward, of magnitude , where m is the mass of the bicyclist and g is the acceleration due to gravityThe normal force exerted by the floor on the bicyclist and the bike, N, vertically upward, and of same magnitude as the gravitational forceThe force of push F", acting horizontally forward, given by the push exerted by the bicyclist on the pedalsThe air drag, F, of magnitude F = 60.0 N, acting horizontally backward, in the direction opposite to the motion of the bicyclist

(2)

The magnitude of net force acting on the bicyclist is given as,

Thus, the magnitude of net force acting on the bicyclist is 165 N.

(3)

We need to find the forward force of push, F'', which is actually the force generated during pedaling.

Then the expression for the forward pushing force F" is given as,

Thus, we can conclude that the force  generated for the pedaling is of 225 N.

Explanation:

The magnitude of the net force on the bicyclist was 0 N.

Her pedaling is generating  a force of  50 N in opposite of the drag force .

Force is defined in physics as: the push or pull on an object with mass that causes it to change velocity. Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.

A spring balance can be used to calculate force.

As the bicyclist (including the bicycle) is pedaling right with a constant speed, the magnitude of the net force on the bicyclist was = mass × acceleration

= 70 kg × 0 m/s²

= 0 N.

Again her pedaling is generating  a force = drag force = 50 N in opposite of the  drag force . So that, net force on it becomes zero.

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It takes approximately 4.59 seconds for the car to come to a stop. the car's initial speed was approximately 110.2 ft/s,

To determine the time it takes for the car to stop and the car's initial speed, we can use the kinematic equation:

v² = u² + 2as

where:

v is the final velocity (0 ft/s, since the car comes to a stop),

u is the initial velocity (unknown),

a is the acceleration (-24.0 ft/s², as the car slows down),

and s is the distance traveled (253 ft).

Plugging in the known values into the equation, we can solve for u:

0² = u² + 2(-24.0 ft/s²)(253 ft)

0 = u² - 48.0 ft/s² * 253 ft

48.0 ft/s² * 253 ft = u²

u² = 12144 ft²/s²

Taking the square root of both sides:

u = √12144 ft/s

u ≈ 110.2 ft/s

So, the car's initial speed was approximately 110.2 ft/s.

Now, to find the time it takes for the car to stop, we can use the equation:

v = u + at

0 = 110.2 ft/s + (-24.0 ft/s²) * t

24.0 ft/s² * t = 110.2 ft/s

t = 110.2 ft/s / 24.0 ft/s²

t ≈ 4.59 s

Therefore, it takes approximately 4.59 seconds for the car to come to a stop.

In summary, the car's initial speed was approximately 110.2 ft/s, and it took approximately 4.59 seconds for the car to come to a stop while skidding a distance of 253 ft.

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Answer:

the answer is A. A school crossing guard raises a stop sign that weigh 10 N

Only the school crossing guard who raises a stop sign that weighs 10 N does the work.

Work done in physics is defined as the dot product of force and displacement caused by it. Mathematically -

W = F.x

W = |F| |x| cos Ф

where Ф is the angle between force and displacement

Given are the various situations from which we have to select the situation in which work is done.

A specific amount of displacement is needed for the work to be done. Similarly, the displacement and the force vectors should not have 90 degree angle between them. If any of this is zero than -

W = F × 0 = F × x × cos(90) = 0

It is only in case A that the guard applies a force equal to the weight of the stop sign and displacement is in the same direction. While in other three cases, either displacement is zero (C) or the angle between displacement and force is 90 degrees (B & D).

Therefore, we can conclude that, only the school crossing guard who raises a stop sign that weighs 10 N does the work.

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During the summertime in Texas, mosquitos swarm. cars driving on the highways get covered in bugs.  which of the two forces is greater, Neither, they both experience the same force in opposite directions.

By Newton's third law, that car pushes on mosquitoes with the same force, but in the opposite direction. This force causes mosquitoes to slow down. One force of the action-reaction force pair is exerted on mosquitoes, and the other force of the force pair is exerted on mosquitoes.

Examples of action-reaction pair:

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A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.

Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.

In Science, the motion of an object or physical body is described in terms of the following parameters:

Furthermore, there are three (3) forms of motion based on dimension and these include:

1. Motion in one dimension

2. Motion in two dimension

3. Motion in three dimension

A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.

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The answers are (a) velocity, v=2.8m/s , mass, m=0.0038kg and x=0.055m.

(b) v=2.7m/s.

Any object or system that has stored energy as a result of its position or component arrangement is said to have potential energy. Nevertheless, it is unaffected by external factors like air pressure or altitude. On the other hand, kinetic energy is the force that propels a moving object or group of particles.

(a) By equating the compressed spring's potential energy to the cork's kinetic energy at release, we have

The formula is :

k = \(\frac{1}{2} mv^2\)

v = \(\sqrt{\frac{2k}{m} }\)

And potential energy of spring = \(\frac{1}{2}mx^2\)

On equating these two equations we get ;

v = x\(\sqrt{\frac{k}{m}\)

After substituting the value of x = 5.5 cm and m = 3.8g we would get

v=2.8m/s m=0.0038kg and x=0.055m.

(b) In the novel scenario, there is some potential energy present just before release. Energy conservation changes when d=0.015m.

Similarly solving the question we get :

v = 2.7 m/s

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Answer:

Explanation:

The equation for centripetal force is

\(F=\frac{mv^2}{r}\). We have all the values we need except for the radius. We have the circumference of the circle, though, so we will solve for the radius using that and the fact that C = 2πr:

3.04 = 2(3.1415)r and

r = .484 m, to the correct number of sig fig's.

Now that we have everything we need and isolating the v NOT squared:

\(v=\sqrt{\frac{rF}{m} }\) and filling in:

\(v=\sqrt{\frac{(.484)(2100)}{905} }\) . This answer will need 2 sig fig's since 2100 has 2 sig fig's in it. That means that the velocity of the test car is

1.1 m/sec

A child sleds down a steep, snow-covered hill with an acceleration of 2.82m/s squared. if her initial speed is 0.0 m/s and her final speed is 15.5 m/s, It takes the child 5.50 seconds to travel from the top of the hill to the bottom.

We can use the following kinematic equation to solve this problem:

v^2 = u^2 + 2as

Where:

v is the final speed

u is the initial speed

a is the acceleration

s is the distance traveled

We are given u = 0.0 m/s, a = 2.82 m/s^2, and v = 15.5 m/s. We need to find s.

Rearranging the equation gives:

s = (v^2 - u^2) / (2a)

Substituting the values gives:

s = (15.5^2 - 0.0^2) / (2 x 2.82) = 74.47 m

Now, we can use another kinematic equation to find the time taken:

v = u + at

Where t is the time taken.

Substituting the values gives:

15.5 = 0.0 + 2.82t

Solving for t gives:

t = 15.5 / 2.82 = 5.50 seconds

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Answer:

7.5 x 10⁻⁸N

Explanation:

Given parameters:

Mass 1  = 60kg

Mass 2  = 75kg

Distance between the bodies  = 2m

Unknown:

Gravitational fore  = ?

Solution:

The gravitational force between the two bodies can be derived using;

  F  = \(\frac{G mass 1 x mass 2}{distance^{2} }\)  

    G is the universal gravitation constant  = 6.67 x 10⁻¹¹m³kg⁻¹s⁻²

Insert the parameters and solve;

  F  = \(\frac{6.67 x 10^{-11} x 60 x 75}{2^{2} }\)   = 7.5 x 10⁻⁸N

The analysts at techno infosystems are considering the four-model approach to system development for a new client. if they make use of the four-model approach, the outcome will be the time taken to develop the model increases.

With a commitment to giving Government PSUs, Educational Institutions, and All Organizations across the country a competitive advantage by making current operations efficient & cost-effective, Techno is a brand name of Richa Infosystems Limited, which is working under the government's initiative to support "Vocal for Local."

The speed of techno, a kind of electronic dance music, frequently ranges between 120 and 150 beats per minute and is typically generated for usage in a continuous DJ set. Common time is usually used for the core rhythm, which is frequently distinguished by a repeating four on the floor beat.

Electronic dance music without vocals or a typical popular song structure, with a quick pace and artificial noises.

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The vacuum needed for the power regen braking will be exhausted if you pump the brake pedal. the Neutral position by moving the gearbox gear selector.

An accelerator pedal that is stuck might happen for a number of reasons. The regular operation of the gas pedal mechanism can occasionally be hampered by floor mats that move in unexpected ways. A broken throttle may be to blame in other situations. Sometimes, a component from outside the system may be in effect.

If your accelerator suddenly becomes stuck, you should shift to neutral, hit the brakes, keep thier eyes on the roadway and search for an exit, alert other drivers by turning on your hazard lights, attempt to move the car off the road safely, and transform off the ignition when you are done changing directions.

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Answer:

apply the brakes before shifting into neutral

Explanation:

Answer:

35 kilogram per stair will weight

Geologists use a tiny magnifying glass to examine rocks up close. In most cases, hand lenses have a 10x magnification and fold into sturdy metal housing.

Geologists can better see the textures and structures of rocks as well as minerals and fossils within them by using magnifying glass. In order to create a magnified image of an item, a magnifying glass is a convex lens. Usually, the lens is housed in a frame with a grip. A magnifying glass can be used to concentrate light and used by geologists, such as the sun's rays to produce a hot spot at the focal for lighting a fire.

Geologists are scientists who investigate the solid, liquid, and gaseous components of the planet Earth and other.

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Answer: skier goes faster

Explanation:

Sharpening the skis reduces the surface area in contact with the snow, and the wax reduces the coefficient of friction between the skis and the snow.  Less friction means less force in the opposing direction of the skier (downhill), so the skier goes faster.  

Oops.

That's my bad then.

The motor boat will require 15.45 seconds to come to a complete stop.

The net force on the boat is the sum of the engine force and the force of the current acting in opposite directions. Therefore, the net force on the boat is,

F_net = F_engine - F_current

F_net = 9,200 N - 12,500 N

F_net = -3,300 N

The negative sign indicates that the net force is acting in the opposite direction to the boat's motion.

We can now calculate the acceleration of the boat using the formula:

a = Fnet / m, where m is the mass of the boat. Plugging in the given values, we get:

a = -3,300 N / 12,000 kg

a = -0.275 m/s², the negative sign indicates that the boat is decelerating.

Finally, we can use the equation of motion, v = u + at, where v is final speed u is initial speed, a and t are acceleration and time.

Rearranging the equation, we get:

t = (v - u) / a

t = (0 - 4.25 m/s) / (-0.275 m/s²)

t = 15.45 s

So, the boat will take 15.45 seconds to stop.

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Answer:

24000 kg*m/s

Explanation:

Given

Mass= 2400-kg

Velocity= 10m/s

We know that

Momentum

P=mv

subsitute

P=2400*10

P= 24000 kg*m/s

Hence the momentum is 24000 kg*m/s

The period of a 3.00kg object moving in a simple harmonic motion is 5.02s

Simple harmonic motion is a system where the object oscillates around the equilibrium position.

Based on the theorem, there are some formulas:

x(t) = A.cos t (ωt+∅)

x max = A

v max = Aω

a max = Aω²

ω = 2π/T = 2πf

From the question, we got some informations:

m = 3.00kg

v max = 4.00 m/s

a max = 5.00 m/s²

T = ?

We will use the formula for a max and v max to find the value of ω:

v max = Aω

v max = 4.00 m/s

Aω = 4.00 m/s ...(i)

a max = Aω²

5.00 = v max (ω)

5.00 = 4.00ω

ω = 1.25 rad/s ..(ii)

Next, we will use the Period formula:

ω = 2π/T

1.25 = 2π/T

T = 1.6π s

T = 5.02s

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The angle of the wavefront of the shock wave produced by a fighter plane flying at Mach 2.20 relative to the plane's direction of motion is approximately 71.6 degrees.

The angle of the shock wave can be determined using the formula:

\(\[ \sin(\theta) = \frac{1}{M}\]\)

where \(\( \theta \)\) is the angle of the wavefront and M is the Mach number. In this case, the Mach number is given as 2.20.

Substituting the given Mach number into the formula, we have:

\(\[ \sin(\theta) = \frac{1}{2.20} \]\)

To find the angle \(\( \theta \)\), we can take the inverse sine (also known as arcsine) of both sides of the equation:

\(\[ \theta = \arcsin\left(\frac{1}{2.20}\right) \]\)

Using a calculator, we can evaluate the arcsine and find that \(\( \theta \)\) is approximately 32.4 degrees. However, this angle represents the angle between the wavefront and the plane's direction of motion. To find the angle of the wavefront relative to the plane's direction of motion, we subtract this angle from 90 degrees since the shock wave is perpendicular to the wavefront:

\(\[ \text{Angle relative to plane's direction} = 90^\circ - \theta = 90^\circ - 32.4^\circ = 57.6^\circ \]\)

Therefore, the angle of the wavefront of the shock wave produced by the fighter plane, relative to the plane's direction of motion, is approximately 57.6 degrees.

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The pressure acting on the top and bottom faces is\(0.1635 N/cm^2\), the pressure acting on the side faces is\(0.4905 N/cm^2,\) and the pressure acting on the front and back faces is \(0.981 N/cm^2.\)

To compute the pressure acting on each face of the rectangular block, we need to know the weight of the block and the area of each face.

The weight of the block can be calculated as follows:

Weight = Mass x Gravity

Weight = 0.3 kg x 9.81 \(m/s^2\)

Weight = 2.943 N

The area of each face can be calculated as follows:

Top and bottom face: length x width = 6 cm x 3 cm = 18 \(cm^2\)

Side faces: length x height = 6 cm x 1 cm = 6 \(cm^2\)

Front and back faces: width x height = 3 cm x 1 cm = 3\(cm^2\)

Now we can calculate the pressure acting on each face:

Top and bottom face: Pressure = Weight / Area = 2.943 N / \(18 cm^2\) = \(0.1635 N/cm^2\)

Side faces: Pressure = Weight / Area = 2.943 N / \(6 cm^2\) = 0.4905 \(N/cm^2\)

Front and back faces: Pressure = Weight / Area = 2.943 N / 3 cm^2 = 0.981 N/cm^2

Therefore, the pressure acting on the top and bottom faces is\(0.1635 N/cm^2\), the pressure acting on the side faces is\(0.4905 N/cm^2,\) and the pressure acting on the front and back faces is \(0.981 N/cm^2.\)

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Answer:

Thanks for the 50 points. Answer eill be always 29.0m

The force between the two particles remains the same when both charges and the separation are doubled.

If the charge of each of the two particles is doubled and the separation between them is also doubled, the force between the two particles can be determined using Coulomb's Law:

F = (k * |q1 * q2|) / r^2

When both charges (q1 and q2) are doubled, the numerator becomes 4 * |q1 * q2|. And when the separation (r) is doubled, the denominator becomes (2r)^2 = 4r^2.

So, the new force (F') is:

F' = (k * 4|q1 * q2|) / (4r^2)

By canceling out the "4" in both numerator and denominator:

F' = (k * |q1 * q2|) / r^2

You'll notice that F' = F, which means the force between the two particles remains the same when both charges and the separation are doubled.

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If the depth of the ocean at a particular place is 1817.5m, the time it would take a sonar signal to travel from a ship to the ocean bottom and back again would depend on the speed of sound in seawater.

The speed of sound in seawater at a temperature of 15°C (59°F) is around 1,530 meters per second. Therefore, to find the time it would take for the sonar signal to travel from the ship to the ocean bottom and back again, we can use the formula: Time = (2 x Depth) / Speed of Sound.

As we know that the depth of the ocean at a particular place is 1817.5 meters. Therefore, we can find out the time it would take for the sonar signal to travel from the ship to the ocean bottom and back again by substituting these values into the formula:

Time = (2 x Depth) / Speed of Sound Time = (2 x 1817.5) / 1530Time = 2.38 seconds.

Therefore, it would take approximately 2.38 seconds for a sonar signal to travel from a ship to the ocean bottom and back again at that particular location in the ocean. It's important to note that this is just an estimate and the actual time may vary depending on factors such as the temperature, pressure, and salinity of the seawater.

The time it would take for a sonar signal to travel from a ship to the ocean bottom and back again would depend on the depth of the ocean and the speed of sound in seawater. Using the formula Time = (2 x Depth) / Speed of Sound, we can estimate the time it would take for the sonar signal to travel based on these factors. In this case, the depth of the ocean was 1817.5 meters and the speed of sound in seawater was 1530 meters per second, so the estimated time it would take for the sonar signal to travel was 2.38 seconds.

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For 1000 seconds , a current of 0.1 A flows so as to transfer charge of 100C

Answer:

Seatbelts

Explanation:

Resistance to change in motion. it presses tour body outside of the loop, keeping you inside the cart

The resistors \(R_1 and R_2 \)are in series connection, so the equivalent resistance of \(R_1 and R_2\) will be their sum.

\( \boxed{ \mathrm{R_t = R_1 + R_2}}\)

Now, the equivalent resistance of \((R_1 and R_2)\) and \(R_3 \) is the total resistance of the circuit, and since they are in parallel connection, Total resistance :

_____________________________

\(\mathrm{ \#TeeNForeveR}\)