Explain what we mean by the statement density of a substance is one gcm^3​

The pulley system to the right will be in static equilibrium at an unknown angle of 90 degrees.

An object must satisfy two requirements of equilibrium in order to maintain static equilibrium. First, there must be no net force acting on the item. Second, there must be no net torque pulling on the object.

The 80 N weight is fastened to a freely rotating pulley in this setup.

As a result, the cable's tension is also 80 N.

The tensions' x components must be balanced against one another:

T1x = T2x

Since T1x = T1 cos(θ) and T2x = 0 (because the cable attached to the wall is vertical), we have:

T1 cos(θ) = 0

Therefore, cos(θ) = 0, which means that θ = 90 degrees.

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Answer:

Baseball is commonly expressed in English units - we'll use that

(Rubber to home plate is 60' 6 '' but the ball is probably released at about 60 ft)

t = S / v      time of fall and time to reach plate

H = 1/2 g t^2

t = (2 H / g)^1/2     we'll use 32.,2 ft / sec^2    for g

t = (2 * 2.81 / 32.2)^1/2 = .418 sec

v = 60 ft / .418 sec = 144 ft/sec

Since 60 mph = 88 ft/sec

v = 144 / 88 * 60 = 98 mph

Answer:

all living things are made of cells

Explanation:

cells are kinda like matter but only for living thing like when someone says you white blood cell count is low its because they are part of you living body.

When a person sings in a shower and causes the shower to resonate with a fundamental frequency of 73 Hz, this is an example of a standing wave, also known as a resonance.

The fundamental frequency of a standing wave is determined by the length of the resonant cavity, which in this case is the shower. The fundamental frequency is related to the length of the cavity by the equation:

f = v / 2L

where f is the frequency, v is the velocity of sound in the medium (in this case, air), and L is the length of the cavity. Given that the shower has a length of 2.40 meters and the fundamental frequency is 73 Hz, we can use the equation above to calculate the velocity of sound in air.

73 = v / (2 * 2.40)

Solving for v, we get:

= v

= (73 * 2 * 2.40)

= 350.4 m/s

The speed of sound in air is approximately 343 m/s at 20 °C at sea level. The velocity of sound in air can change with temperature, humidity and pressure. Given that the velocity of sound in air is around 343 m/s, the frequency of 73 Hz is a close match to the fundamental frequency of the shower with 2.40 meters high, It is important to note that the fundamental frequency is not the only frequency that could resonate in the shower, other overtones and harmonics might also resonate.

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Question- Someone is singing in a shower that measures 2.40 meters from floor to ceiling, and notices their voice causes the shower to resonate with a fundamental frequency of 73 Hz. Here, this situation is an example of? justify. The given situation is an example of which physics phenomenon and justify the given example with some details.

Answer: 25500 joules

Explanation: E = P x t

Answer:

c. 15.4 s

Explanation:

Given the following data;

Mass, m = 50kg

Force, F = 130N

Initial velocity, u = 20m/s

Final velocity, v = 60m/s

To find the time;

First of all, we would solve for acceleration using the formula below;

Force = mass * acceleration

130 = 50*acceleration

Acceleration = 130/50

Acceleration = 2.6m/s²

Now, we would use the first equation of motion to find the time.

V = U + at

60 = 20 + 2.6t

2.6t = 60 - 20

2.6t = 40

t = 40/2.6

Time, t = 15.39 ≈ 15.4 seconds.

The time taken will be 15.4 seconds approximately. The correct answer is option c

NEWTON SECOND LAW

Newton's second law state that, the rate of change of momentum is proportional to the force applied.

Given that  a force of 130 N be applied to an object of mass 50 kg to change its speed from 20 m/s to 60 m/s. The given parameters are;

from Newton's second law,

Ft = m(v - u)

Substitute all the parameters into the formula

130t = 50 (60 - 20)

130t = 50 x 40

130t = 2000

t = 2000/130

t = 15.38 seconds

Therefore, the time taken will be 15.4 seconds approximately. The correct answer is option c

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The electrical component that is used for detecting light levels in digital cameras is the light meter.

A light meter is a device used to measure the amount of light. In photography industry, a light meter is used to determine the proper exposure for a photograph.

A digital camera is a camera that captures photographs in digital memory.

Most digital cameras can be grouped into four main types which includes:

Each type of these digital cameras has advantages and disadvantages, and some the types are more expensive than their counterparts.

There are two different kinds of light meters which are:

-An incident light meter measures all the light falling onto a subject. Incident light meters help a camera focus on a subject regardless of how light or dark the surrounding background is.

- Reflective light meters  on the other hand do the opposite by measuring the light reflected by or bouncing off a subject.

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Answer:

B

Explanation:

V=IR    I= curren V=volt R=resistor

8=2.R   8/2=R R=4

The refractive index of the material is 0.

When the ray is incident on a transparent surface at an angle of 360 and the angle of refraction within the material is 27°, the refractive index of the material can be determined. The formula for Snell’s law is used to calculate refractive index. It states that: `sin i / sin r = n where i is the angle of incidence, r is the angle of refraction and n is the refractive index`.Snell’s law can be re-arranged to make n the subject of the formula to be: `n = sin i / sin r`Hence, we can calculate the refractive index as follows:

For the incident ray, i = 360° and the angle of refraction within the material, r = 27°.n = sin i / sin r= sin 360°/ sin 27°= 0/1 (since sin 360° = 0)= 0Therefore, the refractive index of the material is 0. T

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Answer:

E max

=3.46×10

7

N/C

Explanation:

If the radius and charge are R and Q. We need to calculate the electric field due to the rod. Using formula of electric field. Where, Q = charge. z = distance. If z = 0, Then, The electric field is (b). If z = ∞, z>>R. So, R = 0. Then, the electric field is (c). In terms of R, We need to calculate the positive distance. If . Then, Taking only positive distance (d).

The resistance of a 50-watt bulb is twice greater than that of a 100-watt bulb if both run on the same voltage.

1. Understand the terms involved.
- Resistance: It is the opposition to the flow of electric current and is measured in ohms (Ω).
- Watt: It is the unit of power, which represents the rate of energy transfer or conversion.

2. Use the formula for power.
The power (P) of an electrical device can be calculated using the formula:
P = V^2 / R
where V is the voltage and R is the resistance.

Set up the equation for the two bulbs.
Let R1 be the resistance of the 50-watt bulb and R2 be the resistance of the 100-watt bulb. We know the power (P1 = 50 watts and P2 = 100 watts) and that both bulbs operate at the same voltage (V).

4. Write the equations.
50 = V^2 / R1
100 = V^2 / R2

5. Divide the first equation by the second equation.
(50 / 100) = (V^2 / R1) / (V^2 / R2)
0.5 = R2 / R1

6. Solve for the relationship between R1 and R2.
R1 = 2 * R2

The resistance of a 50-watt bulb is twice that of a 100-watt bulb when both run on the same voltage.

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The unmanned SpaceX rocket that exploded minutes after taking off was launched from Cape Canaveral, Florida, which is located in the United States.

An unmanned SpaceX rocket, known as the Falcon 9, exploded a few minutes after its launch from the Cape Canaveral Space Launch Complex in Florida, United States. The incident occurred on [date]. The rocket was carrying [payload information] and was intended for [mission objective].

The explosion took place during the ascent phase of the rocket's flight, resulting in a catastrophic failure. The exact cause of the explosion is typically investigated by SpaceX and relevant authorities to determine the root cause, which could range from technical malfunctions to operational errors.

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According to the question the speed of the skater's hands is 528 m/min.

To calculate the speed of the skater's hands, we can use the formula:

Speed = Circumference * Revolutions per minute

Given that the skater's hands are 140 cm apart and she spins at 120 rpm, we need to calculate the circumference of the circle formed by her hands.

The circumference of a circle is given by the formula:

Circumference = 2 * π * radius.

In this case, the radius is half the distance between the skater's hands, which is 140 cm / 2 = 70 cm.

Converting the radius to meters, we have 70 cm = 0.7 m.

Now we can calculate the circumference:

Circumference = 2 * π * 0.7 m = 4.4 m (rounded to one decimal place).

Finally, we can calculate the speed of the skater's hands:

Speed = Circumference * Revolutions per minute

     = 4.4 m * 120 rpm

     = 528 m/min.

Therefore, the speed of the skater's hands is 528 m/min.

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Answer:

c

Explanation:

Answer:

c

Explanation:

the DNA replication happens in the s phase of interphase

True, this is because the echo sounder that is applicable to boats cannot be used directly for airplanes

By sending out sound waves and timing how long it takes for them to bounce back, an echo sounder, sometimes referred to as a sonar, is a device frequently used in boats to gauge the depth of the water beneath the craft.

When a sound pulse from an echo sounder strikes a solid item in the water, such as fish, vegetation, or other objects, the signal is reflected back to the surface.

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Answer:

If they both start at the same height then most likely that means that each has an intical velocity  and a net force sooooo ball A 19.6

Explanation:

Answer: The mass of ball C is greater than the mass of ball A but less than the mass of ball B.

In order to have a planet that has a force of gravity similar to that of the earth, the space ship must land in Borros whose radius is half of the earth's radius and has one - fourth of the earth's mass.

The force of gravity is obtained from;

F = Gm1m2/r^2 It is an example of an inverse square law.

For another planet, Borros, the radius is half of that of the earth and the mass is one - fourth of that of the earth, hence;

F = 1/4Gm1m2/(r/2)^2

F = 1/4Gm1m2/r^2/4

F = Gm1m2/r^2

Therefore, the planet that is most similar to the earth is Borros because,  the gravity would be stronger , but since it is only one fourth the mass , the changes balance out and the gravity will be the same as on Earth.

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Answer:

By increasing the distance through which force is applied, by changing the direction of applied force, or by multiplying force of speed of the energy applied.

please Brainlist..☺✌☺

Answer:

Motors convert electrical energy into mechanical energy

Explanation:

A motor uses electrical energy to create mechanical energy by creating magnetic fields causing the motor to spin. A generator is the opposite and converts mechanical into electrical by spinning a motor in a magnetic field.

An electric motor  can transforms electrical energy into mechanical energy. Therefore, option (1) is correct.

Energy can be described as the ability of an object to do work. Energy can also be transformed to work and the work done on an object can be stored in the form of energy.

The energy contained by the object because of its motion is called kinetic energy. The energy contained by an object due to its position is called its potential energy. Mechanical energy can be defined as the sum between the kinetic energy and potential energy of a body according to the law of conservation of energy.

An electric motor is a machine that receives energy from electricity as electrical energy and transforms it into mechanical energy. Therefore, when electric energy is supplied to an electric motor it converts electrical energy into mechanical energy.

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Answer:

1960Joules

Explanation:

Since we are not told what too find, we can as well find the Gravitational Potential Energy.

GPE = mass * acceleration due to gravity * height

GPE = 100*9.8 * 2

GPE = 980*2

GPE = 1960Joules

Hence the gravitational potential Energy is 1960Joules

The correct statement is MPK = 400K^(-0.2). This is because the marginal product of capital (MPK) is derived by taking the partial derivative of the production function with respect to capital (K), holding labor (L) constant

To find the marginal product of labor (MPL) and the marginal product of capital (MPK), we need to take partial derivatives of the production function Q = 500L^0.6K^0.8 with respect to each input.

First, let's find MPL:

∂Q/∂L = 500 * 0.6 * L^(0.6-1) * K^0.8

Simplifying, we have:

MPL = 300L^(-0.4)K^0.8

Comparing this with the given options, we see that MPL = 300L^(-0.4)K^0.8 is not one of the options. Therefore, this option is not true.

Now, let's find MPK:

∂Q/∂K = 500 * 0.8 * L^0.6 * K^(0.8-1)

Simplifying, we have:

MPK = 400L^0.6K^(-0.2)

Comparing this with the given options, we see that MPK = 400K^(-0.2) is one of the options. Therefore, this option is true. In conclusion, the correct statement is MPK = 400K^(-0.2).

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Using the principle of dimensional analysis, the representation of Pressure would be \( P = F^{1}V^{-\frac{2}{3}}D^{0}\)

Pressure is related to Force, Volume and Density thus :

\( Pressure, P = F^{a}V^{b}D^{c}\)

Using dimensional analysis :

Substituting the dimension into the relation :

\( ML^{-1}T^{-2}= [MLT¯²]^{a} [L³]^{b} [ML¯³]^{c} \)

\( ML^{-1}T^{-2} = M^{a+c}L^{a+3b-3c}T^{-2a} \)

Equating the power ;

a + c = 1 - - - (1)

a + 3b - 3c = - 1 - - - (2)

-2a = - 2

a = - 2/-2

a = 1

From (1)

1 + c = 1

c = 1 - 1 = 0

c = 0

From (2) :

1 + 3b - 3(0) = - 1

1 + 3b = - 1

3b = - 2

b = - 2/3

Hence, \( P = F^{1}V^{-\frac{2}{3}}D^{0}\)

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The representation of pressure is:

\(P=FV^{-\frac{2}{3} }\)

Given that:

Force F, volume V and density D are taken as fundamental quantities, hence pressure P is:

\(P=F^aV^bD^c\\\\(ML^{-1}T^{-2})=(MLT^{-2})^a(L^3)^b(ML^{-3})^c\\\\\\(ML^{-1}T^{-2})=(M)^{a+c}(L)^{a+3b-3c}(T)^{-2a}\)

Hence:-

2 = -2a

a = 1

a + c = 1

1 + c = 1

c = 0

a + 3b - 3c = -1

1 + 3b - 3(0) = -1

3b = -2b = -2/3

Hence the representation of pressure is:

\(P=FV^{\frac{-2}{3} }D^{0}\\\\P=FV^{\frac{-2}{3} }\)

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The energy method is a technique used to determine the deflected shape of a rectangular plate subjected to a concentrated load. In this case, the plate is simply supported along each edge and carries a concentrated load F at a position (r1, y).

To find the deflected shape of the plate, we can use the series representation DO MAT nay Amn sin sin b TIL.

Now, let's break down the steps to determine the deflected shape using the energy method:

1. First, we need to calculate the bending moment caused by the concentrated load F. The bending moment can be given by the formula M = F * (b - r1),

where b is the width of the plate and r1 is the distance of the concentrated load from one edge.

2. Next, we need to find the deflection function, which represents the shape of the plate when it is deflected.

The deflection function can be represented by the series DO MAT nay Amn sin sin b TIL, where DO is the maximum deflection, A is a constant, m and n are positive integers, and a and b are the dimensions of the plate.

3. Now, we substitute the deflection function into the plate's governing equation. The governing equation for a rectangular plate simply supported along each edge is given by the biharmonic equation:

   ∇^4w = 0,

  where ∇^4 represents the Laplacian operator.

4. By substituting the deflection function into the biharmonic equation and solving for the unknown coefficients, we can determine the specific form of the deflection function that satisfies the boundary conditions.

5. Finally, with the determined coefficients, we can calculate the deflected shape of the plate by evaluating the deflection function at different points on the plate.

It's important to note that the exact determination of the coefficients Amn requires solving an infinite series of equations.

However, in practical applications, only a few terms of the series are usually considered, resulting in an approximation of the deflected shape.

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Answer:

As per Provided Information

we have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.

\( \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}\)

Substituting the value and let's solve it

\( \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} \)

Now, let's calculate the force applied to stop the car .

\( \pink{\boxed{\bf \: F = ma}}\)

Substituting the value we get

\( \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N\)

Here , negative sign show that the " Force is acting in opposite direction of the motion"

Therefore,

The FALSE statement concerning the work done by a conservative force is (b) It is independent of the path of the body and depends only on the starting and ending points.

For a conservative force, work done is path-independent only for the net work done around a closed path. This is because the net work done around a closed path is zero. However, for any other path, the work done by a conservative force depends on the path taken and not just the initial and final points. This is because the force may vary at different points in the path, and the work done is the integral of the force over the path.

The other statements (a) It can always be expressed as the difference between the initial and final values of a potential energy function, and (c) When the starting and ending points are the same, the total work is zero, are both true statements concerning the work done by a conservative force.

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Answer:

La velocidad angular del niño y del carrusel cuando se mueven juntos es 0.208 radianes por segundo.

Explanation:

Asumamos que tanto el niño como el carrusel no tienen carga externa aplicada sobre aquellos, de modo que se puede aplicar el Principio de Conservación de la Cantidad de Movimiento Angular:

\(m\cdot v \cdot R = (m\cdot R^{2}+I)\cdot \omega\) (1)

Donde:

\(m\) - Masa del niño, medida en kilogramos.

\(v\) - Velocidad lineal inicial del niño, medida en metros por segundo.

\(R\) - Radio máximo del carrusel, medida en metros.

\(I\) - Momento de inercia del carrusel, medida en kilogramo-metros cuadrados.

\(\omega\) - Velocidad angular final del sistema niño-carrusel, medida en radianes por segundo.

Si sabemos que \(m = 25\,kg\), \(v = 2.5\,\frac{m}{s}\), \(R = 2\,m\) y \(I = 500\,kg\cdot m^{2}\), tenemos que la velocidad angular final es:

\(\omega = \frac{m\cdot v\cdot R}{m\cdot R^{2}+I}\)

\(\omega = \frac{(25\,kg)\cdot \left(2.5\,\frac{m}{s} \right)\cdot (2\,m)}{(25\,kg)\cdot (2\,m)^{2}+500\,kg\cdot m^{2}}\)

\(\omega = 0.208\,\frac{rad}{s}\)

La velocidad angular del niño y del carrusel cuando se mueven juntos es 0.208 radianes por segundo.

Answer:

distance = (10/3) m or 3.33... m

Explanation:

When the direction of force and distance is the same,

Work = Force × distance

So,

1000J = 300N × distance

=> 1000J/300N = distance

=> (10/3) m = distance

=> 3.33... m = distance

Given

4th armonic 31.5Hz

Procedure

4f = 31.5

Thrid armonic

Hence the third frequency is 23.625 Hz

Heat energy is also called thermal energy.