explain why a higher difference in electronegativity would create an ionic bond and a lower difference in electronegativity would create a covalent bond

Answer:

How is an environment able to support different varieties of organisms? ... It provides all the necessary conditions, such as temperature, space, water and food resources, oxygen and carbon dioxide, that suit the needs of the organisms. Examples of habitat include forests, mountains, bodies of water, and even puddles.

Explanation:

The molar mass of C4H10 is 58.12 g/mol, and the molar mass of O2 is 32.00 g/mol. When these two reactants combine, the reaction produces 44.01 g of CO2 for each mole of C4H10 and O2. The percent yield for the reaction is 100.84%.

Molar mass is a measure of the mass of a single molecule of a substance and is expressed in units of grams per mole (g/mol). It is calculated by taking the sum of the atomic masses of each atom in the molecule, multiplied by the number of atoms of each kind in the molecule. For example, the molar mass of water (H2O) is 18.015 g/mol, which is calculated by adding the atomic masses of two hydrogen atoms (2 x 1.0079 g/mol) and one oxygen atom (16.00 g/mol). Molar mass is important in chemistry, as it is often used to calculate the number of moles of a substance. It can also be used to help determine the concentration of a solution, and to calculate the mass of an element or compound in a known volume.

balanced equation

2C4H10 + 15O2 -----> 8CO2 + 10H2O

from the balanced equation

15 mol of O2 is giving 8 mol of CO2 this is if you talk in terms of moles

where as if you talk in terms of grams

15 x 32 gr O2 is giveng 8 x 44 gr CO2

480 gr O2 is giving 352 gr CO2

6.49 gr O2 will give 6.49 x 352 / 480 = 4.759 gr of CO2 this is theretically from the equation

but actually he got 4.80 gr

now

% of yield = actual / thritical  x 100

= 4.80 / 4.76 x 100

= 100.84%

Thus, The percent yield for the reaction is 100.84%.

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Two precautions to avoid protonation or reaction with acidic compounds are ensuring anhydrous conditions and controlling pH and temperature.

To avoid the problem of protonation or reaction with acidic compounds like water, alcohols, and carboxylic acids during a specific reaction, two precautions that can be taken are:

1. Anhydrous conditions: One precaution is to ensure anhydrous conditions, meaning that any water or moisture is removed or excluded from the reaction environment. This can be achieved by using drying agents such as molecular sieves, desiccants, or using techniques like vacuum or inert gas purging. By keeping the reaction environment dry, the presence of water is minimized, reducing the chances of unwanted protonation or reaction with acidic compounds.

2. Controlled pH and temperature: Another precaution is to carefully control the pH and temperature of the reaction. By maintaining the reaction at a specific pH range and temperature, the reactivity of acidic compounds can be minimized. This can involve using suitable buffers or adjusting the pH with weak bases to maintain a less acidic environment. Additionally, controlling the temperature within a suitable range can help avoid excessive protonation or reaction with acidic compounds.

By implementing these precautions, it is possible to minimize the unwanted protonation or reaction with acidic compounds, allowing for a more controlled and specific reaction.

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The density of the pebble is 2.5g/cm³

CALCULATE DENSITY:

Density = mass (g) ÷ volume (mL)

Density = 35g ÷ 14cm³

Density = 2.5g/cm³

Therefore, the density of the pebble is 2.5g/cm³

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What is molarity?

Molarity is defined as the number of moles of solute per liter of solution.

M = n / V

where

n = no of moles ( 2 mol)

M = Molarity ?

V = volume of solution ( 1 itre)

M = n / V

  = 2 mol / 1 litre

  = 2 mol/L

What is Osmolarity?

Osmolarity =  Molarity × number of particles of dissociation (n)

according to question, FeCl₃ = 1 Fe + 3Cl ,  where n = 4

Osmolarity = molarity × n

                  = 2 ×4

                  = 8 osmol / L

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Answer:

poor access to health care providers

Explanation:

without health care providers you cant get tested.

Answer:

ionic

Explanation:

because when in molten or dissolved in water  ions are free to move and carry  a charge however when in solid the ions are fixed in position so can't carry a charge.

Answer:

Moles= 11/44 = 0.25 molesof CO2. Click to see full answer Considering this, how many moles of carbon are in 1 mole of co2? A mole of CO2molecules (we usually just say “a mole of CO2”) has one moleof carbonatoms and two molesof oxygen atoms.

Exxplanation:

The ions present in KCL are K⁺ and Cl⁻ which forms KCL by ionic bond. KCL is the chemical formula for potassium chloride. It is created when the extra electron from the potassium atom's valence shell is transferred to the chlorine atom's valence shell, completing the octet valency of both atoms.

K with one dot on the right stands for potassium. If the atom is a noble-gas atom, there are two additional processes that could be used. The outermost filled shell can be thought of as the valence shell, or we can assume that the atom has no valence electrons at all.

When compared to chlorine, which has seven electrons and only one valence electron, potassium provides the final electron that chlorine needs to complete its octet. As a result, potassium and chlorine create an ionic bond, resulting in the formation of potassium chloride.

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If 1.90 g of silver are produced from the reaction, then 0.0176 moles of copper(II) nitrate are also produced.

A chemical reaction occurs when moving molecules hit each other, breaking their bonds and producing an exchange of atoms that form new products. Another way a chemical reaction can occur is through the vibration of substances; when they do so with sufficient energy, they can be broken down into smaller molecules.

we need to use the balanced chemical equation,

3Cu(NO3)2 + 2Al → 3Cu + 2Al(NO3)3

we can see that 3 moles of Cu(NO3)2 react with 2 moles of Al to produce 3 moles of Cu. Therefore, the molar ratio of Cu(NO3)2 to Cu is 3:3 or 1:1.

m(Ag) = 1.90 g

M(Ag) = 107.87 g/mol

n(Ag) = m(Ag) / M(Ag)

n(Ag) = 1.90 g / 107.87 g/mol

n(Ag) = 0.0176 mol

The molar ratio of Cu(NO3)2 to Cu is 1:1, the moles of Cu produced in the reaction is also 0.0176 mol. So, the number of moles of Cu(NO3)2 produced is also 0.0176 mol.

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The reaction between acids in acetic acid in vinegar reacts with bases of calcium carbonate to form calcium acetate salts

Calcium can form deposits on the surface of equipment in contact with water in the form of CaCO₃

vinegar which contains acetic acid can break the bonds between Calcium and Carbonate that form calcium acetate

CaCO₃ + 2CH₃COOH = Ca(CH₃COO)₂ + H₂CO₃

CaCO₃ + 2CH₃COOH = Ca(CH₃COO)₂ + H₂O + CO₂

Answer:

0.3mol C8H18

Explanation:

For this we must first look at the reaction taking place:

C8H18+O2 --> H2O + CO2

Balancing the equation we get:

2(C8H18)+25(O2) --> 18(H2O) + 16(CO2)

Form there we now need to know how many moles of Octane are needed to produce 2.4moles of H2O. The conversion is as follows:

2.4molH2O ((2mol of C8H18)/(18mol of H2O)) = 0.3mol C8H18

The statement that best describes a buffer solution is c) Buffer resists change in pH by accepting hydrogen ions when acids are added to the solution and donating hydrogen ions when bases are added.

A buffer solution is a mixture of a weak acid and its conjugate base (or a weak base and its conjugate acid) that helps to resist changes in pH when small amounts of an acid or base are added to the solution. The weak acid and its conjugate base act together to "buffer" the solution and prevent large changes in pH.

Buffers are important in many biological, chemical, and industrial processes, where the maintenance of a stable pH is crucial. For example, buffer solutions are used in blood and other bodily fluids to regulate the pH, and in many industrial processes to stabilize the pH of process streams and effluents.

Therefore, The statement that best describes a buffer solution is c) Buffer resists change in pH by accepting hydrogen ions when acids are added to the solution and donating hydrogen ions when bases are added.

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Edible mushrooms: Consuming edible mushrooms is safe and provides health advantages like fiber, vitamins, and minerals.

Non-Edible mushrooms: Mushrooms that cannot be eaten could be harmful or have unappealing flavors and textures that could be harmful if consumed.

Answer:

28.23 g NH₃

Explanation:

The balanced chemical equation is:

N₂(g) + 3 H₂(g) → 2 NH₃(g)

Thus, 1 mol of N₂ reacts with 2 moles of H₂ to produce 2 moles of NH₃. We convert the moles to mass (in grams) by using the molecular weight (MW) of each compound:

MW(N₂) = 2 x 14 g/mol = 28 g/mol

mass N₂= 1 mol x 28 g/mol = 28 g

MW(H₂) = 2 x 1 g/mol = 2 g/mol

mass H₂ = 3 mol x 2 g/mol = 6 g

MW(NH₃) = 14 g/mol + (3 x 1 g/mol) = 17 g/mol

mass NH₃= 2 moles x 17 g/mol = 34 g

Now, we have to figure out which is the limiting reactant. For this, we know that the stoichiometric ratio is 28 g N₂/6 g H₂. If we have 36.85 g of H₂, we need the following mass of N₂:

36.85 g H₂ x 28 g N₂/6 g H₂ = 171.97 g N₂

We have 23.15 g N₂ and we need 171.97 g. So, we have lesser N₂ than we need. Thus, the limiting reactant is N₂.

Now, we calculate the product (NH₃) by using the stoichiometric ratio 34 g NH₃/28 g N₂, with the mass of N₂ we have:

23.25 g N₂ x 34 g NH₃/28 g N₂ = 28.23 g NH₃

Therefore, the maximum amount of NH₃ that can be produced is 28.23 grams.

The shape properties of each connected component can be calculated to identify the shape of the fruit.

In order to identify the shape of the fruit, an appropriate technique must be used. This can be done using the following steps:Step 1: Load the image into a software program capable of image analysis.

Step 2: Apply a morphological opening operation to the image using the given structuring elements (1s). This operation is used to remove small objects from the image while preserving the larger shapes.

Step 3: Apply a connected component analysis to the image to identify the separate regions of the image.

Step 4: Calculate the shape properties of each connected component, such as area, perimeter, circularity, and eccentricity. These can be used to identify the shapes of the fruits.

Step 5: Choose the fruits that match the desired shape properties, such as circularity and eccentricity, and label them accordingly.

The above technique can be applied to identify the shape of the fruit.

The technique used here is morphological opening, which removes small objects from the image while preserving the larger shapes.

By applying this operation, the shape of the fruit can be isolated from the rest of the image. Then a connected component analysis can be performed to identify the separate regions of the image.

Finally, the shape properties of each connected component can be calculated to identify the shape of the fruit.

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A compound which has molar mass 123.22g/mol will have a molecular formula as ZrO₂. so the correct option is D.

We need to know the empirical formula of the compound and the quantity of empirical formula units in the molecular formula in order to determine the molecular formula of a substance with a certain molar mass.

The mass of a certain molecule is its molecular mass, which is expressed in daltons. Because they contain various isotopes of an element, multiple molecules of the same substance can have distinct molecular weights.

A) Co₂H₄:

Co: 2 x 58.93 = 117.86

H: 4 x 1.01 = 4.04

Total: 121.9 g/mol

B) PSF:

P: 1 x 30.97 = 30.97

S: 1 x 32.06 = 32.06

F: 1 x 18.99 = 18.99

Total: 82.02 g/mol

C) SrS₃:

Sr: 1 x 87.62 = 87.62

S: 3 x 32.06 = 96.18

Total: 183.8 g/mol

D) ZrO₂:

Zr: 1 x 91.22 = 91.22

O: 2 x 16.00 = 32.00

Total: 123.22 g/mol

The number of empirical formula units in the molecular formula can now be determined by dividing the supplied molar mass by the empirical formula weight:

A)Co₂H₄: 123.22 / 121.9 = 1.01, meaning that the molecular formula and the empirical formula,Co₂H₄, are nearly identical.

B) PSF: 123.22 divided by 82.02 equals 1.50, which means the molecular formula is 1.5 times the empirical formula and can be rounded to PS3F3PS₃F₃.

CSrS₃: 123.22 / 183.8 = 0.67, which means that the molecular formula is equal to 0.67 times the empirical formula, or  SrS₂.

D) ZrZrO₂2: Because the molar mass and empirical formula weight are already equal, the molecular formula, ZrO₂, is also the empirical formula.

Consequently, D) ZrO2rO₂ is the chemical formula for the substance with a molar mass of 123.22 g/mol.

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By ideal gas approximation, the molar mass is 9.84 x 10¯³.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

ρ = 0.862 g/l

T = 298 K

P = 2.14 atm = 216835.5 Pa

Find the molarity of gas

P . V = n . R . T

P / (R. T) = (n/V)

M = P / (R. T)

M = 216835.5  / (8.31 . 298)

M = 87.56 M

Find the molar mass

M = (gr/Mr) / lt

M = (gr/lt) x 1/Mr

M =  ρ / Mr

87.56 = 0.862 / Mr

Mr = 9.84 x 10¯³

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Answer:

The answer would be D.

: )

Explanation:

The number of gas molecules changes as the pressure inside oxygen tanks changes as they are filled. option D is correct.

Oxygen tanks are those in which the oxygen is filled in the liquid form by giving pressure to it with the help of a piston due to more pressure the molecules of oxygen become close.

As the molecule of the oxygen gas is closed to each other they are condensed and changes their state from a gaseous state to a liquid state.

By providing more pressure to the oxygen tank the gas molecules increases due to the decrease in the surface of the tank and molecules condense to liquid form.

Therefore, The number of gas molecules changes as the pressure inside oxygen tanks changes as they are filled. option D is correct.

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Answer:

Static Electricity

Explanation:

Answer:

static electricity

Explanation:

Approximately\(18.64 mL of 0.550 M\) NaOH is required to completely neutralize 25.00 mL of 0.410 M HCl.

To calculate the volume of \(0.550 M NaOH (aq)\) required to completely neutralize\(25.00 mL of 0.410 M HCl (aq),\) we can use the following equation:
\(M1V1 = M2V2\)

Where M1 is the molarity of the \(NaOH\)solution, V1 is the volume of the \(NaOH\)solution we need to find, \(M2\) is the molarity of the HCl solution, and V2 is the volume of the HCl solution we are given\((25.00 mL).\)
Plugging in the given values, we get:

\((0.550 M) V1 = (0.410 M) (25.00 mL)\)

Solving for V1, we get:

\(V1 = (0.410 M) (25.00 mL) / (0.550 M)\\\)

\(V1 = 19.09 mL\)

Therefore, the volume of \(0.550 M NaOH (aq)\)required to completely neutralize \(25.00 mL of 0.410 M HCl (aq) is 19.09 mL\)(rounded to two decimal places).

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If you flow a solution of Na Cl- in water over an Anion resin, what will be in the outlet stream leaving the bed High Resolution. Cost Effective Solutions. High Capacity. Efficient Purification.

A resin or polymer that serves as a medium for ion exchange is known as an ion-exchange resin or ion-exchange polymer. It is an insoluble matrix (or support structure) made from an organic polymer substrate, typically appearing as tiny (0.25-1.43 mm radius) microbeads that are white or bin color. The process is known as ion exchange because the beads are often porous, providing a wide surface area on and inside them where the trapping of ions takes place along with the concomitant release of other ions. Ion-exchange resin comes in many different varieties. Polystyrene sulfonate is the main ingredient in most commercial resins.

Many diverse separation, purification, and decontamination techniques use ion-exchange resins. The most typical examples are water filtration and water softening.

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The percentage of daily kilocalories of the person that come from fat is 20%.

The diet of a person is composed mainly of carbohydrates (C), proteins (P) and fat (F), that is, the sum of the 3 sources amount to 100% of the consumed kilocalories. Given that 50% of the daily kilocalories of this person come from carbohydrates and 30% come from protein, the percentage that comes from fats is:

\(C + P + F = 100\%\\F = 100\% - C - P\\F = 100\% - 50\% - 30\% = 20\%\)

The percentage of daily kilocalories of the person that come from fat is 20%.

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Answer

bitly coin download

Explanation:

bitly coin download

Answer:

the correct answer is gravity

Answer:

the gravitational pull so gravity (b)

To answer your question, the term "orbital period" refers to the time it takes for an object to complete one orbit around another object. This can be applied to any celestial body, such as a planet or a satellite.

To calculate the orbital period of an object, we need to know the distance between the two objects and the gravitational force between them. Using these values, we can use Kepler's laws of planetary motion to determine the orbital period.

For example, if we are calculating the orbital period of a satellite around the Earth, we would need to know the distance between the Earth and the satellite and the force of gravity between them. Once we have these values, we can use Kepler's third law, which states that the square of the orbital period is proportional to the cube of the distance between the two objects.

Therefore, the equation to calculate the orbital period is:

T^2 = (4π^2 / GM) x r^3

where T is the orbital period, G is the gravitational constant, M is the mass of the object being orbited (in this case, the Earth), and r is the distance between the two objects.

Once we have calculated T, we can express it in the appropriate units, which are usually seconds, minutes, or hours. For example, if the orbital period is calculated to be 90 minutes, we would express it as 1.5 hours.

In summary, the orbital period of an object is the time it takes for that object to complete one orbit around another object. We can calculate this period using Kepler's laws of planetary motion and express it in the appropriate units.

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